Suppose you have 300.0 mL of a 0.450 M sodium hydroxide solution.

How many moles of sodium hydroxide are in the solution?

Answers

Answer 1

Answer:

135 moles

Explanation:

300*0.45

= 135

PLS GIVE BRAINLIEST

Answer 2
Answer:

3/2 moles

Explanation:

We are given:

Molarity of the solution = 0.450 M

Volume of the Solution = 300 mL OR 0.3 L

Solving for the number of moles:

We know that the formula for molarity:

M = nV          (where n is the number of moles and V is the volume in Liters)

replacing the variables

0.450 = n * (0.3)

n = 0.450 / 0.3

n = 3/2 moles

Therefore, we have 3/2 moles of Na(OH) in the give solution


Related Questions

How many milliliters of 6.2 M M HCl H C l solution are needed to obtain 0.18 mol m o l of HCl H C l ?

Answers

Answer:

29 mL HCl

General Formulas and Concepts:

Chem

Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

6.2 M HCl

0.18 mol HCl

x L mol HCl

Step 2: Define conversions

1 L = 1000 mL

Step 3: Find L

6.2 M HCl = 0.18 mol HCl / x L HCl

(x L HCl)(6.2 M HCl) = 0.18 mol HCl

x L HCl = 0.18 mol HCl / 6.2 M HCl

x = 0.029032 L HCl

Step 4: Convert

[tex]0.029032 \ L \ HCl(\frac{1000 \ mL \ HCl}{1 \ L \ HCl} )[/tex] = 29.0323 mL HCl

Step 5: Check

We are given 2 sig figs. Follow sig fig rules.

29.0323 mL HCl ≈ 29 mL HCl

Answer:

29 mL HCl

Explanation:

List any three quantum numbers that describe an electron in an atom and state the relationship between any of the two

Answers

Explanation:

To completely describe an electron in an atom, four quantum numbers are needed: energy (n), angular momentum (ℓ), magnetic moment (mℓ), and spin (ms).

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Which is the best example and explanation that a physical change has occurred?
fireworks exploding, because energy is released as light and heat
gasoline burning, because it forms water vapor and carbon dioxide
O crushing an ice cube, because the chemical structure of the ice cube is changed
dicing potatoes, because the molecules are separated but remain the same substance

Answers

dicing potatoes, because the molecules are separated but remain the same substance

Answer:

For the people wondering, yes, dicing potatoes is the correct answer. Because a new substance has not formed.

A. 1

B. 2

C. 3

D. 4

_______________________________________________________

Answers

I think it’s B. I’m not 100% sure but I believe it is B! Srry if this is late btw.

The nucleus of an atom is made up of which of the following combinations of particles?

Answers

Answer:  Atoms of different elements are found to have different number    of protons, neutrons, and electrons. To distinguish one atom from another or to classify the various atoms, a number which indicates the number of protons in the nucleus of a given atom, is assigned to the atoms of each identified element. This number is known as the atomic number of the element. The atomic numbers for some of the elements which are associated with the study of semiconductors are given in the following table.

Explanation:

Element Symbol Atomic Number

Silicon Si 14

Germanium Ge 32

Arsenic As 33

Antimony Sb 51

Indium In 49

Gallium Ga 31

Boron B 5

Answer:

[tex]\boxed {\boxed {\sf Protons \ and \ neutrons}}[/tex]

Explanation:

The atom is made up of two main parts: the nucleus and the electron cloud.

The nucleus is the center and has two subatomic particles: the protons (positive charge) and the neutrons (no/neutral charge). The nucleus as a whole has a positive charge, since the neutrons don't provide a charge.

The electron cloud surrounds the nucleus and houses the negatively charged electrons in a "cloud" of energy levels.

So, the nucleus of the atom is made up of protons and neutrons.

12oz of water initially at 75oF is mixed with 20oz of water intiially at 140oF. What is the final temperature?

Answers

Answer:

[tex]115.625^{\circ}\text{F}[/tex]

Explanation:

[tex]m_1[/tex] = First mass of water = 12 oz

[tex]m_2[/tex] = Second mass of water = 20 oz

[tex]\Delta T_1[/tex] = Temperature difference of the solution with respect to the first mass of water = [tex](T-75)^{\circ}\text{F}[/tex]

[tex]\Delta T_2[/tex] = Temperature difference of the solution with respect to the second mass of water = [tex](T-75)^{\circ}\text{F}[/tex]

c = Specific heat of water

As heat gain and loss in the system is equal we have

[tex]m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}[/tex]

The final temperature of the solution is [tex]115.625^{\circ}\text{F}[/tex].

Sunday
Monday
What
The
Freak
Saturday

Answers

Answer
Long live Pop smoke
Explanation

Total enthalpy of formation of reactants and products, enthalpy of reaction. Cmon goons you’ll be rewarded handsomely

Answers

Answer:

am going to work it out

Explanation:

i am going to work it out and then tell you the answer ok

the position-time graph shows the motion of four people. label the lines on graph need on the motion description in this table.​

Answers

Line 1: straight horizontal line
Line 2: straight line at a slope
Line 3: exponential growth curve
Line 4: the topmost curve (the one that initially increases but then starts levels out)

Answer:

4,2,3,1

Explanation:

What volume will be occupied by 33.0 grams of CO2 at 500 torr and 27 °C?

Answers

Answer:

V = 27.98 L

Explanation:

Given data:

Mass of CO₂ = 33.0 g

Pressure = 500 torr

Temperature = 27°C

Volume occupied = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 33.0 g/ 44 g/mol

Number of moles = 0.75 mol

Volume of CO₂:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K  

Now we will convert the temperature.

27+273 = 300 K

Pressure = 500 /760 = 0.66 atm

By putting values,

0.66 atm×V = 0.75 mol × 0.0821 atm.L/ mol.K  × 300 K

V = 18.47 atm.L/0.66 atm

V = 27.98 L

The volume that will be occupied by 33.0 grams of CO2 at 500 torr and 27 °C is 28.11L.

IDEAL GAS LAW:

The volume of an ideal gas can be calculated using the ideal gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)V = volume (L)n = number of moles (mol)R = gas law constant (0.0821 Latm/molK)T = temperature (K)

According to this question;

P = 500torr = 0.657atmV = ?n = 33/44 = 0.75molT = 27°C = 27 + 273 = 300K

0.657 × V = 0.75 × 0.0821 × 300

0.657V = 18.4725

V = 18.4725 ÷ 0.657

V = 28.11L

Therefore, the volume that will be occupied by 33.0 grams of CO2 at 500 torr and 27 °C is 28.11L.

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The compound F20 has two lone pairs on the central oxygen atom. What's the structure of an F2O molecule? Is this compound polar or non-polar?
A. Trigonal planar, polar
B. Bent or angular non-polar
C. Bent or angular polar
D. Trigonal planar non-polar​

Answers

Answer:

Bent or Angular, Polar

Explanation:

I just took the test!

Answer:

C. Bent or angular polar

Explanation:

Write a balanced half-reaction for the oxidation of gaseous nitric oxide (NO) to aqueous nitrous acid (HNO2) in acidic aqueous solution.

Answers

Answer:

NO + H₂O → HNO₂ + 1 e- + 1 H⁺

Step-by-step explanation:

NO ⇒ oxidation number of N = +2

HNO₂ ⇒ oxidation number of N= +3

Therefore, NO has to lose 1 electron to be oxidized to HNO₂. We write the half-reaction with 1 electron (1 e-) in the products side.

NO → HNO₂ + 1 e-

Now, we have 0 electrical charges in the reactants side, and a total of -1 electrical charge in the products side. As the reaction is in acidic aqueous solution, we have to add H⁺ ions to balance the charges. We perform the balance by adding 1 H⁺ (positive charge) to neutralize the negative charge in the side of the products:

NO → HNO₂ + 1 e- + 1 H⁺

Now, we perform the mass balance. We have:

N: 1 atom in both sides

O: 1 atom in reactants side and 2 atoms in products side

H: 0 atoms in reactants side, 2 atoms in products side.

Thus, we have to add 1 H₂O molecule to the reactants side to equal the masses:

NO + H₂O → HNO₂ + 1 e- + 1 H⁺

Finally, the oxidation half-reaction is:

NO + H₂O → HNO₂ + 1 e- + 1 H⁺

determine moles of 1.5g of sodium carbonate.

Answers

Answer:

0.014mol

Explanation:

Given parameters:

Mass of Na₂CO₃  = 1.5g

Unknown:

Number of moles  = ?

Solution:

Number of moles of a compound is mathematically expressed as;

  Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

 Molar mass of  Na₂CO₃  = 2(23) + 12 + 3(16) = 106g/mol

 Number of moles = [tex]\frac{1.5}{106}[/tex]   = 0.014mol

How many seconds are in 100 years(factor label conversion)

Answers

Answer:

0.0166

Explanation:

This conversion of 100 seconds to minutes has been calculated by multiplying 100 seconds by 0.0166 and the result is 1.6666 minutes.

I hope this helps,

even a little bit

0. 0166 is how many seconds are in the year

What forces cause mechanical weathering? Choose more than one
answer.

Answers

Answer:

mineral crystal growth

acid rain

carbonic acid

Answer:

Mineral crystal growth, Acid rain, Carbonic acid

Which of the following set of properties is most likely for a liquid with large, attractive intermolecular forces?

Answers

Answer:

is it ok na I hope this answers are ok

Answer:

Answer is: C) high melting point and high boiling point.

Explanation:

HOPE IT HELPS

Your Welcome

Mark me Brianly!!!

write the chemical formula of tetraphosporus osctasulfide

Answers

Answer:

P4S8 .

the chemical formula of Tetraphosporus osctasulfide is p4S8


do seeds need energy to germinate

Answers

Answer:

Seeds need oxygen so that they can produce energy for germination and growth. The embryo gets energy by breaking down its food stores. Like all organisms, this is done through a process known as aerobic respiration. —a series of reactions where energy is released from glucose, using oxygen.

Consider the following reaction:2 HgCl2(aq) + C2O42-(aq) 2 Cl-(aq) + 2 CO2(g) + Hg2Cl2(s)(a) The rate law for this reaction is first order in HgCl2(aq) and second order in C2O42-(aq). What is the rate law for this reaction?Rate = k [HgCl2(aq)] [C2O42-(aq)]Rate = k [HgCl2(aq)]2 [C2O42-(aq)]Rate = k [HgCl2(aq)] [C2O42-(aq)]2Rate = k [HgCl2(aq)]2 [C2O42-(aq)]2Rate = k [HgCl2(aq)] [C2O42-(aq)]3Rate = k [HgCl2(aq)]4 [C2O42-(aq)](b) If the rate constant for this reaction at a certain temperature is 0.0169, what is the reaction rate when [HgCl2(aq)] = 0.158 M and [C2O42-(aq)] = 0.202 M?Rate = M/s.(c) What is the reaction rate when the concentration of HgCl2(aq) is doubled, to 0.316 M while the concentration of C2O42-(aq) is 0.202 M?Rate = M/s

Answers

Answer:

b

Explanation:

Which will require more heat, increasing the temperature of 1 mol of C8H18(l) by a certain amount or increasing the temperature of 1 mol of H2O(l) by the same amount?

Answers

Answer:

Increasing the temperature of 1 mol of C8H18(l) requires more energy

Explanation:

To answer this question, we need to define molar heat capacity that is the amount of heat required to increase in 1K the temperature of 1 mole of substance.

That means the substance with higher molar heat requires more energy to increase its temperature

Molar heat of octane, C8H18 is 255.68J/Kmol

Molar heat of water is 75.38J/Kmol

That means increasing the temperature of 1 mol of C8H18(l) requires more energy

Which statement describes a major drawback of the Bohr model that caused scientists to replace it?
(A) It worked only for helium and larger atoms.
(B) It did not identify the distance between an electron and the nucleus.
(C) It contradicted the Heisenberg uncertainty principle.
(D) It stated that spectral lines of atoms are similar.
on edgen

Answers

Answer:

C.it contradicted the heinsberg uncertainly principle

Answer:

C.it contradicted the heinsberg uncertainly principle

Explanation:

Write the molecular, ionic, and net ionic equations for the reaction of Sr(NO3)2(aq) and Li2SO4(aq).

Answers

Answer:

Molecular: [tex]Sr(NO_3)_2(aq) +Li_2SO_4(aq)\rightarrow SrSO_4(s)+2LiNO_3(aq)[/tex]

Ionic: [tex]Sr^{2+}(aq)+2NO_3^-(aq) +2Li^{2+}(aq)+SO_4(aq)^{2-}\rightarrow SrSO_4(s)+2Li^+(aq)+2NO_3^-(aq)[/tex]Net ionic: [tex]Sr^{2}(aq)+SO_4(aq)^{2-}\rightarrow SrSO_4(s)[/tex]

Explanation:

Hello!

In this case, since the molecular, ionic and net ionic equations show the complete molecules, ions and resulting ions respectively, for the reaction between strontium nitrate and lithium sulfate, we can notice the formation of solid strontium sulfate and lithium nitrate as shown below:

[tex]Sr(NO_3)_2(aq) +Li_2SO_4(aq)\rightarrow SrSO_4(s)+2LiNO_3(aq)[/tex]

Which is the molecular equation showing both reactants and products as molecules. Then, the ionic equation shows all the reactants and products as ions, considering that aqueous solutions dissociate whereas solid, liquid and gaseous molecules do not, therefore, we obtain:

[tex]Sr^{2+}(aq)+2NO_3^-(aq) +2Li^{2+}(aq)+SO_4(aq)^{2-}\rightarrow SrSO_4(s)+2Li^+(aq)+2NO_3^-(aq)[/tex]

Finally, for the net ionic equation, we cancel out the spectator ions, which are those at both reactants and products:

[tex]Sr^{2+}(aq)+SO_4(aq)^{2-}\rightarrow SrSO_4(s)[/tex]

Best regards!

Molecular equation - [tex]Sr(NO_3)_2(aq) +Li_2SO_4(aq) \rightarrow SrSO_4 (s) +2LiNO_3 (aq)[/tex]Ionic - [tex]Sr^{2+} (aq) +2NO_3^- (aq) +2Li^+ (aq)+ SO_4^{2-} (aq) \rightarrow SrSO_4 (s)+2Li^+ (aq) +2NO_3^- (aq)[/tex]Net ionic - [tex]Sr^{2+}(aq)+SO_4^{2-} (aq) \rightarrow SrSO_4 (s)[/tex]

A further explanation is below.

Given:

[tex]Sr(NO_3)_2 (aq)[/tex] (Strontium nitrate)[tex]L1_2SO_4 (aq)[/tex] (Lithium sulfate)

Strontium nitrate reacts with Lithium sulfate just to produce Strontium sulfate ([tex]Sr(NO_3)_2[/tex]) and Lithium nitrate ([tex]Li NO_3[/tex]).

The molecular equation will be:

→ [tex]Sr(NO_3)_2(aq) +Li_2SO_4(aq) \rightarrow SrSO_4 (s) +2LiNO_3 (aq)[/tex]

The complete ionic equation will be:

→ [tex]Sr^{2+} (aq) +2NO_3^- (aq) +2Li^+ (aq)+ SO_4^{2-} (aq) \rightarrow SrSO_4 (s)+2Li^+ (aq) +2NO_3^- (aq)[/tex]

By removing the uncharged ions from equation's will be:

Spectator ion:

→ [tex]2Li^+ (aq), 2NO_3^- (aq)[/tex]

Net ionic equation will be:

→ [tex]Sr^{2+}(aq)+SO_4^{2-} (aq) \rightarrow SrSO_4 (s)[/tex]

Thus the response above is right.

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A 45.0 mL solution of 0.0450 M hydroxylamine is extracted with 125 mL of solvent. The distribution constant for the reaction is 5.00 and the pKa of the protonated form of hydroxylamine is 5.960. Calculate the concentration of hydroxylamine remaining in the aqueous phase at pH=4.50 and pH=6.50 .

Answers

Answer:

pH = 4.5, concentration = 0.045 M.

pH = 6.5, concentration = 0.175 M.

Explanation:

The ka for the can be calculated by using the formula below;

Ka = 10^-pka = 10^-5.960 = 1.1 × 10^-6

The concentration of hydrogen ion at pH = 4.50 can be calculated as given below;

{H^+ } = 10^-4.50 = 3.2 × 10^-5 M.

(NB=> 10 in this regards means the inverse of log).

The next step is to determine the distribution coefficient which can be calculated by using the formula below;

distribution coefficient = (partition coefficient) × ka / ka + ( concentration of Hydrogen ion,H^+).

distribution coefficient =( 5 × 1.1 × 10^-6 ) / 1.1 × 10^-6 + 3.2 × 10^-5 M. = 5.5 × 10^-6/ 3.2 = 0.00000171875

The fraction remaining from the compound = 45.0 mL / 45.0 mL + (0.00000171875 × 125).

= 0.999995.

Thus, the concentration at pH = 4.5 = 0.999995 × 0.0450 M = 0.045 M

(B). pH=6.50, thus the concentration of Hydrogen ion = 10^-6.5 = 3.2 × 10^-7 M.

distribution coefficient = (partition coefficient) × ka / ka + ( concentration of Hydrogen ion,H^+).

distribution coefficient = (5 × 1.1 × 10^-6)/ 1.1 × 10^-6 + 3.2 × 10^-7 M).

distribution coefficient = 5.5 × 10^-6/ 1.42 × 10^-6 = 3.9.

Therefore, the concentration = 3.9 × 0.0450 M = 0.175 M.

A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.60 atm. What is the partial pressure of Ar

Answers

The partial pressure of Ne is 1.06 atm. The answer is a. 1.1 atm

Answer:

0.53 atm

Explanation:

First we have to obtain the number of moles of each gas.

Number of moles of Ne = 10g/20g/mol = 0.5 moles

Number of moles of Ar = 10 g/40 g/mol = 0.25 moles

Total number of moles = 0.5 moles + 0.25 moles = 0.75 moles

Partial pressure of Ar = number of moles of Ar/Total number of moles * total pressure

Partial pressure of Ar = 0.25 moles/ 0.75 moles * 1.60 atm

Partial pressure of Ar = 0.53 atm

what are atoms made up of

Answers

Answer:

They are made up of electrons, neutrons and protons

Explanation:

protons, neutrons, and elections ( don’t know if it’s multiple choice but hope this helps)

5. To keep your lunch cold at the beach, would you want a material
that minimizes heat transfer or maximizes heat transfer? Explain (keep it short please)

Answers

Answer:

Minimizes heat transfer

Explanation:

To keep my lunch from getting cold at the beach, a material the minimizes heat transfer will be the most desirable.

Such material should be modified to prevent had transfer by convection, conduction and radiation. This kind of material is desirable because heat generally flows from a place of high amount to that of low amount. Since the food will mostly have a temperature higher than the ambient one, it is expected that heat will flow away from the food to the environment. This will make the food cold. If such heat transfer is prevented, then, the food will remain hot.

The density of krypton gas at 1.35 atm and 54.1°C is ________ g/L.

a. 4.21
b. 0.304
c. 8.42
d. 0.0503
e. 0.237

Answers

a.

Explanation: I saw it on another website.

Use Coulomb's Law to explain why and how atomic radius and IE have an inverse relationship.

Answers

Answer:

Such a relationship between atomic number and atomic radius is a direct correlation. an inverse correlation. According to Coulomb's Law, as the atomic number increases within a series of atoms, the nuclear attraction for electrons will also increase, thus pulling the electron(s) closer to the nucleus.

Explanation:

Calculate the final temperature (once the ice has melted) of a mixture made up initially of 70.0 mL liquid water at 28 oC and 5.0 g ice at 0.0 oC.

Answers

Answer:

21.52° C

Explanation:

From the given information:

mass of the liquid water = 70.0 mL

Initial temperature = 20°C

mass of the ice = 5.0 g

temperature of ice = 0.0°C

Using the calorimetric function:

heat lost by water = heat gained by ice.

mass of water × specific heat of water (s) × ΔT = mass of ice × specific heat of ice (s) × ΔT + n (ΔH_fusion}

⇒ 70 × 4.184 × (28 -x) = 5 × 2.108(x - 0) + [tex](\dfrac{5}{18})[/tex] × 6.01 × 10³

By solving the above equation,

x = 21.52° C

The final temperature of the mixture of water and ice is 21.5 ⁰C.

The given parameters;

initial volume of the liquid = 70 mL initial temperature of the water, = 28⁰Cmass of the ice, = 5.0 gtemperature of the ice, = 0⁰ Cspecific heat capacity of ice = 2.09 J/g ⁰Cheat of fusion of ice = 333.55 J/gspecific heat capacity of water = 4.184 J/g⁰ Cdensity of water = 1 g/ml

Let the final temperature of the mixture = t

mass of the liquid water = 1 g/ml  x 70 ml = 70 g

Apply the principle of conservation of energy to determine the final temperature of the mixture;

heat lost by water = heat gained by ice

[tex]70 \times 4.184(28 - t) = 5\times 2.09(t - 0) \ + \ 5 \times 333.55\\\\8200.64 - 292.88t = 10.45 t + 1667.75\\\\303.33t = 6532.89\\\\t = \frac{6532.89}{303.33}\\\\t = 21.5 \ ^0C[/tex]

Thus, the final temperature of the mixture of water and ice is 21.5 ⁰C.

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After an afternoon party, a small cooler full of ice is dumped onto the hot ground and melts. If the cooler contained 6.60 kg of ice and the temperature of the ground was 42.5 °C, calculate the energy that is required to melt all the ice at 0 °C. The heat of fusion for water is 80.0 cal/g.

Answers

Answer:

The quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

Explanation:

Latent heat of fusion  is the heat absorbed by a unit mass of a given solid at its melting point that completely converts the solid to a liquid at the same temperature. Its unit is Joules/kg or Joules/g.

1 calorie = 4.184 Joules

Therefore , 80.0 cal/g = 80.0 cal/g * 4.184 J/cal = 334.72 J/g

1 g = 0.001 kg; Heat of fusion in J/kg = 334.72 J/g * 1g /0.001 kg = 3.35 * 10⁵ J/kg

Quantity of heat, Q = mass * latent heat of fusion of ice

quantity of heat required = 6.60 kg * 3.35 * 10⁵ J/kg

Quantity of heat required = 2.21 * 10⁶ J

Therefore, the quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

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