A hot-air balloon stays aloft because hot air at atmospheric pressure is less dense than cooler air at the same pressure. If the volume of the balloon is 500.0 m^3 and the surrounding air is at 15.0°C. What must the temperature of the air in the balloon be for it to lift a total load of 290 kg (in addition to the mass of the hot air)? The density of air at 15.0°C and atmospheric pressure is 1.23kg/m^3.

Answers

Answer 1

Answer:

272° C

Explanation:

Given :

Volume of the balloon, V = 500 [tex]m^3[/tex]

The temperature of the surrounding air, [tex]T_{air} = 15^\circ C[/tex]

Total load, [tex]m_{T}[/tex] = 290 kg

Density of the air, [tex]$\rho_{air} = 1.23 \ kg/m^3$[/tex]

We known buoyant force,

[tex]$F_B = \rho_{air} V$[/tex]

For a 290 kg lift,  [tex]$m_{hot} = \frac{F_B}{g} = 290 \ kg$[/tex]

[tex]$m=\rho V$[/tex]

∴ [tex]$m_{hot}=\rho_{hot} V ; \ \ \ \ \ \frac{F_B}{g}-m_{hot} = 290 \ kg$[/tex]

  [tex]$(\rho_{air} - \rho_{hot}) V= 290 \ kg$[/tex]

  [tex]$\rho_{hot} = \rho_{air}- \frac{290}{V} \ kg = 1.23 \ kg/m^3 - \frac{290 \ kg}{500 \cm^3}$[/tex]

  [tex]$\rho_{hot}= 0.65 \ kg/m^3 =\frac{\rho M}{R T_{hot}}$[/tex]

 ∴ [tex]$\rho_{hot} T_{hot}= \rho_{air} T_{air}$[/tex]

   [tex]$T_{hot}= T_{air}\left[\frac{\rho_{air}}{\rho_{hot}}\right]$[/tex]

          [tex]$=288 \ K \times \frac{1.23 \ kg/m^3}{0.65 \ kg/m^3}$[/tex]

         = 545 K

          [tex]$=272^\circ C$[/tex]

Therefore, temperature of the air in the balloon is 272 degree Celsius.

Answer 2

To lift a load more than the weight of the balloon, the temperature of the air in the balloon has to be higher than the air in the surrounding.

The temperature of the air in the balloon to lift a total load of 290 kg is approximately 272.12°C.

Reasons:

Given information are;

Volume of the balloon = 500.0 m³

Temperature of the surrounding air = 15.0°C

Density of air at 15.0°C = 1.23 kg/m³

Required:

The temperature required to lift 290kg.

Solution:

Let, [tex]\rho _{air , b}[/tex], represent the density of the air in the balloon, we have;

[tex]\rho _{air , b}[/tex] × 500.0 + 290 = 1.23 × 500

Therefore;

[tex]\displaystyle \rho _{air , b} = \frac{1.23 \times 500- 290}{500} = 0.65[/tex]

According to the Ideal Gas Law, we have;

ρ₁ × R × T₁ = ρ₂ × R × T₂

Therefore;

[tex]\displaystyle T_2 = \mathbf{\frac{\rho_1 \times T_1}{\rho_2}}[/tex]

Therefore;

[tex]\displaystyle T_2 = \frac{1.23\times288.15}{0.65} \approx 545.27[/tex]

The temperature of the balloon, T₂ ≈ 545.27 -  273.15 = 272.12

The temperature of the air in the balloon, T₂ ≈ 272.12 °C

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Related Questions

The volume of an ideal gas changes from 0.40 to 0.55 m3 although its pressure remains constant at 50,000 Pa. What work is done on the system by its environment

Answers

Answer:

w= p∆v 50000 ( 0.55-0.40) and calculate and you get it

The work done on the system by its environment is 7,500J.

To find the work done, we need to know about the work done on an ideal gas during isobaric process.

What is isobaric process?

When the pressure is remained constant throughout a process, then the process is called isobaric process.

What is the work done on a system in the isobaric process?For a isobaric process, the work done is pressure × (final volume of the system - initial volume)

Here, Final volume= 0.55 m³

         Initial volume= 0.40 m³

         Pressure= 50,000 Pa

Work done = 50,000 × (0.55 - 0.40)

                  = 7,500 J

Thus, we can conclude that 7,500 J of  work is done on the system by its environment.

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If we convert a circuit into a current source with parallel load it is called?​

Answers

Answer:

If we convert a circuit into a current source with parallel load it is called source transformation

an object moves clockwise around a circle centered at the origin with radius m beginning at the point ​(0,​). a. find a position function r that describes the motion of the object moves with a constant​ speed, completing 1 lap every s. b. find a position function r that describes the motion if it occurs with speed .

Answers

Answer:

Answer to An object moves clockwise around a circle centered at the origin with radius 6 m beginning at ... 6 M Beginning At The Point (0,6) B. Find A Position Function R That Describes The Motion If It Occurs With Speed E T A. R(t)= S The Motion Of The Object Moves With A Constant Speed, Completing 1 Lap Every 12 S.

Explanation:

1.A motor is rated at 1.5 hp. At what speed in m/s can this motor raise a
200 kg load?

2. A bucket of water with a total weight of 50 Newtons is lifted at constant
velocity up a 10 meter deep well. If it takes 20 seconds to raise the bucket
this distance, what is the power required to lift the bucket?​

Answers

Answer:

1. 0.57 m/s

2. 25 Watts

Explanation:

1. Determination of the speed.

We'll begin by converting 1.5 hp to watt (W). This can be obtained as follow:

1 hp = 745.7 W

Therefore,

1.5 hp = 1.5 hp × 745.7 W / 1 hp

1.5 hp = 1118.55 W

Next, we shall determine the force. This can be obtained as follow:

Mass (m) = 200 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = m × g

F = 200 × 9.8

F = 1960 N

Finally, we shall determine the speed. This can be obtained as follow:

Power (P) = 1118.55 W

Force (F) = 1960 N

Speed (v) =?

P = F × v

1118.55 = 1960 × v

Divide both side by 1960

v = 1118.55 / 1960

v = 0.57 m/s

Thus, the speed is 0.57 m/s

2. Determination of the power.

We'll begin by calculating the velocity. This can be obtained as follow:

Displacement = 10 m up

Time = 20 s

Velocity =?

Velocity = Displacement / time

Velocity = 10 / 20

Velocity = 0.5 m/s

Finally, we shall determine the power. This can be obtained as follow:

Velocity (v) = 0.5 m/s

Force (F) = 50 N

Power (P) =?

P = F × v

P = 50 × 0.5

P = 25 Watts

Therefore, the power required to lift the bucket is 25 Watts

A body of mass 5 kg is moved by a horizontal force of 0.5 N on a smooth frictionless table for 20 seconds. Calculate the change in kinetic energy.

A. 5 J

B. 20 J

C. 10 J

D. 30 J​

Answers

Answer: 10 J

Explanation:

Trust ;)

Which of these is NOT an effect of humor?


strengthened immune system

reduced stress levels

reduced feelings of anxiety

feelings of jealousy and envy

Answers

feelings of jealousy and envy

Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating about a perpendicular axis at one end is ml2/3. Write your answer with one decimal place.

Answers

Answer:

2.2 s

Explanation:

Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point =  mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)

So, T = 2π√(I/mgh)

T = 2π√(mL²/3 /mgL/2)

T = 2π√(2L/3g)

substituting the values of the variables into the equation, we have

T = 2π√(2L/3g)

T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))

T = 2π√(3.66 m/(29.4 m/s² ))

T = 2π√(0.1245 s² ))

T = 2π(0.353 s)

T = 2.22 s

T ≅ 2.2 s

So, the period of the man's leg is 2.2 s

(10) The use of Doppler radar for speed detection and enforcement on the roads is very common and has been in use for a long time. Suppose a 10 GHz radar (also called radar gun or speed gun) measures the speed of a car at 120 km/h moving towards the radar gun. a. What is the change in the frequency of the reflected wave due to the speed of the car b. Calculate the sensitivity of the device in [Hz/km].

Answers

Answer:

The sensitivity of the device = 1.234 Hz per km

Explanation:

Given  

Frequency (f) = 10 gHz

Speed of the car = 120 Km/h

As per the doppler’s effect

V = (change in frequency /frequency) *(c/2)

Substituting the given values, we get –  

Change in frequency = {(2*10^9*120)/(3*10^8)} * (1000/3600)

Change in frequency =  37.03 Hz

b) speed of light = wavelength * frequency

3*10^8 = wavelength * 10*10^9

Wavelength = 0.03 m

Sensitivity = change in frequency /wavelength = 37.03/0.03 = 1234 Hz/m

1.234 Hz per km

One solenoid is centered inside another. The outer one has a length of 50.0 cm and contains 6750 coils, while the coaxial inner solenoid is 3.0 cm long and 0.120 cm in diameter and contains 15 coils. The current in the outer solenoid is changing at 49.2 A>s. (a) What is the mutual inductance of these solenoids

Answers

Answer: The mutual inductance of these solenoids is [tex]2.88 \times 10^{-7} H[/tex].

Explanation:

Given: Length = 50.0 cm (1 cm = 0.01 m) = 0.50 m

[tex]N_{1}[/tex] = 6750

[tex]N_{2}[/tex] = 15

Radius = [tex]\frac{0.120 cm}{2} = 0.6 cm = 6 \times 10^{-4} m[/tex]

As inner of a solenoid resembles the shape of a circle. So, its area is calculated as follows.

[tex]Area = \pi \times r^{2} = \pi \times (6 \times 10^{-4})^{2}[/tex]

Formula used to calculate mutual conductance of two solenoids is as follows.

[tex]M = \frac{\mu_{o} \times A \times N_{1} \times N_{2}}{l}[/tex]

where,

M = mutual conductance

A = area

[tex]\mu_{o}[/tex] = relative permeability = [tex]4 \pi \times 10^{-7} Tm/A[/tex]

[tex]N_{1}[/tex] = no. of coils in outer solenoid

[tex]N_{2}[/tex] = no. of coils in inner solenoid

l = length

Substitute the values into above formula as follows.

[tex]M = \frac{\mu_{o} \times A \times N_{1} \times N_{2}}{l}\\= \frac{4 \pi \times 10^{-7} Tm/A \times \pi (6 \times 10^{-4})^{2} \times 6750 \times 15}{0.5 m}\\= 2.88 \times 10^{-7} H[/tex]

Thus, we can conclude that the mutual inductance of these solenoids is [tex]2.88 \times 10^{-7} H[/tex].

Astronauts use a centrifuge to simulate the acceleration of a rocket launch. The centrifuge takes 40.0 ss to speed up from rest to its top speed of 1 rotation every 1.30 ss . The astronaut is strapped into a seat 5.90 mm from the axis. What is the astronaut's tangential acceleration during the first 40.0 s?

How many g's of acceleration does the astronaut experience when the device is rotating at top speed? Each 9.80 m/s^2 of acceleration is 1 g.

Answers

Answer:

speed = 0.9 mm/s

Explanation:

time, t = 40 s

initial angular speed, wo = 0 rad/s

final frequency, f = 1/1.03 rps = 0.97 rps

final angular speed, w = 2 x 3.14 x 0.97 = 6.1 rad/s

time, t = 40 s

distance, r = 5.9 mm

The angular acceleration is given y the first equation of motion.

[tex]w =wo + \alpha t\\6.1 = 0 +\alpha \times 40\\\alpha = 0.1525 rad/s^{2}[/tex]

The linear velocity is

[tex]v =5.9\times 10^{-3}\times 0.1525 = 9\times 10^{-4} m/s[/tex]

speed, v = 0.9 mm/s

help me with following question.

Answers

Answer:

The answer for this question is 50k N.m

A balloon contains 0.04m3 of air at a pressure of 1.20 x 105Pa. Calculate the pressure required to reduce its volume to 0.025m3 at constant temperature.​

Answers

Answer:

you can simply answer p1v1=p2v2 p2 = p1v1÷ p2 then inter what given in the formula you get it pl=1.20x 105pa vl= 0.40m3 v2=0.025m3

how can you prove that acceleration is a derived unit​

Answers

a = (dx / dt)²

Explanation:  Unit of distance is m (metres) and unit of time is s (seconds) speed v is  first derivative of distance x versus time:

  v = dx / dt, unit is m/s.    Acceleration is second derivative of

 speed versus time  a = (dx / dt)² = (dv/dt) , unit is m/s²

Answer:

Explanation:

Acceleration is derived unit because it has two fundamental units involved i.e. meter and second square.

Give an example of a vertical motion with a positive velocity and a negative acceleration. Give an example of a vertical motion with a negative velocity and a negative acceleration.

Answers

Answer:

An example of positive velocity is throwing a ball upwards

An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height

Explanation:

In a vertical movement the acceleration is always downwards, therefore negative since it is created by the attraction of the Earth on the body.

An example of positive velocity is throwing a ball upwards

An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height

You drive past a potential parking space in center city. Your new car is travelling at 85% the speed of light. If your car is 6.0 m long (which you measured the day you bought it) and you observe the space to be 3.0 m, should you try to park? Why is your friend on the sidewalk (who hasn't studied relativity) so sure that you can park? How does the situation appear to him?

Answers

Answer:

We should not try to park the car because its rest length is greater than the space available.

The car seems to be approximately equal to the friend (L = 3.16 m). Due to this reason he is sure to park.

Explanation:

We should not try to park the car because its rest length is greater than the space available.

The friend is sure about parking because the car appears short in length to him. For this, we will solve Einstein's length contraction formula from theory of relativity:

[tex]L = L_o\sqrt{1-\frac{v^2}{c^2}}[/tex]

where,

L = Relative length observed by friend = ?

L₀ = rest length = 6 m

v = relative speed = 85% of speed of light = 0.85c

Therefore,

[tex]L = (6\ m)\sqrt{1-\frac{(0.85c)^2}{c^2}}[/tex]

L = 3.16 m

Hence, the car seems to be approximately equal to the friend. Due to this reason he is sure to park.

15. In the diagram shown, the emf of the secondary winding is______ the emf of the primary winding.

A. Less than

B. Equal to

C. Greater than

Answers

Answer:

Greater than

Explanation:

Which property of matter determines the amount of inertia an object has? Matter’s ________

Answers

Answer:

Mater's Mass is the Answer

A battery has an EMF of 12 Volts, internal resistance of 0.5 Ohms, and its terminal voltage is measured to be 13 Volts. The battery is ________ and has a current of ____ Amps passing through.

Answers

Answer:

The battery is charging and has a current of 2Amps passing through.

Explanation:

Given;

EMF of the battery, E = 12 V

internal resistance, r = 0.5 ohms

terminal voltage of the battery, ΔV = 13 volts

When the terminal voltage is greater than the EMF of the battery, the battery is being charged, allowing currents to pass in a reverse direction.

ΔV = E - Ir

ΔV - E = -Ir

13 - 12 = -0.5I

1 = -0.5I

I = 1 / -0.5

I = -2 A

The negative sign indicates the reverse direction of the current.

Therefore, the battery is charging and has a current of 2Amps passing through.

Convert 15000kg/m cube
into gm/cm cube
please write the process also​

Answers

Answer:

15000 Kilograms/Cubic Meters (kg/m3) = 15 Grams/Cubic Centimeters (g/cm3)

Explanation:

1 g/cm3 is equal to 1000 kilogram/cubic meter. To convert 100 gram into kg then divide it by 1000 i.e. 100/1000 = 0.1 kg. To convert any value of gm/cm3 into kg/m3 then multiply it by 1000.

15000 kg / m^3 =

15000 × 10^3 g / m^3 =

15000 × 10^3 × 10^3 mg / m^3 =

15 × 10^9 mg / m^3 =

15 × 10^9 × 10^(-3) mg / dm^3 =

15 × 10^9 × 10^(-3) × 10^(-3) mg / cm^3 =

15 × 10^9 × 10^(-6) mg / cm^3 =

15 × 10^( 9 - 6 ) mg / cm^3 =

15 × 10^3 mg / cm^3 =

15000 mg / cm^3 =

Look : We found the exact thing we had ...

WoW ...

We got a point ;

Remember from now on :

kg / m^3 = mg / cm^3

PLS ANSWER WORTH 10 POINTS PLS HELP

Answers

Answer:

the answer should be D

Explanation:

Because if you want to earn your goals you must complete small goals to earn big goals

A 615 N student standing on a scale in an elevator notices that the scale reads 645 N. From this information, the student knows that the elevator must be moving Group of answer choices You cannot tell if it is moving upward or downward. upward. downward.

Answers

Answer:

The elevator must be moving upward.

Explanation:

During the motion of an elevator, the weight of the person deviates from his or her actual weight. This temporary weight during the motion is referred to as "Apparent Weight". So, when the elevator is moving downward, the apparent weight of the person becomes less than his or her actual weight.

On the other hand, for the upward motion of the elevator, the apparent weight of the person becomes more than the actual weight of that person.

Since the apparent weight (645 N) of the student, in this case, is greater than the actual weight (615 N) of the student.

Therefore, the elevator must be moving upward.

Which statement is true?
a particle of violet light has less energy than a particle of red light
a particle of violet light has more energy than a particle of red light
a particle of violet light has exactly the same energy as a particle of red light
particles of light do not have any energy, regardless of what color the light is

Answers

a particle of violet light has exactly the same energy as a particle of red light

The electric field of a negative infinite line of charge: Group of answer choices Points perpendicularly away from the line of charge and decreases in strength at larger distances from the line charge Points parallel to the line of charge and decreases in strength at larger distances from the line charge Points parallel to the line of charge and increases in strength at larger distances from the line charge Points perpendicularly away from the line of charge and increases in strength at larger distances from the line charge Points perpendicularly toward the line of charge and increases in strength at larger distances from the line charge Points perpendicularly toward the line of charge and decreases in strength at larger distances from the line charge

Answers

Answer:

Points perpendicularly toward the line of charge and decreases in strength at larger distances from the line charge

Explanation:

The electric field for a uniform line of charge is given by E = λ/2πε₀r where λ = charge density and r = distance from line of charge.

If λ is negative, E is negative so it points in the negative direction towards the line of charge.

Also, since for negative charges, electric field lines end up in them, the electric field for an infinitely long negative line of charge points towards the charge perpendicular to it.

Also as r increases, E decreases since E ∝ 1/r

So, the electric field decreases at larger distances from the line of charge.

So, the electric field of a negative infinite line of charge Points perpendicularly toward the line of charge and decreases in strength at larger distances from the line charge.

What is the path of an electron moving perpendicular to a uniform magnetic field?

Answers

since their movement is always free pendicular to the force magnetic force no work and the electrons velocity stays constant since the force is F=QVB a constant magnetic field and another from field force of content magnitude always directed perpendicular to its motion the result is a circle Orbit.

Explanation:

this is your answer I hope it is helpful please mark me brainly

PLEASE HELPPPPPPPPPP​

Answers

Answer:

13.09 s

Explanation:

From the question given above, the following data were obtained:

Power (P) = 275 W

Work (W) = 3600 J

Time (t) =?

Power is defined as the rate at which work is done. Mathematically, it can be expressed:

Power (P) = Work (W) / time (t)

P = W/t

With the above formula, we can obtain the time taken for the swimmer to accomplish the work. This can be obtained as follow:

Power (P) = 275 W

Work (W) = 3600 J

Time (t) =?

P = W/t

275 = 3600/t

Cross multiply

275 × t = 3600

Divide both side by 275

t = 3600 / 275

t = 13.09 s

Thus, it will take the swimmer 13.09 s to accomplish the work.

How are the Northern Lights are formed.

Answers

Answer:

Bottom line: When charged particles from the sun strike atoms in Earth's atmosphere, they cause electrons in the atoms to move to a higher-energy state. When the electrons drop back to a lower energy state, they release a photon: light. This process creates the beautiful aurora, or northern lights.

Explanation:

^-^I hope it's help u

Hey guys....
What is the advantage of a capacitor as it stores charge? ​

Answers

First thing capacitor do not store charge, capacitor actually store an imbalance of charge.They are good at delivering ghe stored imbalance of charge.They have extremely low internal resistanceThey are safe to use

With explanation pls

Answers

Answer:

[tex](x \times 1) = (400 \times 2.5) \\ x = 1000 \: newtons[/tex]

[tex]y = 0[/tex]

A string has a linear density of 8.5 x 10-3 kg/m and is under a tension of 280 N. The string is 1.8 m long, is fixed at both ends, and is vibrating in the standing wave pattern shown in the drawing. Determine the
a. speed.
b. wavelength
c. frequency of the traveling waves that make up the standing wave.

Answers

Answer:

a)  [tex]v=181.497m/s[/tex]

b)  [tex]\lambda=1.2[/tex]

c)  [tex]F=151.248hz[/tex]

Explanation:

From the question we are told that:

Linear density [tex]\rho=8.5 x 10-3 kg/m[/tex]

Tension [tex]T= 280 N[/tex]

Length of string [tex]l= 1.8 m[/tex]

a)

Generally the equation for Speed of travelling wave is mathematically given by

 [tex]v=\sqrt{\frac{T}{\rho}}[/tex]

 [tex]v=\sqrt{\frac{280}{8.5*10^{-3}}[/tex]

 [tex]v=181.497m/s[/tex]

b)

From the Drawing

Wavelength is given as

 [tex]\lambda=\frac{2L}{3}[/tex]

 [tex]\lambda=\frac{2*1.8}{3}[/tex]

 [tex]\lambda=1.2[/tex]

c)

Generally the equation for Frequency of travelling wave is mathematically given by

 [tex]F=\frac[v}{\lambda}[/tex]

 [tex]F=\frac[181.497}{1.2}[/tex]

 [tex]F=151.248hz[/tex]

HELP ME PLEASEEEEEEEEEEEEEE

Answers

Answer: The correct statements are:

The atoms are very attracted to one another.The atoms are held tightly together.

Explanation:

Solid state: In this state, the molecules are closely packed and cannot move freely from one place to another that means no space between them and the intermolecular force of attraction between the molecules are strong.

In solid substance, the particles are very close to each other due to this the intermolecular forces of attraction are strongest.

The key point about solid are:

The atoms are very attracted to one another.The atoms are not moving freely.It will not spread out evenly to fill any container.The atoms are held tightly together.The forces of attraction are strong to bring molecules together.The atoms are close and in fixed positions.
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