A local Little league has a total of 60 players, 80% of whom are right-handed. How many right-handed players are there?
(Please answer step by step.)

Answer:

is that paper or did you write on the screen?

Answer:

0.75

0.7205882

25.5

Result is significant at α = 0.01 and α = 0.05

Model improved

Step-by-step explanation:

Given that:

Number of observations (n) = 20

Total sum of squares (SST) = 1000

Model sum of squares (SSR) = 750

1) R² = SSR / SST = 750 / 1000 = 0.75

2.)

Adjusted R² = [(SST - SSR) /(n-k-1)] / (SST ÷ (n - 1))

k = number of regressors = 2

Adj R² = 1 - ((1000 - 750) / (20-2-1)) / (1000 / (20 - 1))

1 - 0.2794117 = 0.7205882

3.) Fstat = (SSR / k) / ((SST - SSR) / (n - k-1))

= (750 /2) / ((1000 - 750) / (20 - 2 - 1))

= 25.5

4.) At α = 0.05

Fα,k,(n - k-1) = F0.05, 2, (20 - 2 - 1) = F0.05,2, 17 = 3.5915 (f distribution calculator)

Fstat > F0.05, 2, (20 - 2 - 1)

25.5 > 3.5915 (Hence result is significant at α = 0.05

At α = 0.01

Fα,k,(n - k-1) = F0.01, 2, (20 - 2 - 1) = F0.01,2, 17 = 6.112 (f distribution calculator)

Fstat > F0.01, 2, (20 - 2 - 1)

25.5 > 6.112 (Hence result is significant at α = 0.01

Adjusted R² if a 3rd regressors is added : k = 3

Adjusted R² = [(SST - SSR) /(n-k-1)] / (SST ÷ (n - 1))

k = number of regressors = 3

SSR = 785

Adj R² = 1 - ((1000 - 785) / (20-3-1)) / (1000 / (20 - 1))

1 - 0.2553125 = 0.7446875

Adjusted R² value is now 0.7446875 which is greater than with 2 regressors,. Hence, adding a third regressors improved the model.

Answer:

2

4/.5 = 2

Therefore, your answer is 2, or A. Hope this helped!

Answer:

the answer is B) 8

Step-by-step explanation:

hope this helped sorry if it didn't and if it's wrong sorry for that also.

Answer:

Ax=6

Y=12

Therefore a=6, x=1, y=12

Answer:

{([tex]\frac{6}{a}[/tex],12)}

Step-by-step explanation:

[tex]\left \{ {{ax+y=18} \atop {4ax-y=12}} \right.[/tex]

[tex]5ax = 30[/tex]

[tex]x = \frac{6}{a}[/tex]

[tex]a(\frac{6}{a}) + y = 18[/tex]

6 + y =18→y=12

[tex]4a(\frac{6}{a}) - 12 = 12[/tex]

6 - 12 = 12 → 12 = 12 true  x=[tex]\frac{6}{a}[/tex]  y=12

Answer:

We have to choose 21 strings to be sure we have chosen at least 6 strings of the same type.

Step-by-step explanation:

Since the string type is determined by the initial and terminal bits as understood from the question, then the value of the bits between the initial and terminal bits is of no concern to us.

Now, to be sure you have atleast 6 of the same type, we select each string five times. By doing this, we have already selected 20 strings because we have 4 strings there. Now if you choose any of the string one more time, we are certain that we must have chosen atleast 6 strings that are the same. This means we have to choose 21 strings to be sure we have chosen at least 6 strings of the same type.

Answer:

$12.55

Step-by-step explanation:

25-6.75=18.25

18.25-3.70=14.55

14.55-2=12.55

Miguel has $12.55 left

Answer:

Step-by-step explanation:

surface area = 2πrh + 2πr²

where r = 7 m radius

           h = 2 m

plugin values into the formula

surface area = 2πrh + 2πr²

                     = 2π (7) 2  +  2π (7)²

                     = 87.965  +  307.867

                     = 395.841 m²

Answer:

395.841 m²

Step-by-step explanation:

surface area = 2πrh + 2πr² and r = 7 m radius

h = 2 m

Plugin

 2π (7) 2  +  2π (7)²

multiply into itself than add

87.965  +  307.867

add

395.841 m²

Therefore your answer would be 395.841 m²

Answer:

3

Step-by-step explanation:

1+1=2

Answer:

The company is expected the company will receive

Answer:

0.75

Step-by-step explanation:

To find the slope of the graph, you have to find the rise and the run by any two points on the graph. (I'm going to calculate using the two blue dots as shown in the picture)

[tex]\frac{rise}{run}[/tex] = [tex]\frac{(-2)-(-5)}{4-0}[/tex]

           = [tex]\frac{-2+5}{4}[/tex]

           = [tex]\frac{3}{4}[/tex]

           = 0.75

Answer:

Slope = -69, y-intercept is (0, -346)

Step-by-step explanation:

y=-69x-346

x=0

y= -69(0)-346

y=0-346

y=0

sople -69 coefficient of x

Answer:

c

Step-by-step explanation:

Answer:

6543

Step-by-step explanation:

Not much to explain lol

Here,

Odd numbers are 3 and 5.

The largest odd number =6543

Answer:

5/9 x 3/10 = 15/90 as simplified as 1/6 in fraction form.

5/9 multiplied by 3/10 is equal to 1/6 in its simplest form.

We have,

To multiply fractions, we multiply the numerators together and the denominators together.

The resulting fraction is then simplified to its simplest form.

Let's multiply 5/9 by 3/10:

(5/9) x (3/10) = (5 x 3) / (9 x 10) = 15/90

To simplify the fraction 15/90, we can divide both the numerator and denominator by their greatest common divisor, which is 15:

15/90 = (15 ÷ 15) / (90 ÷ 15) = 1/6

Therefore,

5/9 multiplied by 3/10 is equal to 1/6 in its simplest form.

Learn more about fractions here:

https://brainly.com/question/24370499

#SPJ6

Answer:

$11.83

Step-by-step explanation:

1 gallon = 3.785 litres

0.5(1/2gallon) = x liters

x = 0.5 × 3.785 liters

x = 1.89271 liters

0.8 liter = 100 pesos

1.89271 liters = x pesos

x = 1.89271 × 100/0.8

x = 236.58875 pesos

Converting to dollars

1 mexican peso = $0.050

236.58875 pesos = x

x = 236.58875 × $0.050

x = $11.8294375

Approximately = $11.83

A half gallon jug of the same wine cost in dollars $11.83

Step-by-step explanation:

Step one:

We are told that the store offers off 10% of sales, this means that the store is offsetting the price down by 10% hence a price reduction.

Moreso, a coupon is a voucher entitling the holder to a discount off a particular product. the coupon is 40%, hence this is equal to a discount, that is price reduction by 40%.

Step two:

Say the price of an item is $100, a coupon if 40% will entitle the holder to only pay $60, that is

=40/100*100

=0.4*100

=$40 off

= 100-40

=$60

The total percent of reduction 10+40= 50%

This is equal to a discount on the sales price

Answer:

a) $141.5 = 330m + b...... Equation 1

$337.5 = 890m + b..... Equation 2

b) $244.4

Step-by-step explanation:

The phone company Splint has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount of money per minute used on the phone. If a customer uses 330 minutes, the monthly cost will be $141.5. If the customer uses 890 minutes, the monthly cost will be $337.5.

Required:

a. Find an equation in the form y= mx +b, where x is the number of monthly minutes used and y is the total monthly of the Splint plan.

If a customer uses 330 minutes, the monthly cost will be $141.5.

y = mx + b

$141.5 = 330m + b

If the customer uses 890 minutes, the monthly cost will be $337.5.

$337.5 = 890m + b

Combining the equations

$141.5 = 330m + b...... Equation 1

$337.5 = 890m + b..... Equation 2

b. Use your equation to find the total monthly cost if 624 minutes are used

Combining the equations

$141.5 = 330m + b...... Equation 1

$337.5 = 890m + b..... Equation 2

We Subtract Equation 2 from 1

-196 = -560m

m = -196/-560

m = 0.35

$337.5 = 890m + b..... Equation 2

$337.5 = 890 × 0.35 + b

$337.5 - 311.5 = b

b = 26

When x = 624

y = 624× m + b

m = 0.35 , b = 26

y = 624 × 0.35 + 26

y = 218.4 + 26

y = $ 244.4

Answer:

Her brother is 10 years old

Step-by-step explanation:

14 ÷ 2 = 7

7 + 3 = 10

The answer is 10

Answer:

2 and 2/5

Step-by-step explanation:

Trust me on this, also can I have brainlest please? Hope you do well!

2 and two fifths i took the test 6 years ago

Answer:

5.38516480713

Step-by-step explanation:

a^2+b^2=c^2

5^2+2^2=c^2

25+4=c^2

c^2=square root of 29

c=5.38516480713

The answer is 43 because when you multiply 6x6 you get 36 and if you add 6 more you get 42 which is one less that 43

Answer:

The equations have one solution at (5, -5).

Step-by-step explanation:

We are given a system of equations:

[tex]\displaystyle{\left \{ {{-2x+5y=-35} \atop {7x+2y=25}} \right.}[/tex]

This system of equations can be solved in three different ways:

Graphing the Equations

We need to solve each equation and place it in slope-intercept form first. Slope-intercept form is [tex]\text{y = mx + b}[/tex].

Equation 1 is [tex]-2x+5y = -35[/tex]. We need to isolate y.

[tex]\displaystyle{-2x + 5y = -35}\\\\5y = 2x - 35\\\\\frac{5y}{5} = \frac{2x - 35}{5}\\\\y = \frac{2}{5}x - 7[/tex]

Equation 1 is now [tex]y=\frac{2}{5}x-7[/tex].

Equation 2 also needs y to be isolated.

[tex]\displaystyle{7x+2y=25}\\\\2y=-7x+25\\\\\frac{2y}{2}=\frac{-7x+25}{2}\\\\y = -\frac{7}{2}x + \frac{25}{2}[/tex]

Equation 2 is now [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex].

Now, we can graph both of these using a data table and plotting points on the graph. If the two lines intersect at a point, this is a solution for the system of equations.

The table below has unsolved y-values - we need to insert the value of x and solve for y and input these values in the table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & a \\ \cline{1-2} 1 & b \\ \cline{1-2} 2 & c \\ \cline{1-2} 3 & d \\ \cline{1-2} 4 & e \\ \cline{1-2} 5 & f \\ \cline{1-2} \end{array}[/tex]

[tex]\bullet \ \text{For x = 0,}[/tex]

[tex]\displaystyle{y = \frac{2}{5}(0) - 7}\\\\y = 0 - 7\\\\y = -7[/tex]

[tex]\bullet \ \text{For x = 1,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(1)-7}\\\\y=\frac{2}{5}-7\\\\y = -\frac{33}{5}[/tex]

[tex]\bullet \ \text{For x = 2,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(2)-7}\\\\y = \frac{4}{5}-7\\\\y = -\frac{31}{5}[/tex]

[tex]\bullet \ \text{For x = 3,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(3)-7}\\\\y= \frac{6}{5}-7\\\\y=-\frac{29}{5}[/tex]

[tex]\bullet \ \text{For x = 4,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(4)-7}\\\\y = \frac{8}{5}-7\\\\y=-\frac{27}{5}[/tex]

[tex]\bullet \ \text{For x = 5,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(5)-7}\\\\y=2-7\\\\y=-5[/tex]

Now, we can place these values in our table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

As we can see in our table, the rate of decrease is [tex]-\frac{2}{5}[/tex]. In case we need to determine more values, we can easily either replace x with a new value in the equation or just subtract [tex]-\frac{2}{5}[/tex] from the previous value.

For Equation 2, we need to use the same process. Equation 2 has been resolved to be [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex]. Therefore, we just use the same process as before to solve for the values.

[tex]\bullet \ \text{For x = 0,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(0)+\frac{25}{2}}\\\\y = 0 + \frac{25}{2}\\\\y = \frac{25}{2}[/tex]

[tex]\bullet \ \text{For x = 1,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(1)+\frac{25}{2}}\\\\y = -\frac{7}{2} + \frac{25}{2}\\\\y = 9[/tex]

[tex]\bullet \ \text{For x = 2,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(2)+\frac{25}{2}}\\\\y = -7+\frac{25}{2}\\\\y = \frac{11}{2}[/tex]

[tex]\bullet \ \text{For x = 3,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(3)+\frac{25}{2}}\\\\y = -\frac{21}{2}+\frac{25}{2}\\\\y = 2[/tex]

[tex]\bullet \ \text{For x = 4,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(4)+\frac{25}{2}}\\\\y=-14+\frac{25}{2}\\\\y = -\frac{3}{2}[/tex]

[tex]\bullet \ \text{For x = 5,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(5)+\frac{25}{2}}\\\\y = -\frac{35}{2}+\frac{25}{2}\\\\y = -5[/tex]

And now, we place these values into the table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

When we compare our two tables, we can see that we have one similarity - the points are the same at x = 5.

Equation 1                  Equation 2

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]                 [tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

Therefore, using this data, we have one solution at (5, -5).

Answer:

[tex] - \bigg(3a - \frac{5}{2} b) \bigg)^{2} [/tex]

Step-by-step explanation:

[tex]15ab-9a^2-6 \frac{1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\ \\ = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2 \\ \\ = - \{ - 15ab + (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 \} \\ \\ = - \{ (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 - 15ab \} \\ \\ = - \bigg(3a - \frac{5}{2} b \bigg)^{2} [/tex]

Answer:

I mean it would just be q(x) = 0

Step-by-step explanation:

Answer: q=0

Step-by-step explanation: Let's solve for q.

qx=2−2

Step 1: Divide both sides by x.

qx

x

=

0

x

q=0

Answer:

q=0

Answer:

[tex]t=\dfrac{9\pm 3}{6}[/tex]

[tex]1\ \text{hour}[/tex]

[tex]2\ \text{hour}[/tex]

Step-by-step explanation:

s = Speed of Emile = 6 miles/hour

d = Distance traveled by Emile = [tex](9\pm 3)\ \text{miles}[/tex]

Time taken to find the minimum and maximum time Emile ran for is

[tex]t=\dfrac{d}{s}\\\Rightarrow t=\dfrac{9\pm 3}{6}[/tex]

The required equation is [tex]t=\dfrac{9\pm 3}{6}[/tex]

The time taken is

[tex]t=\dfrac{9-3}{6}\\\Rightarrow t=\dfrac{6}{6}\\\Rightarrow t=1\ \text{hour}[/tex]

The minimum number of hours Emile runs is 1 hour.

[tex]t=\dfrac{9+3}{6}\\\Rightarrow t=\dfrac{12}{6}\\\Rightarrow t=2\ \text{hour}[/tex]

The maximum number of hours Emile runs is [tex]2\ \text{hour}[/tex].

Answer:

|6x – 9| = 3

1 Hour

2 Hours

Step-by-step explanation:

The equation that can be used to find the minimum and maximum time (in hours) Emile runs is_|6x – 9|= 3_. For each practice run, the minimum number of hours Emile runs is__1 hour_ and the maximum number of hours he runs is _2 hour.

Answer:

20.77

Step-by-step explanation:

Answer:

20.77

Step-by-step explanation:

Simplify  16.9+ 1.7  to  18.6

18.6 +0.17+2.0

Simplify  18.6+0.17 to  18.77

18.77+2.0

Simplify.

ANddddd the answer is

20.77