Consider the reaction: S(s) O2(g)SO2(g) Write the equilibrium constant for this reaction in terms of the equilibrium constants, Ka and Kb, for reactions a and b below: a.) 2 S(s) 3 O2(g) 2 SO3(g) Ka b.) SO2(g) 1/2 O2(g) SO3(g) Kb

Answers

Answer 1

Answer:

[tex]Ka=\frac{[SO_3]^2}{[O_2]^3} \\\\Kb=\frac{[SO_3]^3}{[SO_2][O_2]^{1/2}}[/tex]

Explanation:

Hello!

In this case, according to the reactions:

a.) 2 S(s) 3 O2(g) ⇔ 2 SO3(g) Ka

b.) SO2(g) + 1/2 O2(g) ⇔ SO3(g) Kb

Thus, according to the law of mass action, we can write Ka and Kb as follows:

[tex]Ka=\frac{[SO_3]^2}{[O_2]^3} \\\\Kb=\frac{[SO_3]^3}{[SO_2][O_2]^{1/2}}[/tex]

Whereas solid carbon is not inserted in the equilibrium expression.

Best regards!


Related Questions

What is the molar mass of Ammonium Carbonate?

Answers

Explanation:

Molar mass

96.09 g/mol

glad to help....

What is the surface composition of planets in the solar system?

A,. Helium or hydrogen
B,. Rock or gas
C., Rock or water
D,. Water or helium

Answers

Answer:

B

Explanation:

Most planets in the solar system don't have water. Helium and hydrogen are two of the many gasses in planets. Therefore, B is the best answer.

forms of energy reflection

Answers

Answer:

any of these

Explanation:

kinetic energy: kinetic is motion, or released energy

Potential energy: porential energy is the energy of position or stored energy.

Thermal energy: is heat energy, it is stored energy that creats heat.

La fórmula molecular del pentano y del nonano son​

Answers

Nose jajajajajaj si mr ayudas te ayudo

What is the electrostatic potential energy (Eel) of the ionic bond between a Ca2+ ion and a S2– ion in joules? Before you do the calculation, predict whether the result you get will be less than (more negative) or greater than (less negative) than the Eel value for KCl. The ionic radii of Ca2+ and of S2– are 100 pm and 184 pm, respectively.

Answers

Answer: the electrostatic potential energy is -3.26 × 10⁻¹⁸ J

Explanation:

Given the data in the question;

I think the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has more charge that is +2 and -2 respectively when compared to Kcl which has +1 and -1 charge.so it will be more negative.

radius = r[tex]_{ca+2}[/tex] + r[tex]_{s-2}[/tex] = 100 + 184 = 284 pm = 2.84 × 10⁻¹⁰ m

we know that; k = 2.31 × 10⁻²⁸ J

q1 = 2  ( charge on Ca⁺² )

q2 = -2( charge on S⁻²)

so

Ep = k × q1q2/r

so we substitute

Ep = 2.31 × 10⁻²⁸ × (+2×-2) / 2.84 × 10⁻¹⁰

Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰

Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰

Ep = -3.26 × 10⁻¹⁸ J

Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J

Based on the data provided, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J

What is electrostatic potential energy?

The electrostatic potential energy is the work done in moving the charge from infinity to that point against the electric field.

The electrostatic potential energy between any two charges q1, q2 separated by distance r is derived from Coulomb’s law and mathematically given as:

E = k × [q1q2/r2]

where

k is a constant = 2.31 × 10⁻²⁸ Jq1 and q2 are the chargesr is the distance of separation

From the data provided:

ionic radii of Ca2+ r1 = 100 pm

ionic radii of S2– = 184 pm.

Chargeon Ca2+ = +2

Charge on S2_ = -2

From the data above, it most likely that the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has a greater charge of +2 and -2 respectively compared to Kcl which has +1 and -1 charge.

Calculating the electrostatic potential energy, Ep:

radius = r1 + r2 = 100 + 184 = 284 pm

r = 2.84 × 10⁻¹⁰ m

k = 2.31 × 10⁻²⁸ J

q1 = 2  ( charge on Ca⁺² )

q2 = -2( charge on S⁻²)

Then:

Ep = k × q1q2/r

Substituting the values above in the equation:

Ep = 2.31 × 10⁻²⁸ × (+2 ×-2) / 2.84 × 10⁻¹⁰

Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰

Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰

Ep = -3.26 × 10⁻¹⁸ J

Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J.

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What a main difference between Earth and Jupiter?

A. Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.

B. Earth is an inner planet with a relatively long distance from the sun, while Jupiter is an outer planet with a relatively short distance from the sun.

C. Earth is an outer planet with a gas surface composition, while Jupiter is an inner planet with a solid rock surface composition.

D. Earth is an outer planet with a relatively short distance from the sun, while Jupiter is an inner planet with a long distance from the sun.

Answers

Answer: A. Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.

Answer: What a main difference between Earth and Jupiter?

Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.

Earth is an inner planet with a relatively long distance from the sun, while Jupiter is an outer planet with a relatively short distance from the sun.

Earth is an outer planet with a gas surface composition, while Jupiter is an inner planet with a solid rock surface composition.

Earth is an outer planet with a relatively short distance from the sun, while Jupiter is an inner planet with a long distance from the sun.

Explanation:

I'LL MARK YOU BRAINLIEST! Please help me balance these chemical reactions. (I'M NOT IN COLLEGE, I'M IN 10TH GRADE) Please help me​

Answers

Answer:

1. H2 + Cl2 => 2HCl

2. Na2S + 2HCl => 2NaCl + H2S

3. 6HCl + 2Al => 2AlCl3 + 3H2

4. C3H8 + 5O2 => 3CO2 + 4H2O

5. C6H12O6 + 6O2 => 6CO2 + 6H2O

6. 4C12H23O11 + 49O2 => 48CO2 + 46H2O

7. 4NH3 + 7O2 => 4NO2 + 6H2O

8. 2Mg + 02 => 2MgO

hope it helps

59. Which one has 0 dipole moment?
a. H2O2 b. Co2 c. HF
d. HBr

Answers

Answer:

the answer to this question is A H202

Consider the reaction 2H2(g)+O2(g)→2H2O(l) 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) What is the mass of water, H2O(l) H 2 O ( l ) , produced when 5.70 g g of O2(g) O 2 ( g ) reacts with excess H2(g) H 2 ( g ) ?hen 5.70 g g of O2(g) O 2 ( g ) reacts with excess H2(g) H 2 ( g ) ?

Answers

Answer:

mH₂O = 6.4116 g

Explanation:

Let's write the given reaction:

2H₂ + O₂ -------> 2H₂O

The problem states that 5.7 g of oxygen reacts with excess hydrogen, hence, the limiting reagent is the oxygen. With this mass of oxygen, we can determine the moles, and then, the moles of water with the mole ratio:

moles = mass / atomic weight        AW of O₂ = 16 g/mol

Replacing we have:

moles O₂ = 5.70 / (16 * 2)

moles O₂ = 0.1781 moles

According to the balanced reaction, 1 mole of Oxygen produces 2 moles of water, so we have a mole ratio 1:2, therefore the moles of water would be twice the moles of oxygen:

moles H₂O = 0.1781 * 2 = 0.3562 moles

Finally the mass of water can be calculated solving for the mass from the expression of moles, and using molecular mass of water:

m = moles * MM          MM H₂O = 18 g/mol

m = 0.3562 * 18

mH₂O = 6.4116 g

Hope this helps

What is the surface composition of planets in the solar system?

A,. Helium or hydrogen
B,. Rock or gas
C., Rock or water
D,. Water or helium

Answers

Answer:

A: Helium or Hydrogen

Explanation:

Terrestrial planets are the 4 inner most planets of the solar system which are mercury, venus, earth, Mars, while the giant planets are the 4 outer most which are Jupiter, Saturn, Uranus and Neptune.

Now, these outer most ones are the surface ones and are surrounded primarily by layers of hydrogen and helium gases.

How many moles are there in 2.30 x 1024 atoms of silver?

Answers

Answer:

Step 1 should be convert atoms to moles (n). Step 2 should be convert moles (n) to mass (m).

Step 1

Use dimensional analysis to convert the number of atoms to moles.

1 mole atoms = 6.022 × 10²³ atoms

n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms) = 3.8193 mol Ag

Step 2

Convert the moles of Ag to mass.

mass (m) = moles (n) × molar mass (M)

n(Ag) = 3.8193 mol Ag

M(Ag) = atomic weight on the periodic table in g/mol = 107.868 g Ag/mol Ag

m(Ag) = 3.8193 mol × 107.868 g/mol = 412 g Ag = 410 g Ag rounded to two significant figures

The mass of 2.3 × 10²⁴ Ag atoms is approximately 410 g.

Explanation:

The number of moles that are present is 2.3 × 10²⁴ atoms of silver are 3.8193 moles that can be determined using Avogadro's law.

The calculation for number of moles:

One mole:

A mole is defined as 6.022 × 10²³ of some chemical unit, be it atoms, molecules, ions, or others.

1 mole = 6.022 × 10²³ atoms

n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms)

n(Ag) = 3.8193 mol Ag

Thus, the number of moles is 3.8193 moles.

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Ethane is a hydrocarbon with a formula of C2H6 . How many Carbon and Hydrogen atoms are contained within 3 molecules of ethane ?

Answers

Answer:

Within three molecules of Ethane, it would have 6 carbon, and 18 hydrogen atoms in it.

Explanation:

Please balance the equation, putting the correct coefficient in each box.

Do not leave any boxes blank! Enter "1" for formulas having a presumed

coefficient of 1.

Bi(OH)3 +

HNO3 →

H2O +

Bi(NO3)3

Answers

Answer: [tex]Bi(OH)_3+3HNO_3\rightarrow 3H_2O+Bi(NO_3)_3[/tex]

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced equation will be:

[tex]Bi(OH)_3+3HNO_3\rightarrow 3H_2O+Bi(NO_3)_3[/tex]

What is the molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution?

Answers

Answer:

0.389 M

Explanation:

From the question given above, the following data were obtained:

Mass of CuCl₂ = 78.5 g

Volume of solution = 1.50 L

Molarity of CuCl₂ =?

Next, we shall determine number of mole in 78.5 g of CuCl₂. This can be obtained as follow:

Molar mass of CuCl₂ = 63.5 + (35.5×2)

= 63.5 + 71

= 134.5 g/mol

Mass of CuCl₂ = 78.5 g

Number of mole of CuCl₂ =?

Mole = mass / Molar mass

Number of mole of CuCl₂ = 78.5 / 134.5

Number of mole of CuCl₂ = 0.584 mole

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Number of mole of CuCl₂ = 0.584 mole

Volume of solution = 1.50 L

Molarity of CuCl₂ =?

Molarity = mole / Volume

Molarity of CuCl₂ = 0.584 / 1.50

Molarity of CuCl₂ = 0.389 M

The molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.

HOW TO CALCULATE MOLARITY?

The molarity of a solution can be calculated

From the question given above, the following data were obtained:

Mass of CuCl₂ = 78.5 gVolume of solution = 1.50 LMolarity of CuCl₂ =?

Next, we shall determine number of moles in 78.5g of CuCl₂. This can be obtained as follow:

Molar mass of CuCl₂ = 63.5 + (35.5×2)

= 63.5 + 71

= 134.5 g/mol

Mass of CuCl₂ = 78.5g

Number of mole of CuCl₂ = 78.5 / 134.5

Number of mole of CuCl₂ = 0.584 moles

The determine the molarity of the solution. This can be obtained as follow:

Number of moles of CuCl₂ = 0.584 molesVolume of solution = 1.50LMolarity of CuCl₂ =?

Molarity = mole / Volume

Molarity of CuCl₂ = 0.584 / 1.50

Molarity of CuCl₂ = 0.389M

Therefore, molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.

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Calculate how many grams of BeCl2 are required to produce 0.52 grams of MnCl2

Answers

Answer:

65.0cp

Explanation:

3. A very large distillation column is separating p-xylene (more volatile) from o-xylene. The column has two feeds that are saturated liquids. Feed 1 flows into the column at a rate of 90 kmol/h and contains 42 mol% p-xylene. Feed 2 flows at a rate of 20 kmol/h and contains 9 mol% p-xylene. The bottoms product should be 97 mol% o-xylene, and the distillate product should be 99 mol% p-xylene. Compute the distillate (D) and the bottoms (B) products flow rates

Answers

Answer:

the distillate (D) and the bottoms (B) products flow rates are;

B = 72.1875 kmol/hr

D = 37.8125 kmol/hr

Explanation:

Given the data in the question;

as illustrated in the image below;

F1 stream, ( 90 kmol/hr ) contains 42 mol% p-xylene and Feed 2 ( 20 kmol/hr) contains 9mol% p-xylene, so;

more volatile → p-xylene

less volatile → o-xylene

now, Overall balance;

F1 + F2 = D + B

90 + 20 = D + B

D + B = 110    ------------- let this be equation 1

p-xylene. component balance;

0.42F1 + 0.09F2 = 0.99D +  0.03B

0.42(90) + 0.09(20) = 0.99D +  0.03B

37.8 + 1.8 = 0.99D +  0.03B

0.99D +  0.03B = 39.6 --------------- let this be equation 2

from equation 1 and 2

input (D = 110 - B) into equation 2

0.99(110 - B) +  0.03B = 39.6

108.9 - 0.99B + 0.03B = 39.6

108.9 - 39.6 = 0.99B - 0.03B

69.3 = 0.96B

B = 69.3 / 0.96

B = 72.1875

now, input B = 72.1875 into equation 1

D + B = 110

D + 72.1875 = 110

D = 110 - 72.1875

D = 37.8125

Therefore, the distillate (D) and the bottoms (B) products flow rates are;

B = 72.1875 kmol/hr

D = 37.8125 kmol/hr

What is the difference between an introduced species and an invasive species?

Answers

Answer and Explanation:

The introduced species is, literally, a species that was introduced into an environment by human action. In other words, an introduced species is one that is not native to a region, does not occur naturally, but has been taken by humans to that region.

An invasive species, on the other hand, is one that was introduced naturally in an environment, but multiplied in a harmful way, causing a strong imbalance in the region.

Skin color variations were caused by:

a). The change in melanin, the skin's brown pigment

b). The climate of where people migrated to

c)Diets that are rich in Vitamin D

d) All of the above

Answers

I'm certain the answer is D: All of the above, but please correct me if I'm wrong ^^

8. Label the type and parts of the waves shown here.
longitudinal wave
WORD BANK
engitudinal wave
• transverse wave
compression
• rarefaction
crest
trough
Houghton Mifflin Harcourt

Answers

Bottom one is transverse and top is longitudinal wave!! Hope it’s right if it’s not let me know

Calculate the number of moles of H2SO4 required to react with 0.93 moles of Al. Do not include units in your answer. Round to the tenths place or further.

Answers

Answer:

1.40 moles of H₂SO₄.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below below:

2Al + 3H₂SO₄ —> Al₂(SO₄)₃ + 3H₂

From the balanced equation above,

2 moles of Al reacted with 3 moles of H₂SO₄.

Finally, we shall determine the number of mole of H₂SO₄ required to react with

0.93 moles of Al. This can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted with 3 moles of H₂SO₄.

Therefore, 0.93 moles of Al will react with = (0.93 × 3)/2 = 1.40 moles of H₂SO₄.

Thus, 1.40 moles of H₂SO₄ is needed for the reaction.

A) Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.43 g of salt and 1.41 g of sand. What is the percent recovery of the mixture?
B) Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.43 g of salt and 1.41 g of sand. What is the percent recovery of the mixture?
C) Calculate the percent by mass of a solution made from 15 g NaCl (the solute) and 69 g water.
D) What percent of 73.0 g is 26.1 g?

Answers

Answer:

A-B) 94 %.

C) 17.9 %.

D) 35.8 %.

Explanation:

Hello!

A-B) In this case, since the total mass of the mixture is 3.02 g and 1.43g+1.41g=2.84 g are recovered in total, we can compute the percent recovery as shown below:

[tex]\%rec=\frac{2.84g}{3.02g}*100\%\\\\\%rec=94\%[/tex]

C) Here, since the solution is made up of NaCl and water, we can say that the mass of the solution is 15g+69g=84g; thus, the percent by mass would be:

[tex]\%=\frac{15g}{84g}*100\%\\\\\%=17.9\%[/tex]

D) In this case, we simply divide 26.1 g by 73.0 g in order to obtain the percent:

[tex]\%=\frac{26.1g}{73.0g}*100\%\\\\\%=35.8\%[/tex]

Best regards!

The percentage in the cases are as follows;

A and B is; 94%C is; 17.9%D is; 35.8%

Questions A and B are similar and can be solved as follows;

The total mass of the mixture is 3.02g.The recovered mass = 1.43g + 1.41g = 2.84g

% recovery = (2.84/3.02) × 100%

% recovery = 94%

Question C can be solved as follows;

Total mass of solution = 15 + 69 = 84gMass of solute = 15g

% by mass = (15/84) × 100%

% by mass = 17.9%

Question D can be solved as follows;

% = (26.1/73) × 100%% = 35.8%

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In the lab activity, the reaction rate was determined by the appearance of a product. However, the reaction rate can also be determined by the disappearance of a reactant. Rate =Δ[product]/Δt or rate−Δ[reactant]Δt. In each situation below, you are given a rate measured by the appearance of one component of the reaction and are asked to predict the rate of appearance or disappearance of another component, based on logic and stoichiometric relationships.

For example, if the reaction is as follows:

A+2B⟶products

For every mole of A that is used, 2 moles of B are used so the rate of disappearance of B is twice the rate of the disappearance of A.

This may be expressed as:

rate=−Δ[B]/Δt=−2[A]/Δt , N2(g)+3H2(g)⟶2NH3(g)

The reaction rate is measured as 0.032 M NH3/s. Determine the rate of disappearance of N2 and the rate of disappearance of H2. Explain how you arrived at your answers.

Answers

Answer: Rate of disappearance of [tex]N_2[/tex]= 0.032 M/s

Rate of disappearance of [tex]H_2[/tex] = 0.096 M/s

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

[tex]N_2(g)+3H_2(g)\rightarrow 2NH_3(g)[/tex]

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of [tex]N_2[/tex] = [tex]-\frac{1d[N_2]}{dt}[/tex]

Rate in terms of disappearance of [tex]H_2[/tex] = [tex]-\frac{1d[H_2]}{3dt}[/tex]

Rate in terms of appearance of [tex]NH_3[/tex] = [tex]\frac{1d[NH_3]}{2dt}[/tex]

Rate = [tex]-\frac{1d[N_2]}{dt}=-\frac{1d[H_2]}{3dt}=\frac{1d[NH_3]}{2dt}[/tex]

Given : = 0.032 M/s

Rate of disappearance of =

Rate of disappearance of [tex]H_2[/tex] = [tex]-\frac{d[H_2]}{dt}=3\times 0.032M/s=0.096M/s[/tex]

Rank the following compounds in order of increasing stability, putting the least stable first. Group of answer choices II < I < III I < II < III III < II < I III < I < II

Answers

Hello. You forgot and show the compounds. The compounds are in the attached image.

Answer:

I < II < III

Explanation:

The stability of the presented compounds must be analyzed, taking into account the free electrons to form arrangements between the atoms. In this case, the molecules of greater stability follow the concept of valence and are characterized as those that manage to reach a large number of elements that manage to obey the octet rule.

DNA forms two strands. One of the strands of a piece of a DNA molecule has the bases ATA.

Which bases does the other strand have?
Select one:

A: CAC.

B: TAT.

C: GTG.

D: ATA.

Answers

Answer:

b

Explanation:

Combinations between two strands:

T - A

A - T

C - G

G - C

(so if one strand has A for example, then the other strand must have T in the same spot)

Bases   which are present on the other strand of DNA are TAT.

What is DNA?

DNA or deoxyribonucleic acid is a hereditary material present in humans as well as all living beings. Almost every cell present in the body has DNA. Most DNA are located inside the cell , that is in the nucleus of the cell. But a small portion of DNA  can be found in the mitochondria of the cell as well.

The information in DNA is stored as a code which is composed of four chemical bases 1) adenine 2)guanine 3) cytosine  4) thymine . The human DNA consists of 3 billion bases . The order of of these bases determine information which is used for building and maintaining an organism.

The DNA bases can pair with each other .Adenine pairs with thymine   and guanine with cytosine to form units which are called as base pairs.Each base apart from other complementary base it also attaches itself to a sugar and a phosphate molecule.

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What is the concentration of a Kl solution of 20.68 g of solute was dissolved in enough water to form 100. ml of solution?

Answers

Answer:

1.25M

Explanation:

3. Noble gases are sometimes called "inert gases." What can you infer about the meaning of the word "inert" in chemistry?

Answers

Answer:

Noble gases are sometimes called "inert gases." What can you infer about the meaning of the word "inert" in chemistry? It refers to substances that easily lose electrons. It refers to substances that do not react with other substances. It refers to substances that have strong electrochemical charges.

Explanation:

Why do you think the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene?

Answers

Answer:

See explanation

Explanation:

The reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate as well as the reaction of  tetraphenylcyclopentadienone and diphenylacetylene are  Diels Alder reactions. The former is performed in presence of a solvent while the former is performed neat.

The reaction of tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate leads to the formation of a more resonance-stabilized aromatic ring(lower energy product) compared to the reaction of  tetraphenylcyclopentadienone and diphenylacetylene.

Hence, the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene.

Using the van der Waals equation, determine the pressure exerted by 4.30 mol Ar in 3.6 L at 325K.

Answers

Answer:

37.7 atm

Explanation:

Using the relation;

(P + an^2/V^2) (V - nb) = nRT

(P + an^2/V^2) = nRT/(V - nb)

a = 0.0341 atm dm^2 Mol^2

b = 0.0237 dm/mol

P = nRT/(V - nb) - an^2/V^2

P = [4.3 * 0.082 * 325 / (3.6 - (4.3 * 0.0237))] - (0.0341 * (4.3^2))/(3.6^2)

P = 114.595/(3.498) - 0.0487

P = 37.7 atm

Question 8 of 25
What is alchemy?
O A. A scientific approach to research that uses observations and
measurements to test ideas
O B. An early form of chemistry that people used to try to turn metal
into gold
O c. A belief that chemistry forms the basis of all areas of science
O D. An ancient philosophy that taught that all matter was composed
of earth, fire, water, and air
SUBMIT

Answers

Alchemy is "an early form of chemistry that people used to try to turn metal into gold".

The development of a universal cure for illness, as well as the discovery of a way to indefinitely extend life, were the goals of mediaeval chemical research and speculative philosophy.

Boyle contributed to the evolution of chemistry from alchemy. He used the experimental approach from physics and applied it to chemistry. Boyle contributed to the comparison of these two fields of knowledge by demonstrating that chemistry is just as important to study as physics.

Therefore, the correct statement will be "An early form of chemistry that people used to try to turn metal into gold".

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The following conditions must be met before a standard calibration curve equation can be used to solve for the concentration of an unknown solution:

a. The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
b. The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
c. The equation from the calibration curve can only be linear.
d. Domain and range restrictions must be observed.

Answers

Answer:

The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.

The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.

Domain and range restrictions must be observed.

Explanation:

Calibration curves are tools necessary in understanding the instrumental response for any analyte.

A calibration curve is obtained by preparing a set of  standard solutions with known concentrations of the analyte. The instrument response for each concentration is measured  and plotted against the concentration of the standard solution. The linear portion of this plot may be used to determine the unknown concentration of a sample of the analyte.  

The equation of the best-fit line is  used to determine the concentration of the unknown sample.

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