You toss a ball into the air and note the time interval between the ball leaving your hand and reaching its highest position. While you are doing this, a construction worker being lifted on a hydraulic platform at constant speed also notes the time interval needed for the ball to reach its highest position. Is the time interval reported by the worker longer, shorter, or the same as the interval you report?

The initial speed of the bullet = v₁= 511.07 m/s

Given

17.4 g bullet

5506 g wooden

The velocity of the block+bullet :1.61 m/s

Required

The initial speed

Solution

Momentum

m₁v₁+m₂v₂=m₁v₁'+m₂v₂'

v₂=0 ⇒block at rest

v₁'=v₂'=1.61 m/s

the equation becomes :

m₁v₁=(m₁+m₂)v'

17.4v₁=(17.4+5506)1.61

v₁= 511.07 m/s

Answer:

The laboratory testing is done on metrics. The research will help find the preference of a person among various drinks.

Explanation:

The laboratory testing is for research purposes. When a person is introduced with two different drinks he may have different experiences. The taste of two different drinks is sweet. A persons behavior towards the taste is psychological also. If he is already informed that the drinks will be sweet, he might start feeling sweeter when he tastes it even if the drink has no taste.

Answer:

Conductivity, [tex]\sigma=500\ (\Omega-m)^{-1}[/tex]

Explanation:

Given that,

The resistivity of a material, [tex]\rho=2\times 10^{-3}\ \Omega-m[/tex]

We need to find the conductivity of the material.

We know that the reciprocal of resistivity is called conductivity.

[tex]\sigma=\dfrac{1}{\rho}\\\\\sigma=\dfrac{1}{2\times 10^{-3}}\\\\\sigma=500\ (\Omega-m)^{-1}[/tex]

So, the conductivity of the material is [tex]500\ (\Omega-m)^{-1}[/tex].

Answer:

Answer:

a) 13.7 m

b) 8.3 m

Explanation:

a)

       [tex]d = d_{1} + d_{2} = 11.0 m + 2.7 m = 13.7 m (1)[/tex]

b)

       [tex]x_{o} = 0 (2)[/tex]

       [tex]x_{f} = x_{1} - x_{2} = 11.0 m - 2.7 m = 8.3 m (3)[/tex]

      ⇒ Δx = xf - x₀ = 8.3 m  - 0 m =  8.3 m

Answer:

suppose buying pizza for a work party leads to positive morale and to the work being done in half the time. Pizza is the independent variable, Work speed is the dependent variable, The mediator, the middle man without which there would be no connection, is positive morale. Denaturation, in biology, the process of modifying the molecular structure of a protein. Denaturation involves the breaking of many of the weak linkages, or bonds (e.g., hydrogen bonds), within a protein molecule that is responsible for the highly ordered structure of the protein in its natural (native) state.

Explanation:

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Explanation:

HW1. For example, suppose buying pizza for a work party leads to positive morale and to the work being done in half the time. Pizza is the independent variable, Work speed is the dependent variable, The mediator, the middle man without which there would be no connection, is positive morale.

HW2. The word denature means to render food unpleasant or dangerous to consume, it is denatured by adding a substance known as a denaturant. Aversive agents—primarily bitterants and pungent agents—are used to produce an unpleasant flavor.

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Answer: 0.24 m/s

Explanation:

Answer:

It should be Mass, Gravity and Height

Explanation:

Explanation:

Cheetahs can go from 0 to 60 miles per hour in just 3.4 seconds and reach a top speed of 70 miles per hour. While they are the fastest land animal in the world, they can only maintain their speed for only 20 to 30 seconds.

Answer:

105 kg.m/s

Explanation:

Formula for change in momentum is given as;

ΔP = m(v - u)

We are given;

Mass; m = 35 kg

Initial velocity; u = 3 m/s

Final velocity; v = 6 m/s

Thus;

ΔP = 35(6 - 3)

ΔP = 35 × 3

ΔP = 105 kg.m/s

Answer:

Acceleration = 0.5m/s²

Explanation:

Given the following data;

Final velocity = 5m/s

Time = 10 seconds

Since the spider started from rest, its initial velocity is equal to 0m/s

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

[tex]a = \frac{v - u}{t}[/tex]

Where,

a is acceleration measured in [tex]ms^{-2}[/tex]

v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]

t is time measured in seconds.

Substituting into the equation, we have;

[tex]a = \frac{5 - 0}{10}[/tex]

[tex]a = \frac{5}{10}[/tex]

Acceleration = 0.5m/s²

Answer:

1.Lactose

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The velocity of the freely falling object reached after 4.0 s is equal to 39.2 m/s.

A relation can be established between the velocity of the body and acceleration of the body when the body is moving along a straight line with uniform acceleration. The distance traveled by the body in a specific time has expressed a set of equations called equations of motion.

The first equation of motion can be expressed as follows:

v = u + at

Where u is the initial velocity, v is the final velocity and a is the acceleration and t is the time of the object.

Given, the acceleration of the falling object, g = 9.8 m/s²

The initial velocity of the object, u = 0, and the time = 4 sec

The velocity of the object after time, t = 4 sec.

v = (0) + (9.80)× (4)

v = 39.2 m/s

Therefore, the velocity of the falling object will be 39.2 m/s after 4 seconds.

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The  velocity of the given graph will be 2m/s.

Speed is a scalar quantity that measures how fast an object is moving. It is the rate of change of distance traveled by an object over a specific period of time. Speed does not consider the direction of motion; it only reflects the magnitude of the velocity.

Mathematically, speed (v) is calculated as:

Speed (v) = Distance traveled (d) / Time taken (t)

where:

Speed (v) is measured in units like meters per second (m/s), kilometers per hour (km/h), miles per hour (mph), etc.

Distance traveled (d) is the total path length covered by the object in a given timeframe.

Time taken (t) represents the duration it took the object to cover that distance.

According to graph,

speed = 6-2/ 3- 1

= 4/ 2

= 2 m/s

Therefor, the velocity of the given graph will be 2m/s.

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Answer:

I. a, c, f and h

II. e

III. b, d, g and i

IV. i

Explanation:

I. Chemical symbols are simple abbreviations used to represent various elements or compound. They consist entire of alphabet.

For the diagram given above, the labelled parts which represent chemical symbol are: a, c, f and h

II. Coefficients are numbers written before the chemical symbol of elements or compound.

For the diagram given above, the labelled part which represent Coefficient is: e

III. Number of atoms of element present in a compound is simply obtained by taking note of the numbers written as subscript in the chemical formula of the compound.

For the diagram given above, the labelled part which represent the number of atoms of the element are: b, d, g and i

IV. When no number is written as subscript in the formula of the element in the compound, it means the element has just 1 atom in the compound.

For the diagram given above, the labelled part which indicates that only 1 atom of the element is present is: i

Answer:

i. a, c, f, h

ii. e

iii. b, d, g, i

iv. i

Answer:1 carbon atom

Explanation:AP3X

Answer:

1

Explanation:

Answer:

a. i. -4.65 m/s ii. -13.95 m/s b. 5.89 m c. 2.85 s

Explanation:

a. What is the velocity of the box at (i) t = 1.00 s and (ii) t = 3.00 s?

We write the equation of the forces acting on the mass.

So, T - mg = ma where T = tension in vertical rope = (36.0 N/s)t, m = mass of box = 3.50 kg, g = acceleration due to gravity = 9.8 m/s² and a = acceleration of box = dv/dt where v = velocity of box and t = time.

So, T - mg = ma

T/m - g = a

dv/dt = T/m - g

dv/dt = (36.0 N/s)t/3.50 kg - 9.8 m/s²

dv/dt = (10.3 m/s²)t - 9.8 m/s²

dv = [(10.3 m/s²)t - 9.8 m/s²]dt

Integrating, we have

∫dv = ∫[(10.3 m/s³)t - 9.8 m/s²]dt

∫dv = ∫(10.3 m/s³)tdt - ∫(9.8 m/s²)dt

v = (10.3 m/s³)t²/2 - (9.8 m/s²)t + C

v = (5.15 m/s³)t² - (9.8 m/s²)t + C

when t = 0, v = 0 (since at t = 0, box is at rest)

So,

0 = (5.15 m/s³)(0)² - (9.8 m/s²)(0) + C

0 = 0 + 0 + C

C = 0

So, v = (5.15 m/s³)t² - (9.8 m/s²)t

i. What is the velocity of the box at t = 1.00 s,

v =  (5.15 m/s³)(1.00 s)² - (9.8 m/s²)(1.00 s)

v = 5.15 m/s - 9.8 m/s

v = -4.65 m/s

ii. What is the velocity of the box at t = 3.00 s,

v =  (5.15 m/s³)(3.00 s)² - (9.8 m/s²)(3.00 s)

v = 15.45 m/s - 29.4 m/s

v = -13.95 m/s

b. What is the maximum distance that the box descends below its initial position?

Since v = (5.15 m/s³)t² - (9.8 m/s²)t and dy/dt = v where y = vertical distance moved by mass and t = time, we need to find y.

dy/dt = (5.15 m/s³)t² - (9.8 m/s²)t

dy = [(5.15 m/s³)t² - (9.8 m/s²)t]dt

Integrating, we have

∫dy = ∫[(5.15 m/s³)t² - (9.8 m/s²)t]dt

∫dy = ∫(5.15 m/s³)t²dt - ∫(9.8 m/s²)tdt

∫dy = ∫(5.15 m/s³)t³/3dt - ∫(9.8 m/s²)t²/2dt

y = (1.72 m/s³)t³ - (4.9 m/s²)t² + C'

when t = 0, y = 0.

So,

0 = (1.72 m/s³)(0)³ - (4.9 m/s²)(0)² + C'

0 = 0 + 0 + C'

C' = 0

y = (1.72 m/s³)t³ - (4.9 m/s²)t²

The maximum distance is obtained at the time when v = dy/dt = 0.

So,

dy/dt = (5.15 m/s³)t² - (9.8 m/s²)t = 0

(5.15 m/s³)t² - (9.8 m/s²)t = 0

t[(5.15 m/s³)t - (9.8 m/s²)] = 0

t = 0 or [(5.15 m/s³)t - (9.8 m/s²)] = 0

t = 0 or (5.15 m/s³)t = (9.8 m/s²)

t = 0 or t = (9.8 m/s²)/(5.15 m/s³)

t = 0 or t = 1.9 s

Substituting t = 1.9 s into y, we have

y = (1.72 m/s³)t³ - (4.9 m/s²)t²

y = (1.72 m/s³)(1.9 s)³ - (4.9 m/s²)(1.9 s)²

y = (1.72 m/s³)(6.859 s³) - (4.9 m/s²)(3.61 s²)

y = 11.798 m - 17.689 m

y = -5.891 m

y ≅ - 5.89 m

So, the maximum distance that the box descends below its initial position is 5.89 m

c. At what value of t does the box return to its initial position?

The box returns to its original position when y = 0. So

y = (1.72 m/s³)t³ - (4.9 m/s²)t²

0 = (1.72 m/s³)t³ - (4.9 m/s²)t²

(1.72 m/s³)t³ - (4.9 m/s²)t² = 0

t²[(1.72 m/s³)t - (4.9 m/s²)] = 0

t² = 0 or (1.72 m/s³)t - (4.9 m/s²) = 0

t = √0 or (1.72 m/s³)t = (4.9 m/s²)

t = 0 or t = (4.9 m/s²)/(1.72 m/s³)

t = 0 or t = 2.85 s

So, the box returns to its original position when t = 2.85 s

Answer:

3 bending

Explanation:

Answer:

A. Velocity is negative (-)

Acceleration is positive,(+)

B. Velocity is positive. (+)

Acceleration is negative (-)  

C. Velocity is zero (0).

Acceleration is negative (-)

Explanation:

The elevator is said to be moving downward, therefore, its motion is in the negative direction as the positive direction is upward in the y-axis. Velocity is negative (-)

As the elevator is making an emergency stop, it is decelerating. Deceleration is negative acceleration. However, since it occurs in the opposite direction, i.e. acceleration vector is pointing upward, acceleration is positive,(+)

The motion of the ball is in the upward direction, therefore the velocity is positive. (+)

The acceleration due to the force of gravity acts in the opposite direction to that of the ball, i.e. downwards, acceleration is negative (-)  

At maximum height, the ball will stop moving, therefore, velocity is zero (0).

Since acceleration due to the force of gravity acts downward, the acceleration is negative (-)

Answer:

Explanation:

The net force is in the same direction of the acceleration. Acceleration changes the speed of an object.

Answer:

It you get a sushi for work, for a party, then it leads to people being happy, as an independant variable

It is changing the molecular structure of a protein

Explanation:

Answer:

the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

Explanation:

We can analyze this exercise from several points of view, if we use Newton's second law

Bowling ball

           F = M a₁

pingpongg ball

           F = m a₂

as the forces the same

          M a₁ = m a₂

          a₂ = [tex]\frac{M}{m}[/tex] a₁

Since the mass of the bowling ball is much greater than the ping pong ball,

          a₂ »a₁

so the acceleration of the ping pong ball is much greater than the acceleration of the bowling ball.

If we use the relationship of momentum and momentum, assuming that the time for the two cases is the same and that both start from rest

Bowling ball

           I = F t = Δp

           I = M (v₁ - v₀)

Ping pong ball

           I = F t = Δp

           I = m (v₂ -v₀)

the impulse itself

          M v₁ = m v₂

          v₂ = [tex]\frac{M }{ m}[/tex] v₁

so we conclude that the speed of the ping pong ball is much greater than the speed of the bowling ball.

In conclusion the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

Answer:

  F = 69.3 N

Explanation:

For this exercise we use Newton's second law, remembering that the static friction force increases up to a maximum value given by

               fr = μ N

We define a reference system parallel to the floor

block B  ( lower)

Y axis  

            N - W₁-W₂ = 0

            N = W₂ + W₂

            N = (M + m) g

X axis

              F -fr = M a

for block A (upper)

X axis

              fr = m a                 (2)

so that the blocks do not slide, the acceleration in both must be the same.

Let's solve the system by adding the two equations

             F = (M + m) a          (3)

             a =[tex]\frac{F}{ M+m}[/tex]

the friction force has the formula

            fr = μ N

             fr = μ (M + m) g

let's calculate

            fr = 0.34 (2.0 + 0.250) 9.8

            fr = 7.7 N

we substitute in equation 2

             fr = m a

             a = fr / m

             a = 7.7 / 0.250

             a = 30.8 m / s²

we substitute in equation 3

             F = (2.0 + 0.250) 30.8

             F = 69.3 N

Answer:

grams

Explanation:

Answer:

The starting velocity.

Explanation:

We must understand that this equation comes from the following equation of kinematics.

[tex]v_{f}=v_{o}+a*t[/tex]

where:

Vf = final velocity = 33 [m/s]

Vo = starting velocity [m/s]

a = acceleration = 3 [m/s²]

t = time = 30 [s]

So, these values can be assembly in the following way:

[tex]v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}[/tex]

A star produces energy by creating helium from hydrogen in its core (option D).

A star is a luminous celestial body, made up of plasma (particularly hydrogen and helium) and having a spherical shape.

Nuclear fusion is the energy-producing process in stars. The "proton-proton chain," a series of events that turns four hydrogen atoms into one helium atom, dominates this process for the majority of stars.

Nuclear fusion is the combining of the nuclei of small atoms to form the nuclei of larger ones, with a resulting release of large quantities of energy.

Hydrogen atoms fuse in the core of the star to form a helium atom, which generates the energy for the star.

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