In a Rankine cycle, steam at 6.89 MPa, 516 degree Celsius enters the turbine with an initial velocity of 30.48 m/s and leaves at 20.68 kPa with a velocity of 91.44 m/s. Mass flow rate of the steam is 136,078 kg/hr.
At 6.89 MPa and 516 degree Celsius:
H = 3451.16 kJ/kg S = 6.86 kJ/kg-K
At 20.68 kPa:
Hv = 2610.21 kJ/kg Hl = 254.43 kJ/kg
Sv = 7.9 kJ/kg-K Sl = 0.841 kJ/kg-K
Vv = 7.41 m3 /kg Vl = 1.02x10-3 m3 /kg
1.) Compute the thermal efficiency of the cycle
a.) 41%
b.) 37%
c.) 22%
d.) 53%
2.) What is the net power produced in hp?
a.) 60000 hp
b.) 40000 hp
c.) 50000 hp
d.) 30000 hp

Answers

Answer 1

1.) The thermal efficiency of the cycle is approximately 74%.

2.) The net power produced in hp is approximately 1,600,000 hp.

1.) To calculate the thermal efficiency of the Rankine cycle, we need to determine the heat input and the net work output. The heat input can be calculated using the enthalpy values at the high-pressure and high-temperature state, and the net work output can be determined by subtracting the enthalpy values at the low-pressure state. By dividing the net work output by the heat input, we can determine the thermal efficiency, which is approximately 74% in this case.

2.) The net power produced in hp can be calculated by multiplying the mass flow rate of the steam by the specific volume difference between the high-pressure and low-pressure states and then converting it to horsepower. The net power produced is approximately 1,600,000 hp.

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Related Questions

Which of the followings is true? Given an RC circuit: resistor-capacitor C in series. The output voltage is measured across C, an input voltage supplies power to this circuit. For the transfer function of the RC circuit with respect to input voltage: O A. Its phase response is -90 degrees. O B. Its phase response is negative. O C. Its phase response is 90 degrees. O D. Its phase response is positive.

Answers

In an RC circuit with a resistor-capacitor in series and the output voltage measured across C while an input voltage supplies power to this circuit, the phase response of the transfer function of the RC circuit with respect to input voltage is -90 degrees.

Hence, the correct answer is option A. A transfer function is a mathematical representation of a system that maps input signals to output signals.The transfer function of an RC circuit refers to the voltage across the capacitor with respect to the input voltage. The transfer function represents the system's response to the input signals.

The transfer function H(s) of the RC circuit with respect to input voltage V(s) is given by the equation where R is the resistance, C is the capacitance, and s is the Laplace operator. In the frequency domain, the transfer function H(jω) is obtained by substituting s = jω where j is the imaginary number and ω is the angular frequency.A phase response refers to the behavior of a system with respect to the input signal's phase angle. The phase response of the transfer function H(jω) for an RC circuit is given by the expression.

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please need answer asap
5 5. An aircraft is moving steadily in the air at a velocity of 330 m/s. Determine the speed of sound and Mach number at (a) 300 K (4 marks) (b) 800 K. (4 marks)

Answers

The speed of sound can be calculated using the equation v = √(γRT), where v is the speed of sound, γ is the adiabatic index (1.4 for air), R is the gas constant (approximately 287 J/kg*K), and T is the temperature in Kelvin.

(a) At 300 K, the speed of sound can be calculated as v = √(1.4 * 287 * 300) = 346.6 m/s. To find the Mach number, we divide the velocity of the aircraft (330 m/s) by the speed of sound: Mach number = 330/346.6 ≈ 0.951.

(b) At 800 K, the speed of sound can be calculated as v = √(1.4 * 287 * 800) = 464.7 m/s. The Mach number is obtained by dividing the velocity of the aircraft (330 m/s) by the speed of sound: Mach number = 330/464.7 ≈ 0.709.

The speed of sound can be calculated using the equation v = √(γRT), where v is the speed of sound, γ is the adiabatic index (1.4 for air), R is the gas constant (approximately 287 J/kg*K), and T is the temperature in Kelvin. For part (a), at a temperature of 300 K, substituting the values into the equation gives v = √(1.4 * 287 * 300) = 346.6 m/s. To find the Mach number, which represents the ratio of the aircraft's velocity to the speed of sound, we divide the given velocity of the aircraft (330 m/s) by the speed of sound: Mach number = 330/346.6 ≈ 0.951. For part (b), at a temperature of 800 K, substituting the values into the equation gives v = √(1.4 * 287 * 800) = 464.7 m/s. The Mach number is obtained by dividing the given velocity of the aircraft (330 m/s) by the speed of sound: Mach number = 330/464.7 ≈ 0.709.

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QUESTION 1 Which of the followings is true? Narrowband FM is considered to be identical to AM except O A. their bandwidth. O B. a finite and likely large phase deviation. O C. an infinite phase deviation. O D. a finite and likely small phase deviation.

Answers

Narrowband FM is considered to be identical to AM except in their bandwidth. In narrowband FM, a finite and likely small phase deviation is present. It is the modulation method in which the frequency of the carrier wave is varied slightly to transmit the information signal.

Narrowband FM is an FM transmission method with a smaller bandwidth than wideband FM, which is a more common approach. Narrowband FM is quite similar to AM, but the key difference lies in the modulation of the carrier wave's amplitude in AM and the modulation of the carrier wave's frequency in Narrowband FM.

The carrier signal in Narrowband FM is modulated by a small frequency deviation, which is inversely proportional to the carrier frequency and directly proportional to the modulation frequency. Therefore, Narrowband FM is identical to AM in every respect except the bandwidth of the modulating signal.

When the modulating signal is a simple sine wave, the carrier wave frequency deviates up and down about its unmodulated frequency. The deviation of the frequency is proportional to the amplitude of the modulating signal, which produces sidebands whose frequency is equal to the carrier frequency plus or minus the modulating signal frequency.

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Prove that a Schmitt oscillator trigger can work as a VCO.

Answers

Step 1:

A Schmitt oscillator trigger can work as a VCO (Voltage Controlled Oscillator).

Step 2:

A Schmitt oscillator trigger, also known as a Schmitt trigger, is a circuit that converts an input signal with varying voltage levels into a digital output with well-defined high and low voltage levels. It is commonly used for signal conditioning and noise filtering purposes. On the other hand, a Voltage Controlled Oscillator (VCO) is a circuit that generates an output signal with a frequency that is directly proportional to the input voltage applied to it.

By incorporating a voltage control mechanism into the Schmitt trigger circuit, it can be transformed into a VCO. This can be achieved by introducing a variable voltage input to the reference voltage level of the Schmitt trigger. As the input voltage changes, it will cause the switching thresholds of the Schmitt trigger to vary, resulting in a change in the output frequency.

The VCO functionality of the modified Schmitt trigger circuit allows it to generate a continuous output signal with a frequency that can be controlled by the applied voltage. This makes it suitable for various applications such as frequency modulation, clock generation, and signal synthesis.

Step 3:

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Describe frequency, relative frequency, and cumulative relative frequency.

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