Answer:
[tex]C=120/2=60[/tex]
Step by step Explanation'
To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.
For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.
Determine the maximum value of C, then the maximum value that C can have is 120/n
Let us represent X as the number of employees with high performance with a binomial distribution of
P =0.02( since the percentage of chance of achieving a high performance level is 2%)
n = 20 ( number of employees who achieve a high performance level)
The probability of X= 0 can be calculated
P( X= 0) = 0.98^n
[tex]P(X=0)=0.98^20[/tex]
[tex]P(X=0)=0.668[/tex]
[tex]P(X=1)=0.02*20*0.98^19[/tex]
[tex]P(X=1)=0.272[/tex]
[tex]P(X=2)=0.02^2*20*0.98^18[/tex]
[tex]P(X=2)=0.053[/tex]
Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)
BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,
Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2
then the maximum value that C can have is 120/n
[tex]C=120/2=60[/tex]
Help me please!!!
10pts
Answer:
-7/2
Step-by-step explanation:
To find the y coordinate of the midpoint and the y coordinates together and divide by 2
(2+-9)/2
-7/2
Answer:
2 goes in green box
Step-by-step explanation:
(9,2) (-7,-9)
(x1, y1) (x2,y2)
Midpoint is (x1+x2)/2 , (y1+y2)/2
(9-7)/2= 1
(2-9)/2 = -7/2
Given that
X : 24 = 6:X
Calculate the positive value of x.
Answer:
X=12
Step-by-step explanation:
Given that: X:24 = 6:X
Then:
[tex]\dfrac{X}{24}= \dfrac{6}{X}\\$Cross multiply\\X^2=24 \times 6\\X^2=144\\X=\pm\sqrt{144}\\X=\pm 12[/tex]
Since we require the positive value of X
X=12.
A sport analyst wants to determine the mean salary of a Baseball player for 2015. He believes an estimate of this average salary using a confidence interval is sufficient. How large a sample should he take to be within $497,000 of the actual average with 80% confidence? He calculates the standard deviation of salary for all baseball players for 2015 is about $5,478,384.55. Round your answer to whole number.
Answer:
The large sample size 'n' = 199.6569≅ 200
Step-by-step explanation:
Step(i):-
Given Standard deviation of salary for all baseball players for 2015 is about $5,478,384.55
Standard deviation of of salary for all baseball players for 2015
(S.D ) σ = $5,478,384.55
Given estimate of this average salary for all baseball players for 2015
= $497,000
Given Margin of error of error is = $497,000
Level of significance ∝ = 80%
The critical value Z₀.₂₀ = 1.282
Step(ii):-
Margin of error of error is determined by
[tex]M.E = \frac{Z_{0.20} S.D}{\sqrt{n} }[/tex]
[tex]497,000 = \frac{1.282 X 5,478,384.55}{\sqrt{n} }[/tex]
Cross multiplication , we get
[tex]\sqrt{n} = \frac{1.282 X 5,478,384.55}{497,000 }[/tex]
On calculation , we get
√n = 14.13
Squaring on both sides, we get
n = 199.6569
Conclusion:-
The large sample size 'n' = 199.6569≅ 200
Please answer this correctly.
Answer:
m=(3+f)/(f-4)
Step-by-step explanation:
To make m the subject of the formula, we want to isolate m. That is, we want to move m to one side of the equation.
First, the fractions need to be taken away. Multiply both sides by m-1 to get: f(m-1)=4m+3.
The distributive property of subtraction tells us a(b-c)=ab-ac. Thus, from this equation we have fm-f=4m+3.
Subtracting 4m, we have fm-4m-f=3
Now, we work the distributive property backwards, where we have ab-ac=a(b-c). Rearrange the terms of fm and 4m, to get mf, and m4. Thus, this can be simplified to m(f-4).
Going back to the equation, we have m(f-4)-f=3.
Add f on both sides, so we have m(f-4)=3+f.
Divide by f-4, so we have m=(3+f)/(f-4)
What is 3/4 divided by 1/6
Answer:
[tex]\frac{9}{2}[/tex]
Step-by-step explanation:
[tex]\frac{3}{4}[/tex] ÷ [tex]\frac{1}{6}[/tex]
Multiply and flip
[tex]\frac{3}{4}[/tex] x [tex]\frac{6}{1}[/tex]
= [tex]\frac{18}{4}[/tex]
= [tex]\frac{9}{2}[/tex]
The value of the division of the two numbers 3/4 and 1/6 results in an improper fraction of 9/2.
To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction.
In this case, we want to divide 3/4 by 1/6, so we multiply 3/4 by the reciprocal of 1/6.
The reciprocal of a fraction is obtained by flipping the fraction upside down. The reciprocal of 1/6 is 6/1 or simply 6.
Therefore, to solve 3/4 divided by 1/6, we can multiply 3/4 by 6:
(3/4) x 6
= (3 x 6) / 4
= 18/4
To simplify the result, we can divide the numerator and denominator by their greatest common divisor, which is 2:
18/4
= (18/2) / (4/2)
= 9/2
So, the division of 3/4 by 1/6 is equal to 9/2.
In mixed number form, 9/2 can be expressed as 4 1/2, meaning there are 4 whole units and 1/2 unit remaining.
Therefore, 3/4 divided by 1/6 is equal to 4 1/2.
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The endpoints of the directed line segment AB are A(−7, 4) and B(8, 9). Find the coordinates of point P along line segment AB so that the ratio of AP to PB is 2 to 3. pls help
Answer:
(-1,5)
Step-by-step explanation:
When a line segment is divided in the ratio m:n, we use the section formula to determine the point P which divides the line segment:
The coordinates of x and y are:
[tex](x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)[/tex]
Given:
[tex]A(x_1,y_1)=(-7, 4)\\B(x_2,y_2)=(8, 9)\\AP:PB=m:n=2:3[/tex]
The coordinates of P is:
[tex](x,y)=\left(\dfrac{2*8+3*-7}{2+3}, \dfrac{2*9+3*4}{2+3}\right)\\=\left(\dfrac{-5}{5}, \dfrac{25}{5}\right)\\\\=(-1,5)[/tex]
It is known that 40% of adult workers have a high school diploma. If a random sample of 10 adult workers is selected, what is the expected number of adult workers with a high school diploma? (That is, what is E(X)?) Round to the whole number. Do not use decimals. Answer:
Answer:
The expected number of adult workers with a high school diploma is 4.
Step-by-step explanation:
This random variable X can be modeled with the binomial distribution, with parameters n=10 (the sample size) and p=0.4 (the probability that a adult worker have a high school diploma).
The expected value of X is then the mean of the binomial distribution with the parameters already mentioned.
This is calculated as:
[tex]E(X)=\mu_b=n\cdot p=10\cdot0.4=4[/tex]
Suppose that weekly income of migrant workers doing agricultural labor in Florida has a distribution with a mean of $520 and a standard deviation of $90. A researcher randomly selected a sample of 100 migrant workers. What is the probability that sample mean is less than $500
Answer:
[tex] z = \frac{500-520}{\frac{90}{\sqrt{100}}}= -2.22[/tex]
And we can find this probability using the normal standard distribution and we got:
[tex] P(z<-2.22) =0.0132[/tex]
Step-by-step explanation:
For this case we have the foolowing parameters given:
[tex] \mu = 520[/tex] represent the mean
[tex] \sigma =90[/tex] represent the standard deviation
[tex] n = 100[/tex] the sample size selected
And for this case since the sample size is large enough (n>30) we can apply the central limit theorem and the distribution for the sample mean would be given by:
[tex] \bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}}) [/tex]
And we want to find this probability:
[tex] P(\bar X <500)[/tex]
We can use the z score formula given by:
[tex] z = \frac{500-520}{\frac{90}{\sqrt{100}}}= -2.22[/tex]
And we can find this probability using the normal standard distribution and we got:
[tex] P(z<-2.22) =0.0132[/tex]
PLEASE HELP ASAP Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false. 1^2+2^2+3^2+...+n^2=n(n+1)(2n+1)/6
Answer:
Step-by-step explanation:
Step 1: Consider P(1) that is n = 1
[tex]1^2 = \frac{1(1+1)(2*1+1)}{6}=\frac{6}{6}=1 \checkmark[/tex]
Step 2: Suppose the equation is true up to n. That is
[tex]1^2 + 2^2+3^2+........+n^2 = \dfrac{n(n+1)(2n+1)}{6 }[/tex]
Step 3: Prove that the equation is true up to (n+1). That is
[tex]1^2 + 2^2+3^2+........+n^2 + (n+1)^2 = \dfrac{(n+1)(n+2)(2n+3)}{6 }[/tex]
The easiest way to prove it is to expend the right hand side and prove that the right hand side = the right hand side of step 2 + (n+1)^2
From step 2, add (n+1)^2 both sides. The left hand side will be the left hand side of step 3, now, the right hand side after adding.
[tex]\dfrac{n(n+1)(2n+1)}{6 }+(n+1)^2 = \dfrac{2n^3+3n^2+n}{6}+\dfrac{6n^2+12n+6}{6}[/tex]
[tex]=\dfrac{2n^3+9n^2+13n+6}{6}[/tex]
If you expend the right hand-side of the step 3, you will see they are same.
Proof done
Answer:
see below
Step-by-step explanation:
1^2+2^2+3^2+...+n^2=n(n+1)(2n+1)/6
Step1
Verify it for n=1
1^2= 1(1+1)(2*1+1)/6= 1*2*3/6= 6/6=1 - correct
Step2
Assume it is correct for n=k
1^2+2^2+3+2+...+k^2= k(k+1)(2k+1)/6
Step3
Prove it is correct for n= k+1
1^2+2^2+3^2+...+(k+1)^2= (k+1)(k+2)(2k+2+1)/6
prove the above for k+1
1^2+2^2+3^2+...+k^2+(k+1)^2= k(k+1)(2k+1)/6 + (k+1)^2=
= 1/6(k(k+1)(2k+1)+6(k+1)^2)= 1/6((k+1)(k(2k+1)+6(k+1))=
=1/6((k+1)(2k²+k+6k+6))= 1/6(k+1)(2k²+4k+3k+6))=
= 1/6(k+1)(2k(k+2)+3(k+2))=
=1/6(k+1)(k+2)(2k+3)
Proved for n= k+1 that:
the sum of squares of (k+1) terms equal to (k+1)(k+2)(2k+3)/6
What is the value of X ?
14
17
24
28
Answer:
24
Step-by-step explanation:
Use the Pythagorean theorem.
Where the sum of the two legs squared is equal to the hypotenuse squared.
10² + x² = 26²
100 + x² = 676
x² = 576
x = √576
x = 24
The value of x is 24.
A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one of the students who takes the examination answers each of the questions with an independent random guess. What is the probability that he answers at least seventeen questions correctly? (Round your answer to three decimal places.)
Answer:
The probability that the student answers at least seventeen questions correctly is [tex]8.03\times 10^{-10}[/tex].
Step-by-step explanation:
Let the random variable X represent the number of correctly answered questions.
It is provided all the questions have five options with only one correct option.
Then the probability of selecting the correct option is,
[tex]P(X)=p=\frac{1}{5}=0.20[/tex]
There are n = 20 question in the exam.
It is also provided that a student taking the examination answers each of the questions with an independent random guess.
Then the random variable can be modeled by the Binomial distribution with parameters n = 20 and p = 0.20.
The probability mass function of X is:
[tex]P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...[/tex]
Compute the probability that the student answers at least seventeen questions correctly as follows:
[tex]P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)[/tex]
[tex]=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}[/tex]
Thus, the probability that the student answers at least seventeen questions correctly is [tex]8.03\times 10^{-10}[/tex].
paulina plays both volleyball and soccer .the probability of her getting injured playing soccer is 1.10 and the probability of her getting injured playing soccer is 0.20 .which of the event is more likely
Which equation can be used to find 150 percent of500
Answer:
150 / 100 x 500
= 150 x 5
= 750
a realtor uses a lock box to store the keys to a house that is for sale. the access code for the lock consist of five digits. the first digit cannot be 1 and the last digit must be even. how many different codes are avaible
Answer:
45,000 codes
Step-by-step explanation:
Given:
Code of 5 digits
Condition
First digit can't be 1Last digit must be evenRequired
Calculate the number of codes available
Digits = {0,1,2....9}
n(Digits) = 10
Let the format of the code be represented as follows;
ABCDE
From the conditions given
A can't be 1;
This means that A can be any of 0,2,3,4....9
This implies that A can be any of the above 9 digits
n(A) = 9
There's no condition attached to BCD;
This means that B can be any of 10 digits
This means that C can be any of 10 digits
This means that D can be any of 10 digits
n(B) = n(C) = n(D) = 10
Lastly, E must be an even number;
This means that E can be any of 0,2,4,6,8
This implies that E can be any of the above 5 digits
n(E) = 5
So,
Number of available codes = n(A) * n(B) * n(C) * n(D) * n(E)
Number of available codes = 9 * 10 * 10 * 10 *5
Number of available codes = 45,000
Hence, there are 45,000 available codes
Juan told Sylvia he got a $0.50 raise this week and his new hourly rate will be $10.25 an hour. Sylvia wants to know what Juan’s hourly rate was before his raise. Which equation and solution can be used to solve this problem? r minus 10.25 = 0.50: Add 10.25 to both sides. The answer is $10.75. r + 0.50 = 10.25: Subtract .50 from both sides. The answer is $9.75. r minus 0.50 = 10.25: Subtract .50 from both sides. The answer is $10.75 r + 10.25 = 0.50: Subtract .50 from both sides. The answer is $9.75.
Answer:
The correct answer is:
r + 0.50 = 10.25: Subtract .50 from both sides. The answer is $9.75.
This is because Juan got a $0.50 raise which means that his new rate will be $0.50 more than his original rate (r).
Answer:
$9.75
Step-by-step explanation:
What is the relative change from Ohio to Indiana if Indiana has 6546 new mathematics teachers and Ohio has 4392 new mathematics teachers? (Round the percentage to the hundredths.)
Answer:
The relative change from Ohio to Indiana is 49.04
Step-by-step explanation:
Alex is paid $30/hr at full rate, and $20/hr at a reduced rate. The hours of work are paid at a ratio of 2:1, full rate : reduced rate. For example, if he worked 3 hours, he would be paid 2 hours at full rate and 1 hour at reduced rate. Calculate his pay for 4 hours of work.
Answer:
$106.67
Step-by-step explanation:
Using the example, for 3 hours work, Alex would be paid ...
(2 hr)($30/hr) +(1 hr)($20/hr) = $60 +$20 = $80
At the same rate of pay, for 4 hours work, the pay would be ...
pay/(4 hr) = $80/(3 hr)
pay = $80(4/3) ≈ $106.67
Alex's pay for 4 hours of work is $106.67.
A survey shows that 10% of the population is victimized by property crime each year. A random sample of 527 older citizens (65 years or more of age) shows a victimization rate of 12.35%. Are older people more likely to be victimized
Answer:
We conclude that older people are more likely to be victimized.
Step-by-step explanation:
We are given that a survey shows that 10% of the population is victimized by property crime each year.
A random sample of 527 older citizens (65 years or more of age) shows a victimization rate of 12.35%
Let p = population proportion of people who are victimized.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]p \leq[/tex] 10% {means that older people are less likely to be victimized or remains same}
Alternate Hypothesis, [tex]H_A[/tex] : p > 10% {means that older people are more likely to be victimized}
The test statistics that would be used here One-sample z-test for proportions;
T.S. = [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of older people who are victimized = 12.35%
n = sample of older citizens = 527
So, the test statistics = [tex]\frac{0.1235-0.10}{\sqrt{\frac{0.10(1-0.10)}{527} } }[/tex]
= 1.798
The value of z-test statistics is 1.798.
Since in the question, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for right-tailed test.
Since our test statistics is more than the critical value of z as 1.798 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that older people are more likely to be victimized.
Which residual plot shows that the model is a good fit for the data?
Answer: the answer is c (the third answer ) ‼️
Step-by-step explanation:
The data in the given residual plot shows that model C has the best fit.
What is a line of fit?A straight line that minimizes the gap between it and some data is called a line of best fit. In a scatter plot containing various data points, a relationship is expressed using the line of best fit.
Given:
The residual plot of the values in the graph,
The points in the first graph are very far from the x-axis and y-axis so, it is not the best fit,
The points in the second graph are very far from the x-axis and y-axis, and they are symmetric to the y-axis but not the best fit.
Most of the points are close to the x-axis, so it is the best fit,
Thus, the third graph is the best line of fit.
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Mary pays income tax according to the graduated schedule shown below. A 3-column table with 6 rows. Column 1 is labeled If taxable income is over with entries 0 dollars, 7,825 dollars, 31,850 dollars, 77,100 dollars, 160,850 dollars, 349,700 dollars. Column 2 is labeled but not over with entries 7,825 dollars, 31,850 dollars, 77,100 dollars, 160,850 dollars, 349,700 dollars, no limit. Column 3 is labeled the tax is with entries 10 percent of the amount of 0 dollars, 782 dollars and 50 cents plus 15 percent of the amount of 7,825 dollars, 4,386 dollars and 25 cents plus 25 percent of the amount of 31,850 dollars, 15,698 dollars and 75 cents plus 28 percent of the amount over 77,100 dollars, 39,148 dollars and 75 cents plus 33 percent of the amount of 160,850 dollars, 101,469 dollars and 25 cents plus 35 percent of the amount over 349,700 dollars. If Mary’s taxable income is $68,562, how much income tax does she owe, rounded to the nearest dollar?
Answer:
$13564
Step-by-step explanation:
[tex]\left|\begin{array}{c|c|c}$If taxable&& \\$income&&\\$ is over&$but not over&$the tax is\\---&---&---\\$0 &7,825 &$10\% of the amount over 0\\7,825 &31,850 &$782.50 plus $15\% $ of the amount over 7,825$ \end{array}\right|[/tex][tex]\left|\begin{array}{c|c|c}31,850 &77,100 &$4,386.25 plus 25\% of the amount over 31,850 \\77,100 &160,850 &$15,698.75 plus 28\% of the amount over 77,100\end{array}\right|[/tex]
[tex]\left|\begin{array}{c|c|c}160,850 &349,700 &$39,148.75 plus 33\% of the amount over 160,850 \\349,700 &$no limit&$101,469.25 plus 35\% of the amount over 349,700\end{array}\right|[/tex]
Mary’s taxable income= $68,562
From the table, If taxable income is over $31,850 but not over $77,100
The tax = $4386.25 + 25% of the amount over 31,850
Amount over $31,850=$68,562-$31,850
=$36,712
Therefore:
Mary's tax = $4386.25 + (25% of $36,712)
=$4386.25 +9,178
=$13564.25
=$13564 (to the nearest dollar)
Income tax is the tax charged on individual's or entities' income
Mary owes $13564 income tax
Given that the taxable income is $68,562.
Using the table as a guide, $68,562 falls within the income range $31,850 - $77,100
So, the tax is $4386 added to 25% of the excess over $31850
This is calculated as:
[tex]Tax = \$4386 + 25\% \times (Income -\$31850)[/tex]
Substitute $68,562 for income
[tex]Tax = \$4386 + 25\% \times (\$68562 -\$31850)[/tex]
Solve the expression in the bracket
[tex]Tax = \$4386 + 25\% \times \$36712[/tex]
Evaluate the product
[tex]Tax = \$4386 + \$9178[/tex]
Add the terms of the expression
[tex]Tax = \$13564[/tex]
Hence, Mary owes $13564 income tax
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For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent Mercer survey showed that 52% of U.S. employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 700 companies. Compute the margin of error and a 95% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage. If required, round your answer to four decimal places. Round intermediate calculations to four decimal places. Margin of Error: Confidence Interval: to
Answer:
The 95% confidence interval estimate of the true population proportion of U.S. employers that were likely to require higher employee contributions for health care coverage is 0.52 +/- 0.0370
= (0.4830, 0.5570)
The margin of error M.E = 0.0370
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
p+/-z√(p(1-p)/n)
p+/-M.E
Given that;
M.E = margin of error
Proportion p = 52% = 0.52
Number of samples n = 700
Confidence interval = 95%
z value (at 95% confidence) = 1.96
Substituting the values we have;
0.52 +/- 1.96√(0.52(1-0.52)/700)
0.52 +/- 1.96(0.0189)
0.52 +/- 0.0370
( 0.4830, 0.5570)
The 95% confidence interval estimate of the true population proportion of U.S. employers that were likely to require higher employee contributions for health care coverage is 0.52 +/- 0.0370
= (0.4830, 0.5570)
The margin of error M.E = 0.0370
Multiply
(-19/29)(11y)
Answer:
[tex]=\frac{-209}{29}y[/tex]
I hope this help you :)
A builder was paid £550 for the work he did. He spent 35% of the money on materials how much did the materials cost
Answer: £192.50
Step-by-step explanation:
550 x 0.35 = 192.50
A Student select a marble from a bag, keeps it and select another. The bag contains 5 Green marbles 4 black marbles and 2 blue marbles. Find the probability of selecting a green marble on the first trial and a black marble on the second trial.
Answer:
Yes because yes.
Step-by-step explanation:
Y + e + s = Yes
Rasheeda sees a garden in a book. She changes the scale because she wants a garden with different dimensions. The figure below shows both scales and a scale drawing of the garden.
Book scale: 1 inch = 2 feet. Rasheeda's Scale: 2 inches = 3 feet. A rectangle with length A of 18 inches and width B of 6 inches.
Which statements about the gardens are true? Select three options.
Answer:
B. Length A of Rasheeda’s garden is 27 ft.
C. Length B of the book’s garden is 12 ft.
E. Length A of the book’s garden is 9 ft longer than length A of Rasheeda’s garden.
Step-by-step explanation:
step 1
Find the dimension of the book's garden
we know that
Book scale: 1 inch = 2 feet
That means
1 inch in the drawing represent 2 feet in the actual
To find out the actual dimensions, multiply the dimension in the drawing by 2
so
Length A of the book’s garden
Width B of the book’s garden
step 2
Find the dimension of Rasheeda’s garden
we know that
Rasheeda's Scale: 2 inch = 3 feet
That means
2 inch inches the drawing represent 3 feet in the actual
To find out the actual dimensions, multiply the dimension in the drawing by 3 and divided by 2
so
Length A of Rasheeda's garden
Width B of Rasheeda's garden
Verify each statement
A. Length A of the book’s garden is 18 ft.
The statement is false
Because, Length A of the book’s garden is 36 ft (see the explanation)
B. Length A of Rasheeda’s garden is 27 ft.
The statement is true (see the explanation)
C. Length B of the book’s garden is 12 ft
The statement is true (see the explanation)
D. Length B of Rasheeda’s garden is 6 ft.
The statement is false
Because, Length B of Rasheeda’s garden is 9 ft. (see the explanation)
E. Length A of the book’s garden is 9 ft longer than length A of Rasheeda’s garden.
The statement is true
Because the difference between 36 ft and 27 ft is equal to 9 ft
F. Length B of the book’s garden is 3 ft shorter than length B of Rasheeda’s garden.
The statement is false
Because, Length B of the book’s garden is 3 ft greater than length B of Rasheeda’s garden.
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Answer:
B. Length A of Rasheeda’s garden is 27 ft.
C. Length B of the book’s garden is 12 ft.
E. Length A of the book’s garden is 9 ft longer than length A of Rasheeda’s garden.
(second, third, and fifth choices)
Explanation: I did the quiz and got it right.
Hope this Helps!
What is the coefficient in this expression? 5 minus 4.7 minus 2 x + StartFraction 5 over 8 EndFraction
Answer:
2 is the coefficient
Step-by-step explanation:
2 is the coefficient bc a coefficient is the number next to a variable (such as x) and 2 is next to x and is the only one in the equation
Answer:
-2
Step-by-step explanation:
I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
Answer:
[tex] \frac{4 {x }^{2} - 17x - 9 }{ {x}^{3} - 7 {x}^{2} + 7x + 15 } [/tex]
Step-by-step explanation:
In the picture.
I hope I am correct
I hope it helps :)
outline any four views of how people approach curriculum
Answer:
they may like it
they may dislike it
Step-by-step explanation:
they amy think ots essentiall
they may think its unescary
Solve for x. whats the solutions from least to greatest. 4x^2 + 48x + 128 = 0
Answer:
[tex]\boxed{\sf \ \ \ x = -8 \ or \ x = -4 \ \ \ }[/tex]
Step-by-step explanation:
Hello,
[tex]4x^2+48x+128=0\\<=> 4(x^2+12x+32)=0\\<=> x^2+12x+32=0\\<=> (x+6)^2 - 36 + 32= 0\\\\<=> (x+6)^2-4=0\\<=> (x+6+2)(x+6-2)=0\\<=> (x+8)(x+4) = 0\\<=> x = -8 \ or \ x = -4[/tex]
vouch, i confirm that -8, -4 are the answers
two technicians regularly make repairs when breakdowns occur on an automated production line. the first technican, who services 40% of the breakdowns, has 5% chance of making incomplete repair. the second technican, who services 60% of the breakdowns, has 3% chance of making an incomplete repair. given that there is a problem with the production line due to an incomplete repair, what is the probability that thids intial repair was made by the first technican
Answer:
52.63% probability that thids intial repair was made by the first technican
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)}[/tex]
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Incomplete repair
Event B: Made by the first technican.
The first technican, who services 40% of the breakdowns, has 5% chance of making incomplete repair.
This means that [tex]P(B) = 0.4, P(A|B) = 0.05[/tex].
Probability of an incomplete repair:
5% of 40%(first technican) or 3% of 60%(second technican). So
[tex]P(A) = 0.05*0.4 + 0.03*0.6 = 0.038[/tex]
Given that there is a problem with the production line due to an incomplete repair, what is the probability that thids intial repair was made by the first technican
[tex]P(B|A) = \frac{0.4*0.05}{0.038} = 0.5263[/tex]
52.63% probability that thids intial repair was made by the first technican