Answer:
Step-by-step explanation:
m= month
3÷100= 0.03
0.03×500=$15
$15/m
$15×5×12=$900
$500-$900=
Answer: -$400
A student answered 12 out of 15 questions on an exam correctly.
a) What fraction of the 15 questions did the student answer correctly? Write your answer in
simplest terms.
b) What percent of the 15 questions did the student answer correctly?
Answer:
1. 4/5
2. 80%
Step-by-step explanation:
A translation moves A(2,3) onto A′(4,8). If B(4,6), what is the image of B under the same translation?
A. (6,11)
B. (12,18)
C. (6,8)
D. (8,12)
What decimal represents the shaded part in the picture?
Answer:
40/100 = 0.4
your welcome
Based on a recent poll, there is a 50-50 chance that randomly selected adut has pierced ears, Express the indicated degree of likelihood as a proabability value between 0 and 1.
Answer:
1/2 or 0.5
Step-by-step explanation:
Saying that there is a 50-50 chance of an event happening is equivalent to saying there is a 1 in 2 chance. Therefore, expressing that degree of likelihood as a value between 0 and 1:
[tex]\frac{1}{2}=0.50[/tex]
There is a 1/2 or 0.5 chance that a randomly selected adult has pierced ears.
Answer:
1/2 or 0.5
Step-by-step explanation:
50-50 chance between 0-1 means half of 0-1 which is 1/2 or 0.5
1/2 or 0.5!
PLEASE. NEED HELP. Find the sum.
Distribute the sum:
[tex]\displaystyle\sum_{i=1}^{24}(3i-2)=3\sum_{i=1}^{24}i-2\sum_{i=1}^{24}1[/tex]
Use the following formulas:
[tex]\displaystyle\sum_{i=1}^n1=n[/tex]
[tex]\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2[/tex]
[tex]\implies\displaystyle\sum_{i=1}^{24}(3i-2)=3\cdot\frac{24\cdot25}2-2\cdot24=\boxed{852}[/tex]
In case you don't know where those formulas came from:
The first one is obvious; you're just adding n copies of 1, so 1 + 1 + ... + 1 = n.
The second can be proved in this way: let S be the sum 1 + 2 + 3 + ... + n. Rearrange it as S = n + (n - 1) + (n - 2) + ... + 1. Then 2S = (n + 1) + (n + 1) + (n + 1) + ... + (n + 1), or n copies of n + 1. So 2S = n(n + 1). Divide both sides by 2 and we're done.
Factor (x^2-1x)(-4x+4), with work shown
Answer:
4 ( -x^3 + 2x - x)
Step-by-step explanation:
refer the attachment
Need help on this math problem!!!
Answer:
[tex](fof^{-1})(x)=x[/tex]
Step-by-step explanation:
Composition of two functions f(x) and g(x) is represented by,
(fog)(x) = f[g(x)]
If a function is,
f(x) = (-6x - 8)² [where x ≤ [tex]-\frac{8}{6}[/tex]]
Another function is the inverse of f(x),
[tex]f^{-1}(x)=-\frac{\sqrt{x}+8}{6}[/tex]
Now composite function of these functions will be,
[tex](fof^{-1})(x)=f[f^{-1}(x)][/tex]
= [tex][-6(\frac{\sqrt{x}+8}{6})-8]^{2}[/tex]
= [tex][-\sqrt{x}+8-8]^2[/tex]
= [tex](-\sqrt{x})^2[/tex]
= x
Therefore, [tex](fof^{-1})(x)=x[/tex]
HELP IF YOU KNOW THIS PLEASEEEE
Answer:
63m
Step-by-step explanation:
Solve for x. Write both solution, separated by a comma. 4x^2-x-3=0.
Answer:
x = -3/4, 1
Step-by-step explanation:
Factor left side of the equation.
(4x + 3)(x - 1) = 0
Set factors equal to 0.
4x + 3 = 0
4x = -3
x = -3/4
x - 1 = 0
x = 1
Answer:
x₁ = -3/4
x₂ = 1
Step-by-step explanation:
4x² - x - 3 = 0
4x² + 3x - 4x - 3 = 0
xx(4x + 3) - 4x - 3 = 0
xx(4x + 3) - (4x + 3) = 0
(4x + 3) × (x - 1) = 0
4x + 3 = 0 → x = -3/4
x - 1 = 0 → x = 1
Hope this helps! :)
13 points, please answer!
Which shows the dilation with a possible scale factor of 1/2?
Answer:
Option B
Step-by-step explanation:
With a scale factor of 1/2, the dilated shape should be smaller because of the scale factor, So in Option B the dilated shape is smaller than the real one.
1) Option A is an enlargement
2) Option B is reduction
3) Option C is equality
Two teaching methods, A and B, are implemented for learning Spanish. There is a 70% chance of successfully learning Spanish if method A is used, and a 85% chance of success if methodB is used. However, method B is substantially more 3. time consuming and is therefore used only 20% of the time (method A is used the other 80% of the time). The following notations are suggested:
A-Method A is used.
B-Method B is used.
L-Spanish was learned successfully Interpret each of the probabilities given in the original problem in probability
a) notation with their respective values (four of these).
b) Draw a Probability Tree representing each of the probabilities mentioned above.
c) What is the likelihood a person does not learn Spanish?
d) A student learned the spanish successfully. What is the probability that they were taught by method B?
Answer:
(a) Shown below.
(b) Shown below.
(c) The probability that a person does not learn Spanish is 0.18.
(d) The probability that method B was used given that a student learned the Spanish successfully is 0.83.
Step-by-step explanation:
(a)
Consider the provided data.
[tex]P(A)=0.20\\P(B)=0.80\\P(L|A)=0.70\\P(L|B)=0.85[/tex]
Then the probability of not learning Spanish using the respective methods are:
[tex]P(L'|A)=1-P(L|A)=1-0.70=0.30\\\\P(L'|B)=1-P(L|B)=1-0.70=0.15[/tex]
(b)
The Probability Tree representing each of the probabilities mentioned above is attached below.
(c)
Compute the probability that a person does not learn Spanish as follows:
[tex]P(L')=P(L'|A)P(A)+P(L'|B)P(B)[/tex]
[tex]=(0.30\times 0.20)+(0.15\times 0.80)\\\\=0.06+0.12\\\\=0.18[/tex]
Thus, the probability that a person does not learn Spanish is 0.18.
(d)
Compute the probability that method B was used given that a student learned the Spanish successfully as follows:
[tex]P(B|L)=\frac{P(L|B)P(B)}{P(L|A)P(A)+P(L|B)P(B)}[/tex]
[tex]=\frac{(0.85\times 0.80)}{(0.70\times 0.20)+(0.85\times 0.80)}\\\\=\frac{0.68}{0.14+0.68}\\\\=0.82927\\\\\approx 0.83[/tex]
Thus, the probability that method B was used given that a student learned the Spanish successfully is 0.83.
In a road-paving process, asphalt mix is delivered to the hopper of the paver by trucks that haul the material from the batching plant. The article "Modeling of Simultaneously Continuous and Stochastic Construction Activities for Simulation" (J. of Construction Engr. and Mgmnt., 2013: 1037-1045) proposed a normal distribution with mean value 8.46 min and standard deviation .913 min for the rv X 5 truck haul time.a. What is the probability that haul time will be at least 10 min? Will exceed 10 min?b. What is the probability that haul time will exceed 15 min?c. What is the probability that haul time will be between 8 and 10 min?d. What value c is such that 98% of all haul times are in the interval from 8.46 2 c to 8.46 1 c?e. If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?
Answer:
a) Probability that haul time will be at least 10 min = P(X ≥ 10) ≈ P(X > 10) = 0.0455
b) Probability that haul time be exceed 15 min = P(X > 15) = 0.000
c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10) = 0.6460
d) The value of c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)
c = 2.12
e) If four haul times are independently selected, the probability that at least one of them exceeds 10 min = 0.1700
Step-by-step explanation:
This is a normal distribution problem with
Mean = μ = 8.46 min
Standard deviation = σ = 0.913 min
a) Probability that haul time will be at least 10 min = P(X ≥ 10)
We first normalize/standardize 10 minutes
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69
To determine the required probability
P(X ≥ 10) = P(z ≥ 1.69)
We'll use data from the normal distribution table for these probabilities
P(X ≥ 10) = P(z ≥ 1.69) = 1 - (z < 1.69)
= 1 - 0.95449 = 0.04551
The probability that the haul time will exceed 10 min is approximately the same as the probability that the haul time will be at least 10 mins = 0.0455
b) Probability that haul time will exceed 15 min = P(X > 15)
We first normalize 15 minutes.
z = (x - μ)/σ = (15 - 8.46)/0.913 = 7.16
To determine the required probability
P(X > 15) = P(z > 7.16)
We'll use data from the normal distribution table for these probabilities
P(X > 15) = P(z > 7.16) = 1 - (z ≤ 7.16)
= 1 - 1.000 = 0.000
c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10)
We normalize or standardize 8 and 10 minutes
For 8 minutes
z = (x - μ)/σ = (8 - 8.46)/0.913 = -0.50
For 10 minutes
z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69
The required probability
P(8 < X < 10) = P(-0.50 < z < 1.69)
We'll use data from the normal distribution table for these probabilities
P(8 < X < 10) = P(-0.50 < z < 1.69)
= P(z < 1.69) - P(z < -0.50)
= 0.95449 - 0.30854
= 0.64595 = 0.6460 to 4 d.p.
d) What value c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)?
98% of the haul times in the middle of the distribution will have a lower limit greater than only the bottom 1% of the distribution and the upper limit will be lesser than the top 1% of the distribution but greater than 99% of fhe distribution.
Let the lower limit be x'
Let the upper limit be x"
P(x' < X < x") = 0.98
P(X < x') = 0.01
P(X < x") = 0.99
Let the corresponding z-scores for the lower and upper limit be z' and z"
P(X < x') = P(z < z') = 0.01
P(X < x") = P(z < z") = 0.99
Using the normal distribution tables
z' = -2.326
z" = 2.326
z' = (x' - μ)/σ
-2.326 = (x' - 8.46)/0.913
x' = (-2.326×0.913) + 8.46 = -2.123638 + 8.46 = 6.336362 = 6.34
z" = (x" - μ)/σ
2.326 = (x" - 8.46)/0.913
x" = (2.326×0.913) + 8.46 = 2.123638 + 8.46 = 10.583638 = 10.58
Therefore, P(6.34 < X < 10.58) = 98%
8.46 - c = 6.34
8.46 + c = 10.58
c = 2.12
e) If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?
This is a binomial distribution problem because:
- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (4 haul times are independently selected)
- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (Only 4 haul times are selected)
- The outcome of each trial/run of a binomial experiment is independent of one another. (The probability that each haul time exceeds 10 minutes = 0.0455)
Probability that at least one of them exceeds 10 mins = P(X ≥ 1)
= P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)
= 1 - P(X = 0)
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = 4 haul times are independently selected
x = Number of successes required = 0
p = probability of success = probability that each haul time exceeds 10 minutes = 0.0455
q = probability of failure = probability that each haul time does NOT exceeds 10 minutes = 1 - p = 1 - 0.0455 = 0.9545
P(X = 0) = ⁴C₀ (0.0455)⁰ (0.9545)⁴⁻⁰ = 0.83004900044
P(X ≥ 1) = 1 - P(X = 0)
= 1 - 0.83004900044 = 0.16995099956 = 0.1700
Hope this Helps!!!
a group of girls bought 72 rainbow hairbands ,144 brown and black hairbands and 216 bright colored hairbands .what is the largest possible number of girls in the group
Answer:
72
Step-by-step explanation:
We are assuming that all girls in the group bought the same number of items.
Therefore, we need to find the highest common factor of 72, 144 and 216.
HCF
72 = 2 * 2 * 2 * 3 * 3
144 = 2 * 2 * 2 * 2 * 3 * 3
216 = 2 * 2 * 2 * 3 * 3 * 3
The product of the emboldened numbers is the highest common factor.
That is:
2 * 2 * 2 * 3 * 3 = 72
Therefore, the largest possible number of girls in the group is 72.
Point S is located on RT so that RS/ST = 1/4. What are the coordinates of Point S? (4 , 4 ) (2.4, 2.4) (8 , 8 ) (4.4, 4.4)
Answer:
(4.4, 4.4)
Step-by-step explanation:
The point S can be found as the weighted average of the end points. The relative weights are the reverse of the distances to the end points:
RS : ST = 1 : 4
S = (4R +1T)/5
S = (4(2, 2) +(14, 14))/5 = (22, 22)/5
S = (4.4, 4.4)
You have a prepaid bus pass that has $10 on it. Every time you ride the bus it costs you 50 cents. Assume that you cannot put anymore money on the card after it is used. Create an equation for the situation above.
Answer:
y = 10 - 0.5x for 0 ≤ x ≤ 20
Step-by-step explanation:
Initial value = (0,10)
final value = (20,0)
Cost per trip = debit of 0.50 = slope
equation : y = 10 - 0.5x for 0 <= x <= 20
exact value of :7 1/2 - 1 5/8 +(1 3/8 × 2 7/11 )
Answer:
261/44
Step-by-step explanation:
hope this helps. :)
Answer:
9 1/2
Step-by-step explanation:
7 1/2 - 1 5/8 + (1 3/8 × 2 7/11) =
= 7 4/8 - 1 5/8 + 11/8 * 29/11
= 6 12/8 - 1 5/8 + 29/8
= 5 7/8 + 3 5/8
= 8 12/8
= 8 + 8/8 + 4/8
= 9 1/2
Use the given degree of confidence and sample data to construct interval for the population proportion. Of 369 randomly selected medical students, 23 said that they planned to work in a rural community. Construct a 95% confidence interval for the percentage of all medical students who plan to work in a rural community. (4.16%, 8.30%) (3.77%, 9.47%) (3.30%, 9.17%) (2.99%, 9.47%) (3.77%, 8.70%) In a poll of registered voters nationwide, 43% of those polled blamed of companies the most for the recent increase in gasoline prices. The margin of error at the 96% confidence level for this point estimate is 2.4%. Construct a 95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices. (0.382, 0.478) (0.368, 0.492) (0.406, 0.477) (0.383, 0.477) Cannot be determined from the information given.
Answer:
e) (3.77%, 8.70%)
95% confidence interval for the percentage of all medical students who plan to work in a rural community
(3.83% , 8.69%)
95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices
(0.406 , 0.454)
Step-by-step explanation:
Step(i):-
Given random sample size 'n' = 369
Sample proportion
[tex]p = \frac{x}{n} = \frac{23}{369} = 0.0623[/tex]
95% confidence intervals are determined by
[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]
[tex](0.0623 - 1.96 \sqrt{\frac{0.0623(1-0.0623)}{369} } , 0.0623 + 1.96\sqrt{\frac{0.0623(1-0.0623)}{369} })[/tex]
(0.0623 - 0.0246 , 0.0623 + 0.0246)
(0.0383 , 0.0869)
(3.83% , 8.69%)
95% confidence interval for the percentage of all medical students who plan to work in a rural community
(3.83% , 8.69%)
Step(ii):-
Given 43% of those polled blamed of companies the most for the recent increase in gasoline prices
sample proportion 'p' = 0.43
Given Margin of error (M.E) = 0.024
95% confidence intervals are determined by
[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })[/tex]
[tex](0.43 - 0.024 } , 0.43 +0.024 )[/tex]
(0.406 , 0.454)
Final answer:-
95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices
(0.406 , 0.454)
. Write an example problem that includes a compound event. b. List all of the outcomes of the sample space of the compound event.
Answer:
living organism
Step-by-step explanation:
soil particals and decad crops living organism
Nash's Trading Post, LLC took a physical inventory on December 31 and determined that goods costing $208,000 were on hand. Not included in the physical count were $30,000 of goods purchased from Swifty Corporation, FOB, shipping point, and $23,500 of goods sold to Marigold Corp. For $30,000, FOB destination. Both the Swifty purchase and the Marigold sale were in transit at year-end.
Answer:
$261,500
Step-by-step explanation:
What amount should Nash report as its December 31 inventory?
Item Amount
Goods on hand as per physical count $208,000
(+) Goods purchased from Swifty $30,000
Corporation FOB shipping point
(+) Goods sold to Marigold Corp $23,500
FOB destination (at cost value)
Ending inventory $261,500
Notes:
1) In case of FOB shipping point, the ownership of goods is transferred to the buyer when the goods are shipped and hence in the case of purchases from Swifty corporation, the goods should be included in the inventory of Nash's Trading Post as the goods are shipped and are in transit.
2) In case of FOB destination, the ownership of goods is transferred to the buyer when the goods reaches to the buyer, hence in the case of sales made to Marigold Corp, the goods are still in transit and the ownership is not transferred to Marigold Corp, hence Nash's Trading Post should included that goods in its inventory.
solve this, please prove it with steps in detail
Answer:
2
Step-by-step explanation:
-(1-√2) -(2-√3) + 1/√3 + 2+1/2+√5-(√5-√6)-(√6-√7)+ 1/√7+2√2+1/2√2+3
-1+√2-√2+√3-(√3-2)-(2-√5)-√5+√6-√6+√7-(√7-2√2)-(2√2-3)
-1+√2-√2+√3-√3+2-2+√5-√5+√6-√6+√7-√7+2√2-2√2+3
2
[tex](7^{x})=\frac{7^{2}*7^{3} }{7^{3x} }[/tex] PLEASE SHOW ME HOW TO DO THIS STEP BY STEP I ALREADY KNOW THE ANSWER. IT IS 1.25 I AM GIVING BRAINLIEST
Answer:
I hope it will help you....
Please help! *grade 9 algebra work* :)
Answer:
9x-3 or 3(3x-1)
Step-by-step explanation:
A triangle has three sides. To find the perimeter, add those side lengths together.
3x-3+(4x-1)+(2x+1)
Add your common terms (xs and constants) together.
3x+4x+2x=9x
-1+-3+1=-3
9x-3
If you want to, you can factor the expression.
3(3x-1)
Answer:
9x - 3
Step-by-step explanation:
The perimeter is all the sides added together.
4x - 1 + 2x + 1 + 3x - 3
Rearrange.
4x + 2x + 3x - 1 + 1 - 3
Combine like terms.
9x - 3
Plz, help if you have the time too
Answer:
Hey there!
You can use the ASA postulate, when two angles are congruent, and one side is congruent.
Hope this helps :)
Please answer i will give thanks and 5 star
Answer:
A, B, and E are all less than 1/8
If (x+3) varies directly as y and x=3 when y=12, what is the value of x when y=8?
Answer:
x = 1.
Step-by-step explanation:
y = k(x + 3)
When x = 3 y = 12 so
12 = k(3 + 3)
6k = 12
k = 2.
So the relation is y = 2(x + 3)
When y is 8:
8 = 2(x + 3)
2x = 8 - 2*3 = 2
x = 1.
Can someone please help me I really need help
Answer:
choice c
Step-by-step explanation:
y axis shows value of computer
v-intercept; x axis = 0
show initial value of the computer
Help!!!!! please!!!!!
Hey there! :)
Answer:
B. The volume of Cylinder B is larger.
Step-by-step explanation:
Find the volumes of each cylinder using the formula V = πr²h:
Cylinder A:
V = π3² · 5
V = 9π · 5
V = 45π units³
Cylinder B:
V = π5²· 3
V = 25π · 3
V = 75π units³
75π u³ > 45π u³, so the volume of Cylinder B is larger.
which is the domain of the function in this table ?
Answer: 1,2,3,4
Step-by-step explanation:
The domain consists of every x value
The mean length of 4 childrens' big finger is 14cm. The mean length of 9 adults' big finger is 16.1cm. What is the mean length (rounded to 2 DP) of these 13 people's big finger?
Answer:
The mean length of the 13 people's big finger is 15.45 cm
Step-by-step explanation:
Given;
mean length of 4 childrens' big finger, x' = 14cm
mean length of 9 adults' big finger is 16.1cm, x'' = 16.1cm
Let the total length of the 4 childrens' big finger = t
[tex]x' = \frac{t}{n} \\\\x' = \frac{t}{4}\\\\t = 4x'\\\\t = 4 *14\\\\t = 56 \ cm[/tex]
Let the total length of the 9 adults' big finger = T
[tex]x'' = \frac{T}{N} \\\\x'' = \frac{T}{9}\\\\T = 9x''\\\\T = 9*16.1\\\\T = 144.9 \ cm[/tex]
The total length of the 13 people's big finger = t + T
= 56 + 144.9
=200.9 cm
The mean length of these 13 people's big finger;
x''' = (200.9) / 13
x''' = 15.4539 cm
x''' = 15.45 cm (2 DP)
Therefore, the mean length of the 13 people's big finger is 15.45 cm
Which of the following is the best definition of slope?
O A. The point where a line crosses the y-axis
B. The measure of the steepness of a line
O C. The value of a dependent variable
O D. The value of an independent variable
Answer: B
Step-by-step explanation: In algebra, we use the word slope to describe how steep a line is and slope can be found using the ratio rise/run between any two points that are on that line.