Given the equation y ^2 − 4y = 3, what constant must be added to both sides so the left side is the square of a binomial?

Answers

Answer 1

Answer:

4

Step-by-step explanation:

y² − 4y = 3

y² - 2*2*y =3

y² - 2*2*y  += 3 +

(y - 2)² = 3 + 4

Answer 2
the constant that must be added is 4. that’s your answer.

Related Questions

A point located at (6, 4) is reflected over the x-axis. What are the coordinates of the image?
(6,4)
(-6,-4)
(-6,4)
(-4, 6)​

Answers

Answer:

(6,-4)

Step-by-step explanation:

Reflecting over the x axis means flipping the point or line over it. Therefore the point's y value would the opposite from the beginning.

Answer:

(6, -4)

Step-by-step explanation:

For any point reflected over the x-axis, the x-coordinate stays the same and the y-coordinate becomes negative.

6 stays the same

4 becomes -4.

I'm always happy to help :)

jed needs to estimate the value of 4.32x10^-4

Answers

Answer:

0.000432

Step-by-step explanation:

Since we have a negative exponent 4 with a base of 10, we simply just move the decimal place 4 places to the left. When you do so, fill in your remaining zeros and you should get your answer.

Answer:

0.000432

Step-by-step explanation:

4.32ₓ10⁻⁴ =

= 4.32ₓ1/10000

= 4.32/10000

= 0.000432

Find the volume of a pyramid with a square base, where the area of the base is
14.1 in' and the height of the pyramid is 11.1 in. Round your answer to the nearest
tenth of a cubic inch.

Answers

I think its 57.17 or about 52.2cubic inch

You want to design a survey to determine how much money people are willing to spend
on concert tickets. Which of the following methods would be most practical and have
the least bias?
Choose 4 neighborhoods at random and poll every home in those
neighborhoods.
Poll 10% of the homes in the area chosen at random.
Poll the first 100 people who enter the mall.
Poll everyone in the area.

Answers

Answer:

The correct option is;

Choosing 4 neighborhoods at random and poll every home in those neighborhoods

Step-by-step explanation:

Given that the survey relate to how much money people are willing to spend on on concert tickets with the goal of being practical and unbiased, we have;

Required sampling = Random Sampling

The preferable type of random sampling is either;

1) Simple random sampling

Sampling a given percentage of the homes in the area randomly

2) Clustered random sampling

Completely polling entire population of randomly selected area

Given the practicability of sampling concert goers, since people may have different interests, a better representative sample will be to perform the clustered random sampling approach by choosing 4 neighborhoods at random and poll every home in those neighborhoods.

Triangle △ABC has an altitude CD . Which of the three points, A, B, D are between the other two if angles A and B are both acute?

Answers

Hi!

Out of the three points D is between the other two acute angles if A and B are both acute.

Hope this helps!

D is point lies between A and B.

Triangle △ABC has an altitude CD.
angles A
and B are both acute.

What is altitude?

Altitude is perpendicular bisector to side of triangle from opposite vertex of triangle.

Since △ABC
A
and B are acute angles, and that altitude CD has one vertex at c and other is between A and B i.e. D

Thus, the required point of Altitude CD D lies between A and B.

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Which choice shows the image of quadrilateral WXYZ after a reflection over the y-axis followed by a translation down 2 units?

Answers

Answer:

Choices are not provided, but you can answer the question as follows: take the coordinates of quadrilateral WXYZ and apply:

W(xW, yW) -> W'(-xW, yW-2)

X(xX, yX) -> X'(-xX, yX-2)

Y(xY, yY) -> Y'(-xY, yY-2)

Z(xZ, yZ) -> Z'(-xZ, yZ-2)

For example, if point W is located at (1, 1), W' would be located at (-1, -1)

Step-by-step explanation:

Reflection over the y-axis transforms point (x, y) into (-x, y)

Translation down 2 units transforms point (x, y) into (x, y-2)

Answer:

The first choice hope this helps :)

Step-by-step explanation:

PLEASE HELP WILL MARK BRAINLIEST Simplify by removing parentheses​ and, if​ possible, combining like terms. 6m-2(-7m+3)

Answers

Answer:

20m-6

Step-by-step explanation:

[tex]6m-2(-7m+3)=\\6m+14m-6=\\20m-6[/tex]

Answer:

20m - 6

Step-by-step explanation:

6m - 2(-7m + 3)

Expand brackets.

6m + 14m - 6

Add like terms.

20m - 6

Please help with this

Answers

Answer:

5/2

Step-by-step explanation:

We take the ratio of a side of ABC over the same side on DEF

AB/ DE

35/14

Divide top and bottom by 7

5/2

A merchant has coffee worth $30 a pound that she wishes to mix with 20 pounds of coffee worth $60 a pound to get mixture that can be sold for $50 a pound. How many pounds of the $30 coffee should be used?

Answers

13 1/3 pounds of coffee should be used
13 1/2 pounds of coffee should be used

What is the maximum number of y-intercepts a line can have?
I will mark brainliest!

Answers

Answer:

one

Step-by-step explanation:

The maximum number of y intercepts a line can have is one

A line can only cross the y axis one time

A line can only cross the x axis one time

Otherwise it is not linear

Identify the explicit function for the sequence in the table.

Answers

Answer:C

Step-by-step explanation: substitute n=3 for all equations and see which equation accurately correlates to the graph for when x=3. When you do this you see that only option C is the correct equation

Answer:

C). [tex]a(n) = 7 + (n - 1) * 12[/tex]

Step-by-step explanation:

Plugin values into the equation.

Find the missing side length and angles of △ABC given that m∠A=56∘, b=9, and c=11. In triangle A B C, side A B is 11 units long, side A C is 9 units long, and side B C is labeled a. Angle A measures 56 degrees.

Answers

Answer:

1) Side a = 9.55

2) Angle B = 51.36°

3) Angle C = 72.67°

Step-by-step explanation:

We would be solving the above questions using Law of Cosines

1) To find Side a using Law of cosines

a² = b² + c² - 2bc × Cos A

a = √(b² + c² - 2bc × Cos A)

a = unknown

b = 9

c = 11

Angle A = 56°

a = √(9² + 11² - 2 × 9 × 11 × Cos 56°

a = 9.55405

Approximately a = 9.55

2) To find Angle B

We would use the Law of Cosines as well

b² = a² + c² - 2ac × Cos B

Cos B = a² + c² - b²/2ac

B = arc cos ( a² + c² - b²/2ac)

a = 9.55

c = 11

b = 9

B = arc cos (9.55² + 11² - 9²/2 × 9.55× 11)

B = 51.36°

3) To find Angle C

We would use the Law of Cosines as well

c² = a² + b² - 2ac × Cos C

Cos C = a² + b² - c²/2ab

C= arc cos ( a² + b² - c²/2ab)

a = 9.55

b = 9

c = 11

C = arc cos (9.55² + 9² - 11²/2 × 9.55× 9)

C= 72.67°

Simplify: x^2-4x-12/x^3-10x^2+24x

Answers

Answer:

(x + 2) / x(x - 4).

Step-by-step explanation:

x^2-4x-12/x^3-10x^2+24x

= (x + 2)(x - 6) / x(x^2 - 10x + 24)

=  (x + 2)(x - 6) / x(x - 4)(x - 6)          x -6 is common to top and bottom so:

= (x + 2) / x(x - 4).

Answer:

x+2/x(x+4) or x+2/x^2-4x

Step-by-step explanation:

from the numerator x^2-4x-12, factorise the numerator

x^2-4x-12

multiplying x^2 and -12=-12x^2

step2:

find two numbers that when multiplied you get -12x^2 and when added you get -12x^2.

This numbers are -6x and 2x.

Therefore,(x^2+2x)-(6x-12)

x(x+2)-6(x+2)

(x-6)(x+2)

Step3

from the denominator x^3-x^2+24x, factorise the denominator

x^3-x^2+24x

What is common to all the numbers, the number that is common is x

Therefore,x(x^2-x^2+24x).

multiplying x^2+24x=24x^2

step2:

find two numbers that when multiplied you get 24x^2 and when added you get 24x^2.

This two numbers are -6x and -4x.

Therefore,x{(x^2-4x)-(6x+24)}

x{x(x-4)-6(x-4)}

x{(x-4)(x-6)

Step4

Bringing the nunerator and denominator together.

(x-6)(x+2)/x{(x-4)(x-6)}

(x-6) divides each other

Therefore,x+2/x(x-4) or (x+2)/x^2-4x

please help I really need it
1. How much is it estimated that the United States population increased from July 1, 2000 to July 1, 2003? From July 1, 2003 to
July 1, 2007?

Answers

Answer:

2.92%

3.85%

Step-by-step explanation:

The population in 2000 is 282,194,308.  The population in 2003 is 290,447,644.  This is an increase of 8,253,336.

290,447,644 - 282,194,308 = 8,253,336

To find the percentage in increase, divide the difference by the original number and multiply by 100%.  The population increased by 2.92%.

8,253,336/282,194,308 = 0.0292 × 100% = 2.92%

The population in 2003 is 290,447,644.  The population in 2007 is 301,621,157.  This is an increase of 11,173,513.

301,621,157 - 290,447,644 = 11,173,513

Divide the difference by the original number and multiply by 100%.  The population increased by 3.85%.

11,173,513/290,447,644 = 0.0385 × 100% = 3.85%


The following is a geometric sequence. Find the next number in this sequence.
1, -2, 4

Answers

Answer:8

Might I be right

Step-by-step explanation:

Find the amount in an account where $500 in invested at 2.5% compounded quarterly for a period of 10 years.

Answers

Answer: $641.51

Step-by-step explanation:

A = p (1+ r/n)^nt

A = 500 (1 + 0.025/4)^4*10

A = 641.51

The amount in an account where $500 in invested at 2.5% is $641.51.

Using this formula

A = p (1+ r/n)^nt

Where:

A=Amount

P= Principal=$500

R=Rate=2.5% or 0.025

n=4 (Quarterly)

T=Time=10 years

Let pug in the formula

A = $500(1 + 0.025/4)^4×10

A=$500(1.28302)

A =$641.51

Inconclusion the amount in an account where $500 in invested at 2.5% is $641.51.

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Mr. Prasad has a Savings Account in a bank. How much money will he have in his account at the end of the first year if he saves $55.00 every
month?​

Answers

Answer: $660

Step-by-step explanation:

If he saves $ 55 every month, he will have

55 x 12 = 660

The total amount of water a tank can hold is 14 and one-half gallons. Raul wants to find out how many 1 and one-fourth-gallon buckets of water can be used to fill the tank. Which expressions could be used to represent this scenario? Select two options.. StartFraction 29 over 2 EndFraction divided by StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction times StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction times StartFraction 4 over 5 EndFraction StartFraction 2 over 29 EndFraction times StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction divided by StartFraction 4 over 5 EndFraction

Answers

Answer:

Water a tank can hold = 14 1/2 = 29/2

Volume of bucket 1 1/4 = 5/4

The expresson can be

29/2 / 5/4

No. of buckets used = 29/2 x 4/5

Answer:

b and e

Step-by-step explanation:

In a newspaper, it was reported that the number of yearly robberies in Springfield in 2013 was 125, and then went down by 12% in 2014. How many robberies were there in Springfield in 2014?

Answers

Answer: 110
Solution: 12% of 125= 15
125-15= 110
Hope you get it.

Answer:

110

Step-by-step explanation:

2013

No of robberies = 125

Percentage = 100%

2014

No of robberies = 'd'

Percentage = 12% lower than 2013 = 100% - 12%

= 88%

No of robberies in 2014 = 88% of the number of robberies in 2013

'd' = 88/100 × 125

'd' = 0.88 × 125

'd' = 110

2014 robberies = 110 in number

HELPPPPP NEEDED FIRST GETS BRAINLLEST !!!! Kobe, Amari, and DJ raised $125.45 for their football team. Kobe collected $24.55 more than Amari, and DJ collected $15.60 less than Kobe. If x = the amount raised by Amari, choose the expressions that represent the amount each other player raised. x + 24.55 x + 8.95 2x – 15.60 3x + 24.55

Answers

Answer:

Kobe raised x + 24.55

Amari raised x

DJ raised 2x – 15.60

Represent the number of feet in y yards, f feet
and i inches.​

Answers

Answer: there a 3 feet to a yard a 36 inches to a yard( 12 inches to a foot) 1/3 of a yard is a foot hope this helps

Step-by-step explanation:

Use the tables below to find (p - 9)(2).

Answers

Answer:

5

Step-by-step explanation:

p(2) - q(2)

3 - (-2)

3 + 2

= 5

A) 136
B) 85
C)65
D)55
PLEASE ANSWER QUICK

Answers

Answer:

B

Step-by-step explanation:

Solve 3n - 5p + 2n = 10p for n

Answers above

Answers

Answer:

D

Step-by-step explanation:

3n - 5p + 2n = 10p

Add like terms.

5n - 5p = 10p

Add 5p to both sides.

5n = 10p + 5p

5n = 15p

Divide both sides by 5.

n = 15/5p

n = 3p

The solution of expression for n is,

⇒ n = 3p

We have to given that,

An expression to solve,

⇒ 3n - 5p + 2n = 10p

Now, We can solve the expression for n as,

⇒ 3n - 5p + 2n = 10p

Combine like terms,

⇒ 3n + 2n = 10p + 5p

⇒ 5n = 15p

Divide by 5 both side,

⇒ n = 15p/5

⇒ n = 3p

Therefore, The correct option is,

D. n = 3p

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If cote = and the terminal point determined by a is in quadrant 3, then:
A. tang = 1
O B. csco = -
Lolo
DC. sing -
ml
O D. Cose =
3
5

Answers

Answer:

The correct option is:

cosθ = -3/5

Step-by-step explanation:

We have been given that:

cotθ = 3/4

such that the terminal side of θ lies in III quadrant.

Consider it a right angled triangle.

We know that:

cotθ = Base / Perpendicular

Which means Base has a magnitude of 3 and Perpendicular has the magnitude of 4.

As It lies in III quadrant, both x and y are negative.

So

Base = -3

Perpendicular = -4

Find the hypotenuse by using Pythagoras Theorem

H² = (-3)² + (-4)²

H = 5

We know that:

cosθ = Base / Hypotenuse

cosθ = -3/5

Answer:

cos=-3/5 and tan=4/3

Step-by-step explanation:

an = -2 + 3/2 (n-1)
What is the 21st term of the sequence?​

Answers

Answer:

[tex]a_{n} = -83/40[/tex]

Step-by-step explanation:

Given

[tex]a_{n} = -2 + 3/2 (n-1)[/tex]

In this problem to find 21st term we put 21 in place of n in the equation

[tex]a_{n} = -2 + 3/2 (21-1) = \\a_{n} = -2 + 3/2 (20)\\a_{n} = -2 + 3/40 = (-2*40 +3)/40 \\a_{n} = -83/40\\[/tex]

Thus, 21st term is -83/40.

If the sum of the integers from 15 to 50,
inclusive, is equal to the sum of the integers
from n to 50, inclusive, and n<15, then n=

A)-49
B)-35
C)-15
D-14​

Answers

Answer:

n = -15

Step-by-step explanation:

Given

Sum of Integers from 15 to 50 (inclusive) = Sum of integers from n to 50 (inclusive)

n < 15

Required

Find n

We can split the given parameters to 2

i. Sum of Integers from 15 to 50 (inclusive)

ii. Sum of integers from n to 50 (inclusive)

Solving for (i): Sum of Integers from 15 to 50 (inclusive)

We'll make use of sum of n terms of an arithmetic;

This is given as follows

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

Where n is the number of terms from 15 to 50

T1 is the first term; T1 = 15

Tn is the last term; Tn = 50

n is calculated using

[tex]n = T_n - T_1 + 1[/tex]

[tex]n = 50 - 15 + 1[/tex]

[tex]n = 36[/tex]

The formula becomes

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

[tex]S_n = \frac{36}{2}(15 + 50)[/tex]

[tex]S_n = \frac{36}{2}(65)[/tex]

[tex]S_n = 18(65)[/tex]

[tex]S_n = 1170[/tex]

Solving for (ii): Sum of integers from n to 50 (inclusive)

We'll also make use of the same formula used above

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

Where n is the number of terms from n to 50

T1 is the first term; T1 = n

Tn is the last term; Tn = 50

n is calculated using

[tex]n = T_n - T_1 + 1[/tex]

[tex]n = 50 - n + 1[/tex]

[tex]n = 50 + 1 - n[/tex]

[tex]n = 51 - n[/tex]

The formula becomes

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

[tex]S_n = \frac{51 - n}{2}(n + 50)[/tex]

Recall that the Sum of Integers from 15 to 50 (inclusive) = Sum of integers from n to 50 (inclusive);

This implies that

Sn (i) = Sn (ii)

As such; we have

[tex]S_n = \frac{51 - n}{2}(n + 50) = 1170[/tex]

[tex]\frac{51 - n}{2}(n + 50) = 1170[/tex]

Multiply both sides by 2

[tex]2 * \frac{51 - n}{2}(n + 50) = 1170 * 2[/tex]

[tex](51 - n)(n + 50) = 1170 * 2[/tex]

[tex](51 - n)(n + 50) = 2340[/tex]

Open Brackets

[tex]51(n + 50) - n(n + 50) = 2340[/tex]

[tex]51*n + 51 * 50 - n * n - n * 50 = 2340[/tex]

[tex]51n + 2550 - n^2 - 50n = 2340[/tex]

Reorder

[tex]-n^2 + 51n - 50n + 2550 = 2340[/tex]

[tex]-n^2 + n + 2550 = 2340[/tex]

Subtract 2340 from both sides

[tex]-n^2 + n + 2550 -2340 = 2340 -2340[/tex]

[tex]-n^2 + n + 210 = 0[/tex]

Multiply both sides by -1

[tex]-1(-n^2 + n + 210) = -1 * 0[/tex]

[tex]n^2 - n - 210 = 0[/tex]

At this point, we have a quadratic equation; as such, it'd be solved as follows:

[tex]n^2 - n - 210 = 0[/tex]

Expand

[tex]n^2 + 15n - 14n - 210 = 0[/tex]

Factorize

[tex]n(n + 15) - 14(n + 15) = 0[/tex]

[tex](n - 14)(n + 15) = 0[/tex]

Split the above expression

[tex](n - 14) = 0 \ or\ (n + 15) = 0[/tex]

[tex]n - 14 = 0 \ or\ n + 15 = 0[/tex]

[tex]n = 14\ or\ n = -15[/tex]

The question states that n < 15;

This means that we'll discard the value of n = 14

Hence, n = -15

Pls help me I need the help!

Answers

Answer:

1a) 15, 7, x+5

1b) 7

2a) 18, 3r

Step-by-step explanation:

1a) Since Claire is 5 years older, she will always be her cousin's age plus 5

1b) Claire is 5 years older, so Claire's cousin is 5 years younger. So, Claire's cousin is Claire's age minus 5

2a) Diego will have the amount of Han's books times 3

Answer:

Clare Questions:

Cousin: 10, Clare: 15

Cousin: 2, Clare: 7

Cousin: x, Clare: x + 5

Cousin: 7, Clare: 12

Diego Questions:

Han: 6, Diego: 18

Han: can't tell if it is a 0 or n, Diego: 0 or 3n, respectively

Step-by-step explanation:

Since Clare is older than her cousin by 5, they will both age at the same rate, thus she will always be 5 years older.

example: if her cousin is 10, Clare will be 10 + 5 years older, therefore being 15.

Since DIego has 3 times as many books than Hans, it multiplies by 3.

example: if Han has 6 books, multiply 6 by 3 and you get Diegos amount, 18.

Please I need help in this question, Best answer gets BRAINLIEST

Answers

Answer:

1 - a/variable

2 - d/statistic

3 - b/population

4 - c/data

5 - e/parameter

6 - f/sample

I did comment asking if the two you'd already selected were definitely correct, but no answer was given, so I apologise if this is wrong. This is what I would put.

Line l has a slope of...

Answers

Hey there! :)

Answer:

Option C.

Step-by-step explanation:

A perpendicular line to 2/3 will be the reciprocal and negative of this fraction. Therefore:

Slope of perpendicular line = -3/2.

Remember, the equation for solving for the slope is:

[tex]m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

We must find points that when plugged into this equation, equal to -3/2.

Plugging in the points in option A:

[tex]\frac{2}{3} \neq \frac{-3}{2}[/tex]

Option B:

[tex]\frac{3}{4} \neq \frac{-3}{2}[/tex]

Option C: This is the correct answer.

[tex]\frac{-3}{2} = \frac{-3}{2}[/tex]

Option D:

[tex]\frac{2}{10}\neq \frac{-3}{2}[/tex]

Hi the answer is c. Hope this helped:)
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