Answer:
A.) an exothermic reaction that has an increase in disorder.
Explanation:
got it correct (unit review test)
Base your answer on the information below. The hydrocarbon 2-methylpropane reacts with iodine as represented by the balanced equation below. At standard pressure, the boiling point of 2-methylpropane is lower than the boiling point of 2-iodo-2-methylpropane. Explain the difference in the boiling points of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity and intermolecular forces.
Answer:
See explanation
Explanation:
The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.
2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.
As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than 2-methylpropane.
PLEASEEEE HELPPP ME WITH THISS
A person riding in the passenger seat of a car is "pushed" into the car door as the car makes a sharp left turn.
Newton's 2nd Law
Newton's 1st Law
Newtons 3rd Law
Answer:
second law
Explanation:
_Li + __F2 → _LIF
How do I balance this?
Answer:
2Li + F₂ → 2LiF
Explanation:
The reaction expression is given as:
Li + F₂ → LiF
We are to balance the expression. In that case, the number of atoms on both sides of the expression must be the same.
Let use a mathematical approach to solve this problem;
Assign variables a,b and c as the coefficients that will balance the expression:
aLi + bF₂ → cLiF
Conserving Li: a = c
F: 2b = c
let a = 1, c = 1 and b = [tex]\frac{1}{2}[/tex]
Multiply through by 2;
a = 2, b = 1 and c = 2
2Li + F₂ → 2LiF
17.Oxygen gas can be prepared by heating potassium chlorate according to the following equation:
2KClO3(s)2KCl(s) + 3O2(g)
The product gas, O2, is collected over water at a temperature of 25 °C and a pressure of 755 mm Hg. If the wet O2 gas formed occupies a volume of 6.22 L, the number of grams of O2 formed is ________
g. The vapor pressure of water is 23.8 mm Hg at 25 °C.
Mass of O₂ formed = 7.84 g
Further explanationGiven
Reaction
2KClO₃(s) ⇒2KCl(s) + 3O₂(g)
P water = 23.8 mmHg
P tot = 755 mmHg
V = 6.22 L
T = 25 + 273 = 298 K
Required
mass of O₂
Solution
P tot = P O₂ + P water
P O₂ = P tot - P water
P O₂ = 755 - 23.8
P O₂ = 731.2mmHg = 0.962 atm
Moles O₂ :
Ideal gas law :
n = PV/RT
n = 0.962 x 6.22 / 0.082 x 298
n = 0.245
Mass O₂ :
= mol x MW
= 0.245 x 32
= 7.84 g
Please help me answer this question but in your own words!!!!
Answer:
when sodium reacts with chlorine atoms, sodium will give an electron which is negative charged to chlorine.it makes sodium(+) and chlorine (-)..then sodium will attract chlorine to form sodium chloride(NaCl)
what type of reaction is Au2S+H2---> 2Au+H2S
Answer:
single replacement reaction is type of reaction is Au2S+H2---> 2Au+H2S.
Which activity is an example of a scientist using creativity?
a scientist exploring evidence from other fields of science to support findings
a scientist transferring data from one experiment into the data analysis from a second experiment
a scientist repeating an older experiment with the latest technology to verify the original findings
a scientist using the latest graphing software to analyze and present the research
A scientist exploring evidence from other fields of science to support findings is an example of a scientist using creativity.
What is creativity?Creativity is a mental cognitive ability that involves the creation and/or discovery of a hidden process.
In science, creativity refers to the application of mental skills to create new experimental designs and extrapolate findings.
In conclusion, a scientist exploring evidence from other fields of science to support findings is an example of a scientist using creativity.
Learn more about creativity here:
https://brainly.com/question/26061350
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16.A mixture of carbon dioxide and hydrogen gases contains carbon dioxide at a partial pressure of 217 mm Hg and hydrogen at a partial pressure of 703 mm Hg. What is the mole fraction of each gas in the mixture?
XCO2 =
XH2 =
x CO₂ = 0.236
x H₂ = 0.764
Further explanationGiven
P CO₂ = 217 mmHg
P H₂ = 703 mmHg
Required
The mole fraction
Solution
Dalton's law :
The total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases
Can be formulated:
P tot = P1 + P2 + P3 ....
P tot for the mixture :
= 217 mmHg + 703 mmHg
= 920 mmHg
Mole fraction of each gas :
x CO₂ = 217 mmHg/920 mmHg = 0.236
x H₂ = 703 mmHg/920 mmHg = 0.764
what is the percent composition of (NH4)2S?
if you can, include the problem shown pls
extra.
Mg(NO3)2
please don't just take the points please :(, do the problem
thank you <333
(NH₄)₂S
%N= 41.18%
%H =11.76%
%S=47.06%
Mg(NO₃)₂
%Mg=32.43%
%N=18.92%
%O=(64.86%
Further explanationGiven
(NH₄)₂S
Mg(NO₃)₂
Required
The percent composition
Solution
(NH₄)₂S MW=68 g/mol
%N=2. Ar N / MW (NH₄)₂S x 100%
%N= (2.14/68) x 100% = 41.18%
%H =(8.1/68) x 100%=11.76%
%S=(32/68)x 100%=47.06%
Mg(NO₃)₂ MW=148 g/mol
%Mg=(2.24/148)x100%=32.43%
%N=(2.14/148)x100%=18.92%
%O=(6.16/148)x100%=64.86%