An unknown acid was titrated two times with 0.10 M NaOH. The first titration was done using an indicator to determine the equivalence point volume. A second titration was carried out where the pH was determined throughout the entire titration. The data is given below.
Titration 1: mL unknown acid = 25.0, mL of NaOH needed to reach equivalence point = 30.00
Titration 2: mL unknown acid = 25.0
mL 0.1M pH
NaOH Added
0.0 3.72
5.0 5.82
10.0 6.22
15.0 6.52
20.0 6.82
25.0 7.22
30.0 9.63
35.0 11.92
a. What is the concentration of the unknown acid?
b. What is the Ka of the unknown acid?
c. Which of the indicators given below would be a good choice to use in the titration of this acid with the NaOH?

Answer:

n = 3.25 mol

Explanation:

Given data:

Pressure of sample = 2 atm

Volume of sample = 40 L

Temperature = 300 K

Number of moles = ?

Solution:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

2 atm ×40 L = n × 0.0821 atm.L/mol.K × 300 K

80 atm.L = n  × 24.63 atm.L/mol

n = 80 atm.L  /24.63 atm.L/mol

n = 3.25 mol

Answer:

Molarity =  2.02 M

Explanation:

Given data:

Molarity of solution = ?

Mass of sodium chloride = 38.5 g

Volume of solution = 325 mL (0.325 L)

Solution:

Number of moles = mass/molar mass

Number of moles = 38.5 g/ 58.44 g/mol

Number of moles = 0.658 mol

Molarity:

Molarity = number of moles / volume of solution in L

Molarity = 0.658 mol /0.325 L

Molarity =  2.02 M

The  formula of the hydrate = CuSO₄• 3H₂O

Given

4.175 grams sample CuSO₄• xH₂O

3.120 grams anhydrous compound CuSO₄

Required

The formula

Solution

mass of H₂O driven off :

= 4.175 - 3.12

= 1.055 g

MW CuSO₄ = 159.5 g/mol

MW H₂O = 18 g/mol

mol ratio of CuSO₄ : H₂O :

= 3.12/159.5 : 1.055/18

= 0.01956 : 0.05861

= 1 : 3

Based on the data provided, the formula of the hydrated salt is CuSO4.3H20

The formula of the hydrate is determined from the mole ratio of the anhydrous saltand water.

Mass of water = 4.175 - 3.120

mass of water = 1.055 g

Mole ratio= mass/molar mass

molar mass of CuSO4 = 160 g/mol

molar mass of H2O = 18 g/mol

CuSO4 = 3.120/160 = 0.0195

H2O = 1.055/18 = 0.0586

CuSO4 = 0.0195/0.0195 = 1

H2O = 0.0586/0.0195 = 3

Therefore, the formula of the hydrated salt is CuSO4.3H20

Learn more about hydrated salts at: https://brainly.com/question/24920157

Answer:

The number of valence electrons increases from top to bottom within each group.

Explanation:

The valence electrons are the outermost shell electrons.

Therefore, the number of valence electrons does not increase from top to bottom within each of the group.

Down a group, the number of valence electrons remains the same.

For group I elements, the number of electrons is 1.

 The group is the vertical arrangement of elements.

From left to right across a period, the number of valence electrons increases because you move from group to group.

Answer:

Molecular solid

Explanation:

Molecular solids have a very low melting point. This is because, they are composed of weak intermolecular forces hence the layers of the solid easily fall apart as the solid melts.

We can see here that the solid being considered melts easily. Hence we can conclude that it is actually a molecular solid.

Answer:

[tex]r_{H_2} = \frac{-1}{2} r_{HI}[/tex]

Explanation:

Hello!

In this case, considering the given chemical reaction:

[tex]H_2(g) + I_2(g) \rightarrow 2HI(g)[/tex]

Thus, by applying the law of rate proportions, we can write:

[tex]\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}[/tex]

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

[tex]r_{H_2} = \frac{-1}{2} r_{HI}[/tex]

Best regards!

Answer:

The object is moving at a constant speed.

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

Answer:

A

Explanation:

Correct on edge

The temperature and moles of gas constants would most likely be filled in the first row of the table. Therefore, option A is correct.

The gas constant, denoted by R, is a physical constant that is expressed in terms of units of energy per temperature increment per mole. It's also referred to as the ideal gas constant, the molar gas constant, or the universal gas constant.

A general constant in the equation of state of gases that is equal to the product of the pressure and volume of one mole divided by the absolute temperature in the case of an ideal gas see gas law sense c.

All gases adapt an equation of state known as the ideal gas law: PV = nRT, where n is the number of moles of the gas and R is the universal gas constant.

Thus, option A is correct.

To learn more about the gas constant, follow the link;

https://brainly.com/question/24281105

#SPJ5

Your question is incomplete, most probably your question was

The incomplete table below shows selected characteristics of gas laws.

Name

Variables

Constants

Equation

?

?

?

PV = k

Charles's law

?

?

V = kT

?

Temperature, pressure

?

P = kT

Combined gas law

Pressure, temperature, volume

?

?

Which constants would most likely be filled in the first row of the table?

temperature and moles of gas

volume and temperature

pressure and volume

pressure and moles of gas

Answer:

a.  x = + 2

b.  x = + 3

c.  x = + 2

d.  x = + 3

Explanation:

The oxidation number is a formal charge assigned to an atom present in a molecule or formula unit or ion based on some arbitrary rules.

a.

HgO

The oxidation number of Hg in HgO is:

x + (-2) = 0

x = +2

b.

Al₄C₃

The oxidation number of Al in Al₄C₃ is:

4x +(3 × -4) = 0

4x - 12 = 0

4x = +12

x = 12/4

x = +3

c. CrF₂

x + ( 2 × - 1) = 0

x - 2 = 0

x = + 2

d. Fe₂S₃

2x + ( 3 × - 2) = 0

2x + (-6) = 0

2x = 6

x = 6/2

x = +3

Answer:

The two elements are FLUORINE AND CHLORINE. These two elements have similar characteristics because they belong to the same group in the periodic table. On the periodic table, elements with similar properties are grouped together in the same group. Both chlorine and fluorine belongs to the halogen group.

Explanation:

Hope it helps, some how.

Answer:

When titanium (II) nitride forms an ionic compound, TiN is the chemical formula of the compound.

Answer:

We divide our value by 1.5×10⁸

Explanation:

AU is a unit to determine distance in the space.

We know that AU means astronomic unit.

The value for conversion is 1.5×10⁸ Km

1 AU = 1.5×10⁸ Km

Let's see the example:

One star is located from the sun, around 3.35×10¹⁰ Km away. To determine the distance in AU we use the conversion factor:

3.35×10¹⁰ Km . 1 AU / 1.5×10⁸ Km = 223.3 AU

Answer:

All organisms begin life as a single cell

Explanation:

Single cell also did you know 15 minutes can save you 15% more on car insurance

whats the question?

Answer:

50000ppm and 0.855M.

Explanation:

ppm is an unit of chemistry defined as the ratio between mg of solute (NaCl) and Liters of solution. Molarity, M, is the ratio between moles of NaCl and liters

A 5% (w/v) NaCl contains 5g of NaCl in 100mL of solution.

To solve the ppm of this solution we need to find the mg of NaCl and the L of solution:

mg NaCl:

5g * (1000mg / 1g) = 5000mg

L Solution:

100mL * (1L / 1000mL) = 0.100L

ppm:

5000mg / 0.100L = 50000ppm

To find molarity we need to obtain the moles of NaCl in 5g using its molar mass:

5g * (1mol / 58.5g) = 0.0855moles NaCl

Molarity:

0.0855mol NaCl / 0.100L = 0.855M

Answer:

0.0802 M.

Explanation:

Hello!

In this case, since the barium acetate has the following formula:

[tex]Ba(CH_3COO)_2[/tex]

So its molar mass is 255.43 g/mol, in order to compute the molarity of the barium cation, we first need the moles in 7.17 g:

[tex]n_{Ba(CH_3COO)_2} = 7.17g*\frac{1molBa(CH_3COO)_2}{255.43g} =0.0281molBa(CH_3COO)_2[/tex]

Now, since one mole of barium acetate contains one mole of barium cations, we infer there are 0.0281 moles of barium cations. Moreover, since the molarity is computed by dividing the moles of those ones by the volume of the solution in liters, 350 mL (0.350 L) as it does not change, it turns out:

[tex]M=\frac{0.0281molBa^{2+}}{0.350L}\\\\M=0.0802M[/tex]

Best regards!

The total mass of insulin in the bottle : m = 4500 mg

Given

225 ml of insulin

The concentration 20 mg/ml

Required

The total mass of insulin

Solution

Density is the ratio of mass per unit volume

Can be formulated

ρ = m / V

m = ρ x V

Input the value :

m = 20 mg/ml x 225 ml

m = 4500 mg

Answer:

Zinc

Explanation:

m = Mass of block [tex]1.8\times 10^{-2}\ \text{kg}=18\ \text{g}[/tex]

Dimension of block is 0.4981 inches by 0.531 inches, by 0.5839 inches

[tex]1\ \text{inch}^3=16.3871\ \text{mL}[/tex]

Volume of block

[tex]V=0.4981\times 0.531\times 0.5839\times 16.3871\ \text{mL}[/tex]

Density is given by

[tex]\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{18}{0.4981\times 0.531\times 0.5839\times 16.3871}\\\Rightarrow \rho=7.112\ \text{g/mL}[/tex]

The density of the metal is [tex]7.112\ \text{g/mL}[/tex]. The metal here is zinc.

Answer:

d. none of the above (all have the same kinetic energy)

Explanation:

The kinetic theory of gases states that the molecules of an ideal gas experience a constant random motion.

At standard temperature and pressure (STP), the kinetic energy of an ideal gas such as hydrogen, argon, neon, sodium, oxygen, helium, magnesium, beryllium, nitrogen, carbon, fluorine, chlorine etc are all the same.

The standard temperature and pressure (STP) of an ideal gas is 273K and 100 kPa.

Hence, all of the gases have the same kinetic energy at standard temperature and pressure (STP).

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where, K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Answer:

How the incident happened

Any chemicals involved in an incident

Any other hazards present in the lab

Explanation:

Above are the types of information that are necessary to communicate with emergency responders. The emergency responders ask the first question that how the incident happened. After that they ask that is there any harmful chemicals are present in the laboratory or what types of chemicals present in the laboratory. These questions were asked by the emergency responders in order to give the patient a suitable treatment.

The emergency responders are persons that helps in the case of emergency to deal with hazardous conditions. The information provided to the emergency responders helps in dealing with the condition.

The information that has to be provided to the emergency responder in case of a laboratory incident helps them to handle the situation. The questions about how the incident occurs, the presence of hazardous chemicals in the laboratory will help in avoiding the further hazard. The involvement of the chemical in the hazard will help to deal with the situation.

For more information about emergency responders, refer to the link:

https://brainly.com/question/20455351

Answer: If I'm correct it's 12.54 mL but don't rely on this because I'm not sure

Explanation:

Answer:

12.49 ml

Explanation:

Density = mass / volume

Volume = mass / density

Volume of zinc = 2.54/7.14

Volume of zinc = 0.3557

Initial volume = 12.13 ml

Total volume = initial volume+ volume of zinc

Total volume = 12.13 + 0.3557

Total volume = 12.4857 = 12.49 ml

Answer:

CoSO4.7H2O

Cobalt II tetraoxosulphate VI heptahydrate

Explanation:

According to IUPAC nomenclature, compounds are named systematically.

We were told that there are seven water molecules in each formula unit Hence the correct formula of the compound is CoSO4.7H2O

According to IUPAC system, the metal is first named, followed by its oxidation state in Roman numerals. Then the name of the anion is mentioned as well as the number of water molecules. We have to take into account the correct prefix signifying the number of molecules of water of crystallization.

Answer:

Chromuates are found in the chromosomes of the eukaryotic cells!!!!

Explanation:

I learned this in 7th grade!!!!

Mark Me Brainliest plzz

Answer:

294.3 g/mol b.

The mass of 1.0*10^9 molecules of aspartame is 2.943*10^11 g/mol

ASPARTAME

Aspartame is  used as an artificial non-saccharide sweetener 200 times sweeter than sucrose, and is commonly used as a sugar substitute in foods and beverages.

CALCULATION

mass  of one molecule of aspartame = 294.3g/mol

mass of 1.0*10^9 molecules of aspartame =294.3*(1.0*10^9) g/mol

                                                                     =2.943*10^11 g/mol

refer https://brainly.com/question/25225559

#SPJ2

Answer:

a. BaCl2 is ionic compound.

b. CH4 is covalent compound.

b. MnO2 is ionic compound.

e. H2S is covalent compound.

c. H3AsO4 is ionic compound.

f. CH3OH is covalent compound.

Explanation:

BaCl2, MnO2 and H3AsO4 are ionic compounds due to the presence of ionic bond between the atoms while on the other hand, CH4, H2S and CH3OH are covalent compounds due to the presence of covalent bond between their atoms. In covalent bonds, sharing of electrons occur whereas in ionic bonds, complete transfer of electrons occur from one atom to another atom.