(need help asap!!)
if the angle between two forces is smaller, what will happen to it's resultant force? will it be bigger or smaller?

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Hi! I'm a few days late since I just saw this question just now, but I'll answer anyway.

Answer:

When an unbalanced force acts on a moving object, the velocity of the object will change. Change in velocity means a change in speed, direction, or both. For example, if you kick a soccer ball and it moves from one place to another, it means that unbalanced forces are acting upon it. The ball moves from one place to another after kicking it so the position changed.

Answer:

7.8cm

Explanation:

Answer:

7.8

Explanation:

Answer:

The electric current in a wire can deflect a compass needle if its magnetized.

Explanation:

Answer:

i think its a lake

Explanation:

Answer: What do you call a large body of water surrounded by land?

A lake is a large body of water surrounded by land on all sides.

Explanation:

We can substitute the given values into the equation for T, given the surrounding temperature T0 = 0, initial temperature T1 = 140, constant k = -0.0815, and time t = 15 minutes.

T = 0 + (140 - 0)e^(-0.0815*15) = 140e^(-1.2225) = 41.23°F

Answer:

Approximately 11.43

Explanation:

Using the formula charge=current×time

then current=charge/time. That then will be C=96/8.4=11.4285714286 so approximately 11.43

The current would be 825.6 × 10⁻³ amperes if 96 mC of charge passes through a wire in 8.4 seconds .

Due to the physical characteristic of electric charge, charged material experiences a force when it is exposed to an electromagnetic field.

The charge on one electron is -1.6 ×10⁻¹⁹ coulomb.

As given in the problem we have to find the current in ampere if 96 mC of charge passes through a wire in 8.4 seconds ,

9.6 mC =  9.6 × 10 ⁻³ Coulombs

The electric current = electric charge × time period

                                = 9.6 × 10 ⁻³ × 8.6

                                = 825.6 × 10 ⁻³ ampere

Thus, the current would be 825.6 × 10 ⁻³ amperes if 96 mC of charge passes through a wire in 8.4 seconds .

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Answer:

The lines are parallel and the students data is 13

Explanation:

The amount of salt added

Answer:

The right answer is "15.072 m/s".

Explanation:

The given values are:

Radius,

= 12 m

Time,

= 5 m/s

As we know,

⇒ [tex]s=\frac{d}{t}[/tex]

On substituting the given values in the above formula, we get

⇒    [tex]=\frac{2 \pi(12)}{5}[/tex]

⇒    [tex]=\frac{2\times 3.14\times 12}{5}[/tex]

⇒    [tex]=\frac{75.36}{5}[/tex]

⇒    [tex]=15.072 \ m/s[/tex]

Answer:

see below

Explanation:

this is because particles in solids are packed very closely together, thus , the particles collide with each other frequently and thus transfer of energy is faster. however, particles in liquid are closely packed but not as close as in solid so the particles do not collide as frequently. thus, transfer of energy slower than in solid. furthermore, the particles in gas are spaced far apart from each other, thus the particles don't collide with each other frequently, thus transfer of energy is very slow in gas.

hope you get it,

please mark

Answer:

C. 100 J

Explanation:

If the 60 you wrote is the degree (60°)

Work done = forcexcos x distance

W= 100x cos 60 x2

W= 100 J

Answer:

100 J

Explanation:

Work done is the product of force and distance. The distance here is easy; it's just 2 m because it was pulled horizontally. The force, on the other hand, requires some more work, no puns intended!

We know the applied force is at an angle. Since work is parallel to the distance, the force used to calculate work must be parallel to the distance as well. This means we must use the horizontal component of the force. This, consequently, calls for the horizontal component of the angle.

Here, that horizontal component is the cosine of theta, cos θ, because the horizontal component must be adjacent to the angle. We know the angle in this case; θ is 60°. So, to find the component of the force parallel to the floor, we must multiply the total force by cos θ.

Here, θ = 60°, and the total force is 100 N. Therefore, the horizontal force equals 100 N × cos 60°. As for cos 60°, its value is 0.5. This means the horizontal force equals 100 N × cos 60° = 50 N.

From here, the work is that force, those 50 N, times the distance the box was pulled, 2 m. Therefore, work equals 50 N × 2 m = 50 N × m = 50 J.

In summary, the total work done is 50 J.

I hope you understand my explanation! Please have a great day!

Answer:

The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.

Explanation:

Answer:

That  drummer has mechanical energy as he moves the drumsticks to hit the drums and cymbals. So I'm pretty sure it's OD. sound energy.

¯\_(ツ)_/¯¯

Answer:

ac=alternating current

Explanation:

It is what ac or alternating current looks like while traveling.

Answer:

b,c,d,and f are the car traveling at the sane velocity

Answer:

50m/s

Explanation:

Given parameters:

Acceleration  = 5m/s²

Time  = 10s

Unknown:

Final velocity of the puppy  = ?

Solution:

Acceleration is the rate of change of velocity with time taken. The puppy has an initial velocity of 0m/s.

 The formula is:

 Acceleration  = [tex]\frac{Final velocity - Initial velocity }{time}[/tex]  

         5  = [tex]\frac{Final velocity - 0 }{10}[/tex]  

               Final velocity  = 50m/s

Explanation:

first line is the group one element all are group 1 elements

Answer:

False.

Explanation:

A forearm pass is a volleyball movement that involves hitting off the forearms in an underhand manner. To create a forearm stance you'd have to clasp your palm together in an overlapping manner and keep them outstretched away from your torso.

Skilled players are more when to use the wrists, the hands, or the forearms as they wield different strengths in passing the ball and are meant to be used at different scenarios.

The forearm pass is best used when you want to position the ball near the net so the setter can set it.

Cheers

Answer:

We follow here the basics of problem-solving presented earlier in this text, but we emphasize specific strategies that are useful in applying Newton’s laws of motion. Once you identify the physical principles involved in the problem and determine that they include Newton’s laws of motion, you can apply these steps to find a solution. These techniques also reinforce concepts that are useful in many other areas of physics. Many problem-solving strategies are stated outright in the worked examples, so the following techniques should reinforce skills you have already begun to develop.

Explanation:

Answer:

C

Explanation:

To know more head to.

https://phys.org/news/2015-12-big-theory.html

Answer:

i think a and c

Explanation:

Answer:

Position A/Position E

[tex]K = E[/tex], [tex]U = 0[/tex]

Position B/Position D

[tex]K = (1-x)\cdot E[/tex], [tex]U = x\cdot E[/tex], for [tex]0 < x < 1[/tex]

Position C

[tex]K = 0[/tex], [tex]U = E[/tex]

Explanation:

Let suppose that ball-Earth system represents a conservative system. By Principle of Energy Conservation, total energy ([tex]E[/tex]) is the sum of gravitational potential energy ([tex]U[/tex]) and translational kinetic energy ([tex]K[/tex]), all measured in joules. In addition, gravitational potential energy is directly proportional to height ([tex]h[/tex]) and translational kinetic energy is directly proportional to the square of velocity.

Besides, gravitational potential energy is increased at the expense of translational kinetric energy. Then, relative amounts at each position are described below:

Position A/Position E

[tex]K = E[/tex], [tex]U = 0[/tex]

Position B/Position D

[tex]K = (1-x)\cdot E[/tex], [tex]U = x\cdot E[/tex], for [tex]0 < x < 1[/tex]

Position C

[tex]K = 0[/tex], [tex]U = E[/tex]

Answer:

Right

Explanation:

75kg soccer player runs rightward with a velocity of +1.5 m/s toward a 0.43 kg soccer ball at rest on the grass. If the final speed of the soccer ball is +15 m/s, ...

Answer:

When the time of fall is doubled, the height of fall will be quadrupled

Explanation:

Given;

height of fall, h = d m

time of fall, t = t s

initial velocity of the object, u = 0 m/d

The height of fall of the object is calculated from the kinematic equation below;

[tex]h = ut + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\2h = gt^2\\\\g = \frac{2h}{t^2}[/tex]

where;

g is acceleration due to gravity, which is constant

if the time of fall is doubled, the height of fall is calculated as;

[tex]\frac{2h_1}{t_1^2} = \frac{2h_2}{t_2^2} \\\\\frac{h_1}{t_1^2} = \frac{h_2}{t_2^2}\\\\(Note: h_1 = d, \ and \ t_1 = t)\\\\h_2 = \frac{h_1t_2^2}{t_1^2} \\\\h_2 = \frac{(d)(2t_1)^2}{t_1^2} \\\\h_2 = \frac{(d)(2t)^2}{t^2}\\\\h_2 = \frac{(d)\times 4t^2}{t^2}\\\\h_2 = 4d[/tex]

Therefore, when the time of fall is doubled, the height of fall will be quadrupled

Answer:

Explanation:

Clean Energy Source It generates more than 800 billion kilowatt hours of electricity each year and produces more than half of the nation's emissions-free electricity. This avoids more than 470 million metric tons of carbon each year, which is the equivalent of removing 100 million cars off of the road.

If I'm wrong I'm sorry

If I'm right thank you and (brainliest plz)

Answer:

vestigial structure

Homologous structure

Explanation:

Did the assignment.

Tetra fish that live in caves are blind and have small eyes that do not work. This is an example of a vestigial structure.

A harbour seal's flipper and a human hand have a very similar structure, but function differently. This is an example of a Homologous structure.

Some organisms have elements that seem to be left over from an earlier ancestor but have no apparent purpose. For instance, because they are evolved from reptiles with legs, certain snakes have pelvic bones despite not having any. The human vermiform appendix is another instance of a structure that serves no purpose.

Vestigial structures are these inactive, purposeless structures. Other examples of vestigial structures are the wings of flightless animals like the ostrich, the leaves of some cacti, the remains of whale pelvic bones, and the eyes that are blind in cave mammals.

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