A mixture of metal and at least one other element
Hope this helps : )
Calculate the work done in lifting 200 kg of water through a vertical height of 6 metres
(g = 10 m/s)
(A) 5000 J
(B) 12000 J
(C) 25000 J
(D) 15000 J
Answer:
[tex]\bf\pink{(C)\:12000\:J}[/tex]Explanation:
Given :-[tex]\sf\red{Mass = 200 \ kg}[/tex][tex]\sf\orange{Gravity = 10 \ m/s}[/tex][tex]\sf\green{Height = 6 \ m}[/tex]Need to find :-[tex]\sf\blue{Work \ done}[/tex]Formula required :-[tex]\sf\purple{Work \ done = Mass \times Gravity \times Height}[/tex]Solution :-[tex]\to\:\:\sf\red{Work \ done = Mass \times Gravity \times Height}[/tex]
[tex]\to\:\:\sf\orange{Work \ done = 200 \times 10 \times 6}[/tex]
[tex]\to\:\:\sf\green{Work \ done = 2000 \times 6}[/tex]
[tex]\to \:\ \sf\blue{ Work \ done = {\bf{\blue{1200\:J}}}}[/tex]
Hence, [tex]\bf\green{(B)}[/tex] is the correct option.