Answer:
The carrying capacity of this population would be 125 we know this because we see that this number occur multiple times and seems to be the tipping point after which the number of the population always go down
Answer:
The carrying capacity of this population would be 125 we know this because we see that this number occur multiple times and seems to be the tipping point after which the number of the population always go down
Explanation:
why do the properties of a material determine the use of the material?
Answer:
Matter is made up of particles whose properties determine the observable characteristics of matter and its reactivity.
Explanation:
13.Which shows the order of increasing ionization energy?
a.Si, Al, Mg, Na
b.Ga, Ge, As, Se
c.Be, Mg, Ca, Sr
d.F, Cl, Br, I
Which situation describes a reaction with a percentage yield of 100%?
Select one:
a. none of them
b. No competing reactions occur and the limiting reagent is fully consumed.
c. The amounts of reactants initially present are stoichiometric.
d. The product is more than the limiting reagent has the potential to produce.
Answer:
Explanation:
D
whats the balance to Sr + O, SrO
Answer:
SrO = Sr + O - Chemical Equation Balancer.
Explanation:
What happens in a
neutralisation reaction.
Answer:
A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water. Salts are also formed in this reaction.
Explanation:
Plzzzzz helpppp meee
Answer:
2 and 5
Explanation:
If you have 15g of sodium carbonate, what
mass of sodium is present in that sample?
Answer: 6.75 g
Explanation:
What is mass in grams of 2.30 moles of Aluminum?
62.1 g Al
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
2.30 mol Al
Step 2: Identify Conversions
[PT] Molar Mass of Al - 26.98 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 2.30 \ mol \ Al(\frac{26.98 \ g \ Al}{1 \ mol \ Al})[/tex]Multiply/Divide: [tex]\displaystyle 62.054 \ g \ Al[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
62.054 g Al ≈ 62.1 g Al
Could someone please help me? You can ignore number 3
For Number 2)
THE ELEMENTS TEND TO FORM COMPOUNDS BECAUSE AOMS ARE UNSTABLE AND CAN SHARE ELECTRONS IN THIER OUTER ENERGY LEVELS .
AS WE KNOW, ATOMS OF AN ELEMENT BECOMES MORE STABLE BY LOSING , GAINING AND SHARING ELECTRONS.
Elements react with each other to complete their octet or duplet so as to become stavle in nature. For e.g. Carbon reacts with oxygen to form carbon dioxide. Carbon reacts with four molecules of hydrogen to form methane - CH4.
Use the half-reaction method to balance the following equations :
MnO4- + Br- = MnO2 + BrO3- (Acidic Solution )
Br- + 2MnO4- + 2H+ → BrO3- + 2MnO2 + H2O
Further explanationGiven
MnO4- + Br- = MnO2 + BrO3-
Required
The half-reaction
Solution
In acidic conditions :
1. Add the coefficient
2. Equalization O atoms (add H₂O) on the O-deficient side.
3. Equalization H atoms (add H⁺ ) on the H -deficient side. .
4. Equalization of charge (add electrons (e) )
5. Equalizing the number of electrons and then adding the two half -reactions together
Oxidation : Br- → BrO3-
Reduction : MnO4- → MnO2
Equalization O atomsBr- + 3H2O → BrO3-
MnO4- → MnO2 + 2H2O
Equalization H atomsBr- + 3H2O → BrO3- + 6H+
MnO4- + 4H+ → MnO2 + 2H2O
Equalization of chargeBr- + 3H2O → BrO3- + 6H+ + 6e- x1
MnO4- + 4H+ + 3e- → MnO2 + 2H2O x2
Equalizing the number of electrons and then adding the two half -reactions togetherBr- + 3H2O → BrO3- + 6H+ + 6e-
2MnO4- + 8H+ + 6e- → 2MnO2 + 4H2O
Br- + 2MnO4- + 3H2O + 8H+ + 6e- → BrO3- + 2MnO2 + 6H+ + 4H2O + 6e-
Br- + 2MnO4- + 2H+ → BrO3- + 2MnO2 + H2O
New rocks are heavier than old rocks.
what sre the group 17 elements are known as
Answer:
Halogen
Explanation:
What happens to particles when their energy levels decrease
ASAP
Answer:
The kinetic theory of matter can be used to explain how solids, liquids and gases are interchangeable as a result of increase or decrease in heat energy. If it is cooled the motion of the particles decreases as they lose energy.
Explanation:
How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
The given question is incomplete. The complete question is:
How much heat is produced when 24.8 g of [tex]CH_4[/tex] is burned in excess oxygen gas
Given: [tex]CH _4 +2O_2\rightarrow CO_2+2H_2O[/tex] ΔH= −802 kJ.
Answer: 1243.1 kJ
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion of 1 mole of methane = 802 kJ kJ/mol
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of [tex]CH_4[/tex] weighs = 16 g
Thus we can say:
16 g of [tex]CH_4[/tex] on combustion releases heat = 802 kJ
Thus 24.8 g of [tex]CH_4[/tex] on combustion releases =[tex]\frac{802}{16}\times 24.8=1243.1kJ[/tex]
Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ
Heat from the sun moves through space by the process of
es
A)
circulation.
B)
conduction
C)
convection.
D)
radiation
help for brainlist and extra points!!
Answer:
Explanation:
c.
what is the name of the compoud H2Co2
In which way are plant and animals cells similar
Answer:
Both animal and plant cells are eukaryotic cells and have several similarities. The similarities include common organelles like cell membrane, cell nucleus, mitochondria, endoplasmic reticulum, ribosomes and golgi apparatus
Explanation:
hey both contain membrane-bound organelles such as the nucleus, mitochondria, endoplasmic reticulum, golgi apparatus, lysosomes, and peroxisomes.
Answer:
Plant and animal cells are very similar, because they are both, Eukaryotic Cells. They both contain membrane-bound organelles such as the: Nucleus, Mitochondria, Endoplasmic Reticulum, Golgi Apparatus, Lysosomes, and Peroxisomes.
Hope this helps.
x
What are the three energy's .
Answer:
Energy and how it can change forms. Kinetic, potential, and chemical energy.
How is Muscular Strength measured and why is this important to know?
Answer:
Your ability to move and lift objects refers to muscular strength. It's measured by how much force you can exert for a short period of time and how much weight you can lift.
Explanation:
The equation below represents chemical reaction that occurs in living cells. C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy How many atoms are represented in the reactants of this equation?
Answer:
36
Explanation:
There are 6 Carbon atoms, 12 Hydrogen atoms, and 18 Oxygen atoms.
What is the amount of diamine silver that can be formed when 10.00 g AgCl is mixed with 1.00 L of 0.100 M NH3?
The amount of diamine silver chloride = 8.87 g
Further explanationGiven
10 g AgCl
1.00 L of 0.100 M NH3
Required
the amount of diamine silver
Reaction
AgCl + 2 NH₃ → [Ag(NH₃)₂]Cl
mol AgCl :
= mass : MW
= 10 g : 143,32 g/mol
= 0.0698
mol NH₃ :
= M x V
= 0.1 x 1
= 0.1
NH₃ as a limiting reactant
mol [Ag(NH₃)₂]Cl based on NH₃ :
= 1/2 x mol NH₃
= 1/2 x 0.1
= 0.05
Mass diamine silver :
= 0.05 x 177.3822 g/mol
= 8.87 g
Which is the balanced chemical equation showing hydrogen peroxide (H2O2) decomposing into hydrogen (H2) and oxygen (O2)? Multiple Choice H2O2 → H2 + O2 H2 + O2 → H2O2 2 H2 + O2 → 2 H2O2 2 H2O2 → 2 H2 + O2 PrevQuestion 13 of 14 Total13 of 14Visit question mapNext
Answer: [tex]H_2O_2\rightarrow H_2+O_2[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical equation for showing hydrogen peroxide decomposing into hydrogen and oxygen is:
[tex]H_2O_2\rightarrow H_2+O_2[/tex]
write and balance the cellular respiration equation of glucose compared with the photosynthesis reaction in the terms of reactants products energy flow in the significance of each.
Answer:
Explanation:
.
2
Convert -27°C to Kelvin.
Answer:
-27 C converted to Kelvin is 246.15 Kelvin.
Explanation:
Hope this helps
Answer:
246.15K
Explanation:
Formula: (-27°)C + 273.15 = 246.15K
a sample of nitrogen gas occupies 1.55l at 27.0c and 1.00 atm what will the volume be at -100.0c and the same pressure
V₂=0.894 L
Further explanationGiven
V₁=1.55 L
T₁=27 + 273 = 300 K
P₁=1 atm
T₂=-100+273 = 173 K
Required
The final volume(V₂)
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
Input the value :
V₂=V₁T₂/T₁
V₂=1.55 x 173/300
V₂=0.894 L
A cylinder of an ideal gas contains 1.2 moles of gas and occupies a volume of 5.0L. If 0.5 moles of a second gas are added to the cylinder, and the cylinder is allowed to expand until it reaches the same temperature and pressure as before, what is the final volume of gas, in liters, that occupies the cylinder?
Answer:
7.08 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.2 + 0.5 = 1.7 moles
Final volume (V₂) =?
From ideal gas equation,
PV = nRT
Divide both by n
PV / n = RT
Divide both side by P
V / n = RT/P
RT/P => constant
Therefore,
V₁ / n₁ = V₂ / n₂
With the above formula i.e
V₁/n₁ = V₂/n₂
We can obtain the final volume of the gas as follow:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.7 moles
Final volume (V₂) =?
V₁/n₁ = V₂/n₂
5 / 1.2 = V₂ / 1.7
Cross multiply
5 × 1.7 = 1.2 × V₂
8.5 = 1.2 × V₂
Divide both side by 1.2
V₂ = 8.5 / 1.2
V₂ = 7.08 L
Therefore, the final volume of the gas is 7.08 L
Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =3 to =1.
Answer:
[tex]1.936\times 10^{-18}\ \text{J}[/tex]
Explanation:
[tex]R_h[/tex] = Rydberg constant = [tex]2.178\times 10^{-18}\ \text{J}[/tex]
[tex]n_i[/tex] = Initial shell = 3
[tex]n_f[/tex] = Final shell = 1
We have the relation
[tex]\Delta E=R_h(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})\\\Rightarrow \Delta E=2.178\times 10^{-18}(\dfrac{1}{1^2}-\dfrac{1}{3^2})\\\Rightarrow \Delta E=1.936\times 10^{-18}\ \text{J}[/tex]
The energy of the photon emitted here is [tex]1.936\times 10^{-18}\ \text{J}[/tex].
How many grams are in 4.3 x 10 -4 moles of calcium phosphate?
Explanation:
Ca3(PO4)2 1 mole has 310.2 g
Ca3(PO4)2 4.3 × 10^-4 moles has 4.3 × 10^-4 × 310.2
= 1,333.86 × 10^-4
= 1.334 × 10^-1
OR 0.1334 g
How does the angle of the incoming light affect the intensity of the light that is refracted?
Answer:
A reflected ray always comes off the surface of a material at an angle equal to the angle at which the incoming ray hit the surface. In physics, you'll hear this called the law of reflection. You've probably heard this law stated as "the angle of incidence equals the angle of reflection
Explanation: