Answer:
3 pounds 13 ounces
Explanation:
Math
Answer:
3.75
Explanation:
A cylinder of an ideal gas contains 1.2 moles of gas and occupies a volume of 5.0L. If 0.5 moles of a second gas are added to the cylinder, and the cylinder is allowed to expand until it reaches the same temperature and pressure as before, what is the final volume of gas, in liters, that occupies the cylinder?
Answer:
7.08 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.2 + 0.5 = 1.7 moles
Final volume (V₂) =?
From ideal gas equation,
PV = nRT
Divide both by n
PV / n = RT
Divide both side by P
V / n = RT/P
RT/P => constant
Therefore,
V₁ / n₁ = V₂ / n₂
With the above formula i.e
V₁/n₁ = V₂/n₂
We can obtain the final volume of the gas as follow:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.7 moles
Final volume (V₂) =?
V₁/n₁ = V₂/n₂
5 / 1.2 = V₂ / 1.7
Cross multiply
5 × 1.7 = 1.2 × V₂
8.5 = 1.2 × V₂
Divide both side by 1.2
V₂ = 8.5 / 1.2
V₂ = 7.08 L
Therefore, the final volume of the gas is 7.08 L
New rocks are heavier than old rocks.
answers this...i gave brainlest!!
Answer:
I hope I can help
Explanation:
I hope I can help you
2) Which liberates the most energy?
A) F(g) + e ➡️ F-(g)
B) N(g) +e- ➡️ N-(g)
C) O(g) +e ➡️ O-(g)
D) C(g) +e ➡️ C-(g)
Answer: [tex]F(g)+e^-\rightarrow F^-(g)[/tex]
Explanation:
Electron gain enthalpy is defined as energy released on addition of electron to an isolated gaseous atom.
The amount of energy released will be maximum when the tendency to attract electrons is maximum. As flourine has atomic number of 9 and has electronic configuration of 2,7. It can readily gain 1 electron to attain stable noble gas configuration and hence liberates maximum energy.
[tex]F(g)+e^-\rightarrow F^-(g)[/tex]
Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =3 to =1.
Answer:
[tex]1.936\times 10^{-18}\ \text{J}[/tex]
Explanation:
[tex]R_h[/tex] = Rydberg constant = [tex]2.178\times 10^{-18}\ \text{J}[/tex]
[tex]n_i[/tex] = Initial shell = 3
[tex]n_f[/tex] = Final shell = 1
We have the relation
[tex]\Delta E=R_h(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})\\\Rightarrow \Delta E=2.178\times 10^{-18}(\dfrac{1}{1^2}-\dfrac{1}{3^2})\\\Rightarrow \Delta E=1.936\times 10^{-18}\ \text{J}[/tex]
The energy of the photon emitted here is [tex]1.936\times 10^{-18}\ \text{J}[/tex].
element A it's valance number is 3 and element B it's valance number is 6 make it compound
Answer:
A2B
Explanation:
A = 3
B = 6
exchange valencies
A6B3
A2B
1 point
If the element Lithium (Li) were to bond with the element Sulfur (s), what
type of bond can you predict will be formed and why?*
A. Covalent-Li and S are two nonmetals
B. Covalent-Li is a metal and S is a nonmetal
C. Ionic-Li and S are two nonmetals
D. Ionic-Li is a metal and S is a nonmetal
Answer:
C. Ionic-Li and S are two nonmetals
How many grams are there in 3.4 x 10^24 atoms of He?
Group of answer choices
2.07
5.7 g
0.57 g
20.7
Given :
Number of He atoms, [tex]n = 3.4\times 10^{24}[/tex] atoms.
To Find :
How many grams are their in given number of He atoms.
Solution :
We know, molecular mass of He is 4 g. It means that their are [tex]6.022 \times 10^{23}[/tex] atoms in 4 g of He.
Let, number of gram He in [tex]3.4\times 10^{24}[/tex] atoms is x , so :
[tex]x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x = $$22.58\ g[/tex]
Therefore, grams of He atoms is 22.58 g .
A __________________ chemical equation shows that the same number of atoms in the reactants are also in the product.
balanced
rearranged
transferred
beautiful
Suppose you have a mixture of iron filings, sand, and sugar and you want to separate the three. Fill in the materials you expect to see at each step as you perform the actions shown to separate them. The materials you may expect to see are: iron filings, sand, sugar, and sugar water.
Answer:
Explanation:
mixture of iron filings, sand, and sugar
First Step - Iron Fillings
Use a magnet to separate the iron fillings from the mixture. Due to magnetic properties of the iron fillings, the magnets would attract the iron fillings and separate it from the mixture.
Second step - Sand
Place the sand and sugar mixture in water. The sugar would dissolve in water and the sand easily separated by filtration.
Third step - Sugar and Sugar water
Boil the sugar water to remove the water and place in the refrigerator for crystallization of the sugar.
I gave brainlest:: answer this .....
What is the amount of diamine silver that can be formed when 10.00 g AgCl is mixed with 1.00 L of 0.100 M NH3?
The amount of diamine silver chloride = 8.87 g
Further explanationGiven
10 g AgCl
1.00 L of 0.100 M NH3
Required
the amount of diamine silver
Reaction
AgCl + 2 NH₃ → [Ag(NH₃)₂]Cl
mol AgCl :
= mass : MW
= 10 g : 143,32 g/mol
= 0.0698
mol NH₃ :
= M x V
= 0.1 x 1
= 0.1
NH₃ as a limiting reactant
mol [Ag(NH₃)₂]Cl based on NH₃ :
= 1/2 x mol NH₃
= 1/2 x 0.1
= 0.05
Mass diamine silver :
= 0.05 x 177.3822 g/mol
= 8.87 g
write the balanced equation for the formation of carbon dioxide.
13.Which shows the order of increasing ionization energy?
a.Si, Al, Mg, Na
b.Ga, Ge, As, Se
c.Be, Mg, Ca, Sr
d.F, Cl, Br, I
why is productivity greatest near the ocean's surface?
Answer:
Sunlight penetrates the top layers of the ocean, so photosynthesis occurs there. ... Upwelling brings nutrients to the surface.
Calculate the number of moles in 2.67 g of carbon trihydride
Answer:0.178 moles
Explanation: carbon trihydride seems to be an unusual name for the methyl group CH3–
ionic wt 15
moles = 2.67/15 = 0.178
5. If all the particles in a material are made up of
several smaller particles, and every larger particle
is identical, is the material a pure substance or
not? Explain your reasoning.
Answer:
No. Because a pure substance, no matter if an element, compound, it can only contain one kind of particle .
Explanation:
1.a)concentrated sulphuric acid reacts with ethanol to produce ethene
(i) state the conditions for the reaction
.......................................................................
write the equation of the leads to formation of ethene In (a) (i) above.
.....................................................................................
state the property of sulphuric acid shown in reaction (a)(ii)
...................................................................................
Answer: a) Temperature of [tex]170^0C[/tex]
b) [tex]C_2H_5OH\stackrel{conc H_2SO_4, 170^0C}\rightarrow C_2H_4+H_2O[/tex]
c) dehydrating agent
Explanation:
Ethanol is heated with an excess of concentrated sulfuric acid at a temperature of 170°C to produce ethene.
The balanced chemical reaction is:
[tex]C_2H_5OH\stackrel{conc H_2SO_4, 170^0C}\rightarrow C_2H_4+H_2O[/tex]
Here concentrated sulfuric acid removes a water molecule from ethanol and thus acts as a dehydrating agent.
"Show a general equation for polymerisation"
Answer:
Polymerisation is the chemical process of monomers joining together to form polymers, often it takes many thousands of monomers to make a single polymer.
Explanation:
Heat from the sun moves through space by the process of
es
A)
circulation.
B)
conduction
C)
convection.
D)
radiation
how many moles are in 6.31x10^24 C atoms
Answer:
Explanation:
1 mol of any chemical is 6.02 * 10^23
x mol of any chemical is 6.31 * 10^24
You should look at this before you put it in your calculator. You should think roughly 10.
Now you can set it up as a proportion
1/x = 6.02 * 10^23/6.31 * 10^24 Cross multiply
6.02 * 10^23 x = 1 * 6.31 * 10^24 Divide by 6.02 * 10^23
x = 6.31 * 10^24 / 6.02 * 10^23
x = 10.48 mols.
whats the balance to Sr + O, SrO
Answer:
SrO = Sr + O - Chemical Equation Balancer.
Explanation:
Calculate the mass (in g) of solute needed to prepare a solution with the given concentration and volume.
Sea water has a concentration of approximately 0.60 M sodium chloride. How much
sodium chloride is dissolved in 1.00 L of solution?
Coke has a concentration of 0.342 M. What mass of sugar (in g) is dissolved in a 2-L
bottle of coke?
What volume of concentrated nitric acid (15.8 M) is needed to prepare 4.0 L of a 2.0 M solution?
What volume of 9.0 M copper (II) sulfate stock solution is needed to prepare 3.0 L of a 5.0 M
solution?
Answer:
1. 35g NaCl.
2. 234g sugar.
3. 0.506L of concentrated nitric acid are needed.
4. 1.67L of 9.0M copper (II) sulfate are needed
Explanation:
Molarity is defined as the ratio between moles of solute and the volume of the solution.
1. 1.00L * (0.60mol / L) = 0.60 moles NaCl are dissolved
To convert moles to mass we must use its molar mass:
0.60mol NaCl * (58.44g/mol) =
35g NaCl
2. 2L * (0.342mol / L) = 0.684 moles Sugar = moles sucrose
0.684 mol * (342.30g / mol) = 234g sugar
3. 4L of a 2.0M are:
4L * (2.0mol/L) = 8moles
8mol * (1L / 15.8mol) = 0.506L of concentrated nitric acid are needed
4. 3.0L * (5.0 mol / L) = 15.0 moles copper (II) sulfate.
15.0mol * (1L / 9.0mol) = 1.67L of 9.0M copper (II) sulfate are needed
An increase in the volume of a substance because of an increase in temperature is called
Answer:
Its called contraction.
Explanation:
How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
The given question is incomplete. The complete question is:
How much heat is produced when 24.8 g of [tex]CH_4[/tex] is burned in excess oxygen gas
Given: [tex]CH _4 +2O_2\rightarrow CO_2+2H_2O[/tex] ΔH= −802 kJ.
Answer: 1243.1 kJ
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion of 1 mole of methane = 802 kJ kJ/mol
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of [tex]CH_4[/tex] weighs = 16 g
Thus we can say:
16 g of [tex]CH_4[/tex] on combustion releases heat = 802 kJ
Thus 24.8 g of [tex]CH_4[/tex] on combustion releases =[tex]\frac{802}{16}\times 24.8=1243.1kJ[/tex]
Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ
An atom absorbs radiation. Select the possible changes this could have on the atom:
*it can change the atomic mass
*it can cause the atom to lose an electron
*it can cause the atom to become and ion
*it cause the atom to change element
Answer:
*it can cause the atom to become and ion
Identify the products in the reaction HCI + NaOH → NaCl + H20.
A. HCI, NaOH, NaCl, and H2O
B. HCl and NaOH
C. NaCl and H20
D. NaOH and H20
The products in the reaction HCI + NaOH → NaCl + H20, are C. NaCl and H20.
How are these the products ?The reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is a neutralization reaction, which means that it produces a salt and water. In this case, the salt is sodium chloride (NaCl) and the water is H2O.
The other options are not correct because they do not include all of the products of the reaction. Option (A) includes HCl and NaOH, but it does not include H2O. Option (B) only includes HCl and NaOH. Option (D) only includes NaOH and H2O.
In conclusion, option C is correct.
Find out more on products at https://brainly.com/question/20322602
#SPJ6
what is 20+9-10+67=?
Answer:
86
Explanation:
20 plus 9 equals 29 minus 10 equals 19 plus 67 equals 86
Answer:
86
Explanation:
20+9=29
29-10=19
19+67=86
2
Convert -27°C to Kelvin.
Answer:
-27 C converted to Kelvin is 246.15 Kelvin.
Explanation:
Hope this helps
Answer:
246.15K
Explanation:
Formula: (-27°)C + 273.15 = 246.15K
with 24.1 moles of P4O10 how many moles of H3PO4 could be made