Answer:
The factorial of 3=6
Explanation:
Following are the description of the given question
This is JavaScript code .Here items are the variable that are holding the integer value "3".After that there is 2 loop are iterating one is outer and one inner loop. When i=1 1<=3 the condition of outer loop is true the control moves the inner loop .In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=1 1>=1 condition of inner loop is true it executed the statement inside the inner loop so result =1 .Now we increment the value of i of the outer loop.i=2 2<=3 the condition of outer loop is true the control moves the inner loop .In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=2 2>=1 condition of inner loop is true it executed the statement inside the inner loop so result =2 .Now we increment the value of i of the outer loop.Now i=3 3<=3 the condition of outer loop is true the control moves the inner loop .In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=3 3>=1 condition of inner loop is true it executed the statement inside the inner loop so result =6 .Now we increment the value of i of the outer loop.i=4 4<=3 the condition of outer loop is false the control moves from the outer loop.It print The factorial of 3=6Sarah's Texas location has a server that is starting to give her trouble. It is needing to be restarted frequently and seems to be very slow. The server is on the replacement schedule and has just overheated, stopped and will not restart. What plan should direct the recovery for this single server
Answer:
Hello your question lacks the required options
A) Business impact analysis plan
B) Business continuity plan
C) Disaster recovery plan
D) Recovery point plan
answer : Disaster recovery plan ( c )
Explanation:
The Disaster recovery plan is a comprehensive creation of a system/set procedures of recovery of the IT infrastructure from potential threats of a company. especially when the interruption is caused by a disaster, accident or an emergency.
The shutting down of the sever due to overheating and not able to restart for Business is an interruption in a critical business process and the plan to direct the recovery for this single server should be the " Disaster recovery plan"
Write a Python function that will accept as input three string values from a user. The method will return to the user a concatenation of the string values in reverse order. The function is to be called from the main method.
Answer:
Following are the program in python language
def cat_rev(x,y,z): # function definition
x=x[::-1]# reverse the first string
y=y[::-1]# reverse the second string
z=z[::-1]# reverse the third string
z=x+y+z; #concat the string
return(z)#return the string
#main method
s=input("Enter the first string:") #read the first string
r=input("Enter the second string:")#Read the second string
t=input("Enter the third string:")#Read the third string by user
rev1= cat_rev(s,r ,t ) #function calling
print(rev1)# display reverse string
Output:
Enter the first string:san
Enter the second string:ran
Enter the third string:tan
nasnarnat
Explanation:
Following are the description of program
In the main function we read the three value by the user in the "s", "r" and "t" variable respectively.After that call the function cat_rev() by pass the variable s,r and t variable in that function .Control moves to the function definition of the cat_rev() function .In this function we reverse the string one by one and concat the string by using + operator .Finally in the main function we print the reverse of the concat string .Design an Ethernet network to connect as a single client PC to a single server. Both the client and the server will connect to their workgroup switches via UTP. The two devices are 900 meters apart. They need to communicate at 800 Mbps. Your design will specify the locations of any switches and the transmission link between the switches.
Answer:
We would need 3 switches to connect a single client PC to a single server.
Connect server to switch 1 (225 m)Connect switch 1 to switch 2 (225 m)Connect switch 2 to switch 3 (225 m)Connect switch 3 to client PC (225 m)Explanation:
The maximum distance for ethernet connection is approximately 100 meters for transmission speeds up to 1000 Mbps but the distance may be increased if we add network switches between the client PC and the server.
After the addition of network switches, the distance may be increased up to 200 meters plus 10 to 30 meters more without any substantial decrease in transmission speed.
So we have 900 meters of distance between the client PC and the server.
The Ethernet network may be designed as below:
Connect server to switch 1 (225 m)Connect switch 1 to switch 2 (225 m)Connect switch 2 to switch 3 (225 m)Connect switch 3 to client PC (225 m)Total distance covered = 225 + 225 + 225 + 225
Total distance covered = 900 meters
Therefore, we would need 3 switches to connect a single client PC to a single server.
The layout of the design is illustrated in the attached diagram.
Answer:
hi
Explanation:
Language/Type: Java ArrayList Collections
Author: Marty Stepp (on 2016/09/08)
Write a method swapPairs that switches the order of values in an ArrayList of Strings in a pairwise fashion. Your method should switch the order of the first two values, then switch the order of the next two, switch the order of the next two, and so on. For example, if the list initially stores these values: {"four", "score", "and", "seven", "years", "ago"} your method should switch the first pair, "four", "score", the second pair, "and", "seven", and the third pair, "years", "ago", to yield this list: {"score", "four", "seven", "and", "ago", "years"}
If there are an odd number of values in the list, the final element is not moved. For example, if the original list had been: {"to", "be", "or", "not", "to", "be", "hamlet"} It would again switch pairs of values, but the final value, "hamlet" would not be moved, yielding this list: {"be", "to", "not", "or", "be", "to", "hamlet"}
Language/Type: Java ArrayList Collections
Author: Marty Stepp (on 2016/09/08)
Write a method removeEvenLength that takes an ArrayList of Strings as a parameter and that removes all of the strings of even length from the list.
Type your solution here:
1. for (Iterator iterator = numbers.iterator(); iterator.hasNext();)
2. { Integer number = iterator.next();
3. if (number % 2 == 0) {
4. System.out.println("This is Even Number: " + number);
5. iterator.remove(); mtino
6
7
8 } This is a method problem.
Write a Java method as described. Do not write a complete program or class; just the method(s) above.
Language/Type: Java ArrayList Collections
Author: Marty Stepp (on 2016/09/08)
Write a method removeDuplicates that takes as a parameter a sorted ArrayList of Strings and that eliminates any duplicates from the list. For example, suppose that a variable called list contains the following values: {"be", "be", "is", "not", "or", "question", "that", "the", "to", "to"} After calling removeDuplicates (list); the list should store the following values: {"be", "is", "not", "or", "question", "that", "the", "to"}
Because the values will be sorted, all of the duplicates will be grouped together.
Type your solution here:
WN 600 O
This is a method problem. Write a Java method as described. Do not write a complete program or class; just the method(s) above.
Answer:
Answer a)public void swapPairs(ArrayList<String> list) {
for(int i = 0; i <= list.size() - 2; i += 2) {
String val= list.get(i + 1);
list.set(i + 1, list.get(i));
list.set(i, val); } }
Answer b)Using the Iterator interface to remove the strings of even length from the list:
public void removeEvenLength( ArrayList<String> list) {
Iterator<String> iter= list.iterator();
while( iter.hasNext() ) {
String str= iter.next();
if( str.length() % 2 == 0 ) {
iter.remove(); } } }
Not using Iterator interface:
public static void removeEvenLength(ArrayList<String> list) {
for (int i = 0; i < list.size(); i++) {
String str= list.get(i);
if (str.length() % 2 == 0) {
list.remove(i);
i--; } } }
Answer c)public static void removeDuplicates(ArrayList<String> list) {
for (int i = 0; i < list.size() - 1; i++) {
if (list.get(i).equals(list.get(i + 1))) {
list.remove(i + 1);
i--; } } }
Explanation:
a) The method swapPairs(ArrayList<String> list) ArrayList is used to store elements of String type. The for loop has a variable i that is initialized by 0. It moves through the list. This loop's body stops executing when the value of i exceeds the size-2 of the list. The size() method returns the size of the list. This means i stops moving through the list after the last pair of values is reached. In the loop body, get(i+1) method is used to obtain the element in the list at a index i+1. Lets say in the list {"four", "score", "and", "seven", "years", "ago"}, if i is at element "four" then i+1 is at "score". Then "score" is stored in val variable. Then set() method is used to set i-th element in an ArrayList object at the i+1 index position. The second set(i,val) method is used to set the value in val variable to i-th position/index. So this is how score and four are switched.
b) The method removeEvenLength( ArrayList<String> list) takes ArrayList of Strings as parameter. Iterator is an interface which is used to traverse or iterate through object elements and here it is used to remove the elements. The iterator() method is used to traverse through the array list. The while loop will keep executing till all the elements of the ArrayList are traversed. hasNext() method is used to return True if more elements in the ArrayList are to be traversed. next() method is used to return next element in the ArrayList and store that element in str variable. Then the if statement is used to check if the element in str variable is of even length. The length() function returns the length of the element in ArrayList and modulus is used to check if the length of the element is even. If the condition evaluates to true then the remove() method is used to remove that element of even length from the list.
c) The method removeDuplicates(ArrayList<String> list) takes ArrayList of Strings as parameter and eliminates any duplicates from the list. It has a for loop that moves through the list and it stops executing when the value of i exceeds the size - 1 of the list. The if condition has two method i.e. get() and equals(). The get() method is used to obtain the element at the specified index position and equals() function is used to compare the two string elements. Here these two strings are obtained using get() method. get(i) gets element at i-th index and get(i+1) gets element at i + 1 position of the list. If both these elements are equal, then the element at i+1 index is removed. This is how all duplicates will be removed.
All of the following are true about hacksaws except: a. A hacksaw only cuts on the forward stroke. b. A coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. c. A fine hacksaw blade (one with many teeth) is better for cutting sheet metal. d. A hacksaw blade is hardened in the center, so it is best to saw only with the center portion of the blade.
All of the following are true about hacksaws, except a coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. The correct option is b.
What is a hacksaw?A hacksaw is a saw with fine teeth that were originally and primarily used to cut metal. Typically, a bow saw is used to cut wood and is the corresponding saw.
Hacksaw is used by hand, it is a small tool for cutting pipes rods wood etc that is very common and homes and in shops. The different types of hacksaws. The main three types of hacksaws are course-grade hacksaws, medium-grade hacksaws, and fine-grade hacks. The difference is just for the quality, and the design of the blade.
Therefore, the correct option is b. Cutting thick steel is easier with a coarse hacksaw blade (one with fewer teeth) than a fine one.
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Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 1024-byte 4-way set associative cache using 32-bit memory addresses and 8-byte cache blocks.
Answer:
The answer is The Cache Sets (S) = 32, Tag bits (t)=24, Set index bits(s) = 5 and Block offset bits (b) = 3
Explanation:
Solution
Given Data:
Physical address = 32 bit (memory address)
Cache size = 1024 bytes
Block size = 8 bytes
Now
It is a 4 way set associative mapping, so the set size becomes 4 blocks.
Thus
Number of blocks = cache size/block size
=1024/8
=128
The number of blocks = 128
=2^7
The number of sets = No of blocks/set size
=128/4
= 32
Hence the number of sets = 32
←Block ←number→
Tag → Set number→Block offset
←32 bit→
Now, =
The block offset = Log₂ (block size)
=Log₂⁸ = Log₂^2^3 =3
Then
Set number pc nothing but set index number
Set number = Log₂ (sets) = log₂³² =5
The remaining bits are tag bits.
Thus
Tag bits = Memory -Address Bits- (Block offset bits + set number bits)
= 32 - (3+5)
=32-8
=24
So,
Tag bits = 24
Therefore
The Cache Sets = 32
Tag bits =24
Set index bits = 5
Block offset bits = 3
Note: ←32 bits→
Tag 24 → Set index 5→Block offset 3
Define a function is_prime that receives an integer argument and returns true if the argument is a prime number and otherwise returns false. (An integer is prime if it is greater than 1 and cannot be divided evenly [with no remainder] other than by itself and one. For example, 15 is not prime because it can be divided by 3 or 5 with no remainder. 13 is prime because only 1 and 13 divide it with no remainder.) This function may be written with a for loop, a while loop or using recursion. Use the up or down arrow keys to change the height.
Answer:
This function (along with the main)is written using python progrmming language.
The function is written using for loop;
This program does not make use comments (See explanation section for detailed line by line explanation)
def is_prime(num):
if num == 1:
print(str(num)+" is not prime")
else:
for i in range(2 , num):
if num % i == 0:
print(str(num)+" is not prime because it can b divided by "+str(i)+" and "+str(int(num/i))+" with no remainder")
break;
else:
print(str(num) + " is prime because only 1 and "+str(num)+" divide it with no remainder")
num = int(input("Number: "))
is_prime(num)
Explanation:
This line defines the function is_prime
def is_prime(num):
The italicize line checks if the user input is 1; If yes it prints 1 is not prime
if num == 1:
print(str(num)+" is not prime")
If the above conditional statement is not true (i.e. if user input is greater than 1), the following is executed
else:
The italicized checks if user input is primer (by using for loop iteration which starts from 2 and ends at the input number)
for i in range(2 , num):
if num % i == 0:
This line prints if the number is not a prime number and why it's not a prime number
print(str(num)+" is not prime because it can b divided by "+str(i)+" and "+str(int(num/i))+" with no remainder")
break;
If otherwise; i.e if user input is prime, the following italicized statements are executed
else:
print(str(num) + " is prime because only 1 and "+str(num)+" divide it with no remainder")
The function ends here
The main begins here
num = int(input("Number: ")) This line prompts user for input
is_prime(num) This line calls the defined function
In cell B17, enter a formula that uses the IF function and tests whether the total sales for January (cell B10) is greater than or equal to 200000.
Answer:
=IF(B10>=200000,"YES","NO")
Explanation:
The following assumptions are made to answer this question
- If the content of cell B10 is greater than or equal to 200000, cell B17 will return YES
- If otherwise, cell B17 will return NO
Having highlighted the above assumptions;
To start with; an excel formula must begin with an = sign
Followed by the IF condition
The content of the IF condition is analyzed as follows:
B10>=200000:- This is to test if cell B10 is greater than or equal to 200000
"YES" -> If the above condition is true, cell B17 will display YES
"NO" -> If otherwise, cell B17 will display NO
The conditional statement, IF to check if total sales is less than or equal to 200000 is =IF(B10 >= 200000, 'TRUE', 'FALSE')
The IF statement in excel is used to check a given condition and a preferred output is given if the condition hold true and another output if otherwise. Excel formulas begin with the equal to sign ; =The statement above checks through each values in cell B10; if the value is greater than or equal to 200000For cells with values greater than or equal to 200,000 display TRUE in the corresponding cell ; otherwise display FALSE.Therefore, the required statement to be entered on cell B17 is =IF(B10 >= 200000, 'TRUE', 'FALSE')
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A security analyst is interested in setting up an IDS to monitor the company network. The analyst has been told there can be no network downtime to implement the solution, but the IDS must capyure all of the network traffic. Which of the following should be used for the IDS implementation?
a. Network tap
b. Honeypot
c. Aggregation
d. Port mirror
Answer:
d. Port mirror
Explanation:
Port mirroring is a method to monitor network traffic and it is used in the Intrusion Detection Systems. It is also called Switched Port Analyzer and is used to analyse the network errors. This technique basically copies the network packets and sends or transmits these copied packed from one port to another in a network device such as a switch. This means that this technique is used to copy the network packets from one switch port and send the copy of these packets to another port where these packets are monitored. This is how it analyses the network errors and incoming traffic for irregular behavior and also this can be done without affecting the normal operation of the switch and other network processes. It is simple, inexpensive and easy to establish and use. The most important advantage of using mirrored ports is that it catches the traffic on several ports at once or can capture all of the network traffic.
Access and read the article "A Brief History Malware" (and perhaps some of the links at its end) and share any experience you may have had with a virus or malware attack. If you haven't knowingly suffered an attack, which of the malware listed would you most fear? And why?
Answer:
The type of malware i would fear the most is the Zeus malware.
This type of malware tries to gain access to private financial information of the user.
This malware can also share the data to even more people and can turn out to to very dangerous to users.
Explanation:
Solution
The presence of malware in the IT world is very common as of today. the most dangerous malware in this regard for me is as follows:
Zeus or Zbot: This is a malware which affects users of Windows and tries to access confidential financial information of the user.
It tries to steal confidential data from the already infected system like gaining access to the user's password, details of bank account, bank credentials.It can steal the hard earned money of users which can upturn the life of people.The malware can then share this data to even more people and can turn to be more dangerous.Dotted Decimal Notation was created to______________. Group of answer choices provide an alternative to IP addressing express each eight bit section of the 32-bit number as a decimal value provide a more convenient notation for humans to understand both a and b both b and c both a and c
Answer:
Both b and c
Explanation:
Dotted Decimal notation is a presentation of numerical data which is expressed as decimal numbers separated by full stops. Dotted decimal notation expresses each eight bit sections of 32 bit numbers as decimal value. It provides convenient notation which is easy to understand by the people who are IT experts.
The performance of a client-server system is strongly influenced by two major network characteristics: the bandwidth of the network (how many bits/sec it can transport) and the latency (how many seconds it takes for the first bit to get from the client to the server). Give an example of a network that exhibits high bandwidth but also high latency. Also give an example of one that has both low bandwidth and low latency. Justify/explain your answers. (
Answer:
A bandwidth is the maximum rate of transfer of data across a given path
Latency refers to the delay of data to travel or move between a source and destination
An example of a high bandwidth and high latency network is the Satellite Internet connectivity.
An example of a low bandwidth and latency network is the telephone system connection.
Explanation:
Solution
Bandwidth: Bandwidth determines how fast data can be transferred for example, how many bits/sec it can transport.
Latency: It refers to the delay or how long it takes for data to travel between it's source and destination.
An example of a high bandwidth and high latency network is the Satellite internet connection.
Satellite internet connection: This is responsible for the connectivity of several systems, it has a high bandwidth, since satellite are in space, due to distance it has a high latency.
So, satellite internet connection is compensated with high latency and high bandwidth.
An example of a low bandwidth and low latency network is the Telephony network.
Telephone/telephony internet connection: This connection does not have much data for transfer. it has low size audio files of which a low bandwidth range. also for both end or end users to understand and talk to each other, it has low latency.
An example of a network that exhibits high bandwidth but also high latency is Satellite internet connection.
An example of one that has both low bandwidth and low latency is telephony internet connection.
Based on the provided information, we can say that Satellite internet connection posses high bandwidth but also high latency because, the fastness of data transfer is based on the bandwidth and how the data to travel between it's source and destination is based on its latency.
We can conclude that telephony internet connection has low bandwidth and low latency because of low data transfer is required.
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Suppose that we pick the following three tuples from a legal instance of a relation S (S has 100 tuples in total). Relation S has the following schema: (A : integer, B : integer, C : integer). The three tuples are: (1,2,3), (4,2,3), and (5,3,3). Which of the following dependencies can you infer does not hold over S?
A. A → B,
B. BC → A,
C. C → B
Answer:
The correct answer is BC → A, A does not hold over S. we noticed the tuples (1 ,2 ,3 ) and (4 ,2 ,3) which can hold over S)
Explanation:
Solution
No, since in this case the instance of S is provided. so such particular dependencies are unable to breach through such instance, but unable to tell which the dependencies hold towards S.
A functional dependency holds towards only when a relation forms a statement regarding the complete allowed instances of relation.
A process on host 1 has been assigned port p, and a process on host 2 has been assigned port q. Is it possible for there to be two or more TCP connections between these two ports at the same time?
Answer:
In this case, a possibility does not occur because a connection is only identified by the sockets. so the (1-p) - (2,q) is the only possible connections between the ports p and q.
Explanation:
Solution
TCP (Transmission Control protocol):
The TCP is a connection-oriented transport protocol; it provides a better, organised and error checked data packet delivery.TCP uses many protocols;the two main protocols are TCP, IP (Internet Protocol).TCP uses a already known standard to transmit the data over networks.The Scenario:
Host 1 process assigned to port ''p''Host 2 process assigned to port ''q''The possibility for the two or more TCP connections between ports p and q:
No, there is no possibility for two or more TCP connections between these two ports simultaneously; this is so because a connection is only identified by the sockets.
Therefore, the (1-p) - (2,q) is the only attainable connections between the ports p and q.
A file manager is used for all of the following except ____. A. to move files and folders B. to reorder files and folders C. to name files and folders D. to navigate between folders
Answer:
C- To name files and folders
Explanation:
This answer was marked correct on my Cengage quiz.
A file manager is used for all of the following except to name files and folders.
A file manager simply means a computer program which provides a user interface that's vital in managing files and folders.A file manager allows the user to move the files and folders from one location to another. It also helps in the reordering of files and folders, and to navigate between folders.It enables the user to view, copy, edit, and delete the files that they've on their computer storage devices. It should be noted that the file manager isn't used for naming files and folders.In conclusion, the correct option is C.
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This program has some errors in it that are needed to be checked import java.io.*;
public class Westside
{
public static void main(String args[])throws IOException
{
double cost=0;
double s=100.0;
int n=100;
int z=0;
double disc=0;
String name[]=new String[n];
double price[]=new double[n];
{
double Billamt=0;
String st;
InputStreamReader read= new InputStreamReader(System.in); BufferedReader in= new BufferedReader(read);
while (true)
{
System.out.println("***********************************************"); System.out.println("*************WELCOME TO WESTSIDE*************** !!!"); System.out.println("***********************************************"); System.out.println(" The Clothing where all your needs for clothes and a little bit of accessories are fulfilled");
System.out.println(" If you are in the mood for shopping... YOU ARE IN THE RIGHT PLACE!"); Westside obj=new Westside(); do { System.out.println(" We allow customers to shop conveniently and provide them a wide variety of choices to choose from"); System.out.println("The choices are \n 1. Women's Wear"); System.out.println("2.Men's Wear \n 3. Surprise Section! \n 4.Kids Wear \n 5. Accessories"); System.out.println("and 6. Shoes"); System.out.println("Enter your choice"); int c=Integer.parseInt(std.readLine()); switch (c) { case 1: obj. Women(); break; case 2: obj. Men(); break; case 3: obj. Surprise(); break; case 4: obj. Kids(); break; case 5: obj. Accessories(); break; case 6: obj. Shoes(); break; default: System.out.println("Please check your Input"); } System.out.println("Please type 'stop' if you want to stop"); System.out.println("Type anything else if you want to continue shopping."); st=std.in.readLine(); while(!(st.equalsIgnoreCase("stop"))); System.out.println("Your Bill:"); System.out.println("Sl.no \t Item Name \t \t \t \t Cost of the Item"); for(int i=0;i
Answer:
for loop statement is not complete
Give an example of a function from N to N that is: Hint: try using absolute value, floor, or ceiling for part (b). (a) one-to-one but not onto (b) onto but not one-to-one (c) neither one-to-one nor onto
Answer:
Let f be a function
a) f(n) = n²
b) f(n) = n/2
c) f(n) = 0
Explanation:
a) f(n) = n²
This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.
Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:
f(a) = f(b) ⇒ a² = b² ⇒ a = b
The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number. For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.
b) f(n) = n/2
The above function example is an onto function because every natural number, let’s say n is a natural number that belongs to N, is the image of 2n. For example:
f(2n) = [2n/2] = n
The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:
When the value of n=1, then
n/2 = [1/2] = [0.5] = 1
When the value of n=2 then
n/2 = [2/2] = [1] = 1
c) f(n) = 0
The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image. The above function example is also not an onto function because every positive integer is not an image of any natural number.
Define a function that takes an argument. Call the function. Identify what code is the argument and what code is the parameter.
Answer:
The programming language is not stated; however, I'll answer this question using Python programming language.
The program is as follows;
def mul(num):
print(num ** 3)
num = 2
mul(num)
Explanation:
The above simple program returns the cube of a number
The parameter is what is being passed to a function;
In this case, the parameter is num
The value of a parameter is what is referred to as argument.
In this case, the argument is 2
So, when the program is executed; the expected output is 8 (i.e. 2³ = 8)
The illustration of a function definition in python is given below, the program is written in python 3 thus :
def cube_value(num):
#initializes a function with takes on one parameter , num
return num**3
#returns the cubed value of the parameter
print(cube_value(5))
#prints the cal’ed function is an argument of 5
The listed names during function definition are called the Parameters The actual values passed at the time the function is called refers to the argument.Hence. num is a parameter ; while, 5 is an argument.
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Beyond personal self-directed learning, engaging the management team of the technology group is a process of strategic learning that can be both developmental for the team and lead to new insights for positioning the function in the future." Discuss this statement, what personal self-directed learning are they talking about? Is this statement true?
Answer:
The statement personal self -directed learning is true because, it is a dynamic learning process that can be both change for the organization and contribute to fresh ideas for potential placement of the company.
Explanation:
Solution
In an organisation the management team plays an important role toward's its growth.
This plays a vital role in meeting up to its long-term targets, forging ahead with passion or determination and making any form of adjustments when necessary.
Management is not just about implementing specified proposals. It calls for the analysis of different critical structure, on spot decision-making. this is about learning and can sometimes lead to newly taught results, sometimes positive other times.
Management refers to being actively and consistently engaged with a group of people who work for them. Successful management entails good team work, support from top to bottom of its hierarchy. It requires leadership over a group of individuals who are expected to execute thoughts and opinions on the organisation.
As a part of the management committee also allows for the team leaders to build individual talent. They learn from their way through the various hiccups they face.
Therefore, aside personal self-directed learning, joining the technology group's management team is a proactive learning process that can be both transformative for the organization and contribute to fresh ideas for potential placement of the company.
Explanation:
This statement is true, as the organizational management team is fundamental to the company's growth and success.
Management does not occur only in the execution of actions proposed by strategic organizational planning, but team management in a way that integrates members and involves them, acts as a form of strategic learning that can help the company to position itself in the market in the future and achieve your organizational goals and objectives.
Effective management must be comprehensive to all organizational resources, including human intellectual capital, which, through effective communication, creating relationships, is capable of transforming the work environment into a motivating place where values and ideas are shared that will help to build a culture focused on the development of skills and competences that are essential for organizational success.
While conducting a vulnerability assessment, you're given a set of documents representing the network's intended security configuration along with current network performance data. Which type of review are you most likely to perform
Answer:
The baseline review
Explanation:
Solution:
The baseline review: this can be defined as the gap analysis or the beginning environmental review (IER). it is an assess study to get information about an organisation's present activities and associated environmental impacts, impacts and legal requirements.
This review issues an overview of the quality and weaknesses of an organisation’s environmental execution and opportunities for improvement.
divide the input array into thirds (rather than halves), recursively sort each third, and finally combine the results using a three-way Merge subroutine. What is the running time of this algorithm as a function of the length n of the input array, ignoring constant factors and lower-order terms
Answer:
The answer is "nlogn".
Explanation:
The time complexity can only shift to 3 with the last instance. For the 2nd case, they need one parallel. However, 2 parallels are needed to sort with splitting into 3-way frames. It decreases the number of passes even after breaking the collection in 3 by increasing contrast. So, the time complexity remains the same but the log is divided into 3 bits. The complexity of time is: [tex]T(n)=3T(\frac{n}{3})+ O(n) = O(nlogn)_3.[/tex]Write VHDL code for a RAM that has 16 locations each 32 bits wide. There will be a chipselect (CS) input that activates the chip. Another input to the circuit is an R/W which determines if the operation is a read or a write to the chip. The address input to the chip is a vector. The input and output would also be a vector(s) that should send and receive the data, depending on the address input to the chip.
Answer:
Hello your question lacks some parts attached is the complete question and the solution is written in the explanation
Explanation:
VHDL CODE::::::
VHDL Code for RAM Design:
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL;
use IEEE.STD_LOGIC_UNSIGNED.ALL;
entity RAM_32Bits is
port (
Clk: in std_logic;
CS: in std_logic;
RW: in std_logic;
Address: in std_logic_vector(3 downto 0);
Data_In: in std_logic_vector(31downto 0);
Data_Out: out std_logic_vector(31downto 0);
)
end entity RAM_32Bits;
architecture RAM_32 of RAM_32Bits is
// Declare Memory Array
type RAM is array (3 downto 0) of std_logic_vector(31 downto 0);
signal mem_array: ram;
// Signal Declaration
signal read_addr: std_logic_vector (3 downto 0);
begin
process (Clk)
begin
if (Clk’event and Clk=’1’) then
if (CS=’1’ and RW=’1’) then
ram(conv_integer(Address)) <= Data_In;
endif;
if (CS=’1’ and RW=’0’) then
read_addr <= Address;
endif;
else
read_addr <= read_addr;
endif;
endprocess
Data_Out <= ram[conv_integer(read_addr)];
end architecture RAM_32;
Assign numMatches with the number of elements in userValues that equal matchValue. Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 2, 1, 2} and matchValue is 2 , then numMatches should be 3.
Your code will be tested with the following values:
* matchValue: 2, userValues: {2, 2, 1, 2} (as in the example program above)
* matchValue: 0, userValues: {0, 0, 0, 0}
* matchValue: 50, userValues: {10, 20, 30, 40}
Answer:
public class ProblemSolution{
public static void main(String[] args) {
int [] userValues = {2, 2, 1, 2};
int NUM_VALS = userValues.length;
int matchValue = 2;
int numMatches = 0;
for (int i = 0; i<NUM_VALS; i++){
if(userValues[i]==matchValue){
numMatches++;
}
}
System.out.println("Number of Matches is: "+numMatches);//prints 3
}
}
Explanation:
Using Java programming language
An array is used to hold userValues
Integer variables are declared to hold matchValue and numMatches
A for loop is used to iterate through the array elements and increase numMatches whenever the element is equal to matchValue
finally print out the numMatches
matchValue: 2, userValues: {2, 2, 1, 2} Prints 3
matchValue: 0, userValues: {0, 0, 0, 0}: Prints 4
matchValue: 50, userValues: {10, 20, 30, 40} Prints 0
Suppose there is exactly one packet switch between a sending user and a receiving user. The transmission rates between the sending user and the switch and between the switch and the receiving user are R1 and R2, respectively. Assuming that the switch uses store-and-forward packet switching, what is the total end-to-end delay to send a packet of length L?
Answer:
[tex]L(\frac{1}{R_1}+\frac{1}{R_2} )[/tex]
Explanation:
[tex]R_1[/tex] is the transmission rates between the sending user and the switch while [tex]R_2[/tex] is the transmission rates between the switch and the receiving user and the length of the packet is L
Considering no propagation delay the time taken to transmit the packet from the sending user to the switch is given as:
[tex]t_1=\frac{L}{R_1}[/tex]
the time taken to transmit the packet from the switch to the receiving user is given as:
[tex]t_2=\frac{L}{R_2}[/tex]
therefore the total end-to-end delay to send a packet is:
[tex]t=t_1+t_2=\frac{L}{R_1}+\frac{L}{R_2} =L(\frac{1}{R_1}+\frac{1}{R_2} )[/tex]
Type dig www.example A in order to get the IP address of www.example. What’s the TTL of the A record returned in the response? Wait a while, and repeat the query. Why has the TTL changed?
Answer:
Your computer now has the IP address of that website cached, and no longer has to lookup the IP address of that domain name. The TTL of the first query is bigger than the TTL of the second query as less time was taken to execute the request.
Explanation:
On the first request to the website, the computer needs to contact other machines to find the record of the IP address.
On the second request, the computer already has the IP address and can use that to connect.
Consider the following algorithm. for i ∈ {1,2,3,4,5,6} do ???? beep for j ∈ {1,2,3,4} do beep for k ∈ {1,2,3} do ???? for l ∈ {1,2,3,4,5} do beep for m ∈ {1,2,3,4} do ???? ???? beep How many times does a beep statement get executed?
Answer:
This is the complete question:
for i ∈ {1,2,3,4,5,6} do beep
for j ∈ {1,2,3,4} do beep
for k ∈ {1,2,3} do
for l ∈ {1,2,3,4,5} do beep
for m ∈ {1,2,3,4} do beep
Explanation:
I will explain the algorithm line by line.
for i ∈ {1,2,3,4,5,6} do beep
This statement has a for loop and i variable that can take the values from 1 to 6. As there are 6 possible values for i so the beep statement gets executed 6 times in this for loop.
for j ∈ {1,2,3,4} do beep
This statement has a for loop and j variable that can take the values from 1 to 4. As there are 4 possible values for j so the beep statement gets executed 4 times in this for loop.
for k ∈ {1,2,3} do
for l ∈ {1,2,3,4,5} do beep
There are two statements here. The above statement has a for loop and k variable that can take the values from 1 to 3. As there are 3 possible values for k so the beep statement gets executed 3 times in this for loop. The below statement has a for loop and l variable that can take the values from 1 to 5. As there are 5 possible values for l so the beep statement gets executed 5 times in this for loop. However these statement work like an inner and outer loop where the outer loop is k and inner one is l which means 1 gets executed for each combination of values of k and l. As there are three values for k and 5 possible values for l so the combinations of values of k and l is 15 because 3 * 5 = 15. Hence the beep statement gets executed 15 times.
for m ∈ {1,2,3,4} do beep
This statement has a for loop and m variable that can take the values from 1 to 4. As there are 4 possible values for m so the beep statement gets executed 4 times in this for loop.
Now lets take the sum of all the above computed beeps.
for i = 6 beeps
for j = 4 beeps
for k and l possible combinations = 15 beeps
for m = 4 beeps
total beeps = 6 + 4 + 15 + 4 = 29 beeps
Write a program that displays, 10 numbers per line, all the numbers from 100 to 200 that are divisible by 5 or 6, but not both. The numbers are separated by exactly one space
My Code:
count = 0
for i in range (100, 201):
if (i %6==0 and i %5!=0) or (i%5==0 and i%6!=0):
print(str(i), "")
count = count + 1
if count == 10:
string = str(i) + str("")
print(string)
count = 0
Any way to put the numbers 10 per line?
Answer & Explanation:
To print 10 on a line and each number separated by space; you make the following modifications.
print(str(i)+" ",end=' ')
str(i)-> represents the actual number to be printed
" "-> puts a space after the number is printed
end = ' ' -> allows printing to continue on the same line
if(count == 10):
print(' ')
The above line checks if count variable is 10;
If yes, a blank is printed which allows printing to start on a new line;
The modified code is as follows (Also, see attachment for proper indentation)
count = 0
for i in range(100,201):
if(i%6 == 0 and i%5!=0) or (i%5 ==0 and i%6!=0):
print(str(i)+" ",end=' ')
count = count + 1
if(count == 10):
print(' ')
count = 0
Given positive integer numInsects, write a while loop that prints that number doubled without reaching 100. Follow each number with a space. After the loop, print a newline. Ex: If numInsects = 8, print:
8 16 32 64
#include
using namespace std;
int main() {
int numInsects = 0;
numInsects = 8; // Must be >= 1
while (numInsects < 100) {
numInsects = numInsects * 2;
cout << numInsects << " ";
}
cout << endl;
return 0;
}
So my question is what am I doing wrong?
Answer:
The cout<<numInsects<<""; statement should be placed before numInsects = numInsects * 2; in the while loop.
Explanation:
Your program gives the following output:
16 32 64 128
However it should give the following output:
8 16 32 64
Lets see while loop to check what you did wrong in your program:
The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100.
So the body of while loop executes. numInsects = numInsects * 2; statement in the body multiplies the value of numInsects i.e 8 with 2 and then cout << numInsects << " "; prints the value of numInsects AFTER the multiplication with 2 is performed. So 8 is not printed in output but instead 16 (the result of 8*2=16) is printed as the result of first iteration.
So lets change the while loop as follows:
while (numInsects < 100) {
cout << numInsects << " ";
numInsects = numInsects * 2;
Now lets see how it works.
The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100
So the body of while loop executes. cout << numInsects << " "; first prints the value of numInsects i.e. 8. Next numInsects = numInsects * 2; multiplies the value of numInsects i.e 8 with 2. So first 8 is printed on the output screen. Then the multiplication i.e. 8*2=16 is performed as the result of first iteration. So now value of numInsects becomes 16.
Next the while loop condition numInsects < 100 is again checked. It is true again as 16<100. Now cout << numInsects << " "; is executed which prints 16. After this, the multiplication is again performed and new value of numInsects becomes 32 at second iteration. This is how while loops continues to execute.
So this while loop stops when the value of numInsects exceeds 100.
A contracting company recently completed its period of performance on a government contract and would like to destroy all information associated with contract performance. Which of the following is the best NEXT step for the company to take?
A. Consult data disposition policies in the contract
B. Use a pulper or pulverizer for data destruction
C. Retain the data for a period of no more than one year.
D. Burn hard copies containing PII or PHI
Answer:
A. Consult data disposition policies in the contract.
Explanation:
The disposition of data should be carefully handled. The data associated with government project should be handled with care as it may include sensitive information. To destroy the data the company should refer the agreement and see if there is any notes included regarding the data disposition policy. The course of action to destroy the data should be according to the agreement.
Denial of service (DoS) attacks can cripple an organization that relies heavily on its web application servers, such as online retailers. What are some of the most widely publicized DoS attacks that have occurred recently? Who was the target? How many DoS attacks occur on a regular basis? What are some ways in which DoS attacks can be prevented? Write a one-page paper on your research.
Answer:
The overview of the given question is described in the explanation segment below.
Explanation:
The number of casualties has occurred in recent years. The following are indeed the assaults:
Arbitrary Remote Code execution attacks:
It's also a very hazardous assault. Unsanitary working on implementing that used operating system including user actions could enable an attacker to execute arbitrary functions mostly on system files.
Sites become targeted with such a DOS assault that will cause them inaccessible whether they close the account to an offender who threatens them.
Prevention: We could protect this by preventing the call from additional assessment by the user. We will disinfect input validation if we transfer values to devise calls. The input data is permitted to transfer on requests, it should have been strictly regulated although restricted to a predetermined system of principles.
Injection attack:
The object of the Injection Attack seems to be to delete vital information from the server. Throughout the list, we have such a user, a code, as well as a lot of several other essential stuff. Assailants are taking vital data and doing the wrong stuff. This can have an impact on the web site or software application interface the SQL.
Prevention: Parameterized functions require developers must specify all of the SQL code, and afterward move the question in-parameter, allowing the server to distinguish between some of the code as well as the information. By decreasing the privilege allocated to each database. White list data validation has been used to prevent abnormal information.
Zero-day attack:
It corresponds to something like a vulnerability flaw undisclosed to the user. The security vulnerability becomes infected with malware. The attackers have access to inappropriate details.
Prevention: The organizations are releasing the patch fixes the found holes. The updated plugin is also a preventive tool.
Buffer overflow attack:
This is indeed a major security threat to the accuracy of the data. This overflow happens since more information becomes set to either a specified size than even the buffer could accommodate. Adjoining program memory is compromised. During that time, the attacker was indeed running obfuscated code. Two key forms of such attack are provided below:
Heap-basedStack-basedPrevention: Standard library features, including such strcpy, should indeed be avoided. Standard testing should be performed to identify as well as resolve overflow.