Answer:
480 hoursSolution,
Time taken by 1 worker to complete the project= 2880 hours
Time taken by 12 workers to complete the project:
[tex] \frac{2880}{12} \\ = 480 \: hours[/tex]
Hope this helps ...
Good luck on your assignment...
Answer:
480
Explanation:
types of educational planning
Answer:
the correct answer is
1.Administrative Planning: Generally speaking Administrative planning refers to planning in administrative perspective.
2. Academic or curricular planning.
3. Co-curricular planning.
4. Instructional planning
5. Institutional planning.
Explanation:
hope this works out!!
what is industrialization
Answer:
idustry is your main source of economic gain in you country
You overhear your assistant teacher telling one of the children that If they do not clean up they will not get any lunch. You have already told this teacher, two days ago, that food may not be used for discipline. What do you do now?
Answer:
Fire her as
Explanation:
Problem solved
(I'm going to school to become a teacher)
The tangent line to the graph of y=g(x) at x=4 has equation y=-3x+11. What is the equation of the tangent line to the graph of y=g(x)^3 at x=4? Need correct answer and explanation as soon as possible! Will give brainliest!
Answer:
The equation of the tangent of g(x)^3 at x = 4 is y = 3 - x
Explanation:
The tangent of y = g(x) = -3·x + 11
Therefore, the slope of g(x) = 1/3
The value of y = -3*4 + 11 = -1
The equation of the line g(x) is given as follows;
y - 1 = 1/3*(x - 4)
y - 1 = 1/3x - 4/3
y = 1/3x - 4/3 + 1 = 1/3x - 1/3
g(x) = 1/3x - 1/3
g(x)^3 = (1/3x - 1/3)^3 = [tex]\dfrac{x^3 -3\cdot x^2 + 3 \cdot x - 1}{27}[/tex]
The slope is therefore;
[tex]\dfrac{\mathrm{d} g(x)^{3}}{\mathrm{d} x} = \dfrac{27 \cdot (3 \cdot x^2 -6\cdot x +3 )}{729}[/tex]
The slope of the tangent is the negative reciprocal of the slope of the line which gives;
[tex]Slope \ of \ tangent \ of \ g(x)^3= -\dfrac{729}{27 \cdot (3 \cdot x^2 -6\cdot x +3 )} = -\dfrac{9}{x^2 -2\cdot x + 1}[/tex]
The value of the slope at x = 4 is [tex]-\dfrac{9}{4^2 -2\cdot 4 + 1} = \dfrac{-9}{9} = -1[/tex]
Therefore, we have;
y at x = 4
[tex]y = \dfrac{4^3 -3\cdot 4^2 + 3 \cdot 4 - 1}{27} = \dfrac{27}{27} = 1[/tex]
Therefore, the equation of the tangent is given as follows;
y - 1 =(-1) × (x - 4) = 4 - x
y = 4 - 1 - x = 3 - x
The equation of the tangent of g(x)^3 at x = 4 is y = 3 - x.