Answer:
The value is [tex]P_2 = 40.54 \ psla[/tex]
Explanation:
From the question we are told that
The initial pressure is [tex]P_1 = 14\ psla[/tex]
The initial temperature is [tex]T_1 = 50 \ F = (50 - 32) * [\frac{5}{9} ] + 273 = 283 \ K[/tex]
The final temperature is [tex]T_2 = 320 \ F = (320 - 32) * [\frac{5}{9} ] + 273 =433 \ K[/tex]
Generally the equation for adiabatic process is mathematically represented as
[tex]PT^{\frac{\gamma}{1- \gamma} } = Constant[/tex]
=> [tex]P_1T_1^{\frac{\gamma}{1- \gamma} } = P_2T_2^{\frac{\gamma}{1- \gamma} }[/tex]
Generally for a monoatomic gas [tex]\gamma = \frac{5}{3}[/tex]
So
[tex]14 * 283^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} } =P_2 * 433^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} }[/tex]
=> [tex]14 * 283^{-2.5} =P_2 * 433^{-2.5}[/tex]
=> [tex]P_2 = 40.54 \ psla[/tex]
A circuit consists of a 12 V battery connected across a single resistor. If the current in the circuit is
3 A, calculate the size of the resistor
Answer:
4 Ohms
Explanation:
Apply the formula:
Voltage = I (current) . Resistance
You can change it the way you want to use for your purpose.
In this case...
R = V/I
R = 12/3
R = 4 Ohms (Ohm is the unit of measurement of eletrical resistance)
You (50 kg) are standing on a skateboard when your friend throws a 5 kg ball at 10 m/s towards your head. You catch the ball to save your face. Describe your motion after you catch the ball, use numbers.
Answer:
v₁ = 1 [m/s].
Explanation:
This problem can be solved by using the principle of conservation of linear momentum. Where momentum is conserved before and after catching the snowball.
[tex]P=m*v[/tex]
where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
[tex]P=m*v\\P=5*10\\P=50[m/s][/tex]
As the momentum is conserved, it will be the same as that received by the person who catches the snowball.
[tex]50= 50*v_{1}\\v_{1}=1[m/s][/tex]
That is, the person who catches the snowball moves backwards with a speed of 1 [m/s].
Calculate the work done in lifting 200 kg of water through a vertical height of 6 metres
(g = 10 m/s)
(A) 5000 J
(B) 12000 J
(C) 25000 J
(D) 15000 J
Answer:
[tex]\bf\pink{(C)\:12000\:J}[/tex]Explanation:
Given :-[tex]\sf\red{Mass = 200 \ kg}[/tex][tex]\sf\orange{Gravity = 10 \ m/s}[/tex][tex]\sf\green{Height = 6 \ m}[/tex]Need to find :-[tex]\sf\blue{Work \ done}[/tex]Formula required :-[tex]\sf\purple{Work \ done = Mass \times Gravity \times Height}[/tex]Solution :-[tex]\to\:\:\sf\red{Work \ done = Mass \times Gravity \times Height}[/tex]
[tex]\to\:\:\sf\orange{Work \ done = 200 \times 10 \times 6}[/tex]
[tex]\to\:\:\sf\green{Work \ done = 2000 \times 6}[/tex]
[tex]\to \:\ \sf\blue{ Work \ done = {\bf{\blue{1200\:J}}}}[/tex]
Hence, [tex]\bf\green{(B)}[/tex] is the correct option.