PLEASE HELP

For the following chemical reaction, what mass of silver iodide, Agl, (in grams) will be produced from 3.11 mol of calcium
iodide, Calz?
Cal, + 2 AgNO, — 2 AgI + Ca(NO3)2

Answer:

Build wind-powered pumps to use groundwater

Explanation:

Answer:

Its B!

Explanation:

Did it on the test!

Answer:

30 ml

Explanation:

Answer:

When the balloon is taken outside if the outside temperature is lower than the temperature inside the shed, the volume of the helium gas will decrease according to Charles' law. However, if the temperatureoutside is higher than inside the shed, the volume of the helium gas in the weather balloons will increase.

Note: The question is not complete. Assumptionshas been made about the temperature.

Explanation:

According to Charles' law of gases, the volume of a given mass of gas is directly proportional to its temperature in Kelvin provided its pressure remains constant.

Mathematically, V1T1 = V2T2

Given that the volume of the helium gas inside the weather balloon is 34.1 L at a temperature of 5 °C;

When the balloon is taken outside if the outside temperature is lower than the temperature inside the shed, the volume of the helium gas will decrease according to Charles' law. However, if the temperatureoutside is higher than inside the shed, the volume of the helium gas in the weather balloons will increase.

Assuming, the temperature outside the shed was 6.5 °C:

V1 = 34.1 L, T1 = 5.°C or 5.0 × 10^-10 °C = 273.1500000005

V2 = ?, T2 = 6.5 °C 6.5 × 10^-10 °C = 273.15000000065

V2 = V1T1/T2

V2 = (34.1 × 273.1500000005) / 273.15000000065

V2 = 34.1 L

Due the very small increase in temperature, the volume of the balloon increases only very slightly that is increase that it is negligible.

Answer:

A

Explanation:

edge2021

Answer:

A.

Explanation:

Edge

Answer:

1.25 *10^2

Explanation:

25*5 = 125

= 1.25 *10^2

Answer:

0.1332 L

Explanation:

The balanced chemical equation is the following:

2 Na(s) + 2 H₂O(l) → 2 NaOH(aq) + H₂(g)

According to the equation, 2 moles of water (H₂O) produce 1 mol of hydrogen (H₂). So, the stoichiometric ratio is 1 mol H₂/2 mol H₂O. To calculate how many moles of H₂O we need to produce 3.7 moles of H₂, we multiply the moles by the stoichiometric ratio:

3.7 moles H₂ x 2 mol H₂O/1 mol H₂ = 7.4 moles H₂O

Now, we have to convert the moles of water to liters. For this, we have to consider the molecular weight (MW) of water and its density (let's consider 1.0 g/mL).

MW(H₂O) = (2 x 1 g/mol H) + 16 g/mol = 18 g/mol

7.4 moles H₂O x 18 g/mol = 133.2 g

133.2 g/(1.0 g/ml) = 133.2 mL

133.2 ml x 1 L/1000 ml = 0.1332 L

Therefore, approximately 0.13 liters of water are needed.

Answer:

1.)    2H2  +  O2  --->  2H2O

2.)   CH4  +  4Cl2 --->  CCl4  +  4HCl

Explanation:

In order to balance the equation, you have to make sure there are the same amount of each element on both sides.

Ex (#1).  By adding the coefficients infront of H2 and H20, You now have 4 hydrogen's and 2 oxygens on the left side as well as 4 hydrogens and 2 oxygens on the right side.

Sorry if that's confusing, but hope this helps! :)

When light travels from less dense air to denser glass or water, it slows down. Slowing down of a ray of light changes the direction of the ray of light.

Light that travels in a straight line in one direction is called a ray of light. When a group of light emanates from a source, it is called a beam of light. A beam of light is defined as the path of a photon or a group of photons traveling through a space appearing as a column of light.

There are three types of light rays. They are

Example of a beam is a beam of light with a pass from a laser or laser pointer. A beam of light is made up of particles called photons that carry specific amounts of energy. We cannot measure the length of a beam.

Thus, when light travels from less dense air to denser glass or water, it slows down. Slowing down of a ray of light changes the direction of the ray of light.

Learn more about Ray of light, here:

https://brainly.com/question/13851007

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Answer:

It is either C or D I think

Explanation:

I did the test a week ago but I can not figure out if it was C or D, but it was one of them...Hope it helps!

I think its C I'm not sure though.

Answer:

[tex]t_{1/2}=375.5min[/tex]

Explanation:

Hello!

In this case, since this problem refers to two different temperatures, it is possible to compute the rate constant at 652 K given the half-life at such temperature:

[tex]k=\frac{ln(2)}{58.0 min}=0.0120min^{-1}[/tex]

Next, by using the T-variable version of the Arrhenius equation, we can compute the rate constant at 623 K:

[tex]ln(\frac{k_2}{k_1} )=-\frac{Ea}{R}(\frac{1}{T_2}-\frac{1}{T_1} ) \\\\ln(\frac{k_2}{k_1} )=-\frac{218000J/mol}{8.3145\frac{J}{mol*K}}(\frac{1}{623K}-\frac{1}{652K})\\\\ln(\frac{k_2}{k_1} )=-1.872\\\\k_2=0.0120min^{-1}exp(-1.872)\\\\k_2=0.00185min^{-1}[/tex]

Finally, the half-life at 623 K turns out to be:

[tex]t_{1/2}=\frac{ln(2)}{0.00185min^{-1}} \\\\t_{1/2}=375.5min[/tex]

Best regards!

Answer:

Which answer would represent 0.001 moles?

Answer:

It forms a water cycle!

Hope it helps!!!

Answer: B. [tex]\frac{\text {2 mol} H_2O}{\text {2 mol HCl}}[/tex]

Explanation:

The balanced chemical equation is:

[tex]Ca(OH)_2(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)[/tex]

is the limiting reagent as it limits the formation of product and is the excess reagent.

According to stoichiometry :

2 moles of produce = 2 moles of

Thus 3.25 moles of [tex]HCl[/tex] will produce=[tex]\frac{2}{2}\times 3.25=3.25moles[/tex]  of [tex]H_2O[/tex]

Thus the tile used is [tex]\frac{\text {2 mol } H_2O}{\text {2 mol HCl}}[/tex]

Answer:Below is the answer to all 5 of stoichiometry question

Explanation:

1. B. The student chose the correct tile, but needs to flip the tile to make the units cancel.

2.C. 2.3 moles of oxygen (O2)

3. B. Tile B

4. A. 2.9 moles of aluminum sulfate

5. B. 42.0 grams

Answer:

Option D. 3 ppm isopropanol.

Explanation:

From the question given above, the following data were obtained:

Mass of isopropanol = 6 mg

Mass of water = 2 Kg

Isopropanol concentration =?

Concentration = mass isopropanol / mass of water

Isopropanol concentration = 6 mg / 2 kg

Isopropanol concentration = 3 mg/Kg

Next, we shall convert 3 mg/Kg to ppm. This can be obtained as follow:

Recall:

1 mg/Kg = 1 ppm

Therefore,

3 mg/Kg = 3 ppm

Thus, the isopropanol concentration is 3 ppm.

Answer:

389929.827

Explanation:

33806.78° C

Answer:

(a) 3.96 (w/w) %

(b) 0.663M

Explanation:

The acetic acid, CH₃COOH, reacts with NaOH as follows:

CH₃COOH + NaOH → CH₃COONa + H₂O

Where 1 mole of acetic acid reacts with 1 mole of NaOH

In the equivalence point of the titration, the moles of acetic acid are equal to moles of NaOH added. To solve this question we need to find the moles of NaOH and thus, the mass of acetic acid

Moles NaOH = Moles acetic acid:

33.0cm³ = 0.033L * (0.100moles / L) = 0.0033 moles

Mass acetic acid -Molar mass: 60g/mol-:

0.0033 moles * (60g / mol) = 0.198g

a) Weight percent is 100 times the ratio of the mass of acetic acid (0.198g) in the mass of vinegar (5.00g):

0.198g / 5.00g * 100 = 3.96 (w/w) %

(b) The volume of the vinegar in the 5.00g is:

5.00g * (1mL / 1.005g) * (1L / 1000mL) = 0.00498L

And the molarity is:

0.0033moles / 0.00498L = 0.663M

Answer:

Any process that leads to the dissociation of a neutral atom or molecule into charged particles ions; the state of being ionized.

Explanation:

Answer:

552 g of LiNO₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 2 L

Molarity of LiNO₃ = 4 M

Mass of LiNO₃ =?

Next, we shall determine the number of mole of LiNO₃ in the solution. This can be obtained as follow:

Volume of solution = 2 L

Molarity of LiNO₃ = 4 M

Mole of LiNO₃ =?

Molarity = mole /Volume

4 = mole of LiNO₃ / 2

Cross multiply

Mole of LiNO₃ = 4 × 2

Mole of LiNO₃ = 8 moles

Finally, we shall determine the mass of of LiNO₃ needed to prepare the solution. This is can be obtained as follow:

Mole of LiNO₃ = 8 moles

Molar mass of LiNO₃ = 7 + 14 + (16×3)

= 7 + 14 + 48

= 69 g/mol

Mass of LiNO₃ =?

Mole = mass /Molar mass

8 = Molar mass of LiNO₃ /69

Cross multiply

Molar mass of LiNO₃ = 8 × 69

Molar mass of LiNO₃ = 552 g

Thus, 552 g of LiNO₃ is needed to prepare the solution.

answer: white fur works as a camouflage against the white snow, allowing polar bears an advantage when hunting for food and hiding from predators

Answer:

Explanation:

Water is capable of dissolving a variety of different substances, which is why it is such a good solvent. And, water is called the "universal solvent" because it dissolves more substances than any other liquid. This allows the water molecule to become attracted to many other different types of molecules.

Answer:

0.5 mole of CO₂.

Explanation:

We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:

Mass of NaHCO₃ = 42 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 42/84

Mole of NaHCO₃ = 0.5 mole

Next, balanced equation for the reaction. This is given below:

NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

Answer:

I got you! I think the answer is D. Warmer air can hold more water vapor than colder air.

Explanation:

Although this statement is true, I could be incorrect, but it is unlikely. When warm air recieves more water vapor it expands while cold air becomes packed and unstable.

Hope this helps out, good luck! (¤﹏¤)

~ #LearnWithBrainly ~

Answer:

Explanation:

Answer:

³₂He

Explanation:

From the question given above, the following equation was obtained

²₁H + ²₁H —> ¹₀n + __

Let ᵇₐX be the missing part of the equation. Thus, the equation becomes:

²₁H + ²₁H —> ¹₀n + ᵇₐX

Next, we shall determine b, a, and X. This can be obtained as follow:

2 + 2 = 1 + b

4 = 1 + b

Collect like terms

b = 4 – 1

b = 3

1 + 1 = 0 + a

2 = 0 + a

a = 2

ᵇₐX => ³₂X => ³₂He

Thus the equation is:

²₁H + ²₁H —> ¹₀n + ᵇₐX

²₁H + ²₁H —> ¹₀n + ³₂He

The missing part is ³₂He

Answer:

a) 0.099 L

b) 9.9

Explanation:

Now, given the equation for the decomposition of H2O2;

2H2O2(l) ------> 2H2O(l) + O2(g)

Mass of H2O2;

percent w/v concentration = mass/volume * 100

volume = 10.0-mL

percent w/v concentration = 3.0 percent

mass of  H2O2 = x

3 = x/ 10 * 100

30 = 100x

x = 30/100

x = 0.3 g of H2O2

Number of moles in  0.3 g of H2O2 = mass/ molar mass

Molar mass of H2O2 = 34.0147 g/mol

Number of moles in  0.3 g of H2O2 = 0.3g/34.0147 g/mol

= 0.0088 moles

From the reaction equation;

2 moles of H2O2 yields 1 mole of oxygen

0.0088 moles of H2O2 = 0.0088 * 1/2  = 0.0044 moles of oxygen

If 1 mole of oxygen occupies 22.4 L

0.0044 moles of oxygen occupies 0.0044 *  22.4/1

= 0.099 L

b) initial volume of the H2O2 solution = 10 * 10-3 L

Hence, ratio of the volume of O2 collected to the initial volume of the H2O2 solution = 0.099 L/10 * 10-3 L = 9.9

Answer:

Chemical reactions leads to formation of a new chemical subtance.

Answer:

  B

Explanation:

Answer:

B) Hope this helps! :)

Explanation:

Answer:

A

Explanation:

195.49 g K x 1 mole / 39.01 g x 6.022 x 10^23 atoms/mole = 30.11 x 10^23 = 3.011 x 10^24

The number of K atoms present in 195.49 grams of K is 3.0110 × 10²⁴ atoms. The correct option is a 3.0110 x 10²⁴.

From the question,

We are to determine the number of K atoms present in 195.49 grams of K.

First, we will determine the number of moles K present

Using the formula,

[tex]Number\ of\ moles = \frac{Mass}{Atomic\ mass}[/tex]

Atomic mass of K = 39.0983 g/mol

Number of moles of K present = [tex]\frac{195.49}{39.0983}[/tex]

Number of moles of K present = 4.99996 moles

Number of moles of K present ≅ 5 moles

Now, for the number of atoms present

From the formula

Number of atoms = Number of atoms × Avogadro's constant

Number of K atoms present = 5 × 6.022 × 10²³

Number of K atoms present = 5 × 6.022 × 10²³

Number of K atoms present = 30.11 × 10²³

Number of K atoms present = 3.0110 × 10²⁴ atoms

Hence, the number of K atoms present in 195.49 grams of K is 3.0110 × 10²⁴ atoms. The correct option is a 3.0110 x 10²⁴.

Learn more on Stoichiometry here: https://brainly.com/question/16505596