Answers
Answer:
D
Step-by-step explanation:
This is an odd degree polynomial (the highest degee is an odd number) so both ends will be in different directions, one will be up the other will be down. So rule out any option that has p(x) pointing in the same direction (A & C)
Now we are between B & D. Look at the leading coefficient 6 which is positive so we know that the left end goes down and the right end goes up. If the lc was negative the opposite would be true. So
D is the right answer
Related Questions
Find the value of x that will make a||b help ?
Answers
Answer:
x=30
Step-by-step explanation:
Find the value of x that will make A and B parallel
For A & B to be parallel, the interior angles must be supplementary, i.e.
4x+2x = 180
6x=180
x=30
When x=30, the interior angles are 120 and 60 which are supplementary.
Which of the following functions is graphed below?
Answers
Answer:
C
Step-by-step explanation:
C is the solution
Answer:
Option C
Step-by-step explanation:
The graph is a horizontal translation 4 units left and a vertical translation 2 units down ⇒ y= |x+4|-2
The ratio of the number of circles to the number of triangles in simplest form is ___. The number of circles that need to be added to make the ratio 1 : 1 is ___.
Answers
Answer:
its 3:4
Hope this helps! :)
The ratio is 3:4 and the number of circle need is 3.
What is ratio?The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.
Here, from the given picture, we get that,
No. of circles = 9
No. of triangles = 12
So, required ratio = 9:12
=3:4
Now, Let, x circles are needed to make ratio 1:1
i.e. 9+x:12=1:1
9+x=12
x=3
Hence, The ratio is 3:4 and the number of circle need is 3.
To learn more on ratio click:
https://brainly.com/question/13419413
#SPJ3
Jason has bought a new pool and has already measured some of the sides. Using the figure below and your knowledge of quadrilaterals, solve for x and y.
Answers
Answer:
x = 12
y = 12
Step-by-step explanation:
Each triangle is a right angle triangle
5² + x² = 13²
x² = 169 - 25
x = √144
x = 12
The shape is a parallelogram
Therefore
x = y
y = 12
Jeff worked 4 and 2/3 hours in the morning and 3 and 3/4 hours in the afternoon. How many total hours did he work
1. 8 and 1/2 hours
2.7 and 5/7 hours
3.7 and 5/12 hours
4.8 and 5/12 hours
Answers
Answer:
4. 8 5/12
Step-by-step explanation:
4 2/3 + 3 3/4 =
= 4 + 2/3 + 3 + 3/4
= 4 + 3 + 8/12 + 9/12
= 7 + 17/12
= 7 + 12/12 + 5/12
= 7 + 1 + 5/12
= 8 5/12
if f(x) = -8 + 2 then f^-1 (x) = HELP ASAP!!!
Answers
Answer:
[tex]f^{-1}(x)= - \frac{1}{8} x+\frac{1}{4}[/tex]
Step-by-step explanation:
[tex]f(x) = -8x + 2[/tex]
[tex]y = -8x + 2[/tex]
[tex]y-2=-8x[/tex]
[tex]- \frac{1}{8} y+\frac{1}{4} =x[/tex]
[tex]- \frac{1}{8} x+\frac{1}{4} =y[/tex]
[tex]f^{-1}(x)= - \frac{1}{8} x+\frac{1}{4}[/tex]
Give the three-letter name of each of the angles in the drawing below. Lines and Angles a. ∠1 b. ∠2 c. ∠3 d. ∠4
Answers
Answer:
a. AEB
b. BEC
c. CED
d. AED
Step-by-step explanation:
Each angle is made up of three points. All three points in order is the name of the angle.
Answer:
a. ∠1 = ∠AEB or ∠BEA
b. ∠2 = ∠BEC or ∠CEB
c. ∠3 = ∠CED or ∠DEC
d. ∠4 = ∠DEA or ∠AED
Step-by-step explanation: Penn <3
There is a safety fence around a circular pool with a gate. The gate is 150 cm wide. What is the length of the fence not including the gate? m Use π = 3.14
Answers
Answer:
The length of the fence is 6.28x-150 cm.
Step-by-step explanation:
Let the circular pool has the radius (r ) = x cm.
Since the pool is in a circular shape so the circumference will be the length of the fence. Moreover, there is a 150cm wide so we have to subtract the 150 cm from the value of circumference in order to get the actual length of the fence.
Length of fence = Circumference of the pool – width of the gate.
Length of fence = 2 π r – 150
Length of fence = 2 × 3.14 × x – 150
Length of fence = 6.28x – 150 cm.
can anyone help me with this?
Answers
Answer: 16y² - x²
Step-by-step explanation: The - sign means a difference, so the choices with + signs are eliminated (though 64x² and 9 are squares)
10 is not a square so that one is eliminated (though the y² and the 4x² are squares)
16 is the square of 4, y² is the square of y, and x² is the square. That expression shows a difference of squares.
pls help me help me
Answers
Answer:
A
Step-by-step explanation:
Determine whether the geometric series is convergent or divergent. If it is convergent, find its sum. (If an answer does not exist, enter DNE.) 2 + 0.6 + 0.18 + 0.054 + ...
Answers
Answer:
sum: 2 6/7
Step-by-step explanation:
The first term is 2, and the common ratio is 0.6/2 = 0.3. This value is less than 1, so the series converges.
The sum is ...
S = a0/(1 -r) = 2/(1 -0.3) = 2/0.7
S = 2 6/7
Which of the following shows the intersection of the sets? {1, 5, 10, 15} {1, 3, 5, 7}
Answers
Answer:
{1,5}
Step-by-step explanation:
The intersection of the sets are all of the numbers that appear in both sets. In this case, the only numbers that appear in both are 1 and 5.
Answer:
{ 1,5}
Step-by-step explanation:
The intersection is what the two sets have in common
{1, 5, 10, 15}∩ {1, 3, 5, 7}
= { 1,5}
WHO CAN HELP ME WITH MY ACCOUNTING HOMEWORK???
Duran Manufacturing uses a process costing system and manufactures its product in three departments. Which of the following is NOT a way in which Duran can use the cost per unit of each process?
A) Duran can look for ways to cut the costs when actual process costs are more than planned process costs.
B) Duran needs to set the selling price to cover the costs of making the product and provide a profit.
C) Duran can only use the cost per unit of each process if all units are fully completed at the end of the accounting period.
D) Duran needs to know the ending balances in the following accounts: Work-In-Process Inventory, Finished Goods Inventory, and Cost of Goods Sold.
Answers
Answer:
C) Duran can only use the cost per unit of each process if all units are fully completed at the end of the accounting period.
Step-by-step explanation:
Duran uses cost accounting technique to identify cost per unit for its products. The costing techniques allows us to identify the cost of unit that are not completely finished. It is not necessary that all unit must be completed in order to find out the cost per unit of the product. The process costing is the best method to identify cost per unit for products that are in process.
The equation x2 − 6x − 27 = 0 when solved is:
Answers
Answer:
-3 , 9
Step-by-step explanation:
Sum = - 6
Product = -27
Factors = 3, -9
x² - 6x-27 = 0
x² + 3x - 9x - 9*3 = 0
x(x + 3) - 9(x + 3) = 0
(x + 3) (x - 9) = 0
x +3 = 0 ; x - 9 = 0
x = - 3 ; x = 9
Solution: x = -3 , 9
Andrea and Helen participated in a donut eating contest. Andrea ate six more than four times the number of donuts that Helen ate. Let d represents the number of donuts Helen ate. Write the expression that gives the number of donuts that Andrea ate.
Answers
Answer:
4d + 6
Step-by-step explanation:
Helen ate d donuts.
Andrea ate 6 more than 4 times d.
4d + 6
Solve for pi : C = 2 pi r
Answers
Answer:
[tex]\frac{C}{2r}[/tex]=pi
Answer:
π= C/2r
Step-by-step explanation:
In order to solve for pi, we must get pi by itself on one side of the equation.
C= 2πr
Let's rearrange the right side of the equation. We can do this because of the commutative property of multiplication.
C= 2πr
C= 2r* π
pi is now being multiplied by 2r. The inverse of multiplication is division. Divide both sides of the equation by 2r.
C/2r= 2r*π/2r
C/2r= π
π=C/2r
A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of cashews should he use?
Answers
Answer:
3lbs
Step-by-step explanation:
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets.
Answers
Complete Question
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets. Could they take 9 children and 4 adults to both shows? Show your work. A yes or no answer is not sufficient for credit.
Answer:
Yes it is possible to take the 9 children and 4 adults to both shows
Step-by-step explanation:
From the question we are told that
The cost of the Matinee tickets for a child is z = $4
The cost of the Matinee tickets for an adult is a = $ 4
The cost of the Evening tickets for a child is k = $6
The cost of the Evening tickets for an adult is b = $8
The maximum amount to be spent on Matinee tickets is m = $80
The maximum amount to be spent on Evening tickets is e = $100
The number of child to be taken to the movies is n = 9
The number of adults to be taken to the movies is j = 4
Now the total amount of money that would be spent on Matinee tickets is mathematically evaluated as
[tex]t = 4 n + 4 j[/tex]
substituting values
[tex]t = 4 * 9 + 4* 4[/tex]
[tex]t = 52[/tex]
Now the total amount of money that would be spent on Evening ticket is mathematically evaluated as
[tex]T = 6n + 8j[/tex]
substituting values
[tex]T = 6(9) + 8(4)[/tex]
[tex]T = 86[/tex]
This implies that it is possible to take 9 children and 4 adults to both shows
given that
[tex]t \le m[/tex]
i.e $56 [tex]\le[/tex]$ 80
and
[tex]T \le e[/tex]
i.e $ 86 [tex]\le[/tex] $ 100
A ball is thrown upward off of a 100 meter cliff with an initial velocity of 6 m/s. The function f(x)=-5x2+6x+100 (graphed below) represents this situation where x is time and y is the distance off of the ground. will mart brainliest yeah
Answers
Answer:
a) The domain of the function is [tex]x \geq 0\,s[/tex] [tex]\wedge[/tex] [tex]x \leq 5.112\,s[/tex]. [tex][0\,s, 5.112\,s][/tex], [tex]\forall x \in \mathbb{R}[/tex], b) The range of the function is [tex]0\,m \leq y \leq 100\,m[/tex]. [tex][0\,m,100\,m][/tex], [tex]\forall y\in \mathbb{R}[/tex], c) The ball is 73 meters off of the ground at x = 3 seconds.
Step-by-step explanation:
The complete statement is: A ball is thrown upward off of a 100 meter cliff with an initial velocity of 6 m/s. The function [tex]f(x) = -5\cdot x^{2} + 6\cdot x + 100[/tex] represents this situation where x is time and y is the distance off of the ground.
a) What domain does the function make sense?
b) What range does the function make sense ?
c) How far off the ground is the ball at time x = 3 seconds?
a) Let [tex]x[/tex] and [tex]f(x)[/tex] be the time, measured in seconds, and the distance of the ground, measured in meters, respectively. Time is a positive variable, so domain corresponds to the interval when [tex]f(x) \geq 0[/tex] and [tex]t \geq 0[/tex]. That is:
[tex]-5\cdot x^{2} + 6\cdot x + 100 \geq 0[/tex]
[tex]-(x-5.112\,s)\cdot (x+3.912\,s) \geq 0[/tex]
Therefore, the domain of the function is [tex]x \geq 0\,s[/tex] [tex]\wedge[/tex] [tex]x \leq 5.112\,s[/tex]. [tex][0\,s, 5.112\,s][/tex], [tex]\forall x \in \mathbb{R}[/tex]
b) The distance off of the ground is also a positive variable, where ball is thrown upward at a height of 100 meters and hits the ground at a height of 0 meters. Hence, the range of the function is [tex]0\,m \leq y \leq 100\,m[/tex]. [tex][0\,m,100\,m][/tex], [tex]\forall y\in \mathbb{R}[/tex]
c) The distance of the ball off of the ground at x = 3 seconds is found by evaluating the function:
[tex]f(3\,s) = -5\cdot (3\,s)^{2} + 6\cdot (3\,s) + 100[/tex]
[tex]f(3\,s) = 73\,m[/tex]
The ball is 73 meters off of the ground at x = 3 seconds.
From a group of graduate students including 25 men and 22 women, 37 are chosen to participate in a presentation. What is the probability that exactly 19 men and 18 women are chosen
Answers
Answer:
25.02% probability that exactly 19 men and 18 women are chosen
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the men and the women are selected is not important, so we use the combinations formula to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Desired outcomes:
19 men, from a set of 25
18 women, from a set of 22
[tex]D = C_{25,19}*C_{22,18} = \frac{25!}{19!6!}*\frac{22!}{18!4!} = 1295486500[/tex]
Total outcomes:
37 people from a set of 25 + 22 = 47. So
[tex]T = C_{47,37} = \frac{47!}{37!10!} = 5178066751[/tex]
Probability:
[tex]p = \frac{D}{T} = \frac{1295486500}{5178066751} = 0.2502[/tex]
25.02% probability that exactly 19 men and 18 women are chosen
Pablo purchased adult and youth tickets for the football game. He bought x adult tickets for $74 each and y youth tickets for $35. Write an expression that can be used to show the total cost, C, of all tickets.
Answers
Answer:
74x + 35y = c
Step-by-step explanation:
Each adult ticket costs $74 and Pablo is purchasing x amount of tickets, so 74 multiplied by x would be the total cost for the adult tickets. Each youth ticket costs $35 and Pablo is puchasing y amount of tickets, so 35 multiplied by y would be the total cost for youth tickets. Then you add the two sums together to find the total cost of all of the tickets.
Answer:
d. C = 74x + 35y
Step-by-step explanation:
I took the test and got the answer right here is the screen shoot to prove it
. A box contains four red, three yellow, and seven green balls. Three balls are randomly selected from the box without replacement. (a) What is the probability that all three balls are the same colo
Answers
Answer:
10/91
Step-by-step explanation:
Number of Red balls = 4
Number of Yellow balls = 3
Number of green balls=7
Total=4+3+7=14
If we pick three balls of the same color, there are three possibilities: (All Red, All Green Or all Yellow).
Therefore:
The probability that all three balls are the same color (note that the selections are without replacement)
=P(RRR)+P(GGG)+P(YYY)
[tex]=(\frac{4}{14} \times \frac{3}{13} \times \frac{2}{12})+(\frac{3}{14} \times \frac{2}{13} \times \frac{1}{12})+(\frac{7}{14} \times \frac{6}{13} \times \frac{5}{12})\\\\=\frac{1}{91} + \frac{1}{364}+ \frac{5}{52}\\\\=\frac{10}{91}[/tex]
The probability that all three balls are the same color is 10/91.
PLSS GUYS I NEED HELP
Answers
Answer:
Option B. is the right choice.
Step-by-step explanation:
f(-3) = 3 and f(3) = 5 (First and the last column of table B)
Best Regards!
Write an equation of the line with the given slope, m, and y-intercept (0, b). m = 4 , b = 9
Answers
Answer:
y = 4x + 9
Step-by-step explanation:
You can use these numbers to create an equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
y = mx + b
y = 4x + 9
After one round in a card game, your score was -50 points. After the second round, your score was 29 points. How many points did you gain in the second game?
Answers
Answer:
79
Step-by-step explanation:
[tex]score = 29 - (-50)[/tex]
Expressed as: The score is the difference between 29 and -50.
Simplify:
[tex]score = 29 + 50[/tex]
Result:
[tex]score = 79[/tex]
Feel free to ask questions, and don't forget to mark as Brainliest if this helped.
An auto parts shop carries an oil filter for trucks. The annual demand for the oil filter is roughly 1200 units. The ordering cost per order for the auto parts shop is $80; the holding cost of carrying 1 unit is $1.2 per year. The shop has 360 working days per year. The lead time is usually 12 working days. Determine the annual total relevant, including ordering and carrying, cost._______
a) 240
b) 80
c) 480
d) 300
e) None of the above.
Answers
Answer:
Total annual inventory cost = $480
c) 480
Step-by-step explanation:
given data
annual demand for the oil filter = 1200 units
ordering cost per order S = $80
holding cost of carrying 1 unit = $1.2 per year
lead time = 12 working days
number of working days = 360 days
solution
we get here economic order quantity that is express as
economic order quantity = [tex]\sqrt{\frac{2DS}{H}}[/tex] ...............1
here D is annual demand and S is ordering cost and H is per unit cost
so put here value and we get
EOQ = [tex]\sqrt{\frac{2\times 1200 \times 80}{1.2}}[/tex]
EOQ = 400 units
and
Annual ordering cost = annual demand × ordering cost ÷ order size .........2
and here
No orders (Q) = annual demand ÷ order size ...........3
Q = 1200 ÷ 400
Q = 3 orders
so
Annual ordering cost = ordering cost × number of order ................4
put here value
Annual ordering cost = 80 × 3
Annual ordering cost = $240
and
Annual carrying cost = average inventory × per unit cost ..........5
and
average inventory = EOQ ÷ 2 ...........6
Annual carrying cost = (EOQ × H) ÷ 2
put here value and we get
Annual carrying cost = 400 × 1.2 ÷ 2
Annual carrying cost = $240
and
so here Total annual inventory cost = Annual ordering cost + Annual carrying cost .........................7
Total annual inventory cost = $240 + $240)
Total annual inventory cost = $480
Toby cuts a pizza into 6 equal slices. He eats half a slice. What fraction of the pizza has he eaten?
Answers
The pizza is cut into 6 slices so each slice would be 1/6 of the pizza.
He at 1/2 of a slice:
1/6 x 1/2 = 1/12 of the pizza
Slices are 1/6th of the pizza
Of indicates multiplication
So
1/6 x 1/2 = 1/12
given that f(x)=x^-1, g(x)=2x+8 find (g-f)(10)
Answers
Hey there! :)
Answer:
(g-f)(10) = 279/10.
Step-by-step explanation:
Given:
[tex]f(x) = x^{-1}[/tex]
and
[tex]g(x) = 2x + 8[/tex]
Begin by solving for (g-f) by subtracting f(x) from g(x):
[tex](g-f)(x) = 2x + 8 - x^{-1}[/tex]
Substitute in 10 for x in the equation to solve this problem:
[tex](g-f)(10) = 2(10) + 8 - 10^{-1}[/tex]
Simplify:
[tex](g-f)(10) = 20 + 8 - \frac{1}{10}[/tex]
Create a common denominator to simplify further:
[tex](g-f)(10) = \frac{200}{10}+ \frac{80}{10} - \frac{1}{10}[/tex]
[tex](g-f)(10) = \frac{279}{10}[/tex]
Therefore:
(g-f)(10) = 279/10.
A food snack manufacturer samples 15 bags of pretzels off the assembly line and weighed their contents. If the sample mean is 9.9 and the sample standard deviation is 0.30, find the 95% confidence interval for the true mean.
Answers
Answer:
[tex]9.9-2.14\frac{0.30}{\sqrt{15}}=9.734[/tex]
[tex]9.9+2.14\frac{0.30}{\sqrt{15}}=10.066[/tex]
Step-by-step explanation:
Information given
[tex]\bar X= 9.9[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
s=0.3 represent the sample standard deviation
n=15 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
The degrees of freedom are given by:
[tex]df=n-1=15-1=14[/tex]
Since the Confidence is 0.95 or 95%, the value of [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and the critical value wuld be [tex]t_{\alpha/2}=2.14[/tex]
Now we have everything in order to replace into formula (1):
[tex]9.9-2.14\frac{0.30}{\sqrt{15}}=9.734[/tex]
[tex]9.9+2.14\frac{0.30}{\sqrt{15}}=10.066[/tex]
find the value of x if (1.1)^x=100
Answers
Answer:
x ≈ 48.3177
Step-by-step explanation:
This is what logarithms are for (among other things).
log(1.1^x) = log(100)
x·log(1.1) = 2
x = 2/log(1.1) ≈ 48.3177