Answer:
15 m/s
Explanation:
Given data
Initial velocity= 0m/s----------since the cart was at rest
Final velocity = 30m/s
time= 30 seconds
Required
the average speed
We know that the sum of the initial and final velocity is divided by 2 to find the average velocity
average velocity= 0+30/2
average velocity= 30/2
average velocity= 15 m/s
Hence the average velocity is 15 m/s
PLS ANSWER FAST THIS IS TIMED TEST AND WILL GIVE BRAINLY!!!
Answer using mass m= F divided by a
Also use kilograms [kg]
A cannonball accelerates at 1000 m/s2 from an applied force of 5000 N . What is the mass of the cannonball?
Answer:
mass is 5 kg
Explanation:
F=m/a
M=f/a
F=5000
a=1000
5000/1000=5
Sound waves are a type of compression wave. In a compression wave, we have areas of compaction and also areas of rarefaction. In
the areas of compression, particles are pushed together and in areas of rarefaction, particle spread apart. Sound waves are different
from light waves in several ways and one is in the type of wave. Light waves are transverse waves that have crests or peaks and
troughs or dips. Which model best shows us a light or transverse wave with very high crests and very low troughs?
Answer: C
Explanation:
The model which represents best of transverse wave with very high crests and low troughs is the third graph. Hence, option C is correct.
What is Sound?Sound is a physical perturbation from an equilibrium position that travels through an elastic medium of material. It is also possible to define sound solely subjectively, as that which is regarded by the ear, but this definition lacks clarity and is overly constrictive because it is useful to discuss sounds that are produced by devices other than the human ear, such as dog whistles and sonar hardware, which cannot be done here by the auditory system.
The characteristics of sound waves should be examined first in any study of sound. Transverse and longitudinal waves are the two fundamental forms of waves, and they differ by the direction wherein they move.
The first graph is uniform trough and crest, but the third one has higher crest but lower trough.
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PLS ANSWER FAST THIS IS TIME TEST AND WILL GIVE BRANINLY!!!!
Answer using mass m= F divided by a
Also use kilograms {kg}
A tiny aeroplane accelerates at 35 m/ s2 with a force of 20 N. What is the mass of the aeroplane?
Answer:
0.57 kg
Explanation:
We are given that
Force, F=20 N
Acceleration ,a =[tex]35m/s^2[/tex]
We have to find the mass of Aero-plane.
To find the value of mass we will divide the force by acceleration.
We know that
Force, F=ma
Using the formula
[tex]20=m\times 35[/tex]
[tex]\frac{20}{35}=m[/tex]
[tex]m=0.57 kg[/tex]
Hence, the mass of the aero-plane=0.57 kg
A force of 500N Is applied to a steel wire of goss_sectional area 0.2m2 the tensele stress is a. 2.5x10 1nm-2 b. 1 0x102nm-2 c. 2.5x103nw-3 d. 1.0x103nm-2
Answer:
the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
Explanation:
Given;
applied force, F = 5000 N
cross sectional area of the steel wire, A = 0.2 m²
The tensile stress of the steel wire, is calculated as;
[tex]\sigma = \frac{F}{A} \\\\\sigma = \frac{500}{0.2} \\\\\sigma = 2500 \ N/m^2\\\\\sigma = 2.5 \ \times \ 10^3 \ Nm^{-2}[/tex]
Therefore, the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?
Answer:
i. 15.6 m/s
ii. I = 1.44 KNs
Explanation:
The impulse, I, on a body is the product of force applied on it and the time it acts.
i.e I = F x t
Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.
i. mass, m, of the player = 92 kg
initial velocity of the player, u = 9.4 m/s
final velocity of the player, v = 6.2 m/s
Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.
So that,
change in velocity of the player = final velocity - initial velocity
= 6.2 - (-9.4)
= 6.2 + 9.4
= 15.6 m/s
change in velocity of the player is 15.6 m/s
ii. Impulse, I = m(v - u)
= 92 x 15.6
= 1435.2
Impulse on the player is 1.44 KNs.
PLEASE HELP ASAP!!!!
Sort the statements based on whether they are correct or incorrect.
All waves have the same
wavelength.
Radio telescopes give us
information about the
birthplace of a star.
If the wavelength of a wave
increases, its frequency
also increases.
Visible light is a kind of
electromagnetic wave.
All objects emit
electromagnetic waves.
Answer: the first is incorrect the second is correct the third is correct
Explanation: the fourth is correct the fifth is incorrect
A 1600 kg car with the brakes applied comes to a stop in 4.20 seconds. During these 4.20 seconds the force of friction slowing down the car is 3900 N. What is the change in momentum of the car?
Answer:
The change in momentum of the car is 16380.8 kg.m/s
Explanation:
Given;
mass of the car, m = 1600 kg
time of motion, t = 4.20s
force of friction on the car, F = 3900 N
final velocity of the car after the brakes were applied, v = 0
The initial velocity of the car during the motion is calculated as;
[tex]F = ma = \frac{mu}{t} \\\\mu = Ft\\\\u = \frac{Ft}{m} \\\\u = \frac{3900\times 4.2}{1600} \\\\u = 10.238 \ m/s[/tex]
The change in momentum of the car is calculated as;
ΔP = mu
ΔP = 1600 x 10.238
ΔP = 16380.8 kg.m/s
A wave travels at 13 m/s and the crests are 6 meters apart. How many waves would you see pass you by per second? (round up to the nearest decimal)
(PLS QUICK)
Answer:Number of waves =2.2
Explanation:
The frequency of A wave is defined as the number of waves moving a fixed point per second which is given as
f=[tex]\frac{N}{t}[/tex]
F= Frequency
N= number of waves
t= time
We first find the frequency
Given velocity of the wave, v = 13m/s
and wavelength, λ as 6meters(distance between two consecutive crest)
, we fiind the frequency using
v= f λ
frequency = v / λ
= (13m/s ) / 6
=2.16s-1
f = [tex]\frac{N}{t}[/tex]
2.16s₋¹= [tex]\frac{N}{1s}[/tex]
Therefore N, Number of waves = 2.16 waves rounded up to 2.2 waves
A portable speaker is switched on. 600 J of energy is transferred from the chemical
store in the battery to the thermal store of surroundings; 250 J by heating and
some by radiation (sound). How much energy is transferred by radiation?
Answer:
350 J of energy is transferred by radiation.
Explanation:
Given that,
600 J of energy is transferred from the chemical store in the battery to the thermal store of surroundings.
Heat energy = 250 J
Sound energy = x
According to the conservation of energy,
600 = 250 +x
x = 600-250
x = 350 J
So, 350 J of energy is transferred by radiation.
The height of a transverse waves is known as its?
Answer:
amplitude
Explanation:
wave is a called the crest, and the low point is called the trough. For longitudinal waves, the compressions and rarefactions are analogous to the crests and troughs of transverse waves. The distance between successive crests or troughs is called the wavelength. The height of a wave is the amplitude.…
Part C
How many combined bits of storage are there on the two tablets?
Answer:
IVE BEEN TRYNA FIND THE ANSWER FOR THE PAST HOUR T-T
Explanation:
Answer:
3.2 x10^11 bits of storage
Explanation:
a car takes 4 hours to cover a distance if it takes at a speed of 40mph. what should be it's speed to cover the same distance in 1.5 hours
Answer:
Speed = 106.67mph
Explanation:
Let the first motion be A.
Given the following data;
Speed A = 40mph
Time A = 4 hours
To find the distance covered in A;
Distance = speed * time
Distance = 40 * 4
Distance = 160 miles.
To find the speed required to cover the above distance in 1.5 hours;
Speed = distance/time
Speed = 160/1.5
Speed = 106.67mph
Two free charges +q and +4q are a distance l apart. A third charge is placed so that the entire system is in equilibrium. Find the location, magnitude and sign of the third charge.
Answer:
the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position x= l/3
Explanation:
The forces in this system are given by Coulomb's law
F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]
As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .
Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge
Let's find the location of charge 3 so that it is in balance
∑ F = F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
we seek every force
F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]
F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]
the distances are
x₁₃ = x-0 = x
x₂₃ = l -x
we substitute
k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}
we solve
(l-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
l² - 2lx + x² = \frac{4q}{q} x²
3x² + 2l x - l² = 0
we solve the quadratic equation
x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)
x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6
x₁ = -l
x₂ = l / 3
as charge 3 must be between the two charges the correct answer is
x = l / 3
with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.
now let's analyze the force on the other charges
charge 1 so that it is in balance
∑F = F₁₃ - F₁₂ = 0
F₁₃ = F₁₂
[tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]
l² q₃ = q₂ (l/3)²
q₃ = q₂ / 9
q₃ = 4q / 9
q₃ = [tex]\frac{4}{9} q[/tex]
in summary the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q
in the position x= l/3
A negative charge of 0.198 C exerts an attractive force of 83,506 N on a second charge that is 3,004 m away. What is the magnitude of the second charge? ( solve for one of the charges)
Answer:
-606.73C
Explanation:
According to coulombs law
F = kq1q2/r^2
Substitute the given value
83,506 = 9*10^9(-0.198)q2/(3004)^2
83,506 = -1.242*10^9q2/9,024,016
-1.242*10^9q2 = 7.54*10^11
q2 = -7.54*10^11/1.242*10^9
q2 = -606.73C
hence the magnitude of the other charge is -606.73C
A bus travelling 30.0 km/h east has a constant increase in speed of 1.5 m/s. What is its velocity 6.8s later
The final velocity of the bus is 9.83 m/s
The given parameters;
initial velocity of the bus, = 30 km/h
constant increase in speed, = 1.5 m/s
time of motion, t = 6.8 s
The initial velocity of the bus in m/s;
[tex]v = 30 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 8.33 \ m/s[/tex]
The acceleration of the bus;
[tex]a = \frac{\Delta v}{\Delta t} = \frac{1.5 \ m/s}{6.8 \ s } = 0.22 \ m/s^2[/tex]
The final velocity of the bus at the given time of motion;
[tex]v= u + at\\\\v = 8.33 + (0.22 \times 6.8)\\\\v = 9.83 \ m/s[/tex]
Thus, the final velocity of the bus is 9.83 m/s
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Suppose 2 C of positive charge is distributed evenly throughout a sphere of 1.27 cm radius. (a) What is the charge per unit volume for this situation? C/m3 (b) Is the sphere insulating or conducting? How do you know? The sphere is conducting. If it were insulating, none of the charge would be in the interior of the sphere; it would only be on the surface. The sphere is insulating. If it were conducting, none of the charge would be in the interior of the sphere; it would only be on the surface. The sphere is conducting. If it were insulating, all of the charge would be in the interior of the sphere; not on the surface. The sphere is insulating. If it were conducting, all of the charge would be in the interior of the sphere; not on the surface.
Answer:
a) ρ = 2.33 10⁵ C / m³, b) INSULATING
Explanation:
a) For this exercise we use the important concept of density
ρ = Q / V
The volume of a sphere is
V = 4/3 πr3
V = 4/3 π (1.27 10⁻²)³
V = 8.58 10⁻⁶ m³
let's calculate
ρ = 2 / 8.58 10⁻⁶
ρ = 2.33 10⁵ C / m³
b) in a conductor the charges are mobile, therefore due to electoral repulsion all the charges must concentrate on the surface.
In an insulator the charges are fixed, therefore they are distributed throughout the volume
Consequently the sphere must be INSULATING
Which vector has an x-component with a length of 3?
А. С.
B. d
C. a
D. b
Answer:
B.d
mark me as brainlist
Answer:
D. b
Explanation:
the endpoint of vector b is at 3, which means the length is 3
Which process causes the transfer of energy by air currents within the Earth's atmosphere?
Answer:
Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface
How quickly will a 4 kg ball be accelerated if it is struck by a 12 N force?
Explanation:
Hey there!
Given that 4kg ball struck by 12 N force.
So, we need acceleration.
Force = Mass × Acceleration
And, so
Acceleration = Force / Mass.
Acceleration = 12/4
Acceleration is equal to 3m/s² in SI units.
Hope it helps :)
Hell it’s due soon??
Explanation:
don't know don't know don't know
A wire in a circuit carries a current of 0.9 A. Calculate the quantity of
charge that flows through the wire in 50 s. Choose the correct unit of
charge with your answer.
45 A
45C
45 J
O 0.018 A
O 0,018
0.018 J
O 55.6 A
55.6 C
55.6J
Answer:
We conclude that the quantity of the charge that flows through the wire in 50 s will be 45 C.
Explanation:
Given
Current I = 0.9 ATime t = 50 sTo determine
We need to find the quantity of the charge that flows through the wire in 50 s.
Important Tip:
A current of 1 Ampere = 1 Coulomb of charge flowing in 1 second
Using the formula involving charge and current
[tex]I=\frac{Q}{t}[/tex]
where:
[tex]I[/tex] represents the current in amperes (A)[tex]Q[/tex] represents the charge in coulomb (C)[tex]t[/tex] represents the time in seconds (s)now substituting I = 0.9 and t = 50 in the formula
[tex]I=\frac{Q}{t}[/tex]
[tex]0.9\:=\:\frac{Q}{50}[/tex]
switch sides
[tex]\frac{Q}{50}=0.9[/tex]
Multiply both sides by 50
[tex]\frac{50Q}{50}=0.9\cdot \:50[/tex]
Simplify
[tex]Q=45[/tex] C
Therefore, we conclude that the quantity of the charge that flows through the wire in 50 s will be 45 C.
Need help ASAP
Thanks + BRAINLIST only for correct answer
1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves
2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above
3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna
Answer:
Explanation:
1.electric
2.radio wave
3.broadcast
Hope it helped you.
What is the mathematical relationship between height, mass, gravity, and gravitational potential energy?
How does the energy from the person's hand get to the last domino?
Answer:
woh its really exist?
Explanation:
cakra
What is the best example of a compound machine A ax. B ramp. C car D screw
Answer: I believe the answer is C
Explanation:
Cars are composed of hundreds of simple machines
does anyone have the same thing for the brainly app
mine said "this operation couldn't complete" an does anyone know how to fix it
i am on iphone
Answer:
PICK ONE
Explanation:
Which examples best demonstrate likely tasks for Legal Services workers? Check all that apply.
Cisco inspects an office building to make sure it meets fire safety regulations.
Gina gathers information about a court case.
Saul oversees inmates at a correctional facility.
Hana interviews and advises a person who has been accused of a crime.
Pamela pursues and arrests a person suspected of a crime.
Dewayne creates the paperwork for a business contract.
Answer:
b. d. f.
Explanation:
Got it right on Edge
Answer:
2. Gina gathers information about a court case.
4. Hana interviews and advises a person who has been accused of a crime.
6. Dewayne creates the paperwork for a business contract.
How much power is developed in a car that can pull a 5000 N at a constant speed
of 20 m/s?
Answer:
YAYA MAN
Explanation:
When a 5 kg rock is dropped from a height of 6 m on Planet X, it loses 24 J of GPE. What is the acceleration due to gravity on Planet X?
Answer:
g = 1.25m/s²
Explanation:
Given the following data;
Mass = 5kg
Height = 6m
Gravitational potential energy = 24J
To find the acceleration due to gravity;
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
[tex] P.E = mgh[/tex]
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
GPE = mgh
Substituting into the equation, we have;
24 = 5*6*g
24 = 30g
g = 30/24
g = 1.25m/s²
Therefore, the acceleration due to gravity on Planet X is 1.25m/s².
Answer:
g=0.8m/s^2
Explanation:
M=5kg
h=6m
GPE=24J
GPE=Mgh
g=GPE/Mh
g=24J/(5kg)(6m)=0.8
g=0.8m/s^2
On earth a bag of sugar weight 10N. on mars a bag of sugar weight 4N. suggest the weight of the sugar is different on earth and mars
Answer:
gravity
Explanation:
there eould be a different gravitational strenght on both of the planets causing it to weigh more, or less
In mars, the effect of gravity on the object is weaker compared to while on earth. This weakness is what causes the reduction in the weight of the bag of sugar while on mars.
We must understand that the mass of an object may differ depending on its location on the planet. This is due to the effect of gravity on the object.
Gravity is simply defined as any force which attracts an object towards the centre of the earth.
From the question given, we are told that the weight of sugar is 10N on the earth and 4N on Mars. This difference in their mass is attributed to the effect of gravity on the object.
In mars, the effect of gravity on the object is weaker compared to while on earth. This weakness is what causes the reduction in the weight of the bag of sugar while on mars.
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