Answer:
For x – 4 to be a factor, you must have x = 4 as a zero. Using this information, I'll do the synthetic division with x = 4 as the test zero on the left:
Step-by-step explanation:
7 points
Sue has a sticker collection with 36 red, 72 blue, and 18 red. She wants to
arrange the stickers in equal rows with only one type of sticker in each
row. Which of the following choices could Sue choose? *
18
4
12
8
Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen at random from box A and placed in box B. Now, a poker chip is chosen at random from those now in box B. What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?
Answer:
0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Coin chosen from box B is red.
Event B: Blue poker chip transferred.
Probability of choosing a red coin:
7/10 of 4/9(red coin from box A)
6/10 of 5/9(blue coin from box A). So
[tex]P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444[/tex]
Blue chip transferred, red coin chosen:
6/10 of 5/9. So
[tex]P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333[/tex]
What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172[/tex]
0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red
Which two prisms have the same height
Answer:
The height of prism A is 4, the height of prism B is 5, the height of prism C is 4, and the height or prism D is 2. Since 4=4, prisms A and C have the same height.
Hope this helped! If it did, please give me brainliest! It would help a lot! Thanks! :D
Help me ASAP for heart, 5 star rating and comment
There is 8 questions which will be posted one after the other. Questions 1-7 the person who answers correctly and quickly will get a heart and 5 star rating and comment and for the 8th question the correct person will get the rewards + brainiest.
1. If U = 35 and V = 7 and T =4 and V = U + AT. How much Is A worth
This question is worth 10 points numbers WILL get higher
Answer:
A=-7
Step-by-step explanation:
7=35+A4
4A=-28
A=-7
A row of plaques covers 288 square feet of space along a wall.
If the plaques are 6 feet tall, what length of the wall do they cover?
Answer:
40 feet
Step-by-step explanation:
There are 420 students at Virginia Middle School. The ratio of girls to boys is 4 to 3. HELPPPPPPPP
Answer:
60 more girls are there than boys at Virginia Middle School.If p represents a number, which expression represents "p divided by 7, increased by 8"?
Answer: p/7 + 8
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
Which statement is correct?
Thank you for anyone who answers
Answer:
I believe the correct answer is C
A) Jerry wants to open a bank account with his money. He will deposit $60.75
per month. If m represents the number of months, write an algebraic expression to
represent the total amount of money he will deposit
Answer:
$60.75×m
Step-by-step explanation:
'5'5"5"5""55
PLEASE HELP MEEEEE ASAP 100 POINTS
Answer:
3. D 4. B
Step-by-step explanation:
3. e^2 = g^2 + f^2, answer is d
4. Let a = 3, b = 4, c = 5
2c = 10
2b = 8
2a = 6
10^2 = 8^2 + 6^2
answer is b
3. The Pythagorean theorem states the hypotenuse squared is equal to each side squared added to each other.
The answer is D. E^2 = f^2 + g^2
4.
To keep the proportion you could multiply the sides by the same numbers . The answer would be 2A, 2b, 2c
find the value of x in each triangle
please help me i really need help please
Which of the following circles has an area greater than 400 square meters and less than 600 square meters? Use 3.14 for π. Select all that apply.
A.Radius: 8 meters
B.Radius: 12 meters
C.Radius: 14 meters
D.Diameter: 12 meters
E.Diameter: 22 meters
F.Diameter: 26 meters
Answer:d
Step-by-step explanation:fkjfkjfkjfkjfkjf
PLEASE HELP ME.............
Answer:
[tex]g(x)=3x^2[/tex]
(1) Justin and Ben are scuba diving. Justin is 7 meters below the
surface of the water. Ben is 3 meters above Justin. Find Ben's
position relative to the surface of the water.
Answer:
Ben is 4 meters below the surface area.
Use the number line to answer the questions that follow
Answer:
A. make a point on the line to the right 2 units from 0
B. the opposite of 2 isn't located at the same place as point P on the number line because the opposite of 2 is -2 and the point P is the opposite of negative 2 which would be positive 2. So the two points are not in the same place because they have different signs.
Step-by-step explanation:
hope this helps
I know the wording is a bit complicated lol <3
What is the volume of a cone with a radius of 6 inches and a height of 15 inches? (Use 3.14 for π.)
188.4 in. 3
565.2 in. 3
726.8 in. 3
1,695.6 in. 3
Thx
Answer:
1,695.6 in. 3
Step-by-step explanation:
the truth table for the formula (X → Y ) ∨ (Z → ¬X)
Answer:
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
Step-by-step explanation:
Let [tex]A[/tex] denote a Boolean variable.
The negation of [tex]A[/tex] ([tex]\lnot A[/tex]) is false if when [tex]\!A[/tex] is true, and true when [tex]A\![/tex] is false. In a truth table:
[tex]\begin{array}{c||c} A & \lnot A \\ \cline{1-2} \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c||c} A & \lnot A \\ \hline \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].
Let [tex]B[/tex] denote another Boolean variable. The material implication "[tex]A[/tex] implies [tex]\!B[/tex]" ([tex]A \to B[/tex]) is true unless [tex]B\![/tex] is false when [tex]A\![/tex] is true.
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex]
The logical or "[tex]A[/tex] or [tex]B[/tex]" is true when either [tex]A\![/tex] or [tex]B\![/tex] is true (and also when both are true.)
[tex]\begin{array}{c|c||c} A & B & A \lor B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm T \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F\end{array}[/tex]
[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].
Start by finding the value of [tex]\lnot X[/tex], [tex](X \to Y)[/tex], and [tex](Z \to \lnot X)[/tex] for each of the [tex]2^3 = 8[/tex] possible combinations of [tex]X[/tex], [tex]Y[/tex], and [tex]Z[/tex].
[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \cline{1-6} \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \cline{1-6} \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].
[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].
The value of [tex](X \to Y) \lor (Z \to \lnot X)[/tex] is true whenever either [tex](X \to Y)[/tex] or [tex](Z \to \lnot X)[/tex] is true (or both.) The combination [tex]X = \rm T[/tex], [tex]Y = \rm F[/tex], and [tex]Z = \rm T[/tex] is the only one among the eight where neither [tex](X \to Y)\![/tex] nor [tex](Z \to \lnot X)\![/tex] is true. [tex](X \to Y) \lor (Z \to \lnot X)\![/tex] would evaluate to true for all other combinations.
Hence, the truth table would be:
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].
Find the positive of x that makes the equation true.
x^2 = 225
Answer:
x = 15
Step-by-step explanation:
15 * 15 = 225
Answer:
X = 15
Step-by-step explanation:
This is because if you square 15, you get 225.
Ms. Day drew a rectangle
on the board with a width
of 14 cm and a diagonal
length of 50 cm. Find the
length of this rectangle in
centimeters.
Answer:
700
Step-by-step explanation:
Which expression is equivalent to the expression 6h + 2?
(2 + 4h) + 2
(2 + 4h) + h
(1 + 5h) + 2
(2 + 5h) + h
Answer:
D
Step-by-step explanation:
What is the area of the shaded region?
Answer:
65
Step-by-step explanation:
( (23 * 13) / 2 ) - ( (13 * 13) / 2 ) = ( 299 / 2 ) - ( 169 / 2 ) = 149.5 - 84.5 = 65
Numbers are slightly unclear but I think this is right.
2y^2 + 4y^2 + 8 + 3 helpp
Answer:
11
Step-by-step explanation:
2y + 4y = 6y = 6y + 8 + 3 Add the numbers: 8 + 3 = 11 hope this helps ;) ITS A ME LUIGI ON THE XBOX ONE WAAAAAAAAAAAAAAAAAAAAAAAAHHOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO
What is one thing that you found interesting about future value and present value for compound interest? 100 words ^
Answer:
Compound interest is that which, once generated, is added to the capital, in order to expand the calculation base on which, in turn, new interests will be generated. Thus, in short, if the interest is, for example, 5 percent, said interest will be added to the initial capital, with which that 5% generated will be increasing, since it will be calculated on an increasingly large basis.
Compound interest is very important for financial investments, as it maximizes the results of said investments, even more so when compared to simple interest, in which the interest generated is not added to the initial capital.
Plz help me !!!! I’m not sure if it’s 20 !
Answer:
D) 20º
Step-by-step explanation:
if one angle is 70º, and the other is 90º, that means that the first two angles equal 160º. since all three interior angles of a triangle have to add up to 180º, the third angle must be 20º.
Slove for the value of x to the nearest whole number?
Answer:
Hello good afternoon
Step-by-step explanation:
you have to put this link
A radioactive isotope is decaying at a rate of 15% every hour. Currently there are 150 grams of the substance. Write an equation that will represent the number of grams present after n hours. How much will be left one day from now?A radioactive isotope is decaying at a rate of 15% every hour. Currently there are 150 grams of the substance. Write an equation that will represent the number of grams present after n hours. How much will be left one day from now?
Answer:
The equation that will represent the number of grams present after n hours is [tex]A(n) = 150(0.85)^n[/tex]
3.035 grams will be left one day from now.
Step-by-step explanation:
Exponential equation for the amount of a substance:
The exponential equation for the amount of a substance is given by:
[tex]A(t) = A(0)(1-r)^t[/tex]
In which A(0) is the initial amount and r is the decay rate, as a decimal, and t is the time period.
A radioactive isotope is decaying at a rate of 15% every hour.
This means that [tex]r = 0.15[/tex]
Currently there are 150 grams of the substance.
This means that [tex]A(0) = 150[/tex]
Write an equation that will represent the number of grams present after n hours.
[tex]A(n) = A(0)(1-r)^n[/tex]
[tex]A(n) = 150(1-0.15)^n[/tex]
[tex]A(n) = 150(0.85)^n[/tex]
How much will be left one day from now?
One day is 24 hours, so this is A(24).
[tex]A(24) = 150(0.85)^{24} = 3.035[/tex]
3.035 grams will be left one day from now.
Movie Theaters There are two movie theaters in a town. A student wants to compare the amount of
money each theater makes over a period of days. The following box plots show the data for the
amount of money each theater makes over a period of days. Compare the median of each box plot.
Click here to see the box plot for movie theater 1.
Click here to see the box plot for movie theater 2.
Vhich of the following is the best description of the medians?
A. The median for Movie Theater 1 is greater.
B. The median for Movie Theater 2 is greater.
C. The medians are about the same.
The medians are about the same.
Option C is the correct answer.
What is a median?It is the middle value of the given set of numbers after arranging the given set of numbers in order.
We have,
Movie theater 1.
From the box plot given,
The median is 995.
Movie theater 2.
From the box plot given,
The median is 995.
Thus,
The median in both the box plot is the same.
Learn more about the median here:
https://brainly.com/question/28060453
#SPJ2
9−z9, minus, z when z = 8z=8z, equals, 8.
A desk is on sale for $217, which is 38% less than the regular price. What is the regular price?
en la pastelería de Luisa le regalan a una casa hogar 18 galletas dé cada 60 que se hornean a la semana si la semana pasada hornearon 720 galletas Cuántas regalaron
Answer:
La pastelería de Luisa regaló 216 galletas a la casa hogar.
Step-by-step explanation:
De acuerdo con el enunciado, la pastelería de Luisa regalan 18 galletas a una casa hogar por cada 60 galletas horneadas en una semana. El total de galletas regaladas por hornear 720 galletas se determina por la siguiente Regla de Tres Simple:
[tex]x = \frac{18}{60}\times 720[/tex]
[tex]x = 216[/tex]
La pastelería de Luisa regaló 216 galletas a la casa hogar.