Three students were lined up in a row. Damon was to the left of Val but not necessarily next to them. The student wearing the blue shirt was to the right of the student wearing the white shirt. The student wearing the black shirt was to the left of Harold. Harold was to the left of Val.



What was the order of the students from left to right? (Names should be separated by commas - e.g. Jane, Tri, Dave)

Answer:

def random_marks(apostrophe, quotation, apostrophe_quotation):

   return "'"*apostrophe + "\""*quotation + "'\""*apostrophe_quotation

print(random_marks(3, 2, 3))

Explanation:

Create a function called random_marks that takes apostrophe, quotation, and apostrophe_quotation as parameters. Inside the function, return apostrophe sign times apostrophe plus quotation mark times quotation plus apostrophe sign quotation mark times apostrophe_quotation.

Note that plus sign (+) is used to concatenate strings. Also, if you multiply a string with a number, you get that number of strings ("#"*3 gives ###).

Then, call the function with given parameters and print

Answer:

Validity

Explanation:

Personnel Selection encompasses all the processes and methods involved in the selection of workers. The purpose of personnel selection is to determine the best candidate for the job and in so doing the recruiting organization must play by the rules laid down by the government for recruitment. Validity refers to the relationship between interviews and excellent performance at the job.

Validity implies that the method of selection must meet up to a standard criterion. This standard criterion is the expected job performance required of the potential employee. Different interview types (such as job-related, situational, and psychological) have different validity levels.  

Answer:

She removed the complex blue background and added artistic effects.

Explanation:

This is the best answer because both aspects are correct. If Megan were to "Crop" the backgrounds the shape would have changed and she would not have been able to get the whole background without cropping some of the flowers out. Therefore it is not A or C. The pictured change is most definitely artistic effects. So D is the best option.

Answer:

She removed the complex blue background and added artistic effects.

Explanation:

on edg

Answer:

I have updated answer in google

Explanation:

please chek it. I hope it will nice

Answer: C. both single threaded and multithreaded

Explanation:

A process can either be single threaded and multithreated. Single threaded processes is when the execution of instructions are in a single sequence i.e the sequence is one command at a time while for multithreaded processes, there are. execution of several multiple parts of a program that occurs at the same time.

A single threaded process only runs on one CPU, whereas for the execution of a multi-threaded, it may be divided amongst the available processors.

Answer:

passwords = ["123456", "123456789", "qwerty", "password", "111111", "12345678", "abc123", "1234567", "password1", "12345"]

used_passwords = []

while True:

   password = input("Choose a password: ")

   if password in passwords:

       print("You must not choose a common password!")

       continue

   elif password in used_passwords:

       print("You used this password before. Choose a new one.")

       continue

   else:

       used_passwords.append(password)

       break

Explanation:

*The code is in Python.

Initialize the passwords array with 10 most common user-selected passwords

Initialize the used_passwords array as empty

Create an infinite while loop. Inside the loop, ask the user to choose a password. Check if entered password is in the passwords or not. If it is, print a warning and ask the user to choose again using continue statement. If the entered password is in the used_passwords, print a warning message and ask the user to choose again using continue statement. If the previous conditions are not satisfied, it means the password is valid. Add the password to the used_passwords array and stop the loop using break statement.

Answer:

Under the Print Tab of the Backstage view of his presentation, Kiaan can print 6 slides on each piece of paper by selecting the "Full Page Slides" which is under settings.

Once that is done, he will be presented with an array of choices.

He is to select whether to print 6 pages/sheet vertically or horizontally under the "Handouts" section.

Thereafter, he can proceed to click on "Print".

Cheers!

Answer: YES

Explanation:

int year=2019;

int yearNext=2020;

 int &ref=year;

&ref=yearNext; {This line leads to error as references cannot be reassigned}

(//compilation error: lvalue required as left operand of assignment

) lvalue(&ref) is not something which can be assigned.

To get this better, here are the difference between pointers and reference variables

Pointers

Pointers can be incremented

Array can be formed with pointers

Pointers can be reassigned

Pointer can be declared as void  

Reference variable

References cannot be incremented

Array cannot be formed with references

References cannot be reassigned as references shares the address of the variable its assigned

References can never be void

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

The code for function calling is coded below.

To assign the maximum sum of `(numA, numB)` plus the maximum of `(numY, numZ)` to the variable `maxSum` using just one statement, you can call the `FindMax()` function twice in an expression.

Here's the code:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

This code calls the `FindMax()` function twice, once with the parameters `(numA, numB)` and again with the parameters `(numY, numZ)`.

It calculates the maximum of each pair of numbers using the `FindMax()` function and then adds the two maximum values together. The result is assigned to the `maxSum` variable.

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Answer: a.

S = {aa ab ba bb}

This clearly shows that that every string that belongs to this language has an even length including 0 length.

This language can be depicted as following

S* = {∧ aa ab ba bb aaaa aaab aaba aabb bbaa . . .}

Regular Expression for this can be

RE = (aa+ab+ba+bb)*

So S* contains all the strings of a's and b's that have even length. This means all strings of even length.

Explanation:

b.

S* contains all possible strings of a's and b's that have length divisible by 3

This means some of the possible strings examples are:

aaa, bbb, aaabbb, aaaaaa, bbbbbb and so on.

Length divisible by 3 means the length of string such as aaa is 3 which is divisible by 3, also  aaaaaa has length 6 which is divisible by 3

This should be something like this:

(( a + b ) ^3)*

For example a^3 = aaa which is divisible by 3

Regular expression can be:

RE of S* = (aaa + bbb)*

For example string bbbbbbbbb has length 9 which is divisible by 3

So the language is

S* = { ∧ aaa bbb aaabbb aaaaaa aaaaaabbb...}

Explanation:

Answer:

1 (true)

Explanation:

10 == 10 is valid=> 10 >= 10 is valid => 10 >=(5*2) is valid

10 == 10 is valid=> 10 <= 10 is valid => 10 <=(5*2) is valid

=>  ((10 >= 5*2) and (10 <= 5*2)) is valid => Return 1 or True

Answer:

Internet backbone

Explanation:

The internet backbone is made up of multiple networks from multiple users. It is the central data route between interconnected computer networks and core routers of the Internet on the large scale. This backbone does not have a unique central control or policies, and is hosted by big government, research and academic institutes, commercial organisations etc. Although it is governed by the principle of settlement-free peering, in which providers privately negotiate interconnection agreements, moves have been made to ensure that no particular internet backbone provider grows too large as to dominate the backbone market.

Answer:

The classification including its given topic has always been outlined in section through below justifications.

Explanation:

Explanation:

Hardware virtualization refers to the creation of virtual (as opposed to concrete) versions of computers and operating systems. ... Hardware virtualization has many advantages because controlling virtual machines is much easier than controlling a physical server.

The name of the provision of services based around hardware visualization is called cloud computing

The cloud hypervisor is the software that is made use of during hardware visualization. The hypervisor does the function of managing hardware resources involving the customer and the service provider.

The work of hypervisor is that it manages the physical hardware resource which is shared between the customer and the provider.

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Answer:

environmental

Explanation:

Answer:

The tokens are:

January

space

1

,

space

2008

Explanation:

StringTokenizer class is basically used to break a string into tokens. The string consists of numbers, letters, quotation marks commas etc,

For example if the string is "My name is ABC" then StringTokenizer will break this string to following tokens:

My

name

is

ABC

So in the above example, the string is "January 1, 2008". It contains January with a space, then 1, then a comma, then 2008

The last comma and true in the statement do not belong to the string. They are the parameters of the StringTokenizer constructor i.e.

StringTokenizer(String str, String delim, boolean flag)

So according to the above constructor str= "January 1, 2008"

String delim is ,

boolean flag = true

So  the StringTokenizer strToken = new StringTokenizer("January 1, 2008", ", ", true); statement has:

a string January 1, 2008

a delim comma with a space (, ) which is used to tokenize  the string "January 1, 2008".

boolean flag set to true which means the delim i.e. (, ) is also considered to be a token in the string. This means the comma and space are considered to be tokens in the given string January 1, 2008.

Hence the output is January space 1 comma space 2008.

Check the attached image to see the output of the following statement.

Following are the java program to separing the string value:

Program Explanation:

Program:

import java.util.*;//import package

public class Main //defining a class main

{

public static void main (String [] ars) //main method

{

Scanner inSS = null;//using Scanner  

String userInput="Jan 12 1992";//defining a String variable userInput that holds a string value

inSS = new Scanner(userInput);//passing userInput value into Scanner class

String userMonth = "";//defining a String variable

int userDate = 0,userYear = 0;//defining an integer variable

inSS.useDelimiter(" ");//calling method useDelimiter

userMonth=inSS.next();//holding value in to the variable

userDate=inSS.nextInt();//holding value in to the variable

userYear=inSS.nextInt();//holding value in to the variable

System.out.println("Month: " + userMonth);//print value with message

System.out.println("Date: " + userDate);//print value with message

System.out.println("Year: " + userYear);//print value with message

return;

}

}

Output:

Please find the attachment file.

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Answer:

In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets. It might go a week or longer between charges if you only use the tablet once or twice each day.

Many people find that charging merely 80% is ineffective. Your phone won't function if you fully charge it and then use it in a single day. The 40-80% rule applies if, like me, your daily usage is limited to 25–50%.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets.                          

Therefore, In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

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Answer:

Following are the correct code to this question:

short_names=['Gus','Bob','Zoe']#defining a list short_names that holds string value

print (short_names[0])#print list first element value

print (short_names[1])#print list second element value

print (short_names[2])#print list third element value

Output:

Gus

Bob

Zoe

Explanation:

Answer:

True

Explanation:

Solution

ZigBee uses unlicensed frequency bands but operate at slower speed or data rates.

ZigBee: This communication is particular designed for control and sensor networks on IEEE 802.15.4 requirement for wireless personal area networks (WPANs), and it is a outcome from Zigbee alliance.

This communication level defines physical and  (MAC) which is refereed to as the Media Access Control layers to manage many devices at low-data rates.

Answer:

Car insurance

Explanation:

they are machines with ai

Answer:

Here is the JavaScript program:

function MatricesMul(matrix1, matrix2) {

   var product = [];

   for (var i = 0; i < matrix1.length; i++) {

       product[i] = [];

       for (var j = 0; j < matrix2[0].length; j++) {

           var total = 0;

           for (var k = 0; k < matrix1[0].length; k++) {

               total += matrix1[i][k] * matrix2[k][j];  }

           product[i][j] = total;        }    }

   return product;}

var matrix1 = [[1,2,3],[4,5,6],[7,8,9]]

var matrix2 = [[3,2,1],[6,5,4],[1,2,3]]

var output = MatricesMul(matrix1, matrix2)

document.write(output);

Explanation:

The function MatricesMul(matrix1, matrix2) takes two matrices (matrix1 and matrix2) as parameters.

var product = [];  product works as an array to contain the result of the multiplication of the two matrices matrix1 and matrix2.

for (var i = 0; i < matrix1.length; i++) this is a loop which iterates through the matrix1 and it continues to execute until the loop variable i exceeds the length of the matrix1. This is basically the loop which iterates through the rows of matrix1.

for (var j = 0; j < matrix2[0].length; j++) this is a loop which iterates through matrix2 and it continues to execute untill the loop variable j exceeds the length of the element of matrix2 at 0-th index (first element). This is basically the loop which iterates through the colulmns of matrix2.

var total = 0;  variable total is initialized to 0 and this variable is used to compute the sum.

for (var k = 0; k < matrix1[0].length; k++) this loop is used for the multiplication of the two matrices matrix1 and matrix2.

total += matrix1[i][k] * matrix2[k][j];  this statement first multiplies each element of matrix1 row to each element of the matrix2 column, takes the sum of pairwise products.

return product; returns the result of the multiplication of matrix1 and matrix2.

For example let matrix1 = [[1,2,3],[4,5,6],[7,8,9]]  and matrix2 = [[3,2,1],[6,5,4],[1,2,3]] .

The first for loop moves through each row of matrix1. The first element of first row of matrix1 is 1, the second element is 2 and third is 3. The second loop iterates through each column of matrix2. Lets take the first column matrix2. The first element of first column of matrix2 i.e. 3, the second element is 6 and the third is 1. Third loop performs the pairwise multiplication of row of matrix1 to column of matrix2 and takes the sum of pairwise product. This means 1 is multiplied to 3, 2 is multiplied with 6 and 3 is multiplied to 1. This will take the form: 1*3 + 2*6 + 3*1 = 3 + 12 + 3 Now their sum is taken and the result is stored in total variable. So the sum of 3 + 12 + 3 is 18. This process will continue until all the rows elements of matrix1 and elements in all columns of matrix2 are multiplied and the sum of each pairwise product is taken.

var matrix1 = [[1,2,3],[4,5,6],[7,8,9]]

var matrix2 = [[3,2,1],[6,5,4],[1,2,3]]

The above two statements two (3,3) square matrices are given values.

var output = MatricesMul() this calls the MatricesMul method and passes the two matrices (matrix1, matrix2) to the function and stores the result of this multiplication to output variable.

document.write(output); displays the result of the multiplication of two square matrices .

Answer:

one disk

Explanation:

RAID 5:is an  independent disks configuration of redundant array that utilizes disk striping in addition to parity. Data and parity bits are striped uniformly across the entire the disks configuration, so that no any single disk can create a bottleneck.  

"Today one disk has failed in this RAID. How many disks do you replace"

Since RAID 5 guard against data through implementation of stripping of both data and parity bits, the failed disk can be replaced to restore the company's RAID 5 array fully back into service.

Answer:

Secure firewall , Access Control Lists (ACLs) , and Bastion hosts

Explanation:

In this scenario, the best options to be able to accomplish this would be a Secure firewall , Access Control Lists (ACLs) , and Bastion hosts. A secure firewall and an access control list will prevent specific harmful files and computers from entering a network unless it has the proper clearance. A bastion host on the other hand is a special-purpose computer on a network specifically designed and configured to withstand attacks, acting as a secondary defense mechanism.

It is possible to restrict connections by using a secure firewall, bastion hosts, and access control lists (ACLs).

In conclusion, it is possible to restrict connections by using a secure firewall, bastion hosts, and access control lists (ACLs).

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Answer:

I am writing a JAVA program.

import java.util.Scanner;  //class to take input from user

import java.io.File;  //class for working with files

import java.io.FileNotFoundException;  // indicates that file could not be opened

import java.io.PrintWriter;  //used to print or formatted data

public class BabyNames{  //class name

public static void main(String[] args) throws FileNotFoundException{  //main function body throws FileNotFoundException to indicate if the file cannot be opened

File input_baby = new File("babynames.txt");  //creates object iFile and passes babynames.txt file name to it

File boy_output = new File("boynames.txt");  //creates object of File and passes boynames.txt name to it This file is to store boys names from babynames.txt

File girl_output = new File("girlnames.txt");  //creates object of File & passes  girlnames.txt name to it. To store girls names from babynames

String[] boy_names = new String[100];  //create an array to hold boys names

String[] girl_names = new String[100];  //creates an array to hold girls names

PrintWriter boyNames = new PrintWriter(boy_output);  //create object of PrintWriter for writing the separated boys names to boynames.txt file

PrintWriter girlNames = new PrintWriter(girl_output);  //create object of PrintWriter for writing the separated  girls names to girlnames.txt file

Scanner input = new Scanner(input_baby);  //creates Scanner class object to scan babyname.txt

int i = 0;  

while (input.hasNextLine()){  //checks if the babynames files has next line until the last line of the file

String str = input.nextLine();  //scans the current line

String[] strings = str.split(" ");  //split the line into array of strings/words based on the space " " delimiter

boy_names[i] = strings[1];  //array to store boys names and strings[1] locates the boys names in input file

girl_names[i++] = strings[3];  }  //array to store girls names strings[3] locates the girls names

for(i = 0; i < 100; i++){  //write the separated boys names to boynames.txt file and separated girls names in girlnames.txt file

           boyNames.write(boy_names[i]);

           boyNames.println();

           girlNames.write(girl_names[i]);

           girlNames.println();}  

input.close();  

boyNames.close();  

girlNames.close(); } }

Explanation:

The program has an input file babynames.txt and two text files to store separated boys and girls names. The while loop reads every line of the babynames.txt at each iteration and and splits each line into array of words strings based on the space delimiter. A line from babynames.txt file: 1 Michael 65,275 Jessica 46,470

boy_names[i] = strings[1] This line in loop basically locates boys names from each line of the babynames file. For the line given above. At first iteration of while loop when i=0 then boy_names[i] = strings[1] statement sets 1st index of strings array to the 0-th index of boy_names. Notice that 1st index of strings array is the second word of the above line i.e. Michael. So Michael is stored as 1st element of array boys_name.

girl_names[i++] = strings[3]; locates girls names in the same way as boy_names[i] = strings[1]

strings[3] means 3rd index of strings array Notice that 3rd index of strings array is Jessica.

There are total of 100 boys and 100 girls names in babynames.txt file so for(i = 0; i < 100; i++) this for loop prints these 100 separated boys and girls names in their respective files.

However this program only separates the boys and girls names and not their data such as in this line of input file Michael has data 65,275 and Jessica has 46,470. If you want to add this data into boynames.txt and girlnames.txt files then alter the above code. The altered code is attached.

create an array to store data of boys.

String[] boy_data = new String[100];

Create an array to store data of girls.

String[] girl_data = new String[100];

Now considering the same example 1 Michael 65,275 Jessica 46,470

boy_data[i] = strings[0] + " " + strings[1] + " " + strings[2];  the boy_data array stores data of boys i.e. the elements of 0th 1st and 2nd index. Notice that element at 0th index is the first element element i.e. 1, element at 1st index is Michael and element at 2nd index is 65275. So this is the data of Michael.

girl_data[i++] = strings[0] + " " + strings[3] + " " + strings[4];  }  the girl_data array stores data of girls i.e. the elements of 0-th 3rd and 4th index. Notice that element at 0-th index is the first element element i.e. 1, element at 3rd index is Jessica and element at 4th index is 46,470. So this is the data of Jessica.

Now the outer loop iterates is used to print the separated data of boys and girls. 1st inner loop has an if statement  if(boy_data[j].split(" ")[1].compareTo(boy_names[i]) == 0) which splits the boy_data and compareTo() method compares the first element of boy_data (Michael) to first element of the boy_names array (Michael). If both are same then it write the data i.e.  to boynames.txt 1 Michael 65,275. Same works for the girls too. The program along with its output is attached.

Answer:

Brainly is not meant to give paragraph answers to large questions.

In a computer (desktop)

There are 8-9 main components to a PC

Motherboard

CPU

GPU (for gamers)

RAM

SSD

HDD

PSU

Cooling fans (for AMD processors stock fans are included)

Case (some fans included)

I personally build my computers (desktops) as its cheaper and I won't have to pay a build fee.

Answer:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Explanation:

The method to generate the binary number from a decimal is :

Keep on dividing the number by 2 and keep on tracking the remainder

And the quotient is again divided and remainder is tracked so that the number is completely divided.

And then write the binary digits from bottom to top.

Please have a look at the method in below examples:

A) 35

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 35 & 1 \\ 2 & 17 & 1 \\ 2 & 8 & 0 \\ 2 & 4 & 0 \\ 2 & 2 & 0 \\ 2 & 1 & 1\end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary number is 100011

B) 3

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 3 & 1 \\ 2 & 1 & 1 \\ \end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 11.

C) 27

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 27 & 1 \\ 2 & 13 & 1 \\ 2 & 6 & 0 \\ 2 & 3 & 1 \\ 2 & 1 & 1 \end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 11011.

D) 16

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 16 & 0 \\ 2 & 8 & 0 \\ 2 & 4 & 0 \\ 2 & 2 & 0 \\ 2 & 1 & 1 \\\end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 10000.

Answers are:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Answer:

Following are the code to this question:

#include <stdio.h> //defining header file

#include <string.h>//defining header file

int main()//defining main method

{

char name[50]; //defining character variable

int A=0,E=0,I=0,O=0,U=0,value=0,i,l; //defining integer variables

printf("Enter string value: ");//print message

gets(name);//input value by gets method

l=strlen(name);//defining l variable to store string length

for(i=0; i<50; i++) //defining loop to count vowels value

{

if(name[i] == 'A' || name[i] == 'a') //defining if condition count A value A++;//increment value by 1

else if(name[i] == 'E' || name[i] == 'e')//defining else if condition count E value

E++;//increment value by 1

else if(name[i] == 'I' || name[i] == 'i') //defining else if condition count I value

I++;//increment value by 1

else if(name[i] == 'O' || name[i]== 'o') //defining else if condition count O value

O++;//increment value by 1

else if(name[i] == 'U' || name[i] == 'u')//defining else if condition count U value

U++;//increment value by 1

else if(name[i]>= '0' && name[i] <= '9')//defining else if condition count digits value

value++;//increment value by 1 }

printf("A: %d\n",A);//print A value

printf("E: %d\n",E); //print E value

printf("I: %d\n",I);//print I value

printf("O: %d\n",O);//print O value

printf("U: %d\n",U);//print U value

printf("value: %d",value);//print digits value

return 0;

}

Output:

please find the attachment.

Explanation:

Answer:

A. LCD power inverter

B. AC adapter

C. Battery

Answer:

total_coins = nickel_count + dime_count

Explanation:

The statement that performs the operation in the question is total_coins = nickel_count + dime_count

Full Program (Written in Python)

nickel_count = int(input("Nickel Count: "))

dime_count = int(input("Dime Count: "))

total_coins = nickel_count + dime_count

print("Total coins: ",total_coins)

The first two lines prompt user for nickel and dime count respectively

The third line adds the two coins categories together

The last line prints the total count of coins

The statement which gives the sum of nickel and dime is written below :

total_coins = nickel_count + dime_count

The statement required is written using Python 3 :

def total(nickel_count, dime_count) :

total_coins = dime_count + nickel_count

print(total_coins)

total(100, 200)

#the function total takes in two arguments(number of nickels and number of dimes)

#assigns the varibale total_coins to the sum of nickel_count and dime_count

nickel_count = int(input('Enter count of nickel : '))

# User is prompted to enter number of nickels

dime_count = int(input('Enter count of dime : '))

# User is prompted to enter number of dimes

total_coins = nickel_count + dime_count

#assigns the varibale total_coins to the sum of nickel_count and dime_count

print(total_coins)

#outputs the value of total_coins

Learn more : https://brainly.com/question/17615351