Find the missing dimension. Use the scale factor 1: 12.
Item
Model
Actual
Wingspan Width: 5.4 ft Width:
yd

Answer:

ratio

Step-by-step explanation:

Answer:

281 feet

Step-by-step explanation:

Answer:

x= -6h

Step-by-step explanation:

opening up the bracket

10x+20h=12x+32h

10x-12x=32h-20h

-2x=12h

x=-6h

Answer:

x=-6h

Step-by-step explanation:

Isolate the variable by diviiding each side by factors that don't contain the variable. Hopefully this is helpful :)

Answer:

D

Step-by-step explanation:

Scatter plot (Use excel with any bivariate data you can find)

A

Step-by-step explanation:

just listen to me because i know your doing benchmark just like me

Answer:

x = 34.5

Step-by-step explanation:

x - 15.4 = 19.1

Add 15.4 to both sides.

x - 15.4 + 15.4 = 19.1 + 15.4

x = 34.5

Answer:

x equals -3

Hope this helps :)

Step-by-step explanation:

Answer:

I think its b

do you have to times it?

Answer:

No Possible Triangles

Step-by-step explanation:

Deltamath

Answer:

The list already says the diameter. Here's the answers for the other stuff though:

A≈201.06

A≈4417.86

Answer:

the answer is to commit uninstall

Step-by-step explanation:

gg wp

its a m8 a a a  a a aa aaa

Answer:

y = 4x, y = 10x, etc.

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

set up an equation:

let h be the number of hours you spent raking.

then, the cost would be 10 + 8 times the number of hours.

In equation form:

[tex]10 + 8h = 42[/tex]

solve:

[tex]10 + 8h = 42\\8h = 32\\h = 4[/tex]

So you worked for 4 hours

Missing part of the question

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 25% of all homeowners.....................

Answer:

[tex]P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}[/tex]

[tex]Mean = 1[/tex]

[tex]Pr = 0.2617[/tex]

Step-by-step explanation:

Given

[tex]n = 4[/tex]

[tex]p = 25\%[/tex]

Solving (a): The probability distribution of x

We have:

[tex]n = 4[/tex]

[tex]p = 25\%[/tex] [tex]= 0.25[/tex]

The probability of not having earthquake insurance (q) is:

[tex]q = 1 - p[/tex]

[tex]q = 1 - 0.25[/tex] [tex]= 0.75[/tex]

If x has insurance, then n - x do not.

The distribution follows a binomial pattern. So, the probability distribution is:

[tex]P(X = x) = ^nC_x * 0.25^x * 0.75^{n-x}[/tex]

Substitute 4 for n

[tex]P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}[/tex]

Solving (b): The most likely value of x i.e. The mean

We have:

[tex]n = 4[/tex] and

[tex]p = 25\%[/tex] [tex]= 0.25[/tex]

[tex]Mean = np[/tex]

[tex]Mean = 4 * 0.25[/tex]

[tex]Mean = 1[/tex]

Solving (c): At least 2 of 4 selected have earthquake insurance.

This is calculated as

[tex]Pr = P(x = 2) + P(x = 3) + P(x = 4)[/tex]

[tex]P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}[/tex]

[tex]P(X=2) = ^4C_2 * 0.25^2 * 0.75^{4-2}[/tex]

[tex]P(X=2) = 6 * 0.25^2 * 0.75^2 = 0.2109375[/tex]

[tex]P(X=3) = ^4C_3 * 0.25^3 * 0.75^{4-3}[/tex]

[tex]P(X=3) = 4 * 0.25^3 * 0.75 = 0.046875[/tex]

[tex]P(X=4) = ^4C_4 * 0.25^4 * 0.75^{4-4}[/tex]

[tex]P(X=4) = 1 * 0.25^4 * 1= 0.00390625[/tex]

So:

[tex]Pr = P(x = 2) + P(x = 3) + P(x = 4)[/tex]

[tex]Pr = 0.2109375 + 0.046875 + 0.00390625[/tex]

[tex]Pr = 0.26171875[/tex]

[tex]Pr = 0.2617[/tex] --- approximated

Answer:

56.137 Square Unit

Step-by-step explanation:

Rectangle: 7x6=42

1/2 Circle: 1/2x3x3x[tex]\pi[/tex]=14.137

42+14.137=56.137

Answer:

very nice

Step-by-step explanation:

Answer:

[tex]25\pi[/tex]

Step-by-step explanation:

The formula for the area of a circle is [tex]A=\pi r^{2}[/tex], r is your radius, A is your area, and π is pi (3.1415...). You plug in your radius, or 5 into r, square it, 25, and multiply it by pi. You may be asked to use a certain number of digits of pi, and in that case you multiply for example 3.14 by 25, however [tex]25\pi[/tex] is the exact answer.

Answer: [tex]\$90[/tex]

Step-by-step explanation:

Given

The price of the ticket prior to match day is [tex]\$30[/tex]

It is stated that there is [tex]200\%[/tex] the markup on match day i.e.

The selling price of the ticket is

[tex]\Rightarrow S.P.=30+30\times 200\%\\\Rightarrow S.P.=30+30\times 2=30+60\\\Rightarrow S.P.=\$90[/tex]

So, han must expect to pay [tex]\$90[/tex]  on that day

Answer:

Triangular prism with base being an equilateral triangle with side of 9.

Area of equilateral triangle with side a:

Volume:

Surface area:

5.7+3.2=8.9

10^8+10^6=10^14

(8.9+10^14)

---

hope it helps

Answer:

The width is 32 inches

Step-by-step explanation:

Answer:

(3+7)2+(-6+6)2

100+0

100

10

Answer:

mode

Step-by-step explanation:

Answer:

0.6856

Step-by-step explanation:

[tex]\text{The missing part of the question states that we should Note: that N(108,20) model to } \\ \\ \text{ } \text{approximate the distribution of weekly complaints).]}[/tex]

Now; assuming X = no of complaints received in a week

Required:

To find P(77 < X < 120)

Using a Gaussian Normal Distribution ([tex]\mu =[/tex]108, [tex]\sigma[/tex] = 20)

Using Z scores:

[tex]Z = \dfrac{77-108}{20} \\\\ Z = -\dfrac{35}{20} \\ \\ Z -1.75[/tex]

As a result  X = 77 for N(108,20) is approximately equal to  to Z = -1.75 for N(0,1)

SO;

[tex]Z = \dfrac{120-108}{20} \\ \\ Z = \dfrac{12}{20}\\ \\ Z = 0.6[/tex]

Here; X = 77 for a N(108,20) is same to Z = 0.6 for N(0,1)

Now, to determine:

P(-1.75 < Z < 0.6) = P(Z < 0.6) - P( Z < - 1.75)

From the standard normal Z-table:

P(-1.75 < Z < 0.6) = 0.7257 - 0.0401

P(-1.75 < Z < 0.6) = 0.6856

Answer: 192.. just took the test :)

Step-by-step explanation:

The number of  boxes contains more than 340 nails will be 190. Option B is correct.

The number of standard deviations by which the value of a raw score is above or below the mean value of what is being observed or measured is known as the Z score.

Z score for the 340 nails is found as;

[tex]\rm Z-score= \frac{340-325}{15} \\\\ Z-score=1[/tex]

If the probability of the z score is grater than 1 is;

P(Z≥1)=1-P(Z≤1)

P(Z≥1)=1-0.8413

P(Z≥1)=0.1587

For the 1200 boxes with more than the 340 nails is 192.

Hence,option B is correct.

Learn more about z-score refer:

https://brainly.com/question/21262765

#SPJ2

Answer:

No, the survey doesn't support the researchers claim that people tend to underestimate the duration of a cold. .

Step-by-step explanation:

We are given;

Population mean; μ = 15

Sample mean; x¯ = 14

Standard deviation; s = 0.5

Sample size; n = 352

Null hypothesis; H0: μ = 15

Alternative hypothesis; Ha: μ < 15

Let's find the z-value;

z = (x¯ - μ)/(s/√n)

z = (14 - 15)/(0.5/√352)

z = -1/0.02665

z = -37.5

From online p-value from z-score calculator attached using z = -37.5; significance level of 0.05; one tailed hypothesis, we have;

p-value = 0.00001

But since we want to find out if they underestimate the duration of the cold then;

P(z > 0.00001) = 1 - 0.00001 = 0.99999

Which is approximately 1.

The p-value is greater than the significance level, therefore we fail to reject the null hypothesis and conclude that the survey doesn't support the researchers claim that people tend to underestimate the duration of a cold.