I need help with number 7 please

Answer:

4 g/cm³

Explanation:

Volume(V) = 60 cm³

mass (m) = 240 gm

density (d) = ?

We know density is defined as mass per unit volume so

d = m / v

= 240 / 60

= 4 g/cm³

Hope it will help

Answer: Periodic Trends

Zeff increases because the positive charge of the nucleus increases while the outermost electrons stay the same distance from the nucleus (filling the same orbital). In other words, going across a period, the outermost electrons are more tightly held. This explains the trend in atomic radius.

It refers to how strongly an atom attracts electrons from other atoms. Electronegativity is a measure of an atom's ability to draw electrons towards itself, or the ability of the nucleus to hold electrons tightly

hope this helps have a great day❤️

Explanation:

Answer:

neon gas

Explanation:

neon is a noble gas, meaning it has a full outer shell of elections. this means it is stable and is very unlikely to have a reaction with another substance.

Answer:

Pretty sure the answer is B

Answer:

3 AU

Explanation:

The distance from the Earth to the Sun is known as 1 AU, or 1 Astronomical Unit. If an asteroid is three times this distance, it is 3 AU away.

Answer:

sorry i dont know

Explanation:

Answer:

170.68

Explanation:

PV=nRT or 22.4L for every mole of a gas at STP

Cuz D is cyclo-thingy molecule and its a sugar

(i think A is fatty acid or other molecules and C is hydrocarbon. B dont have oxygen)

Monosaccharides are the group of carbohydrates that are the simplest form of sugar. Option D. galactose is a monosaccharide sugar.

Monosaccharides are simple sugars and are the fundamental unit of carbohydrates. The general structural formula for the monosaccharides is [tex]\rm (CH_{2}O)_{n}.[/tex]

The structure of the monosaccharide sugar contains carbon, oxygen, and hydrogen molecules in their structure. Option A. is a fatty acid molecule, and option B. lacks an oxygen molecule, and hence they are not monosaccharides.

Option C. is a hydrocarbon chain that lacks oxygen molecules and option D. is a galactose that is a simple sugar with six carbon atom rings.

Therefore, option D. galactose is the monosaccharide.

Learn more about monosaccharides here:

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Answer:

2.14 g.

Explanation:

Hello!

In this case, since the mole ratio between nitrogen and oxygen is 2:5 respectively, we realize we first need the moles of nitrogen given it's atomic mass (14.01 g/mol):

[tex]n_N=0.750g*\frac{1mol}{14.01g}=0.0535molN[/tex]

Now, we calculate the moles of oxygen:

[tex]n_O=0.0535molO*\frac{5molO}{2molN}=0.134molO[/tex]

Then, we compute the moles of oxygen given its atomic mass (16.00 g/mol):

[tex]m_O=0.134molO*\frac{16.00gO}{1molO_2} \\\\m_O=2.14gO[/tex]

Best regards!

Answer:

Human chorionic gonadotropin (HCG) injections are much safer to use with some mild side effects to treat issues of testicular atrophy. Human chorionic gonadotropin (HCG) injections would increase blood flow and enable the testes' produce testosterone, reduce the shrinkage of the testicles and it also aids in the production of sperm cells which has been initially impaired due to testicular atrophy.

Explanation:

Anabolic steroid is a drug that plays the role of testosterone.

Testicular atrophy is the shrinkage of the testicles caused by old age or infections. Once it occurs, it lowers the production of testosterone and sperm cells.

Trenbolone increases muscle building, aids lean fat deposition, reduces the production of testosterone, and could also lead to testicular atrophy.

Answer:

B

Explanation:

All elements on both sides of the equation have the same amount of moles

Answer:

A, B and D

Explanation:

Gas particles move randmly at high speed, colliding with each other

Answer:

That would be 4.17742995 * 10^13 :)

Explanation:

Answer:

0.00011 JK.

The process does NOT violate the second law of thermodynamics

Explanation:

The following parameters are given which are going to help in solving for the change in entropy of the system. The term "entropy'' simply means the degree of disorderliness of a system.

=> The temperature of container A = 305 K, the temperature of container B = 295 K and the amount of heat generated when the containers are placed in contact with each other = 1. 1 J.

The change in entropy of the hot container = -(1/305) = - 0.00328 J/K.

The change in entropy of the cold container = 1/295 = 0.00339 J/K.

Therefore, the change in the entropy of the system = - 0.00328 J/K + 0.00339 J/K = 0.00011 JK.

Note that the change in entropy of the system gives a positive value. Hence, this process does not violate the second law of thermodynamics.

The process does NOT violate the second law of thermodynamics.

Answer:

1 mol C₃H₈

Explanation:

Step 1: Write the balanced equation for the combustion of C₃H₈

C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of C₃H₈ to CO₂ is 1:3.

Step 3: Calculate the moles of C₃H₈ consumed when 3 moles of CO₂ are produced

We will use the established molar ratio.

3 mol CO₂ × 1 mol C₃H₈/3 mol CO₂ = 1 mol C₃H₈

Answer:

H-C-H

Explanation:

hydrogen plus carbon hdrocloide

Answer:

A.

Explanation:

In conclusion, an electrically neutral object is an object that has a balance of protons and electrons. In contrast, a charged object has an imbalance of protons and electrons. ... The type of charge(positive or negative) is determined by whether the protons or the electrons are in excess

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Answer:

0.0977M is the concentration of the final solution

Explanation:

In a dilution process, to the original solution (Stock solution) you add more solvent in order to decrease its original concentration. To know how many times the solution was diluted you must find the dilution factor (Ratio between the initial and final volume). That is:

Intial Volume: 5.73mL

Final volume: 5.73mL + 20.26mL = 25.99mL

Dilution factor: 25.99mL / 5.73mL = 4.536 → 4.536 times the solution is diluted. The concentration of the diluted solution is:

0.443M / 4.536 =

The concentration of the solution is 0.099 M.

We have to use the dilution formula here;

C1V1 = C2V2

Where;

C1 = initial concentration

C2 = final concentration

V1 = initial volume

V2 = final volume

Now;

C2 = C1V1/V2

C2 =0.443 M × 5.73 mL / (5.73 mL  + 20.26 mL)

C2 = 0.099 M

Learn more about Beers law: https://brainly.com/question/7184331

Answer:

Parasites take nutrients from another organism's body.

Explanation:

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Empirical formula =?

Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Mass of Hydrogen (H) =?

Mass of H = mass of compound – mass of C

Mass of H = 6.32 – 5.41

Mass of H = 0.91 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of C = 5.41 g

Mass of H = 0.91 g

Divide by their molar mass

C = 5.41 / 12 = 0.451

H = 0.91 / 1 = 0.91

Divide by the smallest

C = 0.451 / 0.451 = 1

H = 0.91 / 0.451 = 2

Thus, the empirical formula for the compound is CH₂

Answer:

all i can help you with is one of them is Canada. If im

wrong i am sorry.

Explanation:Refer to the map of "The Major North American Land Biomes" to answer the question.

Answer:

is Canada and Texas

good luck and hope it helps

Answer:

Magnesium Sulfate

Explanation:

Answer:

magnesium sulfate

Explanation:

mg stands for magnesium and SO is sulfate

Answer:

a. Speed up, lose

Explanation:

#CARRYONLEARNING

Answer:

b. speed up, gain

Explanation:

Answer:

Answer:

(a). (I). 0.816; 0.816

(ii). 0.917.

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Explanation:

So, without mincing words let's get straight into the solution to the question above.

(a). Using the (i) statistical theory of Flory to Determine the critical extent of reaction gelation, one has to make use of the two equations given below;

P(1) = [ v + vb ( n - 2)^-1/2 ------------------(1).

P(2) = v^1/2 [ 1 + b ( n - 2)^-1/2 ----------(2).

The value for v = 1.2 + 1.2/ 1.2 × 2 = 1.

The value of b = (1.2 + 1.2)/ 1.2 = 0.5.

Thus, putting the values into the equation (1) and (2) above gives;

NB: n = 3.

P(1) = [ 1 + 1 × 0.5 ( 3 - 2)^-1/2 = 0.816.

P(2) = 1^1/2 [ 1 + 0.5 ( 3 - 2)^-1/2 = 0.816.

Using the (ii) carother's theory to Determine the critical extent of reaction gelation.

We have the following values for glycerol: k = 0.4, n = 3.

For ethylene glycol; k = 0.6, n = 2.

Therefore, the critical extent of reaction gelation =2/[ (0.6 × 2) + (0.4 × 3) + (1.2 × 2)/ (0.6 + 0.4 + 1.2)] = 2/ 2.18 = 0.917

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Answer:

[tex]C=0.152\frac{J}{g\°C}[/tex]

Explanation:

Hello!

In this case, when doing calorimetry problems, we need to use the following equation:

[tex]Q=mC(T_2-T_1)[/tex]

Whereas Q is the involved heat, m the mass, C the specific heat and T2 and T1 the final and initial temperatures respectively. Thus, since we need the specific heat, we proceed as follows:

[tex]C=\frac{Q}{m(T_2-T_1)}[/tex]

Thus, we plug in to obtain:

[tex]C=\frac{15,650J}{750g(250\°C-25\°C)} \\\\C=0.152\frac{J}{g\°C}[/tex]

Best regards!

Answer:

Unlike other extinguishing agents - water, dry chemical, CO2, etc., a stable aqueous foam can extinguish a flammable or combustible liquid fire by the combined mechanisms of cooling, separating the flame/ignition source from the product surface, suppressing vapors and smothering. It can also secure for extended periods of time against reflash or reignition. Water, if used on a standard hydrocarbon fuel, is heavier than most of those liquids and if applied directly to the fuel surface, will sink to the bottom having little or no effect on extinguishment or vapor suppression. If the liquid fuel heats above 212ºF, the water may boil below the fuel surface throwing the fuel out of the contained area and spreading the fire. For this reason, foam is the primary fire-extinguishing agent for all potential hazards or areas where flammable liquids are transported, processed, stored or used as an energy source.

this is what I found, hope it helps

In contrast to other extinguishing agents such as water, dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling, separating the flame source from the product surface, suppressing vapors, and smothering.

The term solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.

It can also protect against ref lash or reignition for extended periods of time. Water is heavier than most liquids when used on a standard hydrocarbon fuel and will sink to the bottom if applied directly to the fuel surface, having little or no effect on extinguishment or vapor suppression.

If the liquid fuel heats above 212°F, water may boil beneath the fuel surface, releasing the fuel and spreading the fire.

Thus,  dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling.

To learn more about the solubility, follow the link;

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Answer:

(3rd option) Asexually reproduced offsprings have the same amount of genetic information as the parent, while sexually reproduced offsprings have half as much genetic information.

Explanation:

This is variation is caused as a result of both gamete production and fertilisation.

Answer:

you have to shake the soda up