Answer:
s ಕಣಗಳು ಒಂದು ಮಧ್ಯಮ ಟ್ರೋಗ್ ಹಲೋ ನೀವು ಹೇಗಿದ್ದೀರಿ ಬಿಎನ್ ನಾನು ಹಾಡುಗಳಿಂದ ಸುಳ್ಳಲ್ಲ
Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at sea level. One container is in Denver at an altitude of about 6,000 ft and the other is in New Orleans (at sea level). The surface area of the container lid is A
Answer:
[tex](a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]
[tex](b)\ F_{No} = 771.125N[/tex]
Explanation:
Given
[tex]d_D = 6000ft[/tex] ---- Altitude of container in Denver
[tex]A = 0.0155m^2[/tex] -- Surface Area of the container lid
[tex]P_D = 79000Pa[/tex] --- Air pressure in Denver
[tex]P_{No} = 100250Pa[/tex] --- Air pressure in New Orleans
See comment for complete question
Solving (a): The expression for [tex]F_{No[/tex]
Force is calculated as:
[tex]F = \triangle P * A[/tex]
The force in New Orleans is:
[tex]F_{No} = \triangle P * A[/tex]
Since the inside pressure is half the pressure at sea level, then:
[tex]\triangle P = P_{No} - \frac{P_{area}}{2}[/tex]
Where
[tex]P_{area} = 101000Pa[/tex] --- Standard Pressure
Recall that:
[tex]F_{No} = \triangle P * A[/tex]
This gives:
[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]
Solving (b): The value of [tex]F_{No[/tex]
In (a), we have:
[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]
Where
[tex]A = 0.0155m^2[/tex]
[tex]P_{No} = 100250Pa[/tex]
[tex]P_{area} = 101000Pa[/tex]
So, we have:
[tex]F_{No} = [100250 - \frac{101000}{2}] * 0.0155[/tex]
[tex]F_{No} = [100250 - 50500] * 0.0155[/tex]
[tex]F_{No} = 49750* 0.0155[/tex]
[tex]F_{No} = 771.125N[/tex]
How does rainwater contribute to aquatic succession
Answer:
Rain water carries sediment and then these accumulate on the bottom of ponds, lakes and wetlands. This accumulation build up over time and eventually, the water disappears (because they sink into the ground) and the area once covered with water becomes land.
HELP ME PLEASEEEEEEEEEEEEEEEE
Which of the following means that an
image is real?
A. +do
B. +di
c. -di
D.-do
Answer:
B
Explanation:
A cannonball is shot from the top of a
47.8 m high hill at a speed of 53.7 m/s.
How fast is it going when it reaches
the plain below?
Answer:
61.8
Explanation:
It must be going at a speed of 61.81 m/s when it reaches the plain below
What are kinematic equations?
The kinematic equations are a set of equations that describe the motion of an object with constant acceleration. Kinematics equations require knowledge of derivatives, rate of change, and integrals.
using Kinematics equations
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2gs ( a = g)
= [tex](53.7)^{2}[/tex] + 2 * 9.8 * 47.8 m
v = 61.81 m/s
It must be going at a speed of 61.81 m/s when it reaches the plain below
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on what factors, current sensitivity voltage sensitivity of
a galvanometer depend?
Explanation:
The voltage sensitivity of a galvanometer is given by :
[tex]\dfrac{NBA}{RK}[/tex]
Where
N=Number of turns
A=Area of coil
B=Magnetic field produced in coil
K=Torsion constant of galvanometer
R=Resistance of galvanometer
The current sensitivity of a galvanometer is given by :
[tex]\dfrac{NBA}{K}[/tex]
Hence, this is the required solution.
A certain organ pipe, open at both ends, produces a fundamental frequency of 288 Hz in air. Part A If the pipe is filled with helium at the same temperature, what fundamental frequency tHe will it produce
Answer:
773.25 Hz
Explanation:
Concept : In an open organ pipe in fundamental mode of vibration
wave length of wave λ = 2L
where L is length of the pipe
frequency = velocity of sound / λ
Given values: fundamental frequency = 288 Hz
fluid is air. velocity of sound = 340 m/s
⇒ 288 = 340/2L
⇒L = 59.02 cm
The point to be noted is if the pipe is filled with helium initially at the same temperature, there would be change in the sound velocity .Then, frequency of note produced will also be changed .
We know that velocity of sound is inversely proportional to square root of molar mass of gas
velocity of sound in air / velocity of sound in helium = Square root of (Molar mass of Helium/ molar mass of air)
[tex]\frac{V_a}{V_{He}} = \sqrt{\frac{4}{28.8} } \\\frac{340}{V_{He}} =0.3725\\V_{He} =912.5 m/s[/tex]
Now, frequency = velocity of sound / λ
= 912.75 / (2 x 0.5902)
= 773.25 Hz
The illustration shows ?
A)open circuit
B)broken circuit
C)series circuit
D)parallel circuit
Answer:
D)parallel circuit
Explanation:
the components are placed parallel from eachother
You purchased 1.9 kg of apples from Wollaston. You noticed that they used a spring scale with the smallest division of 2.1 g to weigh them. What is the relative error in this weight measurement as a percentage
The relative error in this weight measurement as percentage is
[tex]0.1105\%[/tex]What is relative error?is the ratio of the absolute error of a measurement to the measurement being taken. In other words, this type of error is relative to the size of the item being measured.
Therefore,
[tex]\% relative error = \frac{smallest division}{mass of apples}*100\\\\\% relative error = \frac{2.1g}{1900}*100\\\\\% relative error = 0.1105\%[/tex]
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Answer:
The relative error in this weight measurement is approximately 0.1105 %.
Explanation:
We know that,
Relative Error is the ratio of the absolute error of a measurement to the actual measurement . It can be mathematically represented as,
Relative Error = (Measured Value - Actual Value) / Actual Value * 100
In this case, the actual weight is 1.9 kg, and the smallest division of the spring scale is 2.1 g.
Actual Weight = 1.9 * 1000 = 1900 (As 1 kg = 1000g)
We know that the absolute error will be equal to the smallest division hence,
Measured Value - Actual Value = 2.1 g
By replacing this in the general formula we get,
Relative Error = (Measured Value - Actual Value) / Actual Value * 100
= [tex]\frac{2.1}{1900} *100[/tex] %
= [tex]\frac{2.1}{19}[/tex] %
≈ 0.1105 %
Therefore, the relative error in this weight measurement is approximately 0.1105 %.
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A woman is 160160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing upright
This question is incomplete, the complete question is;
A woman is 160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing upright.
Hint: Consider the ray diagram below, of the rays that enable her to see her feet and the top of her head.
Use what you know about the law of reflection, together with a bit geometry.
The missing Image is uploaded along this answer below.
Answer:
the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm
Explanation:
Given the data in the question and illustrated in the image below,
From image 2;
The distance from the woman's eyes to the top of her head is represented as b and a represent the distance from her eyes to her feet.
Therefore, since her height is 160 cm
a + b = 160 ------ let this be equation 1
i.e AD + DG = 160 cm
Now, from the same image 2, we will notice that triangle ABC and tringle CBD are similar, so
∠ABC = ∠CBD
AC = CD
since AD = a and AC + CD = A
AC = CD = a/2
Also, triangle DEF and FEG are si,ilar
∠DEF = ∠FEG
so
DF = FG
since DG = b and DF + FG = b
DF = b/2
so the minimum vertical length of a mirror in which the woman can see her entire body while standing upright will be;
⇒ a/2 + b/2
⇒ a + b / 2
from equation 1, a + b = 160
so
⇒ a + b / 2 = 160 / 2 = 80
Therefore, the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm
The minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm.
What is the minimum vertical length?The minimum vertical length of a mirror in which she can see her entire body while standing upright is calculated as follows;
u + v = 160 cm
where;
u is the image heightv is the object heightFor mirror, u = v
2u = 160 cm
u = 160 cm/2
u = 80 cm
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Two identical circular, wire loops 35.0 cm in diameter each carry a current of 2.80 A in the same direction. These loops are parallel to each other and are 24.0 cm apart. Line ab is normal to the plane of the loops and passes through their centers. A proton is fired at 2600 m/s perpendicular to line ab from a point midway between the centers of the loops.
Find the magnitude of the magnetic force these loops exert on the proton just after it is fired.
Answer:
The answer is "[tex]4659.2 \times 10^{-24} \ N[/tex]"
Explanation:
The magnetic field at ehe mid point of the coils is,
[tex]\to B=\frac{\mu_0 i R^2}{(R^2+x^2)^{\frac{3}{2}}}\\\\[/tex]
Here, i is the current through the loop, R is the radius of the loop and x is the distance of the midpoint from the loop.
[tex]\to B=\frac{(4\pi\times 10^{-7})(2.80\ A) (\frac{0.35}{2})^2}{( (\frac{0.35}{2})^2+ (\frac{0.24}{2})^2)^{\frac{3}{2}}}\\\\[/tex]
[tex]=\frac{(12.56 \times 10^{-7})(2.80\ A) \times 0.030625}{( 0.030625+ 0.0144)^{\frac{3}{2}}}\\\\=\frac{ 1.07702 \times 10^{-7} }{0.0095538976}\\\\=112.730955 \times 10^{-7}\\\\=1.12\times 10^{-5}\ \ T\\[/tex]
Calculating the force experienced through the protons:
[tex]F=qvB=(1.6 \times 10^{-19}) (2600)(1.12 \times 10^{-5})= 4659.2 \times 10^{-24}\ N[/tex]
A French submarine and a U.S. submarine move toward each other during maneuvers in motionless water in the North Atlantic. The French sub moves at 43.00 km/hkm/h , and the U.S. sub at 64.00 km/hkm/h . The French sub sends out a sonar signal (sound wave in water) at 1000 Hz. Sonar waves travel at 5470 km/hkm/h . What is the signal's frequency as detected by the U.S. sub
Answer:
[tex]f_{U}= 1019.72hz[/tex]
Explanation:
From the equation we are told that:
Velocity of French sub [tex]V_{U}= 43.00km/h[/tex]
Velocity of U.S. sub at [tex]V_{F}|=64.00 km//h[/tex]
French Wave Frequency [tex]F_{F}=1000Hz[/tex]
Velocity of wave [tex]V_{s}=5470 km/h[/tex]
Generally the equation for Signal's frequency as detected by the U.S. is mathematically given by
Doppler effect
[tex]f_{U} = \frac{ f_F (vs + v_{U})}{(v_s - v_F) }[/tex]
[tex]f_{U}= \frac{ 1000 x ( 5470+64)}{(5470-43)}[/tex]
[tex]f_{U}= 1019.72hz[/tex]
An individual's belief that they can master a situation and produce positive outcomes is
Answer:
optimism
Explanation:
just an idea
....
Help me with this please
Use the drop-down menus to complete each sentence.
The number of half-lives changes. This is the _______ variable.
The number of radioactive atoms changes due to the number of half-lives. The number of radioactive atoms is
therefore the _______
variable.
Answer:
Independent, then dependent
Explanation:
Just took this on Edge 2021
An object is placed 50cm in front of a concave mirror of radius 60cm. How far from the mirror is the image?
Answer:To explian the exact calculation of this pruduct we must not try!
Why does carpet produce static electricity more than hardwood floors?
Answer:
The carpet has a buildup of electrons in it that get released onto your body when you rub across the floor while the hardwood doesn't have electrons built up inside of it.
Explanation:
I study that
PHYSICS HELP !! 30 points please answer correctly !! questions attached below
A spherical conducting shell has an inner radius of 0.2 m and an outer radius of 0.4 m. There is no charge on the outer surface but the shell does have a nonzero net charge. All charges remain at rest. The potential at the outer surface is -2 V. The potential at the center of the cavity is g
Answer:
[tex]P_c=-4v[/tex]
Explanation:
From the question we are told that:
Inner radius [tex]r_1=0.2[/tex]
Outer radius[tex]r_2=0.4[/tex]
Potential at the outer surface is [tex]P_o= -2 V[/tex]
Generally the equation for Potential at the outer surface P_o is mathematically given by
[tex]P_o=\frac{KQ}{r_2}[/tex]
[tex]-2=\frac{KQ}{0.4}[/tex]
Therefore
[tex]KQ=-0.8v[/tex]
Generally the equation for Potential at Center of outer cavity [tex]P_c[/tex] is mathematically given by
[tex]P_c=\frac{KQ}{r_1}[/tex]
[tex]P_c=\frac{-0.8}{0.2}[/tex]
[tex]P_c=-4v[/tex]
Therefore the potential at the center of cavity
[tex]P_c=-4v[/tex]
The potential at the center of the cavity of the spherical conducting shell is -0.4 V.
What is electric potential of spherical shell?Electric potential of spherical shell is the total amount of work required to move a charge in s spherical shell from one point to other.
Electric potential of spherical shell at outer surface can be given as,
[tex]P_{outer}=k\dfrac{Q}{r_o}[/tex]
Electric potential of spherical shell at center of outer gravity can be given as,
[tex]P_{cavity}=k\dfrac{Q}{r_i}[/tex]
Here, (Q) is the charge, (k) is the constant and [tex](r_o, r_i)[/tex] is the outer and inner radius.
A spherical conducting shell has an outer radius of 0.4 m and the potential at the outer surface is -2 V. Thus, the potential at the outer surface can be find out using the above formula as,
[tex]-2=k\dfrac{Q}{0.4}\\kQ=-0.8\rm V[/tex]
The spherical conducting shell has an inner radius of 0.2 m. Thus, the potential at the outer surface can be find out using the above formula as,
[tex]P_{cavity}=k\dfrac{Q}{0.2}\\P_{cavity}=\dfrac{-0.8}{0.2}\\P_{cavity}=-0.4\rm V[/tex]
Thus, the potential at the center of the cavity of the spherical conducting shell is -0.4 V.
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Two parallel slits are illuminated by light composed of two wavelengths, one of which is 657 nm. On a viewing screen, the light whose wavelength is known produces its third dark fringe at the same place where the light whose wavelength is unknown produces its fourth-order bright fringe. The fringes are counted relative to the central or zeroth-order bright fringe. What is the unknown wavelength
Answer:
λ = 5.75 10⁻⁷ mm
Explanation:
This is a slit interference exercise, we analyze each wavelength separately
λ = 657 nm indicate that the third dark pattern
a sin θ = (m + ½) lam
a sin θ = (3 + ½) 657 10⁻⁹
a sin θ = 2299.5 10⁻⁹ nm
for the other wavelength in the same place we have m = 4 bright
a sin θ = m lam
we substitute
2299.5 10⁻⁹ = 4 λ
λ = [tex]\frac{2299.5 \ 10^9 }{ 4}[/tex]
λ = 5.75 10⁻⁷ mm
How long does it take for a 3.5 kW electric water heater to heat 40 kg of water? from 20 ° C to 75 ° C? The specific heat capacity of water is 4190 J/kgK PLEASE HURRY ITS A TEST
Answer:
2633.7 s
Explanation:
From the question,
Heat lost by the water heater = Heat gained by the water
Applying,
P = cm(t₂-t₁)/t.................. Equation 1
Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time
make t the subject of the equation
t = cm(t₂-t₁)/P.............. Equation 2
From the question,
Given: c = 4190 J/kgK, P = 3.5 kW = 3500 W, m = 40 kg, t₁ = 20°C, t₂ = 75°C
Substitute these values into equation 2
t = 4190×40(75-20)/3500
t = 9218000/3500
t = 2633.7 s
Help
An object’s mass 300 kg is observed to accelerate at the rate of 4 m/s^2. Calculate the force required to produce this acceleration. *
1. 1000 N
2 .75 N
3. 1200 N
4. 1250 N
im paying on my phone but dont have full access when i log into computer
Answer:
um let me know what i can do to try get you full access
Explatnation:
Blue whales apparently communicate with each other using sound of frequency 17.0 Hz, which can be heard nearly 1000 away in the ocean. What is the wavelength of such a sound in seawater, where the speed of sound is 1531 m/s
Answer:
the wavelength of the sound in seawater is 90.1 m.
Explanation:
Given;
frequency of the sound, f = 17 Hz
speed of the sound in seawater, v = 1531 m/s
The wavelength of the wave is calculated as follows;
v = fλ
λ = v / f
where;
λ is the wavelength of the sound
λ = 1531 / 17
λ = 90.1 m
Therefore, the wavelength of the sound in seawater is 90.1 m.
Radon has a half-life of 56s. After what time will it's activity be reduced to (a) 90% (b) 50% (c) 10% of it's initial value
Answer:
A) 11.2 s
B) is 56 s
C) 170.8 s
Light travels at 300,000,000 m/s. This is an example
Answer:
ook soooooo
Explanation:
Two waves that have
(10 Points)
will add together to produce beats *
the same frequency
slightly different frequencies
different speeds
the same wavelength
Answer:
slightly different frequencies
Explanation:
The alternate increase or decrease of sound produced by the interference of two sound waves of slightly different frequencies is called ‘Beat’. The maximum beat frequency that a human ear can detect is 7 beats/sec.
This definition of the beats is clearly pointing out that the two waves whose frequencies are slightly different will add together to produce the beats.
Therefore, the correct answer will be:
slightly different frequencies
What happens to the force of gravity between two masses if the mass of one of the objects decreases?
The force of gravity also increases
The force of gravity stays the same
The force of gravity decreases
none of these apply
It increases
Explanation:
The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between object
Answer:
C: Gravity decreases
Explanation:
Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks;
????
is the damping coefficient, with units of kg/sec.
m
This question is incomplete, the complete question is;
Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks; γ is the damping coefficient, with units of kg/sec
m = 0.2, γ = 1.6 and k = 4
Initial displacement is 1 and initial velocity is -2
x" + _____ x' ____x = 0
x(t) =
Answer:
the solution that satisfies the initial conditions specified is;
x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]
Explanation:
Given the data in the question ;
m = 0.2, γ = 1.6, k = 4
x(0) = 1, x'(0) = -2
Now, the differential equation that governs the motions of spring mass system is;
mx" + γx' + kx = 0
so we substitute
0.2x" + 1.6x' + 4x = 0
divide through by 0.2
x" + 8x' + 20x = 0
hence, characteristics equation will be;
m² + 8m + 20 = 0
we find m using; x = [ -b±√(b² - 4ac) ] / 2a
m = [ -8 ± √((8)² - 4(1 × 20 )) ] / 2(1)
m = [ -8 ± √( 64 - 80 ) ] / 2
m = [ -8 ± √-16 ) ] / 2
m = ( -8 ± 4i ) / 2
m = -4 ± 2i
Hence, the general solution of the differential equation is;
x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]
From the initial conditions;
c₁ = 1, c₂ = 1
the solution that satisfies the initial conditions specified is;
x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]
HELP PLZ
Calculate the resistivity of a metal of length 2m at 20°C having the resistance
of 20 ohm and diameter 0.3mm?
Answer:
40*C
Explanation: