Answer:
3h = 39Step-by-step explanation:
The question is incomplete. Here is the complete question.
Translate this sentence into an equation. The product of Holly's height and 3 is 39. Use the variable h to represent Holly's height.
Let holly's savings be h. If the product of Holly's savings and 3 is 39, this can be represented mathematically as h*3 = 39
To get holly's savings "h', we will divide both sides of the equation by 3
h*3 = 39
h*3/ 3= 39/3
h = 13*3/ 3
h = 13 * 3/3
h = 13*1
h = 13
Holly's savings is 13 and the required equation is 3h =39
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.5. (Round your answers to four decimal places.)(a) If the distribution is normal, what is the probability that the sample mean hardness for a random sample of 10 pins is at least 51
Answer:
0.0174 = 1.74% probability that the sample mean hardness for a random sample of 10 pins is at least 51
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
[tex]\mu = 50, \sigma = 1.5, n = 10, s = \frac{1.5}{\sqrt{10}} = 0.4743[/tex]
What is the probability that the sample mean hardness for a random sample of 10 pins is at least 51
This is 1 subtracted by the pvalue of Z when X = 51. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{51 - 50}{0.4743}[/tex]
[tex]Z = 2.11[/tex]
[tex]Z = 2.11[/tex] has a pvalue of 0.9826
1 - 0.9826 = 0.0174
0.0174 = 1.74% probability that the sample mean hardness for a random sample of 10 pins is at least 51
Overweight participants who lose money when they don’t meet a specific exercise goal meet the goal more often, on average, than those who win money when they meet the goal, even if the final result is the same financially. In particular, participants who lost money met the goal for an average of 45.0 days (out of 100) while those winning money or receiving other incentives met the goal for an average of 33.7 days. The incentive does make a difference. In this exercise, we ask how big the effect is between the two types of incentives. Find a 90% confidence interval for the difference in mean number of days meeting the goal, between people who lose money when they don't meet the goal and those who win money or receive other similar incentives when they do meet the goal. The standard error for the difference in means from a bootstrap distribution is 4.14.
Answer:
The 90% confidence interval for the difference in mean number of days meeting the goal is (4.49, 18.11).
Step-by-step explanation:
The (1 - α)% confidence interval for the difference between two means is:
[tex]CI=\bar x_{1}-\bar x_{2}\pm z_{\alpha/2}\times SE_{\text{diff}}[/tex]
It is provided that:
[tex]\bar x_{1}=45\\\bar x_{2}=33.7\\SE_{\text{diff}} =4.14\\\text{Confidence Level}=90\%[/tex]
The critical value of z for 90% confidence level is,
z = 1.645
*Use a z-table.
Compute the 90% confidence interval for the difference in mean number of days meeting the goal as follows:
[tex]CI=\bar x_{1}-\bar x_{2}\pm z_{\alpha/2}\times SE_{\text{diff}}[/tex]
[tex]=45-33.7\pm 1.645\times 4.14\\\\=11.3\pm 6.8103\\\\=(4.4897, 18.1103)\\\\\approx (4.49, 18.11)[/tex]
Thus, the 90% confidence interval for the difference in mean number of days meeting the goal is (4.49, 18.11).
divide and simplify x^2+7x+12 over x+3 divided by x-1 over x+4
Answer:
[tex]\dfrac{x^2+8x+16}{x-1}[/tex]
Step-by-step explanation:
In general, "over" and "divided by" are used to mean the same thing. Parentheses are helpful when you want to show fractions divided by fractions. Here, we will assume you intend ...
[tex]\dfrac{\left(\dfrac{x^2+7x+12}{x+3}\right)}{\left(\dfrac{x-1}{x+4}\right)}=\dfrac{(x+3)(x+4)}{x+3}\cdot\dfrac{x+4}{x-1}=\dfrac{(x+4)^2}{x-1}\\\\=\boxed{\dfrac{x^2+8x+16}{x-1}}[/tex]
Evaluate for f=3. 2f - f +7
It is known that when a certain liquid freezes into ice, its volume increases by 8%. Which of these expressions is equal to the volume of this liquid that freezes to make 1,750 cubic inches of ice?
Answer:
Volume of liquid which freezes to ice is 1620. 37 .
Expression to find this is 108x/100 = 1750
Step-by-step explanation:
Let the volume of liquid be x cubic inches
It is given that volume of liquid increases by 8% when it freezes to ice
increase in volume of x x cubic inches liquid = 8% of x = 8/100 * x = 8x/100
Total volume of ice = initial volume of liquid + increase in volume when it freezes to ice = x + 8x/100 = (100x + 8x)/100 = 108x/100
Given that total volume of liquid which freezes is 1750
Thus,
108x/100 = 1750
108x = 1750*100
x = 1750*100/108 = 1620. 37
Volume of liquid which freezes to ice is 1620. 37 .
Expression to find this is 108x/100 = 1750
Find sin angle ∠ C.
A. 12/13
B. 1
C. 13/12
D. 13/5
Answer:
A
Step-by-step explanation:
We can use the trigonometric ratios. Recall that sine is the ratio of the opposite side to the hypotenuse:
[tex]\displaystyle \sin(C)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]
The opposite side with respect to ∠C is 24 and the hypotenuse is 26.
Hence:
[tex]\displaystyle \sin(C)=\frac{24}{26}=\frac{12}{13}[/tex]
Our answer is A.
Which expression is equivalent to 24 ⋅ 2−7?
Answer:
41
Step-by-step explanation:
[tex]24*2-7=\\48-7=\\41[/tex]
Circle O has a circumference of 36π cm. Circle O with radius r is shown. What is the length of the radius, r? 6 cm 18 cm 36 cm 72 cm
Answer: 18 cm
Step-by-step explanation:
We know the circumference formula is C=2πr. Since our circumference is given in terms of π, we can easily figure out what the radius is.
36π=2πr [divide both sides by π to cancel out]
36=2r [divide both sides by 2]
r=18 cm
Answer:
18cm
Step-by-step explanation:
because i found it lol
Evaluate the expression 4/15÷x+0.4 for x if: x=1, x=4/9, x=1 1/3. Solve for each X. I need help Will give brainliest!
Answer:
4/15 ÷ x + 0.4
When x = 1
4/15 ÷ 1 + 0.4
x = 2/3
When x = 4/9
4/15 ÷ 4/9 +0.4
x = 1
When x = 1 ⅓ = 4/3
4/15 ÷ 4/3 + 0.4
x = 3/5
Hope this helps.
Math 7th grade. help please!!!
Answer:
1 .angle S is 90 degree
2. 12
3. 155 degree
1. x = 3
hope it helps .....
The area of the sector of a circle with a radius of 8 centimeters is 125.6 square centimeters. The estimated value of is 3.14.
The measure of the angle of the sector is
Answer:
225º or 3.926991 radians
Step-by-step explanation:
The area of the complete circle would be π×radius²: 3.14×8²=200.96
The fraction of the circle that is still left will be a direct ratio of the angle of the sector of the circle.
[tex]\frac{125.6}{200.96}[/tex]=.625. This is the ratio of the circe that is in the sector. In order to find the measure we must multiply it by either the number of degrees in the circle or by the number of radians in the circle (depending on the form in which you want your answer).
There are 360º in a circle, so .625×360=225 meaning that the measure of the angle of the sector is 225º.
We can do the same thing for radians, if necessary. There are 2π radians in a circle, so .625×2π=3.926991 radians.
Answer:
225º
Step-by-step explanation:
What is the value of (4-2) – 3x4?
О-20
оооо
4
Answer:
-10
Step-by-step explanation:
Use the Order of Operations - PEMDAS
Do what is in parentheses first - (4-2) = 2
Next multiply 3 and 4 = 12
Last, perform 2 - 12; which equals -10
A sample of 8 students was asked how often they used campus dining facilities during the past month. The responses were as follows. 4 1 6 1 2 10 2 6 The sample standard deviation is _____.
Answer:
Your answer is 3.16227766
Step-by-step explanation:
The length of time for one individual to be served at a cafeteria is an exponential random variable with mean of 5 minutes. Assume a person has waited for at least 3 minutes to be served. What is the probability that the person will need to wait at least 7 minutes total
Answer:
44.93% probability that the person will need to wait at least 7 minutes total
Step-by-step explanation:
To solve this question, we need to understand the exponential distribution and conditional probability.
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
Conditional probability:
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
The length of time for one individual to be served at a cafeteria is an exponential random variable with mean of 5 minutes
This means that [tex]m = 5, \mu = \frac{1}{5} = 0.2[/tex]
Assume a person has waited for at least 3 minutes to be served. What is the probability that the person will need to wait at least 7 minutes total
Event A: Waits at least 3 minutes.
Event B: Waits at least 7 minutes.
Probability of waiting at least 3 minutes:
[tex]P(A) = P(X > 3) = e^{-0.2*3} = 0.5488[/tex]
Intersection:
The intersection between waiting at least 3 minutes and at least 7 minutes is waiting at least 7 minutes. So
[tex]P(A \cap B) = P(X > 7) = e^{-0.2*7} = 0.2466[/tex]
What is the probability that the person will need to wait at least 7 minutes total
[tex]P(B|A) = \frac{0.2466}{0.5488} = 0.4493[/tex]
44.93% probability that the person will need to wait at least 7 minutes total
To reach a particular department at a warehouse, a caller must dial a 4-digit extension. Suppose a caller remembers that the first and last digits of an extension are 5, but they are not sure about the other digits.
How many possible extensions might they have to try?
Answer:
100 possible extensions
Step-by-step explanation:
we can calculated how many possible extensions they have to try using the rule of multiplication as:
___1_____*___10_____*___10_____*____1____ = 100
1st digit 2nd digit 3rd digit 4th digit
You know that the 1st and 4th digits of the extension are 5. it means that you just have 1 option for these places. On the other hand, you don't remember nothing about the 2nd and 3rd digit, it means that there are 10 possibles digits (from 0 to 9) for each digit.
So, There are 100 possibles extensions in which the 5 is the first and last digit.
Rocco used these steps to solve the equation 4x + 6 = 4 + 2(2x + 1). Which choice describes the meaning of his result, 6 = 6?
Answer:
infinite solutions
Step-by-step explanation:
it means that all x are solution of this equation as 6=6 is always true
Sue works an average of 45 hours each week. She gets paid $10.12 per hour and time-and-a-half for all hours over 40 hours per week. What is her annual income?
Step-by-step explanation:
40 x $10.12/hr = $404.80
5 x $15.18/hr = $ 75.90
over time = $10.12 + $5.06 ( half of $10.12) = $15.18/hr
$404.80 + $75.90 = $480.70/weekly pay
assuming she works 52 weeks a year
$480.70 × 52 weeks = $24,996.40/yr
What is the perimeter of A’B’C’D’?
[tex]\displaystyle\bf\\\textbf{At any translation of a quadrilateral the sides remain the same,}\\\\\textbf{the angles remain the same.}\\\\\textbf{It turns out that the quadrilateral remains the same.}\\\\P_{A'B'C'D'}=P_{ABCD}=AB+BC+CD+DA=\\\\~~~~~~~~~~~~~~=2.2+4.5+6.1+1.4=\boxed{\bf14.2}[/tex]
can some one answer this plsss
Answer:
D
Step-by-step explanation:
0.2x+5=8
0.2x=3
x=15
Therefore, the correct answer is choice D. Hope this helps!
The function f(x)= 200/X+ 10 models the cost per student of a field trip when x students go on the trip. How is the parent function
f(x) = 1/x transformed to create the function f(x)= 200/x + 10
O It is vertically stretched by a factor of 200.
O It is vertically stretched by a factor of 200 and shifted 10 units leftt
O It is vertically stretched by a factor of 200 and shifted 10 units up.
O It is vertically stretched by a factor of 200 and shifted 10 units right
Answer:
It is vertically stretched by a factor of 200 and shifted 10 units right
Step-by-step explanation:
Suppose we have a function f(x).
a*f(x), a > 1, is vertically stretching f(x) a units. Otherwise, if a < 1, we are vertically compressing f(x) by a units.
f(x - a) is shifting f(x) a units to the right.
f(x + a) is shifting f(x) a units to the left.
In this question:
Initially: [tex]f(x) = \frac{1}{x}[/tex]
Then, first we shift, end up with:
[tex]f(x+10) = \frac{1}{x + 10}[/tex]
f was shifted 10 units to the left.
Finally,
[tex]200f(x+10) = \frac{200}{x + 100}[/tex]
It was vertically stretched by a factor of 200.
So the correct answer is:
It is vertically stretched by a factor of 200 and shifted 10 units right
Answer:
the answer is D
Step-by-step explanation:
Which of the following equations describes the line shown below? Check all
that apply
Answer:
y-7=1/2(x-8)
y-4=1/2(x-2)
Step-by-step explanation:
Slope: 3/6, or 1/2
y-7=1/2(x-8)
y-4=1/2(x-2)
A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000 women reported drinking alcohol and 552 of 1000 men reported drinking alcohol. What is the 95% confidence interval of the drinking alcohol percentage difference between women and men
Answer:
The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).
Step-by-step explanation:
We want to calculate the bounds of a 95% confidence interval of the difference between proportions.
For a 95% CI, the critical value for z is z=1.96.
The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.
[tex]p_1=X_1/n_1=494/1000=0.494[/tex]
The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.
[tex]p_2=X_2/n_2=552/1000=0.552[/tex]
The difference between proportions is (p1-p2)=-0.058.
[tex]p_d=p_1-p_2=0.494-0.552=-0.058[/tex]
The pooled proportion, needed to calculate the standard error, is:
[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523[/tex]
The estimated standard error of the difference between means is computed using the formula:
[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022[/tex]
Then, the margin of error is:
[tex]MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014[/tex]
The 95% confidence interval for the difference between proportions is (-0.102, -0.014).
Word related to circle
Answer:
Center, radius, chord, diameter... are Words related to circle
Please answer this correctly
Answer:
Raspberry: 30%
Strawberry: 15%
Apple: 20%
Lemon: 35%
Step-by-step explanation:
18 + 9 + 12 + 21 = 60 (there are 60 gummy worms)
18 out of 60 = 30%
9 out of 60 = 15%
12 out of 60 = 20%
21 out of 60 = 35%
Please mark Brainliest
Hope this helps
Answer:
Raspberry Worms: 30%
Strawberry Worms: 15%
Apple Worms: 20%
Lemon Worms: 35%
Step-by-step explanation:
Raspberry Worms: [tex]\frac{18}{18+9+12+21}=\frac{18}{60}=\frac{30}{100}[/tex] or 30%
Strawberry Worms: [tex]\frac{9}{18+9+12+21}=\frac{9}{60} =\frac{15}{100}[/tex] or 15%
Apple Worms: [tex]\frac{12}{18+9+12+21} =\frac{12}{60} =\frac{20}{100}[/tex] or 20%
Lemon Worms: [tex]\frac{21}{18+9+12+21} =\frac{21}{60} =\frac{35}{100}[/tex] or 35%
Find the area of the largest rectangle that can be inscribed in a right triangle with legs of lengths 4 cm and 6 cm if two sides of the rectangle lie along the legs. webassign cengage
Answer:
[tex]6cm^2[/tex]
Step-by-step explanation:
Let x and y be the sides of the rectangle.
Area of the Triangle, A(x,y)=xy
From the diagram, Triangle ABC is similar to Triangle AKL
AK=4-y
Therefore:
[tex]\dfrac{x}{6} =\dfrac{4-y}{4}[/tex]
[tex]4x=6(4-y)\\x=\dfrac{6(4-y)}{4} \\x=1.5(4-y)\\x=6-1.5y[/tex]
We substitute x into A(x,y)
[tex]A=y(6-1.5y)=6y-1.5y^2[/tex]
We are required to find the maximum area. This is done by finding
the derivative of Aand solving for the critical points.
Derivative of A:
[tex]A'(y)=6-3y\\$Set $A'=0\\6-3y=0\\3y=6\\y=2$ cm[/tex]
Recall that: x=6-1.5y
x=6-1.5(2)
x=6-3
x=3cm
Therefore, the maximum rectangle area is:
Area =3 X 2 =[tex]6cm^2[/tex]
Which are the right ones?
Answer:
20 4/5
Step-by-step explanation:
13/5 times 8/1
104/5
which is simplify
to 20 4/5\
hope this helps
Express 12/16 in quarters
I really need help, please help me.
Answer:
96 degrees
Step-by-step explanation:
Since x is half of 168, its angle measure is 84 degrees. Since x and y are a linear pair, their angle measures must add to 180 degrees, meaning that:
y+84=180
y=180-84=96
Hope this helps!
Suppose that the demand function for a product is given by D(p)equals=StartFraction 50 comma 000 Over p EndFraction 50,000 p and that the price p is a function of time given by pequals=1.91.9tplus+99, where t is in days. a) Find the demand as a function of time t. b) Find the rate of change of the quantity demanded when tequals=115115 days. a) D(t)equals=nothing (Simplify your answer.)
Answer:
(a)[tex]D(t)=\dfrac{50000}{1.9t+9}[/tex]
(b)[tex]D'(115)=-1.8355[/tex]
Step-by-step explanation:
The demand function for a product is given by :
[tex]D(p)=\dfrac{50000}{p}[/tex]
Price, p is a function of time given by [tex]p=1.9t+9[/tex], where t is in days.
(a)We want to find the demand as a function of time t.
[tex]\text{If } D(p)=\dfrac{50000}{p},$ and p=1.9t+9\\Then:\\D(t)=\dfrac{50000}{1.9t+9}[/tex]
(b)Rate of change of the quantity demanded when t=115 days.
[tex]\text{If } D(t)=\dfrac{50000}{1.9t+9}[/tex]
[tex]\dfrac{\mathrm{d}}{\mathrm{d}t}\left[\dfrac{50000}{\frac{19t}{10}+9}\right]}}=50000\cdot \dfrac{\mathrm{d}}{\mathrm{d}t}\left[\dfrac{1}{\frac{19t}{10}+9}\right]}[/tex]
[tex]=-50000\cdot\dfrac{d}{dt} \dfrac{\left[\frac{19t}{10}+9\right]}{\left(\frac{19t}{10}+9\right)^2}}}[/tex]
[tex]=\dfrac{-50000(1.9\frac{d}{dt}t+\frac{d}{dt}9)}{\left(\frac{19t}{10}+9\right)^2}}}[/tex]
[tex]=-\dfrac{95000}{\left(\frac{19t}{10}+9\right)^2}\\$Simplify/rewrite to obtain:$\\\\D'(t)=-\dfrac{9500000}{\left(19t+90\right)^2}[/tex]
Therefore, when t=115 days
[tex]D'(115)=-\dfrac{9500000}{\left(19(115)+90\right)^2}\\D'(115)=-1.8355[/tex]
A population of protozoa develops with a constant relative growth rate of 0.7944 per member per day. On day zero the population consists of two members. Find the population size after six days
Answer:
[tex] y =y_o e^{kt}[/tex]
Where [tex] y_o = 2[/tex] the relative growth is [tex] k =0.7944[/tex] and t represent the number of days.
For this case we can to find the population after the day 6 so then we need to replace t =6 in our model and we got:
[tex] y(6) =2 e^{0.7944*6} = 234.99 \approx 235[/tex]
And for this case we can conclude that the population of protozoa for the 6 day would be approximately 235
Step-by-step explanation:
We can assume that the following model can be used:
[tex] y =y_o e^{kt}[/tex]
Where [tex] y_o = 2[/tex] the relative growth is [tex] k =0.7944[/tex] and t represent the number of days.
For this case we can to find the population after the day 6 so then we need to replace t =6 in our model and we got:
[tex] y(6) =2 e^{0.7944*6} = 234.99 \approx 235[/tex]
And for this case we can conclude that the population of protozoa for the 6 day would be approximately 235