Answer:
The correct answer to the following question will be Option d (181 degrees of freedom).
Step-by-step explanation:
The given values are:
Regression model,
n = 200
Observations,
p = 18
Now,
⇒ [tex]n-p-1[/tex]
On putting the estimated values, we get
⇒ [tex]200-18-1[/tex]
⇒ [tex]181[/tex]
So that the correct choice will be "181 degrees of freedom".
Write an equation for a polynomial function that has the given roots
-2. 3i , and 5
Answer:
x^4 - 3x^3 - x^2 - 27x - 90 = 0.
Step-by-step explanation:
If 3i is one root then another is -3i.
In factor form we have:
(x + 2)(x - 5)(x - 3i)(x + 3i) = 0
(x^2 - 3x - 10)(x^2 -9i^2) = 0
(x^2 - 3x - 10)(x^2 + 9) = 0
x^4 + 9x^2 - 3x^3 - 27x - 10x^2 - 90 = 0
x^4 - 3x^3 - x^2 - 27x - 90 = 0.
What are the solutions to the system of equations graphed below? Select all
that apply
A. (-6,8)
B. (0,2)
C. (2,0)
D. (-5,0)
E. (0,-10)
Answer:
c and d
Step-by-step explanation:
the x intercepts are the solutions
Answer:
(0,2) and (-5,0)
Step-by-step explanation:
the point where the two graph lines meet would be the answer.
What is the quoteint of 2/3 in 2/9
Can advise on the solution?
Answer:
340
Step-by-step explanation:
If x is the amount of pages in the book we can write:
1/4x + 5 + 3/5(x - (1/4x + 5)) + 10 + 12 + 24 = x
1/4x + 51 + 3/5(3/4x - 5) = x
1/4x + 51 + 9/20x - 3 = x
7/10x + 48 = x
3/10x = 48
x = 160
Please answer this correctly
Answer:
First box is 4This is because 2 is the stem and the leaves are 1, 2, 4, and 5
so the numbers are 21, 22, 24, and, 25
Second box is 3This is because 2 is the stem for the leaves 6 and 7
3 is the stem for the leaf 0
So the numbers are 26, 27, and 30
Hope this helped
Answer:
As you know about the stem and leaf plot
1 |7 7 7 8 => 17, 17, 17, 18
2|1 2 4 5 6 7 => 21, 22, 24, 25, 26, 27
3|0 2 5 5 6 7 7 8 9 => 30, 32, 35, 35, 36, 37, 37, 38, 39
4|1 2 => 41, 42
Now we count to complete the table:
16-20 | 4 {17, 17, 17, 18}
21-25 | 4 {21, 22, 24, 25}
26-30 | 3 {26, 27, 30}
31-35 | 3 {32, 35, 35}
36-40 | 5 {36, 37, 37, 38, 39}
41-45 | 2 {41, 42}
Hope this helps!
A television network, Network A, is scheduling its fall lineup of shows. For the Tuesday night 8 p.m. slot, Network A has selected its top show. If its rival network, Network B, schedules its top show during the same time slot, Network A estimates that it will get 1.1 million viewers. However, if Network B schedules a different show during that time slot, Network A estimates that it will get 1.9 million viewers. Network A believes that the probability that Network B will air their top show is 0.7 and the probability that Network B will air another show is 0.3. Determine the expected number of viewers for Network A's top show.
Answer:
1,280,000 (1.28 million.)
Step-by-step explanation:
If Network B schedules its top show (with a probability of 0.7), Network A will get 1.1 million viewers.
If Network B schedules a different show during that time slot, (with a probability of 0.3), Network A will get 1.9 million viewers.
Therefore, the probability distribution table of number of viewers of Network A is:
[tex]\left|\begin{array}{c|c|c}$Number of Viewers, x&1.1$ million&$1.7 million\\P(x)&0.7&0.3\end{array}\right|[/tex]
Therefore, the expected number of viewers for Network A's top show
= (1100000 X 0.7) + (1700000 X 0.3)
=1,280,000
The expected number of viewers for Network A's top show is 1.28 million.
Once a fire is reported to a fire insurance company, the company makes an initial estimate, X, of the amount it will pay to the claimant for the fire loss. When the claim is finally settled, the company pays an amount, Y, to the claimant. The comapny has determined that X and Y have the joint density functionf(x,y) = Given that the initial claim estiamted by the comapny is 2, determine the probability that the final settlement amount is between 1 and 3.
Answer:
The probability that the final settlement amount is between 1 and 3 given that the initial claim is 2 = (2/9) = 0.2222
Step-by-step explanation:
The complete question is presented in the attached image to this solution
The joint probability distribution is given as
f(x, y) = {2/[x²(x - 1)} × y^-[(2x-1)/(x-1)] for x>1 And y>1
Given that the initial claim estiamted by the comapny is 2, determine the probability that the final settlement amount is between 1 and 3.
That is, x = 2, and y ranges from 1 to 3
Inserting x = 2 into the expression, we obtain
f(y) = (1/2) × y⁻³ = (y⁻³/2)
The required probability would then be
P(1 < y ≤ 3) = ∫³₁ f(y) dy
= ∫³₁ (y⁻³/2) dy
= [y⁻²/-4]³₁
= [3⁻²/-4] - [1⁻²/-4]
= (-1/36) - (-1/4)
= (1/4) - (1/36)
= (8/36)
= (2/9) = 0.2222
Hope this Helps!!!
Google I would like to purchase 10 bags of chicken wings the store is selling three bags for $51.00 what is the cost of 10 bags of chicken wings
a. 61.00
b. 71.00
c. 170.00
d. 130.00
Answer:
A 61.00
Step-by-step explanation:
51 Added to 10 Equals 61.00 which is the Cost of 10 Bags of chicken Wings. Your Welcome.
Three support beams for a bridge form a pair of complementary angles. Find the measure of each angle. If (3x+3) (5x-9)
Answer:
39 degrees and 51 degrees respectively.
Step-by-step explanation:
Two angles are complementary if their sum adds up to 90 degrees.
Given the pair of complementary angles formed by the three support beams:
3x+3 and 5x-9
Then:
3x+3+5x-9=90 degrees
Collect like terms
3x+5x=90+9-3
8x=96
Divide both sides by 8
x=12
Therefore, the measure of each angle is:
[tex](3x+3)=3(12)+3=36+3=39^\circ\\(5x-9)=5(12)-9=60-9=51^\circ[/tex]
The measure of each angle is 39 degrees and 51 degrees respectively.
Answer:
39 and 51 degrees
Step-by-step explanation:
Jack knows the surface area of a cylinder and its radius. He wants to find the cylinder's helght. He needs to rewrite the formula A = 2#r(+h)
to find the cylinder's height (h) In terms of the cylinder's surface area (A) and its radius (7). Which is the correct formula?
Answer:
h= pi(r)2/A or h= 3.14 times 7 times 2 divided by A
Step-by-step explanation:
u need to do the opposite of multiplication which is division to find the height
hope this helps
correct me if this is wrong
plsssssssssssssssss help
Answer:
60
Step-by-step explanation:
x=60 .
The triangle is equilateral and x=60 cause the two lines are ||
a. x=60°
b. Alternate interior angles
Solution,
Given,
All sides of triangle are equal.
AB=BC=AC
<ABC=<ACB=<BAC=y
By angle sum property of triangle,
<ABC+<BCA+<CAB=180
or y+y+y=180
or 3y=180
or y=180/3
y=60
Now,
<ACB=<CAD
<CAD(x)=60( Alternate interior angles)
Hope this helps ..
Good luck on your assignment..
The sum of the ages of ahsan and his mother is 61 years.The difference in their ages is 29 years.By forming a pair of simultaneous linear equations,find (i)ahsan's present age (ii)the age of ahsan's mother when ahsan is 21 years old
Answer:
a. 16 years
b. 50 years
Step-by-step explanation:
Let us assume the age of Ahsan be X
And, the age of his mother be Y
It is mentioned in the question that the sum of the both ages to be 61 years and their difference is 29 years
So now the equation is as follows
X + Y = 61 .............................. (1)
-X + Y = 29 .............................. (2)
Now solve this
We get
2Y = 90
Y = 45 = Ahsan mother age age
Now put the value of Y in any of the above equation
So X would be
X = 61 - 45
= 16 i.e ahsan age
The mother age is
= 45 years + 5 years
= 50 years
The 5 years come from
= 21 years - 16 years
= 5 years
Suppose we want to study the weekly rate of alcohol drinking among USF undergraduate students. Which of the following would be the LEAST preferred method of randomly selecting participants?
A. Selecting a random sample of students from each residence hall
B. Selecting a random sample of students from the list of all undergraduate students from the university's registrar office
C. Selecting a random sample of students who have used the university health services in the past month
D. Selecting a random sample of students from each college
Answer:
Option D
Step-by-step explanation:
I think the least preferred method the researcher would like is to select a random sample of students from each college. This means the researcher would have to go to every college and randomly selects participants which is very exhausting. Thus, this would be the least prefer method over the others...
A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random sample of 36 bins, the sample mean amount was 48.99 pounds and the sample standard deviation was 3.7 pounds. Conduct the appropriate hypothesis test using a 0.01 level of significance.
a) What is the test statistic? Give your answer to four decimal places.
b) What is the P-value for the test? Give your answer to four decimal places.
Answer:
Step-by-step explanation:
Claim: if the mean amount of garbage per bin is different from 50.
Null hypothesis: u=50
Alternative hypothesis : u =/ 50
Using the z score formular for a one sample z test - z = (x - u ) / (sd/√n)
Where x = 48.99, u = 50 sd =3.7 and n = 36
z = 48.99 - 50 / (3.7/√36)
z = -1.01 / (3.7/6)
z = -1.01/0.6167
z = -1.6377
To find the p value at a 0.01 level of significant from the -1.6377 z score for a two tailed test the p value using the p value calculator is 0.1016. The result is not significant at 0.01 level of significant thus we will fail to reject the null and conclude that the mean amount of garbage per bin is 50.
If f(x) = x^2 is reflected over the x-axis and the shifted 4 units down, what is the equation of the new function, g(x)?
Answer:
g(x) = -x² - 4
Step-by-step explanation:
In this case, we are only changing a (reflection and vertical shrink/stretch) and k (vertical movement)
k = -4 because we are moving 4 units down
a = -1 because we are just reflecting over the x-axis
Which would be appropriate compatible numbers to use to estimate ( 19 4 5 ) ( 4 6 ) ? Using this compatible number, what is the estimated product?
Answer: first box is 20 (1/2)
Second box is 10
Answer:
Answer: first box is 20 (1/2)
Second box is 10
Step-by-step explanation:
A sample of 1300 computer chips revealed that 58% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 61% of the chips do not fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that do not fail is different from the stated percentage. Find the value of the test statistic. Round your answer to two decimal places.
Answer:
There is enough evidence to support the claim that that the actual percentage that do not fail is different from the stated percentage (61%).
Test statistic z = -2.19.
P-value = 0.03.
Step-by-step explanation:
This is a hypothesis test for a proportion.
The claim is that that the actual percentage that do not fail is different from the stated percentage (61%).
Then, the null and alternative hypothesis are:
[tex]H_0: \pi=0.61\\\\H_a:\pi\neq 0.61[/tex]
The significance level is assumed to be 0.05.
The sample has a size n=1300.
The sample proportion is p=0.58.
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.61*0.39}{1300}}\\\\\\ \sigma_p=\sqrt{0.000183}=0.014[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.58-0.61+0.5/1300}{0.014}=\dfrac{-0.03}{0.014}=-2.189[/tex]
This test is a two-tailed test, so the P-value for this test is calculated as:
[tex]\text{P-value}=2\cdot P(z<-2.189)=0.03[/tex]
As the P-value (0.03) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that that the actual percentage that do not fail is different from the stated percentage (61%).
Please answer this correctly
Answer:
# of plants # of gardens
10-14 2
15-19 2
20-24 5
25-29 3
30-34 3
35-39 5
40-44 4
Step-by-step explanation:
10-14: 10, 12 (2 numbers)
15-19: 18, 19 (2 numbers)
20-24: 20, 22, 23, 24, 24 (5 numbers)
25-29: 25, 27, 38 (3 numbers)
30-34: 31, 33, 33 (3 numbers)
35-39: 36, 36, 36, 37, 38 (5 numbers)
40-44: 40, 44, 44, 44 (4 numbers)
Answer:
10-14 ⇒ 2
15-19 ⇒ 2
20-24 ⇒ 5
25-29 ⇒ 3
30-34 ⇒ 3
35-39 ⇒ 5
40-44 ⇒ 4
The mail arrival time to a department has a uniform distribution over 5 to 45 minutes. What is the probability that the mail arrival time is more than 25 minutes on a given day? Answer: (Round to 2 decimal places.)
Answer:
0.5
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X higher than x is given by the following formula.
[tex]P(X > x) = \frac{b - x}{b-a}[/tex]
The mail arrival time to a department has a uniform distribution over 5 to 45 minutes.
This means that [tex]a = 5, b = 45[/tex].
What is the probability that the mail arrival time is more than 25 minutes on a given day?
[tex]P(X > 25) = \frac{45 - 25}{45 - 5} = 0.5[/tex]
So the probability that the mail arrival time is more than 25 minutes on a given day is 0.5.
I sell hot dogs at a football game. I can make a hot dog for $0.65 and sell it for $1.00. If i sell 50 hot dogs, what is my profit? show your work
Answer:
17.50
Step-by-step explanation:
The profit on one hotdog is
1 - .65 = .35
Multiply by the number of hotdogs sold
.35 * 50 =17.50
Please please help me on this one!
Answer:
3422 x232
Step-by-step explanation:
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 442 gram setting. It is believed that the machine is underfilling the bags. A 44 bag sample had a mean of 438 grams. Assume the population variance is known to be 576. A level of significance of 0.1 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.
Answer:
p value is 0.1343
Step-by-step explanation:
Null: u>= 442
Alternative: u < 442
Using the formula for z score:
(x - u)/sd/√n
Where x is 438, u = 442 sd can be determined from the variance = √variance =√576 = 24 and n = 44
z score = 438-442 / (24/√44)
z score = -4/(24/6.6332)
z = -4/3.6182
z =-1.1055
Now let's find the p value at 0.1 significance level using a z score of -1.1055, using a p value calculator, p value is 0.1343 which greatest than 0.1 meaning the day is not sufficient enough to conclude that the machine is underfilling the bags.
Jamie is investing $47,000 in an account paying 9.26% interest compounded continuously. What will Jamie's account balance be in 17 years?
9514 1404 393
Answer:
$226,863.29
Step-by-step explanation:
The amount is given by ...
A = Pe^(rt)
where principal P is invested at annual rate r for t years.
A = $47,000×e^(0.0926×17) ≈ $226,863.29
Answer:
the answer is $226,863.29
The valve was tested on 270 engines and the mean pressure was 6.6 lbs/square inch. Assume the variance is known to be 0.49. If the valve was designed to produce a mean pressure of 6.5 lbs/square inch, is there sufficient evidence at the 0.1 level that the valve does not perform to the specifications
Answer:
[tex]z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347[/tex]
The p value for this case would be given by"
[tex]p_v =2*P(z>2.347)=0.0189[/tex]
For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications
Step-by-step explanation:
Information given
[tex]\bar X=6.6[/tex] represent the sample mean
[tex]s=\sqrt{0.49}= 0.7[/tex] represent the population deviation
[tex]n=270[/tex] sample size
[tex]\mu_o =6.5[/tex] represent the value that we want to test
[tex]\alpha=0.1[/tex] represent the significance level
z would represent the statistic
[tex]p_v[/tex] represent the p value for the test
Hypothesis to verify
We want to verify if the true mean for this case is equal to 6.5 lbs/square inch or not , the system of hypothesis would be:
Null hypothesis:[tex]\mu= 6.5[/tex]
Alternative hypothesis:[tex]\mu \neq 6.5[/tex]
The statistic for this case is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
And replacing we got:
[tex]z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347[/tex]
The p value for this case would be given by"
[tex]p_v =2*P(z>2.347)=0.0189[/tex]
For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications
Fraud detection has become an indispensable tool for banks and credit card companies to combat fraudulent credit card transactions. A fraud detection firm has detected some form of fraudulent activities in 2%, and serious fraudulent activities in 0.75% of transactions. Assume that fraudulent transactions remain stable.
a. What is the probability that fewer than 2 out of 110 transactions are fraudulent?
b. What is the probability that fewer than 2 out of 105 transactions are seriously fraudulent?
Answer:
a) 35.17% probability that fewer than 2 out of 110 transactions are fraudulent
b) 81.35% probability that fewer than 2 out of 105 transactions are seriously fraudulent
Step-by-step explanation:
For each transaction, there are only two possible outcomes. Either they are fradulent(or seriously fraudulent), or they are not. Transactions are independent. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
a. What is the probability that fewer than 2 out of 110 transactions are fraudulent?
2% are fraudulent, so [tex]p = 0.02[/tex]
110 transactions, so [tex]n = 110[/tex]
This is
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{110,0}.(0.02)^{0}.(0.98)^{110} = 0.1084[/tex]
[tex]P(X = 1) = C_{110,1}.(0.02)^{1}.(0.98)^{109} = 0.2433[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.1084 + 0.2433 = 0.3517[/tex]
35.17% probability that fewer than 2 out of 110 transactions are fraudulent.
b. What is the probability that fewer than 2 out of 105 transactions are seriously fraudulent?
0.75% are seriously fraudulent, so [tex]p = 0.0075[/tex]
105 transactions, so [tex]n = 105[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
[tex]P(X = 0) = C_{105,0}.(0.0075)^{0}.(0.9925)^{105} = 0.4536[/tex]
[tex]P(X = 1) = C_{105,1}.(0.0075)^{1}.(0.9925)^{104} = 0.3599[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.4536 + 0.3599 = 0.8135[/tex]
81.35% probability that fewer than 2 out of 105 transactions are seriously fraudulent
State whether the decay is linear or exponential, and answer the associated question. The value of a car is decreasing by 9% per year. If the car is worth $11 comma 000 today, what will it be worth in two years? g
Answer:
ExponentialA(2)=$9109.10Step-by-step explanation:
Since the value of the car decreases by a common factor each year, the decay is exponential.
An exponential decay function is of the form
[tex]A(t)=A_0(1-r)^t$ where:\\Initial Value, A_0=\$11,000\\$Decay Factor, r=9%=0.09[/tex]
Therefore, the function modeling the car's decay is:
[tex]A(t)=11000(1-0.09)^t[/tex]
We want to determine the car's value in two years.
When t=2
[tex]A(2)=11000(1-0.09)^2\\A(2)=\$9109.10[/tex]
The value of the car in 2 years will be A(t)=$9109.10
Final value of the car after 2 years will be $9109.10
Value of the car decay by 9%.
Since, 9% is a common factor by which the value of car is decreasing,
Therefore, decay will be exponential.
Expression for the exponential decay is given by,
[tex]P=P_0(1-\frac{r}{100} )^t[/tex]
Here, [tex]P=[/tex] Final price
[tex]P_0=[/tex] Initial price
[tex]r=[/tex] Rate of decay
[tex]t=[/tex] time
If initial price of the car [tex]P_0=11000[/tex], rate of decay [tex]r=0.09[/tex] and [tex]t=[/tex] Number of years
By substituting the values in the expression,
P = [tex]11000(1-0.09)^2[/tex]
= 11000(0.91)²
= $9109.10
Therefore, final value of the car after 2 years will be $9109.10
Learn more,
https://brainly.com/question/24515212
Write the number six hundred and forty-
nine thousand and six in figures
Answer:
649,006
Step-by-step explanation:
Six hundred and forty nine thousand= 649,000
and six so we have
649006
THE ANSWER IS 649,006 HOPE IT HELPS
Which is the better buy?. Store A $180 at 1/3 off Or Store B $110 at 10% off (SHOW YOUR WORK)
Answer:
not 100% sure but my answer is 110
Step-by-step explanation:
It is More Affordable and is the better Buy From All the other choices.
Question 1 of 10
2 Points
The standard form of the equation of a parabola is y = 7x2 + 14x + 4.
What is the vertex form of the equation?
A. y = 7(x + 1)2-3
B. y= 7(x + 2)2-3
c. y= 7(x + 1)2 + 3
D. y= 7(x + 2)2 + 3
SUBMIT
Answer:
A. y = 7(x + 1)²-3
Step-by-step explanation:
Parabola:
[tex]y = 7x^{2} + 14x + 4[/tex]
[tex]y = 7(x^{2} + 2x) + 4[/tex]
Putting into vertex form, remember that:
[tex](x + a)^{2} = x^{2} + 2ax + a^{2}[/tex]
In this question:
[tex]x^{2} + 2x[/tex], to put into this format:
[tex]x^{2} + 2x + 1 = (x + 1)^{2}[/tex]
We add one inside the parenthesis to do this. The parenthesis is multiplied by 7, so for the equivalent, we also have to subtract 7. Then
Vertex form:
[tex]y = 7(x^{2} + 2x + 1) + 4 - 7[/tex]
[tex]y = 7(x + 1)^{2} - 3[/tex]
So the correct answer is:
A. y = 7(x + 1)²-3
What is the product -3 1/3of -8 7/10 and ?
Answer:
Brainliest!!!
Step-by-step explanation:
See picture!!
Answer:
29
Step-by-step explanation: