The volume of 3.5 lb of titanium is 21.47 in³.
The density of titanium is 4.51 g/cm³.The weight of titanium is 3.5 lb.
Formula used:
Density, D = M/V, where D is density, M is mass, and V is volume.
The conversion factor of 1 inch³ = 16.39 cm³.1 lb = 453.592 g.
First, we will calculate the mass of titanium.
3.5 lb = 3.5 × 453.592 g
= 1587.772 g
Next, we will calculate the volume of titanium.
Volume of titanium = Mass of titanium / Density of titanium
= 1587.772 g / 4.51 g/cm³
= 352.044 cm³
Next, we will convert the volume from cm³ to in³.
1 inch³ = 16.39 cm³.
Volume of titanium in in³ = Volume of titanium / 16.39
= 352.044 cm³ / 16.39
= 21.47 in³
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A compound consisting of carbon and hydrogen consists of 67.90%
carbon by mass. If the compound is measure to have a mass of 37.897
Mg, how many grams of hydrogen are present in the compound?
Given that the compound consists of 67.90% carbon by mass and has a total mass of 37.897 Mg, we can calculate the mass of hydrogen in the compound.
Let's assume the mass percentage of hydrogen in the compound is denoted by "y." According to the law of constant composition, the sum of the mass percentages of carbon and hydrogen is equal to 100.
Mass% of Carbon + Mass% of Hydrogen = 100
Since the mass percentage of carbon is 67.90%, we can calculate the mass percentage of hydrogen as follows:
Mass% of Hydrogen = 100 - 67.9
Mass% of Hydrogen = 32.1
Therefore, the compound contains 32.1% of hydrogen by mass.
Next, we can calculate the mass of hydrogen present in the compound using the following formula:
Mass of hydrogen = Percentage of hydrogen x Total mass of the compound / 100
Substituting the given values, we find:
Mass of hydrogen = 32.1 x 37.897 Mg / 100
Now, we need to convert the mass from megagrams (Mg) to grams:
Mass of hydrogen = 32.1 x 37.897 Mg x 10^6 g / 100
Calculating this expression, we find:
Mass of hydrogen = 12.159 grams
There are 12.159 grams of hydrogen present in the compound.
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