Answer:
There is enough evidence at the α-: 0.05 level of significance to support the claim that the true population mean market value of houses in the neighborhood where Rebecca works is greater than $250,000.
Step-by-step explanation:
We are given that Rebecca randomly selects 35 houses in the neighborhood and finds that the sample mean market value is $259,860 with a sample standard deviation of $24.922.
Let [tex]\mu[/tex] = population mean market value of houses in the neighborhood.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = $250,000 {means that the population mean market value of houses in the neighborhood where she works is equal to $250,000}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $250,000 {means that the population mean market value of houses in the neighborhood where she works is greater than $250,000}
The test statistics that would be used here One-sample t-test statistics because we don't know about population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean market value = $259,860
s = sample standard deviation = $24,922
n = sample of houses = 35
So, the test statistics = [tex]\frac{259,860-250,000}{\frac{24,922}{\sqrt{35} } }[/tex] ~ [tex]t_3_4[/tex]
= 2.34
The value of t-test statistic is 2.34.
Also, P-value of the test statistics is given by;
P-value = P([tex]t_3_4[/tex] > 2.34) = 0.0137
Since our P-value is less than the level of significance as 0.0137 < 0.05, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that the population mean market value of houses in the neighborhood where she works is greater than $250,000.
HELP ME Answer it from the forst one to the last one with the rght answer please.This is Urgent so do it Faster if u now the answers
Step-by-step explanation:
2) 63
3) 7000
4) 10
These are some answers
A film distribution manager calculates that 4% of the films released are flops. If the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%
Answer:
9.34%
Step-by-step explanation:
p = 4%, or 0.04
n = Sample size = 667
u = Expected value = n * p = 667 * 0.04 = 26.68
SD = Standard deviation = [tex]\sqrt{np(1-p)} =\sqrt{667*0.04*(1-0.04)}[/tex] = 5.06
Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?
This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35
Since,
Z = (X - u) / SD
We have;
Z = (33.35 - 26.68) / 5.06
Z = 1.32
From the Z-table, the p-value of 1.32 is 0.9066
1 - 0.9066 = 0.0934, or 9.34%
Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.
In a certain community, eight percent of all adults over age 50 have diabetes. If a health service in this community correctly diagnosis 95% of all persons with diabetes as having the disease and incorrectly diagnoses ten percent of all persons without diabetes as having the disease, find the probabilities that:
Complete question is;
In a certain community, 8% of all people above 50 years of age have diabetes. A health service in this community correctly diagnoses 95% of all person with diabetes as having the disease, and incorrectly diagnoses 10% of all person without diabetes as having the disease. Find the probability that a person randomly selected from among all people of age above 50 and diagnosed by the health service as having diabetes actually has the disease.
Answer:
P(has diabetes | positive) = 0.442
Step-by-step explanation:
Probability of having diabetes and being positive is;
P(positive & has diabetes) = P(has diabetes) × P(positive | has diabetes)
We are told 8% or 0.08 have diabetes and there's a correct diagnosis of 95% of all the persons with diabetes having the disease.
Thus;
P(positive & has diabetes) = 0.08 × 0.95 = 0.076
P(negative & has diabetes) = P(has diabetes) × (1 –P(positive | has diabetes)) = 0.08 × (1 - 0.95)
P(negative & has diabetes) = 0.004
P(positive & no diabetes) = P(no diabetes) × P(positive | no diabetes)
We are told that there is an incorrect diagnoses of 10% of all persons without diabetes as having the disease
Thus;
P(positive & no diabetes) = 0.92 × 0.1 = 0.092
P(negative &no diabetes) =P(no diabetes) × (1 –P(positive | no diabetes)) = 0.92 × (1 - 0.1)
P(negative &no diabetes) = 0.828
Probability that a person selected having diabetes actually has the disease is;
P(has diabetes | positive) =P(positive & has diabetes) / P(positive)
P(positive) = 0.08 + P(positive & no diabetes)
P(positive) = 0.08 + 0.092 = 0.172
P(has diabetes | positive) = 0.076/0.172 = 0.442
Using formula:
[tex]P(\text{diabetes diagnosis})\\[/tex]:
[tex]=\text{P(having diabetes and have been diagnosed with it)}\\ + \text{P(not have diabetes and yet be diagnosed with diabetes)}[/tex]
[tex]=0.08 \times 0.95+(1-0.08) \times 0.10 \\\\=0.08 \times 0.95+0.92 \times 0.10 \\\\=0.076+0.092\\\\=0.168[/tex]
[tex]\text{P(have been diagnosed with diabetes)}[/tex]:
[tex]=\frac{\text{P(have diabetic and been diagnosed as having insulin)}}{\text{P(diabetes diagnosis)}}[/tex]
[tex]=\frac{0.08\times 0.95}{0.168} \\\\=\frac{0.076}{0.168} \\\\=0.452\\[/tex]
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find the are of the kite.
a. 96 ft^2
b.192 ft^2
c.64 ft^2
d.348 ft^2
Answer:
A
Step-by-step explanation:
The area of a kite is half of the product of the length of the diagonals, or in this case 16*12/2=96 square feet. Hope this helps!
Answer:
a. 96 ft^2
Step-by-step explanation:
You can cut the kite into 2 equal triangle halves vertically.
Then you can use the triangle area formula and multiply it by 2 since there are 2 triangles.
[tex]\frac{1}{2} *12*8*2=\\6*8*2=\\48*2=\\96ft^2[/tex]
The kite's area is a. 96 ft^2.
finding angle measures between intersecting lines.
Answer: x=45°
Step-by-step explanation:
Angles opposite from each other are equal. The angle 160 degrees in red on the bottom encompasses two angles: BEG and CEG. Angle BEG is on the opposite side as FEA which means it is equal to x.
Since angle FED on the other side is 115, you subtract 115 from 160 to get 45 degrees.
Answer: x=45°
The angle BEG, which is opposite to the angle FEA, is determined to be 45 degrees.
According to the information provided, in a figure with an angle of 160 degrees (red angle on the bottom), there are two angles labeled as BEG and CEG. It is stated that the angle BEG is opposite to the angle FEA, making them equal, so we can represent this angle as x.
Additionally, it is mentioned that the angle FED on the other side measures 115 degrees.
To find the value of x, we subtract 115 degrees from the angle of 160 degrees.
=160-115
= 45
Thus, the solution is x = 45°.
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pls help me I would be happy if do
Answer:
a prism is a three dimensional shape with the same width all the way through.
Step-by-step explanation:
Step-by-step explanation:
i think this will help.
What is the greatest integer value of y for whic 5y - 20 < 0 ?
Answer:
3
Step-by-step explanation:
Step 1: Isolate y
5y < 20
y < 4
When we figure out the inequality, we see that y has to be less than 4. Therefore, the highest integer value will have to be 3.
A line has a slope of -3/2 and has a y-intercept of 3. What is the x-intercept of the line?
Answer:
x = 2
Step-by-step explanation:
the equation of the line can be found using the slope intercept form
y = mx +b
y= -3/2 x + 3
x intercept is found by setting y=0 bc that will give you the x-value at which the line crosses the x -axis so
0 = -3/2x+3 (subtract the 3 on both sides) would cancel out the + 3 and would
-3 = -3/2 x (divide by -3/2 on both sides to cancel out the -3/2)
x = 2
Allie Maxudywishes to retire 25 years. She has decided that she should be able to invest $5000 per year in her retirement fund. If she makes the payments in quarterly installments at the beginning of the each year, and earn an annual percentage rate of 8% on her money how much she will have at the time of her retirement?
Answer:
$394,772.11
Step-by-step explanation:
This requires using compound interest as follows:
Principal = $5,000
Time = 25 years
Interest rate per annum = 8%
1st year: principal = 5000
Interest capitalized (5000*0.08) = 400
Amount (5000 + 400) = $5400
2nd year: principal = 5400 + 5000 = 10,400
Interest capitalized (10,400*0.08) = 832
Amount (10,400 + 832) = $11,232
3rd year: principal = 11,232+5000 = $16,232
Interest capitalized (16,232*0.08) = 1,298.56
Amount (16,232+1,298.56) = $17,530.56
4th year: principal = 17,530.56+5000 = $22,530.56
Interest capitalized (22,530.56*0.08) = 1,802.45
Amount (22,530.56+1,802.45) = $24,333.01
5th year: principal = 24,333.01+5000 = $29,333.01
Interest capitalized (29,333.01 * 0.08) = 2,346.64
Amount (29,333.01 + 2,346.64) = $31,679.65
6th year: principal = 31,679.65 + 5000 = $36,679.65
Interest capitalized (36,679.65 * 0.08) = 2,934.37
Amount (36,679.65 + 2,934.37) = $39,614.02
7th year: principal = 39,614.02 + 5000 = $44,614.02
Interest capitalized (44,614.02 * 0.08) = 3,569.12
Amount (44,614.02 + 3,569.12) = $48,183.14
8th year: principal = 48,183.14 + 5000 = $53,183.14
Interest capitalized (53,183.14 * 0.08) = 4,254.65
Amount (53,183.14 + 4,254.65) = $57,437.79
9th year: principal = 57,437.79 + 5000 = $62,437.79
Interest capitalized (62,437.79 * 0.08) = 4,995.02
Amount (62,437.79 + 4,995.02) = $67,432.81
10th year: principal = 67,432.81 + 5000 = $72,432.81
Interest capitalized (72,432.81 * 0.08) = 5,794.63
Amount (72,432.81 + 5,794.63) = $78,227.44
11th year: principal = 78,227.44 + 5000 = $83,227.44
Interest capitalized (83,227.44 * 0.08) = 6,658.20
Amount (83,227.44 + 6,658.20) = $89,885.64
12th year: principal = 89,885.64 + 5000 = $94,885.64
Interest capitalized (94,885.64 * 0.08) = 7,590.85
Amount (94,885.64 + 7,590.85) = $102,476.49
13th year: principal = 102,476.49 + 5000 = $107,476.49
Interest capitalized (107,476.49 * 0.08) = 8,598.12
Amount (107,476.49 + 8,598.12) = $116,074.61
14th year: principal = 116,074.61 + 5000 = $121,074.61
Interest capitalized (121,074.61 * 0.08) = 9,685.97
Amount (121,074.61 + 9,685.97) = $130,760.58
15th year: principal = 130,760.58 + 5000 = $135,760.58
Interest capitalized (135,760.58 * 0.08) = 10,860.85
Amount (135,760.58 + 10,860.85) = $146,621.43
16th year: principal = 146,621.43 + 5000 = $151,621.43
Interest capitalized (151,621.43 * 0.08) = 12,129.71
Amount (151,621.43 + 12,129.71) = $163,751.14
17th year: principal = 163,751.14 + 5000 = $168,751.14
Interest capitalized (168,751.14 * 0.08) = 13,500.09
Amount (168,751.14 + 13,500.09) = $182,251.23
18th year: principal = 182,251.23 + 5000 = $187,251.23
Interest capitalized (187,251.23 * 0.08) = 14,980.10
Amount (187,251.23 + 14,980.10) = $202,231.33
19th year: principal = 202,231.33 + 5000 = $207,231.33
Interest capitalized (207,231.33 * 0.08) = 16,578.51
Amount (207,231.33 + 16,578.51) = $223,809.84
20th year: principal = 223,809.84 + 5000 = $228,809.84
Interest capitalized (228,809.84 * 0.08) = 18,304.79
Amount (228,809.84 + 18,304.79) = $247,114.63
21st year: principal = 247,114.63 + 5000 = $252,114.63
Interest capitalized (252,114.63 * 0.08) = 20,169.17
Amount (252,114.63 + 20,169.17) = $272,283.8
22nd year: principal = 272,283.8 + 5000 = $277,283.8
Interest capitalized (277,283.8 * 0.08) = 22,182.70
Amount (277,283.8 + 22,182.70) = $299,466.5
23rd year: principal = 299,466.5 + 5000 = $304,466.5
Interest capitalized (304,466.5 * 0.08) = 24,357.32
Amount (304,466.5 + 24,357.32) = $328,823.82
24th year: principal = 328,823.82 + 5000 = $333,823.82
Interest capitalized (333,823.82 * 0.08) = 26,705.91
Amount (333,823.82 + 26,705.91) = $360,529.73
25th year: principal = 360,529.73 + 5000 = $365,529.73
Interest capitalized (365,529.73 * 0.08) = 29,242.38
Amount (365,529.73 + 29,242.38) = $394,772.11
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of decay is proportional to the amount of the substance present at time t, determine the half-life of the radioactive substance. (Round your answer to one decimal place.)
The radioactive compound has a half-life of around 3.09 hours.
The period of time needed for a radioactive substance's initial quantity to decay by half is known as its half-life. The half-life of a drug may be calculated as follows if the rate of decay is proportionate to the amount of the substance existing at time t:
Let t be the half-life of the substance, then after t hours, the amount of the substance present will be,
100 mg × [tex]\dfrac{1}{2}[/tex] = 50 mg.
At time 6 hours, the amount of the substance present is,
100 mg × (1 - 3%) = 97 mg.
Given that the amount of material available determines how quickly something degrades,
The half-life can be calculated as follows:
[tex]t = 6 \times \dfrac{50}{ 97} = 3.09 \ hours[/tex]
Therefore, the half-life of the radioactive substance is approximately 3.09 hours.
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How many different triangles can you make if you are given
these three lengths for sides?
Answer:
Step-by-step explanation:
i think its 3
Answer:
0
Step-by-step explanation:
You cannot make any triangles with this angle
Please answer this correctly
Answer:
101-120=4
Step-by-step explanation:
All that you need to do is count how many data points fall into this category. In this case, there are four data points that fall into the category of 101-120 pushups
111111105113Therefore, the answer to the blank is 4. If possible, please mark brainliest.
Answer:
There are 4 numbers between 101 and 120.
Step-by-step explanation:
101-120: 105, 111, 111, 113 (4 numbers)
According to a Harris Poll in 2009, 72% of those who drive and own cell phones say they use them to talk while they are driving. If you wish to conduct a survey in your city to determine what percent of the drivers with cell phones use them to talk while driving, how large a sample should be if you want your estimate to be within 0.02 with 95% confidence.
Answer:
We need a sample of at least 1937.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
For this problem, we have that:
[tex]\pi = 0.72[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
How large a sample should be if you want your estimate to be within 0.02 with 95% confidence.
We need a sample of at least n.
n is found when M = 0.02. So
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.02 = 1.96\sqrt{\frac{0.72*0.28}{n}}[/tex]
[tex]0.02\sqrt{n} = 1.96\sqrt{0.72*0.28}[/tex]
[tex]\sqrt{n} = \frac{1.96\sqrt{0.72*0.28}}{0.02}[/tex]
[tex](\sqrt{n})^{2} = (\frac{1.96\sqrt{0.72*0.28}}{0.02})^{2}[/tex]
[tex]n = 1936.16[/tex]
Rounding up to the nearest number.
We need a sample of at least 1937.
A human resource manager for a large company takes a random sample of 60 employees from the company database. Based on the sample she calculates a 95% confidence interval for the mean time of employment for all employees to be 8.7 to 15.2 years. Which of the following will provide a more informative (i.e., narrower) confidence interval than the 95% confidence interval?
A. Using a 90% confidence level (instead of 95%)
B. Using a 99% confidence level (instead of 95%)
C. Using a sample size of 40 employees (instead of 60)
D. Using a sample size of 90 employees (instead of 60)
Answer:
A. Using a 90% confidence level (instead of 95%)
D. Using a sample size of 90 employees (instead of 60)
Step-by-step explanation:
The margin of error of a confidence interval is given by:
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which z is related to the confidence level, [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
The higher the margin of error, the less precise the confidence interval is.
We have:
A 95% confidence interval, with a sample of 60.
We want to make it more precise:
Two options, decrease z(decrease the confidence level), or increase n(increase the sample size).
So the correct options are:
A. Using a 90% confidence level (instead of 95%)
D. Using a sample size of 90 employees (instead of 60)
If an image of a triangle is congruent to the pre-image, what is the scale factor of the dilation?
0.1
1/2
1
10
Find all real solutions of the equation.
x7 + 64x4 = 0
Answer:
Let's solve your equation step-by-step.
[tex]x^7+64x^4=0[/tex]
Step 1: Factor left side of equation.
[tex]x^4(x+4)(x^2-4x+16)=0[/tex]
Step 2: Set factors equal to 0.
[tex]x^4=0[/tex] or [tex]x+4=0[/tex] or [tex]x^2-4x+16=0[/tex]
[tex]x^4=0[/tex] or [tex]x=0[/tex]
Answer:
x=0 or x=0 or x=−4I hope this help you :)
Please answer this correctly
Answer:
Hiking: 28%
Canoeing: 16%
Swimming: 24%
Fishing: 32%
Step-by-step explanation:
21 + 12 + 18 + 24 = 75 (there are 75 campers)
21 out of 75 = 28%
12 out of 75 = 16%
18 out of 75 = 24%
24 out of 75 = 32%
Hope this helps!
Please mark Brainliest if correct
Write an expression without exponent that is equivalent to 2 to 3rd power nd 4 to the 3rd power
Answer:
2 to the 3rd power,
2*2*2
4 to the 3rd power,
4*4*4
Step-by-step explanation:
The "3rd power" means how many times the number given to it would be multiplied. Aka, 2 to the 4th power would mean 2 times 2 times 2 times 2, (2 four times).
How many solutions does 6-3x=4-x-3-2x have?
Answer:
no solutions
Step-by-step explanation:
6-3x=4-x-3-2x
Combine like terms
6-3x =1 -3x
Add 3x to each side
6 -3x+3x = 1-3x+3x
6 =1
This is not true so there are no solutions
Answer:
No solutions.
Step-by-step explanation:
6 - 3x = 4 - x - 3 - 2x
Add or subtract like terms if possible.
6 - 3x = -3x + 1
Add -1 and 3x on both sides.
6 - 1 = -3x + 3x
5 = 0
There are no solutions.
In triangle ABC, the measure of angle A is half the measure of angle B, and the measure of angle C is 50° less than the measure of angle B. Find the measure of the smallest angle. (Recall that the sum of the measures of the angles in a triangle is 180°.)
Answer:
42º
Step-by-step explanation:
You can start by setting up the equations that are given in the stem of the problem: a=.5b, c=b-50, a+b+c=180. Then plug in the values of b in relation to the other values into the equation a+b+c=180. This will give you (.5b)+b+(b-50)=180. By expanding this and combining like terms, we will get 2.5b=230. By dividing each side by 2.5, we get b=92. Then, referencing the first equations, a=.5(92)=46, and c=92-50=42. The smallest of all of these is c, 42.
Please answer this correctly
Answer:
The second graph.
Step-by-step explanation:
0-9: 6 numbers
10-19: 2 numbers
20-29: 1 number
30-39: 3 numbers
40-49: 1 number
50-59: 2 numbers
60-69: 0 numbers
70-79: 5 numbers
80-89: 3 numbers
90-99: 1 number
dakota received a bonus check for $2,500 and is going to deposit the money into a bank account that receives 5.5% compounded annually. What is dakotas account balance after five years?
Answer: $3267.40
Step-by-step explanation:
A = P (1+r/n)^nt
A= 2500 (1+0.055)^nt
A= 2500 x 1.30696
A = 3267.40
Which of the following is not an undefined term?
point, ray, line, plane
Answer:
Step-by-step explanation:
Ray
Answer:
ray
Step-by-step explanation:
ray is a part of a line that has an endpoint in one side and extends indefinitely on the opposite side. hence, the answer is ray
hope this helps
Which fraction is equivalent to 20%?
Answer:
1/5
Step-by-step explanation:
20*5 = 100, so 20 is 1/5
John took all his money from his savings account. He spent $48 on a radio and 3/8 of what was left on presents for his friends. Of the money remaining, John put 2/3 into a checking account and the last remaining $100 was left to charity. How much money did John orginally have in his savings account?
Answer:
Step-by-step explanation:
Let a = original amt in the savings account
"He spent $48 on a radio and 3/8 of what was left on presents for his friends."
Therefore he kept 5/8 of what was left
5/8(a - 48)
5/8(a - 30) left
:
John then put 2/3 of his remaining money into a checking account and donated the $100 that was left to charity.
a = 2/3(5/8a - 30) + 100
a = 5/12a - 20 + 100
a = 5/12a + 80
a - 5/12a = 80
7/12a = 80
a = $137.17 originally in his saving acct
PLEASE HELP ME WITH THIS, HELP NEEDED ASAP
Answer:
x = 16.5
Step-by-step-explanation:
The height of the larger triangle is 11, and the height of smaller triangle is 2. Which means that the larger triangle height is 5.5 times greater than the smaller triangle's height.
If the base of the smaller triangle is 3, that means that base of the whole/larger triangle is 16.5 because 3 * 5.5 = 16.5
11. cos theta = 3/4, in quadrant 1
Answer:
Step-by-step explanation:sin
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Hee lllp!!! Now 70 points
Answer:
[tex]\huge\boxed{Option \ 1}[/tex]
Step-by-step explanation:
Since, AE = CE and BE = DE , then E is the midpoint of AC and BD. Causius can use that to show that AC and BD bisect each other which means that they both are the diagonals of a parallelogram bisecting each other. Hence, It will be proved that ABCD is a || gm.
Hope this helped!
~AnonymousHelper1807A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimate μ. (Round your answers to four decimal places.)
Required:
a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)?
b. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?
Answer:
a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.
b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
[tex]\mu = 200, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5[/tex]
a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)?
This is the pvalue of Z when X = 200 + 5 = 205 subtracted by the pvalue of Z when X = 200 - 5 = 195.
Due to the Central Limit Theorem, Z is:
[tex]Z = \frac{X - \mu}{s}[/tex]
X = 205
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{205 - 200}{5}[/tex]
[tex]Z = 1[/tex]
[tex]Z = 1[/tex] has a pvalue of 0.8413.
X = 195
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{195 - 200}{5}[/tex]
[tex]Z = -1[/tex]
[tex]Z = -1[/tex] has a pvalue of 0.1587.
0.8413 - 0.1587 = 0.6426
0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.
b. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?
This is the pvalue of Z when X = 210 subtracted by the pvalue of Z when X = 190.
X = 210
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{210 - 200}{5}[/tex]
[tex]Z = 2[/tex]
[tex]Z = 2[/tex] has a pvalue of 0.9772.
X = 195
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{190 - 200}{5}[/tex]
[tex]Z = -2[/tex]
[tex]Z = -2[/tex] has a pvalue of 0.0228.
0.9772 - 0.0228 = 0.9544
0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.
(a): The required probability is [tex]P(195 < \bar{x} < 205)=0.6826[/tex]
(b): The required probability is [tex]P(190 < \bar{x} < 200)=0.9544[/tex]
Z-score:
A numerical measurement that describes a value's relationship to the mean of a group of values.
Given that,
mean=200
Standard deviation=50
[tex]n=100[/tex]
[tex]\mu_{\bar{x}}=200[/tex]
[tex]\sigma{\bar{x}} =\frac{\sigma}{\sqrt{n} } \\=\frac{50}{\sqrt{100} }\\ =5[/tex]
Part(a):
within [tex]5=200\pm 5=195,205[/tex]
[tex]P(195 < \bar{x} < 205)=P(-1 < z < 1)\\=P(z < 1)-P(z < -1)\\=0.8413-0.1587\\=0.6826[/tex]
Part(b):
within [tex]10=200\pm 10=190,200[/tex]
[tex]P(190 < \bar{x} < 200)=P(-1 .98 < z < 1.98)\\=P(z < 2)-P(z < -2)\\=0.9772-0.0228\\=0.9544[/tex]
Learn more about the topic Z-score:
https://brainly.com/question/5512053
Lard-O potato chips guarantees that all snack-sized bags of chips are between 16 and 17 ounces. The machine that fills the bags has an output with a mean of 16.5 and a standard deviation of 0.25 ounces. Construct a control chart for the Lard-O example using 3 sigma limits if samples of size 5 are randomly selected from the process. The center line is ____. The standard deviation of the sample mean is ____. The UCL
Answer:
- The center line is at 16.5 ounces.
- The standard deviation of the sample mean = 0.112 ounce.
- The UCL = 16.836 ounces.
- The LCL = 16.154 ounces.
Step-by-step explanation:
The Central limit theorem allows us to write for a random sample extracted from a normal population distribution with each variable independent of one another that
Mean of sampling distribution (μₓ) is approximately equal to the population mean (μ).
μₓ = μ = 16.5 ounces
And the standard deviation of the sampling distribution is given as
σₓ = (σ/√N)
where σ = population standard deviation = 0.25 ounce
N = Sample size = 5
σₓ = (0.25/√5) = 0.1118033989 = 0.112 ounce
Now using the 3 sigma limit rule that 99.5% of the distribution lies within 3 standard deviations of the mean, the entire distribution lies within
(μₓ ± 3σₓ)
= 16.5 ± (3×0.112)
= 16.5 ± (0.336)
= (16.154, 16.836)
Hope this Helps!!!