Suppose that 25,0 mL of a gas at 725 mmHg and 298K is converted to
273'K and 760 mmHg atm. What would be the new volume? Hinto use the
following gas law equation (p1"V1) /T1 = (p2*V2)/72 "SHOW WORK *
28.15 ml
25.18 ml
21.85 mL
Particles of a liquid"

Suppose That 25,0 ML Of A Gas At 725 MmHg And 298K Is Converted To273'K And 760 MmHg Atm. What Would

Answers

Answer 1

The new volume : 21.85 ml

Further explanation

Given

V1=25,0 ml

P1=725 mmHg

T1=298K is converted to

T2=273'K

P2=760 mmHg atm

Required

V2

Solution

Combined gas law :

[tex]\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}[/tex]

Input the value :

V2=(P1.V1.T2)/(P2.T1)

V2=(725 x 25 ml x 273)/(760 x 298)

V2=21.85 ml


Related Questions

Why do earthquakes occur more often in some countries than in others?

Answers

Answer:

Some places have more earthquakes than others because they sit on the edges of tectonic plates.

A scientist measures the standard enthalpy change for the following reaction to be -17.2 kJ : Ca(OH)2(aq) 2 HCl(aq)CaCl2(s)
2 H2O(l) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(aq) is kJ/mol.

Answers

Answer: [tex]\Delta H^{0}=-173.72[/tex] kJ/mol

Explanation: Enthalpy Change is the amount of energy in a reaction - absorption or release - at a constant pressure. So, Standard Enthalpy of Formation is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

[tex]\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}[/tex]

[tex]Ca(OH)_{2}_{(aq)}+2HCl_{(aq)}[/tex] → [tex]CaCl_{2}_{(s)}+2H_{2}O_{(l)}[/tex]

Standard Enthalpy of formation for the other compounds are:

Calcium Hydroxide: [tex]\Delta H^{0}=[/tex] -1002.82 kJ/mol

Calcium chloride: [tex]\Delta H^{0}=[/tex] -795.8 kJ/mol

Water: [tex]\Delta H^{0}=[/tex] -285.83 kJ/mol

Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

[tex]-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H][/tex]

[tex]-17.2=-1367.46+1002.82-2\Delta H[/tex]

[tex]2\Delta H=17.2-364.64[/tex]

[tex]\Delta H=-173.72[/tex]

So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.150 M NaOH. It requires 21.4 mL of the NaOH solution to reach the end point of the titration. A buret filled with a titrant is held above a graduated cylinder containing an analyte solution. What is the initial concentration of HCl

Answers

Answer:

0.321 M

Explanation:

The neutralization reaction of HCl with NaOH is the following:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

So, 1 equivalent of HCl reacts with 1 equivalent of NaOH. In this case:

1 equivalent HCl = 1 mol HCl

1 equivalent NaOH = 1 mol NaOH

At the equivalence point, the amount of HCl reacts completely with the added amount of titrant (NaOH). As 1 mol of reactant is calculated from the product of the molarity of the solution and the volume, in the equivalent point:

moles HCl = moles NaOH

M(HCl) x V(HCl) = M(NaOH) x V(NaOH)

We have:

M(NaOH) = 0.150 M

V(NaOH) = 21.4 mL = 0.0214 L

V(HCl) = 10.0 mL = 0.01 L

Thus, we calculate the initial concentration HCl as follows:

M(HCl) = (M(NaOH) x V(NaOH))/ (V(HCl))

            = (0.150 M x 0.0214 L)/(0.01 L) = 0.321 M

?
Which of the following can you conclude about a particle labeled
Check all that apply.
D A. It has one nucleon.
B. It has one proton.
I C. It has no neutrons.
D. It has one neutron.
E. It is a beta particle.
F. It has one electron.
G. It is an alpha particle.

Answers

Answer:it has one proton,

and one electron

Explanation:

It has one neutron and It has one nucleon

A 2.54 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL h2o. What will be the final volume reading on the graduated cylinder, in mL?

Answers

Answer: If I'm correct it's 12.54 mL but don't rely on this because I'm not sure

Explanation:

Answer:

12.49 ml

Explanation:

Density = mass / volume

Volume = mass / density

Volume of zinc = 2.54/7.14

Volume of zinc = 0.3557

Initial volume = 12.13 ml

Total volume = initial volume+ volume of zinc

Total volume = 12.13 + 0.3557

Total volume = 12.4857 = 12.49 ml

reddit mcat In a titration, 27.4 mL of a 0.0154 M solution of Ba(OH)2 is needed to neutralize 20.0 mL of HCl. What was the concentration of the acid solution

Answers

Answer:

0.422 M

Explanation:

Equation of the reaction,

2HCl(aq) + Ba(OH)₂(aq) ⇒ BaCl₂(aq)+2H₂O(l)

From the recation above,

2 moles of HCl is needed to neutralize 1 mole of Ba(OH)₂.

Using,

C'V'/CV = a/b......................... Equation 1

Where C' = concentration of acid, C = concentration of base, V' = volume of acid, V = volume of base, a = number of moles of acid, b = number of moles of base.

make C' the subject of the equation.

C' = aCV/bV'................. Equation 2

a = 2 mole, b = 1 mole, C = 0.0154 M, V = 27.4 mL, V' = 20 mL

Substitute into equation 2

C' = (2×0.0154×27.4)/(1×20)

C' = 0.422 M.

Hence the concentration of acid is 0.422 M

Does acid rain make new substances? Construct an argument that uses data from this investigation as evidence for your claim.

Answers

Answer:

Acid rain, like all acids, generates dissolution of chemical compounds, and reacts together with bases to be able to carry out oxide reduction reactions, which by deduction is very likely to form new substances as a result of the dissolution or acid erosion caused.

Explanation:

Acid rain is more likely to occur in large cities or large sources of pollution, since the excess of carbon dioxide in the atmosphere causes it to increase its partial pressure in a condensed way in the clouds, this is how then this cloud when being loaded with water and then generating the rain drags these masses of condensed carbon dioxide in the form of acid rain.

The degree of acidity is directly proportional to the amount of partial pressure of carbon dioxide in the atmosphere.

When C2H4(g) reacts with H2O(g) to form CH3CH2OH(g) according to the following equation, energy is released into the surroundings. C2H4(g) H2O(g) CH3CH2OH(g) Is this reaction endothermic or exothermic

Answers

Answer:

Exothermic

General Formulas and Concepts:

Chemistry

Thermodynamics

Exothermic - releases heat as a productEndothermic - absorbs heat as a reactant

Explanation:

We are given that the reaction takes place between C₂H₄ (g) and H₂O (g) to form CH₃CH₂OH (g) and is releasing heat.

This means that heat would be product as it is being released during the reaction.

Therefore, we have an exothermic reaction.

What is the formula for zinc fluoride?

Answers

The answer is : ZnF₂.

A metal sphere of 0.5 kg is heated to 300 o C, than dropped into a beaker holding 4.08 kg mercury at 20 o C. The temperature of the mercury stabilizes at 99o C after a couple of minutes. What metal was the sphere made of

Answers

Answer:

The metal sphere was made of iron.

Explanation:

From the question,

Heat lost by the metal sphere = heat gained by the mercury.

Cm(t₁-t₃) = C'm'(t₃-t₂)................... Equation 1

Where C = specific heat capacity of the metal sphere, m = mass of the metal sphere, C' = specific heat capacity of the mercury, m' = mass of the mercury.

t₁ = initial temperature of the metal sphere, t₂ = initial temperature of the mercury, t₃ = Final temperature of the mixture.

Make C the subject of the equation

C = C'm'(t₃-t₂)/m(t₁-t₃)................. Equation 2

Given: m = 0.5 kg, m' = 4.08 kg, t₁ = 300 °C, t₂ = 20 °C, t₃ = 99 °C

Constant: C' = 140 J/kgK.

Substitute into equation 2

C = [140×4.08×(99-20)]/[0.5×(300-99)]

C = 45124.8/100.5

C = 449.0 J/kgK.

Hence from the specific heat capacity data sheet, the metal is suspected to  be  made of iron.

An irregularly-shaped piece of aluminum (Al) has a mass of 66.0 grams. What is the volume in cm³ of this piece of aluminum if its density is 2.70 g/cm³?

Answers

Answer:

[tex]V=24.45\ \text{cm}^3[/tex]

Explanation:

Given that,

Mass of a piece of Aluminium, m = 66 grams

The density of Aluminium, d = 2.70 g/cm³

We need to find the volume of this piece in cm³.

We know that,

Density = mass per unit volume

[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{66\ g}{2.7\ g/cm^3}\\\\V=24.45\ \text{cm}^3[/tex]

So, the volume of the piece is [tex]24.45\ \text{cm}^3[/tex].


P4010
+ 4P + 5 O2
How many moles of phosphorus would be
produced if 8.19 mol of P4010 reacted? Enter
your answer with 2 decimal places.

Answers

Answer:

32.76mole of P

Explanation:

The reaction expression is given as;

          P₄O₁₀  →    4P  +  5O₂

Given parameters:

Number of moles of   P₄O₁₀  = 8.19mol

Unknown:

Number of moles of P produced = ?

Solution:

From the balanced reaction expression;

             1 mole of P₄O₁₀  will produce 4 mole of P

         8.19mole of P₄O₁₀  will therefore produce 4 x 8.19  = 32.76mole of P

A student measures 48.8 mL of concentrated nitric acid, which has a density of 1.55g/ mL. What is the mass of the acid?

Answers

The mass of the acid : 75.64 g

Further explanation

Given

volume = 48.8 ml

density = 1.55 g/ml

Required

the mass

Solution

Further explanation

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

 Density formula:

[tex]\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}[/tex]

Input the value :

mass = ρ x V

mass = 1.55 g/ml x 48.8 ml

mass = 75.64 g

Question text What is the mole fraction of benzene in a benzene-toluene solution whose vapor pressure is 51 torr at 20°C?

Answers

Answer:

Mole fraction for benzene is 0.683

Explanation:

We need to determine the colligative property about vapour pressure which formula is:

ΔP = P° . Xm

where P° is vapour pressure of pure solvent.

ΔP = Vapor pressure of pure solvent - Vapor pressure of solution

In this case, our solvent is benzene and the solute is toluene. For this colligative property vapour pressure of solution is lower than pure solvent.

P° of benzene at 20°C is 74.7 Torr

Xm is the value for the mole fraction of solute.

Let's replace data: 74.7 Torr - 51 Torr = 74.7 Torr . Xm

Xm = 0.317 → That's the mole fraction for toluene.

Then, mole fraction for benzene will be: 1 - 0.317 → 0.683

What is the mass of 1.2x10^25 atoms of Helium

Answers

Answer:

dunno

Explanation:

sorry

What volume of gold would be equal in mass to a piece of copper with a volume of 121 mL? The density of gold is 19.3 g/mL; the density of copper is 8.96 g/mL.

Answers

Answer:

We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.

Explanation:

Details:

Density of Copper= 8.96 g/ml

Volume of Copper=141 ml

mass of Gold = mass of Copper

Density of Gold=19.3 g/ml

In order to solve for the mass of copper, we need to use the density formula

Density= mass/volume

Since we are to solve for the mass of copper

mass of copper= Density of Copper * Volume of Copper

mass of copper= 8.96 g/ml* 141 ml= 1263.36 g

Thus,

mass of gold=mass of copper=1263.36 g

Hence,

Using still the density formula to solve for the volume of gold,

Volume of gold=mass of gold/ Density of gold

Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL

Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper

Write the balanced COMPLETE ionic equation for the reaction when aluminum nitrate and sodium hydroxide are mixed in aqueous solution. If no reaction occurs, simply write only NR.

Answers

Answer:See explanation

Explanation:

MOLECULAR REACTION EQUATION;

Al(NO3)3(aq) + 3NaOH(aq) --->Al(OH)3(s) +3NaNO3(aq)

complete ionic equation:

Al^3+(aq) + 3NO3^-(aq)  + 3Na^+(aq) + 3OH^-(aq) ---->Al(OH)3(s) + 3Na^+(aq) + 3NO3^-(aq)

Net ionic reaction equation;

Al^3+(aq) + 3OH^-(aq) ------> Al(OH)3(s)

what is the molarity of a solutoin which contains 38.5 g of sodium chloride disolved in 325 ml solution ?

Answers

Answer:

Molarity =  2.02 M

Explanation:

Given data:

Molarity of solution = ?

Mass of sodium chloride = 38.5 g

Volume of solution = 325 mL (0.325 L)

Solution:

Number of moles = mass/molar mass

Number of moles = 38.5 g/ 58.44 g/mol

Number of moles = 0.658 mol

Molarity:

Molarity = number of moles / volume of solution in L

Molarity = 0.658 mol /0.325 L

Molarity =  2.02 M

What is missing from the temperature and volume
graph shown at right?

Answers

X axis hopes this helps
It is the X-axis because you have the Y-axis but not the x-axis

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.40 moles moles of magnesium perchlorate, Mg(ClO4)2Mg(ClO4)2. Express the number of moles of MgM, Cl Cl, and OO atoms numerically, separated by commas.

Answers

Answer:Moles of Mg, Cl,  0 =  5.40, 10.80, 43.2

Explanation:

1  mole of Mg(ClO4)2  contains  1 mole of Magnesium, Mg atoms

                                                    2 Moles of Chlorine, Cl atoms

                                                    8 Molresof Oxygen atoms

Such that to find the number of moles of each element, We have that

------1 mole Magnesum  atoms/ 1 mol of  Mg(ClO4)2   x 5.40 moles  of magnesium perchlorate, Mg(ClO4)2 = 1 x 5.40 =5.40 moles

------2 moles ofChlorine atoms/ 1 mol of Mg(ClO4)2   x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 2 x 5.40 = 10.80 moles

------8 moles Oxygen atoms/ 1 mol of  Mg(ClO4)2   x 5.40 moles  of magnesium perchlorate, Mg(ClO4)2 = 8 x 5.40 = 43.2 moles

Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have to convert from grams to troy ounces as well.)

Answers

Answer:

0.010 $.

Explanation:

Hello!

In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:

[tex]1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}[/tex]

Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:

[tex]m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g[/tex]

Thus, the price is:

[tex]\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$[/tex]

Best regards!

Calculate the molar mass of hafnium (II) iodide, HfI2. This is 1 Hf and 2 Iodine. No hydrogen.

Answers

It 3 iv been studying it my hole life

Neutralisation reactions

A)endothermic
B)exothermic

Answers

Answer:

Neutralisation reactions are generally B) Exothermic.

Answer: Exothermic.

Explanation: Neutralisation reaction are mostly exothermic.

Hope this helps! ^^

A substance has a density of .80g/cm3 if you have 60cm3 what is the mass?

Answers

Answer:

168.56

Explanation:

Answer:

48 grams

Explanation:

If p and V are already given, calculate m by multiplying those two values.

m = pV

m = 4/5 * 60/1

m = 240/5

m = 48 grams

The mass of that substance is 48 grams.

Radio waves are used to transmit information on various channels. What is the wavelength of a radio wave having the frequency of 5.40 × 1010 Hz?

Answers

Answer:

tyduyfjhg

Explanation:

A student is making a glucose solution. The student is using 12.55 g of glucose (C6H1206) and a 500 mL volumetric flask. Use this information to calculate the molarity of the glucose solution.​

Answers

Answer:

M = 0.138 M

Explanation:

Given data:

Mass of glucose = 12.55 g

Volume of solution = 500 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 12.55 g/ 180.156 g/mol

Number of moles = 0.069 mol

Volume in L:

500 mL × 1 L /1000 mL

0.5 L

Molarity:

M = 0.069 mol / 0.5 L

M = 0.138 M

A chemist has a block of aluminum metal (density is 2.7 g/mL). The block weighs 2.3 g. What is the volume, in mL, of the aluminum block?

Answers

Answer:

0.85 mL

Explanation:

Step 1: Given data

Density of aluminum (ρ): 2.7 g/mLMass of the aluminum block (m): 2.3 gVolume of the aluminum block (V): ?

Step 2: Calculate the volume of the aluminum block

Density is an instrisic property. It is equal to the mass of the block divided by its volume.

ρ = m/V

V = m/ρ

V = 2.3 g/(2.7 g/mL)

V = 0.85 mL

The heat gained by the ice melted the ice and raised the temperature of the melted ice from its initial temperature to the final temperature of the water.

a. True
b. False

Answers

Answer:

True

Explanation:

When ice is heated, the ice gains heat.

This heat gained by the ice is both used to break the intermolecular forces in ice to form water, as well as to raise the temperature of the water to it's final temperature.

What are the ingredients in a margaritaWhat are the ingredients in a margarita drink

Answers

Answer:

cointreau, tequila,lime juice

An ion can be created when a .................... is lost or gained by an element.

Answers

Answer:

electron and ignore this woejdnks

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