How much work is done by a babysitter who uses 8000 W of power to lift a baby in 2s?

Answer:

no it would not. that is an open circuit and it would need to be closed at the switch for current to flow.

Answer:

Hydrosphere and atmosphere

Explanation:

Answer:

B. Fahrenheit measures temperature!

Whenever a body is in motion there is always a friction to oppose the motion.

"Friction is a force that resists the motion of one object against another."

Friction is a force that opposes relative motion between surfaces in contact. One of the simpler characteristics of friction is that it is parallel to the contact surface between surfaces and always in a direction that opposes motion or attempted motion of the systems relative to each other.

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Answer:

90.0N

Explanation:

According to Newtons second law;

F = ma

\sumFx = max

Fm - Ff = max

Given

Moving force Fm = 90.0N

Ff is the frictional force is the mass

ax is the acceleration = 0m/s^2 (constant speed)

Substitute

90 - Ff = 75(0)

90 - Ff = 0

Ff = 90 - 0

Ff = 90.0N

Hence the frictional force is 90.0N

Answer:

A. 8.51x10^-31 kgm/s

B. 1.51mm

Explanation:

We have a∆Py >= h/2

∆Py = uncertainty

a = width

We calculate ∆Py =

1.055x10^-34/2x(0.0620x10^-3)

= 8.51x10^-31 kg m/s

This is the maximum value of uncertainty

B.

h/lambda

Lambda = 585

h = 6.626x10^-34

= 6.626x10^-34 / 585x10^-9

= 1.13x10^-27

From our answer in part a, we solve for the width

8.51x10^-31 / 1.13x10^-27

= 7.53x10^-4

Width = 2 * 7.53x10^-4

= 1.55mm

Please check attachment for the solution I provided

(a) The minimum uncertainty in the vertical component of the momentum of each photon in the beam is [tex]5.33 \times 10^{-30}\;\rm kg.m/s[/tex].

(b) The width of the central diffraction maximum  observed on the screen is [tex]2.48 \times 10^{-4} \;\rm m[/tex].

Given data:

The wavelength of laser light beam is, [tex]\lambda = 585\;\rm nm =585 \times 10^{-9} \;\rm m[/tex].

The width of narrow slit is, [tex]a = 0.0620 \;\rm mm =0.0620 \times 10^{-3} \;\rm m[/tex].

The distance between the slit and screen is, [tex]D = 2.00 \;\rm m[/tex].

(a)

The minimum uncertainty in the vertical component of the momentum of each photon is given as,

[tex]a \times \Delta P =\dfrac{h}{2}[/tex]

Here, h is the Planck's constant.

[tex](0.0620 \times 10^{-3}) \times \Delta P =\dfrac{6.62 \times 10^{-34}}{2}\\\\\Delta P = \dfrac{6.62 \times 10^{-34}}{2 \times (0.0620 \times 10^{-3})}\\\\\Delta P = 5.33 \times 10^{-30}\;\rm kg.m/s[/tex]

Thus, we can conclude that the minimum uncertainty in the vertical component of the momentum of each photon in the beam is [tex]5.33 \times 10^{-30}\;\rm kg.m/s[/tex].

(b)

The width of the central diffraction maximum that is observed on the screen

is obtained by the expression,

[tex]w' = \dfrac{D \times h}{\Delta P}[/tex]

Solving as,

[tex]w' = \dfrac{2.00 \times (6.62 \times 10^{-34})}{5.33 \times 10^{-30}}\\\\w' = 2.48 \times 10^{-4} \;\rm m[/tex]

Thus, we can conclude that the width of the central diffraction maximum  observed on the screen is [tex]2.48 \times 10^{-4} \;\rm m[/tex].

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Explanation:

Given info: The Number of turns in the wire is 580 the diameter of  

tube is [tex]8.00 \mathrm{~cm}[/tex] and the length of the tube up to which wire is wrapped is [tex]36.0 \mathrm{~cm}[/tex].  

Formula to calculate the inductance of the coil is,  

[tex]L=\frac{\mu_{0} N^{2} A}{l}[/tex]  

Here,  

[tex]L[/tex] is inductance of the coil.  

[tex]\mu_{0}[/tex] is the permittivity.  

[tex]N[/tex] is the number of turns.  

[tex]l[/tex] is the length up to which wire is wrapped.  

[tex]A[/tex] is the cross sectional area of the coil.  

The expression for the area is,  

[tex]A=\frac{\pi d^{2}}{4}[/tex]

Substitute [tex]\frac{\pi d^{2}}{4}[tex] for [tex]A[/tex] in equation (1).  

[tex]L=\frac{\left(\mu_{0} N^{2}\right) \frac{d d^{2}}{4}}{l}[/tex]

Substitute 580 for [tex]N, 4 \pi \times 10^{-7}[tex] for [tex]\mu_{0}, 8.00 \mathrm{~cm}[tex] for [tex]d[tex] and [tex]36.0 \mathrm{~cm}[tex] for [tex]l .[/tex]  

[tex]\begin{array}{c}  

=\frac{4 \pi \times 10^{-7} \times 580 \times 580 \times \frac{x(8.00 \mathrm{~cm} \times 8.00 \mathrm{~cm})}{4}}{36 \mathrm{~cm}} \\  

=5.90 \mathrm{mH}  

\end{array} [/tex]

Conclusion:  

Therefore, the inductance of the given single conductor wire is  

[tex]5.90 \mathrm{mH} .[/tex]

Given info: The rate of increasing current [tex]4.00 \mathrm{~A} / \mathrm{s}[/tex] and the inductance of the coil [tex]5.90 \mathrm{mH}[/tex].

The generated emf is,

[tex]

\varepsilon=L \frac{d i}{d t}

[/tex]

Here,

[tex]\varepsilon[/tex] is the generated emf.

[tex]L[tex] is the inductance of the coil.

[tex]\frac{d i}{d t}[tex] is the rate of change of current.

Substitute [tex]5.90 \mathrm{mH}[tex] for [tex]L[tex] and [tex]4.00 \mathrm{~A} / \mathrm{s}[tex] for [tex]\frac{d i}{d t}[/tex]

[tex]\begin{array}{c}

\varepsilon=5.90 \mathrm{mH} \times 4.00 \mathrm{~A} / \mathrm{s} \\

= & 23.6 \mathrm{mV}

\end{array}[/tex]

Conclusion:

Therefore, the generated emf is [tex]23.6 \mathrm{mV}[/tex].

Answer:

It's the Pendulum, it is because during its to and fro motion, it vibrates and simulataneously exhibit kinetic energy.

Explanation:

:)

Answer:

bouncing ball bc it has kinetic energy. the pendulum has potential energy.

Explanation:

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Power and Energy.

As a pendulum swings from the bottom position to the top position, it gains a height which means it gains the Potential energy.

hence we can say that, kinetic energy is changed into potential energy.

So, the Option A.) is correct.

Answer:

I think it's A)

Explanation:

it could be wrong i don't know hope it's not good luck!

Answer:

Newtons 1st law of inertia

Explanation:

Explanation:

probably the 1st law of motion, it'll continue at in a straight line as long as no external force is added or the net force equals to zero, same for the centrifugal force and the gravitational force

Answer:

Equal to 30°C.

Explanation:

The final temperature of both objects are equal to 30°C because of the conduction heat from one object to another. Both objects have same mass of 2 kg and both were isolated from the external environment so conduction of heat occurs from the more hotter body to the less hotter body until the temperature of both objects are equal to each other.

The final temperature of both objects is less than 30° C

The specific heat of an object is the minimum required quantity of heat needed to raise the temperature of 1 gram of the object(substance) by 1° C.

From the parameters given:

Using the Calorimetry principle, we need to understand that the heat lost by an object at a high temperature is proportionally equal to that heat gained by the object at a low temperature.

i.e.

[tex]\mathbf{Q_{lost}= Q_{gain}}[/tex]

[tex]\mathbf{ms_B \Big[40^0 \ C - \theta_o\Big]= ms_A \Big [ \theta_o - 20^0 \ C \Big]}[/tex]

Given that:

Then, let us consider a scenario where [tex]\mathbf{S_A = 1.5S_B}[/tex]

Thus;

[tex]\mathbf{S_B \Big[40^0 \ C - \theta_o\Big]= 1.5S_B \Big [ \theta_o - 20^0 \ C \Big]}[/tex]

[tex]\mathbf{40^0 \ C - \theta_o= 1.5 \theta_o - 20^0 \ C}[/tex]

[tex]\mathbf{ 2.5\theta_o= 70^0 \ C}[/tex]

[tex]\mathbf{ \theta_o= \dfrac{70^0 \ C}{2.5}}[/tex]

[tex]\mathbf{ \theta_o=28 ^0 C}[/tex]

Therefore, we can conclude that since the specific heat of object A is larger than that of object B i.e. [tex]\mathbf{S_A> S_B}[/tex], then the final temperature [tex]\mathbf{ \theta_o<30 ^0 C}[/tex]

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The correct answer is (A) 8.3mm.

The total displacement will be the vector sum of the two displacements given in the question.

let the displacement to the south represent vector A = 5mm in magnitude directed toward south.

let the displacement to the south-west represent vector B = 4mm in magnitude directed toward south-west.

The angle between vector A and vector B is 45°, the angle between south and south-west.

SO the resultant

R = vectro A + vector B

[tex]R=\sqrt{A^{2}+B^{2}+2ABcos(45) } \\\\R=\sqrt{25+16+40*\frac{1}{\sqrt{2} } } \\\\R=8.3mm[/tex]

The ant's displacement is 8.3 mm in magnitude.

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Answer:

d. remains same​

Explanation:

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Force = mass * acceleration

[tex] Acceleration = \frac {Force}{mass} [/tex]

If both the mass of the body and the force acting on it are doubled, then acceleration remains the same​.

Given the following data;

Mass = 2Mass

Force = 2Force

Substituting into the formula, we have;

[tex] Acceleration = \frac {2Force}{2Mass} [/tex]

[tex] Acceleration = \frac {Force}{Mass} [/tex]

Answer:

That's almost the true

Explanation:

it does not happen all the time

The answer is A: Repel More Strongly

Explanation: I took the test but two alike magnets will push away form each other

Answer:

D

Explanation:

my instinct tell me so, that's why I chose D

Answer:

6.621 minutes per mile  

Explanation:

the .621 is repeating

Answer:

there are no pictures attached.

Answer:

Dynamic equilibrium

Explanation:

This is because dynamic equilibrium is when the body is set on motion at constant velocity. When humans are walking, when achieve unstable equilibrium that is not static or dynamic on the first foot and a non equilibrium when the other foot is involved. In human movement,it is at constant velocity and the Total number of forces acting is zero. This type of equilibrium always return to it's initial point after disturbances since humans did not continually walk all the time .

Answer:

the answer is D

Explanation:

just took the test

Answer:

  λ = 6 10⁻⁷ m, color orange

Explanation:

This problem is about the interference phenomenon, constructive interference occurs when the path difference is equal to an integer number of wavelengths

          d sim θ = m λ

Let's use trigonometry, remembering that the angles for these experiments are very small.

          Sin θ = y / L

          tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ

          sin θ = y / L

we substitute

         [tex]d \ \frac{y}{L} = m \lambda[/tex]

A) Donut length is requested

        λ = [tex]\frac{d \ y}{m \ L}[/tex]

let's calculate

        λ = 5 10⁻⁵ 0.06 /( 1  5)

        λ = 6 10⁻⁷ m

B) let's express the wavelength in nm

      λ = 6 10⁻⁷ m = 600 nm

this corresponds to the color orange

Answer:

[tex]f= 3.0 \times 10 {}^{8} \div 7.0 \times 10 {}^{7} \\ f = 4.28hz[/tex]

Given

Answer:

low pressure systems

Explanation:

with a low pressure system over the area the storm can't form

Answer:

the three major elements of language include form, content, and use. form involves three sub-components of syntax, morphology, and phonology. content is also known as semantics and use can be known as pragmatics.

Explanation:

hope this helps! :)

Answer:

14 secs and velocity will be 48

Explanation:

Answer:

C. Decreasing the pressure

Explanation:

Answer:

the total force vector, on test charge is points from origin to point C( 1, 1 )

Explanation:

Given the data in the question, as illustrated in the image below;

from the Image, OA = 1, OB = AC = 1

so using Pythagoras theorem

a² = b² + c²

a = √( b² + c² )

so

OC = √( OB² + AC² )

we substitute

OC = √( OA² + AC² )

OC = √( 1² + 1² )

OC = √( 1 + 1 )

OC = √2

Coordinate of C( 1, 1 )

Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )

Answer:

The correct response is "54.19 kg".

Explanation:

The given values are:

Force,

F = 500 N

Coefficient of static friction,

μ = 0.61

Angle,

[tex]\Theta = 25^{\circ}[/tex]

As we know,

⇒  [tex]F_x=F= \mu_s.N[/tex]

then,

⇒  [tex]FCos \Theta=\mu_s(mg+FSin \Theta)[/tex]

On substituting the given values, we get

⇒  [tex]500Cos(25^{\circ})=0.61[m(9.81)+500 Sin25^{\circ}][/tex]

On substituting the values of Cos and Sin, we get

⇒  [tex]453.154=0.61(9.81m+211.31)[/tex]

⇒  [tex]453.154=5.9842m+128.8991[/tex]

⇒  [tex]453.154-128.8991=5.9842m[/tex]

⇒                  [tex]324.2549=5.9842m[/tex]

⇒                            [tex]m=\frac{324.2549}{5.9842}[/tex]

⇒                            [tex]m=54.19 \ kg[/tex]