Answer:
Brainliest!
Explanation:
The primary or most-commonly-used HTTP verbs (or methods, as they are properly called) are POST, GET, PUT, PATCH, and DELETE. These correspond to create, read, update, and delete (or CRUD) operations, respectively. There are a number of other verbs, too, but are utilized less frequently.
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restapitutorial
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com
AJAX
The word that is not an HTTP verb is AJAX.
But PUT, GET, and DELETE are HTTP verbs.
A HTTP verb is a word or method (it can also be a noun) for retrieving information (documents) in a web-based environment. There are other HTTP verbs used for various purposes. The most common include PUT, GET, DELETE, and POST.
HTTP is a computer-based abbreviation that means Hypertext Transfer Protocol. It is the protocol for transferring data over the web using a client's home computer, laptop, or mobile device.
AJAX, which means Asynchronous Javascript and XML, is mainly used as a technique for creating fast and dynamic web pages using small amounts of data.
There is no suitable reference of HTTP verbs at brainly.com.
Write a program that prompts the user to enter integers in the range 1 to 50 and counts the occurrences of each integer. The program should also prompt the user for the number of integers that will be entered. As an example, if the user enters 10 integers (10, 20, 10, 30, 40, 49, 20, 10, 25, 10), the program output would be:
Answer:
import java.util.Scanner; public class Main { public static void main(String[] args) { int num[] = new int[51]; Scanner input = new Scanner(System.in); System.out.print("Number of input: "); int limit = input.nextInt(); for(int i=0; i < limit; i++){ System.out.print("Input a number (1-50): "); int k = input.nextInt(); num[k]++; } for(int j=1; j < 51; j++){ if(num[j] > 0){ System.out.println("Number of occurrence of " + j + ": " + num[j]); } } } }Explanation:
The solution is written in Java.
Firstly, create an integer array with size 51. The array will have 51 items with initial value 0 each (Line 5).
Create a Scanner object and get user entry the number of input (Line 6-7).
Use the input number as the limit to control the number of the for loop iteration to repeatedly get integer input from user (Line 9-13). Whenever user input an integer, use that integer, k, as the index to address the corresponding items in the array and increment it by one (LINE 11-12).
At last, create another for loop to iterate through each item in the array and check if there is any item with value above zero (this means with occurrence at least one). If so, print the item value as number of occurrence (Line 14-17).
Write a python program that asks the user to enter a student's name and 8 numeric tests scores (out of 100 for each test). The name will be a local variable. The program should display a letter grade for each score, and the average test score, along with the student's name. There are 12 students in the class.
Write the following functions in the program:
calc_average - this function should accept 8 test scores as arguments and return the average of the scores per student
determine_grade - this function should accept a test score average as an argument and return a letter grade for the score based on the following grading scale:
90-100 A
80-89 B
70-79 C
60-69 D
Below 60 F
Answer:
The program doesn't make use of comments (See Explanation)
Also the source code is attached as image to enable you see the proper format and indexing of the source code
The program using python is as follows
def calc_average(name):
score = []
sum = 0
for j in range(8):
inp = int(input("Test Score"+str(j+1)+": "))
score.append(inp)
sum = sum + inp
if inp>=90 and inp<=100:
print("A")
elif inp>=80 and inp<90:
print("B")
elif inp>=70 and inp<80:
print("C")
elif inp>=60 and inp<70:
print("D")
else:
print("F")
avg = sum/8
print("Result Details of "+name)
print("Average Score: "+str(avg))
return avg
def determine_grade(result):
if float(result) >= 90.0 and float(result) <= 100.0:
print("Letter Grade: A")
elif float(result) >= 80.0 and float(result) <90.0:
print("Letter Grade: B")
elif float(result) >= 70.0 and float(result) < 80.0:
print("Letter Grade: C")
elif float(result) >= 60.0 and float(result) < 70.0:
print("Letter Grade: D")
else:
print("Letter Grade: F")
print(" ")
for i in range(2):
name = input("Student Name: ")
result = calc_average(name)
determine_grade(result)
Explanation:
def calc_average(name): -> Declares the function calc_average(name); It accepts local variable name from the main function
score = []
-> Initialize an empty list to hold test scores
sum = 0
-> Initialize sum of scores to 0
for j in range(8):
-> Iterate from test score 1 to 8
inp = int(input("Test Score"+str(j+1)+": "))
-> This line accepts test score from the user
score.append(inp)
-> The user input is then saved in a lisy
sum = sum + inp
-> Add test scores
The following lines determine the letter grade of each test score
if inp>=90 and inp<=100:
print("A")
---
else:
print("F")
avg = sum/8 -> Calculate average of the test score
The next two lines prints the name and average test score of the student
print("Result Details of "+name)
print("Average Score: "+str(avg))
return avg
-> This line returns average to the main method
The following is the determine_grade method; it takes it parameter from the main method and it determines the letter grade depending on the calculated average
def determine_grade(result):
if float(result) >= 90.0 and float(result) <= 100.0:
print("Letter Grade: A")
elif float(result) >= 80.0 and float(result) <90.0:
print("Letter Grade: B")
elif float(result) >= 70.0 and float(result) < 80.0:
print("Letter Grade: C")
elif float(result) >= 60.0 and float(result) < 70.0:
print("Letter Grade: D")
else:
print("Letter Grade: F")
print(" ")
for i in range(2):
-> This is the main method
name = input("Student Name: ") -> A local variable stores name of the student
result = calc_average(name) -> store average of scores in variable results
determine_grade(result)-> Call the determine_grade function
In this exercise we have to use the computer language knowledge in python to write the code as:
the code is in the attached image.
In a more easy way we have that the code will be:
def calc_average(name):
score = []
sum = 0
for j in range(8):
inp = int(input("Test Score"+str(j+1)+": "))
score.append(inp)
sum = sum + inp
if inp>=90 and inp<=100:
print("A")
elif inp>=80 and inp<90:
print("B")
elif inp>=70 and inp<80:
print("C")
elif inp>=60 and inp<70:
print("D")
else:
print("F")
avg = sum/8
print("Result Details of "+name)
print("Average Score: "+str(avg))
return avg
def determine_grade(result):
if float(result) >= 90.0 and float(result) <= 100.0:
print("Letter Grade: A")
elif float(result) >= 80.0 and float(result) <90.0:
print("Letter Grade: B")
elif float(result) >= 70.0 and float(result) < 80.0:
print("Letter Grade: C")
elif float(result) >= 60.0 and float(result) < 70.0:
print("Letter Grade: D")
else:
print("Letter Grade: F")
print(" ")
for i in range(2):
name = input("Student Name: ")
result = calc_average(name)
determine_grade(result)
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11.19 (Constructor Failure) Write a program that shows a constructor passing information about constructor failure to an exception handler. Define class SomeClass, which throws an Exception in the constructor. Your program should try to create an object of type SomeClass and catch the exception that’s thrown from the constructor
Answer:
You absolutely should throw an exception from a constructor if you're unable to create a valid object. This allows you to provide proper invariants in your class. ... Throw an exception if you're unable to initialize the object in the constructor, one example are illegal arguments.
Explanation:
Error codes cannot be used in constructors since they lack a return type. Therefore, throwing an exception is the most effective technique to indicate constructor failure. Here is a workaround if you don't have or are unwilling to use exceptions.
What constructor passing information, constructor failure?When an exception is thrown in a constructor, memory for the actual object has already been set aside before the constructor is even invoked. Therefore, after the exception is thrown, the compiler will immediately deallocate the memory the object was using.
There are two solutions to that: Simple and conventional approach: Use arrows. To make use of a two-stage construction, use a custom “construct” function after a default constructor that cannot throw exceptions.
Therefore, The constructor has the ability to “zombie” an object if it fails.
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(Convert milliseconds to hours, minutes, and seconds) Write a function that converts milliseconds to hours, minutes, and seconds using the following header: def convertMillis(millis): The function returns a string as hours:minutes:seconds. For example, convertMillis(5500) returns the string 0:0:5, convertMillis(100000) returns the string 0:1:40, and convertMillis(555550000) returns the string 154:19:10. Write a test program that prompts the user to enter a value for milliseconds and displays a string in the format of hours:minutes:seconds. Sample Run Enter time in milliseconds: 555550000 154:19:10
Answer:
I am writing the Python program. Let me know if you want the program in some other programming language.
def convertMillis(millis): #function to convert milliseconds to hrs,mins,secs
remaining = millis # stores the value of millis to convert
hrs = 3600000 # milliseconds in hour
mins = 60000 # milliseconds in a minute
secs = 1000 #milliseconds in a second
hours =remaining / hrs #value of millis input by user divided by 360000
remaining %= hrs #mod of remaining by 3600000
minutes = remaining / mins # the value of remaining divided by 60000
remaining %= mins #mod of remaining by 60000
seconds = remaining / secs
#the value left in remaining variable is divided by 1000
remaining %= secs #mod of remaining by 1000
print ("%d:%d:%d" % (hours, minutes, seconds))
#displays hours mins and seconds with colons in between
def main(): #main function to get input from user and call convertMillis() to #convert the input to hours minutes and seconds
millis=input("Enter time in milliseconds ") #prompts user to enter time
millis = int(millis) #converts user input value to integer
convertMillis(millis) #calls function to convert input to hrs mins secs
main() #calls main() function
Explanation:
The program is well explained in the comments mentioned with each line of code. The program has two functions convertMillis(millis) which converts an input value in milliseconds to hours, minutes and seconds using the formula given in the program, and main() function that takes input value from user and calls convertMillis(millis) for the conversion of that input. The program along with its output is attached in screenshot.
if you want to exclude a portion of an image which option should be chosen?? A. Arrange B. Position C. Crop D. Delete
In this lab, you declare and initialize constants in a C++ program. The program, which is saved in a file named NewAge2.cpp, calculates your age in the year 2050.
Answer:
#include <iostream>
using namespace std;
int main()
{
const int YEAR = 2050;
int currentYear = 2020;
int currentAge = 38;
cout<<"You will be " << currentAge + (YEAR - currentYear) << " years old in " << YEAR;
return 0;
}
Explanation:
Initialize the YEAR as a constant and set it to 2050
Initialize the currentYear as 2020, and currentAge as 38
Calculate and print the age in 2050 (Subtract the currentYear from the YEAR and add it to the currentAge)
DEF is a small consulting firm with ten on-site employees and 10 to 12 part-time (off-site) software consultants. Currently, the network consists of 2 servers for internal business processes, 1 server that handles the call-in connections; 10 on-site wireless workstations/devices, and 2 printers. Respond to the following in a minimum of 175 words: Identify one network security strategy that would help this organization. Why did you choose this strategy over others
Answer:
What i would suggest for the organization is to use the Testing Infrastructure strategy. it is good for your consulting firm because it is less costly and provide security.
Explanation:
Solution
There are different network security strategy which is listed below:
Segment the network:
Segmentation in network is very useful for providing security.If any threat is occur only one segment is effected remaining are safe and it is less cost process. very useful for small organizations.
Test your infrastructure :
Testing infrastructure also very good technique.
Always we have to test our infrastructure whether threat is occur or not.
If any threat is happen we can detect that easily by testing our infrastructure.
Regularly update anti-virus software :
This is very useful for small organizations and it is less cost.with less cost we can provide security for all devices like computer,server,modems etc.
Frequently backup your critical data :
This is very good technique for crucial data.If we backup important data any time that will be useful if any attack is happen.
This is less costs and simple.
Change router default security settings :
Changing router password and settings also helpful for providing security.If we maintain same password and same settings for a long time that may lead to data hacking.It is cost less process very useful for small organizations.
All of the following are true about hacksaws except: a. A hacksaw only cuts on the forward stroke. b. A coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. c. A fine hacksaw blade (one with many teeth) is better for cutting sheet metal. d. A hacksaw blade is hardened in the center, so it is best to saw only with the center portion of the blade.
All of the following are true about hacksaws, except a coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. The correct option is b.
What is a hacksaw?A hacksaw is a saw with fine teeth that were originally and primarily used to cut metal. Typically, a bow saw is used to cut wood and is the corresponding saw.
Hacksaw is used by hand, it is a small tool for cutting pipes rods wood etc that is very common and homes and in shops. The different types of hacksaws. The main three types of hacksaws are course-grade hacksaws, medium-grade hacksaws, and fine-grade hacks. The difference is just for the quality, and the design of the blade.
Therefore, the correct option is b. Cutting thick steel is easier with a coarse hacksaw blade (one with fewer teeth) than a fine one.
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Describe any five GSM PLMN basic services?
Answer:
Your answer can be found in the explanation below.
Explanation:
GSM is the abbreviation for Global System for Mobile communication. Its purpose is to transmit voice and data services over a range. It is a digital cellular technology.
PLMN is the abbreviation for Public Land Mobile network. It is defined as the wireless communication service or combination of services rendered by a telecommunication operator.
The plmn consists of technologies that range from Egde to 3G to 4G/LTE.
PLMN consists of different services to its mobile subscribers or users but for the purpose of this question, i will be pointing out just 5 of them alongside its definitions.
1. Emergency calls services to fire or police: Plmn provides us with the option to make emergency calls in the event of any accident or fire incident, etc.It is available on devices either when locked or unlocked.
2. Voice calls to/from other PLMN: This entails the putting of calls across to persons we cannot reach very quickly. PLMN helps to connect persons through its network of from other networks thus making communication easier.
3. Internet connectivity: PLMN provieds us with internet services through wifi or bundles that enable us have access to the internet as well as help us communicate with people and loved ones over a distance. Internet service are possble either on GPRS or 3G or 4G networks.
4. SMS service: SMS means short messaging service. This is also know as text messages. PLMN allows us to be able to send short messages to people as oppposed to mails. It is mostly instant and can be sent or recieved from the same PLMN or others.
5. MMS service: Multimedia messaging service whose short form is MMS ccan be descibed as the exchange of heavier messages such as a picture or music or document but not from an email. It is availabel for use from one PLMN to another.
Cheers.
The performance of a client-server system is strongly influenced by two major network characteristics: the bandwidth of the network (how many bits/sec it can transport) and the latency (how many seconds it takes for the first bit to get from the client to the server). Give an example of a network that exhibits high bandwidth but also high latency. Also give an example of one that has both low bandwidth and low latency. Justify/explain your answers. (
Answer:
A bandwidth is the maximum rate of transfer of data across a given path
Latency refers to the delay of data to travel or move between a source and destination
An example of a high bandwidth and high latency network is the Satellite Internet connectivity.
An example of a low bandwidth and latency network is the telephone system connection.
Explanation:
Solution
Bandwidth: Bandwidth determines how fast data can be transferred for example, how many bits/sec it can transport.
Latency: It refers to the delay or how long it takes for data to travel between it's source and destination.
An example of a high bandwidth and high latency network is the Satellite internet connection.
Satellite internet connection: This is responsible for the connectivity of several systems, it has a high bandwidth, since satellite are in space, due to distance it has a high latency.
So, satellite internet connection is compensated with high latency and high bandwidth.
An example of a low bandwidth and low latency network is the Telephony network.
Telephone/telephony internet connection: This connection does not have much data for transfer. it has low size audio files of which a low bandwidth range. also for both end or end users to understand and talk to each other, it has low latency.
An example of a network that exhibits high bandwidth but also high latency is Satellite internet connection.
An example of one that has both low bandwidth and low latency is telephony internet connection.
Based on the provided information, we can say that Satellite internet connection posses high bandwidth but also high latency because, the fastness of data transfer is based on the bandwidth and how the data to travel between it's source and destination is based on its latency.
We can conclude that telephony internet connection has low bandwidth and low latency because of low data transfer is required.
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Give an example of a function from N to N that is: Hint: try using absolute value, floor, or ceiling for part (b). (a) one-to-one but not onto (b) onto but not one-to-one (c) neither one-to-one nor onto
Answer:
Let f be a function
a) f(n) = n²
b) f(n) = n/2
c) f(n) = 0
Explanation:
a) f(n) = n²
This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.
Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:
f(a) = f(b) ⇒ a² = b² ⇒ a = b
The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number. For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.
b) f(n) = n/2
The above function example is an onto function because every natural number, let’s say n is a natural number that belongs to N, is the image of 2n. For example:
f(2n) = [2n/2] = n
The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:
When the value of n=1, then
n/2 = [1/2] = [0.5] = 1
When the value of n=2 then
n/2 = [2/2] = [1] = 1
c) f(n) = 0
The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image. The above function example is also not an onto function because every positive integer is not an image of any natural number.
Complete a prewritten C++ program for a carpenter who creates personalized house signs. The program is supposed to compute the price of any sign a customer orders, based on the following facts:
The charge for all signs is a minimum of $35.00.
The first five letters or numbers are included in the minimum charge; there is a $4 charge for each additional character.
If the sign is made of oak, add $20.00. No charge is added for pine.
Black or white characters are included in the minimum charge; there is an additional $15 charge for gold-leaf lettering.
Instructions:
Ensure the file named HouseSign.cppis open in the code editor. You need to declare variables for the following, and initialize them where specified:
A variable for the cost of the sign initialized to 0.00 (charge).
A variable for the number of characters initialized to 8 (numChars).
A variable for the color of the characters initialized to "gold" (color).
A variable for the wood type initialized to "oak" (woodType).
Write the rest of the program using assignment statements and ifstatements as appropriate. The output statements are written for you.
Answer:
#include <iostream>
#include <string>
using namespace std;
int main()
{
double charge = 0.00;
int numChars = 8;
string color = "gold";
string woodType = "oak";
if(numChars > 5){
charge += (numChars - 5) * 4;
}
if(woodType == "oak"){
charge += 20;
}
if(color == "gold"){
charge += 15;
}
charge += 35;
cout << "The charge is: $" << charge << endl;
return 0;
}
Explanation:
Include the string library
Initialize the variables as specified
Check if the number of characters is greater than 5 or not. If it is, add 4 to the charge for each character that is greater than 5
Check if the sign is made of oak or not. If it is, add 20 to the charge
Check if the color is gold or not. If it is, add 35 to the charge
Add the minimum cost to the charge
Print the charge
In this exercise we have to use the knowledge of the C++ language to write the code, so we have to:
The code is in the attached photo.
So to make it easier the code can be found at:
#include <iostream>
#include <string>
using namespace std;
int main()
{
double charge = 0.00;
int numChars = 8;
string color = "gold";
string woodType = "oak";
if(numChars > 5){
charge += (numChars - 5) * 4;
}
if(woodType == "oak"){
charge += 20;
}
if(color == "gold"){
charge += 15;
}
charge += 35;
cout << "The charge is: $" << charge << endl;
return 0;
}
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What is
relation degree.
Answer:
Explanation:
The degree of relationship can be defined as the number of occurrences in one entity that is associated with the number of occurrences in another entity. There is the three degree of relationship: One-to-one (1:1) One-to-many (1:M)
Given positive integer numInsects, write a while loop that prints that number doubled without reaching 100. Follow each number with a space. After the loop, print a newline. Ex: If numInsects = 8, print:
8 16 32 64
#include
using namespace std;
int main() {
int numInsects = 0;
numInsects = 8; // Must be >= 1
while (numInsects < 100) {
numInsects = numInsects * 2;
cout << numInsects << " ";
}
cout << endl;
return 0;
}
So my question is what am I doing wrong?
Answer:
The cout<<numInsects<<""; statement should be placed before numInsects = numInsects * 2; in the while loop.
Explanation:
Your program gives the following output:
16 32 64 128
However it should give the following output:
8 16 32 64
Lets see while loop to check what you did wrong in your program:
The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100.
So the body of while loop executes. numInsects = numInsects * 2; statement in the body multiplies the value of numInsects i.e 8 with 2 and then cout << numInsects << " "; prints the value of numInsects AFTER the multiplication with 2 is performed. So 8 is not printed in output but instead 16 (the result of 8*2=16) is printed as the result of first iteration.
So lets change the while loop as follows:
while (numInsects < 100) {
cout << numInsects << " ";
numInsects = numInsects * 2;
Now lets see how it works.
The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100
So the body of while loop executes. cout << numInsects << " "; first prints the value of numInsects i.e. 8. Next numInsects = numInsects * 2; multiplies the value of numInsects i.e 8 with 2. So first 8 is printed on the output screen. Then the multiplication i.e. 8*2=16 is performed as the result of first iteration. So now value of numInsects becomes 16.
Next the while loop condition numInsects < 100 is again checked. It is true again as 16<100. Now cout << numInsects << " "; is executed which prints 16. After this, the multiplication is again performed and new value of numInsects becomes 32 at second iteration. This is how while loops continues to execute.
So this while loop stops when the value of numInsects exceeds 100.
If i wanted to change my phones simcard, does anything need transferring, or is it an easy swap?
Many treadmills output the speed of the treadmill in miles per hour (mph) on the console, but most runners think of speed in terms of a pace. A common pace is the number of minutes and seconds per mile instead of mph. Write a program that starts with a quantity in mph and converts the quantity into minutes and seconds per mile. As an example, the proper output for an input of 6.5 mph should be 9 minutes and 13.8 seconds per mile. If you need to convert a double to an int, which will discard any value after the decimal point, then you may use intValue
Answer:
This question is answered using C++ programming language.
This program does not make use of comments; However, see explanation section for detailed line by line explanation.
The program starts here
#include <iostream>
using namespace std;
int main()
{
double quantity,seconds;
int minutes;
cout<<"Quantity (mph): ";
cin>>quantity;
minutes = int(60/quantity);
cout<<minutes<<" minutes and ";
seconds = (60/quantity - int(60/quantity))*60;
printf("%.1f", seconds);
cout<<" seconds per mile";
return 0;
}
Explanation:
The following line declares quantity, seconds as double datatype
double quantity,seconds;
The following line declares minutes as integer datatype
int minutes;
The following line prompts user for input in miles per hour
cout<<"Quantity (mph): ";
User input is obtained using the next line
cin>>quantity;
The next line gets the minute equivalent of user input by getting the integer division of 60 by quantity
minutes = int(60/quantity);
The next statement prints the calculated minute equivalent followed by the string " minuted and " without the quotes
cout<<minutes<<" minutes and ";
After the minutes has been calculated; the following statement gets the remainder part; which is the seconds
seconds = (60/quantity - int(60/quantity))*60;
The following statements rounds up seconds to 1 decimal place and prints its rounded value
printf("%.1f", seconds);
The following statement prints "seconds per mile" without the quotes
cout<<" seconds per mile";
Following are the program to the given question:
Program Explanation:
Defining the header file.Defining the main method.Inside the method, three double variables "mph, sec, and min_per_mile", and one integer variable "min" is defined. After defining a variable "mph" is defined that inputs value by user-end.After input value, "sec, min_per_mile, and min" is defined that calculates the value and prints its calculated value.Program:
#include<iostream>//header file
using namespace std;
int main()//defining main method
{
double mph,sec,min_per_mile;//defining a double variable
int min;//defining integer variable
cout<<"Enter the speed of the treadmill in mph:";//print message
cin>>mph;//input double value
min_per_mile=(1/mph)*60;//defining a double variable that calculates minutes per mile
min=static_cast<int>(min_per_mile);//defining int variable that converts min_per_mile value into integer
sec=(min_per_mile-min)*60;//defining double variable that calculates seconds per mile value
cout<<"A common pace is the "<<min<<" minutes and "<<sec<<" seconds per mile"<<endl;//print calculated value with message
return 0;
}
Output:
Please find the attached file.
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Type a statement using srand() to seed random number generation using variable seedVal. Then type two statements using rand() to print two random integers between (and including) 0 and 9. End with a newline. Ex: #include < iostream > #include < cstdlib > // Enables use of rand() #include < ctime > // Enables use of time() using namespace std: int main() { int seedVal = 0 /* Your solution goes here */ return 0: }
Answer:
Replace /* Your solution goes here */ with the following code segment
srand(seedVal);
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
Explanation:
From the code segment, the seedVal has already been declared and initialized to 0; The next step is to seed it as random number using srand.
The first line of the code segment in the Answer section "srand(seedVal); " is used to achieve that task.
Having done that, the next step is to write statements to generate the two random numbers using rand();
When generating random numbers, two things are to be noted;
The lower bound; LThe upper bound; UHere, the lower bound is 0 and the upper bound is 9;
C rand() function uses the following syntax to generate random numbers
rand()%(int)(U - L + 1) + L
Where U = 9 and L = 0
Replacing U and L with there respective values; the syntax becomes
rand()%(int)(9 - 0 + 1) + 0
So, the two print statements will be written as
cout<<rand()%(int)(9 - 0 + 1) + 0;
Also, the question states that, each print statement be ended with a new line;
So, the print statements will be
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
Alternatively, by solving (9 - 0 + 1) + 0; the statements can be written as
cout<<rand()%(int)(10)<<endl;
Conclusively, the complete statements is as follows;
srand(seedVal);
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
or
srand(seedVal);
cout<<rand()%(int)(10)<<endl;
cout<<rand()%(int)(10)<<endl;
A security analyst is interested in setting up an IDS to monitor the company network. The analyst has been told there can be no network downtime to implement the solution, but the IDS must capyure all of the network traffic. Which of the following should be used for the IDS implementation?
a. Network tap
b. Honeypot
c. Aggregation
d. Port mirror
Answer:
d. Port mirror
Explanation:
Port mirroring is a method to monitor network traffic and it is used in the Intrusion Detection Systems. It is also called Switched Port Analyzer and is used to analyse the network errors. This technique basically copies the network packets and sends or transmits these copied packed from one port to another in a network device such as a switch. This means that this technique is used to copy the network packets from one switch port and send the copy of these packets to another port where these packets are monitored. This is how it analyses the network errors and incoming traffic for irregular behavior and also this can be done without affecting the normal operation of the switch and other network processes. It is simple, inexpensive and easy to establish and use. The most important advantage of using mirrored ports is that it catches the traffic on several ports at once or can capture all of the network traffic.
Assign True to the variable is_ascending if the list numbers is in ascending order (that is, if each element of the list is greater than or equal to the previous element in the list). Otherwise, assign False with is_ascending.
Answer:
The question seem incomplete as the list is not given and the programming language is not stated;
To answer this question, I'll answer this question using Python programming language and the program will allow user input.
Input will stop until user enters 0
The program is as follows
newlist = []
print("Input into the list; Press 0 to stop")
userinput = int(input("User Input:"))
while not userinput == 0:
newlist.append(userinput)
userinput = int(input("User Input:"))
is_ascending = "True"
i = 1
while i < len(newlist):
if(newlist[i] < newlist[i - 1]):
is_ascending = "False"
i += 1
print(newlist)
print(is_ascending)
Explanation:
This line declares an empty list
newlist = []
This line prompts gives instruction to user on how to stop input
print("Input into the list; Press 0 to stop")
This line prompts user for input
userinput = int(input("User Input:"))
This next three lines takes input from the user until the user enters 0
while not userinput == 0:
newlist.append(userinput)
userinput = int(input("User Input:"))
The next line initialized "True" to variable is_ascending
is_ascending = "True"
The next 5 line iterates from the index element of the list till the last to check if the list is sorted
i = 1
while i < len(newlist):
if(newlist[i] < newlist[i - 1]):
is_ascending = "False"
i += 1
The next line prints the list
print(newlist)
The next line prints the value of is_ascending
print(is_ascending)