Find the value of y.

Find The Value Of Y.

Answers

Answer 1

[tex]y^2 = 9(3+9)\\\\y^2 = 3^2\cdot3\cdot2^2\\\\y = 6\sqrt{3}[/tex]


Related Questions

Find the point, Q, along the directed line segment AB that
divides AB into the ratio 2:3. The 2:3 ratio means that the line
should be broken up in to 5 equal sections (2 + 3 = 5). This
means that each of the 5 sections can be represented by the
expression AB/5. Therefore, the point that divides AB into the
ratio 2:3 is the distance (AB/5)(2) from A.

Answers

Answer:

Point Q is at a distance of 4.7 units from A.

Step-by-step explanation:

From the graph, AC = 10 units and BC = 6 units. Applying the Pythagoras theorem,

[tex]AB^{2}[/tex] = [tex]AC^{2}[/tex] + [tex]BC^{2}[/tex]

      = [tex]10^{2}[/tex] + [tex]6^{2}[/tex]

      = 100 + 36

     = 136

AB = [tex]\sqrt{136}[/tex]

AB = 11.6619

AB = 11.66

     ≅ 11.7 units

But point Q divides AB into ratio 2:3. Therefore:

AQ = [tex]\frac{2}{5}[/tex] × AB

     =  [tex]\frac{2}{5}[/tex] × 11.66

     = 4.664

AQ = 4.664

AQ ≅ 4.7 units

QB = [tex]\frac{3}{5}[/tex] × AB

     =  [tex]\frac{3}{5}[/tex] × 11.66

     = 6.996

QB  ≅ 7.0 units

So that point Q is at a distance of 4.7 units from A.

Use the data below, showing a summary of highway gas mileage for several observations, to decide if the average highway gas mileage is the same for midsize cars, SUV’s, and pickup trucks. Test the appropriate hypotheses at the α = 0.01 level.
n Mean Std. Dev.
Midsize 31 25.8 2.56
SUV’s 31 22.68 3.67
Pickups 14 21.29 2.76

Answers

Answer:

Step-by-step explanation:

Hello!

You need to test at 1% if the average highway gas mileage is the same for three types of vehicles (midsize cars, SUV's and pickup trucks) to compare the average values of the three groups altogether, you have to apply an ANOVA.

                n  |  Mean |  Std. Dev.

Midsize  | 31 |  25.8   |  2.56

SUV’s     | 31 |  22.68 |  3.67

Pickups  | 14 |  21.29  |  2.76

Be the study variables :

X₁: highway gas mileage of a midsize car

X₂: highway gas mileage of an SUV

X₃: highway gas mileage of a pickup truck.

Assuming these variables have a normal distribution and are independent.

The hypotheses are:

H₀: μ₁ = μ₂ = μ₃

H₁: At least one of the population means is different.

α: 0.01

The statistic for this test is:

[tex]F= \frac{MS_{Treatment}}{MS_{Error}}[/tex]~[tex]F_{k-1;n-k}[/tex]

Attached you'll find an ANOVA table with all its components. As you see, to manually calculate the statistic you have to determine the Sum of Squares and the degrees of freedom for the treatments and the errors, next you calculate the means square for both and finally the test statistic.

For the treatments:

The degrees of freedom between treatments are k-1 (k represents the amount of treatments): [tex]Df_{Tr}= k - 1= 3 - 1 = 2[/tex]

The sum of squares is:

SSTr: ∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= grand mean, is the mean that results of all the groups together.

So the Sum of squares pf treatments SStr is the sum of the square of difference between the sample mean of each group and the grand mean.

To calculate the grand mean you can sum the means of each group and dive it by the number of groups:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (25.8+22.68+21.29)/3 = 23.256≅ 23.26

[tex]SS_{Tr}[/tex]= (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (25.8-23.26)² + (22.68-23.26)² + (21.29-23.26)²= 10.6689

[tex]MS_{Tr}= \frac{SS_{Tr}}{Df_{Tr}}= \frac{10.6689}{2}= 5.33[/tex]

For the errors:

The degrees of freedom for the errors are: [tex]Df_{Errors}= N-k= (31+31+14)-3= 76-3= 73[/tex]

The Mean square are equal to the estimation of the variance of errors, you can calculate them using the following formula:

[tex]MS_{Errors}= S^2_e= \frac{(n_1-1)S^2_1+(n_2-1)S^2_2+(n_3-1)S^2_3}{n_1+n_2+n_3-k}= \frac{(30*2.56^2)+(30*3.67^2)+(13*2.76^2)}{31+31+14-3} = \frac{695.3118}{73}= 9.52[/tex]

Now you can calculate the test statistic

[tex]F_{H_0}= \frac{MS_{Tr}}{MS_{Error}} = \frac{5.33}{9.52}= 0.559= 0.56[/tex]

The rejection region for this test is always one-tailed to the right, meaning that you'll reject the null hypothesis to big values of the statistic:

[tex]F_{k-1;N-k;1-\alpha }= F_{2; 73; 0.99}= 4.07[/tex]

If [tex]F_{H_0}[/tex] ≥ 4.07, reject the null hypothesis.

If [tex]F_{H_0}[/tex] < 4.07, do not reject the null hypothesis.

Since the calculated value is less than the critical value, the decision is to not reject the null hypothesis.

Then at a 1% significance level you can conclude that the average highway mileage is the same for the three types of vehicles (mid size, SUV and pickup trucks)

I hope this helps!

what is 1000 x 10 -5000 +23 - 93 giving brainist thanks!!!

Answers

Answer:

Step-by-step explanation:

We must use PEMDAS for this answer.

First, we must multiply 1000 and 10.

10,000-5000+23-93

Next, we must subtract 10,000 and 5,000

5000+23-93

Add 5000 and 23

5023-93

For our final step, subtract and you get your answer.

4,930

The monthly profit for a company that makes decorative picture frames depends on the price per frame. The company determines that the profit is approximated by f(p)= -80p + 3440p -36,000, where p is the price per frame and f(p) is the monthly profit based on that price.

Requried:
a. Find the price that generates the maximum profit.
b. Find the maximum profit.
c. Find the price(s) that would enable the company to break even.

Answers

Answer:

a. $21.50

b. $980

c. $25 and $18

Step-by-step explanation:

a. The price that generates the maximum profit is

In this question we use the vertex formula i.e shown below:

[tex](-\frac{b}{2a}, f(-\frac{b}{2a} ))\\\\[/tex]

where a = -80

b = 3440

c = 36000

hence,

P-coordinate is

[tex](-\frac{b}{2a}, (-\frac{3440}{2\times -80} ))\\\\[/tex]

[tex]= \frac{3440}{160}[/tex]

= $21.5

b. Now The maximum profit could be determined by the following equation

[tex]f(p) = 80p^2 + 3440p - 36000\\\\f($21.5) = -80(21.5)^2 + 3440(21.5) - 36000\\\\[/tex]

= $980

c. The price that would enable the company to break even that is

f(p) = 0

[tex]f(p) = -80p^2 + 3440p - 36000\\\\-80p^2 + 3440p - 36000 = 0\\\\p^2 -43p + 450 = 0\\\\p^2 - 25p - 18p + 450p = 0\\\\p(p - 25) - 18(p-25) = 0\\\\(p - 25) (p - 18) = 0[/tex]

By applying the factoring by -50 and then divided it by -80 and after that we split middle value and at last factors could come

(p - 25) = 0 or (p - 18) = 0

so we can write in this form as well which is

p = 25 or p = 18

Therefore the correct answer is $25 and $18

Mark each statement True or False. Justify.
1. A linear transformation T W Rn ! Rm is completely determined by its effect on the columns of the n * n identify matrix.
A. True
B. False
2. If A is a 3 * 2 matrix, then the transformation x Ax cannot be one-to-one.
A. TrueB. False

Answers

Answer:

1. A. True

2. B. False

Step-by-step explanation:

The columns of the identity matrix are basis vector in Rn. Every vector can be written as linear combination and T is linear transformation. The transformation map can be from R2 to R3. It can be one to one. If A is 3*1 matrix, then transformation x Ax can not be R2 onto R3. Properties of linear transformations are preserved under rotation.

Suppose the following items were on a menu:_________.
a. Soup - Miso(M) or Lentil Bean (L)
b. Salad - Fresh Greens (G) or Fruit (F)
c. Entrees - Pasta Primavera (P) or Black Bean Burger (B)
If we are to select one of each (soup, salad, entrée), what is the sample space? (show all of the combinations, like in a tree diagram or using the 3 letters)

Answers

Answer:

{MGP,MGB,MFP,MFB,LGP,LGB,LFP,LFB}

Step-by-step explanation:

Soup - Miso(M) or Lentil Bean (L): Types of Soup =2

Salad - Fresh Greens (G) or Fruit (F): Types of Salad =2

Entrees - Pasta Primavera (P) or Black Bean Burger (B): Types of Entrees =2

Therefore, the sample space will have a total of 2X2X2=8 combinations.

If we are to select one of each, the sample space will be:

S={MGP,MGB,MFP,MFB,LGP,LGB,LFP,LFB}

For the binomial distribution with the given values for n and p, state whether or not it is suitable to use the normal distribution as an approximation. n = 24 and p = 0.6.

Answers

Answer:

Since both np > 5 and np(1-p)>5, it is  suitable to use the normal distribution as an approximation.

Step-by-step explanation:

When the normal approximation is suitable?

If np > 5 and np(1-p)>5

In this question:

[tex]n = 24, p = 0.6[/tex]

So

[tex]np = 24*0.6 = 14.4[/tex]

And

[tex]np(1-p) = 24*0.6*0.4 = 5.76[/tex]

Since both np > 5 and np(1-p)>5, it is  suitable to use the normal distribution as an approximation.

Find the first four nonzero terms in a power series expansion about xequals0 for the solution to the given initial value problem. w prime prime plus 3 xw prime minus wequals​0; ​w(0)equals4​, w prime (0 )equals0

Answers

Answer:

The first four terms are;

w(x)= 4 + 2x² - ⁵/₆x⁴+ ¹¹/₃₆x⁶ +......

Step-by-step Explanation:

This is the interpretation of the question

w″ + 3xw′ -w=0

W(0)=4

W′(0)=0

CHECK THE ATTACHMENT FOR STEP BY STEP EXPLANATION

What is the length of the hypotenuse of the triangle? Triangle A B C. Side A C is 8 centimeters and side C B is 15 centimeters. Hypotenuse A B is unknown. StartFraction 94 EndFraction cm StartFraction 161 EndFraction cm 17 cm 23 cm AWNSER ASPA!

Answers

Answer:

The hypotenuse is 17

Step-by-step explanation:

We can use the Pythagorean theorem since this is a right triangle

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

8^2 + 15^2 = c^2

64 + 225 = c^2

289 = c^2

Take the square root of each side

sqrt(289) = sqrt(c^2)

17 = c

Answer:

17 cm

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem.

[tex]a^2+b^2=c^2[/tex]

where a and b are the legs and c is the hypotenuse.

In this triangle, 8 cm and 15 cm are the legs, because they form the right angle. The hypotenuse is unknown.

a= 8

b= 15

[tex]8^2 + 15^2= c^2[/tex]

Solve the exponents on the left side of the equation.

8^2= 8*8= 64

[tex]64+15^2=c^2[/tex]

15^2= 15*15= 225

[tex]64+225=c^2[/tex]

Add 64 and 225

[tex]289=c^2[/tex]

c is being squared. We want to get c by itself, so we must perform the inverse. The inverse would be taking the square root.

Take the square root of both sides.

[tex]\sqrt{289} =\sqrt{c^2}[/tex]

[tex]\sqrt{289} =c[/tex]

[tex]17=c[/tex]

c= 17 cm

The length of the hypotenuse is 17 centimeters.

The solutions to the inequality y < to -x+1 sre shaded on the graph. Which point is a solution

Answers

Answer:  B.  (3,-2)

There are two ways to confirm this is the answer. The first is to note that (3,-2) is on the boundary, so it is part of the solution set. This only works if the boundary line is a solid line (as opposed to a dashed or dotted line).

The second way is to plug (x,y) = (3,-2) into the given inequality to find that

[tex]y \le -x+1\\\\-2 \le -3+1\\\\-2 \le -2[/tex]

which is a true statement. So this confirms that (3,-2) is in the solution set of the inequality.

Evelyn wants to estimate the percentage of people who own a tablet computer she surveys 150 indvidals and finds that 120 own a tablet computer. Identify the values needed to calculate a confidence interval at the 99% confidence level. Then find the confidence interval.
0.10 0.05 0.025 0.01 0.005
1.282 1.645 1.960 2.326 2 576

Answers

Answer:

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

Step-by-step explanation:

Confidence interval for the proportion of people who own a tablet:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 150, \pi = \frac{120}{150} = 0.8[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.576[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.7159[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.8841[/tex]

Percentage:

Multiply the proportion by 100.

0.7159*100 = 71.59%

0.8841*100 = 88.41%

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

What is coefficient of the term of degree of degree 5 in the polynomial below 3x^6+5-x^2+4x^5-9 which one is the right answer and how would i show my work in a explanation.? A. 3 B. 4 C. 6 D. 5

Answers

Answer:

B. 4

Step-by-step explanation:

We are looking for the coefficient of the term x⁵. When we see it in the polynomial as 4x⁵, our coefficient and answer would then be 4.

This is an identification problem. You look for the term and you determine the coefficient. It's just look, find, and answer.

Find the raw scores that cut-off the most extreme 5% under the normal distribution's curve that has a mean of 12 and standard deviation of 3.5.

Answers

Answer:

5.14 and 18.86

Step-by-step explanation:

They give us the following information:

mean (m) = 12

standard deviation (sd) = 3.5

For cutting extreme 5% under the normal distribution curve standard normal score is + - 1.96

we have to:

z = (x - m) / sd

Lower limit is

-1.96 = (x -12) /3.5

-6.86 = x - 12

x = 5.14

Upper limit is

1.96 = (x -12) /3.5

6.86 = x - 12

x = 18.86

Therefore, the raw scores are 5.14 and 18.86

When 440 junior college students were surveyed, 200 said they have a passport. Construct a 95% confidence interval for the proportion of junior college students that have a passport.

Answers

sample proportion: 190/425 = 0.45
ME = 1.96*sqrt[0.45*0.55/425] = 0.047
-----
95% CI: 0.45-0.047 < p < 0.45+0.047

The Confidence Interval is 0.403 < p < 0.497

What is Confidence Interval?

The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval. Within a specific level of confidence, this is the range of values you anticipate your estimate to fall within if you repeat the test. In statistics, confidence is another word for probability.

Given:

Sample proportion =  190/425

                                = 0.45

Now, [tex]\mu[/tex] = 1.96 x √[0.45 x 0.55/425]

          [tex]\mu[/tex] = 0.047

So, 95% CI:

0.45-0.047 < p < 0.45+0.047

0.403 < p < 0.497

Learn more about Confidence Interval here:

https://brainly.com/question/24131141

#SPJ5

The foundation of a building is in the shape of a rectangle, with a length of 20 meters (m) and a width of 18 m. To the nearest meter, what is the distance from the top left corner of the foundation to the bottom right corner?

Answers

Answer:

27m

Step-by-step explanation:

It's the Pythagorean Theorem.

20^2+18^2=c^2

400+324=c^2

724=c^2

take the square root of both sides

26.9m=c

to the nearest meter = 27

What is the equation of the line graphed below?

Answers

y=3x-2

That’s the answer

(a +2b)2 + 4b² - a²​

Answers

Answer:

a^2+4b^2+2a+4b

Step-by-step explanation:

(a +2b)2 + 4b² - a²​

=2a+4b+4b^2+a^2

=a^2+4b^2+2a+4b

Find the Area of this shape

Answers

Answer:

42.5

Step-by-step explanation:

see attached image.

Answer:

42.5

Step-by-step explanation:

So first we have to split this shape into many parts

The simplest way we can do that is by simply drawing a line between the small square and the big rectangle.

Now we calculate the area of each part.

1. Big rectangle

--> So we would just simply multiply the length and width for this one which is 3.5 by 9 --> 3.5 x 9 = 31.5

2. (Left) Right Triangle

Since it's a right triangle we can simply multiply it's L and W then divide by 2

--> 2 x 2 = 4 --> 4/2 = 2

3. (Right) Right Triangle

Same way as previous right triangle l x w / 2

--> 2 x 5 = 10 --> 10/2 = 5

4. Square (Bottom)

And lastly, we have the small square at the bottom

--> l x w = area.

-->given 9 = 2 + x + 5,

x = 9 - 7 --> x = 2

so, 2 x 2 = area --> . 4

Calculate the actual area. of the whole entire shape -->

So this is very simple we just add the area of the shapes (area) we calculated below.

--> 31.5 + 2 + 5 + 4

--> Add parenthasees 31.5 + (2 + 5 + 4)

[To make calculating simpler]

=> 11 + 31.5

=> 32.5 + 10

=> 42.5

Hope this helps!

Use slopes to determine if the lines 5x−4y=−1 and 4x−y=−9 are perpendicular.

Answers

Answer:

Not perpendicular

Step-by-step explanation:

Convert it to y-intercept form first:

5x - 4y = -1

-4y = -5x - 1

y = 5/4x + 1/4

4x - y = -9

-y = -4x - 9

y = 4x + 9

y = 5/4x + 1/4

y = 4x + 9

From the slopes, they are not considered perpendicular because one of the line slope is not a negative reciprocal of the other line slope.

Answer:

The lines are not perpendicular.

Step-by-step explanation:

If the lines are perpendicular, the product of the slopes should be -1.

These equations are in standard form (Ax + By = C), so we can easily find the slopes through using equation: slope= - A / B

For line 5x−4y=−1,

slope = -A / B

= - 5 /- 4

= 5/4

For line 4x−y=−9

slope = -A / B

= - 4 / -1

= 4

Now multiply the slopes to find the product:

5 /4 x 4

= 5

Since 5 ≠ -1, the lines are not perpendicular.

what is the product?
(x-3)(2x²-5x+1)
C) 2x³-11x²+16x-3 ​

Answers

Answer:

2x^3-11x^2+16x-3

Step-by-step explanation:

1) multiply each term inside the parentheses with all other terms:

(x*2x^2)=2x^3

x*-5x=-5x^2

x*1=x

-3*2x^2=-6x^2

-3*-5x=15x

and

-3*1=-3

so

2x^3-5x^2+x-6x^2+15x-3

is our equation

to simplify:

2x^3-11x^2+16x-3 is the answer

A total of 76 groom's guests and 64 bride's guests attended a wedding. The bride's guests used 96 tissues. The groom's guests used 152 tissues. Calculate approximately how many tissues each bride's guest used.

Answers

Answer:

The tissues each bride's guest used is 1.5.

Step-by-step explanation:

We are given that a total of 76 groom's guests and 64 bride's guests attended a wedding. The bride's guests used 96 tissues. The groom's guests used 152 tissues.

We have to find that approximately how many tissues each bride's guest used.

As we know that whenever we have to find the value of 'each item', we have to use division.

Number of bride's guests who attended a wedding = 64

Number of tissues used by the bride's guests = 96

So, the tissues each bride's guest used =  [tex]\frac{\text{Total tissues used by bride's guests}}{\text{Total number of bride's guests}}[/tex]

                                                                    =  [tex]\frac{96}{64}[/tex]

                                                                    =  [tex]\frac{3}{2}[/tex]  =  1.5

Hence, each bride's guest used approximately 1.5 tissues.

How do I construct bisectors, angles, & segments?

Answers

Answer:

Step-by-step explanation:

These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.

1. Angle construction:

Given an angle. construct an angle congruent to the given angle.

Given: Angle ABC

Construct: An angle congruent to angle ABC

Procedure:

1. Draw a ray. Label it ray RY.

2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.

3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.

4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.

5. Draw ray RQ.

Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.

You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.

Solve the following proportion for 17/13=9/u

Answers

Answer:

u = 6.88

Solution,

[tex] \frac{17}{13} = \frac{9}{u} [/tex]

Sinplify the equation using cross multiplication

[tex]17 \times u = 13 \times 9[/tex]

Calculate the product

[tex]17u = 117[/tex]

Divide both sides of the equation by 17

[tex] \frac{17u}{17} = \frac{117}{17} [/tex]

Calculate

[tex]u = 6.88[/tex]

Hope this helps...

Good luck on your assignment..

Which statement is true about the steps that Pablo used to simplify the expression?

Answers

can you provide the statements?

ASAP NEED HELP PRETTY PLEASEAssuming that the petals of the flower are congruent, how many lines of symmetry does the figure have? A. 0 B. 4 C. 6 D. 8

Answers

Answer:

Hey there!

This flower has 8 lines of symmetry.

Hope this helps :)

The line x + y - 6= 0 is the right bisector
of the segment PQ. If P is the point (4,3),
then the point Q is

Answers

Answer:

Therefore, the coordinates of point Q is (2,3)

Step-by-step explanation:

Let the coordinates of Q be(a,b)

Let R be the midpoint of PQ

Coordinates of R [tex]=(\frac{4+a}{2}, \frac{3+b}{2})[/tex]

R lies on the line x + y - 6= 0, therefore:

[tex]\implies \dfrac{4+a}{2}+ \dfrac{3+b}{2}-6=0\\\implies 4+a+3+b-12=0\\\implies a+b-5=0\\\implies a+b=5[/tex]

Slope of AR X Slope of PQ = -1

[tex]-1 \times \dfrac{b-3}{a-4}=-1\\b-3=a-4\\a-b=-3+4\\a-b=-1[/tex]

Solving simultaneously

a+b=5

a-b=-1

2a=4

a=2

b=3

Therefore, the coordinates of point Q is (2,3)

what's the equivalent expression ​

Answers

Answer:

2^52

Step-by-step explanation:

(8^-5/2^-2)^-4 = (2^-15/2^-2)^-4= (2^-13)^-4= 2^((-13*(-4))= 2^52

Kara categorized her spending for this month into four categories: Rent, Food, Fun, and Other. The amounts she spent in each category are pictured here. Rent $433 Food $320 Fun $260 Other $487 What percent of her total spending did she spend on Rent? % (Please enter your answer to the nearest whole percent.) What percent of her total spending did she spend on Food? % (Please enter your answer to the nearest whole percent.) What percent of her total spending did she spend on Fun? % (Please enter your answer to the nearest whole percent.)

Answers

Answer: Rent = 29%,  Food = 21%,    Fun = 17%

Step-by-step explanation:

Rent =     $433

Food =    $320

Fun =       $260

Other =   $487  

TOTAL = $1500

[tex]\dfrac{Rent}{Total}=\dfrac{433}{1500}\quad =0.2886\quad =\large\boxed{29\%}\\\\\\\dfrac{Food}{Total}=\dfrac{320}{1500}\quad =0.2133\quad =\large\boxed{21\%}\\\\\\\dfrac{Fun}{Total}=\dfrac{260}{1500}\quad =0.1733\quad =\large\boxed{17\%}[/tex]

Solve the equation -4x + 7 y equals 20. Y=3x+15

Answers

Substitue what y equals for y and solve.

[tex]

-4x+7(3x+15)=20 \\

-4x+27x+105=20 \\

23x=-85 \\

x=-\boxed{\frac{85}{23}}

[/tex]

Hope this helps.

The average height of women between ages 30-39 is 163.2 cm with a standard deviation of 9.3 cm. Find the probability that a woman in this age group is over 160 cm tall if it is known that the distribution is approximately normal. Group of answer choices

Answers

Answer:

D) 0.6346

Step-by-step explanation:

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