Answers
Answer:
B. 2/6
Step-by-step explanation:
A fair ordinary dice has 6 sides.
The numbers 4 or 5 on the dice are 2 numbers out of 6 total numbers.
2/6
Answer:
B. 2/6
Step-by-step explanation:
A ordinary dice has 6 sides.
4 and 5 make 2 sides.
So the answer will be 2/6
Related Questions
Samuel wants to estimate what 5843 x .00243 is. What should his first step be?
Answers
What is 2+2 I have no idea please help
Answers
Answer:
2+2=4
Step-by-step explanation:
2+2=4
good question like if you have two chocolates and your mom gives you two more than there will be 4 and they will be too delicious
i hope this will help you :)
have a great day
Answer:
2+2=4
Step-by-step explanation:
So you take the 2 numbers 2+2 and you use your finger counting to get to 4. It’s really hard mathematics but you’ll get there. Have a great day!
Your friend is having trouble solving word problems. Create a word problem of your own and provide the answer along with a detailed explanation of how you solved your equation.
Answers
Step-by-step explanation:
Places A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the car travel in the same direction at different speeds, they meet in 5 hours. If they travel towards each other, they meet in 1 hour. What are the speeds of the two cars?
Solution :
Let “x km/hr” be the speed of 1st car
Let “y km/hr” be the speed of the 2nd car
Time = Distance/Speed
Speed of both cars while they are traveling in the same direction = (x – y)
Speed of both cars while they are traveling in the opposite direction = (x + y)
5 = 100/(x -y)
x – y = 100/5
x - y = 20
x - y - 20 = 0 ---(1)
1 = 100/(x + y)
x + y = 100
x + y - 100 = 0--b----(2)
x/(100 + 20) = y/(-20 + 100) = 1/(1 + 1)
x/120 = y/80 = 1/2
x/120 = 1/2 y/80 = 1/2
x = 120/2 y = 80/2
x = 60 y = 40
So, the speed of first car = 60 km/hr
Speed of second car = 40 km/hr
Hi, if it's possible to answer this now, Thank you so much. If you don't know the answer, that's ok :D
Answers
Answer:
5x4^10
Step-by-step explanation:
Hope this helps have a nice day :)
Answer:
5. [tex]4^{9}[/tex]
Step-by-step explanation:
There is a common ratio r between consecutive terms, that is
r = 20 ÷ 5 = 80 ÷ 20 = 320 ÷ 80 = 4
This indicates the sequence is geometric with n th term
[tex]a_{n}[/tex] = a . [tex]r^{n-1}[/tex]
Here a = 5 and r = 4 , thus
[tex]a_{10}[/tex] = 5. [tex]4^{9}[/tex]
PLEASE HELP IMA MARK BRAINLIST
Answers
Answer:
53
Step-by-step explanation:
Explicit Formula: an = a1 + d(n - 1)
Simply plug in your known variables:
an = 8 + 3(n - 1)
Then plug in 16 for n:
a(16) = 8 + 3(16 - 1)
a(16) = 8 + 3(15)
a(16) = 8 + 45
a(16) = 53
Answer:
53
Step-by-step explanation:
an = dn + (a - d)
an = 3n + 8 - 3
an = 3n + 5
Put n as 16 and solve.
3(16) + 5
48 + 5
= 53
The population, P (t), of an Ontario city is modeled by the function p(t) = 14t^2 + 650t + 32,000. If t = 0 corresponds to the year 2,000. When was the population 25,000?
Answers
Answer:
The population of the city was 25,000 in 1970 and 1983.
Step-by-step explanation:
In order to find the year at which the population was 25,000 we need to make p(t) equal to that number and solve for t as shown below.
[tex]25000 = 14*t^2 + 650*t + 32000\\14*t^2 + 650*t + 7000 = 0\\t^2 + 46.43*t + 500 = 0\\t_{1,2} = \frac{-46.43 \pm \sqrt{(46.43)^2 - 4*1*500}}{2}\\t_{1,2} = \frac{-46.43 \pm \sqrt{155.75}}{2}\\t_{1,2} = \frac{-46.43 \pm 12.48}{2}\\t_1 = \frac{-33.95}{2} = -16.98\\t_2 = \frac{-58.91}{2} =- 29.5[/tex]
Since t = 0 corresponds to the year 2000, then t1 = 1983 and t2 = 1970.
Mei Su had 80 coins. She gave most of them to her friends in such a way that each of her friends got at least one coin and no two of her friends got the same number of coins. What is the largest number of friends to whom Mei Su could have given coins?
Answers
Answer: 12 friends.
Step-by-step explanation:
the data we have is:
Mei Su had 80 coins.
She gave the coins to her friends, in such a way that every friend got a different number of coins, then we have that:
The maximum number of friends that could have coins is when:
friend 1 got 1 coin
friend 2 got 2 coins
friend 3 got 3 coins
friend N got N coins
in such a way that:
(1 + 2 + 3 + ... + N) ≥ 79
I use 79 because "she gave most of the coins", not all.
We want to find the maximum possible N.
Then let's calculate:
1 + 2 + 3 + 4 + 5 = 15
15 + 6 + 7 + 8 + 9 + 10 = 55
now we are close, lets add by one number:
55 + 11 = 66
66 + 12 = 78
now, we can not add more because we will have a number larger than 80.
Then we have N = 12
This means that the maximum number of friends is 12.
Answer:
12
Step-by-step explanation:
my
Erin travels north and south from Main Station. The distance, in km, of the train from Main Station is
modeled by the function d(t) = t3 - 9t2 + 6t, where North is positive and South is negative. Time
elapsed after the start of a shift, in hours, is represented by t, where t € (0,12]. 'If the shift starts at
noon, determine at which time(s) the train is more than 16 km south of Main Station.
Answers
Answer:
The times are t = 9, t = 10, t = 11 and t = 12
Step-by-step explanation:
For the train to be more than 16 km South and since south is taken as negative,
d(t) > -16
t³ - 9t² + 6t > -16
t³ - 9t² + 6t + 16 > 0
Since -1 is a factor of 16, inserting t = -1 into the d(t), we have
d(-1) = (-1)³ - 9(-1)² + 6(-1)+ 16 = -1 - 9 - 6 + 16 = -16 + 16 = 0. By the factor theorem, t + 1 is a factor of d(t)
So, d(t)/(t + 1) = (t³ - 9t² + 6t + 16)/(t +1) = t² - 10t + 16
Factorizing t² - 10t + 16, we have
t² - 2t - 8t + 16
= t(t - 2) - 8(t - 2)
= (t -2)(t - 8)
So t - 2 and t - 8 are factors of d(t)
So (t + 1)(t -2)(t - 8) > 0
when t < -1, example t = -2 ,(t + 1)(t -2)(t - 8) = (-2 + 1)(-2 -2)(-2 - 8) = (-1)(-4)(-10) = -40 < 0
when -1 < t < 2, example t = 0 ,(t + 1)(t -2)(t - 8) = (0 + 1)(0 -2)(0 - 8) = (1)(-2)(-8) = 16 > 0
when 2 < t < 8, example t = 3 ,(t + 1)(t -2)(t - 8) = (3 + 1)(3 -2)(3 - 8) = (4)(1)(-5) = -20 < 0
when t > 8, example t = 9,(t + 1)(t -2)(t - 8) = (9 + 1)(9 -2)(9 - 8) = (10)(7)(1) = 70 > 0
Since t cannot be negative, d(t) is positive in the interval 0 < t < 2 and t > 8
Since t ∈ (0, 12]
In the interval 0 < t < 2 the only value possible for t is t = 1
d(1) = t³ - 9t² + 6t = (1)³ - 9(1)² + 6(1) = 1 - 9 + 6 = -2
Since d(1) < -16 this is invalid
In the interval t > 8 , the only possible values of t are t = 9, t = 10.t = 11 and t = 12.
So,
d(9) = 9³ - 9(9)² + 6(9) = 0 + 54 = 54 km
d(10) = 10³ - 9(10)² + 6(10) = 1000 - 900 + 60 = 100 +60 = 160 km
d(11) = 11³ - 9(11)² + 6(11) = 1331 - 1089 + 66 = 242 + 66 = 308 km
d(12) = 12³ - 9(12)² + 6(12) = 1728 - 1296 + 72 = 432 + 72 = 504 km
A bank is advertising that new customers can open a savings account with a 2% interest rate compounded annually. Kristy invests $3000 in an account at this rate. If she makes no additional deposits or withdrawals on her account, find the amount of money she will have after 5 years. A.)1020.21 B.)2274.57 C.)3312.24 D.)4158.18
Answers
Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximations). The figures below are based on semicircles or quarter circles and problems b), c), and d) are involving portions of a square.
Answers
Answer:
The area of the shaded region = (36·π - 72) cm²
The perimeter of the shaded region = (6·π + 12·√2) cm
Step-by-step explanation:
The given figure is a sector of a circle and a segment of the circle is shaded
We have that since the arc AC subtends an angle 90° at the center of the circle, the sector is a quarter of a circle, which gives;
Area of sector = 1/4×π×r²
As seen the radius, r = AB = 12 cm
∴ Area of sector = 1/4×π×12² = 36·π cm²
The area of the segment AB = Area of sector ABC - Area of ΔABC
Area of ΔABC = 1/2×Base ×Height =
Since the base and the height = The radius of the circle = 12 cm, we have;
Area of ΔABC = 1/2×12×12 = 72 cm²
The area of the segment AB = 36·π cm² - 72 cm² = (36·π - 72) cm²
The area of the shaded region = The area of the segment AB = (36·π - 72) cm²
The perimeter of the shaded region = 1/4 perimeter of the circle with radius r + Line Segment AC
The perimeter of the shaded region = 1/4 × π × 2 × r + √(12² + 12²) = 1/4 × π × 2 × 12 + 12·√2 = (6·π + 12·√2) cm
2) A girl starts from a point A and walks 285m to B on a bearing of 078°. She then walks due south to a point C which is 307m from A. What is the bearing of A from C , and is the distance |BC| ?
Answers
Answer:
bearing of A from C is - 65.24°
the distance |BC| is 187.84 m
Step-by-step explanation:
given data
girl walks AB = 285 m (side c)
bearing angle B = 78°
girl walks AC = 307 m (side a)
solution
we use here the Cosine Law for getting side b that is
ac² = ab² + bc² - 2 × ab × cos(B) ...............1
307² = 285² + x² - 2 × 285 cos(78)
x = 187.84 m
and
now we get here angle θ , the bearing from A to C get by law of sines
sin (θ) = [tex]\frac{187.84}{307} \times sin(78)[/tex]
sin (θ) = 0.5985
θ = 36.76°
and as we get here angle BAC that is
angle BCA = 180 - ( 36.76° + 78° )
angle BCA = 65.24°
and here negative bearing of A from C so - 65.24°
Please Help Me i beg
Answers
Answer:
B is P(x)=(x-3)^2 +2
C is P(x)=(x-1)^2 -5
Step-by-step explanation:
i think i am right
At a college there are 120 freshmen, 90 sophomores, 110 juniors, and 80 seniors. A school administrator selects a random sample of 12 of the freshmen, a random sample of 9 of the sophomores, a random sample of 11 of the juniors, and a random sample of 8 of the seniors. She then interviews all the students selected. Identify the type of sampling used in this example.
Answers
Answer:
Stratified sampling
Step-by-step explanation:
The is a type of sampling in which the population of interest is divided into subpopulations and then each subpopulation is randomly sampled.
In this case study, instead of just doing a random sampling of all students, the research divided the population of all students into subpopulations which includes freshmen, sophomores, juniors and seniors and then she makes a random sampling of each of these subpopulations.
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Answers
Answer:
second option
Step-by-step explanation:
Given
[tex]x^{4}[/tex] + 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ± [tex]\sqrt{-1}[/tex] = ± i ( noting that [tex]\sqrt{-1}[/tex] = i ), and
x² = - 5 ( take the square root of both sides )
x = ± [tex]\sqrt{-5}[/tex] = ± [tex]\sqrt{5(-1)}[/tex] = ± [tex]\sqrt{5}[/tex] × [tex]\sqrt{-1}[/tex] = ± i[tex]\sqrt{5}[/tex]
Solutions are x = ± i and x = ± i[tex]\sqrt{5}[/tex]
If f(x) = –x2 + 3x + 5 and g(x) = x2 + 2x, which graph shows the graph of (f + g)(x)?
Answers
Answer:
The answer is
the last graphStep-by-step explanation:
To find the graph which shows (f + g)(x) we must first find (f + g)(x)
That's
f(x) = - x² + 3x + 5
g(x) = x² + 2x
To find (f + g)(x) add g(x) to f(x)
That's
(f + g)(x) = -x² + 3x + 5 + x² + 2x
Group like terms
(f + g)(x) = - x² + x² + 3x + 2x + 5
We have (f + g)(x) as
(f + g)(x) = 5x + 5
Since (f + g)(x) is linear the graph which shows (f + g)(x) is the last graph
Hope this helps you
Answer:
last graph or D
Step-by-step explanation:
If a function is defined by the equation y=5x−5, which equation defines the inverse of this function?
Answers
Answer:
[tex]\displaystyle y = \frac{1}{5}x+1[/tex]
Or:
[tex]x + 5 = 5y[/tex]
Step-by-step explanation:
We have the function:
[tex]y=5x-5[/tex]
And we want to find its inverse.
To find the inverse of a function, we:
Flip x and y. And solve for y.Hence:
[tex]x=5y-5[/tex]
Solve for y. Add:
[tex]\displaystyle x + 5 = 5y[/tex]
Divide:
[tex]\displaystyle y = \frac{x+5}{5}[/tex]
Simplify. Hence:
[tex]\displaystyle y = \frac{1}{5}x+1[/tex]
In conclusion, the inverse function is:
[tex]\displaystyle y = \frac{1}{5}x+1[/tex]
Leslie went out for a jog. When she returned she went to the tap and filled up her 500 mL reusable water bottle. She drank 250 mL at a constant rate in one minute. Her phone rang, she set down the bottle of water and talked to her friend for four minutes. After her phone call she sipped the rest of her bottle at a constant rate in two minutes. Create a voulme vs. time graph for this story.
Answers
Answer:
Please find attached the required graph and
Step-by-step explanation:
The values for the information given can be written down as follows;
Time, seconds Volume mL
0, 500
12, 450
24, 400
36, 350
48, 300
60, 250
72 250
84 250
96 250
108 250
120 250
132 250
144 250
156 250
168 250
180 250
192 250
204 250
216 250
228 250
240 250
252 250
264 250
276 250
288 250
300 250
312 225
324, 200
336, 175
348, 150
360, 125
372, 100
384, 75
396, 50
408, 25
420, 0
A group of 4 friends are posing for a photograph. If 2 of the friends want to stand beside each other, how many ways can the picture be taken? 6,10,12,20
Answers
Answer:
6
Step-by-step explanation:
If 2 of the friends wants to stand beside each other, we can take these 2 friends like 1 option and calculated the number of ways, using the rule of multiplication as:
__ 3_____ * ____2_____ *____1____ = 6
1st place 2nd place 3rd place
Because we have 3 options (2 friends and the friends that are beside each other) for the first place of the picture, 2 options for the second and 1 option for the third.
Simplify fully
e x e x e x e x f ÷ e x e x e x f x f
Answers
Answer:
e/f
Step-by-step explanation:
Common factors in the numerator and denominator cancel.
[tex]\dfrac{e\times e\times e\times e\times f}{e\times e\times e\times f\times f}=\dfrac{e}{e}\times\dfrac{e}{e}\times\dfrac{e}{e}\times\dfrac{e}{f}\times\dfrac{f}{f}=1\times1\times1\times\dfrac{e}{f}\times1=\boxed{\dfrac{e}{f}}[/tex]
The required simplification of the expression is [tex]\dfrac{e}{f}[/tex].
We have to the given expression, e x e x e x e x f ÷ e x e x e x f x f.
The given expression is simplify in the following steps given below.
Expression; [tex]\dfrac{e \times e \times e \times e \times f}{e \times e \times e \times f \times f}[/tex]
Then,
The simplification of the given expression,
[tex]=\dfrac{e \times e \times e \times e \times f}{e \times e \times e \times f \times f}\\\\[/tex]
Cancel out the same term from denominator and numerator,
[tex]= \dfrac{e}{f} \times \dfrac{e}{f} \times \dfrac{e}{f} \times \dfrac{e}{f} \times \dfrac{f}{f} \\\\= 1 \times 1 \times 1 \times \dfrac{e}{f} \times 1 \\\\= \dfrac{e}{f}[/tex]
Hence, The required simplification of the expression is [tex]\dfrac{e}{f}[/tex]
To know more about Multiplication click the link given below.
https://brainly.com/question/16871801
a) A graph is drawn below.
Explain how you know that y is not directly proportional to x.
Answers
Step-by-step explanation:
y isn't directly proportional with x because the graph doesn't cross O the origin, it starts from a y-intercept wich is not a property for proportional portions
adjust number into correct standard form, 6552× 10(tex)1 Please answer
Answers
Answer:
6.552×10³×10
6.552×10^3+1
6.552×10^4 is the standard form
i hope this will help you :)
HELPPP ME PLEASEEEEEEEEE
Answers
Answer:
7. a = 50 degrees
b = 50 degrees
c= 50 degrees
d = 75 degrees
8.
Step-by-step explanation:
7.
a. Vertically opposite angles are equal
b. Vertically opposite angles are equal
c Alternate angles
d. Angles on a straight line.
8. 45 + 45 + 65 + 35 + 40 + 30 = 200m
Hope this helps
out of 8000 students of Chitwan district 10% take tuition in various subject before the SLC examination. Among them 40% take tuition in English only,20% in math only and 80 students in other subject. Compare the number of students who take tuition on both subject and the total number of students.
Answers
Answer:
Out of 8000 students, 10% take tuition in various subjects before the exam.
10% of 8000 is:
10/100 * 8000 = 800
Among the 800, 40% take tuition in English only and 20% take tuition in Math only.
80 students take tuition in other subjects, therefore, in percentage:
80/800 * 100 = 10%
Therefore, the percentage of students that take tuition in both Math and English is:
100% - (40% + 20% + 10%) = 100% - 70% = 30%
30% of the 800 students take tuition in both subjects. That is:
30/100 * 800 = 240 students
Therefore, among the 8000 students in the district, only 240 take tuition in both English and Math.
In percentage:
240/8000 * 100 = 3%
3% of students take tuition in both English and Math.
In Ratio:
3 : 100
3 out of 100 students take tuition in English and Math.
PLEASE HELP ASAP!!!! what is 3/5x + 22 = 28? Explain!
Answers
i did this for homework
(please help) List the three lowest numbers that have the following characteristics. Work must be shown. 60 is a multiple of the number 3 is a factor of the number 4 is not a factor of the number
Answers
Answer:
3, 6, and 15
Step-by-step explanation:
Notice that if 60 is a multiple, the numbers in question could have the same factors as 60.
So let's look at 60's prime factors:
60 = 2 * 2 * 3 * 5
we also know that 3 is a factor, so the factor 3 must be included in all three options, we also know that 4 is NOT a factor, so both factors 2 cannot be included (but only one of them could).
So, in order to build the lowest possible numbers that verify such conditions, we can use:
3
3 * 2 = 6
since 3 or 2 cannot be repeated, the next smaller would be:
3 * 5 = 15
Which ordered pair is a solution to the system of inequalites graphed here?
Answers
Answer:
B. (2, 2)
Step-by-step explanation:
In order for the coordinate to be a solution of the systems of inequalities, it has to be in the shaded region (not on the line since both are dotted). Only B fits in the shaded region.
Add the sum of (−5.4) and 8.2 to the opposite of (−2 3/4 ).
Answers
Answer:2
Step-by-step explanation:
-5.4+8.2=14/5 and then opposite of -2 3/4 is 2.
Solve (x - 4)2 = 5.
O A. x-5+
O B. * = 41.5
O C. X = 9 and x = -1
O D. X=-4115
Answers
Answer:
x=4_+√5option B is the correct option.
Solution,
[tex] {(x - 4)}^{2} = 5 \\ [/tex]
x-4=_+√5
X=4_+√5
Hope this helps...
Good luck on your assignment...
Answer:
(x-4)^2 =5
x^2-16=5
x^2=5+16
x^2=21
√x^2=√21
x=√21
Step-by-step explanation :
First of all open the bracket which has square
Secondly change the position of 16
Note: when a number changes its place , the symbol also changes
then when you get the value take the square root on both sides
and you'll get the answer
Prove that (〖sin〗^2 θ)/(1+cosθ)=1-cosθ
Answers
Answer:
proved
Step-by-step explanation:
prove that : (sin^2 θ)/(1+cosθ)=1-cosθ
(sin^2θ)*(1−cosθ)/(1+cosθ)(1+cosθ) =
sin^2Ф)(1-cosФ)/1-cos^2Ф since 1-cos^2Ф=sin^2Ф then:
(sin^2Ф)(1-cosФ)/sin^2Ф =
1-cosФ (sin^2Ф/sin^Ф=1)
proved
Answer:
Step-by-step explanation:
take it befor delete
The UK has an area of 243,610km2 and a population of 6.41 x 107. Calculate the population density the United Kingdom. Answer to the nearest whole person and give your answer in standard form, such as a x 10b where you are required to enter the values of A and B
A =
B =
Answers
Answer: Population density the United Kingdom [tex]=2.63\times10^2[/tex]
A= 2.63
B= 2
Step-by-step explanation:
We know that, to calculate the population density, we will divide the population by the size of the area.
i.e. [tex]\text{Population density}=\dfrac{\text{Population size}}{\text{Area}}[/tex]
Given : Area of UK = 243,610 km²1
Population = [tex]6.41 \times 10^7[/tex]
Then, the population density the United Kingdom would be :
[tex]\text{Population density}=\dfrac{6.41 \times 10^7}{243,610}\\\\=\dfrac{64100000}{243610}=263.125487459\\\\\approx263=2.63\times10^2[/tex]
On comparing to [tex]A\times10^B[/tex], we get
A= 2.63
B= 2