Why did scientists reject Lamarck’s idea of evolution?


Organisms cannot change their characteristics during their lifetime.


Traits acquired during a lifetime are not passed on to offspring.


Organisms have not changed during Earth’s history.


Traits acquired during a lifetime are of no use to an individual.

Answer:

See Explanation

Explanation:

The equation of the reaction;

KHSO4(aq) + KOH(aq) -------> K2SO4(aq) + H2O(l)

Number of moles of KHSO4 = 49.6 g/136.169 g/mol = 0.36 moles

Since the reaction is in a mole ratio of 1:1, 0.36 moles of K2SO4 is produced.

Number of moles of KOH = 25.3 g/56.1056 g/mol = 0.45 moles

Since the reaction is 1:1, 0.45 moles of K2SO4 is produced

Hence K2SO4 is the limiting reactant.

Mass of K2SO4 formed = 0.36 moles of K2SO4 * 174.26 g/mol = 62.7 g

So;

1 mole of KHSO4 reacts with 1 mole of KOH

0.36 moles of KHSO4 reacts with 0.36 * 1/1 = 0.36 moles of KOH

Amount of excess KOH = 0.45 moles - 0.36 moles = 0.09 moles

Mass of excess KOH = 0.09 moles * 56.1056 g/mol  = 5 g of excess KOH

Answer:

Moving two particles of the opposite charge close together.

Explanation:

Think about it.

Opposites attract.

When you attempt to move particles with the same charges, a force is created.

Answer:asexual- Energy is not required to find a mate. Offspring are genetic clones. A negative mutation can make asexually produced organisms susceptible to disease and can destroy large numbers of offspring. Some methods of asexual reproduction produce offspring that are close together and compete for food and space.

Explanation:During sexual reproduction the genetic material of two individuals is combined to produce genetically diverse offspring that differ from their parents.

Answer:

solution A

Explanation:

it is because solution A has a pH of 2.0 and solution B has the pH of 5.0 and also whose number is greater than the solution A .That is why it is acidic

Answer:

pOH = 3.18

Explanation:

The equilibrium of a weak base as NX3 is:

NX3(aq) + H2O(l) ⇄ HNX3⁺(aq) + OH-(aq)

Where the equilibrium constant, Kb, is:

Kb = 2.5x10⁻⁶ = [HNX3⁺] [OH-] / [NX3]

As both HNX3⁺ and OH- ions comes from the same equilibrium, their concentrations are the same, that is:

[HNX3⁺] = X

[OH-] = X

And: [NX3] = 0.175M:

2.5x10⁻⁶ = [X] [X] / [0.175M]

4.375x10⁻⁷ = X²

X = 6.61x10⁻⁴M = [OH-]

As pOH = -log [OH-]

Answer:

a

Explanation:

The molecules of a substance formed a rigid repeating crystal structure. Then, a phase change occurred. That structure is now more like clusters of molecules moving past one another this change is caused by condensing phase.

The transformation of water vapor into liquid is known as condensation. The process is the opposite of evaporation, in which liquid water turns into a vapor. Either the air is chilled to its dew point or it gets too saturated with water vapor to retain any more water, causing condensation to occur.

By removing and transferring heat from the vapor to a cooling medium, condensation is the process by which a substance goes from its vapor phase to its liquid phase. The vapor must be saturated for the process to begin as well as having its vaporization heat reduced.

Thus, option A is correct.

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Answer:

D

Explanation:

Because the Earth rotates through two tidal “bulges” every lunar day, coastal areas experience two high and two low tides every 24 hours and 50 minutes!!!

Answer:

yoooo si se puede jejeje

Explanation:

Answer:

Explanation:

hola como esta yo tan biene es  aburrido

Answer:

A common characteristic of most Alkali Metals is their ability to displace H2(g) from water. This is represented by their large, negative electrode potentials. In this event, the Group 1 metal is oxidized to its metal ion and water is reduced to form hydrogen gas and hydroxide ions. The general reaction of an alkali metal (M) with H2O (l) is given in the following equation:2M(s)+2H2O(l)⟶2M+(aq)+2OH−(aq)+H2(g)(1)

Explanation:

Answer:

Outer electrons.

Explanation:

All bonds are localized bonds formed between two atoms by the donation of electrons from each atom.

Answer:

Mass of 1 litre of this gas at 273 degree Celsius and 1140 mm Hg pressure is

3 grams. So, (T1) = (273 + 273) degree Absolute = 546 degree Absolute and

(P1) = (760 + 1140) mm Hg = 1900 mm Hg and (V1) = 1 Litre

First, we have to find out how much volume does it occupy at NTP; (T2) = 273 degree Absolute and (P2) = 760 mm Hg.

So, (V2) = (1900*1 / 546)*(273 / 760) = 1.25 litre.

So, the mass of 1.25 litre volume of this gas = 3 grams

Therefore, the mass of 22.4 litre volume of this gas = (3*22.4 / 1.25) grams

= 53.76 grams.

So, the gram molecular mass of the gas is 53.76.

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Answer:

6.31g/mol

Explanation:

Using the ideal gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Mole (n) = mass (m)/molar mass (Mm)

* Mm = m/n

Also, density (p) = mass (m) ÷ volume (V)

PV = nRT

Since n = M/Mm

PV = M/Mm. RT

PV × Mm = m × RT

Divide both sides by V

P × Mm = m/V × RT

Since p = m/V

P × Mm = p × RT

Mm = p × RT/P

Mm = 0.249 × 0.0821 × 293/0.95

Mm = 5.989 ÷ 0.95

Mm = 6.31g/mol

The substance which completely consumed in a chemical reaction are known as Limiting reagents. Hence, option (1) is the correct option.

It is the reactant in a chemical reaction that gets consumed first in a chemical reaction and therefore limits how much product can be formed, Thus, known as Limiting reagent.

Hence, The substance which completely consumed in a chemical reaction are known as Limiting reagents. Hence, option (1) is the correct option.

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Answer:

[CH₃COOH] = 1.70 M

Explanation:

When we talk about concentration we can determine Molarity

Molarity determines the moles of solute that are contained in 1L of solution.

In this case our solute is the acetic acid.

M = mol/L

M = 0.99 mol /0.58L → 1.70 M

We can also make a rule of three

In 0.58 L of solution we have 0.99 moles of solute

In 1 L of solution we may have (1 . 0.99) / 0.58 = 1.70 moles

Acetic acid is a weak acid, partially dissociated in water.

CH₃COOH  +  H₂O  ⇄  CH₃COO⁻  +  H₃O⁺     Ka

Answer:

I think its alike.... Pretty sure actually

Answer:

Explanation:

a. direct

Amplitude and wavelength are the property of the waves. These both are directly related to each other. Thus, option A is correct.

Amplitude is the measure of the wavelength that is estimated from the peak or crest to the trough of the wave. Wavelength is the measurement of the length of the wave from one peak to the crest of another wave.

Though there is no relationship between the wavelength and amplitude of the waves they can be said to have direct relation as wavelength and frequency are indirectly related.

Therefore, option A. direct relation is correct.

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Answer:

0.25M

Explanation:

acording to M1V1/M2V2=n1/n2

Answer:

B

Explanation:

Neutron, neutral subatomic particle that is a constituent of every atomic nucleus except ordinary hydrogen. It has no electric charge and a rest mass equal to 1.67493 × 10−27 kg—marginally greater than that of the proton but nearly 1,839 times greater than that of the electron.

Answer:

When chlorine water is added to potassium bromide solution, chlorine will displace the bromine from the salt solution. The chlorine will be REDUCED (gain electrons) to chlorine ions. The bromide ions will be OXIDISED (lose electrons) to become bromine. The bromine will turn the solution orange.

Explanation:

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Answer:

Explanation:

Na2O has 2 atoms of Sodium and 1 atom of Oxygen

So, the molecular mass of Na2O is:

(2 x Atomic weight of Na) + (1 x Atomic weight of O)

Atomic weight of Na = 22.99 g

Atomic weight of O = 16 g

Therefore, Molecular Mass of Na2O = (2x 22.99g) + (1 x 16g)

= (45.98 + 16)g = 61.98 g

Therefore 61.98 g of Na2O contains 6 x 10^23 molecules (Avogadro's number).

24.6 g of Na2O therefore contains:

(24.6/61.98) x 6 x 10^23 = Answer!

Answer:

M

Explanation:

Hope it helped u alot

P. Cyanide is toxic to clover plants because they use cytochrome c oxidase for electron transport in the mitochondria.

The correct option is B.

Various bacteria, fungi, and algae have the ability to produce cyanides. Tapioca, spinach, willow shoots, almonds, string beans, fruit seeds, and car fumes are other items that contain cyanides.

Smoking cigarettes and the byproducts of the combustion of synthetic fibers, including plastics, contain cyanide. Combustion products are chemicals that are released while combustion. The paper production, textiles, and plastics all use cyanide. The chemicals used it to develop pictures include it. Unfortunately, cyanide is not like other materials. By utilizing this approach, you simply cannot develop a natural tolerance to cyanide.

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The complete question is -

Which statement describes the likely metabolic impact of cyanide

production on clover plants?

A-M. Cyanide is nontoxic to clover plants because they produce ATP without the electron transport in the mitochondria.

B-P. Cyanide is toxic to clover plants because they use cytochrome c oxidase for electron transport in the mitochondria.

C-R. Cyanide is toxic to clover plants because they use cytochrome c oxidase for ATP synthesis in the chloroplasts.

D-S. Cyanide is nontoxic to clover plants because they carry out electron

transport in chloroplasts rather than in mitochondria.

Answer:

Option 2: X is the screening constant, & it remains constant across a period.

Explanation:

I took the test and got the question correct :)

As we move across the period, X is the screening constant, and it remains constant across a period.

As we move across the period, the size of atoms become smaller because of an increase in the size of the nuclear charge. This leads to a decrease in atomic radius.

As the size of atom decreases, the screening effect on the outermost electron decreases accordingly. Hence, as we move across the period, X is the screening constant, and it remains constant across a period. This is because, no new shells are added across the period.

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D. 1-butyne.

The name of this molecule is 1-butyne.

The name of this molecule is 1-butyne. D is correct.

IUPAC nomenclature of organic chemistry is a method of naming organic chemical compounds as given by the International Union of Pure and Applied Chemistry (IUPAC).

There are 3 main parts of IUPAC nomenclature -

1. Prefix

2. Root word

3. Suffix

We have to select the longest continuous chain in a compound and give prefixes as the substituents. Root word will the part which depends on no. of carbon atoms such as meth or eth. And in suffix we focus on type of carbon chain whether it is saturated or not and also the functional group.

Here, we can say that the numbering will be started from the carbon having triple bond and it is present at first position.

Therefore, The name of this molecule is 1-butyne. D is correct.

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Balanced equation is [tex]C_6H_{12}[/tex] + [tex]9O_2[/tex] → [tex]6CO_2[/tex] + [tex]6H_2O[/tex].

A balanced chemical equation occurs when the number of the atoms involved on the reactants side is equal to the number of atoms on the products side.

Balanced equation is [tex]C_6H_{12}[/tex] + [tex]9O_2[/tex] → [tex]6CO_2[/tex] + [tex]6H_2O[/tex]. Where there are 6 carbon atoms, 18 oxygen atoms, and 12 hydrogen atoms.

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Answer: i dont understand

Explanation:

Question

What is the name of this ben zene ?

the name of this benzene is benzene circle

if you also don't understand the go in this link

https://en.m.wikipedia.org/wiki/File:Benzene_circle.svg

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Answer:

Oxidation half-reaction : Na(s) → Na⁺ + 1 e-

Reduction half-reaction: Cl₂ + 2 e- → 2 Cl⁻

Explanation:

Oxidation half-reaction: solid sodium (Na(s)) has an oxidation number of 0. It loses 1 electron and forms the cation Na⁺. So, the half-reaction is the following:

Na(s) → Na⁺ + 1 e-

Reduction half-reaction: chlorine gas (Cl₂) has an oxidation number of 0. Each atom of Cl gains 1 electron to form two Cl⁻ ions, according to the following half-reaction:

Cl₂ + 2 e- → 2 Cl⁻

The total oxidation-reduction reaction is obtained by adding the oxidation half-reaction multiplied by 2 (to balance the electrons) and the reduction half-reaction, as follows:

2 x (Na(s) → Na⁺ + 1 e-)

Cl₂ + 2 e- → 2 Cl⁻

--------------------------------

2Na(s) + Cl₂ → 2NaCl