Answer:
136Hz
0.0074s
Explanation:
Given parameters:
Velocity of the wave = 340m/s
Wavelength = 2.5m
Unknown:
Frequency and period = ?
Solution:
To solve this problem, we use the wave velocity equation;
V = F ∧
V is the velocity
F is the frequency
∧ is the wavelength
Let us find the frequency
340 = F x 2.5
F = 136Hz
Period is the inverse of frequency;
Period = [tex]\frac{1}{136}[/tex] = 0.0074s
A wagon, initially traveling at a constant 8.2 m/s, starts going down a hill that creates an acceleration of 9.0 m/s2. What is the wagon's velocity 6.6 s after it starts accelerating down the hill?
Answer:
67.6m/s
Explanation:
Given parameters:
Initial velocity = 8.2m/s
Acceleration = 9.0m/s²
Time = 6.6s
Unknown:
Final velocity = ?
Solution:
To solve this problem, we use the expression below:
Acceleration = [tex]\frac{v - u }{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
9 = [tex]\frac{v - 8.2}{6.6}[/tex]
v - 8.2 = 59.4
v = 59.4 + 8.2 = 67.6m/s
A negative charge of -0.00067 C and a positive charge of 0.00096 C are separated by 0.7 m. What is the force between the two charges?
Answer:
-11,813.87N
Explanation:
According to coulombs law, the Force between the two charges is expressed as;
F = kq1q2/d²
k is the coulombs constant = 9*10⁹kg⋅m³⋅s⁻²⋅C⁻².
q1 = -0.00067 C
q2 = 0.00096 C
d = 0.7m
Substitute into the formula:
F = 9*10^9 * -0.00067 * 0.00096/0.7²
F = 9*10⁹*-6.7*10⁻⁴*9.6*10⁻⁴/0.49
F = -578.88*10⁹⁻⁸/0.49
F = -578.88*10/0.49
F = -5788.8/0.49
F = -11,813.87N
Hence the force between the two charges is -11,813.87N
Help!! ASAP plz
Determine the mass of the object below to the correct degree of precision.
358.3g
358.20g
358.30g
358.2g
Indiana Jones is being chased over the rooftops of Marseilles by some random villain. He looks ahead and sees that there is a 7 meter gap between this rooftop, which is 25 meters above the ground, and the next, which is 19 meters above the ground. He gathers up all his strength and runs and leaps from the higher roof to the lower. How fast must he run so he doesn't go plummeting into the street below? *
5 points
Answer:
30 mph
Explanation:
Which one doesn't belong in the group? oxygen, sulfur, selenium,
tellurium *
Your answer
This is a required question
borons
Radar tells an air traffic controller that a jet is slowing as it nears the
airport. Which might represent the jet's velocity?
A. 700 h/km
B. 700 km
C. 700 km/hr
D. 700 km/h west
Choice-D is the only velocity on the list.
(It has a speed and a direction.)
The jet's velocity might be represented by 700 km/h west. Hence, option (D) is correct.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
In this question, 700 h/km, 700 km have different unit that of velocity. So, option (A) and option (B) is not correct. . 700 km/hr has same unit that of velocity. But it does not has direction. So, option (C) is also incorrect. 700 km/h west has the same unit of velocity with define direction. So, option (D) is correct.
Hence option (D) is correct answer.
Learn more about velocity here:
https://brainly.com/question/18084516
#SPJ6
Reading the temperature of a solution by using a thermometer is an example of a(n) ________.
A.
hypothesis
B.
observation
C.
inference
D.
conclusion
Answer:
B. Observation
Explanation:
Using a thermometer to read the temperature of a solution is tantamount to the making an observation.
Observation are recorded using our senses of sight, taste, earing, feeling etc or by the use of instrument.
Through observation, data is usually collected to make inferences about an experiment. An observation leads to the formulation of a hypothesis which is scientific guess that leads to experimental designs. Conclusions are drawn from the information of data obtained from an experiment.The common version of Newton’s second law of motion, EF= ma, is actually a special case that is true only when an objects _____ is constant.
-Mass
-Momentum
-Force
-Velocity
Answer:
A
Explanation:
only is true when the objects mass is constant
Answer:
A.
Explanation:
When the mass is constant. Newton's second law will work perfectly.
Fun fact you probably won't need to know this, but the original formula that Newton derived was F=change in momentum divided by change in time. Momentum will account for a change in mass. The schooling system lies to you all the time especially in physics.
Please help me
27. A 20 kg object is at rest. A 6 N force pulls to the right on
the object for 10 seconds.
A) Find the impulse on the object.
B) Find the final momentum of the object.
C) What is its final velocity?
Answer:
a. 60 N*s
b. 60 (kg*m)/s
c. 3 m/s
Explanation:
Givens:
m = 20 kg
v_i = 0 m/s
t = 10 s
F = 6 N
a) Impulse:
I = F*t
I = 6 N*10 s
I = 60 N*s
b) Momentum:
p = v*m
F = m(a)
a = F/m
a = 6 N/20 kg
a = 0.3m/s^2
a = (v_f -v_i)/t
v_f = (0.3 m/s^2)*10 s
v_f = 3.0 m/s
p = 3 m/s*20 kg
p = 60 (kg*m)/s
c. Final velocity
a = (v_f -v_i)/t
v_f = (0.3 m/s^2)*10 s
v_f = 3.0 m/s
The impulse, momentum and final velocity can all be obtained from Newton's second law.
Let us recall that the impulse is obtained as the product of force and time.
Impulse = Force × time
Impulse = 6 N × 10 s = 60 Ns
From Newton's second law of motion;
F.t = mv - mu
Since the object was initially at rest;
F.t = mv
Hence, the final velocity of the object is 60 Kgms-1
The final velocity is obtained from;
F.t = mv
v = F.t/m
v = 6 × 10/20
v = 3 m/s
Learn more about impulse and momentum: https://brainly.com/question/904448
An airplane accelerates from a speed of 88m/s to a speed of 132 m/s during a 15 second time interval. How far did the airplane travel during the time interval?
Answer:
[tex]1650\:\mathrm{m}[/tex]
Explanation:
We can use the following kinematics equations to solve this problem:
[tex]v_f=v_i+at,\\{v_f}^2={v_i}^2+2a\Delta x[/tex].
Using the first one to solve for acceleration:
[tex]132=88+a(15),\\15a=44,\\a=\frac{44}{15}=2.9\bar{3}\:\mathrm{m/s^2}[/tex].
Now we can use the second equation to solve for the distance travelled by the airplane:
[tex]132^2=88^2+2\cdot2.9\bar{3}\cdot \Delta x,\\\Delta x= \frac{9680}{2\cdot2.9\bar{3}},\\\Delta x =\fbox{$ 1650\:\mathrm{m}$}[/tex](three significant figures).
What is happening to the average kinetic energy of the molecules in a pot of water when it is heated on a stove? Explain your answer.
Answer:
Explanation:
The average kinetic energy of molecules in a pot increases when it is heated on a stove . The heat energy is spent to decrease the intermolecular attractive force . The result is increase in kinetic energy due to increase in the velocity of molecules
formula for kinetic energy of one mole of a monoatomic gas
= 3/2 RT
when temperature increases , kinetic energy increases .
A rectangle box was measured with a length of 4cm, width 2cm, and height 2cm. What is the volume of the box?
Answer:
volume is 64
Explanation:
2×2×4×4
=64
Answer:
[tex]V = 16\ cm^3[/tex]
Explanation:
The Volume of a Rectangular Prism
A rectangular prism is also called a rectangular box and has three dimensions all perpendicular to each other.
Given a rectangular prism of length L, width W, and height H, the volume is calculated as:
V = WLH
We are given the dimensions of a rectangular box: L= 4 cm, W = 2 cm, H = 2 cm. Computing the volume:
V = 2 cm * 4 cm * 2 cm
[tex]\mathbf{V = 16\ cm^3}[/tex]
A 2 kg marble moving at 4 mi./s collides into a 1 kg marble at rest. After collision, the 2 kg marble speed decreased to 2 mi./s. Calculate the velocity and speed of the 1 kg marble immediately after colliding.
Please show work and please help me as fast as possible because this is time
Please help as soon as possible please
Please I’m begging
Answer:
[tex]2\sqrt{6}[/tex] [tex]\frac{mi}{s}[/tex]
Explanation:
Assuming there is no waste of energy:
[tex]K_{1} = K_{2}\\\frac{1}{2}m_{1}v_{1_{1}}^{2} + \frac{1}{2}m_{2}v_{2_{1}}^2 = \frac{1}{2}m_{1}v_{1_{2}}^{2} + \frac{1}{2}m_{2}v_{2_{2}}^2\\\\=> m_{1}v_{1_{1}}^{2} + m_{2}v_{2_{1}}^2 = m_{1}v_{1_{2}}^{2} + m_{2}v_{2_{2}}^2\\\\m_{1} = 2 kg, m_{2} = 1 kg, v_{1_{1}} = 4 \frac{mi}{s} , v_{2_{1}} = 0\\=> 32 = 8 + v_{2_{2}}^{2} => v_{2_{2}} = 2\sqrt{6} \frac{mi}{s}[/tex]
A force of 49 Newtons is applied to a rock, which causes it to be lifted 2 meters in 5 seconds. How much power is exerted during this time?
Select one:
9.8 W
19.6 W
56.4 W
98 W
Answer: 19.6 watts
=================================================
Explanation:
power = (change in work)/(change in time)
p = w/t
work = force*displacement
w = f*d
So we can say:
p = (f*d)/t
We know the following
f = 49 = applied forced = 2 = displacementt = 5 = change in timeLeading to...
p = (f*d)/t
p = (49*2)/5
p = 98/5
p = 19.6 watts
Side note: 1 watt is equal to 1 joule per second
At the top of a roller coaster 20 m above the ground the 5 kg car is moving at 2 m/s how fast is it moving at the bottoms of the hill
Answer:
VB = 19.9 [m/s]
Explanation:
In order to solve these problems, we must use the principle of energy conservation. Which tells us that the energy between two points after an instant of time must be equal. This is we have two points A & B, in point A is the highest point while Point B is the lowest
Now we need to identify the types of energy at each point.
For point A
At this point we have two energies, the kinetic energy since the roller coaster moves at a speed of 2 [m/s], in the same way there is potential energy since the roller coaster is 20 [m] above ground level.
For point B
At Point B we only have kinetic energy, since it is located at zero meters with respect to the ground. In this way we can determine the velocity at this point.
And the energy is expressed by means of the following expression:
[tex]E_{A}=E_{B}\\\frac{1}{2} *m*v_{A}^{2} +m*g*h_{A}=\frac{1}{2} *m*v_{B}^{2}[/tex]
where:
m = mass = 5 [kg]
VA = velocity of the roller coaster in point A = 2[m/s]
hA = elevation of the roller coaster = 20 [m]
vB = velocity of the roller coaster in point B [m/s]
Now replacing:
[tex]\frac{1}{2}*5*(2)^{2} +(5*9.81*20)=\frac{1}{2}*(5)*v_{B}^{2}\\991=2.5*v_{B}^{2}\\v_{B}x^{2} =991/2.5\\v_{B}=\sqrt{396.4} \\v_{B}=19.9[m/s][/tex]
Define the terms resultant and equilibriant of
two forces acting at a point. Explain the
difference between the two terms.
Find the magnitude and direction of (a) the
resultant (b) the equilibriant of two forces, 10
N acting in the direction N 30 East and 15 N
acting in the easterly direction, if both forces
act at a point.
Answer:
1) Resultant and Equilibrant explained below
2) Resultant = 24.18 N in a direction of 11.93° NE
3)Equilibrant = 24.18 N in a direction of 11.93° SW
Explanation:
1) Resultant force: If two or more forces are acting at a certain point, their resultant force would be defined as the force that when applied at that same point, it will have the exact same effect like the two independent forces acting together.
Equilibrant of 2 forces: This is defined as the force exactly equal and has an opposite direction to the resultant
2)a.) we are told that 10 N acts in the direction N 30 East and 15 N acts in the easterly direction, if both forces
act at a point. Thus, coordinates are;
(10cos30,10sin30) and (15,0)
Therefore, resultant coordinate is;
R→ = (10cos30, 10sin30) + (15, 0)
R→ = (15 + 10cos30, 0 + 10 sin 30)
This gives;
R→ = (23.66, 5)
Thus the resultant is;
R = √(23.66² + 5²)
R = √584.7956
R = 24.18 N
b) direction is gotten from;
tan θ = 5/23.66
θ = tan^(-1) 5/23.66
θ = 11.93° NE
c) Equilibrant is equal force but opposite direction. Thus, Equilibrant = 24.18 N in a direction of 11.93° SW
I’m NC the wind is blowing from the north. If the wind changes direction and begins to blow from the south, what will most likely result.
NC means North Carolina.
Answer:
The temperatures will increase.
Explanation:
What will happen is that the temperature will increase. This is because, in wind direction and weather forecasting, a wind that shifts from the south means that warmer air/temperatures are approaching whereas a wind shift from the north implies that cooler air/temperatures are approaching.
Explain the difference between transverse and longitudinal waves.
A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil up and down. Energy will begin to be transported through the slinky from left to right. As the energy is transported from left to right, the individual coils of the medium will be displaced upwards and downwards. In this case, the particles of the medium move perpendicular to the direction that the pulse moves. This type of wave is a transverse wave. Transverse waves are always characterized by particle motion being perpendicular to wave motion.
A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil left and right. Energy will begin to be transported through the slinky from left to right. As the energy is transported from left to right, the individual coils of the medium will be displaced leftwards and rightwards. In this case, the particles of the medium move parallel to the direction that the pulse moves. This type of wave is a longitudinal wave. Longitudinal waves are always characterized by particle motion being parallel to wave motion.