7. A complex arrangement of pulleys forms what is called the block in a block
and tackle. The rope used to lift the pulleys and the load is the tackle. A block
and tackle is used to lift a truck engine, which weighs nearly 7,406 N. The
force required to lift this weight using the block and tackle is 308.6 N. What is
the mechanical advantage of the block and tackle?
Answer:
24
Explanation:
Given parameters:
Load = 7406N
Effort = 308.6N
Unknown:
The mechanical advantage of the block and tackle system = ?
Solution:
Mechanical advantage is the ability of a simple machine to amplify or increase the force needed to do work.
Mathematically;
M.A = Output force / Input force
Output force = Load
Input force = Effort
M.A = 7406N / 308.6N = 24
The mechanical advantage is 24
2) A car is towed by a horizontal rope at a constant speed.
draw the free body diagram
Answer:
\
\
\
Explanation:
The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.0059 m/s/s, what is the sun’s acceleration toward the Earth?
Answer:
this is the answer according to my calculations
Explanation:
0.001.9
1.
A student pushes against a wall with 20 N of force and the wall does not move. In this situation, the
wall exerts -
A.
A.20 N of force in the same direction as the push.
B.20 N of force in the opposite direction of the push.
C.less than 20 N of force.
D.more than 20 N of force.
Answer:
B
Explanation:
This is a balanced force. In a balanced force, nothing happens.
A windshield hits a bug with force of 10 N.
What force does the bug hit the windshield?
Explain using Newton's third law.
Unit 2 kinetic energy mastery test
Answer: kinetic energy is Energy of motion.
Explanation:
What happens to the gravitational force between two objects as the bodies become closer to each other? A. The gravitational force begins to repel the objects. B. The gravitational force increases. C. The gravitational force decreases. D. The gravitational force stays the same.
Answer:
Explanation:
The gravitational force between two objects becomes weaker if the two objects are moved apart and stronger if they are brought closer together; that is, the force depends on the distance between the objects.
The gravitational force between two objects as the bodies become closer to each other increases.
Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,
F ∝ m₁.m₂
F ∝ 1/r²
F = G m₁,m₂÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
As distance decreases the Force increases
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Which Box in the diagram above, should this picture go into?
Box A
ООО
O Box B
O Box C
Plzz answerr idk
HELP PLEASE
A load is a device that changes electrical energy into other forms of energy. Which load converts electrical energy into thermal energy by passing an electric current through a high-resistance material?
A.
Hand-powered generator
B.
Toaster
C.
Fan
D.
Electrical drill
Answer:
A toaster because you plug it up for electric energy and heat to toast it
How does changing the initial mass of the copper affect how much heat energy it has?
Answer:
Increasing the temperature of the copper made the final temperature increase and decreasing the temperature of the copper made the final temperature decrease. ... How does changing the initial mass of the copper affect how much heat energy it has? The more copper, the more heat energy.
Explanation:
Decreasing the temperature of the copper made the final temperature decrease. But the mass remains constant.
What is heat energy?Heat is energy that is transmitted from one body to another as a result of a temperature differential. When two bodies of different temperatures come into contact,
Thermal expansion is the tendency of matter to alter its form, area, volume, and density in response to a change in temperature.
Thermal expansion is caused by heating. The mass remains constant. The loudness rises. As a result, the density drops.
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A tourist wishes to catch a train in 1.2 hours, which is 115 km away. If she spends the first half-hour going 90km/h, how fast will she need to go to get to station on time?
Answer:
100km/hr
Explanation:
From the problem statement we know that distance of the trip is 115km
Expected time for the trip = 1.2hrs
→ If she spends the first half-hour going 90km/hr,
Here time = 0.5hr
speed = 90km/hr
The distance covered;
Distance covered = Speed x time
Distance covered = 90 x 0.5 = 45km
→The remaining distance will be:
Total distance - distance covered
115km - 45km = 70km
→ The remaining time;
1.2hr - 0.5hr = 0.7hr
Speed = [tex]\frac{distance}{time}[/tex]
Insert the parameters and solve;
Speed = [tex]\frac{70}{0.7}[/tex] = 100km/hr
For the remaining lap, the tourist must travel at a rate of 100km/hr to catch up.
Why is physics worth knowing about
Answer:
Physics can help you in your everyday life.
Explanation:
It can also help you in life treating situations.
Circle the letter of each factor that determines whether a molecule
is polar or nonpolar.
a. the number of atoms in the molecule
b. the type of atoms in the molecule
c. the number of bonds in the molecule
d. the shape of the molecule
A car travels west for 200000 m in 12600 s what’s its velocity
Answer:
Velocity = 15.87m/s
Explanation:
Given the following data;
Distance, d = 200000m
Time, t = 12600secs
*To find the velocity*
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
[tex]Velocity = \frac{distance}{time}[/tex]
Substituting into the equation, we have;
[tex]V = \frac{200000}{12600}[/tex]
Velocity = 15.87m/s
Therefore, the velocity of the car is 15.87 meters per seconds due west.
A man has a mass of 66 kg on Earth. What is his weight in Newtons?
Answer:
answer is 66 kilograms-force = 647.2389 newtons
Explanation:
Answer:
[tex]\boxed {\boxed {\sf 646.8 \ Newtons }}[/tex]
Explanation:
Weight in Newtons can be found by multiplying the mass times the acceleration of gravity.
[tex]W=m*g[/tex]
The mass of the man is 66 kilograms on Earth.
Earth has an acceleration of gravity that is 9.8 meters per square second.
[tex]m= 66 \ kg \\g=9.8 \ m/s^2[/tex]
Substitute the values into the formula.
[tex]W=66 \ kg *9.8 \ m/s^2[/tex]
Multiply.
[tex]W=646.8 \ kg*m/s^2[/tex]
1 kg * m/s² is equal to 1 Newton, therefore our answer of 646.8 kg *m/s² is also equal to 646.8 Newtons, or N.
[tex]W=646.8 \ N[/tex]
The man's weight in Newtons in 646.8 Newtons.
The diagram below shows the velocities of two runners.
11 m/s west
Runner 1
5 m/s east
Runner 2
From the frame of reference of runner 1, what is the velocity of runner 2?
O A. 5 m/s east
O B. 6 m/s east
C. 16 m/s west
O D. 16 m/s east
Answer : 16 m/s east
Explanation: Trust the process!!
From the frame of reference of runner 1, the velocity of runner 2 will be D) 16 m/s east
What is relative velocity ?
The relative velocity is defined as the velocity of an object with respect to another observer
When two bodies are moving in opposite directions , relative velocity get added and if bodies are moving in same direction , relative velocity will get subtracted .
From the frame of reference of runner 1, the velocity of runner 2 will be
v (relative) = v1 + v1
v1 = velocity of runner 1 = 11m/s west
v2 = velocity of runner 2 = 5m/s
v = 11 + 5 = 16 m/s
correct answer will be O D. 16 m/s east as runner 2 is running in east direction
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n
Which of the following has a crystalline appearance?
baking soda
salt
baking powder
corn starch
Answer:
B: Salt
Explanation:
I answered this correct beforehand.
what is the unit measurement of the surface? physics
Answer:
square metre is the answer
Explanation:
Hope this helps u
Crown me as brainliest:)
hey guys, l need some help! what is the weight of potatoes of mass 75 kg on the surface of the earth? (g=9.8m/s square) ans=735N l need process
Answer:
735N
Explanation:
Weight is a measurement of force.
F = Force
m = mass
a = acceleration
F = m*a
F = 75kg*9.8m/s²
F = 735N
A ball is thrown upwards from the ground. The ball reaches its maximum height after 3.3 s. What is the initial velocity of the ball at the moment the ball is released and starts to rise?
Plyometrics can help a person maintain cardiorespiratory fitness. Please select the best answer from the choices provided. T F
Answer: IT IS TRUE
Explanation:
Hope this helps
Plyometrics can help a person maintain cardiorespiratory fitness T
It is TRUE that plyometrics can help a person maintain cardiorespiratory fitness
PlyometricsPlyometrics is a type of exercise training that works with the principle of using speed and force of different movements to build muscle power.
Plyometrics include different types of exercises such as pushups, throwing, running, jumping, and kicking.
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hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest
Answer:
A. Cue, White Ball, Blue Ball
Explanation:
Visualize in which order things are being hit
what is the spring constant for a spring if pulling it back .0391m causes a force in the opposite direction of .922N?
-0.361N
.361N
-2.36N
2.36N
Answer: correct me if i'm wrong but is it 0.361N
In the human circulatory system, arteries carry blood away from the heart to different parts of the body. Veins carry blood from different parts of the body back to the heart. A scientist claims that the greater the amount of exercise a person performs, the greater the amount of oxygen (O2) the body uses. He records the oxygen concentration in the blood of people while they are riding an exercise bike. The graphs show the results of this investigation.
a. Identify at least two systems within the human body that work together during exercise.
b. Explain how the evidence from the data in the graphs supports or does not support the scientist’s claim.
Answer:
There are many different systems involved in when we exercise, the three main ones are the Respiratory system which is involved in breathing the circulatory system which is about circulation of blood around the body and finally the muscular system and finally the Muscular system which is about how we move.
Explanation:
If the data consistently do not support the hypothesis, then CLEARLY, the hypothesis is NOT a reasonable explanation of what you are investigating. The hypothesis is rejected, and we search for a new interpretation, an new hypothesis that supports the experimental data
Respiratory and circulatory systems are the two systems within the human body that work together during exercise.
How does the respiratory and circulatory systems work together during exercise?The respiratory system:
allows the exchange of gases intake of oxygen and exhalation of carbon-dioxide.oxygenation of blood at the lungs.The circulatory system:
transports deoxygenated blood to the lungs for oxygenation.delivers oxygenated blood to the appropriate tissue.Hence, during exercise more oxygen is used by the body.The claim by scientist is true?During exercise:
breathing rate increases from about 15 times per minute to roughly 40–60 times per minute.heart rate also rises, providing more oxygen to reach your muscles and allowing them to continue moving.To learn more about respiratory system, circulatory system, blood, exercise, and oxygen here,
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Scince Why do cells need to adjust when conditions change? ____________________________________________________________________________________________
Answer:
A cell is the basic block of life and is always changing to fit its environment.
Explanation:
A cell is the basic founding block of a living organisms. In other words, a cell is the basic membrane unit which contains fundamental molecules of life. It is the cell that all living things are composed of.
The cell always changes with the surroundings and environment and it adapts to it. The cells requires a constant adjustments as the conditions inside and the outside the cells changes to keep a stable internal environment. Because the environment internally and externally is always changing, the cell continuously make adjustments to stay at or the near the set point.
What is the weight, on Earth, of a book with a mans of 1.5 kg?
15N
66N
11 3N
14,7N
plzzzz help me and I will mark u the brainiest
what is the coefficent for hydrochloric acid
Answer:
HCI
Explanation:
I dont know what you mean by coefficient but that's the thing you would see in the periodic table
Write an equation of the line in slope-intercept form.
Please explain.
Answer:
y = [tex]-\frac{1}{4}[/tex]x + 3
Explanation:
The equation of a straight line is given as:
y = mx + c
y and x are the coordinates
m is the slope
c is the y -intercept
The y-intercept = 3;
Slope = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
x₁ = 0
x₂ = 4
y₁ = 3
y₂ = 2
Slope = [tex]\frac{2-3}{4 -0 }[/tex] = [tex]-\frac{1}{4}[/tex]
y = mx + c
y = [tex]-\frac{1}{4}[/tex]x + 3
Explica la relación entre momento de torsión y aceleración angular mencionando tres ejemplos Una varilla uniforme delgada mide 1.5 m de longitud y tiene una masa de 6kg si la varilla se hace girar en un centro y se queda en rotación con una velocidad angular de 16 rad/seg calcular la cantidad de movimiento
Answer:
1) τ = I α whereby the torque is provided by the angular acceleration
2) L = 216 Kg m² / s
Explanation:
1) Let's start with Newton's second law
F = m a
multiply by the arm or perpendicular distance
F r = m a r
if the distance is not perpendicular a way of realizing the relations using the vector product
τ = F r = F x r
the bold are vectors. The angular and linear acceleration are related
a = α r=
τ = m (α r) r
τ = (m r²) α
the inertia of the rotational motion is
I = m r²
we substitute
τ = I α
whereby the torque is provided by the angular acceleration.
As an example we have:
* a spinning disk
* a ball rotating in the air
* a pulley
2) The rotational momentum is
L = I w
the moment of inertia of a rod that through its center
I = m L²
we substitute
L = m L² w
let's calculate
L = 6 1.5 2 16
L = 216 Kg m² / s
La cantidad de movimiento angular de la varilla uniforme es 18 kilogramos-metro cuadrado por segundo.
1) La relación entre el momento de torsión ([tex]M[/tex]), una variable cinética y relacionada con la aplicación de una fuerza externa cuya línea de proyección no cruza el centro de masa del objeto, y la aceleración angular ([tex]\alpha[/tex]), una variable cinemática, es la resistencia del cuerpo a rotar, la cual es función de su masa y su geometría, representada por la variable de momento de inercia.
A continuación, presentamos tres ejemplos del concepto:
Giro de una tuerca como consecuencia del giro de una llave inglesa por la acción de una mano y un brazo.Transmisión del movimiento a través de la transmisión de una bicicleta.Cierre de una compuerta mediante una transmisión rígida por engranes y un volante.2) Asumamos que la varilla uniforme es de masa constante, con una rotación a velocidad angular constante y con un centro de rotación localizado en el centro geométrico de la varilla. La cantidad de movimiento es expresada mediante la siguiente ecuación:
[tex]L = I\cdot \omega[/tex] (1)
Donde:
[tex]L[/tex] - Cantidad de movimiento angular, en kilogramos-metro cuadrado por segundo.[tex]I[/tex] - Momento de inercia, en kilogramos-metro cuadrado.[tex]\omega[/tex] - Rapidez angular, en radianes por segundo.El momento de inercia de una varilla uniforme con centro de rotación en el centro queda expresado por la siguiente fórmula:
[tex]I = \frac{1}{12}\cdot m\cdot L^{2}[/tex] (2)
Donde:
[tex]m[/tex] - Masa de la varilla, en kilogramos.[tex]L[/tex] - Longitud de la varilla, en metros.Al aplicar (2) en (1), tenemos la expresión resultante:
[tex]L = \frac{1}{12} \cdot m\cdot L^{2}\cdot \omega[/tex] (3)
Si sabemos que [tex]m = 6\,kg[/tex], [tex]L = 1.5\,m[/tex] y [tex]\omega = 16\,\frac{rad}{s}[/tex], entonces la cantidad de movimiento angular es:
[tex]L = \frac{1}{12}\cdot (6\,kg)\cdot (1.5\,m)^{2}\cdot \left(16\,\frac{rad}{s} \right)[/tex]
[tex]L = 18\,\frac{kg\cdot m^{2}}{s}[/tex]
La cantidad de movimiento angular de la varilla uniforme es 18 kilogramos-metro cuadrado por segundo.
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