Answer:
Calculated value will be greater than the actual value here. The reason for this being that a small amount was wasted. An example for explanation of this can be:
suppose the solution required 10 ml of KOH. Now the reading will be from 0 to 10 ml in the buret. Since a small amount was wasted, let this wasted amount be 2 ml, so the reading will now start from 2 ml for the actual experiment and go till 12 ml. But the person taking the reading will observe the value to be 12 ml, hence his calculated value will be greater than actual value.
Explanation:
brainliess plssss
The calculated value in this case will be higher than the real value. This happened because a minor amount was lost.
What is titration?Titration is a method of chemical analysis where the quantity of a sample's constituents is established by adding a precisely measured amount of a different substance whereby the desired constituent will react in a specific, known proportion.
A burette, which is essentially a long, calibrated measuring tube with such a stopcock as well as a delivery tube at its bottom end, is used to gradually administer a standard solution of titrating reagent, called titrant, to a specified concentration. Whenever the equilibrium is achieved, the addition is terminated. The calculated value in this case will be higher than the real value. This happened because a minor amount was lost.
Therefore, the calculated value in this case will be higher than the real value. This happened because a minor amount was lost.
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A sample of gas occupies a volume of 67.5 mL . As it expands, it does 131.0 J of work on its surroundings at a constant pressure of 783 Torr . What is the final volume of the gas g
Answer:
The final volume [tex]V2=1.3175L[/tex]
Explanation:
between work ( w), pressure ( P ) and volume ( V ) is the following:
w=−PΔV
where,
ΔV=V2−V1
It was stated that the gas is expanding, then the work is done by the system and it is of a negative value .
Note that work, should be expressed in 1L⋅atm=101.3J
CHECK THE ATTACHMENT FOR DETAILED EXPLATION
Oxygen gas is most soluble in water under which set of conditions?
High pressure and low temperature.
ii)
An organic liquid having carbon, hydrogen, nitrogen and oxygen was found to
contain C = 41.37%; H = 5.75% ; N= 16.09 % and the rest oxygen. Calculate
the Empirical formula
(6 marks)
Answer:
C3H5NO2
Explanation:
C = 41.37%;
H = 5.75% ;
N= 16.09 %;
O= (100 - 41.37 - 5.75 - 16.09)% = 36.79 %.
In 100 g of substance we have
C = 41.37 g;
H = 5.75 g ;
N= 16.09 g;
O = 36.79 g.
Molar mass (C) = 12 g/mol;
Molar mass(H) =1 g/mol;
Molar mass(N)= 14 g/mol;
Molar mass(O) = 16 g/mol.
C = 41.37 g* 1 mol/12g = 3.4475 mol;
H = 5.75 g *1 mol/1g = 5.75 mol;
N= 16.09 g*1mol/14g = 1.1493 mol;
O = 36.79 g* 1mol/16g = 2.2994 mol.
The Empirical formula shows ratio of moles of elements in the substance , so
C : H : N : O = 3.4475 mol : 5.75 mol : 1.1493 mol : 2.2994 mol =
= (3.4475 mol /1.1493 mol) : (5.75 mol/1.1493 mol) : (1.1493 mol /1.1493 mol) : :( 2.2994 mol/1.1493 mol) = 3 : 5 : 1 : 2
C : H : N : O = 3 : 5 : 1 : 2
C3H5NO2
all compounds are neutral true or false
Answer:
Even all compounds are neutral.
Explanation:
Some of them exhibit polarity. Because of the difference in electron affinity of the constituent atoms, the shared electrons are pulled towards the atom with high affinity to electrons.
2co(g) + o2(g)→2co2 (g) What type of reaction is shown
408 J of energy is transferred to a system consisting of 2.0 moles of an ideal gas. If the volume of this gas stays at a constant 4.4 L, calculate the change in internal energy of the gas.
Answer: The change in internal energy of the gas is +408 J
Explanation:
According to first law of thermodynamics:
[tex]\Delta E=q+w[/tex]
[tex]\Delta E[/tex] =Change in internal energy
q = heat absorbed or released
w = work done or by the system
w = work done on the system= [tex]-P\Delta V[/tex]
As volume is constant , [tex]\Delta V[/tex] = 0 and w = 0.
q = +408J {Heat absorbed by the system is positive}
[tex]\Delta E=+408J+(0J)=+408J[/tex]
Thus the change in internal energy of the gas is +408 J
A sample of chlorine gas starting at 686 mm Hg is placed under a pressure of 991 mm Hg and reduced to a volume of 507.6 mL. What was the initial volume of the chlorine gas container if the process was performed at constant temperature
Answer:
The initial volume of the chlorine gas [tex]V1=733.28mL[/tex]
Explanation:
Given:
P1= 686mmHg
P2= 991mmHg
V2= 5076mL
V1=?
According to Boyle's law which states that at a constant temperature, the pressure on a gas increases as it's volume decreases.
It can be expressed as : P1V1 = P2V2
Where P1 is the initial pressure
P2= final pressure
V1= initial volume
V2 = final volume
[tex]V1= (P2V2)/P1[/tex]
V1= (991mmHg*507.6mL)/686mmHg
V1=503031.6/686
[tex]V1=733.28mL[/tex]
Therefore, The initial volume of the chlorine gas [tex]V1=733.28mL[/tex]
When solutions of and are mixed, the mixture becomes cloudy. After a few days, a white solid is observed on the bottom of the beaker with a clear liquid above it. (a) Write a balanced equation for the reaction that occurs. (b) Why is the solution cloudy at first
Answer:
(a) [tex]BaCl_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaCl(aq)[/tex]
(b) The particles of the formed barium sulfate remain suspended in the aqueous media forming a colloid.
Explanation:
Hello,
In this case, when solutions of barium chloride and sodium sulfate are mixed, the following chemical reaction is carried out:
[tex]BaCl_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaCl(aq)[/tex]
Thus, we can notice that the product barium sulfate remains solid since its solubility in aqueous media is very low, for that reason at the beginning the solution becomes cloudy as its particles remain suspended in the water forming a colloid. Nevertheless, after some days, the suspended particles get precipitated by the effect of the gravity, therefore, we observe the solid on the bottom of the beaker.
Regards.
Which phrase describes one characteristic of radioactive elements?
are produced in a laboratory
O decay at a constant rate
O have a consistent number of particles
release energy and particles to maintain radioactivity
Answer:
B) decay at a constant rate
Explanation:
Over their lifetime, the radioactive elements tend to have constant rate of decay. This is seen in chemistry in Kinetics, where we see that radioactive elements follow first order kinetics where the rate at which they decay is constant (no matter what concentration we have)
Answer:
B) decay at a constant rate
Explanation:
just took the test
please helppp asaappppppp
Answer:
B. s, p, d, f
Explanation:
These things are often referred to as suborbitals and you normally have s,p,d,f.
S has 1 two orbitals
P has 3 orbitals
D has 5 orbitals
F has 7 orbitals
and each orbital can house 2 electrons
can a kind human being help me with this table at least only with the first burning fire wood someone please
Answer:
See below
Explanation:
* Burning fire wood is given to be our first option. Now burning tends to be a property of wood, and it does effect the chemical compositions of it. Wood, in the presence of fire / oxygen, turns into ash and carbon dioxide.
* Decomposition is recognized as a chemical change, and heating copper carbonate is a perfect example of decomposition. When energy is added to this chemical process, the copper carbonate decomposes into copper oxide.
* Mixing sodium chloride solution and silver nitrate solution. When this reaction takes place, a white precipitate of AgCl is formed. And of course, this is a chemical reaction.
* When acids or bases come in contact with citric acid, the pH degree changes much. Due to this, carbon dioxide bubbles are formed.
* When eggs are fried they absorb the heat in the pan. Doing so the egg starts to curl a bit, resulting in the formation of new particles.
_______________________________________________________
I hope this gave you a start!
What is the mole fraction of a acetyl bromide
Answer:
Mole fraction(CHCl3) = 0.681
Mole fraction (CH3COBr) = 0.319
Explanation:
Molar mass(CHCl3) = 12+ 1 + 3*35.5 = 119.5 g/mol
Molar mass(CH3COBr) = 2*12 + 3*1 + 16 + 80 = 123 g/mol
112. g* 1mol/119.5g = 0.9372 mol CHCl3
54. g * 1 mol/123g = 0.4390 mol CH3COBr
Mole fraction(CHCl3) = 0.9372/(0.9372+0.4390) = 0.681
Mole fraction (CH3COBr) = 0.4390/(0.9372+0.4390) = 0.319
0.681+0.319 =1.000 true
3. The Kp for the reaction below is 1.49 × 108 at 100.0 °C:CO (g) + Cl2 (g) → COCl2 (g)In an equilibrium mixture of the three gases, PCO = PCl2 = 1.76 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is ________ atm.
Answer:
In an equilibrium mixture of the three gases, PCO = PCl2 = 2.22 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is kp=(COCl2)/(CO)(Cl2) which is . So, the correct answer is 7.34.
Write the electron configuration for the element titanium, Ti.
Express your answer in condensed form in the order of orbital filling as a string without blank space between orbitals. For example, the electron configuration of Li could be entered as 1s^22s^1 or [He]2s^1.
Answer:
[tex][Ar] 3d^{2} 4s^{2}[/tex]
Explanation:
You can look at the periodic table and figure out the electron config.
Q4. A 0.100 M solution of the weak acid HA was titrated with 0.100 M NaOH.The pH
measured when Vb = ½ Ve was 4.62. Using activity coefficients,calculate pKa.The size of the
A− anion is 450 pm.
Do you think there is a limit to the size of Atoms scientist can make? prove with evidence.
Answer:
Yes, there is a limit to the size of atoms that scientists can make.
Explanation:
In the nucleus, atoms contain protons and neutrons. It is known that as the number of protons in the nucleus increases, the atom becomes unstable due to the repulsion of positively charged protons clumped together in the small space of the nucleus.
However, an attractive force exists between neutrons and protons which binds the nucleus together and minimizes repulsion between protons. Even neutrons have recently been found to slightly repel each other.
Several attempts made at synthesizing many very heavy elements lately have proved abortive because the elements only exist for a few fractions of a second owing to large repulsion between the particles in the nucleus.
This goes a long way to show that there is a limit to the number of protons and neutrons that can be assembled together to form a new nucleus. We cannot bring an unlimited number of nucleons together to form new atoms due to inter particle repulsive forces.
artaric acid, H2C4H4O6, has two acidic hydrogens. The acid is often present in wines and precipitates from solution as the wine ages. A solution containing an unknown concentration of the acid is titrated with NaOH. It requires 21.65 mL of 0.3500 M NaOH solution to titrate both acidic protons in 50.00 mL of the tartaric acid solution. You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem. Part A Write a balanced net ionic equation for the neutralization reaction. Express your answer as a chemical equation including phases.
Answer:
2H⁺(aq) + + 2OH⁻(aq) → 2H₂O(l)
Explanation:
A acid that has two acidic hydrogens requires to moles of NaOH per mole of acid producing the salt of the acid and water.
If the acid is tartaric acid, H₂C₄H₄O₆, the reaction with NaOH is:
H₂C₄H₄O₆(aq) + 2NaOH(aq) → 2H₂O(l) + 2NaC₄H₄O₆(aq)
Now, ions in solution in the reaction are:
2H⁺(aq) + C₄H₄O₆²⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → 2H₂O(l) + 2Na⁺(aq) +C₄H₄O₆²⁻(aq)
Thus, net ionic equation (Lisiting only the ions involved in the reaction) is:
2H⁺(aq) + + 2OH⁻(aq) → 2H₂O(l)In the diagram below, particles of the substance are moving from the liquid phase to the gas phase at the same rate as they move from the gas phase to the liquid phase. A number of balls are loosely packed in the bottom of a container, beneath a line across the middle of the container, and a few balls above the line. 2 balls below the line have arrows pointing upward through the centerline; a few of the balls above the line have arrows pointing down through the centerline. The gas and liquid are at equilibrium. a high vapor pressure. a low vapor pressure. zero vapor pressure.
Answer:
The gas and liquid is in equilibrium.
Explanation:
liquids within a container undergoes state change, changing into gas. If this container is left open, these gases will escape into the external environment. In a situation in which the container is closed, the molecules that leave the liquid surface as gas will eventually condense on contact with the cover wall and change back into the liquid state. Some of these gases will reenter the liquid surface. At first, more of the liquid is transformed into gas and escape into the space above the liquid surface. Eventually, the available space becomes saturated with vapor, and then some of the gases start entering the liquid phase at the same rate as the liquid enters the gas phase. At this stage, the gas and liquid phase now exists in equilibrium.
Given a gas whose temperature is 418 K at a pressure of 56.0 kPa. What is the pressure of the gas if its Temperature changes to 64°C?
Answer: P₂=0.44 atm
Explanation:
For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.
Gay-Lussac's Law: [tex]\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }[/tex]
First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.
64+273K=337K
Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.
[tex]56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm[/tex]
Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.
[tex]P_{2} =\frac{T_{2} P_{1} }{T_{1} }[/tex]
[tex]P_{2}=\frac{(337K)(0.55atm)}{418K}[/tex]
P₂=0.44 atm
The partial Lewis structure that follows is for a hydrocarbon molecule. In the full Lewis structure, each carbon atom satisfies the octet rule, and there are no unshared electron pairs in the molecule. The carbon-carbon bonds are labeled 1, 2, and 3.
A) How many hydrogen atoms are in the molecule?
B) Rank the carbon-carbon bonds in order of increasing bond length.
C) Which carbon-carbon bond is the strongest one?
Answer:
A) How many hydrogen atoms are in the molecule?
The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperature, the chemical reactions associated with the cooking of food take place at a greater rate. (a) Some food cooks fully in 7.00 min in a pressure cooker at 113.0°C and in 49.0 minutes in an open pot at 100.0°C. Calculate the average activation energy for the reactions associated with the cooking of this food. kJ mol-1 (b) How long will the same food take to cook in an open pot of boiling water at an altitude of 10000 feet, where the boiling point of water is 89.8 °C? min
Answer:
the activation energy Ea = 179.176 kJ/mol
it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.
Explanation:
From the given information
[tex]T_1 = 100^0 C = 100+273 = 373 \ K \\ \\ T_2 = 113^0 C = 113 + 273 = 386 \ K[/tex]
[tex]R_1 = \dfrac{1}{7}[/tex]
[tex]R_2 = \dfrac{1}{49}[/tex]
Thus; [tex]\dfrac{R_2}{R_1} = 7[/tex]
Because at 113.0°C; the rate is 7 time higher than at 100°C
Hence:
[tex]In (7) = \dfrac{Ea}{8.314}( \dfrac{1}{373}- \dfrac{1}{386})[/tex]
1.9459 = [tex]\dfrac{Ea}{8.314}* 9.0292 *10^{-5}[/tex]
[tex]1.9459*8.314 = Ea * 9.0292*10^{-5}[/tex]
[tex]16.1782126= Ea * 9.0292*10^{-5}[/tex]
[tex]Ea = \dfrac{16.1782126}{ 9.0292*10^{-5}}[/tex]
Ea = 179.176 kJ/mol
Thus; the activation energy Ea = 179.176 kJ/mol
b)
here;
[tex]T_2 = 386 \ K \\ \\T_1 = (89.8 + 273)K = 362.8 \ K[/tex]
[tex]In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})[/tex]
[tex]In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})[/tex]
[tex]In (\dfrac{R_2}{R_1}) = 0.00357[/tex]
[tex]\dfrac{R_2}{R_1}= e^{0.00357}[/tex]
[tex]\dfrac{R_2}{R_1}= 1.0035[/tex]
where ;
[tex]R_2 = \dfrac{1}7{}[/tex]
[tex]R_1 = \dfrac{1}{t}[/tex]
Now;
[tex]\dfrac{t}{7}= 1.0035[/tex]
t = 7.0245 mins
Therefore; it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.
a). The activation energy given by the reactions related to the cooking of food in the pressure cooker would be:
[tex]Ea = 179.176 kJ/mol[/tex]
b). The time duration that is taken by the same food to cook in an open vessel would be:
[tex]7.0245 mins[/tex]
Activation Energya). Given that,
Temperature [tex]1[/tex] [tex]= 100[/tex]° C
Temperature [tex]2[/tex] [tex]= 113[/tex]° C
In Kelvin,
Temperature [tex]1[/tex] [tex]= 100 + 273[/tex]
[tex]= 373 K[/tex]
Temperature [tex]2[/tex] [tex]= 113 + 273[/tex]
[tex]= 386 K[/tex]
[tex]R_{1} = 1/7\\R_{2} = 1/49[/tex]
∵ [tex]R_{2}/R_{1} = 49/7 = 7[/tex]
It is given that at [tex]113[/tex] rate [tex]=[/tex] [tex]7[/tex] × [tex]100[/tex]°C
Therefore,
[tex]Ea/8.314 (1/373 - 1/386) =[/tex] [tex]In(7)[/tex]
so,
[tex]Ea[/tex] [tex]= 16.1782126/(9.0292 * 10^{-5})[/tex]
∵ Activation energy [tex]= 179.176 kJ/mol[/tex]
b). As we know,
[tex]T_{2}[/tex] [tex]= 386 K[/tex]
[tex]T_{1}[/tex] [tex]= (89. 8 + 273)[/tex]
[tex]= 362.8 K[/tex]
by employing the formulae,
[tex]In(\frac{R_{2} }{R_{1} }) = \frac{Ea}{R} (1/T_{1} - 1/T_{2})[/tex]
[tex]In(\frac{R_{2} }{R_{1} }) = 179.176/8.314 (1/362.8 - 1/386)[/tex]
By solving this, we get
[tex]R_{2}/R_{1} = 1.0035[/tex]
Thus,
[tex]R_{2} = 1/7[/tex]
[tex]R_{1} = 1/t[/tex]
∵ t [tex]= 7.0245 min[/tex]
Thus, the time duration would be [tex]7.0245 minutes[/tex].
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This ether can, in principle, be synthesized by two different combinations of haloalkane and metal alkoxide. Draw the combination of alkyl chloride and potassium alkoxide that forms the higher yield of ether. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Include counter-ions, e.g., Na , I-, in your submission, but draw them in their own separate sketcher. Separate multiple reactants using the sign from the drop-down menu.
Answer:
The 2 different combinations are given in the attached figure. The 2nd combination has a higher yield due to less hindrance by the alkyl halide.
Explanation:
The first reaction is between an alkyl halide and metal alkoxide. In this case, the alkyl chloride would be a secondary component and thus will cause greater hindrance to the yield. The reaction is as given in the attached figure
The second reaction is between a benzene ring containing halide and metal alkoxide. Now as the reaction is via alkyl chloride being the primary agent, there is less hindrance and thus greater yield in this case.
A theater director reinterprets a play by replacing its classical score with
current pop hits. Which statement describes the most likely effect of this
change on audience members?
O A. The main characters will appear more conservative.
B. The play will be more appealing to a younger audience.
C. The audience will think more about themes of patriotism.
O D. The tone will be more negative and depressing.
Answer:
The play will be more appealing to a younger audience.
Explanation:
A younger audience will more likely appreciate current pop hits rather than classical score.
Answer:
B. The play will be more appealing to a younger audience.
Explanation:
If the audience is younger, then this would be more appealing to them because pop has always been one of the fan-favorties of younger generations
The proposed mechanism for a reaction is: Step 1: A + B X (fast) Step 2: X + C Y (slow) Step 3: Y D (fast) What is the overall reaction? A. A + B + C D B. A + X Y + D C. A + B Y D. A + Y D
Answer:
A. A + B + C --> D
Explanation:
Step 1: A + B --> X (fast)
Step 2: X + C --> Y (slow)
Step 3: Y --> D (fast)
To obtain the overall reaction, we have to sum up the reactants and products of all step and eliminate the intermediates.
Reactants:
A + B + X + C + Y
Products:
X + Y + D
So we have;
A + B + X + C + Y --> X + Y + D
Upon elimination of intermediates, we have;
A + B + C --> D
The correct option is A.
When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are:
sulfur dioxide (g) + water (l) __________sulfurous acid (H2SO3) (g) + water (I)
Answer:
Sulfur dioxide + 2 ( water ) -----> sulfurous acid + water /
SO2 + 2 ( H2O ) -----> H2SO3 + H2O
Explanation:
This formula may not be right. Sulfur dioxide tends to react with water to produce sulfurous acid as per it's formula, but then again that chemical reaction need not be balanced. However, I will solve for either case here -
Sulfur dioxide + water -----> sulfurous acid,
Sulfur dioxide + water -----> sulfurous acid + water
_______________________________________________________
As I mentioned before, Sulfur dioxide + water -----> sulfurous acid is a chemical reaction that need not balancing as the number of each element present on the reactant and product side are the same. To help, let me rewrite this reaction -
SO2 + H2O -----> H2SO3,
Reactant | Product
Sulfur = 1, Sulfur = 1,
Oxygen = 3, Oxygen = 3,
Hydrogen = 2 Hydrogen = 2
And hence the equation is already balanced. Now let us consider the case we supposedly have at hand - Sulfur dioxide + water -----> sulfurous acid + water. Take a look at the attachment below;
Choose the correct option for the redox reaction below : 8H+(aq) + MnO4-(aq) + 5Fe2+(aq) → Mn2+(aq) + 5Fe3+(aq) 4H2O(l) H+ (oxidized or reduced) Answer 1 Choose... MnO4- (oxidizing or reducing agent) Answer 2 Choose... Fe2+ (oxidizing or reducing agent) Answer 3 Choose... Fe2+ (oxidized or reduced) Answer 4 Choose... O in MnO4- (oxidized or reduced) Answer 5 Choose... Mn in MnO4- (oxidized or reduced) Answer 6 Choose...
Explanation:
8H+(aq) + MnO4-(aq) + 5Fe2+(aq) → Mn2+(aq) + 5Fe3+(aq) + 4H2O(l)
To determine if a substance was reduced or oxidized, the oxidation number at the reactant and product side is compared.
When oxidation occurs, an element loses electrons and its oxidation number increases (becomes more positive). When reduction occurs, an element gains electrons and its oxidation number decreases or is reduced (becomes more negative).
H+ (oxidized or reduced) Answer 1 Choose...
There is an increase in oxidation number from 0 to 1. This means H+ was oxidized.
MnO4- (oxidizing or reducing agent) Answer 2 Choose...
In chemistry, an oxidizing agent is a substance that has the ability to oxidize other substances — in other words to accept their electrons
MnO4- is a strong oxidizing agent.
Fe2+ (oxidizing or reducing agent) Answer 3 Choose...
A reducing agent means it will itself get oxidized. In this reaction, Fe2+ is the reducing agent.
Fe2+ (oxidized or reduced) Answer 4 Choose...
Oxidized
O in MnO4- (oxidized or reduced) Answer 5 Choose...
There is no change in oxidation number of , so it was neither reduced nor was it oxidized.
Mn in MnO4- (oxidized or reduced) Answer 6 Choose...
There is a decreaase in oxidation number from +7 to +2. This means reduction.
What is the net ionic equation of the reaction of MgSO4 with Ba(NO3)2 ?
Answer:
Ba(+2)(aq) + SO4(-2)(aq) -----> BaSO4(s)
Explanation:
Take a look at the attachment below;
What is the purpose of a buffer?
A. To limit pH changes in solution
B. To force the pH of a solution to change
C. To make a solution form a salt
O D. To neutralize the pH of a solution
Answer:
To limit pJ changes in solution
Which group of diamagnetic transition metals exhibits trends in density and melting points that don't match the same trends seen in other groups?
A. Group 12
B. Group 3
C. Group 11
D. Group 7
Answer:
Group 12
Explanation:
Group 12 transition metals include; zinc cadmium, mercury and copernicium. Because of their striking difference in property when compared to other transition elements, they are sometimes called post-transition elements.
These elements possess completely filled ns and nd orbitals hence they are diamagnetic. They have the lowest melting points and densities among all transition metals. Their densities in gcm^-3 are; Zn (7.14), Cd(8.65) and Hg (13.5). We can see that unlike other transition metal groups, their densities vary only within a narrow margin hence they have properties slightly different from other transition elements.
what type of matter is toluene
Answer:
is an organic chemical conpond