Answer:
max(1, 8, 12, 9, 11, 2, 14, 5, 10, 4) = 14
Step-by-step explanation:
Here is the algorithm to find the maximum element:
procedure max(a1, a2, . . . , an : integers)
max := a1
for i := 2 to n
if max < ai then max := ai
return max{max is the largest element}
Now lets see how this algorithm works with the given sequence. 1, 8, 12, 9, 11, 2, 14, 5, 10, 4.
The value of max is set to 1. So max = 1.Now the for loop starts. The loop variable i which works as an index moves throughout the sequence i.e. from 2 to n. The value of n is 10 since the total number of elements in the sequence are 10. The first iteration: i=2. Now the IF condition if max < ai inside this FOR loop checks if the value of max is less than the element at i-th position. As the current value of max=1 and the value at i=2 is 8 which means the second element of the sequence. So this condition evaluates to true as 1 < 8. So the IF part is executed which has a statement max := ai which means if the value of max is less than the element at i-th index then the value of max is set to that element. So max = 8.The second iteration: at i = 3. Now the IF condition if max < ai checks if the value of max is less than the element at i-th position. As the current value of max= 8 and current value of i=3 means the third element of the sequence which is 12. So this condition evaluates to true as 8 < 12. So the IF part is executed which has a statement max := ai which means if the value of max is less than the element at i-th index then the value of max is set to that element. So max = 12.The third iteration at i = 4. Now the IF condition if max < ai checks if the value of max is less than the element at i-th position. As the current value of max= 12 and current value of i=4 means the fourth element of the sequence which is 9. Now the IF condition evaluates to false because 12 > 9. Hence the value of max remains the same. So max = 12.The fourth iteration at i = 5. Now the IF condition if max < ai checks if the value of max is less than the element at i-th position. As the current value of max= 12 and current value of i=5 means the fifth element of the sequence which is 11. Now the IF condition evaluates to false because 12 > 11. Hence the value of max remains the same. So max = 12.The fifth iteration at i = 6. Now the IF condition if max < ai checks if the value of max is less than the element at i-th position. As the current value of max= 12 and current value of i=6 means the sixth element of the sequence which is 2. Now the IF condition evaluates to false because 1 2> 2. Hence the value of max remains the same. So max = 12.The sixth iteration at i = 7. Now the IF condition if max < ai checks if the value of max is less than the element at i-th position. As the current value of max= 12 and current value of i=7 means the seventh element of the sequence which is 14. So this condition evaluates to true as 14 < 12. So the IF part is executed which has a statement max := ai which means if the value of max is less than the element at i-th index then the value of max is set to that element. So max = 14.The seventh iteration at i = 8. Now the IF condition if max < ai checks if the value of max is less than the element at i-th position. As the current value of max= 14 and current value of i=8 means the eighth element of the sequence which is 5. Now the IF condition evaluates to false because 1 4> 5. Hence the value of max remains the same. So max = 14.The eighth iteration at i = 9. Now the IF condition if max < ai checks if the value of max is less than the element at i-th position. As the current value of max= 14 and current value of i=9 means the ninth element of the sequence which is 10. Now the IF condition evaluates to false because 1 4> 10. Hence the value of max remains the same. So max = 14.The ninth iteration at i = 10. Now the IF condition if max < ai checks if the value of max is less than the element at i-th position. As the current value of max= 14 and current value of i=10 means the tenth element of the sequence which is 4. Now the IF condition evaluates to false because 1 4> 4. Hence the value of max remains the same. So max = 14.Now the loop ends as the value of i now becomes 11 because the loop is execute at i from 2 to n and value of n = 10. So the loop breaks and the next statement return max{max is the largest element} is executed which returns the current value of max. This means it returns the largest element in the sequence. Since the current value of max = 14. Hence max = 14 is the largest element.The phone company Blurizon has a monthly cellular plan where a customer pays a flat
fee for unlimited voice calls and then a certain amount per GB of data used. If a
customer uses 12 GB, the monthly cost will be $105. If the customer uses 34 GB, the
monthly cost will be $237.
A) Find an equation in the form y = mx + b, where is the number of GB of data
used in a month and y is the total monthly cost of the Blurizon plan.
Answer: y =
B) Use your equation to find the total monthly cost if 14 GB are used.
Answer: If 14 GB are used, the total cost will be____
dollars.
Answer:
(a)y=6x+33
(b)$117
Step-by-step explanation:
If a customer uses 12 GB, the monthly cost will be $105.
If the customer uses 34 GB, the monthly cost will be $237.
given that
x is the number of GB of data used in a month; and y is the total monthly cost of the Blurizon plan.We have the pairs: (12, 105) and (34, 237)
(A)To determine the straight-line equation, we first determine the slope, m.
[tex]m=\dfrac{237-105}{34-12}\\\\=\dfrac{132}{22}\\\\m=6[/tex]
Substitution into y = mx + b, we have: y=6x+b
Next, we determine the value of b
When y=105, x=12
105=6(12)+b
b=105-6(12)=33
Therefore, an equation in the form y = mx + b is:
y=6x+33
(B)
Total Cost, y=6x+33
When 14 GB are used, i.e. x=14
y=6(14)+33
y=$117
If 14 GB are used, the total cost will be 117 dollars.
This applet illustrates 95% confidence intervals for samples from a normal distribution with known variance.
When taking 100 samples of size 30 or greater from a population, exactly 95 of them will create a confidence interval that contains the true population mean.
a. True
b. False
Which statement is the correct interpretation of the confidence interval in this illustration
a. The probability the true mean is between 76.08 and 83.92 is 0.95 or 95%.
b. We are 95% confident that the true mean is between 76.08 and 83.92.
Answer:
1- b. False
2 b. We are 95% confident that the true mean is between 76.08 and 83.92.
Step-by-step explanation:
Confidence Interval is the estimated value that is computed from the statistic of data which is observed. The range value is plausible for unknown parameters. To find the critical value the confidence interval value is observed through the t-value table.
Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation to (4|3)? A. (4|-3)
B.(-3|4)
C.(3|-4)
D.(-4|3)
Answer:
C.(3|-4)
Step-by-step explanation:
Given the vector:
[tex]\left[\begin{array}{ccc}4\\3\end{array}\right][/tex]
The transformation Matrix is:
[tex]\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right][/tex]
The image of the vector after applying the transformation will be:
[tex]\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right][/tex]
The correct option is C
The image after applying the transformation to the matrix is [tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex].
What is a matrix ?Matrix, a set of numbers arranged in rows and columns so as to form a rectangular array. The numbers are called the elements, or entries, of the matrix.
It is given that the vector is
[tex]\begin{bmatrix}4\\ 3\end{bmatrix}[/tex]
and the transformation matrix is
[tex]\begin{bmatrix}0 &1 \\ -1 &0 \end{bmatrix}[/tex]
The image after applying the transformation
[tex]\begin{bmatrix}4\\ 3\end{bmatrix}\begin{bmatrix}0 &1 \\ -1 &0 \end{bmatrix}[/tex]
[tex]\begin{bmatrix}0*4+0*3 \\-1*4+0*3 \end{bmatrix}[/tex]
[tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex]
Therefore the image after applying the transformation to the matrix is [tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex].
To know more about Matrix
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Mighty Casey hits two baseballs out of the park. The path of the first baseball can be described by the displacement (distance and direction) vector,
b1 = 100 i ^ + 10 j ^. The path of the second baseball can be described by the displacement vector b2 = 90 i ^ + (−20) j ^.
(a) How much farther did the first ball travel than the second? (Round your final answer to the nearest tenth.)
(b) How far are the baseballs apart? (Round your final answer to the nearest tenth.)
Answer:
a) 8.3 units of length
b) 31.6 units of length
Step-by-step explanation:
a) The distances traveled by each ball are given by:
[tex]d_1^2=100^2+10^2=10,100\\d_1=100.5\\\\d_2^2=90^2+(-20^2)=8,500\\d_2=92.2[/tex]
The diference between the distance traveled by both balls is:
[tex]d_1-d-2=100.5-92.2\\d_1-d_2=8.3[/tex]
The first ball traveled 8.3 units of length farther than the second ball.
b) The distance between both balls is:
[tex]d^2=(i_1-i_2)^2+(j_1-j_2)^2\\d^2=(100-90)^2+(10-(-20))^2\\d^2=1,000\\d=31.6[/tex]
The balls are 31.6 units of length apart.
standard form of line that passes thru (-3,5) and (-2,-6)
Answer:
11x + y = -28
Step-by-step explanation:
Step 1: Find slope
(6-5)/(-2--3) = -11
Step 2: Find y-intercept
y = -11x + b
5 = -11(-3) + b
5 = 33 + b
b = -28
Step 3: Write in slope-intercept form
y = -11x - 28
Step 4: Convert to standard form
11x + y = 28
And we have our final answer!
I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
Answer:
[tex]g(2) = 4(2) + 6 = 14[/tex]
[tex]f(2) = 2(2) + 3 = 7[/tex]
[tex](g - f)(2) = 14 - 7 = 7[/tex]
problem decoded dude
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Evaluate (x + y)0 for x = -3 and y = 5
Answer:
0Step-by-step explanation:
[tex](x + y)0 \\ x = -3 \\y = 5\\(-3+5)0\\(2)0\\= 0[/tex]
Please answer this correctly
Answer:
9 bags
Step-by-step explanation:
130, 134, 136, 145, 145, 147, 147, 151, 154
9 bags had at least 130 peanuts.
When a ladder of length 2.5 m leans against the
of 55° with the ground. When the ladder leans
top edge of a window of a building, it forms an
angle
against the lower edge of the same window,
it forms an angle of 38° with the ground. Find the
height of the window, giving your answer in
centimetres.
Answer: window = 0.50 m
Step-by-step explanation:
First, draw a picture (see image below).
Then set up two equations that eventually you can set equal to each other.
Given: Ladder (hypotenuse) = 2.5
Angle to Top edge of window = 55°
Angle to Lower edge of window = 38°
[tex]\sin \text{Top}=\dfrac{opposite}{hypotenuse}\qquad \qquad \sin \text{Lower}=\dfrac{opposite}{hypotenuse}\\\\\\\sin 55^o=\dfrac{h+y}{2.5}\qquad \qquad \qquad \sin 38^o=\dfrac{y}{2.5}\\\\\\\underline{\text{Solve both equations for y:}}\\2.5\sin 55^o-h=y\qquad \qquad 2.5\sin 38^o=y\\\\\\\underline{\text{Set the equations equal to each other and solve for h:}}\\\\2.5\sin 55^o-h=2.5\sin 38^o\\2.5\sin 55^0-2.5\sin 38^o=h\\\large\boxed{0.50=h}[/tex]
Which is the cosine ratio of
Answer:The answer is B
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Cos A = [tex]\frac{Adjacent}{Hypotenuse}[/tex]
Where Adjacent = 28, Hypotenuse = 197
Cos A = [tex]\frac{28}{197}[/tex]
In accounting, cost-volume-profit analysis is a useful tool to help managers predict how profit will be affected by changes in prices or sales volume. Net income, NININ, I, is calculated using the formula NI = (SP-VC)(V)-FCNI=(SP−VC)(V)−FCN, I, equals, left parenthesis, S, P, minus, V, C, right parenthesis, left parenthesis, V, right parenthesis, minus, F, C, where SPSPS, P is the sales price, VCVCV, C is the variable cost per unit, VVV is the sales volume, and FCFCF, C are fixed costs. Rearrange the formula to solve for sales volume (V)(V)left parenthesis, V, right parenthesis.
Answer:
(a)[tex]V=\dfrac{NI+FC}{SP-VC}[/tex]
(b)V=240 Units
Step-by-step explanation:
NI=(SP-VC)V-FC
We are required to make V the subject of the equation
Add FC to both sides
NI+FC=(SP-VC)V-FC+FC
NI+FC=(SP-VC)V
Divide both sides by SP-VC
[tex]V=\dfrac{NI+FC}{SP-VC}[/tex]
When
Net Income(NI)=$5000Sales Price(SP)=$40Variable Cost(VC)=$15Fixed Costs(FC)=$1000Volume of Sales
[tex]V=\dfrac{5000+1000}{40-15}\\=\dfrac{6000}{25}\\\\=240[/tex]
9+9+3=21
1234+1234+1234= 30
9+1224+12=?
Answer:
9+1224+12=1245
Hope this helps
Answer:
Mathematically,
9+1224+12 = 1245
But, Logically, here:
9+1224+12 = 21
If it takes 4 hours for 2 men to mow a sports field,how long would it take 6 men working at the same rate to do the job?solution plis
Answer:
4/3 hours
Step-by-step explanation:
[tex]\frac{4*2}{6}\\=\frac{8}{6} \\= 4/3 hours[/tex]
The Toyota Camry is one of the best-selling cars in North America. The cost of a previously owned Camry depends on many factors, including the model year, mileage, and condition. To investigate the relationship between the car’s mileage and the sales price for Camrys, the following data show the mileage and sale price for 19 sales (PriceHub web site, February 24, 2012).Miles(1000s) Price($1,000s) 22 16.2 29 16.0 36 13.8 47 11.5 63 12.5 77 12.9 73 11.2 87 13.0 92 11.8 101 10.8 110 8.3 28 12.5 59 11.1 68 15.0 68 12.2 91 13.0 42 15.6 65 12.7 110 8.3A. Test whether each of the regression parameters b0 and b1 are equal to zero at 0.01 level of significance.B. What are the correct interpretations of the estimated regression parameters?C. Are these interpretations reasonable?
Answer:
Step-by-step explanation:
Hello!
Given the variables
Y: Cost of a previously owned Camry.
X: Mileage of a previously owned Camry.
Scatter plot in attachment.
As you can see in the scatter plot, the price of the previously owned Camry decreases as their mileage increases this suggest that there is a negative linear regression between these two variables.
Hypothesis test for the y-intercept
H₀: β₀ = 0
H₁: β₀ ≠ 0
Level of significance α: 0.01
p-value < 0.0001
The decision is to reject the null hypothesis. You can conclude that the population mean of the cost of a previously owned Camry, when the mileage is zero, is different from zero.
H₀: β = 0
H₁: β ≠ 0
Level of significance α: 0.01
p-value: 0.0003
The decision is to reject the null hypothesis. You can conclude that the population mean of the cost of a previously owned Camry is modified when the mileage increases in one unit.
The personnel department of a large corporation wants to estimate the family dental expenses of its employees to determine the feasibility of providing a dental insurance plan. A random sample of 12 employees reveals the following family dental expenses (in dollars). See Attached Excel for Data. Construct a 97% confidence interval estimate for the average family dental expenses for all employees of this corporation.
The data cited is in the attachment.
Answer: 308.2±106.4
Step-by-step explanation: To construct a confidence interval, first calculate mean (μ) and standard deviation (s) for the sample:
μ = Σvalue/n
μ = 308.2
s = √∑(x - μ)²/n-1
s = 147.9
Calculate standard error of the mean:
[tex]s_{x} = \frac{s}{\sqrt{n} }[/tex]
[tex]s_{x}[/tex] = [tex]\frac{147.9}{\sqrt{12} }[/tex]
[tex]s_{x}[/tex] = 42.72
Find the degrees of freedom:
d.f. = n - 1
d.f. = 12 - 1
d.f. = 11
Find the significance level:
[tex]\frac{1-0.97}{2}[/tex] = 0.015
Since sample is smaller than 30, use t-test table and find t-score:
[tex]t_{11,0.015}[/tex] = 2.4907
E = t-score.[tex]s_{x}[/tex]
E = 2.4907.42.72
E = 106.4
The interval of confidence is: 308.2±106.4, which means that dental insurance plan varies from $201.8 to $414.6.
Do all systems of linear inequalities have solutions? If not, write a system of inequalities that has no solution. What would the graph of a system of linear inequalities with no solution look like?
Answer: There are systems with no solutions, and the graphs may show two regions with no intersections (as you know, the solution set is in the intersection of the sets of solutions for each inequality)
Step-by-step explanation:
Ok, suppose that our system is:
y > x
and
y < x.
This system obviously does not have any solution, because y can not be larger and smaller than x at the same time.
The graph of y > x is where we shade all the region above the line y = x (the line is not included)
and the graph of y < x is where we sade all the region under the line y = x (the line is not included)
So we will look at a graph where we never have a region with the two shades overlapping (so we do not have a intersection in the sets of solutions), meaning that we have no solutions.
Tell whether the following set is an empty set or not? A = { A quadrilateral having 3 obtuse angles}
Answer:
No.
Step-by-step explanation:
A quadrilateral with 3 obtuse angles is possible. You could have 100°+100°+100°+60° quadrilateral or whatever. As long as it's inner angles add up to 360°, it is possible.
Answer:
[tex]\boxed{\mathrm{It \: is \: not \: an \: empty \: set}}[/tex]
Step-by-step explanation:
A quadrilateral with 3 obtuse angles is possible.
A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.
Let’s say three angles are measuring 91 degrees in a quadrilateral.
91 + 91 + 91 + x = 360
x = 87
The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.
5. A worker can do a piece of
piece of wook
in 14 days.
How much coook does he do ini day!
. How much work does he do in 7 days?
lijIt he works for 2 days and leaves,
how much work is left to finish it?
Answer:
therefore the left work of worker will be 6/7 part of work
Please answer this correctly
Answer:
sorry about that that was my sister . the correct answer is yes
Step-by-step explanation:
please mark as brainliest
2 = x-3, then x equals
Answer:
x = 5
Step-by-step explanation:
2 = x-3
Adding 3 to both sides
2+3 = x
5 = x
OR
x = 5
Answer:
[tex] \times = 2 + 3 \\ \\ x = 5[/tex]
30 students, along with some of their parents, are going to a trip to Washington DC. Some of the adults are driving cars, and each car can accommodate up to 5 people including the driver. What is the smallest number of adults that should be invited on the trip to get all 30 students to Washington?
Answer:
Minimum 08 adults / drivers
Maximum 10 adults / drivers
Step-by-step explanation:
Total students are 30
Each car can take total 5 incl. drive
There needs to be 7 cars taking the 30 students, which also means there have to be minimum 7 drivers / adults.
Min. passengers = 30 + 7
Of course, there will be space for 3 more in the 8th car since 5 x 8 = 40
if each angle of triangle is less than the sum of of other two show that the triangle is acute angled triangle
Suppose you will perform a test to determine whether there is sufficient evidence to support a claim of a linear correlation between two variables. Find the critical values of r given the number of pairs of data n and the significance level α. n = 12, α = 0.01
Answer:
[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]
And is distributed with n-2 degreed of freedom. df=n-2=12-2=10
The significance level is [tex]\alpha=0.01[/tex] and [tex]\alpha/2 = 0.005[/tex] and for this case we can find the critical values and we got:
[tex] t_{\alpha/2}= \pm 3.169[/tex]
Step-by-step explanation:
In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:
Null hypothesis: [tex]\rho =0[/tex]
Alternative hypothesis: [tex]\rho \neq 0[/tex]
The statistic to check the hypothesis is given by:
[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]
And is distributed with n-2 degreed of freedom. df=n-2=12-2=10
The significance level is [tex]\alpha=0.01[/tex] and [tex]\alpha/2 = 0.005[/tex] and for this case we can find the critical values and we got:
[tex] t_{\alpha/2}= \pm 3.169[/tex]
Find an equation of the plane that passes through the point P0(- 3,3,1) with a normal vector n = (1,4, -3). Which of the following equations is an equation of the plane that passes through the point P0( - 3,3,1) with a normal vector n (1,4, -3)?
a. An equation for the plane is -3x+3y + Z = 6.
b. An equation for the plane is x+ 3y +z = 19.
c. An equation for the plane is x + y+ z = 26.
d. An equation for the plane is x +4y - 3z= 6.
Take an arbitrary vector (x, y, z), which goes from the origin to some point (x, y, z) on the plane we want to find.
Subtract from this vector, the vector that points to [tex]P_0[/tex], which is (-3, 3, 1). This translates the first vector so that it starts at the point [tex]P_0[/tex] and is directed at some point (x, y, z). We get a new translated vector, (x + 3, y - 3, z - 1), which lies in the plane.
The normal vector to the plane is orthogonal to every vector in the plane. So taking the dot product of any vector in the plane with the normal to the plane will always result in 0. We use this to find the plane's equation:
[tex]\vec n\cdot((x,y,z)-P_0)=(1,4,-3)\cdot(x+3,y-3,z-1)=0[/tex]
[tex]\implies(x+3)+4(y-3)-3(z-1)=0[/tex]
[tex]\implies x+4y-3z=6[/tex]
and so the answer is D.
The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking samples of sizes n = 160 units. Suppose that today’s sample contains 14 defectives. How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% (using the information from today’s sample--that is using the result that f$hat {767} =0.0875f$
Answer:
[tex]n=\frac{0.0875(1-0.0875)}{(\frac{0.02}{1.96})^2}=766.82[/tex]
And rounded up we have that n=767
Step-by-step explanation:
We know the following info:
[tex] n=160[/tex] represent the sample size selected
[tex] x= 14[/tex] represent the number of defectives in the sample
[tex]\hat p= \frac{14}{160}= 0.0875[/tex] represent the estimated proportion of defectives
[tex] ME = 0.02[/tex] represent the margin of error desired
The margin of error for the proportion interval is given by this formula:
[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex] (a)
And on this case we have that [tex]ME =\pm 0.02[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:
[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex] (b)
The crtical value for a confidence level of 95% is [tex] z_{\alpha/2}=1.96[/tex]
And replacing into equation (b) the values from part a we got:
[tex]n=\frac{0.0875(1-0.0875)}{(\frac{0.02}{1.96})^2}=766.82[/tex]
And rounded up we have that n=767
SOMEONE PLEASE HELP ME ASAP PLEASE!!!
Answer:
A = 45 units^2
Step-by-step explanation:
This is a trapezoid
A = 1/2 (b1+b2) h
b1 is the top = 7
b2 is the bottom = 11
h = 5
A = 1/2 ( 7+11) *5
A = 1/2 ( 18)*5
A = 45 units^2
Use the diagram to find the angle measures that satisfy each case. Find the measures of all four angles if 3·(m∠1+m∠3) = m∠2+m∠4.
Answer:
m∠1=45 degreesm∠2=135 degreesm∠3=45 degreesm∠4=135 degreesStep-by-step explanation:
Given that: 3(m∠1+m∠3) = m∠2+m∠4.
From the diagram:
m∠1=m∠3 (Vertical Angles)m∠2=m∠4 (Vertical Angles)Therefore:
3(m∠1+m∠1) = m∠2+m∠2
3(2m∠1)=2m∠2
Divide both sides by 2
3m∠1=m∠2
m∠1+m∠2=180 (Linear Postulate)
Therefore:
m∠1+3m∠1=180
4m∠1=180
Divide both sides by 4
m∠1=45 degrees
Since m∠1=m∠3
m∠3=45 degrees
Recall: m∠1+m∠2=180 (Linear Postulate)
45+m∠2=180
m∠2=180-45
m∠2=135 degrees
Since m∠2=m∠4
m∠4=135 degrees
A supplier of heavy construction equipment has found that new customers are normally obtained through customer requests for a sales call and that the probability of a sale of a particular piece of equipment is 0.15. If the supplier has four pieces of the equipment available for sale, what is the probability that it will take fewer than six customer contacts to clear the inventory?
Answer:
The probability that it will take fewer than six customer contacts to clear the inventory is 0.8%.
Step-by-step explanation:
We have a probability of making an individual sale of p=0.15.
We have 4 units, so the probability of clearing the inventory with n clients can be calculated as:
[tex]P=\dbinom{n}{4}p^4q^{n-4}=\dbinom{n}{4}0.15^4\cdot 0.85^{n-4}[/tex]
As we see in the equation, n has to be equal or big than 4.
In this problem we have to calculate the probability that less than 6 clients are needed to sell the 4 units.
This probability can be calculated adding the probability from n=4 to n=6:
[tex]P=\sum_{n=4}^6P(n)=\sum_{n=4}^6 \dbinom{n}{4}0.15^4^\cdot 0.85^{n-4}\\\\\\P=0.15^4(\dfrac{4!}{4!0!}\cdot 0.85^{4-4}+\dfrac{5!}{4!1!}\cdot0.85^{5-4}+\dfrac{6!}{4!2!}0.85^{6-4})\\\\\\P=0.15^4(1\cdot0.85^0+5\cdot0.85^1+15\cdot0.85^2)\\\\\\P=0.00051(1+4.25+10.84)\\\\\\P=0.00051\cdot16.09\\\\\\P=0.008[/tex]
6• 2hen+3pens-5anchors
Answer:
[tex]180[/tex]
Step-by-step explanation:
[tex]6 \times 2 \times 3 \times 5[/tex]
[tex]12 \times 15[/tex]
[tex]=180[/tex]
Steps to solve:
6 * 2 + 3 - 5
~Multiply
12 + 3 - 5
~Add
15 - 5
~Subtract
10
Best of Luck!
match the term with the definition
Answer:
1 - c
2 - a
3 - e
4 - d
5 - b
Answer: c, a, e, d, b
Step-by-step explanation:
1. Angle: (c) A figure consisting of two rays with the same endpoint.
2. Circle: (a) The set of all points in a plane that are a given distance from a point. That distance is called the radius.
3. Point: (e) A location, has no size.
4. Ray: (d) The portion of a line that starts at one point and goes off to infinity.
5. Vertex: (b) A point where two or more rays or "arms" of an angle meet.