What do I do please help

Answer:

A. 336 ft²

Step-by-step explanation:

Add the sides: 6*8 + 6*12 + 12*8 + 10*12 = 336

One little trick: the area of the triangle sides is base times half height, i.e., 6*8/2, but since we have two of them you can just use 6*8!

Answer:

[tex](fof^{-1})(x)=x[/tex]

Step-by-step explanation:

Composition of two functions f(x) and g(x) is represented by,

(fog)(x) = f[g(x)]

If a function is,

f(x) = (-6x - 8)² [where x ≤ [tex]-\frac{8}{6}[/tex]]

Another function is the inverse of f(x),

[tex]f^{-1}(x)=-\frac{\sqrt{x}+8}{6}[/tex]

Now composite function of these functions will be,

[tex](fof^{-1})(x)=f[f^{-1}(x)][/tex]

                  = [tex][-6(\frac{\sqrt{x}+8}{6})-8]^{2}[/tex]

                  = [tex][-\sqrt{x}+8-8]^2[/tex]

                  = [tex](-\sqrt{x})^2[/tex]

                  = x

Therefore, [tex](fof^{-1})(x)=x[/tex]

Answer:

Option B

Step-by-step explanation:

With a scale factor of 1/2, the dilated shape should be smaller because of the scale factor, So in Option B the dilated shape is smaller than the real one.

1) Option A is an enlargement

2) Option B is reduction

3) Option C is equality

Answer:

I hope it will help you....

Answer:

The mean length of the 13 people's big finger is 15.45 cm

Step-by-step explanation:

Given;

mean length of 4 childrens' big finger, x' = 14cm

mean length of 9 adults' big finger is 16.1cm, x'' = 16.1cm

Let the total length of the 4 childrens' big finger = t

[tex]x' = \frac{t}{n} \\\\x' = \frac{t}{4}\\\\t = 4x'\\\\t = 4 *14\\\\t = 56 \ cm[/tex]

Let the total length of the 9 adults' big finger = T

[tex]x'' = \frac{T}{N} \\\\x'' = \frac{T}{9}\\\\T = 9x''\\\\T = 9*16.1\\\\T = 144.9 \ cm[/tex]

The total length of the 13 people's big finger = t + T

                                                                           = 56 + 144.9

                                                                            =200.9 cm

The mean length of these 13 people's big finger;

x''' = (200.9) / 13

x''' = 15.4539 cm

x''' = 15.45 cm (2 DP)

Therefore, the mean length of the 13 people's big finger is 15.45 cm

Answer:

Step-by-step explanation:

Solve 3x + 5y = 1 for y to obtain the slope of the given line:

5y = -3x + 1, or y = (-3/5)x + 1.

Any line perpendicular to this one has the slope which is the negative reciprocal of (-3/5):  That would be 5/3.

The desired line has slope 5/3 and passes through (2, 7);

Adapt y = mx + b by substituting the known values, to find b:

7 = (5/3)(2) + b.  The LCD is 3, so multiply each term by 3 to eliminate the fractional coefficient:

21 = 10 + 3b, or 11 = 3b.  Then b = 11/3, and the desired equation in slope intercept form is

y = (5/3)x + 11/3

To obtain the standard form, multiply all three terms by 3 again:

3y = 5x + 11, or

5x + 11 - 3y = 0, or

5x - 3y + 11 = 0

Answer:

sin(B) = cos(90 - B).

Step-by-step explanation:

To answer this question, you must understand SOH CAH TOA.

SOH = Sine; Opposite divided by Hypotenuse

CAH = Cosine; Adjacent divided by Hypotenuse

TOA = Tangent; Opposite divided by Adjacent

I roughly drew a triangle for reference. Let's say we have a 3-4-5 triangle.

As you can see, sin(b) does not equal sin(a). To get the sine of an angle, you would do opposite over hypotenuse. For angle B, that would be 3/5, while for angle A, that would be 4/5.

As stated above, sin(B) is 3/5. Now, if you did cos(90 - B), it would be the same thing as cos(A). This is because the triangle is a right triangle. Since a triangle has 180 degrees, and one angle is a right triangle, the other two angles will add up to be 90 degrees. So, 90 - B = A. cos(A) is the same thing as adjacent over hypotenuse, which is 3/5. So, sin(B) = cos(90 - B) must be true.

Let's just check the others to make sure they are false.

cos(B) = 4/5.

sin(180 - B) is basically the same thing as sin(A + C), which is definitely NOT 4/5.

cos(B) = 4/5, which is NOT the same as A.

So, your answer is sin(B) = cos(90 - B).

Hope this helps!

Answer:

9x-3 or 3(3x-1)

Step-by-step explanation:

A triangle has three sides. To find the perimeter, add those side lengths together.

3x-3+(4x-1)+(2x+1)

Add your common terms (xs and constants) together.

3x+4x+2x=9x

-1+-3+1=-3

9x-3

If you want to, you can factor the expression.

3(3x-1)

Answer:

9x - 3

Step-by-step explanation:

The perimeter is all the sides added together.

4x - 1 + 2x + 1 + 3x - 3

Rearrange.

4x + 2x + 3x - 1 + 1 - 3

Combine like terms.

9x - 3

Answer:

  (4.4, 4.4)

Step-by-step explanation:

The point S can be found as the weighted average of the end points. The relative weights are the reverse of the distances to the end points:

  RS : ST = 1 : 4

  S = (4R +1T)/5

  S = (4(2, 2) +(14, 14))/5 = (22, 22)/5

  S = (4.4, 4.4)

Answer:

choice c

Step-by-step explanation:

y axis shows value of computer

v-intercept; x axis = 0

show initial value of the computer

Answer: 1,2,3,4

Step-by-step explanation:

The domain consists of every x value

Answer:

no

Step-by-step explanation:

Answer:

No is the answer you are welcome

Answer:

40/100 = 0.4

your welcome

Step-by-step explanation:

Total letters = 11

Probability of letter M = 2/11

Probability of second M = 1/10

Answer:

40 km away.

Step-by-step explanation:

a^2 + b^2 = c^2

In this case, a = 16 * 2 = 32 km, since he travels 16 km per hour for 2 hours.

b = 12 * 2 = 24 km, since she travels 12 km per hour for 2 hours.

32^2 + 24^2 = c^2

1,024 + 576 = c^2

1600 = c^2

c^2 = 1600

c = plus or minus 40

Since distance cannot be negative, they will be 40 km away.

Hope this helps!

The required, after 2 hours, Rachel and Amos will be 40 kilometers apart.

In a right-angled triangle, its sides, such as hypotenuse, and perpendicular, and the base is Pythagorean triplets.

Here,

We can use the Pythagorean theorem to solve this problem. After 2 hours, Rachel will have traveled 24 kilometers (12 km/hour x 2 hours) due east, and Amos will have traveled 32 kilometers (16 km/hour x 2 hours) due north. Let's call the distance between them after 2 hours "d".

Using the Pythagorean theorem, we can write:

d² = (24 km)²+ (32 km)²

Simplifying this expression:

d² = 576 km² + 1024 km²

d² = 1600 km²

Taking the square root of both sides,

d = 40 km

Therefore, after 2 hours, Rachel and Amos will be 40 kilometers apart.

Learn more about Pythagorean triplets here:

brainly.com/question/22160915

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Distribute the sum:

[tex]\displaystyle\sum_{i=1}^{24}(3i-2)=3\sum_{i=1}^{24}i-2\sum_{i=1}^{24}1[/tex]

Use the following formulas:

[tex]\displaystyle\sum_{i=1}^n1=n[/tex]

[tex]\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2[/tex]

[tex]\implies\displaystyle\sum_{i=1}^{24}(3i-2)=3\cdot\frac{24\cdot25}2-2\cdot24=\boxed{852}[/tex]

In case you don't know where those formulas came from:

The first one is obvious; you're just adding n copies of 1, so 1 + 1 + ... + 1 = n.

The second can be proved in this way: let S be the sum 1 + 2 + 3 + ... + n. Rearrange it as S = n + (n - 1) + (n - 2) + ... + 1. Then 2S = (n + 1) + (n + 1) + (n + 1) + ... + (n + 1), or n copies of n + 1. So 2S = n(n + 1). Divide both sides by 2 and we're done.

Answer:

e)  (3.77%, 8.70%)

95% confidence interval for the percentage of all medical students who plan to work in a rural community

(3.83% , 8.69%)

95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices

(0.406 , 0.454)

Step-by-step explanation:

Step(i):-

Given random sample size 'n' = 369

Sample proportion

                              [tex]p = \frac{x}{n} = \frac{23}{369} = 0.0623[/tex]

95% confidence intervals are determined by

[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]

[tex](0.0623 - 1.96 \sqrt{\frac{0.0623(1-0.0623)}{369} } , 0.0623 + 1.96\sqrt{\frac{0.0623(1-0.0623)}{369} })[/tex]

(0.0623 - 0.0246 , 0.0623 + 0.0246)

(0.0383 , 0.0869)

(3.83% , 8.69%)

95% confidence interval for the percentage of all medical students who plan to work in a rural community

(3.83% , 8.69%)

Step(ii):-

Given 43% of those polled blamed of companies the most for the recent increase in gasoline prices

sample proportion 'p' = 0.43

Given Margin of error (M.E) = 0.024

95% confidence intervals are determined by

[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]

[tex](0.43 - 0.024 } , 0.43 +0.024 )[/tex]

(0.406 , 0.454)

Final answer:-

95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices

(0.406 , 0.454)

Answer:

63m

Step-by-step explanation:

Answer:

Hey there!

You can use the ASA postulate, when two angles are congruent, and one side is congruent.

Hope this helps :)

Answer:

[tex]m\angle 2=53^{\circ}[/tex]

[tex]m\angle 7=74^{\circ}[/tex]

Step-by-step explanation:

It is given that quadrilateral GHJK is a rectangle and [tex]n\angle 3=37^{\circ}[/tex].

All interior angles of a rectangle are right angles. Diagonals are equal and bisect each other.

Now,

[tex]m\angle HKJ+m\angle HKG=90^{\circ}[/tex]    (Interior angles of a rectangle are right angles)

[tex]m\angle 3+m\angle HKG=90^{\circ}[/tex]

[tex]37^{\circ}+m\angle HKG=90^{\circ}[/tex]

[tex]m\angle HKG=90^{\circ}-37^{\circ}[/tex]

[tex]m\angle HKG=53^{\circ}[/tex]

In an isosceles triangle, angle with equal sides are equal.

[tex]m\angle JGK=m\angle HKG[/tex]

[tex]m\angle 2=53^{\circ}[/tex]

Therefore, measure of angle 2 is 53 degrees.

Let the diagonals intersect each other at point O.

In triangle OGK,

[tex]m\angle OGK+m\angle OKG+m\angle GOK=180^{\circ}[/tex]    (Angle su property)

[tex]53^{\circ}+53^{\circ}+m\angle GOK=180^{\circ}[/tex]

[tex]106^{\circ}+m\angle GOK=180^{\circ}[/tex]

[tex]m\angle GOK=180^{\circ}-106^{\circ}=74^{\circ}[/tex]

Vertical opposite angles are equal. So,

[tex]m\angle 7=74^{\circ}[/tex]

Therefore, measure of angle 7 is 74 degrees.

Answer:

y = 10 - 0.5x for 0 ≤  x ≤ 20

Step-by-step explanation:

Initial value = (0,10)

final value = (20,0)

Cost per trip = debit of 0.50 = slope

equation : y = 10 - 0.5x for 0 <=  x <= 20

Answer: B

Step-by-step explanation: In algebra, we use the word slope to describe how steep a line is and slope can be found using the ratio rise/run between any two points that are on that line.

Answer:

living organism

Step-by-step explanation:

soil particals and decad crops living organism

Step-by-step explanation:

great circle = 9[tex]\pi[/tex] = r^2.[tex]\pi[/tex] --> r = 3 m

Surface area S = 4[tex]\pi[/tex].r^2 = 36[tex]\pi[/tex] m^2

Volume V = 4/3[tex]\pi[/tex].r^3 = 36[tex]\pi[/tex] m^3

The volume of a sphere is 36π m³ and the Surface area of sphere 36π m². Therefore, option A is the correct answer.

The volume of sphere is the measure of space that can be occupied by a sphere.  If the radius of the sphere formed is r and the volume of the sphere is V. Then, the volume of the sphere is given by: Volume of Sphere, V = (4/3)πr³

Given that, sphere with great circle area 9π m².

We know that, area of a circle = πr²

Now, πr²=9π m²

r=3 m

Here, volume of a sphere = 4/3 ×π×3³

= 36π m³

Surface area of sphere = A = 4πr²

= 4×π×3²

= 36π m²

Therefore, option A is the correct answer.

To learn more about the volume of a sphere visit:

https://brainly.com/question/9994313.

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Answer:

The answer is option A.

Hope this helps you

Answer:

A, B, and E are all less than 1/8

Answer:

a) Probability that haul time will be at least 10 min = P(X ≥ 10) ≈ P(X > 10) = 0.0455

b) Probability that haul time be exceed 15 min = P(X > 15) = 0.000

c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10) = 0.6460

d) The value of c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)

c = 2.12

e) If four haul times are independently selected, the probability that at least one of them exceeds 10 min = 0.1700

Step-by-step explanation:

This is a normal distribution problem with

Mean = μ = 8.46 min

Standard deviation = σ = 0.913 min

a) Probability that haul time will be at least 10 min = P(X ≥ 10)

We first normalize/standardize 10 minutes

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69

To determine the required probability

P(X ≥ 10) = P(z ≥ 1.69)

We'll use data from the normal distribution table for these probabilities

P(X ≥ 10) = P(z ≥ 1.69) = 1 - (z < 1.69)

= 1 - 0.95449 = 0.04551

The probability that the haul time will exceed 10 min is approximately the same as the probability that the haul time will be at least 10 mins = 0.0455

b) Probability that haul time will exceed 15 min = P(X > 15)

We first normalize 15 minutes.

z = (x - μ)/σ = (15 - 8.46)/0.913 = 7.16

To determine the required probability

P(X > 15) = P(z > 7.16)

We'll use data from the normal distribution table for these probabilities

P(X > 15) = P(z > 7.16) = 1 - (z ≤ 7.16)

= 1 - 1.000 = 0.000

c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10)

We normalize or standardize 8 and 10 minutes

For 8 minutes

z = (x - μ)/σ = (8 - 8.46)/0.913 = -0.50

For 10 minutes

z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69

The required probability

P(8 < X < 10) = P(-0.50 < z < 1.69)

We'll use data from the normal distribution table for these probabilities

P(8 < X < 10) = P(-0.50 < z < 1.69)

= P(z < 1.69) - P(z < -0.50)

= 0.95449 - 0.30854

= 0.64595 = 0.6460 to 4 d.p.

d) What value c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)?

98% of the haul times in the middle of the distribution will have a lower limit greater than only the bottom 1% of the distribution and the upper limit will be lesser than the top 1% of the distribution but greater than 99% of fhe distribution.

Let the lower limit be x'

Let the upper limit be x"

P(x' < X < x") = 0.98

P(X < x') = 0.01

P(X < x") = 0.99

Let the corresponding z-scores for the lower and upper limit be z' and z"

P(X < x') = P(z < z') = 0.01

P(X < x") = P(z < z") = 0.99

Using the normal distribution tables

z' = -2.326

z" = 2.326

z' = (x' - μ)/σ

-2.326 = (x' - 8.46)/0.913

x' = (-2.326×0.913) + 8.46 = -2.123638 + 8.46 = 6.336362 = 6.34

z" = (x" - μ)/σ

2.326 = (x" - 8.46)/0.913

x" = (2.326×0.913) + 8.46 = 2.123638 + 8.46 = 10.583638 = 10.58

Therefore, P(6.34 < X < 10.58) = 98%

8.46 - c = 6.34

8.46 + c = 10.58

c = 2.12

e) If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?

This is a binomial distribution problem because:

- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (4 haul times are independently selected)

- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (Only 4 haul times are selected)

- The outcome of each trial/run of a binomial experiment is independent of one another. (The probability that each haul time exceeds 10 minutes = 0.0455)

Probability that at least one of them exceeds 10 mins = P(X ≥ 1)

= P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

= 1 - P(X = 0)

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 4 haul times are independently selected

x = Number of successes required = 0

p = probability of success = probability that each haul time exceeds 10 minutes = 0.0455

q = probability of failure = probability that each haul time does NOT exceeds 10 minutes = 1 - p = 1 - 0.0455 = 0.9545

P(X = 0) = ⁴C₀ (0.0455)⁰ (0.9545)⁴⁻⁰ = 0.83004900044

P(X ≥ 1) = 1 - P(X = 0)

= 1 - 0.83004900044 = 0.16995099956 = 0.1700

Hope this Helps!!!

Answer:

1. 4/5

2. 80%

Step-by-step explanation:

Answer:

[tex]\boxed{\mathrm{view \: attachment}}[/tex]

Step-by-step explanation:

The zeros of a function is where the function crosses the x-axis. The x-intercepts are the zeros of a function.

[tex]f(x) = (x - 1)(x - 7)[/tex]

Let output equal to 0.

[tex]0 = (x - 1)(x - 7)[/tex]

Set factors equal to 0.

[tex]x-1=0\\x=1[/tex]

[tex]x-7=0\\x=7[/tex]

The zeros of the function are [tex]x=1[/tex] and [tex]x=7[/tex].

Answer:

Step-by-step explanation:

Hope this Helps ;)

Answer:

$261,500

Step-by-step explanation:

What amount should Nash report as its December 31 inventory?

Item                                                             Amount

Goods on hand as per physical count    $208,000

(+) Goods purchased from Swifty             $30,000

Corporation FOB shipping point    

(+) Goods sold to Marigold Corp               $23,500

FOB destination (at cost value)

Ending inventory                                        $261,500

Notes:

1) In case of FOB shipping point, the ownership of goods is transferred to the buyer when the goods are shipped and hence in the case of purchases from Swifty corporation, the goods should be included in the inventory of Nash's Trading Post as the goods are shipped and are in transit.

2) In case of FOB destination, the ownership of goods is transferred to the buyer when the goods reaches to the buyer, hence in the case of sales made to Marigold Corp, the goods are still in transit and the ownership is not transferred to Marigold Corp, hence Nash's Trading Post should included that goods in its inventory.