Newton's theory of gravitation allows people to successfully predict when and where an eclipse may be observed.

a. True
b. False

Answers

Answer 1

Answer:

A. True, I think

Explanation:


Related Questions

Definition of waves ​

Answers

Answer:

A wave can be described as a disturbance that travels through a medium from one location to another location.

Explanation:

A uniform rod of length 80cm rotated in the xy plane about a frictionless pin passing through one end (as shown in figure). If the angular
velocity of the rod is 4rad/s, find the linear velocity (in m/s) of its mid-point C
Rod
Pin
С
Select one:
O a. 0.5
O b. 1.6
O c. 1.3
O d. 0.8​

Answers

Answer:

Linear velocity (in m/s) = 1.6 m/s

Explanation:

Given:

Length of rotational plane = 80 cm

Angular  velocity of the rod = 4rad/s

Find:

Linear velocity (in m/s)

Computation:

Radius from mid point C = Length of rotational plane / 2

Radius from mid point C = 80 / 2

Radius from mid point C = 40 cm

Radius from mid point C = 0.4 m

Linear velocity (in m/s) = Angular  velocity of the rod x Radius from mid point C

Linear velocity (in m/s) = 0.4 x 4

Linear velocity (in m/s) = 1.6 m/s

The bands on Jupiter are ultimately caused by...


the Coriolis effect.


its magnetic fields.


precession.


the Great Red Spot.

Answers

Precision because it’s the answer

What is the frequency of microwaves of wavelength 3 cm?
Give your answer to the
nearest GHz and without units.

Answers

Answer:

10 GHz

Explanation:

Applying,

v = λf.................... Equation 1

Where v = speed of microwave, λ = wavelength, f = frequency.

make f the subject of the equation

f = v/λ................ Equation 2

Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s

From the question,

Given: λ = 3 cm = 0.03 m

Constant; v = 3×10⁸ m/s

Substitute these values into equation 2

f = 3×10⁸/(0.03)

f = 10¹⁰ Hz

f = (10¹⁰/10⁹) GHz

f = 10 GHz

Phobos's Orbit. Phobos orbits Mars at a distance of 9,380 km from the center of the planet and has a period of 0.3189 days. Assume that Phobos's orbit is circular. Calculate the mass of Mars. Express your answer in units of kg. (Hint: Use the circular orbit velocity formula ; remember to use units of meters, kilograms, and seconds.) Please round the answer to four significant digits. m

Answers

Answer:

Explanation:

The relation between time period of moon in the orbit around a planet can be given by the following relation .

T² = 4 π² R³ / GM

G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .

Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)²  = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )

M = .06424  x 10²⁵

= 6.4 x 10²³ kg .

If the height is 10m, what is the potential energy? Asuming that the mass is 10

Answers

[tex]\huge{\textit{\sf{{\color{m}{Answer}}{\color{b}{࿐}}}}}[/tex]

we know,

[tex] \boxed{potential \: energy = mgh}[/tex]

So,

[tex]\longmapsto10 \times 9.8 \times 10[/tex]

[tex]\longmapsto980 \: joules[/tex]

a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceleration of 3 m/s^2. how much work must this force do to stop the block?
a. -576 J
b. -360 J
c. -288 J
d. 360 J
e. 576 J
walk me through this please. NO LINKS. ​

Answers

Answer:

Is there a picture?

Explanation:

A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current running from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]

Answers

Answer:

Explanation:

Force on a current carrying wire in a magnetic field

= B i L where B is magnetic field , i is current and L is length of the wire .

Putting in the given values in the question

force on a current carrying wire in a magnetic field  = .001 T x i x .5 m

5 x 10⁻⁴ i  N .

weight of the wire = .050 kg x 9.8 m/s²

= .49 N .

For equilibrium

5 x 10⁻⁴ i  = .49

i = 980 A .

An object has one force acting on it. It is a 33- Newton force pointing downward. To create a net force of zero on the object, which force must be applied to it?

Answers

As soon as I see "Which...", I know that the last part of the question is the list of answer choices, but you decided not to let us see them.

The answer is: A 33-Newton force pointing upward.

A solid, uniform sphere of mass 2.0 kg and radius 1.8 m rolls from rest without slipping down an inclined plane of height 7.5 m. What is the angular velocity of the sphere at the bottom of the inclined plane

Answers

Answer:

[tex]w^2=5.5rads/s[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=2.0kg[/tex]

Radius [tex]r=1.8m[/tex]

Height [tex]h=7.5m[/tex]

Generally the equation for Potential energy is mathematically given by

Potential energy=Kinetic energy+Rotational energy

 [tex]mgh=\frac{1}{2}mv^2+\frac{1}{2}Iw^2[/tex]

Since there is no slipping

 [tex]v=rw[/tex]

Therefore

 [tex]mgh=\frac{1}{2}mr^2w^2+\frac{1}{2}Iw^2[/tex]

Where

      [tex]I=\frac{1}{2}mr^2[/tex]

      [tex]l=3.24m[/tex]

 [tex]2*9.81*7.5=\frac{1}{2}(2)(1.8)^2w^2+\frac{1}{2}(3.24)w^2\\\\[/tex]

 [tex]147.15=3.24w^2+1.62w^2[/tex]

 [tex]w^2=\frac{147.15}{4.86}[/tex]

 [tex]w^2=\sqrt{\frac{147.15}{4.86}}[/tex]

 [tex]w^2=5.5rads/s[/tex]

The planets and the asteroid belt orbit the Sun in __________. Multiple Choice a spherical distribution, whereas the Oort cloud of comets orbits in a plane planes, whereas the Oort cloud of comets has a spherical distribution orbits nearly identical to the Oort cloud of comets planes tilted at an angle to the plane of the Oort cloud of comets a spherical distribution similar to that of the Oort cloud of comets

Answers

Answer:

planes, whereas the Oort cloud of comets has a spherical distribution.

Explanation:

A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.

Basically, the planets are divided into two (2) main categories and these includes;

I. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.

II. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.

These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.

Oort cloud is also referred to as Opik and it typically comprises of icy pieces of planetesimals (space debris) that spherically surrounds the sun at distances ranging from about 3000 to 100,000 AU.

Hence, the planets and the asteroid belt orbit the Sun in planes, whereas the Oort cloud of comets has a spherical distribution.

Which refers to the density of the medium’s particles at the compression of a sound wave?

Answers

Answer:

Explanation:

Amplitude. the density of a mediums particles at the compression of the wave. Rarefaction. the part of a wave where the particles of the medium are farther apart.

Answer: amplitude

Explanation:

In an electric resistance of 20 ohms, if the current intensity passing through it
is doubled, its value becomes ........ ohms.
b. 20
d. 40
a. 10
c. 30​

Answers

Answer:

a.  10 ohms.

Explanation:

Given;

first electrical resistance, r₁ = 20 ohms

let the first current through the circuit = I₁

let the second current through the circuit, I₂ = 2I₁ (since it is doubled)

then, the new value of the resistance after doubling the current = r₂

the current intensity is given as;

[tex]\frac{dI}{dt} = I = \frac{v}{r} \\\\I_1r_1 = I_2r_2\\\\r_2 = \frac{I_1r_1}{I_2} \\\\r_2 = \frac{I_1 \times 20}{2I_1 } \\\\r_2 = 10 \ ohms[/tex]

Therefore, the new value of the resistance is 10 ohms.


An object
moves through space with balanced forces acting on it. Which statement
best describes the speed and direction of the object as long as the forces acting on it
remain balanced?

Pls answer number 4 and an explanation

Answers

Answer: G the speed and direction of the object will remain constant.

A gondola can carry 20 skiers, with a total mass of up to 2250 kg. The gondola ascends at a constant speed from the base of a mountain, at 2150 m, to the summit at 3345 m. (a) How much work does the motor do in moving a full gondola up the mountain

Answers

Answer:

[tex]$2.63\times 10^{7} \ J$[/tex]

Explanation:

Given :

Total mass that a gondola can carry, m = 2250 kg

Displacement, s = 3345 - 2150

                           = 1195 m

Gravitational force, F = mg

                                  = 2250 x 9.8

                                 = 22050 N

Therefore the work done by the motor in moving the full gondola up the mountain,

W = F x s

    = 22050 x 1195

    = [tex]$2.63\times 10^{7}$[/tex] J

A system is in liquid-vapor mixture of 0.5 kg of saturated water vapor and 0.5 kg
of saturated liquid. Calculate the quality.​

Answers

Answer:

x = 0.5 = 50%

Explanation:

The quality of a water liquid-vapor mixture can be defined as the fraction of water vapor present in the water liquid-vapor mixture. Therefore, it can be calculated by the use of the following formula:

[tex]x = \frac{m_{vap}}{m}[/tex]

where,

x = quality = ?

m_vap = mass of saturated water vapor = 0.5 kg

m = total mass = mass of saturated vapor + mass of saturated liquid

m = 0.5 kg + 0.5 kg = 1 kg

Therefore,

[tex]x = \frac{0.5\ kg}{1\ kg}[/tex]

x = 0.5 = 50%

Un corredor hace los 400 metros lisos en 50 seg. Calcula la velocidad en la carrera.

Answers

Answer:

8 meters/second

Explanation:

Rate x Time = Distance

R x T = D

R x 50sec = 400meters

R x 50sec/50sec = 400meters/50sec

R = 8meters/sec

An open cart is rolling to the left on a horizontal surface. A package slides down a chute and lands in the cart. Which quantity or quantities have the same value just before and just after the package lands in the cart

Answers

Answer: the horizontal component of total momentum

Explanation:

Since the open cart is rolling to the left on the horizontal surface, the quantity that has the same value just before and just after the package lands in the cart is the horizontal component of total momentum.

Momentum, is the product of the mass of a particle and the velocity of the particle. The change of momentum depends on the force which acts on it. The addition of the the individual momenta is the total momentum.

The instrument measuring the temperature change between inspired cool air and expired warm air is called?​

Answers

Answer:

It's called a Spirometer

If I have a sphere rolling on a table with an initial velocity and then it falls off the edge of the table, from this point on it is taken as if my initial velocity were zero, or it starts from the initial velocity that I had before in the table?

Answers

Answer:

The initial velocity after leaving the table is the same as it was before leaving the table (nothing is present to produce discontinuties in the velocity).

Before leaving the table the vertical velocity was zero and is zero when it leaves the table.

The horizontal velocity is constant with no forces present to change the velocity.

DESCRIBE THE REQUIREMENTS OF AN INTERNET CONNECTION?
please tell me the answer​

Answers

Answer: The basic requirements for connecting to the Internet are a computer device, a working Internet line, and the right modem for that Internet line. In addition, software programs such as Internet browsers, email clients, Usenet clients, and other special applications are needed in order to access the Internet.

Explanation: brainleist pls :)

If you cut a permanent magnet into four pieces,
you will have what?

A) four temporary magnets
B) four smaller permanent magnets
C) two north poles and two south poles
D)four objects that are no longer magnets

Answers

you would have C) two north poles and two south poles

what determines the strength of a base?

Answers

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms. Two hours later, the numbers of the two atoms are equal. The half-life of A is 0.77 hours. What is the half-life of B in hours?

Answers

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A)  = N₀(B)

N = N₀ [tex]e^{-\lambda t}[/tex]

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ [tex]e^{-\lambda_1 t}[/tex]

For B

N(B) = N(B)₀ [tex]e^{-\lambda_2 t}[/tex]

N(A) = N(B) , for t = 2 h

N(A)₀ [tex]e^{-\lambda_1 t}[/tex] = N(B)₀ [tex]e^{-\lambda_2 t}[/tex]

N(A)₀ [tex]e^{-\lambda_1 t}[/tex] = 5 x N₀(A)  [tex]e^{-\lambda_2 t}[/tex]

[tex]e^{-\lambda_1 t}[/tex] = 5  [tex]e^{-\lambda_2 t}[/tex]

[tex]e^{\lambda_2 t}[/tex] = 5  [tex]e^{\lambda_1 t}[/tex]

half life = .693 / λ

For A

.77 =  .693 / λ₁

λ₁ = .9 h⁻¹

[tex]e^{\lambda_2 t}[/tex] = 5  [tex]e^{\lambda_1 t}[/tex]

Putting t = 2 h , λ₁ = .9 h⁻¹

[tex]e^{\lambda_2\times 2}[/tex] = 5  [tex]e^{.9\times 2}[/tex]

[tex]e^{\lambda_2\times 2}[/tex] = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .


What are 3 facts you learned about the periodic table:

Answers

Answer: the rarest element is Francium. J is not on the periodic table. also Dmitri Mendeleev proposed the periodic table.

Explanation: Kinda looked the last one up.

A 6.00 kg object at rest is suddenly broken apart into two fragments by an explosion. The fragment with mass 3.50 kg is moving 24.0m/s to the left. The other fragment is moving _______m/s to the right. Group of answer choices

Answers

Answer: 33.6 m/s

Explanation:

Given

The initial mass of the object is [tex]6\ kg[/tex]

It breaks into two fragments of 3.5 and 2.5 kg

3.5 kg part moves at 24 m/s towards left

Suppose 2.5 kg part moves with a speed of v towards the right

As the center of mass is at rest before the collision, it continues to remain at rest after the collision.

[tex]\therefore 6\times 0=3.5\times 24-2.5\times v\\\Rightarrow 3.5\times 24=2.5\times v\\\\\Rightarrow v=33.6\ m/s[/tex]

Therefore, the velocity of 2.5 kg mass is 33.6 m/s towards right.

а)
In figure below, assume that a 20-mm-diameter rivet joins the plates that are each 110 mm
wide. The allowable stresses are 120 MPa for bearing in the plate material and 60 MPa for
shearing of rivet. Find the followings. Express your final answer in N/mm².
110 mm
20-mm
P
(1) Determine the minimum thickness of each plate and largest average tensile stress in the
plates.
(6 marks)

Answers

Image of the plate is missing, so i have attached it.

Answer:

A) t = 7.854 mm

B) σ = 26.67 MPa

Explanation:

A) From shearing of rivet, formula for pressure is;

P = τ•A_rivets

Where;

τ is allowable stress

A_rivets is Area of rivet

We are given:

τ = 60 MPa

Diameter; d = 20 mm

A_rivets = πd²/4 = π × 20²/4 = 100π

Thus;

P = 60 × 100π

P = 6000π N

From bearing of plate material, we can calculate pressure as;

P = σ_b•A_b

We are given;

σ_b = 120 MPa

A_b is area of plate = 20t

Where t is the thickness

Thus;

6000π = 120 × 20t

t = 6000π/(120 × 20)

t = 7.854 mm

B) Largest average tensile stress is given by the formula;

σ = P/A

Where A = 110t - 20t

A = 90t

A = 90 × 7.854

Thus;

σ = 6000π/(90 × 7.854)

σ = 26.67 MPa

What is the term for the force that holds protons and neutrons together in the nucleus of
an atom?
a electromagnetism
b. gravity
c. the strong force
d the weak force

Answers

Protons and neutrons are held together in a nucleus of an atom by the strong force. C hope this helped!
C is the answer I took the test

Does the law of attraction actually have a basis in physics?

Answers

Answer:

Scientific theories are cited by proponents of the Law of Attraction as evidence in its favor. It, on the other hand, has no theoretical basis. A variety of scientists have questioned the promoters' abuse of scientific principles.

a particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity​

Answers

Answer:

vi =2

Explanation:

Δx = 1/2 (vi + vf) t

10 = 1/2 ( vi + 8 ) 2

10 = vi + 8

10-8 = vi

vi = 2 m/s

vi= initial velocity

vf= final velocity

Δx= distance

t= time

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