Answer:

303 Ω

Explanation:

Given

Represent the resistors with R1, R2 and RT

R1 = 633

RT = 205

Required

Determine R2

Since it's a parallel connection, it can be solved using.

1/Rt = 1/R1 + 1/R2

Substitute values for R1 and RT

1/205 = 1/633 + 1/R2

Collect Like Terms

1/R2 = 1/205 - 1/633

Take LCM

1/R2 = (633 - 205)/(205 * 633)

1/R2 = 428/129765

Take reciprocal of both sides

R2 = 129765/428

R2 = 303 --- approximated

what is the meaning of the word physics

**Answer:**

the scientific study of natural forces such as light, sound, heat, electricity, pressure, etc.

**Explanation:**

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One airplane is approaching an airport from the north at 181 kn/hr. A second airplane approaches from the east at 278 km/hr. Find the rate at which the distance between the planes changes when the southbound plane is 30 km away from the airport and the westbound plane is 15 km from airport.

Answer:

The value is [tex] \frac{dR}{dt} = -286.2 \ km/hr [/tex]

Explanation:

From the question we are told that

The speed of the airplane from the north is [tex]\frac{dN}{dt} = -181 \ km /hr[/tex]

The negative sign is because the direction is towards the south

The speed of the airplane from the east is [tex]\frac{dE}{dt} = -278 \ km/hr[/tex]

The negative sign is because the direction is towards the west

The distance of the southbound plane from the airport is [tex]N = 30 \ km[/tex]

The distance of the westbound plane is [tex]E = 15 \ km[/tex]

Generally the distance between the plane is mathematically represented using Pythagoras theorem as

[tex]R^2 = N^2 + E^2[/tex]

Next differentiate implicitly this equation to obtain the rate at which the distance between the planes changes

So

[tex]2R\frac{dR}{dt} = 2N \frac{dN}{dt} + 2E\frac{dE}{dt}[/tex]

Here

[tex]R = \sqrt{N^2 + E^2}[/tex]

=> [tex]R = \sqrt{30^2 + 15^2}[/tex]

=> [tex]R = \sqrt{30^2 + 15^2}[/tex]

=> [tex]R =33.54 \ m [/tex]

[tex]2(33.54) * \frac{dR}{dt} = 2( 30)*(-181) + 2*15*(-278)[/tex]

=> [tex] 67.08 * \frac{dR}{dt} = -19200[/tex]

=> [tex] \frac{dR}{dt} = -286.2 \ km/hr [/tex]

The **rate **of change of the **distance **between the **planes **is **286.23 km/hr.**

The given parameters;

The **distance **between the two **planes **is calculated by applying **Pythagoras theorem** as shown below;

[tex]d^2 = n^2 + e^2\\\\d = \sqrt{n^2 + e^2} \\\\d = \sqrt{30^2 + 15^2} \\\\d = 33.54 \ km[/tex]

The **rate **of **change **of the **distance **between the **planes **is calculated as follows;

[tex]d^2 = e^2 + n^2\\\\2\frac{dd}{dt} = 2e\frac{de}{dt} + 2n\frac{dn}{dt} \\\\d\frac{dd}{dt} = e\frac{de}{dt} + n\frac{dn}{dt}\\\\(33.54) \frac{dd}{dt} = (15)(278) \ + (30)(181)\\\\(33.54) \frac{dd}{dt} = 9600\\\\\frac{dd}{dt} = \frac{9600}{33.54} \\\\\frac{dd}{dt} = 286.23 \ km/hr[/tex]

Thus, the **rate **of change of the **distance **between the **planes **is **286.23 km/hr.**

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when hydrogen shares electrons with oxygen the outermost shell of the hydrogen atoms are full with how many electrons? and oxygens valence shell is full with how many electrons? because the valence shells of these atoms are full,the atoms are stable.

**Answer:**

2 and 8

**Explanation:**

please mark me brainiest I would really appreciate it.

Find the linear velocity of a point moving with uniform circular motion, if the point covers a distance s in the given amount of time t. s

**Answer:**

The linear velocity is represented by the following expression: [tex]v = \frac{s}{t}[/tex]

**Explanation:**

From Rotation Physics we know that linear velocity of a point moving with uniform circular motion is:

[tex]v = r\cdot \omega[/tex] **(Eq. 1)**

Where:

[tex]r[/tex] - Radius of rotation of the particle, measured in meters.

[tex]\omega[/tex] - Angular velocity, measured in radians per second.

[tex]v[/tex] - Linear velocity of the point, measured in meters per second.

But we know that angular velocity is also equal to:

[tex]\omega = \frac{\theta}{t}[/tex] **(Eq. 2)**

Where:

[tex]\theta[/tex] - Angular displacement, measured in radians.

[tex]t[/tex] - Time, measured in seconds.

By applying **(Eq. 2)** in **(Eq. 1)** we get that:

[tex]v = \frac{r\cdot \theta}{t}[/tex] **(Eq. 3)**

From Geometry we must remember that circular arc ([tex]s[/tex]), measured in meters, is represented by:

[tex]s = r\cdot \theta[/tex]

[tex]v = \frac{s}{t}[/tex]

The linear velocity is represented by the following expression: [tex]v = \frac{s}{t}[/tex]

am I right? be honest

**Answer:**

I chose c because it is the greater slope at point c

A designer is creating an obstacle for an obstacle course where a person starts on a moveable platform of height H from the ground. The person grabs a rope of length L and swings downward. At the instant the rope is vertical, the person lets go of the rope and attempts to reach the far side of a water-filled moat. The left side of the moat is directly below the position where the person will let go of the rope. The designer runs several tests in which the rope has different lengths and moves the platform such that the rope is always initially horizontal. The designer notices that the person cannot land on the other side if the length L is very short. The designer also notices that the person also cannot land on the other side if the length L is very close to the height H.

Assume the size of the person is much smaller than the lengths L and H. Let D represent the horizontal distance from below the release point to where the person lands.

Required:

a. Why does the person land in the moat if the rope's length is very short?

b. Why does the person land in the moat if the length is nearly the same as the height of the platform?

**Answer:**

* when L → H chord too long

in this case we see that the speed to cross the well grows a lot (it goes towards infinity) therefore we do not have enough speed in the movement to cross

* when L → 0 very short string

the speed of the platform is very small, so we do not have the minimum required value

vox = √ (g / (2 (H)) D

**Explanation:**

For this exercise we are going to solve it using conservation of energy to find the velocity of the body and the launch of projectiles to find the velocity to cross the well.

Let's start with the projectile launch

as the body leaves the vertical its velocity must be horizontal

x = v₀ₓ t

y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

when reaching the ground its height of zero (y = 0) and the initial vertical velocity is zero

t = √ 2 y₀ / g

we substitute

x = vox √2y₀ / g

v₀ₓ = √(g / 2y₀) x

In the exercise, it tells us that the width of the well is D (x = D) and the initial height is the height of the platform minus the length of the rope (I = H - L)

v₀ₓ = √(g /(2 (H -L)) D

this is the minimum speed to cross the well.

Now let's use conservation of energy

starting point. On the platform

[tex]Em_{o}[/tex] = U = m g H

final point. At the bottom of the swing

Em_{f} = K + U = 1 / 2m v² + m g (H -L)

as there is no friction the mechanical energy is conserved

Em_{o} = Em_{f}

m g H = 1 / 2m v² + m g (H -L)

v = √ (2gL)

let's write our two equations

the minimum speed to cross the well

v₀ₓ = √ (g /(2 (H -L)) D

the speed at the bottom of the oscillatory motion

v = √ (2g L)

we analyze the extreme cases

* when L → H chord too long

in this case we see that the speed to cross the well grows a lot (it goes towards infinity) therefore we do not have enough speed in the movement to cross

* when L → 0 very short string

the speed of the platform is very small, so we do not have the minimum required value

vox = √ (g / (2 (H)) D

From this analysis we see that there is a range of lengths that allows us to have the necessary speeds to cross the well

V₀ₓ = v

g / (2 (H -L) D² = 2g L

4 L (H- L) = D²

4 H L - 4 L2 - D² = 0

L² - H L - D² / 4 = 0

let's solve the quadratic equation

L = [H ± √ (H2-D2)] / 2

we assume that H> D

L = ½ H [1 + - RA (1 - (D / H) 2)]

The two values of La give the range of values for which the two speeds are equal

A) The **person lands** in the moat if the **rope's length** is very short because :

B) The **person lands** in the moat if the rope length is similar to the **height** of the platform because :

Following the assumptions;

size of the person is much smaller than L and H

D = horizontal distance

The conditions that will cause the person to land on the moatTheHence we can conclude that The **person lands** in the moat if the **rope's length** is very short because The **speed** of the platform is less than the required **minimum speed** and The **person lands** in the moat if the rope length is similar to the **height** of the platform because,the** speed** required to cross the moat approaches **infinity.**

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The horizontal surface on which the block slides is frictionless. The speed of the block before it touches the spring is 6.0 m/s. How fast is the block moving at the instant the spring has been compressed 15 cm

**Answer:**

The final speed of the block moving at the instant the spring has been compressed is approximately 3.674 meters per second.

**Explanation:**

The spring constant is 2000 newtons per meter. Let consider the spring-block system, from Principle of Energy Conservation we can represent it by the following model:

[tex]U_{k,1}+K_{1} = U_{k,2}+K_{2}[/tex]

[tex]K_{2} = K_{1}+(U_{k,1}-U_{k,2})[/tex] **(Eq. 1)**

Where:

[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final kinetic energies of the block, measured in joules.

[tex]U_{k,1}[/tex], [tex]U_{k,2}[/tex] - Initial and final elastic potential energy, measured in joules.

And we expand the equation above by definitions of elastic potential energy and kinetic energy:

[tex]\frac{1}{2}\cdot m \cdot v_{2}^{2} = \frac{1}{2}\cdot m\cdot v_{1}^{2} + \frac{1}{2}\cdot k\cdot (x_{1}^{2}-x_{2}^{2})[/tex]

[tex]v_{2} = \sqrt{v_{1}^{2}+\frac{k}{m}\cdot (x_{1}^{2}-x_{2}^{2}) }[/tex] **(Eq. 1b)**

Where:

[tex]m[/tex] - Mass of the block, measured in kilograms.

[tex]k[/tex] - Spring constant, measured in newtons per meter.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final velocities of the block, measured in meters per second.

[tex]x_{1}[/tex], [tex]x_{2}[/tex] - Initial and final positions of spring, measured in meters.

If we know that [tex]v_{1} = 6\,\frac{m}{s}[/tex], [tex]k = 2000\,\frac{N}{m}[/tex], [tex]m = 2\,kg[/tex], [tex]x_{1} = 0\,m[/tex] and [tex]x_{2} = 0.15\,m[/tex], the final speed of the block moving at the instant the spring has been compressed is:

[tex]v_{2} = \sqrt{\left(6\,\frac{m}{s} \right)^{2}+\left(\frac{2000\,\frac{N}{m} }{2\,kg} \right)\cdot [(0\,m)^{2}-(0.15\,m)^{2}]}[/tex]

[tex]v_{2}\approx 3.674\,\frac{m}{s}[/tex]

The final speed of the block moving at the instant the spring has been compressed is approximately 3.674 meters per second.

Derivation 1.2 showed how to calculate the work of reversible, isothermal expansion of a perfect gas. Suppose that the expansion is reversible but not isothermal and that the temperature decreases as the expansion proceeds. (a) Find an expression

**Answer:**

(a) The work done by the gas on the surroundings is, 17537.016 J

(b) The entropy change of the gas is, 73.0709 J/K

(c) The entropy change of the gas is equal to zero.

Explanation:

(a) The expression used for work done in reversible isothermal expansion will be,

where,

w = work done = ?

n = number of moles of gas = 4 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = 240 K

= initial volume of gas =

= final volume of gas =

Now put all the given values in the above formula, we get:

The work done by the gas on the surroundings is, 17537.016 J

(b) Now we have to calculate the entropy change of the gas.

As per first law of thermodynamic,

where,

= internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

Thus, w = q = 17537.016 J

Formula used for entropy change:

The entropy change of the gas is, 73.0709 J/K

(c) Now we have to calculate the entropy change of the gas when the expansion is reversible and adiabatic instead of isothermal.

As we know that, in adiabatic process there is no heat exchange between the system and surroundings. That means, q = constant = 0

So, from this we conclude that the entropy change of the gas must also be equal to zero.

**Explanation:**

A soccer ball accelerates from rest and rolls 6.5m down a hill in 3.1 s. It then bumps into a tree. What is the speed of the ball just before it hits the tree.

Answer:

2.096m/s

Explanation:

The speed of this soccer ball can be calculated using the formula;

Speed = distance/time

According to this question, the distance of the ball before it hits the tree is 6.5m, the time it takes is 3.1s, hence;

Speed = 6.5/3.1

Speed of the ball = 2.096m/s

Therefore, the speed of the ball before hitting the tree is 2.096m/s

1. What is Ohm"s law?

2. If you placed a negatively charged hairbrush near your hair, what charge would your hair be?

3. You must change a lightbulb and the new lightbulb has a larger resistance. If the voltage of the battery does not change, what happens to the current going through the flashlight?

HELLPPPP

1. Ohm's law shows the relationship between:

voltagecurrentresistanceFormula: voltage = current x resistance

2. The negative charge on the hairbrush will induce a positive charge on your hair. As a result, your hair is going to be attracted to the hairbrush (and repelled by other strands of hair.)

3. V = IR, so if the resistance of the current increases, and the voltage of the current stays the same, there is as a result, going to be less current.

Best of Regards!

A person walks 2.00 m east, then turns and goes 4.00 m west, then turns and goes back 1.00 m east. what is the distance and displacement

**Explanation:**

Let east = E, and, west = opposite to east = - E.

Here, displacement:

=> 2m east + 4m west + 1m east

=> 2E + 4(-E) + 1E

=> 2E - 4E + 1E

=> - 1E

=> 1(-E)

=> 1m west

And, distance,

=> 2m + 4m + 1m = 7m

The **distance **of a person is **7 m** and the **displacement **of the person is **1m west.**

To **find **the distance and displacement, the given values are,

A person **walks **2.00 m east, then turns and goes 4.00 m west, then turns and **goes **back 1.00 m east.

**Displacement**:

**Distance**:

Let us **consider **East = E and west = **opposite **to east = - E.

**Calculating **the **displacement**:

= 2m east + 4m west + 1m east

= 2E + 4(-E) + 1E

= 2E - 4E + 1E

= - 1E

= 1(-E)

= 1m west.

The **displacement **is **1m west**.

Now **calculating **the distance,

= 2m + 4m + 1m

= 7m

The **distance **is **7m.**

Thus, the displacement and the distance is found as **1 m west and 7m.**

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Research has shown that this type of interview is the most effective in predicting later job

performance.

**Answer:**

Situational Interview

**Explanation:**

A situational interview is about as close to the real job as it gets. During this type of interview, candidates may be presented with a visual or audio simulation of a scenario and asked to respond to it. They are asked to analyze a problem and profer suggestions on how they would handle it.

If the candidate has solved similar problems in the past, it will come to the fore.

If they haven't then the best outcome is that it will tell the interviewers how well the candidate is able to solve similar problems.

An example of a Situational Interview question is this:

**How would you handle an angry customer who for no justifiable reason has decided to create a problematic scene to disrupt the business?**

Because Situational Interviews are about behavioral responses (present, past, and future), they are powerful tools in determining or predicting future job performance. An interviewing technique that is developed using this methodology is called the S.T.A.R.

This is an acronym for **Situation, Task, Action, Result.**

Situation: the candidate is asked to present a challenging situation that occurred recently. *This tests what the candidate sees as a challenging situation.*

Task: The candidate based on the situation is asked to identify what they need to do to remedy the problem. *This tells the interviewer(s) whether or not the candidate can think up a solution for the problem.*

Action: Here they define the actual steps taken to resolve the problem

Result: The candidate against the above is required to give the result gotten

**Action** and **Result **tell the interviewer the quality of the candidate's ability to follow through and achieve the intended results. This also judges the quality of execution in terms of cost and time. The candidate with the lowest cost and time and the highest quality of outcome is considered the best.

Cheers

A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?

The force 120 Newton’s

Silly Goose falls 1.0 m to the floor. How long does the fall take

**Answer:**You need to give more explanation sorry

**Explanation:**

**Answer:**

4.20 seconds

**Explanation:**

Supposing that silly goose weighs 69 pounds, we need to start on the math.

Simple maths, truly and really. 69/1=69, of course.

Therefore it will take 4.20 seconds for silly goose to hit the ground. if he is going to be a silly goose though, he can just go in the pond, instead of wasting his time.

plzzz helppp

You are pushing a box North in the hallway, at 20n, and a friend gets in front of the box and goes in the opposite direction, at 30n. What direction is the box going at? How much force does the box have going in that direction?

**Answer:**

the box is going south at 10n

**Explanation:**

If 0.5 kg of this material is used in a transformer core, how long would it have to operate at a frequency of 60 cps to heat up 1

**Answer:**

Hello your question is incomplete attached below is the complete question

answer : 49 seconds

**Explanation:**

considering only Hysteresis loss

we have to calculate the Area affected/under the Hysteresis loss

= volume * area

= 4 * ( 1.5 * 20 ) = 120 tesla. A/m

**next we calculate the volume of the material**

= mass of material / density

= 500 grams / 7.9 g/cm^3 = 6.33 * 10^-5 m^3

**next we calculate the heat lost per cycle **

= 6.33 * 10^-5 m^3 * 120 = 0.007596 joules

**The total heat required to raise temperature by 1°c**

= Cp * ΔT * n

= 3R * n * ΔT = 3(8.314) * 8.95 * 1 = 223.23 Joules

where n = number of moles = 500grams / 55.85 = 8.95moles

ΔT = 1

Therefore the time required to have to operate at a frequency of 60 cps

= Total heat required / heat lost per cycle

=( 223.23 / 0.007596 ) 60 cps

= 489.796 seconds ≈ 49 seconds

A person has a mass of 1000g and an acceleration of 20 m/s/s. What is the force on the person

**Answer:**

20000

**Explanation:**

Newtons Second law states that the force acting on an object is equal to its mass times its acceleration, f=ma. To solve for force, plug in your values for m and a, and then solve. f = (1000)*(20) = 20000

A .05 kg rubber ball is dropped and hits the floor with an initial velocity of 10 m/s. It rebounds away from the floor with a final speed of 7 m/s after being in contact with the floor for .01 seconds. Find the magnitude of the force exerted by the floor on the rubber ball.

**Answer:the answer is 3**

**Explanation:**

It took 50 joules to push a chair 5 meters across the floor. With what force was the chair pushed?

**Answer:**

The chair was pushed with 10 N.

**Explanation:**

The chair was pushed with 50 Joules.

Work = Force * Distance

50 J = F * 5m

F = 50 / 5 = 10N

The chair was pushed with 10 N.

The chair was pushed with **10 N **force.

**Work **is defined as the measure of **energy transfer **that occurs when an object is moved over a distance by an external force, at least part of which is applied in the direction of **displacement**.

If the force is **constant **then **work **can be calculated by multiplying the length of the path by the component of the force acting along the path, which is expressed mathematically as work W equal to the force f over a distance d, or **W = fd. **

So, for above given information,

Work done= 50 joules

Distance covered by the chair = 5m

Then, Force= W/d

=50/5= 10N

Thus, the chair was pushed with **10 N **force.

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Examine the diagram below.

Which of the above objects is moving the fastest?

A.

All 3 objects are moving at the same speed.

B. B

C. C

D. A

**Answer:**

*Correct choice: D. Object A is the fastest*

**Explanation:**

In a distance vs time graph, the distance is plotted vertically, and the time is plotted horizontally.

The diagram shows three graphs of objects A, B, and C.

The graph of A shows the object traveled 12 meters in 3 seconds, for a speed of 12/3= 4 m/s.

The graph of B shows the object traveled 8 meters in 4 seconds for a speed of 8/4=2 m/s.

Finally, the object C travels 4 meters in 4 seconds, for a speed of 4/4= 1 m/s

Thus, **the fastest object is A.**

Grass and plants get energy from

А

the sun.

B

eating food.

с

windmills.

D

electrons.

A is the answer for that question

**Answer:**

From the Sun

**Explanation:**

Plants can't eat any food. They don't ue or need windmills to get energy. They are plants so they don't have any electrons. The only way that they can recive energy from is the sun. Sometimes plants die when they don't get enough sun because they don't have any energy to live.

A

6. All other changeable factors that must

be kept the same to ensure a fair test

(what you keep the same).

**Answer:**

a constant variable?

**Explanation:**

A constant variable is any aspect of an experiment that a researcher intentionally keeps unchanged throughout an experiment.

Experiments are always testing for measurable change, which is the dependent variable. You can also think of a dependent variable as the result obtained from an experiment. It is dependent on the change that occurs

What is the key for a successful relationship? and Why?

**Answer:**

communication, if you don't talk you'll never know what's going on.

**Explanation:**

The boys are finally old enough to compete in the box car derby race at the local fair. They have been working on their cars since the conclusion of the race last year. One boy's car raced down the track and placed 2nd in his race. However, the other boy's car started well but half-way through the race a wheel came off and his car came to a complete stop. The boy was very disappointed and the other boy felt horrible for his friend. Which of the following graphs best represents the motion of boy's car that stopped?

i think it’s b because they both stumbled up a hole

Compare and contrast the CONFLICT (choose one) in the short story you read with the elements appearing in The Watsons Go to Birmingham—1963. Explain how they are similar or different in a few sentences.

**Answer:**

they were in two places in flint and Birmingham and in Birmingham it is hot but flint of cold the Simi is they both have Sunday school for Joetta

**Explanation:**

use in your own words teachers know when your not trust me.

The Earth's magnetic field is modeled as that of a bar magnet with the geographic poles being Magnetic poles of the bar magnet, Based on our definitions of Magnetic Poles, if you were to go to the Earth's Geographic North Pole, you would be at a Magnetic _______________ of the bar magnet.

**Answer:**

**South pole**

**Explanation:**

In a bar magnet, field lines go from the North Pole to the South Pole (outside the magnet).

As the earth magnetic field lines go from South Pole (geographic) to the North one, this means that the North pole (geographic) really behaves as a South Pole (magnetic).

A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s2 over a distance of 340 m. How fast is it going after that acceleration?

**Answer:68.15m/s**

**Explanation:**

**Given: **

v₁=15m/s

a=6.5m/s²

v₁=?

x=340m

**Formula:**

v₁²=v₁²+2a (x)

**Set up:**

=[tex]\sqrt{15m/s} ^{2} +2(6.5m/s^2)(340m)[/tex]

Two charged objects are separated by distance, d. The first charge has a larger magnitude (size) than the second charge. Which one exerts the most force?

**Answer:**

The two charged objects will exert equal and opposite forces on each other.

**Explanation:**

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of charges on the objects and inversely proportional to the square of the distance between the two objects.

This force of attraction or repulsion between the two charged objects is always equal and opposite.

Therefore, **the two charged objects will exert equal and opposite forces on each other.**

A vector of components (−23, −22) is multiplied by the scalar value of −6. What is the magnitude and direction of the resultant vector?

**Answer:**

(1,)

**Explanation:**

**Answer:**

magnitude: 21.6; direction: 33.7°

**Explanation:**

Write a haiku

poem

explaining

why graphing

is useful.

If you are

able, share

your poem

with others.

**Answer:**

**Explanation:**

graphing is helpful

helps visualize the line

of your equation

What algebraic expression could represent the average of 2x, x + 3, and 6x?
You throw a ball straight up into the air at a velocity of 15 m/s. You want to know how high above your hand the ball will be at exactly 2.5 sec after you released it. You must SHOW ALL WORK to receive credit!!! Of the 5 motion variables - Vi, Vf, a, X, and T, identify which one you are solving for and the magnitudes and directions of all of the others that are known: Which of the motion equations is best to use to determine the height of the ball? How high is the ball above your hand at 2.5 sec after you throw it?
HELP WILL MARK YOU BRAINLIEST NO GUESSES PLZ!!!!
22 pts + brainliest Pls help ! At what point in the writing process shouldyou focus on your introductory paragraph: a) the end of drafting processb) beginning of the pre writing processc) end of editing processd) beginning of drafting Process
Which of the following is NOT a characteristic of all living things?Ability to reproduceAbility to moveO Growth and developmentHomeostasis
Define the following terms:
Drag the tiles to the correct boxes to complete the pairs.The poet seeks to draw a contrast between the permanence of Nature and the changeableness of men. As the poet returns tothe rivulet over the course of his life, he is acutely aware of certain truths. Match these truths, or themes, to the lines from thepoem that represent themPeople have dreams thatremain unfulfilledPeople have pleasant lifeexperiences worth recallingPeople cannot stay the samepeople must age and pass awayLines from PoemThemesAnd the grave stranger, come to seeThe play-place of his infancy,And, singing down thy narrow glen,Shalt mock the fading race of men.I've tried the world-- it wears no moreThe colouring of romance it wore.RI3:54 PM10/18/2020
pros and cons of being a federalist
Curbs on the power of the majority to make decisions that would benefit some at the expense of other are called?
20How do you determine the number of barium atoms in the formula below?4Ba(OH)2F# of Ba atoms = coefficient 4 + subscript 1 = 5G# of Ba atoms = coefficient 4 X subscript 1 = 4H# of Ba atoms = subscript 4 X coefficient 2 = 6# of Ba atoms coefficient 1 + subscript 1 = 2J
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Please answer quickly if you can.Which element is most important in a multimedia presentation?A.Each slide should cover only one topic.B.The fonts and colors should be bright and cheerful.C.The slides should be organized in order of importance.D.Each slide should have as much information as possible.
what is the diffrent between weather and climate
Organelle that makes glycoproteins, which help transport proteins out of the cell.O Golgi ApparatusMitochondriaO NucleusRibosomes
PLS TELL ME WHICH ONE IS TRUE PLS DONT LIE
A coordinate plane is shown. Triangle PQR has vertices P at negative 6 comma 6, Q at negative 6 comma 3, and R at negative 3 comma 3. Triangle P prime Q prime R prime has vertices at P prime negative 2 comma 2, Q prime at negative 2 comma 1, and R prime at negative 1 comma 1. What is the scale factor of dilation?
Maggies brother is 11 years younger than four times her age. The sum of their ages is 54. How old is Maggie?
help please!!For the following situation, identify the explanatory and response variable. Then discuss what reservations (think cautions) you might have about the results of the experiment. Asking What if type questions may help.Do the high, centered brake lights (which have been required on all U.S. cars since 1986) really reduce the frequency of rear-end collisions? Randomized comparative experiments with fleets of rental and business cars, done before the lights were required, showed that the third brake light reduced rear-end collisions by as much as 50%. After the lights were required the drop was only 5%.
research and tell the story about a case in which bones helped identify a missing person or helped solve a crome
do any of you know how to do algebra 2 ?