Answer:
h = [tex](\frac{m}{m+M} )^2 \ \frac{v_o^2}{2g}[/tex]
Explanation:
To solve this problem, let's work in parts, let's start with the conservation of the moment, for this we define a system formed by the block and the bullet, in such a way that the forces during the collision have been internal and the moment is conserved.
initial instant. Before the crash
p₀ = m v₀
final instant. Right after the crash, but before the pendulum started to climb
m_f = (m + M) v
the moment is preserved
p₀ = p_f
m v₀ = (m + M) v
v = [tex]\frac{m}{m+M} \ v_o[/tex]
Now we work the pendulum system with embedded block, we use the concept of conservation of energy
starting point. Lower
Em₀ = K = ½ (m + M) v²
final point. higher, when it stops
Em_f = U = (m + M) g h
as there is no friction, energy is conserved
Em₀ = Em_f
½ (m + M) v² = (m + M) g h
h = [tex]\frac{v^2}{2g}[/tex]
we substitute the speed value of the block plus bullet set
h = [tex]( \frac{m}{ m+M} \ v_o )^2 \ \frac{1}{2g}[/tex]
h = [tex](\frac{m}{m+M} )^2 \ \frac{v_o^2}{2g}[/tex]
Read the following statements. Which statement provides the correct definition of weather? Select your answer from the options below. * 1 point
Atmospheric conditions at a specific time in a specific area
Atmospheric conditions over a period of time in a specific area
Average atmospheric conditions over a period of time in a region
Average atmospheric conditions across the world
Answer:
In one day, a store sells 14 pairs of jeans. The 14 jeans represent 20% of the total number of items sold that day. How many items did the store sell in one day? Explain or show how you got your answer.
plz help with the qsn
Explanation:
A 95-kg astronaut is stranded from his space shuttle. He throws a 2-kg hammer away from the shuttle with a velocity of 19 m/s. How fast will he be propelled toward the shuttle, in m/s? (Round your answer to one decimal place if necessary.)
Answer:
The astronaut will be propelled towards the shuttle at the rate of 0.4 m/s.
Explanation:
Given;
mass of the astronaut, m₁ = 95 kg
mass of the hammer thrown, m₂ = 2 kg
velocity of the hammer, v₂ = 19 m/s
let the recoil velocity of the shuttle = v₁
Apply the principle of conservation of linear momentum;
m₁v₁ = m₂v₂
v₁ = m₂v₂/m₁
v₁ = (2 x 19) / 95
v₁ = 0.4 m/s
Therefore, the astronaut will be propelled towards the shuttle at the rate of 0.4 m/s.
Evaluate for f(-4)
F(x) =3x2 -5 +7
Answer: -4f=8
Explanation:
The graph shows the range of frequencies commonly heard by some animals. A graph with frequency in Hertz on the axis from 0 to 100, 000. On the y axis are porpoise, bat, moth, cat, human, bird, fish, cricket and snake. Porpoise is 60 to 105,000 Hertz. Bat is 55 to 100,000 Hertz. Moth is 250 to 100,000 Hertz. Cat is 60 to 80, 000 Hertz. Human is 20 to 12,000 Hertz. Bird is 65 to 9000 Hertz. Fish is 80 to 2000 Hertz. Cricket is 55 to 1,000 Hertz. Lastly snake is 100 to 1000 Hertz. Which animals can hear a sound wave that has 18,500 cycles in 0.75 seconds? Check all that apply. bats moths cats humans birds fish crickets
Answer:A,B,C or you could say bats, moths, cats
Explanation:
Trust me i got you, i promise u gonna get the answer right
The animals that can hear a sound wave that has 18,500 cycles in 0.75 seconds are bats, moths and cats.
What is frequency?It is the number of oscillations per second of the sinusoidal wave.
The graph shows the range of frequencies commonly heard by some animals. A graph with frequency in Hertz on the axis from 0 to 100, 000. On the y axis are porpoise, bat, moth, cat, human, bird, fish, cricket and snake.
Porpoise is 60 to 105,000 Hertz.
Bat is 55 to 100,000 Hertz.
Moth is 250 to 100,000 Hertz.
Cat is 60 to 80, 000 Hertz.
Human is 20 to 12,000 Hertz.
Bird is 65 to 9000 Hertz.
Fish is 80 to 2000 Hertz.
Cricket is 55 to 1,000 Hertz.
Snake is 100 to 1000 Hertz.
Thus, the animals that can hear a sound wave that has 18,500 cycles in 0.75 seconds are bats, moths and cats.
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.HOW DOES PHYSICAL EDUCATION BENEFIT YOUR EMOTIONAL HEALTH ?
Answer: reduce anxiety, depression, and negative mood and by improving self-esteem and cognitive function.
Explanation:
A 70 kg bicyclist rides his 9.8 kg bicycle with a speed
of 16 m/s.
How much work must be done by the brakes to bring the bike and rider to a stop?
Hello,
QUESTION)✔ We have Ek = 1/2m x v²
Ek = 1/2 x 79.8 x 16²Ek = 10 214.4 JIn order to come to a complete stop, the cyclist must convert all his kinetic energy into thermal energy. Given that the braking force opposes movement, the work is therefore resistant, i.e. W = -10 214.4 J.
A 64-kg skater initially at rest throws a 4.0-kg medicine ball horizontally to the left. Suppose the ball is accelerated through a distance of 1.0 mm before leaving the skater's hand at a speed of 7.0 m/s. Assume the skater and the ball to be point-like and the surface to be frictionless and ignore air resistance. Use a vertical y-axis with the positive direction pointing up and a horizontal x-axis with the positive direction pointing to the right.
Required:
a. Determine the acceleration of the ball during the throw.
b. Determine the acceleration of the skater during the throw.
Answer:
yeah
Explanation:
Solved: Problem 2.41 A 64-kg Skater Initially At Rest Thro ...www.chegg.com › ... › physics questions and answers
Suppose The Ball Is Accelerated Through A Distance Of 1.0 M Before Leaving The Skater's Hand At A Speed Of 7.0 M/s . Assume The Skater And The Ball To Be Point-like, The Surface To Be Frictionless, And Ignore Air Resistance. Use A ... A 64-kg skater initially at rest throws a 5.0-kg medicine ball horizontally to the left
1.Briefly describe the wind motion of the stationary front
.
2.What is another name for stationary front.
Answer:
stationary front is when it is not moving that is why weather is the same in some areas
Explanation:quasi-stationary front
A light string is wrapped around the edge of the smaller disk, and a 1.50 kgkg block is suspended from the free end of the string. If the block is released from rest at a distance of 2.40 mm above the floor, what is its speed just before it strikes the floor
Answer:
The speed of the block before it strikes the floor is 0.217 m/s.
Explanation:
Given;
mass of the block, m = 1.5 kg
height above the ground through the block was released, h = 2.4 mm = 2.4 x 10⁻³ m
The speed of the block before it strikes the floor will be maximum.
Let the speed of the block before it strikes the floor = v
Apply the principle of conservation of mechanical energy to determine the speed of the block.
K.E = P.E
¹/₂mv² = mgh
¹/₂v² = gh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 2.4 x 10⁻³)
v = 0.217 m/s
Therefore, the speed of the block before it strikes the floor is 0.217 m/s.
Which of the following situations would cause the greatest decrease in the
motion of molecules in a system?
A
Explanation:
hindi ako sure kung tama ba yan
3. How much work is necessary to lift 10 kg 5m in the air?
1) 10N
3) 490 J
2) 50 J
4) 4900 J
Answer:
I'm not 100 percent sure but I have had a question very similar to this and I think 2.)50 j
A 100 W engine generates 1000 J of energy. How long did it run for?
A. 1 s
B. 10 s
C. 5 s
D. 100 s
Answer:
B. 10 s
Explanation:
Given the following data;
Power = 100 Watts
Energy = 1000 Joules
To find the time;
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
[tex] Power = \frac {Energy}{time} [/tex]
Making time the subject of formula, we have;
[tex] Time = \frac {Energy}{Power} [/tex]
Substituting into the formula, we have;
[tex] Time = \frac {1000}{100} [/tex]
Time = 10 seconds
To determine the pressure in a fluid at a given depth with the air-filled cartesian diver, we can employ Boyle's law, which states that the pressure in an ideal gas (held at constant temperature) is inversely proportional to its volume. At a fluid's surface, the pressure of the fluid is the same as the pressure of the atmosphere just above it, which we'll denote as LaTeX: P_{atm}P a t m. If the volume of air, which can be treated as an ideal gas here, in the cartesian diver decreases by 19% as it is lowered to a specific depth in the fluid, the pressure of the fluid at this depth, in terms of atmospheric pressure, is
Answer:
The pressure at this depth is [tex]1.235\cdot P_{atm}[/tex].
Explanation:
According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:
[tex]\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}[/tex] (1)
Where:
[tex]V_{1}, V_{2}[/tex] - Initial and final volume.
[tex]P_{1}, P_{2}[/tex] - Initial and final pressure.
If we know that [tex]V_{2} = 0.81\cdot V_{1}[/tex], then the pressure ratio is:
[tex]\frac{P_{2}}{P_{1}} = 1.235[/tex]
If [tex]P_{1} = P_{atm}[/tex], then the final pressure of the gas is:
[tex]P_{2} = 1.235\cdot P_{atm}[/tex]
The pressure at this depth is [tex]1.235\cdot P_{atm}[/tex].
The pressure of the fluid at this depth will be "1.16 [tex]P_{atm}[/tex]".
Pressure and VolumeAccording to the question,
Let,
The volume of surface be "100 units".
then,
The volume of depth be:
= 100 - 14
= 86 units
We know the relation,
P ∝ [tex]\frac{1}{V}[/tex]
here, PV = Constant
By using Boyle's law,
→ P₁ V₁ = P₂ V₂
or,
→ P₂ = [tex]\frac{P_1 V_1}{V_2}[/tex]
By substituting the values, we get
= [tex]\frac{P_{atm}\times 100}{86}[/tex]
= 1.16 [tex]P_{atm}[/tex]
Thus the above answer is appropriate.
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Which DOES NOT happen during the phase change from liquid to solid?
Kinetic energy decreases
Particles move slower
Freezing occurs
Temperature increases
Answer:
Temperature increases
During the phase transition from liquid to solid, kinetic energy diminishes, particles move slower, and freezing occurs.
Phase change:Extreme heat is more likely to occur as a result of rising temperatures, and it will last longer. Heatwaves can indeed be deadly, resulting in manifestations including heat kinks and heat exhaustion, as well as death.
Warmer temperatures have the potential to trigger a cascade of other changes around the world.The greenhouse effect is worsened by these gas emissions, which cause the earth's crust temperature to rise. Burning fossil fuels has the greatest impact on climate change of any human activity.Since in changement from liquid to solid the temperature will decrease.Therefore, the final answer is "Temperature increases".
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A still ball of mass 0.514kg is fastened to a cord 68.7cm long and is released when the cord is horizontal. At the bottom of its path, the ball strikes a 2.63kg steel block at rest on a horizontal frictionless surface. On collision, one-half the kinetic energy is converted to internal energy. Find the final speeds.
Answer:
1.21 m/s
Explanation:
From the law of conservation of energy,
U₁ + K₁ + E₁ = U₂ + K₂ + E₂
where U₁ = initial potential energy of system =initial potential energy of still ball = mgh where m = mass of still ball = 0.514 kg, g = acceleration due to gravity = 9.8 m/s² and h = height = length of cord = 68.7 cm = 0.687 m.
K₁ = initial kinetic energy of system = 0
E₁ = initial internal energy of system = unknown and
U₂ = final potential energy of system = 0
K₁ = final kinetic energy of system = final kinetic energy of ball + steel block = 1/2(m + M)v² where m = mass of still ball, M = mass of steel block = 2.63 kg and v = speed of still ball + steel block
E₁ = final internal energy of system = unknown
So,
U₁ + K₁ + E₁ = U₂ + K₂ + E₂
mgh + 0 + E₁ = 0 + 1/2(m + M)v² + E₂
mgh = 1/2(m + M)v² + (E₂ - E₁)
Given that (E₂ - E₁) = change in internal energy = ΔE = 1/2ΔK where ΔK = change in kinetic energy. So, ΔE = 1/2ΔK = 1/2(K₂ - K₁) = K₂/2 = 1/2(m + M)v²/2 = (m + M)v²/4
Thus, mgh = 1/2(m + M)v² + (E₂ - E₁)
mgh = 1/2(m + M)v² + (m + M)v²/4
mgh = 3(m + M)v²/4
So, making v subject of the formula, we have
v² = 4mgh/3(m + M)
taking square root of both sides, we have
v = √[4mgh/3(m + M)]
Substituting the values of the variables into the equation, we have
v = √[4 × 0.514 kg × 9.8 m/s² × 0.687 m/{3(0.514 kg + 2.63 kg)}]
v = √[13.8422/{3(3.144 kg)}]
v = √[13.8422 kgm/s²/{9.432 kg)}]
v = √(1.4676 m²/s²)
v = 1.21 m/s
The final speed of the given ball law of conservation of energy. The final speed of the given ball is 1.21 m/s.
The law of conservation of energy,
U₁ + K₁ + E₁ = U₂ + K₂ + E₂
where
U₁ = initial potential energy
K₁ = initial kinetic energy
E₁ = initial internal energy
U₂ = final potential energy
K₁ = final kinetic energy
E₁ = final internal energy
So,
mgh + 0 + E₁ = 0 + 1/2(m + M)v² + E₂
mgh = 1/2(m + M)v² + (E₂ - E₁)
Given that (E₂ - E₁) = change in internal energy,
ΔE = 1/2ΔK
Where
ΔK = change in kinetic energy.
So,
ΔE = 1/2ΔK = 1/2(K₂ - K₁)
ΔE = K₂/2
ΔE = 1/2(m + M)v²/2
ΔE = (m + M)v²/4
Thus,
mgh = 1/2(m + M)v² + (E₂ - E₁)
mgh = 1/2(m + M)v² + (m + M)v²/4
mgh = 3(m + M)v²/4
v² = 4mgh/3(m + M)
Take square root of both sides,
v = √[4mgh/3(m + M)
put the values in the formula,
v = √[4 × 0.514 kg × 9.8 m/s² × 0.687 m/3(0.514 kg + 2.63 kg)
v = 1.21 m/s
Therefore, the final speed of the given ball is 1.21 m/s.
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A continental polar air mass forms in
a. the Pacific Ocean.
b. northern Canada.
c.
the Gulf of Mexico.
the desert Southwest.
d.
Please select the best answer from the choices provided
А
B
ОООО
С
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my uq xbbbnxnjjxjxusjhhhwhhhnn he c x. Yes suhsjjdhhehy yes eirui
M I was going ask m
Iqijjm.ndjbh
Answer:
B. Northern Canada
Explanation:
A continental polar air mass can form over the land during the winter months. In the Northern Hemisphere, it originates in northern Canada or Alaska. As it moves southward, it brings dry weather conditions to the United States. Temperature and humidity levels are both low. Hope this helps :)
Select the correct answer.
In general, how does an increase in distance from the Sun affect a planet?
ОА. .
The amount of sunlight the planet receives decreases.
OB.
The gravitational force exerted by the Sun increases.
ОС.
The thickness of a planet's atmosphere increases.
OD. The planet's atmosphere absorbs more heat.
Answer:
a.
gravity decreases by distance
thickness doesn't change
Less heat.
A closed pipe creates a fifth
harmonic frequency of 125 Hz.
What is the next lower frequency
that will create a standing wave in
the pipe?
(Speed of sound = 343 m/s)
(Unit = Hz)
PLEASE HELP QUICKLY, WILL GIVE BRAINLIEST
Answer:
75 hz
Explanation:
Trust
The next frequency will be 75.0 Hertz
Wait, how do you know if it is correct?!
Well, it is correct for Acellus:)
Try it in other schools/academies:)
explain why radiation is dangerous for humans
Answer:
because it affects the attom in living things
Two adjacent students stand on stationary skateboards, face each other, and
push apart. The skateboarder on the left weighs 55 kg, the one on the right is
65 kg. If the lighter skateboarder moves at 4.2 m/s, determine the speed and
direction of the heavier skateboarder.
uppose that white light strikes a flat piece of flint glass in air, coming in at an angle of 60 degrees to the surface (30 degrees from the normal or perpendicular). The index of refraction of this dense glass for red light is 1.710, for green light is 1.723, and for blue light is 1.735. What is the order of colors you would see in the refracted light inside the glass as they leave the surface
Answer:
Explanation:
Snell's law for index of refraction of a medium is as follows .
sin i / sin r = μ
i is angle of incidence , r is angle of refraction and μ is refractive index.
sin r = sin i / μ .
As μ for blue light is greatest , angle of refraction for blue light will be least . Similarly , angle of refraction will be maximum for red light .
So maximum deviation in the direction of light will occur in blue light due to least angle of refraction because
deviation angle = angle of incidence - angle of refraction .
So the order of light from inward towards surface
= blue , green , red .
Most stars are _____ compared to the sun.
slightly smaller
much bigger
much smaller
slightly bigger
Help me with both questions please?
Answer:
1. They all accelerate at the same rate.
2.The object travels at a constant velocity throughout the fall.
Explanation:
Earths gravitational pull is at a constant 9.08 m/s^2. so when objects are free falling, the objects in question can only fall so fast before it would break gravity so to speak.
A 2000-kg elevator is at rest when its cable breaks. The elevator falls 26 m before it encounters a giant spring at the bottom of the elevator shaft. As the elevator falls, its safety clamp applies a constant frictional force of 17,000 N. 1. List all the forces acting on the elevator after the cable breaks but before it hits the spring. Determine the work done by each force on the elevator. Make sure these work terms have the appropriate signs (positive or negative). 2. Calculate the net work done on the elevator. 3. Use the work-kinetic-energy theorem to determine the speed of the elevator right before it encounters the spring. 4. After the elevator encounters the spring, the spring compresses by 0.6 m before the elevator comes to rest. The safety clamp continues to apply a constant 17,000 N force. List all the forces acting on the elevator while it falls this final 0.6 m. 5. For each force listed in question F4, determine an expression for the work it does on the elevator. Make sure each work term has the appropriate sign (positive or negative). 6. Use the work-kinetic-energy theorem to determine the value of the spring constant k.
Explanation:
work done =force *distance
work done =17000*26
work done=442,000 joules.
In the “Elastic Collision" part of this activity, what happened to the momentum of the red cart after the collision? What happened to the momentum of the blue cart after the collision?
Explanation:
Elastic collision between balls of equal mass viimis 1.5 mys 1.5m/s 1! mis ... Make a data table for the following: mass, velocity and momentum of each ball before ... Part 2 moving faster. ... Summary: Describe the main ideas learned in this activity regarding initial and ... Collision 2: Blue Cart Moving Slower than the Red Cart.
Oil having a density of 926 kg/m3 floats on water. A rectangular block of wood 3.69 cm high and with a density of 974 kg/m3 floats partly in the oil and partly in the water. The oil completely covers the block. How far below the interface between the two liquids is the bottom of the block
Answer:
the position of the wood below the interface of the two liquids is 2.39 cm.
Explanation:
Given;
density of oil, [tex]\rho _o[/tex] = 926 kg/m³
density of the wood, [tex]\rho _{wood}[/tex] = 974 kg/m³
density of water, [tex]\rho _w[/tex] = 1000 kg/m³
height of the wood, h = 3.69 cm
Based on the density of the wood, it will position across the two liquids.
let the position of the wood below the interface of the two liquids = x
Let the wood be in equilibrium position;
[tex]F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood} -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood} -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm[/tex]
Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.
Sound waves rely on matter to transmit their energy. They cannot ravel in a vacuum. True or false
Answer:
false
Explanation:
Hello,
QUESTION)True,Sound travels in a material medium, in space, there is no matter, so sound cannot propagate.
12. Which of the following observations provides the best evidence for the claim that gravity acts between
objects across a distance?
A. Heavier objects have more gravity acting on them
B. The moon orbits Earth due to a gravitational field
C. An object at rest on the ground doesn't respond to gravity
D. Objects float freely in space where there is no gravity
The moon orbits Earth due to a gravitational field. This observations provides the best evidence for the claim that gravity acts between objects across a distance.
What is the Universal Law of Gravitation?According to Newton's Law of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is directly proportional to the product of their masses and inversely proportional to their distance from one another.
The moon orbits Earth due to a gravitational field of the earth. Gravity, an attraction force that acts on all objects, keeps the Moon in its orbit. Satellites can orbit a body and fall around it rather than into it if the speed and gravity are just right. Hence, option (B) is correct.
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A person holds a gallon of milk with a mass of 3 kg away from their body so that their forearm is completely parallel with the ground. The length of the forearm is .38 meters. The biceps brachii attaches to the forearm 4 cm from the elbow at an angle of 60 deg. How much force must be exerted by the bicep in order to keep the forearm level while holding the milk
Answer:
"322.5 N" is the appropriate solution.
Explanation:
The given values are:
Mass,
m = 3 kg
Length of forearm,
= .38 meters
Angle,
= 60°
As we know,
⇒ [tex]FSin60^{\circ}\times 0.04=mg\times 0.38[/tex]
⇒ [tex]F =\frac{mg\times 0.38}{Sin60^{\circ}\times 0 .04}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{3\times 9.8\times 0.38}{0.04\times \frac{\sqrt{3}}{2}}[/tex]
⇒ [tex]=\frac{11.172}{0.0346}[/tex]
⇒ [tex]=322.5 \ N[/tex]
Is this a balanced equation? 6O2+ C6H12O6---> 6 CO2 + 6H2O
]
Yes, this equation is balanced.
You can check it using the law of conservation of mass, i.e., the total mass of the products formed must be equal to the total mass of the reactants.