Answer:
C.No, because bromine has lower activity than iodine
Explanation:
Hello,
In this case, for answering the given question we should remember that the higher the period the higher the activity of an element, therefore, since iodine is in period 6 and bromine is in period 5, we can say that the described reaction is not possible due to the fact that bromine is less active. For that reason answer is C.No, because bromine has lower activity than iodine.
Best regards.
Answer:
Yes, because bromine has lower activity than iodine
Explanation:
Write the name for the following molecular compounds. Remember to use the correct prefix for each compound.
a. CS2
b. PBr3
c. NO
d. CF4
e. P2O5
Answer:
Hey there!
CS2) Carbon Disulfide.
PBr3) Phosphorus Tribromide
NO) Nitric Oxide
CF4) Carbon Tetrafluoride
P2O5) Phosphorus Pentoxide
Let me know if this helps :)
When solutions of hydrochloric acid and sodium hydroxide are mixed, a chemical reaction occurs forming aqueous sodium chloride and water. What would you expect to observe if you ran the reaction in the laboratory
Answer:
a change in temperature would be observed(ΔH is -ve)
Explanation:
Hydrochloric acid react with sodium hydroxide to give salt(sodium chloride) and water
HCl(aq) + NaOH(aq) =====> NaCl(aq) + H2O(l)
There would be no notable change since sodium chloride dissolved in water but there would be a change in temperature.
Since neutralization is exothermic(heat is evolved), therefore ΔH is negative
Need help with a chemistry question
Answer:
Sn2 mechanism reaction
Explanation:
In this case, we have a primary substrate (1-bromo-3,3-dimethylbutane). Because the leaving group "Br" is bonded to a primary carbon. Additionally, the nucleophile will come from the "NaI" (sodium iodide). This is an ionic compound, so, in solution, a cation and an anion would be produced. The anion [tex]I^-[/tex] would be the nucleophile.
Due to the primary substrate, we will have an Sn2 reaction. So, the attack of the nucleophile and the removal of the leaving group will take place in 1 step. Producing a "transition state" and finally and the final product (1-iodo-3,3-dimethylbutane).
See figure 1
I hope it helps!
Steam reforming of methane ( ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a tank with of methane gas and of water vapor, and when the mixture has come to equilibrium measures the amount of carbon monoxide gas to be .Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to significant digits.
The given question is incomplete, the complete question is:
Calculating an equilibrium constant from a partial equilibrium... Steam reforming of methane (CH) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 25.0L tank with 8.0 mol of methane gas and 1.9 mol of water vapor, and when the mixture has come to equilibrium measures the amount of carbon monoxide gas to be 1.5 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to 2 significant digits.
Answer:
The correct answer is 2.47.
Explanation:
Based on the given information, the equation for the synthesis gas is,
CH₄ (g) + H₂O (g) ⇔ CO (g) + 3H₂ (g)
Based on the given information, 25.0 L is the volume of the tank, the concentration of CH₄ is 8.0 mol, the concentration of water vapor is 1.9 mol, and the concentration of CO gas is 1.5 mol.
Therefore, 25 L of the solution comprise 8.0 mole of CH₄. So, 1 L of the solution will comprise 8.0 / 25 mole CH₄,
= 0.32 mole of CH₄
Thus, the concentration of CH₄ or [CH₄] will be 0.32 mole/L or 0.32 M.
Similarly, the concentration of H₂O or [H₂O] will be 1.9/25 = 0.076 M
and [CO] is 1.5/25 = 0.06 M
The concentration equilibrium constant for the steam will be,
Kc = [CO] pH₂ / [CH₄] [H₂O] (Here pH₂ is the partial pressure of H₂)
Now lets us assume that the reaction has taken place in a constant atmospheric pressure, therefore, pH₂ will be equal to 1.
= 0.06 M/0.32 M × 0.076 M
= 2.47
Identify the correct structure of 5-bromo-4-isopropylheptanoic acid.
Answer:
See attached picture.
Explanation:
Hello,
In this case, given the IUPAC name, we can infer we have a seven-carbon carboxylic acid that has a bromine at the fifth carbon, an isopropyl at the fourth carbon and the carboxyl functional group (COOH) at the first carbon, thus, on the attached document, you will find the correct structure.
Best regards.
A 110.0 L weather balloon filled with 4.00 mol of helium has a small leak. If the helium leaks at a rate of 10.0 mmol/hr, what is the volume of the balloon after 38.0 hours
Answer:
The volume of the balloon after 38.0 hours is 99.55 L
Explanation:
Given;
volume of helium in the weather balloon, V = 110 L
initial mole of the gas, n = 4 mol
the rate leak of the gas, dn/dt = 10 mmol/hr
After 38.0 hours, the moles of the gas lost = 38hr x 10 x 10⁻³ mol/hr = 0.38 mol
the moles of the gas lost = 0.38 mol
Number of moles of helium in balloon after 38.0 hours = 4 mol - 0.38 mol
= 3.62 mol
Volume of helium in balloon after 38.0 hours ;
[tex]= 110(L) (\frac{3.62 \ mol}{4 \ mol} )\\\\= 99.55 \ L[/tex]
Therefore, the volume of the balloon after 38.0 hours is 99.55 L
How many moles of gaseous boron trifluoride, BF3, are contained in a 4.3410 L bulb at 788.0 K if the pressure is 1.220 atm What is the complete ground state electron configuration for the neon atom
Answer:
n= 0.08186
{He}2s^2 2p^6
Explanation:
PV=nRT
n=PV/RT
n= (1.220 atm)(4.3410 L) / (0.0821 atm*L/mol*K)(788.0 K)
n=0.08186
As for the electron configuration:
Ne:
{He} 2s^2 2p^6
or long hang:
1s^2 2s^2 2p^6
[tex][Ne]=1s^22s^22p^{10}[/tex]
Given:
A gaseous boron trifluoride in a 4.3410 L bulb at 788.0 K, if the pressure is 1.220 atm.Neon atom.To find:
The moles of gaseous boron trifluoride in a container.The electronic configuration of neon in the ground state.1.
The pressure of the gaseous boron trifluoride = P = 1.220 atm
The volume of the gas in bulb = V = 4.3410 L
The moles of the gaseous boron trifluoride = n
The temperature of gaseous boron trifluoride = T = 788.0 K
Using an ideal gas equation:
[tex]PV = nRT\\\\1.220 atm\times 4.3410 L=n\times 0.0821 atm L/mol K\times 788.0 K\\\\n=\frac{1.220 atm\times 4.3410 L}{0.0821 atm L/mol K\times 788.0 K}\\\\n=0.08186 mol[/tex]
The moles of gaseous boron trifluoride is 0.08186 moles.
2.
The atomic number of neon atom = 10
The electronic configuration in the ground state is the most stable arrangement of the electrons in the lowest energy levels.
The ground state electronic configuration of neon is:
[tex][Ne]=1s^22s^22p^{10}[/tex]
Learn more about the ideal gas equation and electronic configuration here:
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g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empirical formula of the compound?
Answer:
THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O
Explanation:
The empirical formula for the unknown compound can be obtained by following the processes below:
1 . Write out the percentage composition of the individual elements in the compound
C = 75.68 %
H = 8.80 %
O = 15.52 %
2. Divide the percentage composition by the atomic masses of the elements
C = 75 .68 / 12 = 6.3066
H = 8.80 / 1 = 8.8000
O = 15.52 / 16 = 0.9700
3. Divide the individual results by the lowest values
C = 6.3066 / 0.9700 = 6.5016
H = 8.8000 / 0.9700 = 9.0722
O = 0.9700 / 0.9700 = 1
4. Round up the values to the whole number
C = 7
H = 9
O = 1
5 Write out the empirical formula for the compound
C7H90
In conclusion, the empirical formula for the unknown compound is therefore C7H9O
what are structure for each of the compounds listed. Explain why the name given is incorrect. And give a correct name in each case
(1) 1-methylbutane
(2) 1,1,3-trimethylhexane
(3) 5octyne
(4)2-ethyl-1-propanol
(5)2,2-dimethyl1-3-butanol
Answer:
Explanation:
(1) 1-methylbutane
(2) 1,1,3-trimethylhexane
(3) 5octyne
(4)2-ethyl-1-propanol
(5)2,2-dimethyl1-3-butanol
How much heat will be absorbed by a 63.1 g piece of aluminum (specific heat = 0.930 J/g･°C) as it changes temperature from 23.0°C to 67.0°C?
Answer:
[tex]Q=2582J=2.58kJ[/tex]
Explanation:
Hello,
In this case, for us to compute the absorbed heat, we apply the following equation:
[tex]Q=m_{Al}Cp_{Al}(T_2-T_1)[/tex]
Whereas we use the mass, specific heat and temperature change for the piece of aluminium, thus, we obtain:
[tex]Q=63.1g*0.930\frac{J}{g*\°C}*(67.0-23.0)\°C\\ \\Q=2582J=2.58kJ[/tex]
It is positive as the heat is entering, therefore the temperature raises.
Best regards.
Given Ba, Li, Na, Cs, and Be, arrange the group 1 and 2 elements in order of increasing reactivity to water (H2O).
1. Be∠Na∠ Li∠ Ba∠ Cs
2. Be∠ Li∠ Ba∠ Na∠ Cs
3. Cs∠ Na∠ Be∠ Li∠ Ba
4. Li∠ Cs∠ Na∠ Be∠ Ba
I think it's the third option, but the Beryllium and Barium are messing me up! And a brief explanation too. Thanks!
Answer:
Be∠ Li∠ Ba∠ Na∠ Cs
Explanation:
Beryllium does not react with water. It is the only alkaline earth metal that does not react with water because of its small size and high ionization energy. Beryllium differs considerably from other members of group two, its compounds when anhydrous show a considerable degree of covalent character.
As the atomic number of the group two elements increases, their ionization energies decreases and their electrode potentials become more negative hence their reactivity increases down the group. This implies that barium will have a very negative electrode potential comparable to that of the alkali metals, hence it reacts considerably with water.
The reactivity of alkali metals with water increases down the group. Lithium reacts quietly with water, sodium and potassium react with water with increasing vigour while rubidium and cesium react with water with exceptional violence.
This little explanation, is the reason behind the option chosen as the answer.
Order these species by increasing concentration of H30+ in a 1.0 M aqueous solution. (From the
solution with the least hydronium concentration to the solution with the most hydronium concentration)
NO
H2CO3, NH4, OH, HCO3, NH3, H20
Home
ir
H2CO3,NH4+, OH", HCO3, NH3,
H20
Paste
H20, H2CO3, NH4+, OH", HCO3-
NH3
6
con
O
OH", NH3, HCO3, H20, NH4+,
H2CO3
None of the answer choices are
correct.
Answer:
OH⁻ < NH₃ < HCO₃⁻ < H₂O < NH₄⁺ < H₂CO₃
Explanation:
We can do some rough calculations to find the approximate pH values of these solutions.
H₂CO₃
Kₐ ≈ 10⁻⁶
[tex]\text{H}^{+} = \sqrt{K_{\text{a}}c} = \sqrt{10^{-6} \times 10^{-1}} = \sqrt{10^{-7}} = 10^{-3.5}\\\text{pH} = -\log (10^{-3.5}) = \mathbf{3.5}[/tex]
NH₄⁺
Kb of NH₃ ≈ 10⁻⁵
Kₐ of NH₄⁺ ≈ 10⁻⁹
[tex]\text{H}^{+} = \sqrt{K_{\text{a}}c} = \sqrt{10^{-9} \times 10^{-1}} = \sqrt{10^{-10}} = 10^{-5}\\\text{pH} = -\log (10^{-5}) = \mathbf{5}[/tex]
OH⁻
Strong base
[OH⁻] = 10⁻¹
pOH = 1
pH = 14 - 1 = 13
HCO₃⁻
Salt of dibasic acid
K₁ ≈ 10⁻⁶; K₂ ≈ 10⁻¹⁰
[tex]{\text{H}^{+}} = \sqrt{K_{1}K_{2}} = \sqrt{10^{-6}\times 10^{-10}} = \sqrt{10^{-16}} = 10^{-8}\\\text{pH} = -\log (10^{-8}) = \mathbf{8}[/tex]
NH₃
Kb ≈ 10⁻⁵
[tex]\text{OH}^{-} = \sqrt{K_{\text{b}}c} = \sqrt{10^{-5} \times 10^{-1}} = \sqrt{10^{-6}} = 10^{-3}\\\text{pOH} = -\log (10^{-3}) = 3[/tex]
pOH = 14 - 3 = 11
H₂O
Neutral. pH = 7
Order from lowest [H₃O⁺] to highest [H₃O⁺]:
OH⁻ < NH₃ < HCO₃⁻ < H₂O < NH₄⁺ < H₂CO₃
pH 1 3 11 8 7 5 3.5
Which short-term environmental change would a very small asteroid or comet impact on Earth most likely cause? flooding extinction surface craters weather pattern changes
The correct answer is C. Surface craters
Explanation:
Short-term environmental changes involve temporary changes and effects in the ecosystem, which are mainly minor. In the case of a small asteroid or comet, this will likely lead to surface craters or changes in the surface of the impact zone. This is because the craters and asteroids impact the surface at hight speed. Also, because this is a minor event it might lead to the death of some organisms but not the extinction of these and it is not expected this has major effects such as changes in weather. Thus, the short-term effect that this will most likely cause is "surface craters."
Answer:
surface
Explanation:
Identify the structure of S (molecular formula C7H14O2). Compound S the odor of rum, (1H NMR data (ppm) at 0.93 (doublet, 6 H), 1.15 (triplet, 3 H), 1.91 (multiplet, 1 H), 2.33 (quartet, 2 H), and 3.86 (doublet, 2 H) ppm.Compound S:_______.
Answer:
Following are the answer to this question:
Explanation:
The structure of the S molecular formula [tex]C_7H_{14}O_2[/tex] defined in the attachment file.
Please find the attachment file.
30. A. An organic compound - A (C4H80) forms phenyl
hydrazone with phenyl hydrazine and reduces Fehling's
mpt any two questions:
solution. It has negative iodoform test. Identify the
organic compound A.
Answer:
Methyl ethyl ketone
Explanation:
Compound 'A' forms phenyl hydrazone, so it must be a carbonyl compound. Since it also gives a negative iodoform test, so it can't be an aldehyde.
'A' on reduction gives propane. So, it must be butanone. Ketone reacts with phenyl hydrazine to form phenyl hydrazone but gives a negative iodoform test.
Thus, the correct answer is - Methyl ethyl ketone
why we used petrol for vehicles not water?
Answer:
Water isn't combustible. There is nothing you can add to it other than gasoline that will make it even remotely combustible. Now, through electrolysis, it can be broken down into hydrogen and oxygen, which could be burned in an internal combustion engine.
because the water in itself does not produce energy
How many grams of H 2O are produced from 28.8 g of O 2? (Molar Mass of H 2O = 18.02 g) (Molar Mass of O 2=32.00 g) 4 NH 3 (g) + 7 O 2 (g) → 4 NO 2 (g) + 6 H 2O (g)
Answer: 13.9 g of [tex]H_2O[/tex] will be produced from the given mass of oxygen
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} O_2=\frac{28.8g}{32.00g/mol}=0.900moles[/tex]
The balanced chemical reaction is:
[tex]4NIO_2(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)[/tex]
According to stoichiometry :
7 moles of [tex]O_2[/tex] produce = 6 moles of [tex]H_2O[/tex]
Thus 0.900 moles of [tex]O_2[/tex] will produce =[tex]\frac{6}{7}\times 0.900=0.771moles[/tex] of [tex]H_2O[/tex]
Mass of [tex]H_2O=moles\times {\text {Molar mass}}=0.771moles\times 18.02g/mol=13.9g[/tex]
Thus 13.9 g of [tex]H_2O[/tex] will be produced from the given mass of oxygen
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degrees celsius . During the reaction 69.0kJ of heat flows out of the bath and into the flask.Calculate the new temperature of the water bath. You can assume the specific heat capacity of water under these conditions is 4.18J*g*K.
Answer:
309.1K
Explanation:
Step 1: Convert the flown heat to Joule
We will use the relationship 1 kJ = 1,000 J.
[tex]69.0kJ \times \frac{1,000J}{1kJ} = 69.0 \times 10^{3} J[/tex]
Step 2: Convert the mass of water to gram
We will use the relationship 1 kg = 1,000 g.
[tex]8.10 kg \times \frac{1,000g}{1kg} = 8.10 \times 10^{3} g[/tex]
Step 3: Convert the initial temperature to Kelvin
We will use the following expression.
K = °C + 273.15 = 33.9°C + 273.15 = 307.1 K
Step 4: Calculate the final temperature
We will use the following expression.
[tex]Q = c \times m \times (T_f - T_i)[/tex]
where,
Q: heatc: specific heat capacitym: massT f: final temperatureT i: initial temperature[tex]T_f = \frac{Q}{c \times m} + T_i = \frac{69.0 \times 10^{3}J }{4.18J/g.K \times 8.10 \times 10^{3}g} + 307.1K = 309.1K[/tex]
A critical reaction in the production of energy to do work or drive chemical reactions in biological systems is the hydrolysis of adenosine triphosphate, ATP, to adenosine diphosphate, ADP, as described by the reactionATP(aq)+ H2O(l) → ADP(aq)+ HPO4^-2 (aq)for which ΔGrxn = -30.5 kj/mol at 37.0C and pH 7.0. Required:a. Calculate the value of ΔGrxn in a biological cell in which [ATP] = 5.0 mM, [ADP] = 0.30 mM, and HPO4^-2= 5.0mMb. Is the hydrolysis of ATP spontaneous under these conditions?
Answer:
Δ [tex]G_{rxn}[/tex] = −51. 4 kJ/mol
However, since Δ [tex]G_{rxn}[/tex] is negative. The hydrolysis of ATP for this reaction is said to be spontaneous
Explanation:
From the question; The equation for this reaction can be represented as :
[tex]ATP_{(aq)} + H_2O_{(l)} \to ADP_{(aq)}+ HPO_4^{2-}} _{(aq)}[/tex]
where:
[tex]\Delta G ^0 _{rxn} =[/tex]-30.5 kJ/mol
= -30.5 kJ/mol × 1000 J/ 1 kJ
= -30.5 × 10 ⁻³ J/mol
Temperature T = 37 ° C
= (37+273)
= 310 K
pH = 7.0
[ATP] = 5.0 mM
= 5.0mM × 1M/1000mM
= 0.005 M
[ADP] = 0.30 mM
= 0.30 mM × 1M/1000mM
= 0.0003 M
[tex][HPO_4^{2-}}][/tex] = 5.0 mM
= 5.0mM × 1M/1000mM
= 0.005 M
The objective is to calculate the value for Δ [tex]G_{rxn}[/tex] in the biological cell and to determine if the hydrolysis of ATP is spontaneous under these conditions.
Now;
From the equation given; the equilibrium constant [tex]K_{eq}[/tex] can be expressed as:
[tex]K_{eq} = \dfrac{[ADP][ HPO_4^{2-}]} {[ATP]}[/tex]
[tex]K_{eq} = \dfrac{(0.0003 \ M)(0.005 \ M)} {(0.005 \ M)}[/tex]
[tex]K_{eq} = 3*10^{-4}[/tex]
The Δ [tex]G_{rxn}[/tex] in the biological cell can now be calculated as:
Δ [tex]G_{rxn}[/tex] = [tex](-30.5 * 10 ^3 \ J/mol) + (8.314 \ J/mol.K)(310 K ) In ( 3*10^{-4})[/tex]
Δ [tex]G_{rxn}[/tex] = [tex](-30.5 * 10 ^3 \ J/mol) + (-20906.68126)[/tex]
Δ [tex]G_{rxn}[/tex] = −51406.68 J/mol
Δ [tex]G_{rxn}[/tex] = −51. 4 × 10³ J/mol
Δ [tex]G_{rxn}[/tex] = −51. 4 kJ/mol
Thus since Δ [tex]G_{rxn}[/tex] is negative. The hydrolysis for this reaction is said to be spontaneous
a piece of copper weighing 850 grams is placed in a cup with 450 ml of water at 21 C and the Cp of the cup is 47 J/K, how many grams of gasoline would it take to heat the entire system to 110 C?
Answer:
4.2g of gasoline
Explanation:
In the problem, you need to give energy to the cup from the combustion of gasoline. The energy you need to give is:
Qcup + QWater + QCopper
As you need to increase (110ºC - 21ºC = 89º = Increase 89K) 89K, the Qcup is:
Qcup = 89K × (47J/K) = 4183J.
You can find Qwater using its specific heat, C (4.18Jg⁻¹K⁻¹), its mass (450mL = 450g) and the change of temperature, 89K:
QWater = CₓmₓΔT
QWater = 4.184Jg⁻¹K⁻¹ ₓ 450g×89K
QWater = 167569J
And Q of Copper, QCu, could be obtained in the same way (Specific heat Cu: 0.387 J/g⁻¹K⁻¹:
QCu = CₓmₓΔT
QCu = 0.387 J/g⁻¹K⁻¹ₓ850gₓ89K
QCu = 29277J
Thus, total heat you need is:
Q = Qcup + QWater + QCopper
Q = 4183J + 167569J + 29277J
Q = 201029J = 201kJ
The combustion of gasoline (Octane) produce 47.8kJ/g (Its heat of combustion). that means to produce 201kJ of energy you require:
201kJ × (1g / 47.8kJ) =
4.2g of octane = Gasoline you requireWhich correctly lists three characteristics of minerals?
solid, crystal structure, definite chemical composition
organic, crystal structure, definite chemical composition
human-made, solid, organic
crystal structure, definite chemical composition, human-made
Answer:a
Explanation:
The three characteristics of minerals are that they are solid, have definite crystal structure and definite chemical composition.
What are minerals?Minerals are defined as a chemical compound which has a well -defined composition and possesses a specific crystal structure.It occurs naturally in the pure form.
If a compound occurs naturally in different crystal structure then each structure is considered as a different mineral.The chemical composition of a mineral varies depending on the presence of small impurities which are present in small quantities.
Some minerals can have variable proportions of two or more chemical elements which occupy equivalent position in the crystal structure.It may also have variable composition which is split into separate species.
Physical properties of minerals include color,streak, luster,specific gravity and cleavage.
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in an endothermic reaction the ____ have more energy than the ____?
Answer: products; reactants
Explanation: as the endothermic reactions are tye one which absorbs energy
What is the pressure in millimeters of mercury of 0.0150 mol of helium gas with a volume of 213 mL at 50. C? (Hint: You must convert each quantity into the correct units (L, atm, mol and K) before substituting into the ideal gas law.)
Explanation:
0.08206 L atm mol-1K-1
pv=nRT
Px213 x10^-³ = 0.0150 x 0.08206 x 323
px213 x10^-³ = 0.398
p = 0.398/213 x10^-³
p = 1.87 x 10^-6atm
p = 0.0014mmHg
please brainliest
Given the thermochemical expression
BaO (s) + CO2 (g) =
BaCO3(s)
AH° = -662.8 kJ
Write the thermochemical expression for the production of 4 mol CO2 by decomposition of solid
barium carbonate.
Answer:
[tex]4BaCO_3(s)\rightarrow 4BaO(s)+4CO_2(g)\ \ \ ;\ \ \ \Delta H=2651.2kJ[/tex]
Explanation:
Hello,
In this case, in order to answer to the requirement, we first should invert the given reaction since it is the formation of barium carbonate and we need its decomposition:
[tex]BaCO_3(s)\rightarrow BaO(s)+CO_2(g)[/tex]
Thereby, the enthalpy of reaction is inverted, to positive since it is the contrary reaction:
[tex]\Delta H=662.8kJ[/tex]
Nevertheless, we need to specify it for the formation of 4 moles of carbon dioxide it means:
[tex]4BaCO_3(s)\rightarrow 4BaO(s)+4CO_2(g)\\\Delta H=662.8kJ*4[/tex]
Which finally results in the following thermochemical expression:
[tex]4BaCO_3(s)\rightarrow 4BaO(s)+4CO_2(g)\ \ \ ;\ \ \ \Delta H=2651.2kJ[/tex]
Regards.
Each energy level contains a different number of sublevels which means each
energy level can hold a different amount of electrons. How many electrons does
the third energy level hold?
A.2
B. 32
C. 8
D. 18
The third energy level will hold 18 electrons. Hence, option (D) is correct.
What is Energy Level ?The electrons surrounding an atom are located in regions around the nucleus called “energy levels”.
An energy level represents the 3-dimensional space surrounding the nucleus where electrons are most likely to be.
The general formula is that the nth shell can hold up to 2(n²) electrons in principle.
Therefore, The third energy level will hold 18 electrons. Hence, option (D) is correct.
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Perform the following
mathematical operation, and
report the answer to the correct
number of significant figures.
5.446 x 0.14156
calculate the volume i liters of a 3.48g/dl potassium iodide solution that contains 341.g of potassium iodide (KI) round your answer to 3 significant figures
Answer:
[tex]V=980L[/tex]
Explanation:
Hello,
In this case, we have a concentration that is per unit of deciliters, therefore, we need to convert it to litre basis:
[tex]3.48\frac{g}{dL} *\frac{1L}{10dL}=0.348\frac{g}{L}[/tex]
Then, to compute the volume we use the given mass to obtain:
[tex]V=\frac{341g}{0.348g/L}\\ \\V=980L[/tex]
Best regards.
Hypochlorous acid is formed in situ by reaction of aq. sodium hypochlorite solution with acetic acid. Draw balanced chemical equations to show the formation of hypochlorous acid and protonated hypochlorous acid.
Answer:
NaClO + CH₃COOH ----> HClO + CH3CO- + Na
Explanation:
This reaction occurs between the combination of a salt and an acid, that is, an oxide-reduction reaction
Searches related to If 0.75 grams of iron (Fe) react according to the following reaction, how many grams of copper (Cu) will be produced? Fe + CuSO4 -> Cu + FeSO4
Answer:
0.83 g
Explanation:
Step 1: Write the balanced equation
Fe + CuSO₄ ⇒ Cu + FeSO₄
Step 2: Calculate the moles corresponding to 0.75 g of Fe
The molar mass of Fe is 55.85 g/mol.
[tex]0.75g \times \frac{1mol}{55.85g} = 0.013 mol[/tex]
Step 3: Calculate the moles of Cu produced from 0.013 moles of Fe
The molar ratio of Fe to Cu is 1:1. The moles of Cu produced are 1/1 × 0.013 mol = 0.013 mol.
Step 4: Calculate the mass corresponding to 0.013 moles of Cu
The molar mass of Cu is 63.55 g/mol.
[tex]0.013mol \times \frac{63.55g}{mol} = 0.83 g[/tex]
Answer:
If 0.75 grams of iron (Fe) react, 0.85 grams of copper (Cu) will be produced.
Explanation:
You know the following balanced reaction:
Fe + CuSO₄ ⇒ Cu + FeSO₄
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following quantities react and are produced:
Fe: 1 moleCuSO₄: 1 moleCu: 1 moleFeSO₄: 1 moleBeing:
Fe: 55.85 g/moleCu: 63.54 g/moleS: 32 g/moleO: 16 g/molethe molar mass of the compounds participating in the reaction is:
Fe: 55.85 g/moleCuSO₄: 63.54 g/mole + 32 g/mole+ 4* 16 g/mole= 159.54 g/moleCu: 63.54 g/moleFeSO₄: 55.85 g/mole + 32 g/mole+ 4* 16 g/mole= 151.85 g/moleThen, by stoichiometry of the reaction, the amounts of reagent and product that participate in the reaction are:
Fe: 1 mole*55.85 g/mole= 55.85 gCuSO₄: 1 mole* 159.54 g/mole= 159.54 gCu: 1mole* 63.54 g/mole= 63.54 gFeSO₄: 1 mole* 151.85 g/mole= 151.85 gThen you can apply a rule of three as follows: if 55.85 grams of Fe produces 63.54 grams of Cu, 0.75 grams of Fe how much mass of Cu does it produce?
[tex]mass of Cu=\frac{0.75 grams of Fe*63.54 grams of Cu}{55.85 grams of Fe}[/tex]
mass of Cu= 0.85 grams
If 0.75 grams of iron (Fe) react, 0.85 grams of copper (Cu) will be produced.
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Answer:
Explanation:
equilibrium constant
Kc = [ C ]² / [ A ] [ B ]
= .5² / .2 x 3
= .4167
Let moles of A to be added be n
concentration of A unreacted becomes .2 + n M
increase of product C by .2 M will require use of A and B be .1 M
So unreacted A = .2 + n - .1 = n + .1
Kc = [ C ]² / [ A ] [ B ]
.4167 = .7² / ( n + .1 ) ( 3 - .1 )
n + .1 = .4
n = . 3 moles .
So .3 moles of A to be added .