Answer:
Plasma is by far the most common form of matter. Plasma in the stars and in the tenuous space between them makes up over 99% of the visible universe and perhaps most of that which is not visible. On earth we live upon an island of "ordinary" matter.
why dont feel the earth rising up as we throw a stone upwards and falling down?
Answer:Because, first, the atmosphere is moving with the Earth’s Surface. Secondly, although you might aim straight up, you, the stone and the Earth’s surface are moving at up to about 1000mph depending on how close to the equator you are. So you throw the stone upwards at a few metres per second, but it also has the same horizontal momentum as you and the Earth’s surface, up to 400m/sec. So if you threw it up exactly vertical, it will come down nearly on top of you, unless there is a local wind blowing, in which case it might miss by a few feet.
Try throwing a stone sideways from a moving car. Aim at a tree you are passing. The stone will land a long way from the tree somewhere near 90° from your car. Because you have imparted two vectors of motion to it. One sideways from your throw, and one forwards equal to the speed of the car.
A skateboarder rides swiftly up the edge of a bowl-shaped surface and leaps into the air. While in the air, the skateboarder flips upside and tosses the skateboard from hand to hand. The skateboarder then rides safely back down the bowl. During the time that the skateboarder and skateboard are not touching anything, one aspect of their motion that is constant is their total (or combined) [note: neglect any effects due to the air]
a. angular momentum.
b. angular velocity.
c. velocity.
d. momentum.
Answer:
Option(a) is the correct answer to the given question .
Explanation:
The main objective of the angular momentum is evaluating however much the rotational movement as well as the angular velocity in the entity does have.The angular momentum is measured in terms of [tex]kgm^{2 }\ / s[/tex].
In the given question the skateboarder rides quickly up the bottom of a bowl-shaped surface and climb into the air.it means it is rotational movement also it is not touching anything so it is angular momentum.All the other option is incorrect because it is not follows the given scenarioJorge camina en línea recta por una plaza, cruzándola de forma diagonal, recorriendo 60 m en 3 min. A partir de esta situación, responde: a) ¿Cuál es la distancia que recorre? b) ¿Cuál es el módulo del desplazamiento? c) ¿Qué valor tendrá su rapidez y el módulo de su velocidad?
Answer:
a) d = 60m (distance)
b) D = 60m (displacement)
c) v = 20 m/min
d) |v| = 20 m/min
Explanation:
a) The distance traveled by Jorge is 60m
d = 60m
b) The module of the displacement D, is equal to the values of the distance d, because Jorge walked in a straight line.
D = d = 60m
c) The speed of Jorge is given by the following formula:
[tex]v=\frac{d}{t}[/tex]
d: distance = 60m
t: time of the walk = 3min
[tex]v=\frac{60m}{3min}=20\frac{m}{min}[/tex]
The speed is 20 m/min
The module of the Jorge's velocity is:
[tex]|v|=\frac{D}{t}[/tex]
D: displacement = d = 60m
t: time = 3 min
[tex]|v|=\frac{60m}{3min}=20\frac{m}{min}[/tex]
The module of Jorge's velocity is 20 m/min
Jorge recorre una distancia de 60 m en 3 min. Su desplazamiento de 60 m, lo hace con una rapidez, y módulo de su velocidad, de 20 m/min.
Jorge camina en linea recta por una plaza recorriendo 60 metros en 3 minutos (t).
La distancia recorrida (d) es 60 m.
Como se mueve en linea recta, el desplazamiento (D) coincide con la distancia recorrida, es decir, es de 60 m.
Podemos calcular la rapidez (s) de Jorge usando la siguiente fórmula.
[tex]s = \frac{d}{t} = \frac{60m}{3min} = 20m/min[/tex]
La rapidez es una magnitud escalar y coincide con el modulo de la velocidad, dado que la velocidad es vectorial.
Jorge recorre una distancia de 60 m en 3 min. Su desplazamiento de 60 m, lo hace con una rapidez, y módulo de su velocidad, de 20 m/min.
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Part II # 1 A mass on a string of unknown length oscillates as a pendulum with a period of 4 sec. What is the period if: (Parts (1-4 are independent questions, each referring to the initial situation.) 1) The mass is doubled? 2) The string length is doubled? 3) The string length is halved? 4) The amplitude is halved? A. 1) No Change (4 sec) 2) 2.8 sec 3) 5.7 sec 4) No Change (4 sec) B. 1) 5.7 sec 2) No Change (4 sec) 3) 2.8 sec 4) No Change (4 sec) C. 1) No Change (4 sec) 2) 5.7 sec 3) 2.8 sec 4) No Change (4 sec) D. 1) 5.7 sec 2) No Change (4 sec) 3) No Change (4 sec) 4) 2.8 sec
Answer:
C. 1) No Change (4 sec) 2) 5.7 sec 3) 2.8 sec 4) No Change (4 sec)
Explanation:
Given that:
Period (T) = 4 s
1) If the mass is doubled.
The period of a pendulum is given by the formula:
[tex]T=2\pi\sqrt{\frac{L}{g} }[/tex] where L is the length and g is the acceleration due to gravity.
From the formula, the period does not depend on the mass of the spring therefore if the mass is doubled the period does not change.
2) The string length is doubled
Given that:
[tex]T=2\pi\sqrt{\frac{L}{g} }, but\ T =4s\\4=2\pi\sqrt{\frac{L}{g} }[/tex]
if the length is doubled, the new spring length is 2L. Therefore the new period (T1) is given as:
[tex]T_1=2\pi\sqrt{\frac{2L}{g} }=\sqrt{2} (2\pi\sqrt{\frac{L}{g} })=\sqrt{2}*4=5.7\ sec[/tex]
3) The string length is halved
Given that:
[tex]T=2\pi\sqrt{\frac{L}{g} }, but\ T =4s\\4=2\pi\sqrt{\frac{L}{g} }[/tex]
if the length is halved, the new spring length is L/2. Therefore the new period (T1) is given as:
[tex]T_1=2\pi\sqrt{\frac{L}{2g} }=\sqrt{1/2} (2\pi\sqrt{\frac{L}{g} })=\sqrt{1/2}*4=2.8\ sec[/tex]
4) The amplitude is halved
From the formula, the period does not depend on the amplitude therefore if the amplitude is halved the period does not change.
A frog jumps to the left with an average speed of 1.8\,\dfrac{\text m}{\text s}1.8 s m 1, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, end fractionfor 0.55\,\text s0.55s0, point, 55, start text, s, end text. What was the frog's displacement in meters
Complete Question
A frog jumps to the left with an average speed of 1.8m/s for 0.55s What was the frog's displacement in meters.
Answer:
The displacement is [tex]d = -0.99 \ m[/tex]
Explanation:
From the question we are told that
The average speed is [tex]v = -1.8 \ m/s[/tex]
The negative sign indicates that the frog jumped to the left (negative x-axis )
The time taken is [tex]t = 0.55 \ s[/tex]
Generally displacement is mathematically represented as
[tex]d = v * t[/tex]
[tex]d = -1.8 * 0.55[/tex]
[tex]d = -0.99 \ m[/tex]
Which actions most likely cause the domains in a ferromagnetic material to align? Check all that apply. heating the material rubbing the material against a magnet passing electricity around the material placing the material in a magnetic field of opposite polarity placing the material near a strong magnet hitting the material
Answer:
i. rubbing the material against a magnet
ii. placing the material in a magnetic field of opposite polarity
iii. placing the material near a strong magnet
Explanation:
Ferromagnetic materials are majorly metals which can be easily attracted by a magnet. ferromagnetic materials are made up of domains, behaves as minute pieces of magnet. They can be rearranged to align when under the influence of an external magnetic field.
The alignment of the domains in a ferromagnetic material can be caused by either of the following: rubbing the material against a magnet, placing the material in a magnetic field of opposite polarity, placing the material near a strong magnet.
Answer:
B, D, E
Explanation:
edg2020
Three charges are located at the vertices of a triangle, as
shown.
Which vector best represents the net force acting on the
+4 C charge in the diagram?
+5 C
X
OW
Ο Χ
OY
OZ
+4 C
W+
Z
+10 C
Answer:
B. X is the answer, hope it helps
Explanation:
X vector best represents the net force acting on the +4C charge in the diagram. Therefore, the correct option is option B.
What is force?A force in physics is an effect that changes the velocity, or acceleration, of a mass-moving object. It is a vector quantity since it can be a pushing or a pull and always has magnitude and direction. It is denoted by the letter F and is measured in newtons (N), the SI unit of force.
The net force acting on an object being equal to the rate where its momentum varies over time, according to Newton's second law in its original formulation. This law suggests that now the acceleration that an object experiences being directly correlated with the total force exerted on the object. X vector best represents the net force acting on the +4C charge in the diagram.
Therefore, the correct option is option B.
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Show all work and answer all 4 parts. Projectile motion. 20 points. Thank you.
Answer:
(i have corrected the answers to 3 significant figures)
When dealing with projectile motion, we should consider its vertical and horizontal components.
Vertical velocity = 50sin60° m/s
Horizontal velocity = 50cos60° m/s
a) when it reaches the peak, meaning it can no longer travel further upwards, indicating the final vertical velocity is 0.
Take g=9.80665
using formula a = (v-u) /t
9.80665= (0-50sin60°) / t
t= 4.42 s
b) Consider the vertical component.
using formula t = 2u / g
t = 2(50sin60°) / 9.80665
t = 8.83s
c) Consider the vertical component again,
using formula H = u² / 2g
H = (50sin60°)² / 2(9.80665)
H = 95.6m
d) This is also the range of the projectile motion.
Using formula R = u²sin2θ / g
This time u should just be the initial velocity (neither horizontal/vertical)
R = 50²sin2(60) / 9.80665
= 221 m
- you can also do this by using s = ut formula, using the time calculated from b), but consider the u as the horizontal component.
Un cuerpo de masa m. Tiene una velocidad V. Si la masa del cuerpo se incrementa al triple de su valor original y la velocidad se mantiene constante en dirección y sentido, pero su módulo aumenta al cuádruplo de su valor original, en tal caso la razón entre el tamaño del momentum inicial P2 y el tamaño del momentum final P1 es:
Answer: El momento final es 12 veces el momento inicial.
Explanation:
El momento es definido como la cantidad de movimiento, y la ecuación es:
P1 = m*V
donde m es masa y V es velocidad
Si este es el momento inicial de nuestro objeto, y ahora la masa se triplica y la velocidad se cuadriplica (en modulo) el nuevo momento es:
P2 = (3*m)*(4*V) = 3*4*m*V = 12*m*V
Entonces la razón entre los momentos es:
P2/P1 = 12m*V/(m*V) = 12
Two particles having charges of 0.50~\text{nC}0.50 nC (q_1q 1 ) and 10~\text{nC}10 nC (q_2q 2 ) are separated by a distance of 3~\text{m}3 m (r = 3~\text{m}r=3 m). At what distance away from charge q1 along the line connecting the two charges can a third positive charge be placed such that it experiences a net electric force equal to zero?
Answer:
The third charge must be placed 0.548 m from q₁.
Explanation:
Let r = 3m be the distance between charge q₁ and q₂.
Let x be the distance between charge q₁ and charge q₃ (the third positive charge)
Then r - x is the distance between charge q₂ and q₃
Let the electrostatic force between q₁ and q₃ be F = kq₁q₃/x²
Let the electrostatic force between q₂ and q₃ be F' = kq₂q₃/(r - x)²
Since F + (-F') = 0 (the signs on the forces are different since the forces are in opposite directions)which is required when the net force on q₃ is zero, then
F - F' = 0
F = F'
So, kq₁q₃/x² = kq₂q₃/(r - x)²
q₁/x² = q₂/(r - x)²
[(r - x)/x]² = q₂/q₁
taking square-root of both sides,
(r - x)/x = ±√q₂/q₁
r/x - 1 = ±√q₂/q₁
r/x = 1 ±√q₂/q₁
x = r/(1 ±√q₂/q₁)
substituting the values of the variables r = 3 m, q₁ = 0.50 nC and q₂ = 10 nC
x = 3 m/(1 ±√10 nC/0.5 nC)
x = 3 m/(1 ±√20)
x = 3 m/(1 ± 4.472)
x = 3 m/5.472 or 3 m/-3.472
x = 0.548 m or -0.864 m
So the third charge must be placed 0.548 m to the right of q₁ or 0.864 m to the left of q₁.
Since we are concerned about the line of charge that connects q₁ and q₂, the third charge must be placed 0.548 m from q₁.
What happens to a hockey puck when a net force of 5 N acts on it? a It accelerates. b It remains at rest. c It increases in mass. d It moves at a constant speed.
Answer:
I think it is A
Explanation:
a student pushed a 100 N bicycle over a distance of 15 m in 5 s. calculate the power generated.
The catch in this one is: We don't know how much force the student used to push the bike.
It wasn't necessarily the 100N. That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium. The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push. That's what's so great about wheels ! That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel". I looked at it, I turned it over and I looked on all sides. I thought it was too simple. I didn't know then it was elegant. I threw him out. I was so dumb. I could have invested money in that guy, today I would have probably more than a hundred dollars.
Anyway, can we figure out how much force the student used to push with ? Stay tuned:
-- The bike covered 15 meters in 5 seconds. Its average speed during the whole push was (15m/5s) = 3 meters/sec.
-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.
-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²
-- The bike's weight is 100N.
(mass) x (gravity) = 100N
Bikemass = (100N) / (9.8 m/s²)
Bikemass = 10.2 kilograms
-- F = m A
Force = (mass) x (acceleration)
Force = (10.2 kg) x (1.2 m/s²)
Force = 12.24 N
-- Work = (force) x (distance)
Work = (12.24 N) x (15 m)
Work = 183.67 Joules
-- Power = (work done) / (time to do the work)
Power = (183.67 joules) / (5 seconds)
Power = 36.73 watts
If the phase of the vibrating sources was changed so that they were vibrating completely out of phase, what effect would this have on the interference pattern?
Answer:
There would be complete destructive interference.
Explanation:
This is because since the waves are completely out of phase, the phase difference is half wavelength, that is the phase angle is 180°. The vibrating sources are 180° out of phase with each other.
Since this is the case, the crest of the one source meets the trough of the other, this causes the resultant vibrational wave to cancel out, thus producing a destructive interference pattern.
Since the vibrating sources are completely out of phase, every point they meet is completely out of phase, so the resultant interference pattern would produce a complete destructive interference pattern of no wave.
Study the scenario. The particles in some system are moving around quickly. A few minutes later, the particles are moving, on average, more slowly. How does this change in motion affect the temperature of the system? A. The temperature of the system did not change. The speed of the particles has no effect on the temperature, only the type of atom affects the temperature. B. The temperature of the system is higher now than it was initially. Slower moving particles result in a higher temperature for the system. C. The temperature of the system did not change. The speed of the particles does not affect temperature, the number of particles affects the temperature. D. The temperature of the system is lower now than it was initially. Faster moving particles result in a higher temperature for the system.
Answer:
The correct answer is option D.
Explanation:
With an increase in temperature, the particles increase kinetic energy and move quicker. The normal speed of the particles relies upon their mass just as the temperature – heavier particles move more gradually than lighter ones at a similar temperature.
The temperature increase in this system since the average kinetic energy of the particles increases and particles move quickly. And after some time the temperature of the system is lower now than it was initially.
Thus, the correct answer is option D.
The impact of the change in motion should be option D.
Impact on the temperature:In the case when there is an increase in temperature, the particles should increase kinetic energy and move faster. The normal speed of the particles believes their mass is like the temperature. The temperature rises in this system because the average kinetic energy of the particles should rised and particles move faster.
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Briefly discuss:
(i) The principles of detecting thermal neutrons utilizing a Si detector.
(ii) The physics of fast neutron detection.
(iii) The principle of operation of strip detectors for charged particle detection and
their application.
Answer:
(i) Si device are coated with B or Li for neutron detection
(ii) Fast neutrons are normally first slowed down to thermal energies before measurement
(iii) The strip detectors consists of p⁺ and n implants in the region of a very thin (300 to 400 μm) depletion zone though which the neutrons traverse producing a readout based on the generated charges being directed to the cathode, p⁺, material which then transmits the charge to the device electronics
Explanation:
(i) Detection of neurons with only an Si device in not possible due to the large neutrons path in Si such that the silicon needs to be coated with B or Li which readily interact with neutrons. The neutron interaction with the reactive coating produces an alpha particle which can be detected by the semi conductor and a nucleus
(ii) Neutrons having a kinetic energy that is more than 1 MeV which as such has a velocity of more than 15,000 km/s is known as fast neutrons or fission neutrons. The fast neutrons are slowed in a nuclear reactor by neutron moderation to thermal energies
Due their high speed, fast neutrons are normally slowed down which however results in the loss of some vector properties of the neutron
Techniques for fast neutron detection includes,
1) Recoil detectors which are capable of fast neutron detection without moderation
2) Bonner spheres detector first converts the fast moving electron to slow down before detection
3) Scintillation counter are widely used but require the conversion of the neutron to a charged particles before detection
(iii) Strip detectors provide high precision measurement of a particle's crossing point which can be further improved by use of low noise electronics
Applications of silicon strip detectors include
1) Particle tracking in research in particle physics
2) Particle tracking in researches in x-spectroscopy nuclear research
3) Imaging in x-talography
4) Medical research imaging
5) Particle tracking and imaging in astrophysics.
Even after the body stops moving in a collision, the internal organs are still moving.
Answer:
True
Explanation:
The bodies internal organs move around, even after a collision that may impact your skeletal system.
When a collision occurs and the body comes to a sudden stop, the internal organs can continue to move due to their inertia. Yes, that statement is generally true.
Inertia is the property of an object that resists changes in its state of motion. The internal organs of the body, such as the heart, lungs, liver, and others, are not directly attached to the skeletal structure and are instead supported by connective tissues and surrounded by fluids.
During a collision, the body experiences a rapid deceleration or change in velocity. While the external motion of the body may come to a stop, the internal organs, due to their inertia, continue to move forward momentarily until they are acted upon by internal forces. This phenomenon is known as "organ motion" or "organ inertia."
In situations where high-impact collisions occur, such as in car accidents or contact sports, the continued motion of internal organs can result in serious injuries, even when external signs of trauma may be minimal.
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Yeah Physics!!!! I will give Brainliest to whoever can solve this question!!!
If i workout 90 minutes on earth, if I am on a rocket traveling 0.80c, according to the timer on the rocket, how long should I exercise?
Answer:
The person should exercise 150 minutes
Explanation:
Recall that the Lorentz factor must be applied to the relationship between the elapsed time (T) of the clock at rest (time measured on Earth), and the elapsed time (T') measured by the clock in the frame moving at 0.8 c. The equation becomes:
[tex]T'=\frac{T}{\sqrt{1-(\frac{0.8\,c}{c})^2 } } \\T'=\frac{90\,min}{\sqrt{1-0.8^2} } \\T'=150\,\,min[/tex]
As a motorcycle takes a sharp turn, the type of motion that occurs is called _______________ motion.
Answer:
circular motion
Explanation:
As a motorcycle takes a sharp turn, the type of motion that occurs is called circular motion.
Circular motion is a movement of an object along a circular path. As this motorcycle makes the sharp turn, it is acted upon by a centripetal force which directs the motorcycle towards the center.
Therefore, circular motion is the correct answer to the question.
Answer:
Circular Motion
Madison applied a force of 150 N in a horizontal direction to a sleigh. Meanwhile the sleigh slid 30.0 m across a level surface of snow. The work done on the sleigh by Madison is _________ J.
Answer:
4500 joules
Explanation:
since work(joules) = force(newtons) x distance(meters),
150N x 30M = 4500 Joules
Answer:
4500 joules
Explanation:
150 N x 30 M = 4500 joules
A shower has a power of 10kw. A family uses the shower for 1 hour per day calculate how much energy, in kilowatt hours, they would have to pay for each week for using the shower. An electricity company charges 10p for each kwh calculate the cost in pounds
Answer:
70p per week
Explanation:
Power * time = energy
1 kw * 1 hour = 1 kwh per day
For 7 days,
Energy used = 1 kwH/day * 7 days = 7kwh
Total cost per week = 7 kwh * 10p
= 70p
I NEEED HELP!!!!! Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern.
Do this using three different methods.
The angle to the eighth maximum is 1.12°.
The distance from the slits to the screen is 302.0 cm.
The distance from the central maximum to the fifth minimum is 3.33cm.
The distance between the slits is 0.000250 m
Answer:
The wavelength is approximately 611 nm
Explanation:
We can use the formula for the condition of maximum of interference given by:
[tex]d\,sin(\theta)=m\,\lambda\\(0.000250\,\,m)\,\,sin(1.12^o)=8\,\lambda\\\lambda=\frac{1}{8} \,(0.000250\,\,m)\,\,sin(1.12^o)\\\lambda \approx 610.8\,\,nm[/tex]
We can also use the formula for the distance from the central maximum to the 5th minimum by first finding the tangent of the angle to that fifth minimum:
[tex]tan(\theta)=\frac{y}{D}\\ tan(\theta)=\frac{0.0333}{3.02} =0.011026[/tex]
and now using it in the general formula for minimum:
[tex]d\,sin(\theta)\approx d\,tan(\theta)=(m-\frac{1}{2} )\,\lambda\\\lambda\approx 0.00025\,(0.011026)/(4.5)\,\,m\\\lambda\approx 612.55\,\,nm[/tex]
Answer:
The correct answer is [tex]6.1\times10^{-7}\:m[/tex]
Explanation:
The distance from the central maxima to 5th minimum is:
[tex]x_{5n}-x_{0} =3.33\:cm=0.033\:m[/tex]
The distance between the slits and the screen:
[tex]L = 302\:cm = 3.02\:m[/tex]
Distance between 2 slits: [tex]d = 0.00025\:m[/tex]
[tex](n-\frac{1}{2})\lambda=\frac{d(x_n)}{L}[/tex]
For fifth minima, n = 5... so we have:
[tex]x_{5n}=\frac{9\lambda L}{2d}[/tex]
For central maxima, n = 0... so we have:
[tex]x_{0}=\frac{n\lambda L}{d}=0[/tex]
So the distance from central maxima to 5th minimum is:
[tex]\frac{9\lambda \:L}{2d}-0=0.033[/tex] (Putting the values, we get):
[tex]\Rightarrow \lambda = 6.1\times 10^{-7}\:m[/tex]
Best Regards!
In 2000, a 20-year-old astronaut left Earth to explore the galaxy; her spaceship travels at 2.5 x 10^8 m/s. She returns in 2040. About how old will she appear to be?
Answer:
42.11 years old
Explanation:
Given that:
In 2000, a 20-year-old astronaut left Earth to explore the galaxy; her spaceship travels at 2.5 x 10^8 m/s. She returns in 2040
To find her age we use:
[tex]\Delta t_m=\frac{\Delta t_s}{\sqrt{1-\frac{v^2}{c^2} } }\\[/tex]
Δtm is time interval for the observer stationary relative to the sequence of
events = 2040 - 2000 = 40 years
Δts is is the time interval for an observer moving with a speed v relative to the sequence of event
v = velocity = 2.5 x 10^8 m/s
c = speed of light = 3 x 10^8 m/s
[tex]\Delta t_s=\Delta t_m}{\sqrt{1-\frac{v^2}{c^2} } }\\\Delta t_s=40\sqrt{1-\frac{(2.5*10^8)^2}{(3*10^8)^2}}\\\Delta t_s=22.11\ yr[/tex]
Here age in 2000 is 20 year, therefore when she appear she would be 20 year + 22.11 year = 42.11 years old
the value of MA in the third class lever is alaways less than one,why
Answer:
It is always less than 1 because the load arm is always longer than effort arm.
Explanation:
In the formula, MA= effort divided by load which makes it less than 1.
This helps by reducing the applied force(effort). It is a speed multiplier.
Hope it helps.
Why is it that when I ask a physics question, literally NO ONE answers. Like I thought that this was a site where al answers were answers. Its so frustrating!!!!! I bet no one will look at this because it says physics.
Answer:
ooof mood
Explanation:
Answer:
i kinda like physics.
Explanation:
Dan's plant will require two shifts of skilled workers, seven days a week. As he does his research, he
will pay particular attention to
A. the labor market.
B. regulatory restrictions.
C. performance measures.
D. his target market.
Answer:
the labor market.
Explanation:
Dan's plant will require two shifts of skilled workers, seven days a week. As he does his research, he will pay particular attention to the labor market.
21. When air is blown into a balloon, it expands equally in all directions. The best explanation for this is (circle the correct answer): A - The gas molecules in the balloon are expanding B - Internal air pressure acts at right angles to the balloon surface. C - As more air is blown in, the temperature increases causing the balloon to expand.
Answer:
C
Explanation:
I would have said B but air pressure acts at ALL angles(directions). C makes sense because the increase in the temperature would cause the molecules to bounce off the walls of the balloon and each other which exerts pressure.
Answer:
C c hagwguawnjaahwbhanwbhsqn2nusbwvwf
A 7.00 g bullet, when fired from a gun into a 1.00 kg block of wood held in a vise, penetrates the block to a depth of 8.00 cm before stopping due to the frictional force between the wood and bullet. This block of wood is next placed on a friction-less horizontal surface, and a second 7.00-g bullet is fired from the gun into the block. To what depth will the bullet penetrate the block in this case
Answer:
Explanation:
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Given the resistivities below, which matedal is best described as an insulator?
O A. 4.5 Ω•m
O B. 2.8 x 10-8 Ω•m
O c. 3.2 x 108 Ω•m
O D. 1.7 x 10-8 Ω•m
Answer:
C. 3.2 x 10^8 Ω•m
Explanation:
An insulator is a material that resists the flow of electricity.
In the given data the material with the highest resistivity is the best insulator
3.2 x 10^8 Ω•m
PLEASE HELP!!!! Look at the circuit diagram. What type of circuit is shown? A. Closed series circuit B. Closed parallel circuit C. Open parallel circuit D. Open series circuit
Answer:
A. Closed Series Circuit
Explanation:
Let's dissect the image. Just a heads up, I'm going to use a few of street/road analogies here. Think of the current as cars/people, the circuit path as streets/roads, and the resistors(in the bulbs) are like speed bumps.
We have arrows dictating the direction of the current caused by the battery. If the circuit were open, it'd be as though we had a gap in a road so that no cars/people could go through. But because we have a current, that indicates that the circuit is closed.Next there's the question of the whether the resistors are in series or parallel. In simple cases like this, ask yourself if the resistors are on the same "street" or not. By that I mean, can you follow one line of current without breaking off to a different path? Here, it looks like the two resistors/bulbs are in series because they are on the same path.So what you're looking at is a closed series circuit.
An electron moving with a velocity of 5 × 104 m s -1 enters into a uniform electric field and acquires a uniform acceleration of 104 m s -2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this tim
Answer:
(i) t = 5s
(ii) x = 3.75*10^5 m
Explanation:
(i) To calculate the time that the electron takes to reach twice the value of its initial velocity, you use the following formula:
[tex]v=v_o+at[/tex] (1)
vo: initial velocity of the electron = 5*10^4 m/s
v: final velocity of the electron = 2vo = 1*10^5 m/s
a: acceleration of the electron = 1*10^4 m/s^2
You solve the equation (1) for t, and replace the values of the parameters:
[tex]t=\frac{v-v_o}{a}=\frac{1*10^5m/s-5*10^4m/s}{1*10^4m/s^2}=5s[/tex]
The electron takes 5s to reach twice its initial velocity.
(ii) The distance traveled by the electron in such a time is:
[tex]x=v_ot+\frac{1}{2}at^2[/tex] (2)
you replace the values of the parameters in the equation (2):
[tex]x=(5*10^4m/s)(5s)+\frac{1}{2}(1*10^4m/s^2)(5s)^2\\\\x=3.75*10^5m[/tex]
The distance traveled by the electron is 3.75*10^3m/s