Factors such as brake shoe orientation, pin location, and direction of rotation determine whether a particular brake shoe is considered to be self-energizing or self-deenergizing. Sketch a brake drum where the left shoe is self-energizing and the right shoe is self-deenergizing. Which shoe will produce more braking torque, assuming equal actuation forces and identical brake shoes

probably alot lol

Explanation:

it probably is

Answer:

0.49

0.51

Explanation:

Probability that bulb is defective :

Let :

b1 = box 1 ; b2 = box 2 ; b3 = box 3

d = defective

P(defective bulb) = (p(b1) * (d|b1)) + (p(b2) * p(d|b2)) + (p(b3) * p(d|b3))

P(defective bulb) = (1/3 * 10/20) + (1/3 * 7/15) + (1/3 * 5/10))

P(defective bulb) = 10/60 + 7/45 + 5/30

P(defective bulb) = 1/6 + 7/45 + 1/6 = 0.4888

= 0.49

P(bulb is good) = 1 - P(defective bulb) = 1 - 0.49 = 0.51

Answer:

GRADUATED CYLINDER

Explanation:

Answer:

Air is a gas

Explanation:

i think. beavuse it cant be a liqued or a solid. i dont think a plasma. i would answer gas

Answer:

P=900KG/M3

U=0.0002 M2/S

RE=PV/U

=900*10/0.0002

=45000000

Explanation:

The Reynold number will be 4.5×10⁷. Reynold's number is found as the ratio of the inertial to the viscous force.

Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.

The mass and density relation is given as

mass = density × volume

The ratio of inertial to viscous force is known as Reynold's number.

[tex]\rm R_E= \frac{\rho u L}{\mu} \\\\ \rm R_E=\frac{900 \times 10}{0.0002} \\\\ R_E=45000000[/tex]

Hence, the Reynold number will be 4.5×10⁷.

To learn more about the density refers to the link;

brainly.com/question/952755

#SPJ2

Answer:

a) 0.01558 Ω per 1000 feet

b) 0.0923  Ω per mile

c)  3.57%

Explanation:

a) Calculate and verify the DC resistance

Dc resistance = R = р [tex]\frac{l}{A}[/tex]

for aluminum at 20°C

р = 17 Ωcmil/ft

hence R = 17 * 1000 / ( 113000 ) = 0.01527 Ω per 1000 feet

there when there is an increase in resistance of 2% spiraling

R = 1.02 * 0.01527 = 0.01558 Ω per 1000 feet

b) Calculate the DC resistance at 50°C

R2 = R1 ( [tex]\frac{T+t2}{T+ t1}[/tex] )

where ; R1 = 0.01558 , T = 228 , t2 = 50, t1 = 20 ( input values into equation above )

hence R2 = ( 0.01746 / 0.189 ) Ω per mile = 0.0923  Ω per mile

c ) Determine the percentage increase due to skin effect

AC resistance = 0.0956 ohm per mile

Hence; Increase in skin effect

= ( 0.0956  -0.0923 ) / 0.0923

=  0.0357 ≈ 3.57%

Answer:

True because some ducks can't swim but have to learn it

Answer:

you can't eat your school computer or a pencil.

Answer:

Tires or wheels? I think this is the answer. ^_^

Explanation:

Answer: A. whether his geology studies exposed him to principles of geotechnical engineering

Explanation:

The options include:

a. whether his geology studies exposed him to principles of geotechnical engineering

b. the size of the geology program he attended

c. the size of the architecture firm

d. whether the architecture firm was intending to offer Miguel a full-time position

Since Miguel, is a former geology student with experience as an intern at an architecture firm, and Sarah is considering him for an assistant site investigation position, the option that will be relevant for her to make a decision is to know whether his geology studies exposed him to principles of geotechnical engineering.

Geotechnical engineering, is a branch of engineering that makes use of principles of rock mechanics to solve engineering challenges. Since Sarah needs him for an assistant site investigation position, he'll need to investigate souls, rocks and evaluate them.

Answer:

C

Explanation: Freedmens Bureau provided resources for southerners and newly freed slaves

Answer:

I think The Battle of Sabine Pass

Answer:

The specific enthalpy of the exit stream is 63.267 Btu per pound-mass.

Explanation:

This case represents a mixing chamber, a steady state device where two streams of the same fluid (cold and hot streams) are mixed with negigible changes in kinetic and gravitational potential energy and likewise in heat work interactions with surroundings. By Principle of Mass Conservation and First Law of Thermodynamics we have the following Mass and Energy Balances:

Mass Balance

[tex]3\cdot \dot m_{in} - \dot m_{out} = 0[/tex] (1)

Where:

[tex]\dot m_{in}[/tex] - Mass flow of the hot stream, in pounds-mass per second.

[tex]\dot m_{out}[/tex] - Mass flow of the resulting stream, in pounds-mass per second.

Energy Balance

[tex]2\cdot \dot m_{in}\cdot h_{c}+\dot m_{in}\cdot h_{H}-\dot m_{out}\cdot h_{out} = 0[/tex] (2)

Where:

[tex]h_{c}[/tex] - Specific enthalpy of the cold stream, in BTU per pound-mass.

[tex]h_{h}[/tex] - Specific enthalpy of the hot stream, in BTU per pound-mass.

[tex]h_{out}[/tex] - Specific enthalpy of the resulting stream, in BTU per pound-mass.

By applying (1) in (2) we eliminate [tex]\dot m_{in}[/tex] and clear [tex]h_{h}[/tex]:

[tex]h_{out} = \frac{2\cdot h_{c}+h_{h}}{3}[/tex]

From Property Charts of the Refrigerant 134a, we have the following information:

Cold fluid (Subcooled liquid)

[tex]p = 100\,psia[/tex]

[tex]T = 30\,^{\circ}F[/tex]

[tex]h_{c} \approx 37.870\,\frac{Btu}{lbm}[/tex]

Hot fluid (Superheated steam)

[tex]p = 100\,psia[/tex]

[tex]T = 80\,^{\circ}F[/tex]

[tex]h_{h} = 114.06\,\frac{Btu}{lbm}[/tex]

If we know that [tex]h_{c} \approx 37.870\,\frac{Btu}{lbm}[/tex] and [tex]h_{h} = 114.06\,\frac{Btu}{lbm}[/tex], then the specific enthalpy of the resulting stream is:

[tex]h_{out} = 63.267\,\frac{Btu}{lbm}[/tex]

The specific enthalpy of the exit stream is 63.267 Btu per pound-mass.

Answer:

A

Explanation:

Answer:

a

Explanation:

Answer:

a) 0.50613

b) 22.639 kJ

Explanation:

From table A-11 , we will make use of the properties of Refrigerant R-13a at 24°C

first step : calculate the  volume of R-13a  ( values gotten from table A-11 )

V = m1 * v1 = 5 * 0.0008261 = 0.00413 m^3

next : calculate final specific volume ( v2 )

v2 = V / m2 = 0.00413 / 0.25 ≈ 0.01652 m^3/kg

a) Calculate the mass of refrigerant that entered the tank

v2 = Vf + x2 * Vfg

v2 = Vf +  [ x2 * ( Vg - Vf ) ] ----- ( 1 )

where:  Vf = 0.0008261 m^3/kg, V2 = 0.01652 m^3/kg , Vg = 0.031834 m^3/kg  ( insert values into equation 1 above )

x2 = ( 0.01652 - 0.0008261 ) / 0.031834

     = 0.50613 ( mass of refrigerant that entered tank )

b) Calculate the amount of heat transfer

Final specific internal energy = u2 = Uf + ( x2 + Ufg ) ----- ( 2 )

uf = 84.44 kj/kg , x2 = 0.50613 , Ufg = 158.65 Kj/kg

therefore U2 = 164.737 Kj/kg

The mass balance  ( me ) = m1 - m2 --- ( 3 )

energy balance( Qin ) = ( m2 * u2 ) - ( m1 * u1 ) + ( m1 - m2 ) * he

therefore Qin = 41.184 - 422.2 + 403.655  = 22.639 kJ

Answer:

A)

i) 592.2 k

ii) - 80 kw

B)

i) 105.86 kw

ii) 78%

Explanation:

Note : Nitrogen is modelled as an ideal gas hence R - value = 0.287

A) Determine the minimum theoretical power input required  and exit temp

i) Exit temperature :

[tex]\frac{T_{2s} }{T_{1} } = (\frac{P2}{P1} )^{\frac{k-1}{k} }[/tex]

∴ [tex]T_{2s}[/tex]  = ( 37 + 273 ) * [tex](\frac{10}{1} )^{\frac{1.391-1}{1.391} }[/tex]  =  592.2 k

ii) Theoretical power input :

W = [tex]\frac{-n}{n-1} mR(T_{2} - T_{1} )[/tex]

where : n = 1.391 , m = 1000/3600 , T2= 592.2 , T1 = 310 , R = 0.287

W = - 80 kW  ( i.e. power supplied to the system )

B) Determine power input and Isentropic compressor efficiency

Given Temperature = 3978C

i) power input to compressor

W = m* [tex]\frac{1}{M}[/tex] ( h2 - h1 )

h2 = 19685 kJ/ kmol ( value gotten from Nitrogen table at temp = 670k )

h1 = 9014 kj/kmol ( value gotten from Nitrogen table at temp = 310 k )

m = 1000/3600 ,  M = 28

input values into equation above

W = 105.86 kw

ii) compressor efficiency

П = ideal work output / actual work output

   = ( h2s - h1 ) / ( h2 - h1 ) = ( T2s - T1 ) / ( T2 - T1 )

  = ( 592.2 - 310 ) / ( 670 - 310 )

  = 0.784 ≈ 78%

Answer:

B. food safety and quality assurance manager

Explanation:

PLATO