Answer:
495 students
Step-by-step explanation:
The 4 part of the ratio is the number of boys.
Divide the number of boys by 4 to find the value of one part of the ratio.
220 ÷ 4 = 55 ← value of 1 part of the ratio, thus
5 parts = 5 × 55 = 275 ← number of girls
Number of students = 220 + 275 = 495
Answer:
495 studentsStep-by-step explanation:
[tex]220 \: boys \\ 4:5 = 4 + 5 \\ boys \: = \frac{4}{9} \times x = 220 \\ = \frac{4x}{9} = \frac{220}{1} [/tex]
[tex]4x = 1980 \\ \frac{4x}{4} = \frac{1980}{4} \\ x = 495 \\ total \: no \: of \: students \: = 495 \\ [/tex]
the table shows the heights of 40 students in a class calculate an estimate for the mean height of the students
Answer:
For mean
To show the mean of height measures for 40 students, you need to write-out exactly 40 heights into a calculator and add them up.
Then divide that total number by 40.
Step-by-step explanation:
Eg for 4 students
5 , 5.1, 5.2, 5.7 = 21ft
21/4 = 5.25ft.
Apply the same method but use 40 measures in addition for calulator or long addition. Then divide by 40.
Help please For the following function, construct a table.
Answer:
See the attachment below.
Step-by-step explanation:
Best Regards!
A sequence is defined by the recursive function f(n+1)= f(n) -2. If f(1) =10. what is f(3)?
Answer:
f(3) is 30
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Use a calculator to find tan 72°. Round to the nearest thousandth.
Answer:
3.078
Step-by-step explanation:
tan 72° = 3.078
Answer:
tan 72 = 3.078
Step-by-step explanation:
rounded like requested
The composite figure is made up of a triangle, a square and a trapezoid find the area
===============================================
Work Shown:
P = area of triangle
P = 0.5*base*height
P = 0.5*5*4
P = 10 square units
----------------
Q = area of square
Q = side*side
Q = 5*5
Q = 25 square units
----------------
R = area of trapezoid
R = height*(base1+base2)/2
R = 5*(7+5)/2
R = 5*12/2
R = 60/2
R = 30
----------------
T = total area of the entire figure
T = P+Q+R
T = 10+25+30
T = 65 square units
Answer: 71 sq. units
Step-by-step explanation:
formula: 1/2bh + lw + 1/2h(b1+b2)
1/2(20) + (25) + 1/2 (6) (12)
10 + 25 + (3) (12)
10+ 25 + 36 = 71
Antonio was eating a bag of M&Ms. There were 4 green M&Ms, 20 brown M&Ms, 16 red
M&Ms, and 11 blue M&Ms. What is the probability of Antonio eating a blue M&M next?
Answer:
11/51 or 0.21468627
Step-by-step explanation:
graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 3, negative 2, and 2 Which of the following functions best represents the graph? f(x) = (x − 2)(x − 3)(x + 2) f(x) = (x + 2)(x + 3)(x + 12) f(x) = (x + 2)(x + 3)(x − 2) f(x) = (x − 2)(x − 3)(x − 12)
Answer:
i would say f(x) = (x-2)(x-3)(x+2) but i could be wrong its a confusing question the way it's worded
Step-by-step explanation:
If anyone is good at math can you help me pls :/
Answer:
C
Step-by-step explanation:
An apothem is a line segment connecting the center of a regular polygon to the midpoint of its vertex.
Solve for x: [tex]22y\3x=8[/tex]
Answer:
x = 4/(11y)
Step-by-step explanation:
22yx = 8
Solve for x so divide each side by 22y
22xy/22y = 8/22y
x = 4/(11y)
Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a
sample of size 131 with 81% successes. Enter your answer as a tri-linear inequality using decimals (not
percents) accurate to three decimal places.
apa
> Next Question
Answer:
[tex]0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730[/tex]
[tex]0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890[/tex]
And the confidence interval would be:
[tex] 0.730 \leq \p \leq 0.890[/tex]
Step-by-step explanation:
Information given:
[tex] n=131[/tex] represent the sample size
[tex] \hat p=0.81[/tex] represent the estimated proportion
The confidence interval would be given by this formula
[tex]\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]
For the 98% confidence interval the value of [tex]\alpha=1-0.98=0.02[/tex] and [tex]\alpha/2=0.01[/tex], with that value we can find the quantile required for the interval in the normal standard distribution.
[tex]z_{\alpha/2}=2.326[/tex]
And replacing into the confidence interval formula we got:
[tex]0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730[/tex]
[tex]0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890[/tex]
And the confidence interval would be:
[tex] 0.730 \leq \p \leq 0.890[/tex]
whats the answer???
Answer:The answer is C 20 cm^3
Step-by-step explanation:
You just multiply 2 by 2 and get 4 and you have 5 squares and you get 4 times 5 which is 20 cm^3
Answer:
Divide the figure into 5 squares.
then find the area 1 square and multiply with 5.
Area of square=s*s
=4 cm²
Then 5*4=20 cm²
so c is the correct option.
HOPE IT HELPS!
7. The probability of passing an
examination is 0.77. What is the
probability of failing the examination?
A. 0.22
B 0.23 C. 0.33
D. 0.72
E. 0.77
Answer:
Option B
Step-by-step explanation:
Total Probability = 1
Probability of passing = 0.77
Probability of failing = 1-0.77
=> 0.23
What is the value of c in the equation? 15.3 = StartFraction c Over 2.1 EndFraction 13.2 17.4 32.13 321.3
Answer:
32.13
Step-by-step explanation:
15.3= c/2.1
c= 15.3* 2.1
c= 32.13
Answer:
32.13 aka C got it right on my quiz
Mark the person on top as Brainliest there are right and answered first
jessica put 4 tables together for the Pie day sale. Each table is 42 inches long. What is the total length of the tables expressed in feet and inches
Answer:
14 feet OR 168 inches
Step-by-step explanation:
4 tables multiplied by 42 inches equals 168 inches total
168 inches divided by 12 inches per feet equals 14 feet.
Given:
MNOP is a parallelogram
Prove:
PM ON
(For this proof, use only the definition of a parallelogram; don’t use any properties)
Answer:
[tex]\overline{PM}\cong\overline{ON}[/tex]:, Segment subtended by the same angle on two adjacent parallel lines are congruent
Step-by-step explanation:
Statement, Reason
MNOP is a parallelogram:, Given
[tex]\overline{PM}\left | \right |\overline{ON}[/tex]:, Opposite sides of a parallelogram
∠PMO ≅ ∠MON:, Alternate Int. ∠s Thm.
[tex]\overline{MN}\left | \right |\overline{PO}[/tex]:, Opposite sides of a parallelogram
∠POM ≅ ∠NMO:, Alternate Int. ∠s Thm.
OM ≅ OM:, Reflexive property
[tex]\overline{PM}\cong\overline{ON}[/tex]:, Segment subtended by the same angle and on two adjacent parallel lines are congruent
Find the missing number in the pattern! PLEASE HELP The half-life of caffeine is 5 hours; this means that approximately 1/2 of the caffeine in the bloodstream is eliminated every 5 hours. Suppose you drink a 16-ounce drink that contains 80 mg of caffeine. Suppose the caffeine in your bloodstream peaks at 80 mg. 1. How much caffeine will remain in your bloodstream after 5 hours? 10 hours? 1 hour? 2 hours? Record your answers in the table
Answer:
After five hours, there will be 40 mg of caffeine remaining in the blood.
After 10 hours, 20 mg.
After only one hour, about 69.64 mg.
And after two hours, about 60.63 mg.
Step-by-step explanation:
We are given that one-half of the caffeine in the bloodstream is eliminated every five hours.
We are also given that the initial amount is 80 mg.
Using this information, we can write the following function:
[tex]\displaystyle f(x)=80\left(\frac{1}{2}\right)^{\dfrac{x}{5} }[/tex]
Where x is the number of hours that has passed.
Using this function, we can evaluate for f(5), f(10), f(1), and f(2).
They evaluate to:
[tex]f(5)=40[/tex] [tex]f(10)=20[/tex] [tex]f(1)\approx 69.6440[/tex] [tex]f(2) \approx 60.6287[/tex]
So, after five hours, there are 40 mg of caffeine remaining in the blood.
After 10 hours, 20 mg of caffeine.
After only one hour, about 69.64 mg.
And after two hours, about 60.63 mg.
Select the three expressions that are equivalent to 6^{2}6 2 6, squared. a: (6^9/6^8)^2 b: 6 times 6 times 6 times 6 times 6 times 6 times 6 / 6 times 6 times 6 c: 6^4/6^2 d: 6^5 times 6^7/6^10
Question:
Select the three expressions that are equivalent to [tex]6^2[/tex]:
a: [tex](\frac{6^9}{6^8})^2[/tex]
b: [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex]
c: [tex]\frac{6^4}{6^2}[/tex]
d: [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]
Answer:
a: [tex](\frac{6^9}{6^8})^2[/tex]
c: [tex]\frac{6^4}{6^2}[/tex]
d: [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]
Step-by-step explanation:
Given
[tex]6^2[/tex]:
Required
Find equivalent expressions
To solve this question; we'll simplify options a to do, one after the other
a: [tex](\frac{6^9}{6^8})^2[/tex]
From laws of indices;
[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This implies that;
[tex](\frac{6^9}{6^8})^2 = (6^{9-8})^2[/tex]
[tex](\frac{6^9}{6^8})^2 = (6^{1})^2[/tex]
From laws of indices;
[tex]{a^m}^n = a^{m*n} = a^{mn}[/tex]
This implies that
[tex](\frac{6^9}{6^8})^2 = (6^{1*2})[/tex]
[tex](\frac{6^9}{6^8})^2 = 6^{2}[/tex]
Hence, [tex](\frac{6^9}{6^8})^2[/tex] is equivalent to [tex]6^2[/tex]
b. [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex]
From laws of indices;
[tex]a^m * a^n = a^{m+n}[/tex]
This implies that
[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{1+1+1+1+1+1}}{6^{1+1+1}}[/tex]
[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{6}}{6^{3}}[/tex]
From laws of indices;
[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This implies that
[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{6-3}[/tex]
[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{3}[/tex]
Hence; [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex] is not equivalent to [tex]6^2[/tex]
c. [tex]\frac{6^4}{6^2}[/tex]
From laws of indices;
[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This implies that
[tex]\frac{6^4}{6^2} = 6^{4-2}[/tex]
[tex]\frac{6^4}{6^2} = 6^{2}[/tex]
Hence, [tex]\frac{6^4}{6^2}[/tex] is equivalent to [tex]6^2[/tex]
d. [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]
From laws of indices;
[tex]a^m * a^n = a^{m+n}[/tex]
This implies that
[tex]\frac{6^5 * 6^7}{6^{10}} = \frac{6^{5+7}}{6^{10}}[/tex]
From laws of indices;
[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This implies that
[tex]\frac{6^5 * 6^7}{6^{10}} = 6^{5+7-10}[/tex]
[tex]\frac{6^5 * 6^7}{6^{10}} = 6^{2}[/tex]
Hence, [tex]\frac{6^5 * 6^7}{6^{10}}[/tex] is equivalent to [tex]6^2[/tex]
Help please can’t get this wrong. Am I doing this right if not correct me. And how do I write it
Answer:
I think it’s correct
Step-by-step explanation:
The segments shown below could form a triangle
O A. True
O B. False
Answer:
Which value of a in the exponential function below would cause the function to stretch?
(one-third) Superscript x
0.3
0.9
1.0
1.5
Step-by-step explanation:
Answer:
This can form a triangle
Step-by-step explanation:
Taking the two smaller segments
The larger segment must be greater than the sum of the two smaller
6+5 > 8
11>8 true
Find the total current drawn by the following appliances by adding the currents of
each appliance. Electric iron: 4.12 amps, clock: 0.02 amps, light bulb: 0.91 amps, and a
workshop motor: 1 amp.
Answer:
The total current drawn is 6.05 amps
Step-by-step explanation:
Simply add the current that each appliance draws, to get the total current required. Notice that they are all given in the same units (amps), so there is no units conversion needed:
Electric iron : 4.12 amps
Clock; 0.02 amps
light bulb : 0.91 amps
motor : 1 amp
Total current : 4.12 amps + 0.02 amps + 0.91 amps + 1 amp = 6.05 amps
simplify 10+4(−8q−4)
Answer:
10 + 4(-8q - 4)
= 10 + 4 * (-8q) + 4 * (-4) (Distribute 4)
= 10 - 32q - 16 (Expand)
= -32q - 6 (Combine like terms)
Answer:
[tex]-32q-6[/tex]
Step-by-step explanation:
[tex]10+4(-8q-4)[/tex]
[tex]10+4(-8q)+4(-4)[/tex]
[tex]10+-32q+-16[/tex]
[tex]-32q+-16+10[/tex]
[tex]-32q+-6[/tex]
Which scatterplot correctly represents the table of values below? Number of years collecting stamps Number of stamps in collection 2 100 5 175 4 150 3 125 4 175 3 100 A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 200). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 150), (4, 150), (4, 175), and (5, 175). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 175). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 75), (3, 100), (3, 125), (4, 150), (4, 175), and (5, 175).
Answer:
C. A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 175)
Step-by-step explanation:
In the x-axis goes the values from the column 'Number of years collecting stamps' of the table. And In the y-axis goes the values from the column 'Number of stamps in collection' of the table.
To make the graph identify each pair of values in the plane and mark it.
Answer:
c
Step-by-step explanation:
its corect on edge
The ratio of Tom's studying time on a weekday to his studying
time on a weekend day is 4:5. If he studies 2.4 hours each
weekday, how many hours does Tom study in total every
week?
_hours
Answer:
6 hrs
Step-by-step explanation:
4:5
2.4 : 3.2
2.4+3.2=6 hrs
involving the use of variables, properties, expressions, and equations
Work it out for me plz
Answer:
180 centimeters cubed.
Step-by-step explanation:
The volume of a cuboid is lwh.
Length × Width × Height
(9)×(5)×(4)
(45)×(4)
=180
Answer:
180 cm^3Solution,
[tex]volume \: of \: cuboid \\ = l \times w \times h \\ = 5 \times 9 \times 4 \\ = 180 {cm}^{3} [/tex]
hope this helps...
Good luck on your assignment...
[tex]( - 8x}^{2} - 5x - 6) + ( - x { }^{2} - x + 5)[/tex]
Solve
Answer:zooooooooooooooooooooooooooooooooom
Step-by-step explanation:
If y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8?
1/9
2/3
54
96
Answer:
Y=2/3
Step-by-step explanation:
Y varies directly as X
Y=k x
K is a constant
6=k72
K=1/12
Y=1/12x
Y=1/12×8
y=2/3
in a right triangle, what is the 3rd angle measure if an angle is 25
Answer:
65
Step-by-step explanation:
The sum of the angles in a triangle is 180. In a right triangle, there is one 90 degree angle. If the second angle is 25, and 90+25+the last angle must add up to 180, simple math can find the value of the last angle.
180-90-25=65
Answer:
65
Step-by-step explanation:
right angle=90
[tex] {90}^{0} [/tex]
therefore 90-25=the third angle 65
Find
[tex]( {10x}^{2} - 11x + 8) + ( {2x}^{2} + 7x - 5 )[/tex]
Answer:
[tex]12x^2-4x+3[/tex]
Step-by-step explanation:
Parentheses do not matter in this equation.
[tex](10x^2-11x+8)+(2x^2+7x-5)=\\10x^2-11x+8+2x^2+7x-5=\\12x^2-11x+8+7x-5=\\12x^2-4x+8-5=\\12x^2-4x+3[/tex]
Our answer is [tex]12x^2-4x+3[/tex]
Need help if you can, help please help
Answer:
4.4 km/h
Step-by-step explanation:
From the graph you can see she was at the shop after 30 minutes. If you travel 2.2 km in 30 minutes, your speed is 2.2 / 0.5 = 4.4 km/h
So the trick is to express the 30 minutes as 1/2 hour.
Answer:
4.4 km/h
Step-by-step explanation: