Answer:
9+ (nine or older)
Step-by-step explanation:
Answer:
Greater then 9
Step-by-step explanation:
He paid and anyone under 9 dosent have to pay
What is the median price?
Answer:
23000
solution,
Arranging the data in ascending order:
12000, 12000 , 23000, 26000, 30000
N(total number of items)=5
Now,
[tex]median = ( \frac{n + 1}{2}) ^{th \: item} \\ \: \: \: \: \: \: = ( \frac{5 + 1}{2} ) ^{th \: item} \\ \: \: \: \: \: = ( \frac{6}{2} )^{th \: item} \\ \: \: \: = {3}^{rd\: item} [/tex]
Hope this helps..
Good luck on your assignment
Which functions have an axis of symmetry of x = -2? Check all that apply. A. f(x) = x^2 + 4x + 3 B. f(x) = x^2 - 4x - 5 C. f(x) = x^2 + 6x + 2 D. f(x) = -2x^2 - 8x + 1 E. f(x) = -2x^2 + 8x - 2
Answer:
A. f(x) = x^2 + 4x + 3
D. f(x) = -2x^2 - 8x + 1
Step-by-step explanation:
The axis of symmetry is found by h = -b/2a where ax^2 +bx +c
A. f(x) = x^2 + 4x + 3
h = -4/2*1 = -2 x=-2
B. f(x) = x^2 - 4x - 5
h = - -4/2*1 = 4/2 =2 x=2 not -2
C. f(x) = x^2 + 6x + 2
h = -6/2*1 = -3/2 = x=-3/2 not -2
D. f(x) = -2x^2 - 8x + 1
h = - -8/2*-2 = 8/-4 =-2 x=-2
E. f(x) = -2x^2 + 8x - 2
h = - 8/2*-2 = -8/-4 =2 x=2 not -2
Answer:
Hey there! The answer to this question is
A. f(x) = x^2 + 4x + 3
D. f(x) = -2x^2 - 8x + 1
Eric's age is 8 and her mother is 42.In how many years time will the mother be 3 times as old as her son
Answer:
9 years
Step-by-step explanation:
Let's call the amount of years x. We can write
42 + x = 3(8 + x)
42 + x = 24 + 3x
2x = 18
x = 9
me Left:1:23:57
Mandeep Sharma: Attempt 1
Question 1 (2 points)
A scientist records the internal temperature of a kiln that has been turned off for maintenance after
a limestone calcination reaction as 794 °C. He then leaves the room to allow the kiln cool further.
The room temperature is 25°C. An equation that models the temperature of the cooling kiln (T in °C,
t in min) is as follows:
T(t) = 1.0.73l/3.7 + 25
How fast is the reaction cooling rate (%T lost/min) to the nearest whole number?
Your Answer:
Answer
Answer:
c and I will talk to you later today or tomorrow morning and then I will
Step-by-step explanation:
email to you later today to see you and the kids are doing well and that you
An article reported that for a sample of 52 kitchens with gas cooking appliances monitored during a one-week period, the sample mean CO2 level (ppm) was 654.16, and the sample standard deviation was 165.4.
Required:
a. Calculate and interpret a 9596 (two-sided) confidence interval for true average C02 level in the population of all homes from which the sample was selected.
b. Suppose the investigators had made a rough guess of 175 for the value of s before collecting data. What sample size would be necessary to obtain an interval width of 50 ppm for a confidence level of 95%?
Answer:
a) [tex]654.16-2.01\frac{165.4}{\sqrt{52}}=608.06[/tex]
[tex]654.16+2.01\frac{165.4}{\sqrt{52}}=700.26[/tex]
b) [tex]n=(\frac{1.960(175)}{25})^2 =188.23 \approx 189[/tex]
So the answer for this case would be n=189 rounded up to the nearest integer
Step-by-step explanation:
Part a
[tex]\bar X=654.16[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
s=165.4 represent the sample standard deviation
n =52represent the sample size
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
The degrees of freedom aregiven by:
[tex]df=n-1=52-1=51[/tex]
Since the Confidence is 0.95 or 95%, the significance [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and the critical value would be [tex]t_{\alpha/2}=2.01[/tex]
Now we have everything in order to replace into formula (1):
[tex]654.16-2.01\frac{165.4}{\sqrt{52}}=608.06[/tex]
[tex]654.16+2.01\frac{165.4}{\sqrt{52}}=700.26[/tex]
Part b
The margin of error is given by this formula:
[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (a)
And on this case we have that ME =25 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
[tex]n=(\frac{z_{\alpha/2} s}{ME})^2[/tex] (b)
The critical value for this case wuld be [tex]z_{\alpha/2}=1.960[/tex], replacing into formula (b) we got:
[tex]n=(\frac{1.960(175)}{25})^2 =188.23 \approx 189[/tex]
So the answer for this case would be n=189 rounded up to the nearest integer
A boat that can travel 18 mph in still water can travel 21 miles downstream in the same amount of time that it can travel 15 miles upstream. Find the speed (in mph) of the current in the river.
Hey there! I'm happy to help!
We see that if the river isn't moving at all the boat can move at 18 mph (most likely because it has an engine propelling it.)
We want to set up a proportion where our 21 miles downstream time is equal to our 15 miles upstream time so we can find the speed. A proportion is basically showing that two ratios are equal. Since our downstream distance and upstream distance can be done in the same amount of time, we will write it as a proportion.
We want to find the speed of the river. We will use r to represent the speed of the river. When going downstream, the boat will go faster, so it will have a higher mph. So, our speed going down is 18+r. When you are going upstream, it's the opposite, so it will be 18-r.
[tex]\frac{distance}{speed} =\frac{21}{18+r} = \frac{15}{18-r}[/tex]
So, how do we figure out what r is now? Well, one nice thing to know about proportions is that the product of the items diagonal from each other equals the product of the other items. Basically, that means that 15(18+r) is equal to 21(18-r). This is a very nice trick to solve proportions quickly. We see that we have made an equation and now we can solve it!
15(18+r)=21(18-r)
We use the distributive property to undo the parentheses.
270+15r=378-21r
We subtract 270 from both sides.
15r=108-21
We add 21 to both sides.
36r=108
We divide both sides by 36.
r=3
Therefore, the speed of the river is 3 mph.
You also could have noticed that 18mph to 21 mph is +3, and 18mph to 15 mph -3 in -3 mph, so the speed of the river is 3 mph. That would have been a quicker way to solve it XD!
Have a wonderful day!
Calculate sales tax using the following information: Taxable amount of the sale: $ 142 Sales tax percentage: 7 % What is the amount of the sales tax? Round the answer to the nearest cent (hundredths).
Answer:
Step-by-step explanation:
142(.07)= 9.94 amount of the sales tax
$142+9.94= $151.94
i need help please!!!
Answer:
1 = 95
2 = 77
3 = 85
4 = 103
Step-by-step explanation:
Inscribed angles are half their arc that their 2 lines intersect.
the linear equation y=2x represents the cost y of x pounds of pears. which order pair lies on the graph of the equation? A. (2,4) B. (1,0) C.(10,5) D. (4,12)
Answer:
A. (2, 4)
Step-by-step explanation:
The ordered pairs represent (x, y). Since you have y =2x, this is the same as ...
(x, 2x)
That is, the second number in the pair needs to be twice the first number in the pair. Since you know your times tables, you know that this is not the case for (1, 0), (10, 5) or (4, 12). Those values of x would give (1, 2), (10, 20), (4, 8).
It is the case that you have (x, 2x) for (2, 4).
The point (2, 4) lies on the graph of y = 2x.
At what point does the line
Y = 2X + 6 intercept the Y-axis?
A. 2.
B. 8
C. -2
D. 1/6
E. 6
Answer:
E. 6
Step-by-step explanation:
The y-intercept is where the graph crosses the y-axis when x = 0. In that case, simply plug in x as 0:
y = 2(0) + 6
y = 6
Therefore, our graph crosses the y-axis at 6.
Answer: 6
Step-by-step explanation: The equation of this line is written in slope-intercept form which is more commonly known as y = mx + b form.
In this form, the m or the coefficient of the x term represents the slope
of the line and the b or the constant term represents the y-intercept.
We can see that the y-intercept is 6.
A line with points (-4.0) and (-3.1)
has a slope of?
Slope is the change in y over the change in x
Slope = (1-0) /( -3 - -4)
Slope = 1/1
Slope = 1
The Social Justice Club is going to rent a mammoth barbeque to cook the hot dogs for the hot dog sale. After contacting three rental companies in town, you have found out that each one will deliver and pick up their barbeque. The cost of propane is included in the rental. The rental costs are indicated below.
Rental A: $15/h
Rental B: $5/h + 50
Rental C: $9/h + 20
Student selling hot dogs at a table.
Write an equation that models the rental cost, C, for each company.
Graph all three models onto the same set of coordinate axis.
Which rental company should be chosen if you use the barbeque during lunch (11:05 - 12:30) and keep the barbeque to continue sales during the football game that will end about 4:30? Justify your answer.
Which rental company should be chosen if your school lunch hours run from 11:05 - 12:30? Justify your answer.
Which rental company should be chosen if your school returned the barbeque the following day? Justify your answer.
Answer:
(A)Cost of Rental A, C= 15h
Cost of Rental B, C=5h+50
Cost of Rental C, C=9h+20
(B)
i. Rental C
ii. Rental A
iii. Rental B
Step-by-step explanation:
Let h be the number of hours for which the barbeque will be rented.
Rental A: $15/h
Cost of Rental A, C= 15hRental B: $5/h + 50
Cost of Rental B, C=5h+50Rental C: $9/h + 20
Cost of Rental C, C=9h+20The graph of the three models is attached below
(b)11.05-4.30
When you keep the barbecue from 11.05 to 4.30 when the football match ends.
Number of Hours = 4.30 -11.05 =4 hours 25 Minutes = 4.42 Hours
Cost of Rental A, C= 15h=15(4.42)=$66.30 Cost of Rental B, C=5h+50 =5(4.42)+50=$72.10 Cost of Rental C, C=9h+20=9(4.42)+20=$59.78Rental C should be chosen as it offers the lowest cost.
(c)11.05-12.30
Number of Hours = 12.30 -11.05 =1 hour 25 Minutes = 1.42 Hours
Cost of Rental A, C= 15h=15(1.42)=$21.30 Cost of Rental B, C=5h+50 =5(4.42)+50=$57.10 Cost of Rental C, C=9h+20=9(4.42)+20=$32.78Rental A should be chosen as it offers the lowest cost.
(d)If the barbecue is returned the next day, say after 24 hours
Cost of Rental A, C= 15h=15(24)=$360 Cost of Rental B, C=5h+50 =5(24)+50=$170 Cost of Rental C, C=9h+20=9(24)+20=$236Rental B should be chosen as it offers the lowest cost.
A soda factory has a special manufacturing line to fill large bottles with 2 liters of their beverage. Every process is computerized. However, it doesn't always fill exactly 2 liters. It follows a normal distribution, witha mean of 1.98 liters and a variance of 0.0064 liters. If the amount of soda in a bottle is more than 1.5 standard deviations away from the mean, then it will be rejected. Find the probability that a randomly selected bottle is rejected.
A 0
B 0.04
C 0.07
D 0.13
E 0.
Answer:
[tex] z= \frac{2.1-1.98}{0.08}= 1.5[/tex]
And we can use the normal standard table and the complement rule and we got:
[tex]P(z>1.5)= 1-P(Z<1.5) =1- 0.933= 0.067 \approx 0.07[/tex]
And the best answer would be:
C 0.07
Step-by-step explanation:
Let X the random variable who represent the amount of soda filled in large bottles and we know this:
[tex]\mu = 1.98, \sigma =\sqrt{0.0064}= 0.08[/tex]
And we want to find this probability:
[tex] P(X> \mu +1.5 \sigma = 1.98 +1.5*0.08 =2.1)[/tex]
And for this case we can use the z score formula given by:
[tex] z=\frac{X -\mu}{\sigma}[/tex]
And replacing we got:
[tex] z= \frac{2.1-1.98}{0.08}= 1.5[/tex]
And we can use the normal standard table and the complement rule and we got:
[tex]P(z>1.5)= 1-P(Z<1.5) =1- 0.933= 0.067 \approx 0.07[/tex]
And the best answer would be:
C 0.07
You are riding your bike up Elm Trail towards Deer Trail. You plan to make a left turn on to Deer Trail. What is the angle measure of the turn?
Answer:
90 degrees
Step-by-step explanation:
This question can be explained using the plan x and y axis.
Suppose you are moving from any positive point on x axis which can be considered Elm trail
let say point be (5,0).
Now you move at origin and
then take left turn,
your left turn at origin will be negative side of y axis(which can be considered Deer trail)
hence, you move on negative y axis.
Since we know that angle of intersection of x and y axis is 90 degrees.
Thus, angle measure of turn is 90 degrees.
Identify which quadrant of the coordinate plane the point (−3, 15) lies in.
Answer:
Quadrant II.
Step-by-step explanation:
Quadrant | has positive x and y coordinates.
Quadrant || has negative x and positive y coordinates.
Quadrant ||| has negative x and y coordinates.
Quadrant |V has positive x and negative y coordinates.
Since -3 is negative and 15 is positive, the answer is Quadrant II.
The complement of the universal set U is 0. True of False
To study bonding between mothers and infants, a researcher places each mother and her infant in a playroom and has the mother leave for 10 minutes. The researcher records crying time in the sample of infants during this time that the mother was not present and finds that crying time is normally distributed with M= 7 and SD = 1.1.
Based on the empirical rule, state the range of crying times within 68% of infants cried, 95% of infants cried, and 99.7% of infants cried.
Answer:
The range of crying times within 68% of the data is (5.9, 8.1).
The range of crying times within 95% of the data is (4.8, 9.2).
The range of crying times within 99.7% of the data is (3.7, 10.3).
Step-by-step explanation:
According to the Empirical Rule in a normal distribution with mean µ and standard deviation σ, nearly all the data will fall within 3 standard deviations of the mean. The empirical rule can be broken into three parts:
68% data falls within 1 standard deviation of the mean. That is P (µ - σ ≤ X ≤ µ + σ) = 0.68. 95% data falls within 2 standard deviations of the mean. That is P (µ - 2σ ≤ X ≤ µ + 2σ) = 0.95. 99.7% data falls within 3 standard deviations of the mean. That is P (µ - 3σ ≤ X ≤ µ + 3σ) = 0.997.The mean and standard deviation are:
µ = 7
σ = 1.1
Compute the range of crying times within 68% of the data as follows:
[tex]P(\mu-\sigma\leq X\leq \mu+\sigma)=0.68\\\\P(7-1.1\leq X\leq 7+1.1)=0.68\\\\P(5.9\leq X\leq 8.1)=0.68[/tex]
The range of crying times within 68% of the data is (5.9, 8.1).
Compute the range of crying times within 95% of the data as follows:
[tex]P(\mu-2\sigma\leq X\leq \mu+2\sigma)=0.95\\\\P(7-2.2\leq X\leq 7+2.2)=0.95\\\\P(4.8\leq X\leq 9.2)=0.95[/tex]
The range of crying times within 95% of the data is (4.8, 9.2).
Compute the range of crying times within 99.7% of the data as follows:
[tex]P(\mu-3\sigma\leq X\leq \mu+3\sigma)=0.997\\\\P(7-3.3\leq X\leq 7+3.3)=0.997\\\\P(3.7\leq X\leq 10.3)=0.997[/tex]
The range of crying times within 99.7% of the data is (3.7, 10.3).
Suppose a geyser has a mean time between irruption’s of 75 minutes. If the interval of time between the eruption is normally distributed with a standard deviation 20 minutes, answer the following questions. (A) What is the probability that a randomly selected Time interval between irruption’s is longer than 84 minutes? (B) what is the probability that a random sample of 13 time intervals between irruption‘s has a mean longer than 84 minutes? (C) what is the probability that a random sample of 20 time intervals between irruption‘s has a mean longer than 84 minutes? (D) what effect does increasing the sample size have on the probability? Provide an exclamation for this result. Choose the correct answer below. (E) what might you conclude if a random sample of 20 time intervals between irruption‘s has a mean longer than 84 minutes? Choose the best answer below. I’m not entirely certain about my answer for a bit I am completely and utterly lost on the other questions... please help.
Answer:
(a) The probability that a randomly selected Time interval between irruption is longer than 84 minutes is 0.3264.
(b) The probability that a random sample of 13 time intervals between irruption has a mean longer than 84 minutes is 0.0526.
(c) The probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is 0.0222.
(d) The probability decreases because the variability in the sample mean decreases as we increase the sample size
(e) The population mean may be larger than 75 minutes between irruption.
Step-by-step explanation:
We are given that a geyser has a mean time between irruption of 75 minutes. Also, the interval of time between the eruption is normally distributed with a standard deviation of 20 minutes.
(a) Let X = the interval of time between the eruption
So, X ~ Normal([tex]\mu=75, \sigma^{2} =20[/tex])
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time between irruption = 75 minutes
[tex]\sigma[/tex] = standard deviation = 20 minutes
Now, the probability that a randomly selected Time interval between irruption is longer than 84 minutes is given by = P(X > 84 min)
P(X > 84 min) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{84-75}{20}[/tex] ) = P(Z > 0.45) = 1 - P(Z [tex]\leq[/tex] 0.45)
= 1 - 0.6736 = 0.3264
The above probability is calculated by looking at the value of x = 0.45 in the z table which has an area of 0.6736.
(b) Let [tex]\bar X[/tex] = sample time intervals between the eruption
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time between irruption = 75 minutes
[tex]\sigma[/tex] = standard deviation = 20 minutes
n = sample of time intervals = 13
Now, the probability that a random sample of 13 time intervals between irruption has a mean longer than 84 minutes is given by = P([tex]\bar X[/tex] > 84 min)
P([tex]\bar X[/tex] > 84 min) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{84-75}{\frac{20}{\sqrt{13} } }[/tex] ) = P(Z > 1.62) = 1 - P(Z [tex]\leq[/tex] 1.62)
= 1 - 0.9474 = 0.0526
The above probability is calculated by looking at the value of x = 1.62 in the z table which has an area of 0.9474.
(c) Let [tex]\bar X[/tex] = sample time intervals between the eruption
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time between irruption = 75 minutes
[tex]\sigma[/tex] = standard deviation = 20 minutes
n = sample of time intervals = 20
Now, the probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is given by = P([tex]\bar X[/tex] > 84 min)
P([tex]\bar X[/tex] > 84 min) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{84-75}{\frac{20}{\sqrt{20} } }[/tex] ) = P(Z > 2.01) = 1 - P(Z [tex]\leq[/tex] 2.01)
= 1 - 0.9778 = 0.0222
The above probability is calculated by looking at the value of x = 2.01 in the z table which has an area of 0.9778.
(d) When increasing the sample size, the probability decreases because the variability in the sample mean decreases as we increase the sample size which we can clearly see in part (b) and (c) of the question.
(e) Since it is clear that the probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is very slow(less than 5%0 which means that this is an unusual event. So, we can conclude that the population mean may be larger than 75 minutes between irruption.
Determine the sum of the arithmetic series 6 + 11 + 16 +......
91.
Answer:
873
Step-by-step explanation:
so the equation is: 5x+1
sum is:
[tex] \frac{first \: one \: + \: last \: one}{2} \times quantity \: of \: terms \\ [/tex]
we have 6( 5×1+1) to 91 (5×18+1)
so we have 18 terms
then:
[tex] \frac{91 + 6}{2} \times 18 = 873[/tex]
Please help. Use your calculator to work out. (:
Answer:
83.6155156
Step-by-step explanation:
[tex] \frac{ {16}^{2} - 17 }{ \sqrt{2.3 + 5.87} } \\ \\ = \frac{ 256 - 17 }{ \sqrt{8.17} } \\ \\ = \frac{ 239}{2.85832119 } \\ \\ = 83.6155156 \\ [/tex]
Solve of the following equations for x: x + 3 = 6
Answer:
X = 3Step-by-step explanation:
[tex]x + 3 = 6[/tex]
Move constant to R.H.S and change its sign:
[tex]x = 6 - 3[/tex]
Calculate the difference
[tex]x = 3[/tex]
Hope this helps...
Good luck on your assignment..
To measure the height of the cloud cover at an airport, a worker shines a spotlight upward at an angle 75° from the horizontal. An observer D = 585 m away measures the angle of elevation to the spot of light to be 45°. Find the height h of the cloud cover. (Round your answer to the nearest meter.)
Answer:
585m
Step-by-step explanation:
using SOHCAHTOA to solve the question
the angle of elevation is 45° so therefore the answer is 585 m
6th grade math, help me please :)
Answer:
(14,4) (21, 6) (28,8) If they had six losses, they would have 21 wins
Step-by-step explanation:
According to the information given, for every 7 wins, they lose 2 games. That means in order to finish the table, we have to find multiples of 7 and 2. If they won 14 games, they would have 4 losses. This is because since 14 is twice the value of 7, they would have lost twice the number of games.
The next would be 21 wins since 7x3 is 21 and 6 losses since 2x3 is 6
The last one would be 28 wins (7x4) and 8 losses (2x4)
If they had six losses, they would have 21 wins
Select the only true statement from the following. Question 17 options: Opposite numbers have the same sign and are the same distance from zero. Opposite numbers have different signs but are the same distance from zero. Opposite numbers have different signs and are different distances from zero. Opposite numbers have the same sign but are different distances from zero
Answer:
The true statement is "Opposite numbers have different signs but are the same distance from zero."
Some examples of opposite numbers are 1 and -1, 6 and -6, and 10 and -10.
Answer:
Opposite numbers have different signs but are the same distance from zero.
Step-by-step explanation:
Please answer this correctly
What is the value of x?
Answer:
x=98°
Step-by-step explanation:
The angles of a triangle must equal 180°.
To get the third angle (G) you must do: 180°-53°-45°
That will give you 82°
Anglr G and angle x create a straight line which is 180°.
so to get the answer you must do 180°-G=x
180°-82°=98°
Therefore x=98°
I need help asap I don't understand this
Answer:
[tex]\boxed{\sf \ \ \ a=-2, \ b = 1 \ \ \ }[/tex]
Step-by-step explanation:
Hello,
saying that the function is continuous means that you cannot have a "jump" in the graph of the function
so we want
a*(-3)+b=7 and a*4+b=-7
it comes
(1) -3a + b = 7
(2) 4a + b = -7
(2)-(1) gives 4a + b + 3a - b =7a = -7-7 = -14
so a = -14/7 = -2
we replace in (1)
b = 7 + 3*(-2) = 7 - 6 = 1
hope this helps
What is the volume of this aquarium?
Answer:
4,224 in ^3
Step-by-step explanation:
5184-960 (subtract the cut-out from the entire shape)
given that 3*6=12 and 2*5=9, then a*b may be defined as
Answer:
I noticed a pattern:
3 * 2 + 6 = 12 and 2 * 2 + 5 = 9
This means that a*b = 2a + b.
The sum of the numerator and the denominator of a fraction is 216. The fraction is equivalent to $\frac{2}{7}$. What is the value of the denominator?
Answer:
168
Step-by-step explanation:
The fraction is 48/168.
48 + 168 = 216
48/168 = 2/7
The value of the denominator is 168.
We can solve simultaneous equations to get the x and y coordinates.
x + y = 216
x/y = 2/7
x = 48
y = 168