Can you freeze sound waves

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The fluids that have no resistance or zero resistance to internal friction are known as non- viscous fluids. • The fluid which has more resistance to flow is called viscous fluid. Viscosity is a property of a fluid, which is a degree of the amount of resistance between the fluid layers.

Answer:

[tex]1.2\times 10^{10}\ kg[/tex]

Explanation:

Given that,

The energy of the nuclear plant, [tex]E=10^{27}\ J[/tex]

We need to find how much mass wast lost.

The relation between energy and mass is given by :

[tex]E=mc^2[/tex]

Where

c is speed of light

[tex]m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg[/tex]

So, [tex]1.2\times 10^{10}\ kg[/tex] of mass was lost.

Answer:

Energy stored, E = 5929 J

Explanation:

Given that,

The mass of a test dummy, m = 55 kg

It is launched 11 m into the air.

We need to find the energy stored in the bungee cords. It can be calculated as follows :

[tex]E=mgh\\\\E=55\times 9.8\times 11\\\\E=5929\ J[/tex]

So, 5929 J of energy is stored in the bungee cords.

Answer:

Explanation:

Answer:

5 m/s

Explanation:

The formula of speed is : distance/time taken.

The skateboarder covered a distance of 20 meters in 4 seconds. So,

Distance = 20 meters

Time Taken = 4 seconds

Speed = 20/4 = 5 m/s

Answer:

Fapp =44N is the correct answer

Explanation:

Please mark brainliest

Answer:

C is the answer

Explanation:

Earth is the third planet from the sun

you are cheating on your test, I know

Answer:

C..

Explanation:

I'm not sure about answer...

Answer:

10m/s

Explanation:

Vf=v0+at

30m/s=v0+2.5m/s^2*8s

Solve for v0=10m/s

Sorry for the vague explanation I'm on my phone right now. Hope this still helps!

Initial velocity of the car where final velocity of a car is 30m/s and it is accelerating at a rate of 2.5 [tex]m/s^{2}[/tex] over an 2.8 [tex]m/s^{2}[/tex] 8 second period of time is 10 m/s.

To find the initial velocity of the car, we can use the kinematic equation:

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)).

Given the final velocity (v) as 30 m/s, acceleration (a) as 2.5 [tex]m/s^{2}[/tex], and time (t) as 8 seconds, we can plug these values into the equation:

30 m/s = u + (2.5 [tex]m/s^{2}[/tex] * 8 s).

Now, solve for the initial velocity (u):

30 m/s = u + 20 m/s.

Subtract 20 m/s from both sides:

u = 30 m/s - 20 m/s = 10 m/s.

Therefore, the initial velocity of the car is 10 m/s.

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The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.  

The potential energy can be calculated with the following equation:

[tex] E_{p} = mgh [/tex]

Where:

m: is the mass of the baseball

g: is the acceleration due to gravity

h: is the height

We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:

[tex] E_{p_{1}} = mg*1 = mg [/tex]  (1)

[tex] E_{p_{2}} = mg*2 = 2mg [/tex]   (2)

By entering equation (1) into 2 we have:

[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]

Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.

Therefore, the baseball held 2 m above the ground has more potential energy.

You can learn more about potential energy here: https://brainly.com/question/15813853?referrer=searchResults

I hope it helps you!

Answer:

120.48hz

Explanation:

f=1/t..........

Either the wavelength, velocity, or wave period—the amount of time it takes for a wave cycle to complete—must be known. If you know the period, divide 1 by it and, if necessary, convert it to seconds. The outcome will be the frequency in Hertz.

As with all waves, the relationship between the speed of sound, its frequency, and its wavelength is vw=f, where vw is the speed of sound, f is the frequency, and is the wavelength.It is necessary to know either the wavelength, the velocity, or the wave period, which is the duration of a wave cycle.

Therefore, More oscillations are produced at higher frequencies. Hertz are the frequency measurement units (Hz). Noises between 20 Hz and 20,000 Hz can be heard by those with normal hearing. Ultrasound is a term for frequencies greater than 20,000 Hz.

Learn more about sound waves here:

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Answer:

options?!?

Explanation:

give us some options

Answer:

b

Explanation:

I did this question earlier

Answer:

The mass of the locomotive is 288,000 kg

Explanation:

The question relates to the law of conservation of energy

The given parameters are;

The form of engine on the locomotive = Rocket engine

The mass of the locomotive = m

The initial velocity of the locomotive, v = 0 m/s

The duration at which the engine is fired = 20 s

The mass of the kerosene expelled, m₁ = 500 kg

The average speed with which the kerosene is expelled, v₁ = 1,200 m/s

The final speed of the locomotive engine after 20-s, v₂ = 50 m/s

Kinetic energy, K.E. = 1/2·m·v²

The total kinetic energy of the kerosene particles, K.E.[tex]_k[/tex] = 1/2 × 500 × 1,200² = 360,000,000

∴ K.E.[tex]_k[/tex] = 360,000,000 J

By the conservation of energy, the kinetic energy of the expelled kerosene particles is equal to the kinetic energy gained by the moving locomotive

Therefore, we have;

K.E.[tex]_L[/tex] = K.E.[tex]_k[/tex]

K.E.[tex]_L[/tex] = 1/2 × m × v₂² = 1/2 × m × 50²

∴ K.E.[tex]_L[/tex] = 1/2 × m × 50² = K.E.[tex]_k[/tex] = 360,000,000 J

1/2 × m × 50² = 360,000,000 J

m = 360,000,000 J/(1/2 × (50 m/s)²) = 288,000 kg

m = 288,000 kg

The mass of the locomotive, m = 288,000 kg

Answer:

The density pf each piece will be the same, since density is defined as a mass per unit volume, so even when you cut an object it will not change

Answer:

1) The angle of projection of the ball is approximately 52.496° above the horizontal

2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s

Explanation:

In the projectile motion of the ball, the parameters are;

The distance the boy stands from the front of the house = 5 m

The depth of the house, front to back = 6 m

The height of the opening of the front window above him = 5 m

The height of the back window = 2 m higher than the front window

Therefore, the height of the back window = 5 m + 2 m = 7 m

1) The general formula for the vertical height of a parabolic projectile motion is given as follows;

y = a·x² + b·x + c

At y = 0, x = 0, therefore, c = 0

At y = 5, x = 5, we have;

5 = a·5² + b·5

∴ 5 = 25·a + 5·b...(1)

At y = 7, x = 11, we have;

7 = a·11² + b·11

7 = 121·a + 11·b...(2)

Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;

For equation (1);

a = (5 - 5·b)/25 = 1/5 - b/5

a = 1/5 - b/5

For equation (2);

a = (7 - 11·b)/121 = 7/121 - b/11

a = 7/121 - b/11

∴ 1/5 - b/5 = 7/121 - b/11

1/5 - 7/121 = b/5 - b/11

86/605 = 6·b/55

b = (86/605) × (55/6) = 43/33

b = 43/33

a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33

∴ y = (-2/33)·x² + (43/33)·x

The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33

The slope of the curve at any point on the projectile = -4/33·x + 43/33

The slope at the origin is given by plugging x = 0  as follows

The slope at the origin = -4/33 × 0 + 43/33 = 43/33

The slope at the origin = tan(θ) = 43/33

Where;

θ = The angle of projection of the ball

∴ θ = arctan(43/33) ≈ 52.496°

The angle of projection of the ball, θ ≈ 52.496° above the horizontal

2) At the back widow, the equation for the vertical height, 'h', is given as follows;

[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]

Where;

h = The vertical height of the back window = 7 m

tan∠θ = 43/33

x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m

g = The acceleration due to gravity = 9.8 m/s²

v₁ = The velocity with which the boy throws the ball

cos²∠θ = cos²(arctan(43/33)) = 1089/2938

Plugging in the values gives;

[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]

[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]

[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]

The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.

Answer:

Given: V = 220V, Pmin = 360W, Pmax = 840W

For minimum heating case:

We know that

Pmin = VI

360 = 220 X I

I = 1.63 amp

R = V/I

R = 220/1.63

R = 134.96ohms

For maximum heating case:

We know that

Pmax = VI

840 = 220 X I

I = 3.81 amp

R = V/I

R = 220/3.81

R = 57.74 ohms

Answer:

c. shot put

Explanation:

cause the shot is a ball

Explanation:

Basalt is not a metamorphic rocks

Answer:

13 Hz Ans..

Explanation:

Data:

wavelength = 5 m

v = 65 m\s

f = ?

Formula:

v = f w

f= v\w

Solution:

f = 65 \ 5

f = 13 Hz Ans .........

Answer:

weight on earth is mg

which is 5*9.8

49 Newton

weight on moon is 1/6 th of weight on earth

1/6*49

8.166 Newton..

Answer:

1

For instance, on Earth, a 5.0-kg object weighs 49 N; on the Moon, where g is 1.67 m/s2, the object weighs 8.4 N.

2

The weight of the object on the surface of earth would be 5kg. The weight of the object on the surface of moon would be 5/6= 0.83 as the weight of any object on earth is six times than that on moon.

Answer:

a.) Maximum height of the projectile. =32.5m

b.) The time it takes to reach the maximum height=2.6s

c.) Time of flight=2.6s

d.) Range=99.5m

Explanation:

Answer:

The answer is "0.047".

Explanation:

Given value:

[tex]\to t_{\frac{1}{2}}= 0.4406\\\\\to V=0.9375 V_{max}[/tex]

Calculating the capacitance:

[tex]\to V=V_{max} (1-e^{\frac{-t}{Rc}})[/tex]

In this, the t = time, which is taken to calculates its maximum voltage.

[tex]\to 0.9375 V_{max} = V_{max}(1-e^{- \frac{t}{103\times(165.279\times10^{-6})}})\\\\\to e^{- \frac{t}{103\times(165.279\times10^{-6})}}= 0.0625\\\\\to - \frac{t}{103\times(165.279\times10^{-6})} = \ln(0.0625)\\\\\to -t= 0.01702\times(-2.77258) \\\\ \to -t = -0.04719 \\\\ \to t= 0.04719 \approx 0.047 \ s[/tex]

Answer:

[tex]H=\frac{V^2}{R}[/tex]

Explanation:

Let H be  heat produced per sec

Time, t=1 sec

Resistance of resistor=R ohm

We have to write down the expression for the  heat produced per second in a resistor in terms of potential difference and resistance​.

We know that

Heat, [tex]H=I^2 Rt=\frac{V^2}{R}t[/tex]

Substitute the value

Then, we get

Heat,[tex]H=\frac{V^2}{R}\times 1[/tex]

[tex]H=\frac{V^2}{R}[/tex]

This is required expression for the heat produced per second in a resistor  in terms of potential difference and resistance​.

Answer:

C2H6 up the road to be with its own in